Line k contains the points (-9,4) and (9,-8) in the xy-coordinate plane. What are the two other points that lie on line k?
Answers
Answer
D. (-3, 0) and (3, -4)
Explanation
Let the coordinate of the points be A(-9, 4) and B(9, -8).
We shall look for the gradient m of line using
m = (y₂ - y₁)/(x₂ - x₁)
Substitute for x₁ = -9, y₁ = 4, x₂ = 9 and y₂ = -8
m = (-8 - 4)/(9 - -9) = -12/18 = -2/3
From option A - D given, only C and D would have the same gradient of -2/3 as line AB
To know the correct option, we shall look for the equation of the line AB, that is,
(y - y₁)/(x - x₁) = (y₂ - y₁)/(x₂ - x₁)
(y - 4)/(x - -9) = (-8 - 4)/(9 - -9)
(y -4)/(x + 9) = -12/18
(y - 4)/(x + 9) = -2/3 -----------*
Between option C and D, only D satisfies the equation *
That is, using (-3, 0), we have (0 - 4)/(-3 + 9) = -4/6 = -2/3
Also, using (3, -4), we have (-4 - 4)/(3 + 9) = -8/12 = -2/3
Related Questions
Find the critical value z a/2 that corresponds to the confidence level 96%
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To find the Z a/2 for the 96% confidence. We write the confidence level in decimal form, in this case 0.96.
Now:
[tex]\alpha=1-0.96=0.04[/tex]and then:
[tex]\frac{\alpha}{2}=0.02[/tex]Now we subtract this value to 0.5 to know the value we need to find in the Z table:
[tex]0.5-0.02=0.48[/tex]Now we look at the Z table for this value, by finding we notice that this happens when Z=2.05.
Therefore the Z a/2 value is 2.05
How long will it take for an investment of 2900 dollars to grow to 6800 dollars, if the nominal rate of interest is 4.2 percent compounded quarterly? FV = PV(1 + r/n)^ntAnswer = ____years. (Be sure to give 4 decimal places of accuracy.)
Answers
ANSWER :
The answer is 20.3971 years
EXPLANATION :
The compounding interest formula is :
[tex]FV=PV(1+\frac{r}{n})^{nt}[/tex]where :
FV = future value ($6800)
PV = present value ($2900)
r = rate of interest (4.2% or 0.042)
n = number of compounding in a year (4 : compounded quarterly)
t = time in years
Using the formula above :
[tex]6800=2900(1+\frac{0.042}{4})^{4t}[/tex]Solve for t :
[tex]\begin{gathered} \frac{6800}{2900}=(1.0105)^{4t} \\ \text{ take ln of both sides :} \\ \ln(\frac{6800}{2900})=\ln(1.0105)^{4t} \\ \operatorname{\ln}(\frac{6800}{2900})=4t\operatorname{\ln}(1.0105) \\ 4t=\frac{\ln(\frac{6800}{2900})}{\ln(1.0105)} \\ t=\frac{\ln(\frac{6800}{2900})}{4\ln(1.0105)} \\ t=20.3971 \end{gathered}[/tex]In Square ABCD, AE = 3x + 5 and BD = 10x + 2.What is the length of AC?
Answers
Let's begin by identifying key information given to us:
We have square ABCD
[tex]\begin{gathered} AE=3x+5 \\ BD=10x+2 \\ BD=2\cdot AE \\ 10x+2=2(3x+5) \\ 10x+2=6x+10 \\ \text{Put like terms together, we have:} \\ 10x-6x=10-2 \\ 4x=8 \\ \text{Divide both sides by ''4'', we have:} \\ \frac{4x}{4}=\frac{8}{4} \\ x=2 \\ \\ \end{gathered}[/tex]For a square, the diagonals are equal, AC = BD
[tex]\begin{gathered} AC=BD \\ AC=10x+2 \\ x=2 \\ AC=10(2)+2=20+2 \\ AC=22 \end{gathered}[/tex]A = P + PRT/100Make P the subject from the formula.
Answers
ANSWER
[tex]P=\frac{100A}{100+RT}[/tex]EXPLANATION
We want to make the subject of the formula in the given equation:
[tex]A=P+\frac{PRT}{100}[/tex]First, factorize the right-hand side of the equation:
[tex]A=P(1+\frac{RT}{100})[/tex]Simplify the bracket:
[tex]A=P(\frac{100+RT}{100})[/tex]Now, divide both sides by the term in the bracket:
[tex]\begin{gathered} \Rightarrow P=A\cdot\frac{100}{100+RT} \\ \Rightarrow P=\frac{100A}{100+RT} \end{gathered}[/tex]That is the answer.
