Answer:
I think the Answer is ( B. No Lisa forgot the factor 4.)
Step-by-step explanation:
Please help I’m confused also if you can’t see it just click on the picture.
Find the slope: change in y over change in x:
Slope = 30 - -5/ 6- -1 = 35/7 = 5
Find y intercept (the y value when x is 0)
Y = 5(0) = 0
There is no y intercept
The function rule would be:
Y = 5x
Find the value of x
Step-by-step explanation:
By Exterior Angle Theorem, the sum of the 2 inner angles of the triangle is equal to the exterior angle by a straight line.
Therefore we have x + 72° = 90° + 34°.
=> x + 72° = 124°, x = 52°.
Hence the value of x is 52°.
Step by step explanation
Answer: x = 4
Step-by-step explanation:
x/2=10/5
Multiply both sides of the equation by 2.
2⋅ x/2 = 10 /5 ⋅ 2
Simplify both sides of the equation.
Cancel the common factor of 2.
Rewrite the expression.
x= 2 ⋅ 10/5
Divide 10 by 5.
x= 2 ⋅ 10/5
Multiply 2 by 2.
x = 2 ⋅ 2
x = 4
please give brainiest :)
Which graph has a slope of -3?
D.
Its the only one going down 3 and over 1.
The answer would be D because it says -3 and not just 3.
A bridge spans a distance of 1012m. Large cables are attached to the tops of the towers, 45 m above the road. The road is suspended from the large cables by many smaller vertical cables. The smallest vertical cable measures about 1.5m. Determine a quadratic equation for the large cables.
Answer:
A quadratic equation for the large cables is [tex]f(x) = \dfrac{87 }{512072} \cdot x^2 + 1.5[/tex]
Step-by-step explanation:
The shape of the quadratic equation representing the large cables is a parabola
Taking the point of the smallest vertical cables as the vertex, (h, k) with coordinates, (0, 1.5), we have;
h = -b/(2·a)
∴ 0 = -b/(2·a), from which we have, b = 2·a × 0 = 0
k = 1.5 = c - (b²/(4·a) = c - (0/(4·a)) = c
∴ c = 1.5
The standard form of the quadratic equation, a·(x - h)² + k is therefore, given as follows;
f(x) = a·(x - 0)² + 1.5 = a·x² + 1.5
At the towers which are on either side of the bridge, when x = 1012/2 = 506, f(x) = y = 45
Therefore, we have;
45 = a·506² + 1.5
a = (45 - 1.5)/506² = 87/512072 ≈ 1.699 × 10⁻⁴
The quadratic equation for the large cables, f(x), can therefore be presented as follows;
[tex]f(x) = \dfrac{87 }{512072} \cdot x^2 + 1.5[/tex]
Hey can yall help me with this question thank you
Step-by-step explanation:
a. 2x+5
b. 3x+5
c. 5x+4
i hope it will help you