How many distinct 3 digit code can i create such that this code is divisible by 4.
For example these codes are rejected since they have repeating numbers/less than 3 digits:
024/100/112/996/444
The other answer is just wrong.
There are 9•9•8 = 648 distinct 3-digit codes. The first digit can be any numeral from 1-9, the next digit can be any from 0-9 minus the one used in the first position, and the last digit can be any from 0-9 minus both the numerals used in the first two positions.
But that doesn't even account for the divisibility constraint.
Let the code be [tex]abc[/tex]. We can expand this as
[tex]100a + 10b + c[/tex]
In order for this to be divisible by 4, we observe that
[tex]100a + 8b + 2b + c = 4 (25a + 2b) + (2b+c)[/tex]
so we only need [tex]2b+c[/tex] to be divisible by 4.
The last digit must be even, so there are only 5 choices for the last digit. I list the possibilities and outcomes below. For some integer [tex]k[/tex], we need
[tex]c=0 \implies 2b=4k \implies b=2k[/tex]
[tex]c=2 \implies 2b+2=4k \implies b = 2k-1[/tex]
[tex]c=4 \implies 2b+4 = 4k \implies b = 2(k-1)[/tex]
[tex]c=6 \implies 2b+6 = 4k \implies b = 2k-3[/tex]
[tex]c=8 \implies 2b+8=4k \implies b = 2(k-2)[/tex]
Ignoring [tex]a[/tex] for the moment, in the cases of [tex]c\in\{0,4,8\}[/tex], [tex]b[/tex] is also even. This leaves 3 choices for [tex]c[/tex] and 2 choices for [tex]b[/tex].
Likewise, in the cases of [tex]c\in\{2,6\}[/tex], [tex]b[/tex] is odd. This leaves 2 choices for [tex]c[/tex] and 5 choices for [tex]b[/tex].
Now taking into account the choice for [tex]a[/tex], we have the following decision tree.
• If [tex]a\in\{2,6\}[/tex] and [tex]c\in\{0,4,8\}[/tex], then [tex]b\in\{0,2,4,6,8\}\setminus\{a,c\}[/tex] - a total of 2•3•3 = 18 codes.
• If [tex]a\in\{4,8\}[/tex] and [tex]c\in\{0,4,8\}\setminus\{a\}[/tex], then [tex]b\in\{0,2,4,6,8\}\setminus\{a,c\}[/tex] - a total of 2•2•3 = 12 codes.
• If [tex]a\in\{2,6\}[/tex] and [tex]c\in\{2,6\}\setminus\{a\}[/tex], then [tex]b\in\{1,3,5,7,9\}\setminus\{a,c\}[/tex] - a total of 2•1•5 = 10 codes.
• If [tex]a\in\{4,8\}[/tex] and [tex]c \in\{2,6\}[/tex], then [tex]b\in\{1,3,5,7,9\}[/tex] - a total of 2•2•5 = 20 codes.
• If [tex]a\in\{1,3,5,7,9\}[/tex] and [tex]c\in\{0,4,8\}[/tex], then [tex]b\in\{0,2,4,6,8\}\setminus\{c\}[/tex] - a total of 5•3•4 = 60 codes.
• If [tex]a\in\{1,3,5,7,9\}[/tex] and [tex]c\in\{2,6\}[/tex], then [tex]b\in\{1,3,5,7,9\}\setminus\{a\}[/tex] - a total of 5•2•4 = 40 codes.
Hence there are a total of 18 + 12 + 10 + 20 + 60 + 40 = 160 codes.
Show that 9.1 is not a solution of the equation n-6.4 = 2.61. Then find
the solution
Answer:
The solution is 9.01.
Step-by-step explanation:
To prove that 9.1 isn't the solution we have to plug 9.1 into the equation. By replacing n with 9.1 we get 2.7 which isn't equal to 2.61.
To find the solution we must add 6.4 to both sides of the equation.