What is the equation of a line with slope 7/12 and y-intercept -3?
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The equation of a line in the slope intercept form is expressed as
y = mx + c
where
m represents slope
c represents y intercept
Given that m = 7/12 and c = - 3, the equation of the line would be
y = 7x/12 - 3
24) The radius of a circle is 6 inches. What is the area of a sector that has a central angle of 100 degrees 
Answers
Answer
Area of the sector = 31.42 square inches
Explanation
The area of a sector that has a central angle, θ, in a circle of radius r, is given as
[tex]\begin{gathered} \text{Area of a sector = }\frac{\theta}{360\degree}\times(Area\text{ of a circle)} \\ \text{Area of a circle =}\pi\times r^2 \\ \text{Area of a sector = }\frac{θ}{360°}\times\pi\times r^2 \end{gathered}[/tex]For this question,
θ = central angle = 100°
π = pi = 3.142
r = radius = 6 inches
[tex]\begin{gathered} \text{Area of a sector = }\frac{θ}{360°}\times\pi\times r^2 \\ \text{Area of a sector = }\frac{100\degree}{360\degree}\times3.142\times6^2=31.42\text{ square inches} \end{gathered}[/tex]Hope this Helps!!!
the drop down menus choices are: two imaginary solutionstwo real solutionsone real solution
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Given a quadratic equation of the form:
[tex]ax^2+bx+c=0[/tex]The discriminant is:
[tex]D=b^2-4ac[/tex]And we can know the number of solutions with the value of the discriminant:
• If D < 0, the equation has 2 imaginary solutions.
,• If D = 0, the equation has 1 real solution
,• If D > 0, the equation has 2 real solutions.
Equation One:
[tex]x^2-4x+4=0[/tex]Then, we calculate the discriminant:
[tex]D=(-4)^2^-4\cdot1\cdot4=16-16=0[/tex]D = 0
There are 1 real solution.
Equation Two:
[tex]-5x^2+8x-9=0[/tex]
Calculate the discriminant:
[tex]D=8^2-4\cdot(-5)\cdot(-9)=64-20\cdot9=64-180=-116[/tex]D = -116
There are 2 imaginary solutions.
Equation Three:
[tex]7x^2+4x-3=0[/tex]
Calculate the discriminant:
[tex]D=4^2-4\cdot7\cdot(-3)=16+28\cdot3=16+84=100[/tex]D = 100
There are 2 real solutions.
Answers:
Equation 1: D = 0, One real solution.
Equation 2: D = -116, Two imaginary solutions.
Equation 3: D = 100, Two real solutions.
Solve graphically by the intersection method. Give the solution in interval notation.5x+2<2x−4
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The green line represents 5x + 2
The purple line represents 2x - 4
The orange-colour line represents the intersection of the lines above, which is the solution to the inequality:
5x + 2 < 2x - 4
The intersection is represented by a broken line, to signify the strict < in the equation
How far is the bottom of the ladder from thebottom of the wall? Use the PythagoreanTheorem to determine the solution. Explain howyou found your answer.
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The Pythagorean Theorem is
[tex]c^2=a^2+b^2[/tex]where
c=hypotenuse=13
a=12
b=x
then we substitute the values
[tex]13^2=12^2+x^2[/tex]then we isolate the x
[tex]\begin{gathered} x=\sqrt[]{13^2-12^2} \\ x=\sqrt[]{169-144} \\ x=\sqrt[]{25} \\ x=5 \end{gathered}[/tex]The bottom of the ladder is 5m far from the bottom of the wall
Determine whether the graph shown is the graph of a polynomial function
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the given graph is smooth and its domain is containing all real numbers
so it is a polynomial function.
help meeeeeeeeee pleaseee !!!!!
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The values of the functions are:
a. (f + g)(x) = x² + 3x + 5
b. (f - g)(x) = x² - 3x + 5
c. (f * g)(x) = 3x³ + 15x
d. (f/g)(x) = (x² + 5)/3x.
How to Determine the Value of a Given Function?For any given function, we can evaluate the function by plugging in the equation of each of the functions in the given expression.
