Look at the diagram of metallic bonding. The light blue area represents a sea of... what?

Taking into account the degrees Celsius and Kelvin, if the temperature changes by 100 K, by 100 degrees Celsius it change in degrees Celsius.

A degree Centigrade is a unit of temperature (the physical quantity that reveals the level of heat) whose symbol is °C.

On the other hand, the degree Kelvin, whose symbol is K, is the unit of temperature on the scale created by William Thomson Kelvin, in 1848, based on the degree Celsius, he established his zero point (0) at zero absolute (-273.15 ° C). The figure 0 K is equivalent to the theoretical point where gases have no volume. Absolute zero or 0 K is the point where molecules theoretically stop moving. It is the "perfect" cold.

Considering that zero on the Celsius or degrees centigrade (0 ° C) scale is defined as the equivalent of 273.15 K, the conversion from degrees ° C to K is carried out using the following expression:

T(K)= T(°C) + 273.15 K

In this case, if the temperature changes by 100 K, as it is a change in temperature, the numerical value in K units is the same in ° C units.

Then, the correct answer is option B. if the temperature changes by 100 K, by 100 degrees Celsius it change in degrees Celsius.

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The mass of water decomposed to produce 50 g oxygen has been 56.28 g. Thus, option D is correct.

The reaction for the decomposition of water has been:

[tex]\rm 2\;H_2O\;\rightarrow\;H_2\;+\;O_2[/tex]

From the balanced equation, 2 moles of water decomposes to form 1 moles of hydrogen and 1 mole of oxygen.

The mass of oxygen produced has been 50 g. The moles of oxygen has been given by:

[tex]\rm Moles=\dfrac{mass}{molar\;mass}[/tex]

The moles of oxygen has been:

[tex]\rm Moles_O_2=\dfrac{50}{32}\;mol\\Moles_O_2=1.5625\;mol[/tex]

The moles of oxygen produced has been 1.5625 mol.

The moles of hydrogen decomposed has been given from the balanced chemical equation as:

[tex]\rm 1 \;mole\;O_2=2\;mole\;H_2O\\1.5625\;mol\;O_2=1.5625\;\times\;2\;mol\;H_2O\\1.5625\;mol\;O_2=3.125\;mol\;H_2O[/tex]

The moles of hydrogen decomposes has been 3.125 mol.

The mass of hydrogen decomposed has been given by:

[tex]\rm Mass=moles\;times\;molar\;mass\\Mass_{H_2O}=3.125\;\times\;18.01\;g\\Mass_{H_2O}=56.28\;g[/tex]

The mass of water decomposed to produce 50 g oxygen has been 56.28 g. Thus, option D is correct.

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Explanation:

a particle smaller than an atom (e.g., a neutron) or a cluster of such particles (e.g., an alpha particle).

Answer:

base

Explanation:

The substance NaOH will be disassociated in ions of Na and OH.

Ahrrenius concept of base it's anything that dissolved in water produces OH.

Answer:

Well he couldn't be pushed back as there isn't a place for him to float back, because of Newton's third law: Every force has an opposite force when Eugene pushes, he will float backwards

Explanation:

Hope this helps!

The greenhouse gases are carbon dioxide, methane, and nitrous oxide.

The greenhouse effect has been defined as the entrapment of the sun's energy by the gases that result in the earth becoming warmer and a better place to live.

The gases present in the atmosphere that has been able to entrap the heat energy has been termed the greenhouse gases.

The greenhouse gases have been carbon dioxide, methane, and nitrous oxide.

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Answer:

carbon dioxide, nitrous oxide, methane

Explanation:

Answer:

2-ethly-3-5 dimethylheptam

Explanation:

trust meeeeee

Answer:

There are many with atomic number 1

hydrogen , helium , lithium , beryllium etc.

Hope this answer helps you dear!.

Answer:

With atomic number 1 is hydrogen

Explanation:

The valence with 1 is hydrogen, lithium.....