PLEASE HELP! 50 POINTS! Consider the following set of sample data: (34, 32, 34, 32, 40, 37, 31, 31, 29, 27). Which of the following will give a 95% t confidence interval for the mean of the population from which the sample was drawn?
Answer:
(15.23,41.016)
Step-by-step explanation:
WE must determine the mean of the data set: Which is the sum of the set divided by the number in the set.
[tex]= (21 + 24 + 25 + 32 + 35 + 31 + 29 + 28)/8 = 225/8 = 28.125[/tex]
We must also determine the standard deviation: Which is the square root of the variance and the variance is the sum of squares of the sample number minus the mean divided by the number if the set data:
[tex]= ((21 - 28.125)^{2} + (24 - 28.125)^{2} +(25 - 28.125)^{2} + (32 - 28.125)^{2} + (35 - 28.125)^{2} + (31 - 28.125)^{2} + (29 - 28.125)^{2} (28 - 28.125)^{2}[/tex]
[tex]= 148.877/8 = 18.6[/tex]
The 95% confidence interval is defined as: The mean ± 1.96*standard deviation divided by the sqaure root of the number of data in the set:
[tex]= 28.125 + (1.96 *18.6)/(\sqrt{8} )[/tex]
[tex]= 41.016[/tex]
[tex]= 28.125 - (1.96 * 18.6)/(\sqrt{8}) = 15.23[/tex]
The confidence interval for this data set is (15.23,41.016)
Answer:
32.7 ± 2.262(1.19)
Step-by-step explanation:
See attached pictures
A wire is first bent into the shape of a triangle. Each side of the triangle is 16 long. Then the wire is unbent and reshaped into a rectangle. If the length of the rectangle is 15 in, what is its width?
Answer:
the width is 9in
Step-by-step explanation:
perimeter of triangle =3×16 = 48
let w= width of rectangle
perimeter of triangle = perimeter of rectangle
48= 2(15 +w)
24= 15 + w
w= 9
Urgente!!! Doy 20 puntos
Answer:
74-7, 0, +9Step-by-step explanation:
Hope this helps
The sales tax on a table saw is $8.25.
a. What is the purchase price of the table saw (before tax) if the sales tax rate is 5.5%?
b. Find the total price of the table saw.
Answer:
a. $150
b. $158.25
Step-by-step explanation:
a.The amount of tax is the product of the tax rate and the price being taxed. This relation can let us solve for the price.
tax = tax rate × price
price = tax/(tax rate) = $8.25/0.055 = $150.00
The purchase price of the table saw is $150.00.
__
b.The total price is the sum of the purchase price and the tax.
total price = price + tax
total price = $150.00 +8.25 = $158.25
The total price of the table saw is $158.25.
What is the area?
This is 6th grade math
Answer:
Find the base, and then the height of this rhombus;
Base: 7 square units
Height: 7 square units
Multiply your base by the height to get the area;
Because the formula for the area of a rhombus is, A = BH
So,
A = 7(7)
A(area) = 49 square units.
I will give the brainiest if you get it right.
Answer:
1 ≤ x < 7/4
Step-by-step explanation:
The function f(x) is defined as increasing on the domain (-8, 4), so the ordering of the arguments is not changed by the function. We can solve the inequality as though f(x) = x, which is increasing everywhere.
Inequality solutionsf(4x -3) ≥ f(2 -x²)
4x -3 ≥ 2 -x² . . . . . . using our assumed definition of f(x)
x² +4x -5 ≥ 0 . . . . . subtract 2-x²
(x -1)(x +4) ≥ 0 . . . . factored form; zeros at -4, +1
The values of x that make this true are ones that make the factors have the same signs: x ≤ -4 or x ≥ 1.