Thus, we have the following given functions:
f(x) = x² + 5
g(x) = 3x
a. Find the value of the function for the expression (f + g)(x).
We are required here to add the expression for each of the functions, f(x) and g(x) together, which is:
(f + g)(x) = (x² + 5) + (3x)
(f + g)(x) = x² + 3x + 5
b. Evaluate (f - g)(x) by subtracting the function g(x) from f(x):
(f - g)(x) = (x² + 5) - (3x)
(f - g)(x) = x² - 3x + 5
c. Find (f * g)(x):
(f * g)(x) = (x² + 5) * (3x)
(f * g)(x) = x²(3x) + 5(3x)
(f * g)(x) = 3x³ + 15x
d. Find (f/g)(x):
(f/g)(x) = (x² + 5)/3x
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Unit 6 lesson3 plsss help
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From the triangles ∠ABC ≅ ∠MNP.
Given we have two triangles ABC and PNM
Both triangles have same shape but different angles.
we need to find ∠ABC ≅ ?
we can notice that :
∠A ≅ ∠M
∠B ≅ ∠N
∠C ≅ ∠P
hence these angles are similar to each other.
So, ∠ABC ≅ ∠MNP.
Hence we get the answer as ∠ABC ≅ ∠MNP.
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In ABC, B = 51°, b = 35, and a = 36. What are the two possible values for angle A to the nearest tenth of a degree?Select both correct answers.
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Using the law of sines:
[tex]\frac{a}{\sin(A)}=\frac{b}{\sin (B)}[/tex]Solve for A using the data provided:
[tex]\begin{gathered} \sin (A)=\frac{\sin (B)\cdot a}{b} \\ A=\sin ^{-1}(\frac{\sin (51)36}{35}) \\ A\approx53.1 \\ or \\ A\approx126.9 \end{gathered}[/tex]3. Jeremy asked a sample of 40 8th grade students whether or not they had a curfew. He then asked if they had a set bedtime for school nights. He recorded his data in this two-way frequency table. Bedtime 21 Curfew No Curfew Total No Bedtime Total 4 25 12 16 40 3 15 24 a. What percentage of students surveyed have a bed time but no curfew?
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40 students (the total) represents 100%
To find what percentage represents 3 students (number of students with bedtime but no curfew), we can use the next proportion:
[tex]\frac{40\text{ students}}{3\text{ students}}=\frac{100\text{ \%}}{x\text{ \%}}[/tex]Solving for x,
[tex]\begin{gathered} 40\cdot x=100\cdot3 \\ x=\frac{300}{40} \\ x=7.5\text{ \%} \end{gathered}[/tex]Plot the point given by the following polar coordinates on the graph below. Each circular grid line is 0.5 units apart.230(2.5. -,
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Solution:
Given:
[tex](2.5,-\frac{2\pi}{3})[/tex]Graph the line with the given slope m and y-intercept b.
m = 4,b=-5
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The graph of the linear equation can be seen in the image at the end.
How to graph the linear equation?
The general linear equation is.
y = m*x + b
Where m is the slope and b is the y-intercept.
Here we know that m = 4 and b = -5, so we have:
y = 4*x - 5
To graph this line, we need to find two points.
Evaluating in x = 0 we get:
y = 4*0 - 5 = -5
Evaluating in x = 2 we get:
y = 4*2 - 5 = 8 - 5 = 3
So we have the points (0, -5) and (2, 3), so now we need to graph these points and connect them with a line, the graph can be seen below:
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Sydney is making bracelets, 3 bracelets require 21 beads. The number of braclets varies directly with the number of beads.
Write an equation in the form of y = ax then find the amount o
beads needed for 32 bracelets.
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Step-by-step explanation:
"varies DIRECTLY with" means there is an y = ax relationship.
y = number of bracelets
x = number of beads
3 = a×21
a = 3/21 = 1/7
now, when we have 32 bracelets
32 = 1/7 × x
32×7 = x = 224
224 beads are needed for 32 bracelets.