Answer:

b

Explanation:

because its the atom of the same element, the no of protons doesn't change but the mass number changes so we can find the mass number by:

(mass number = atomic no/no of protons + no of neutrons)

here;

mass number given = 65

and we know, no of protons = 29

let no of neutrons = x

hence,

65 = 29 + x

x= 65 – 29

x= 36

hence your answer is b

Answer:

ʏᴇs, ɪ ᴛʜɪɴᴋ

Explanation:

TᕼᗩᑎKՏ ᒪOᗪՏ

Answer:

distance traveled per unit of time.

Answer:

The is less friction on an icy surface

Explanation:

This is because when u walk on plain ground there is steady friction on the surface but when u walk on an icy floor these is barely any friction which is why it's hard to walk on.

Answer:

There is less friction on an icy surface.

Hope that helps.

Explanation:

If 25.0ml neutralizes 35.0 ml of a 0.200M HCl solution, the molarity of KOH solution is 0.28M

The reaction between KOH solution and HCl is written below.

[tex]HCl + KOH \rightarrow KCl + H_2O[/tex]

Volume of KOH, [tex]V_B[/tex] = 25.0 ml

Volume of HCl, [tex]V_A=35.0 ml[/tex]

Molarity of HCl, [tex]C_A=0.200 M[/tex]

Molarity of KOH, [tex]C_B=?[/tex]

Number of moles of HCl, [tex]n_A=1[/tex]

Number of moles of KOH, [tex]n_B=1[/tex]

The mathematical equation for neutralization reaction is:

[tex]\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}[/tex]

Substitute  [tex]C_A=0.200 M[/tex],  [tex]n_A=1[/tex],  [tex]n_B=1[/tex],  [tex]V_B[/tex] = 25.0 ml, and  [tex]V_A=35.0 ml[/tex] into the equation above in order to solve for [tex]C_B[/tex]

[tex]\frac{0.2 \times 35}{C_B \times 25}=\frac{1}{1} \\\\25C_B=7\\\\C_B=\frac{7}{25} \\\\C_B=0.28M[/tex]

Therefore, the molarity of KOH solution is 0.28M

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Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = 240.9

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = 144

Now we can find percentage composition / percentage by mass of oxygen.

% composition = [tex]\frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound}[/tex] × 100

% composition = [tex]\frac{144}{240.9}[/tex] × 100 = 59.776%

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

Answer:  For the reaction, K c = 255 at 1000 K. If a reaction mixture initially contains a CO concentration of 0.1550 M and a Cl 2 concentration of 0.171 M at 1000 K. 1.

Explanation:

Sleet is a type of precipitation that is formed by water and snow that is usually partially molten.

Sleet consists of icy raindrops that hit the surface, that is, part of the precipitation is frozen and the other forms water droplets.

Therefore, we can conclude that sleet is a form of winter precipitation, in which rain and snow occur at the same time.

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Answer: C) Rain droplets

Explanation: Trust me.

Answer:

B. atomic mass

Explanation:

He arranged the elements into rows in order of increasing mass so that elements with similar properties were in the same column.

Answer:

stock and traditional

Explanation:

the iupac says so

Answer:

a hydrogen atom contains only one proton in it's nucleus, while atoms of all other elements contain more than one proton

Brainliest plzz

Answer:

matter should be the answer

Explanation:

Hope this helps!

Answer:

matter because matter makes up everything in the world EVERYTHING like this computer ri am typing on? matter. what ever device you are using to view this? matter. everything is made of matter. matter is starting to sound weird now so I'm gonna stop saying it and this is the end of the answer remember THAT ANSWER IS MATTERR!!!!!

Answer:

Ok, so the process here is to convert the mass of H2 (hydrogen gas) to moles by dividing the mass by the molar mass of H2. Once you have the moles then you have to multiply by the STP (standard temperature and pressure) molar volume which should be 22.4.

Molar mass of H2 = (1.01)x2 = 2.02g/mol

19.3/2.02 = 9.55 moles

Now just multiply the moles by the molar volume

9.55 moles x 22.4 = 213.92 Litres of H2 are in 19.3g of H2

It requires 60 mL of 0.20 M sodium hydroxide [tex](NaOH)[/tex] to neutralize 25 mL of carbonic acid [tex](H_2CO_3)[/tex], hence the carbonate ions concentration is [tex]0.24M[/tex].