Domain restrictionsThe domain of f(x) is -8 < x < 4, so we require the arguments of f be restricted to those values
Left side
-8 < 4x -3 < 4
-5 < 4x < 7
-5/4 < x < 7/4
Right side
-8 < 2 -x² < 4 . . . . . right side is always true
x² < 10 . . . . . . . . . . . add x² +8
|x| < √10 . . . . . . . . . . less restrictive than the the left-side restriction
SolutionWith the given domain restrictions on f(x), the inequality will be true on the interval ...
1 ≤ x < 7/4
__
Additional comment
The attached graph shows the left-side function argument (dashed blue) and the right-side function argument (dashed green) with the given domain restrictions. The red curve is the difference in function values for the function defined as above. It is only non-negative between 1 and 1.75 as we found above.
This general behavior is applicable for any f(x) that can be described as in the problem statement. For example, f(x) = √(x+8) also gives an increasing curve for the difference f(4x-3)-f(2-x²) on the interval (-5/4, 7/4) with an x-intercept of +1.
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Jack is 3 times as old as Lacy. 9 years ago the sum of their ages was 22 . How old are they now?
Answer:
Jack is 31
Lacy is 10
Step-by-step explanation:
x - 9 = 22
since jack is 3 times as old as lacy,
the formula is
3x - 9 = 22
3x = 31
x = 10.3
So Jack is 31
And Lacy is 10
To prove this, subract 9 (years) from both ages
It will give you an approximate sum of 22 years for both their ages, as the question states
Since Lacy is a little over 10 years old, Jack is 31 instead of 30
The formula was taken from someone elses answer so sorry if it`s wrong
What is the definition of a Pythagorean triple?
Answer:
a set of numbers that are used to find the hypotenuse
Step-by-step explanation:
brainliest
The integer solutions to the Pythagorean theorem, are called Pythagoras triples.
Definition of Pythagorean Triples:
The integer solutions to the Pythagorean theorem, [tex]a^{2} +b^{2} =c^{2}[/tex] are called Pythagorean triples which contains three positive integers a, b and c.
For example:
(3, 4, 5)
By evaluating we get
[tex]3^{2} +4^{2} =5^{2}[/tex]
⇒ 9 + 16 = 25
Hence, 3, 4 and 5 are Pythagorean triples.
Learn more about Pythagorean Triples here:
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ANSWER FOR EXTRA POINTS ⭐️⭐️⭐️
the answer is b if i remeber
3 lines are shown. A line with points M, H, K intersects a line with points J, H, L at point H. A line extends from point H to point P between angle K H J. Angle M H L is 140 degrees and angle K H P is 20 degrees.
What is mAnglePHJ?
100°
120°
140°
160°
Answer:
120
Step-by-step explanation:
Given:
3 Lines
A line with points M, H, K intersects a line with points J, H, L at point H.
A line extends from point H to point P between angle K H J.
Angle M H L is 140 degrees and angle K H P is 20 degrees.
Solve:
Since, Angle M H L is 140 degrees and angle K H P is 20 degrees.
Then 140 - 20 = 120
Answer is 120
~Lenvy~
Z
77°
P
W
X
What is the measure of arc XWZ?
OA
257°
O B. 1039
O C. 206°
O D. 1543
Help me the question 1 in my picture
Answer:
Number 1 is b
I found the answer on a website
Solve for b. -36 + 2.5 = 4
Answer:
False
Step-by-step explanation:
The sides are not equal
What is the area of this figure?
Answer:
20
Step-by-step explanation:
from the numbers i was seeing my answer is 20 i am so sorry if it not right.