suppose that the amount of time it takes to build a highway vadies directly with the length of the highway and inversely with the number of workers. suppose also that it takes 300 workers 22 week to build 24 miles of highway. how long will it take 225 to build 27 miles of highway
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12"retest: CirclesOASelect the correct answerArc XY located on circle A has a length of 40 centimeters. The radius of the circle is 10 centimeters. What is the measure of the correspondingcentral angle for XY in radians?O B.OC.OD. 34TResetSubmit TestNextReader Tools
Answers
step 1
Find out the circumference
[tex]C=2\pi r[/tex]where
r=10 cm
substitute
[tex]\begin{gathered} C=2\pi(10) \\ C=20\pi\text{ cm} \end{gathered}[/tex]Remember that
The circumference subtends a central angle of 2pi radians
so
Applying proportion
Find out the central angle by an arc length of 40 cm
[tex]\begin{gathered} \frac{2\pi}{20\pi}=\frac{x}{40} \\ \\ x=4\text{ rad} \end{gathered}[/tex]therefore
The answer is 4 radians Option BCarrie sold 112 boxes of cookies, Megan sold 126 boxes of cookies, Julie sold 202 boxes of cookies, and Ashton sold 176 boxes of cookies. what was the average number of boxes of cookies sold by each individual
Answers
Answer:
154 boxes.
Explanation:
To calculate the average number of boxes of cookies sold by each individual, we use the formula:
[tex]\text{Average=}\frac{\text{Sum of all boxes sold}}{\text{Number of individuals}}[/tex]This gives:
[tex]\begin{gathered} \text{Average}=\frac{112+126+202+176}{4} \\ =\frac{616}{4} \\ =154\text{ boxes} \end{gathered}[/tex]The average number of boxes of cookies sold by each individual was 154 boxes.
to rent a van a moving company charges $40.00 plus $0.50per miles
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The problem talks about the cost for renting a van, which can be calculated adding $40.00 plus $0.50 for each mile.
The problem asks to wirte an explicit equation in slope-intercept form which can represent the cost of renting a van depending on the amount of miles. Then, the problem asks to find the cost if you drove 250 miles.
In scalene triangle ABC shown in the diagram below, m2C = 90°.B.Which equation is always true?sn A = sin Bcos sn A = cos BCanAB4 5 678 9 1011
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inNote: To know which equation is true, then we will have to TEST for each of the choices we are to pick from.
From the tirangle in the image.
[tex]\begin{gathered} 1)\sin \text{ A =}\frac{\text{ Opp}}{\text{Hyp}}\text{ = }\frac{a}{c} \\ \cos \text{ B = }\frac{\text{ADJ}}{\text{HYP}}\text{ = }\frac{a}{c} \\ So\text{ from the above, we can s}ee\text{ that: SinA = Cos B :This mean the choice are equal} \\ \end{gathered}[/tex][tex]\begin{gathered} 2)\text{ To test for the second choice we have..} \\ \text{ Cos A = Cos B} \\ \text{for Cos A =}\frac{\text{Adj}}{\text{Hyp}}\text{ =}\frac{b}{c} \\ \\ \text{for Cos B = }\frac{Adj}{\text{Hyp}}\text{ = }\frac{a}{c} \\ \text{from here we can s}ee\text{ that Cos A }\ne\text{ Cos B : meaning Cos A is not equal to Cos B} \\ \end{gathered}[/tex]3) To test for the third choice: Sin A = Cos A
[tex]\begin{gathered} \sin \text{ A=}\frac{opp}{\text{Hyp}}\text{ = }\frac{a}{c} \\ \cos \text{ A = }\frac{Adj}{\text{Hyp}}\text{ = }\frac{b}{c} \\ we\text{ can s}ee\text{ that sinA }\ne\text{ cos }A,\text{ This mean they are not equal} \end{gathered}[/tex][tex]\begin{gathered} 4)\text{ To test if: tan A = sin B} \\ \text{ }tan\text{ A = }\frac{opp}{\text{Adj}}\text{ = }\frac{a}{b} \\ \\ \text{ sin B = }\frac{Opp}{\text{Hyp}}\text{ = }\frac{b}{c} \\ so\text{ from what we have, w can s}ee\text{ that tan A }\ne\text{ sinB: Meaning they are not equal.} \end{gathered}[/tex]Meaning the first choice is the answer that is sin A = CosB
Shown in the equation are the steps a student took to solve the simple interest formula A=P(1+rt) for r
Answers
Given:
We're given the steps a student took to solve the simple interest formula.
To find:
The algebraic error in student's work.
Step-by-step solution:
Let us first solve the equation and then we will spot the error in the solution:
A = P(1 + rt)
A = p + prt
A - p = prt
A - p / pt = r
Upon comparing both solutions, we can clearly see that the student made a mistake in the second step in the multiplication process.