Given:

Reaction:

[tex]\to \bold{2NaOH + H_2CO_3 \to Na_2CO_3 + 2H_20 }[/tex]

[tex]NaOH[/tex] volume [tex](V_B) = 60 \ ml[/tex]  

[tex]H_2CO_3[/tex] Volume [tex](V_A) = 25\ ml[/tex]  

[tex]NaOH[/tex] Molarity [tex](C_B) = 0.20\ M[/tex]

[tex]H_2CO_3[/tex] moles [tex](n_A) = 1[/tex]

[tex]NaOH[/tex] moles [tex](n_B) = 2[/tex]

To find:

[tex]H_2CO_3[/tex] Molarity [tex](C_A) =?[/tex]

Solution:

Using the neutralization reaction:  

[tex]\to \frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B} \\\\[/tex]

[tex]\to C_B = 0.2\ M \\\\ \to n_A = 1 \\\\ \to n_B = 2 \\\\ \to V_B = 60\ ml \\\\ \to V_A = 25\ ml[/tex]

Calculating the [tex]C_A[/tex]:

 [tex]\to \frac{C_A \times 25}{0.2 \times 60} =\frac{1}{2} \\\\\to C_A =\frac{1 \times 0.2 \times 60}{2 \times 25} \\\\\to C_A =\frac{1 \times 2 \times 12}{2 \times 5 \times 10} \\\\ \to C_A =\frac{ 12}{ 5 \times 10} \\\\\to C_A = \frac{6}{5 \times 5} \\\\\to C_A = \frac{6}{25} \\\\\to C_A=0.24\ M[/tex]

Therefore, the concentration of carbonic acid is "0.24M".

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The concentration of carbonic acid( H₂CO₃) is 0.24 M.

The given reaction:

2 NaOH + H₂CO₃ → Na₂CO₃ + 2H₂O

Volume of NaOH  = 60mL

Volume of H₂CO₃ = 25 mL

Molarity of NaOH= 0.20M

To find:

Molarity of H₂CO₃=?

2 moles of NaOH and 1 mol of H₂CO₃ reacts to give 1 mol of Na₂CO₃.

Using the neutralization reaction:  

Consider A to be NaOH and B to be  H₂CO₃

[tex]\frac{\text{Number of moles of A}}{\text{Number of moles of B}} =\frac{\text{Molarity of A*Volume of A}}{\text{Molarity of B*Volume of B}}[/tex]

On substituting the values in order to calculate molarity of H₂CO₃:

[tex]\text{Molarity of B}=\frac{1*0.2*60}{2*25} \\\\\text{Molarity of B}=0.24M[/tex]

Therefore, the concentration of H₂CO₃ is 0.24 M.

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Slaked lime is the ans

thank me later : p

Answer:

Organic matter composted with earthworms, often known as vermicompost, has been demonstrated in studies to have disease-suppressing qualities. The earthworms loosen the soil and enrich it with humus. As a result, they are known as farmer's pals. They help the crops grow healthier and over the time have earned farmers trust.

Explanation:

Hope this helps in some way!

Answer:

1. Get the mass of each element by assuming a certain overall mass for the sample (100 g is a good mass to assume when working with percentages). ...

2. Convert the mass of each element to moles. ...

3. Find the ratio of the moles of each element. ..

4. Use the mole ratio to write the empirical fomula

Answer:

Multiply each result by the given mass.

Explanation:

Hi!

In order to find percent/mass composition you would

1. write the formula

2. calculate the molar mass for each equation

3. add all the masses to get the compound molar mass

4. divide each molar mass by the total mass

and then for mass composition, you would multiple eachy result by the given mass.

For example;

Calculate the number of grams of gold in 89.6 grams of gold(1) perchlorate.

Your formula would be AuClo4

Au : 196.96 x 1

Cl: 35.4 x 1

O: 16 x 4

Add the masses together to get 296.5 g/mol

Lets say we're looking for Oxygen. You would take what you got (16 x 4) and divide it by the total mass. 64/296.5

This would equal 0.215. Instead of multiplying this by 100 like you would for percent, for mass you would multiply by what is given. in this instance it is 89.6.

0.215 x 89.6 = 19

But the question is asking for gold,

197/296

= 0.664 x 89.6

= 59.5

Your answer would be 59.5 grams Au

Hope this helped! : D