Solve the following equation:
3 x one half
==========================================================
Let's simplify the expression:-
[tex]\bigstar{\boxed{\frac{3}{1} *\frac{1}{2}}[/tex]
Multiply 3 times 1 and 1 times 2:-
[tex]\bigstar{\boxed{\pmb{\frac{3}{2} }}[/tex]
======================================================
note:-Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)
Help ASAP.
i need you to please break it down ive tried and just don't understand
Answer:
A) -4
Step-by-step explanation:
Question
[tex]\sf evaluate \ \dfrac{-4+(m+2)}{n} \ \sf when \ m=\dfrac23 \ and \ \sf n=\dfrac13[/tex]
Solution
Substitute the given values of m and n into the original expression:
[tex]\sf \implies \dfrac{-4+(\frac23+2)}{\frac13}[/tex]
Carry out the operation in the brackets first [tex]\sf (\frac23+3)=\frac83[/tex]
[tex]\sf \implies \dfrac{-4+\frac83}{\frac13}[/tex]
Now carry out the operation in the numerator [tex]-4+\frac83=-\frac43[/tex]
[tex]\sf \implies \dfrac{-\frac43}{\frac13}[/tex]
Dividing by a fraction is the same as multiplying by the flipped version of the fraction (flipped = swap the numerator and denominator of the fraction we are dividing by):
[tex]\sf \implies -\dfrac43 \div \dfrac13=-\dfrac43 \times \dfrac31[/tex]
To multiply a fraction, simply multiply the numerators and multiply the denominators:
[tex]\sf \implies -\dfrac43 \times \dfrac31=\dfrac{-4 \times 3}{3 \times 1}=-\dfrac{12}{3}[/tex]
Finally simplify:
[tex]\sf \implies -\dfrac{12}{3}=-4[/tex]
True or False: In an exponential regression, the data points tend to increase in one direction and flatten out in the other direction.
Answer:
T
Step-by-step explanation:
The regression line is flat when there is no ability to predict whatsoever. The regression line is sloped at an angle when there is a relationship. The extent to which the regression line is sloped, however, represents the degree to which we are able to predict the y scores with the x scores
Write the equation of the line perpendicular to y=5/6x+7/6 that passes through the point (-8,9) .
keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above
[tex]y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{5}{6}}x+\cfrac{7}{6}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]
so we can say that
[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{5}{6}} ~\hfill \stackrel{reciprocal}{\cfrac{6}{5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{6}{5}}}[/tex]
so we're really looking for the equation of a line with a slope of -6/5 and that passes through (-8 , 9)
[tex](\stackrel{x_1}{-8}~,~\stackrel{y_1}{9})\qquad\qquad \stackrel{slope}{m}\implies -\cfrac{6}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{-\cfrac{6}{5}}(x-\stackrel{x_1}{(-8)})\implies y-9=-\cfrac{6}{5}(x+8) \\\\\\ y-9=-\cfrac{6}{5}x-\cfrac{48}{5}\implies y=-\cfrac{6}{5}x-\cfrac{48}{5}+9\implies y=-\cfrac{6}{5}x-\cfrac{3}{5}[/tex]
A farmer wants to know how many of his cows have no spots. He has 200 cows total. He takes a random sample of 40 cows. Of these, 11 of the cows have no spots. What can the farmer predict about the entire population?
The farmer can predict that 11 cows in the entire population have no spots
The farmer can predict that 55 cows in the entire population have no spots
The farmer can predict that 40 cows in the entire population have no spots
The farmer can predict that all of the cows have no spots
Answer:
The farmer can predict that 55 cows in the entire population have no spots.
Step-by-step explanation:
The farmer can predict that 40 cows in the entire population have no spots, the correct option is C.
How to find the confidence interval for population proportion from large sample?Suppose we're given that:
Favourable Cases X (in count, in sample)
Sample Size N
Level of significance =[tex]\alpha[/tex]
Then, the sample proportion of favorable cases is:
[tex]\hat{p} = \dfrac{X}{N}[/tex]
The critical value at the level of significance[tex]\alpha is Z_{1- \alpha/2}[/tex]
The corresponding confidence interval is:
[tex]CI = & \displaystyle \left( \hat p - z_c \sqrt{\frac{\hat p (1-\hat p)}{n}}, \hat p + z_c \sqrt{\frac{\hat p (1-\hat p)}{n}} \right)[/tex]
The given information;
The farmer took a random sample of 40 cows out of 200 total cows and found that 11 of those cows have no spots. We can use this sample data to make a prediction about the entire population using statistical inference.