The student should write A = p + prt in the second step in place of
A = p + rt, because p is multiplied with the whole bracket.
Solve the system withelimination.1-2x + y = 813x + y = -2([?],[?]
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Now we substitute the value of x into the first equation to get the value of y
[tex]\begin{gathered} -2\cdot-2+y=8 \\ 4+y=8 \\ y=8-4=4 \end{gathered}[/tex]Finally the solution is (-2,4)
What is the APY for money invested at each rate?(A) 14% compounded semiannually(B) 13% compounded continuously
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APY means Annual Percentage Yield
The APY is given by the formula:
[tex]\text{APY}=\lbrack(1+\frac{r}{n}\rbrack^n-1[/tex]where r is the rate (in decimals)
n is the number of times the interest was compounded
A) For the money invested at 14% compounded semiannually
r = 14% = 14/100
r = 0.14
n = 2
Substitute n = 2, r = 0.14
[tex]\begin{gathered} \text{APY = \lbrack{}1+}\frac{0.14}{2}\rbrack^2-1 \\ \text{APY}=\lbrack1+0.07\rbrack^2-1 \\ \text{APY}=\lbrack1.07\rbrack^2-1 \\ \text{APY}=0.1449 \\ \text{APY}=0.1449\times100\text{ \%} \\ \text{APY}=14.49\text{ \%} \end{gathered}[/tex]B) For the money invested at 13% compounded continuously
Describe the two different methods shown for writing the complex expression in standard form. Which method do you prefer? Explain
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The first method simlpy executes the distributive property of multiplication over addition, and the definition of the imaginary number, i.
The second method factored out 4i first then perform the operation on the terms left inside the parenthesis , then executes the distributive property of multiplication over addition and the definition of the imaginary number, i.
I prefer the first method . It's simple and straight forward,
The graph shows the distance a car traveled, y, in x hours: What is the rise-over-run value for the relationship represented in the graph?
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
point 1 (2 , 60) x1 = 2 y1 = 60
point 2 (4 , 120) x2 = 4 y2 = 120
Step 02:
slope formula
[tex]m\text{ = }\frac{y2-y1}{x2-x1}[/tex][tex]m\text{ = }\frac{120-60}{4-2}=\text{ }\frac{60}{2}=30[/tex]The answer is:
30
Finding the final amount in a word problem on continuous exponential growth or decay
Answers
Given:
The mass of radioactive follows an exponential decay model
The initial mass = 418 kg
Decreases at a rate = r = 4% per day
So, the general formula for the mass will be:
[tex]m=418\cdot(1-0.04)^d[/tex]where: (m) is the mass after (d) days
So, to find the mass after 2 days, we will substitute with d = 2
so,
[tex]m=418\cdot(1-0.04)^2=418\cdot0.96^2=385.2288[/tex]rounding to the nearest tenth
so, the answer will be mass after 2 days = 385.2 kg
Determine the value of x Round results to an appropriate number of significant digits
Answers
Given
Find
The value of x.
Explanation
length of AB = 22 - 3 = 19
using the trignometric ratios , we have
[tex]\begin{gathered} \sin13\degree=\frac{BD}{AB} \\ \sin13\degree=\frac{\frac{x}{2}}{19} \\ \sin13\degree\times38=x \\ 8.548=x \end{gathered}[/tex]Final Answer
Therefore , the length of x is 8.548
Find the volume of a cone with a height of 10cm and diameter of 6cm. Round to the nearest tenth. Use 3.14 for .
Answers
We can find the volume of a cone using the formula
[tex]V=\frac{\pi r^2h}{3}[/tex]Where
h = height
r = radius
Remember that
[tex]d=2r\Rightarrow r=\frac{d}{2}[/tex]Therefore, let's find out the radius first, the problem says that the diameter is 6cm, then
[tex]r=\frac{6}{2}=3\text{ cm}[/tex]The radius is 3cm and the height is 10cm, let's use it in our formula:
[tex]\begin{gathered} V=\frac{\pi\cdot(3)^2\cdot10}{3} \\ \\ V=30\pi \end{gathered}[/tex]The problem also say to use = 3.14, then the volume is
[tex]\begin{gathered} V=30\cdot3.14 \\ V=94.2 \end{gathered}[/tex]Therefore, the volume is
[tex]V=94.2\text{ cm}^3[/tex]