Now,
Plugging in the values, we get:
CI = 0.275 ± 1.96sqrt((0.275(1-0.275))/40)
CI = 0.275 ± 0.139
CI = (0.136, 0.414)
This means that we can be 95% confident that the true proportion of cows with no spots in the entire population lies between 0.136 and 0.414.
the farmer can predict that between 13.6% and 41.4%
Therefore, by confidence interval the answer will be farmer can predict that 40 cows in the entire population have no spots
Learn more about confidence interval for population proportion here:
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Given m \| nm∥n, find the value of x. (7x-10)° (6x-5)°
7x-10=6x-5
We simplify the equation to the form, which is simple to understand
7x-10=6x-5
We move all terms containing x to the left and all other terms to the right.
+7x-6x=-5+10
We simplify left and right side of the equation.
+1x=+5
We divide both sides of the equation by 1 to get x.
x=5
Estimate f(4.04) for f as in the figure
Answer:
2.013 to 3 DP's.
Step-by-step explanation:
f(4.04) will be very close to the tangent line.
Equation of tangent line
is y - 4 = m(x - 10)
m = (4-2) / (10-4) = 1/3
y - 4 = 1/3(x - 10)
y = 1/3x - 10/3 + 4
y = 1/3x + 2/3
So the require estimate of f(4.04)
= 1/3(4.04) + 2/3
= 2.013333
[tex]x^{2} -36\frax+5/(x+6)[/tex]
the answer is
x^{2}-31x+5b
Help picture below problem 10
Answer:
180-52=128
Do mark BRAINLIEST
Express the set using interval notation.
x≥1
Answer:
[1,∞)
Step-by-step explanation:
Brackets indicate equal to while parentheses indicate not equal to this bound.
Jorge's math grade is calculated using a weighted average. Quizzes are worth 30%, homework is worth 10%, unit tests are worth 40%, and the final exam is worth 20%.
Jorge earned an average of 92% on his quizzes, 98% on his homework, 91% on his unit tests, and a score of 95% on his final exam.
What is Jorge's final math grade?
By rewriting the weights in decimal form and applying them to the correspondent percentages, we will see that the final grade is 92.8%.
What is Jore's final math grade?
The final grade will be given by:
G = a₁*x₁ + a₂*x₂ + ...
Where the values "a" are the weights, and the values "x" are the averages of Jeorge.
We know that the weights are:
30% on Quizzes.10% on homework40% on unit test.20% on the final exam.Then we can write the weights in decimal form:
a₁ = 0.3
a₂ = 0.1
a₃ = 0.4
a₄ = 0.2
And the scores are:
92% on quizzes.98% on homework91% on unit tests95% on final exam.So the final math grade will be:
G = 0.3*92 + 0.1*98 + 0.4*91 + 0.2*95 = 92.8%
If you want to learn more about percentages, you can read:
https://brainly.com/question/843074
Answer:
the answer is 92.8%
Step-by-step explanation:
Y varies inversely as x: y=13, when x=3
Answer:
I'm not to sure of this answer
Andrew drinks 1.9 litres of water each day for three years. By rounding the amount of water an the number of days to one significant figure find the approximate amount of water he drinks during the three years. [One year = 365 or 366 days]
Answer:
2081days or 2086days
Step-by-step explanation:
1.9(365)=693.5
1.9(366)=695.4
693.5(3)=2080.5
695.4(3)=2086.2
(2x+3)+(5x17)+90=180
Answer:
x=10
Step-by-step explanation:
Answer:
x is 10 degrees
Step-by-step explanation:
180-90=90
(2x+3)+(5x+17) = 90
7x+20=90
7x=70
x=10