kmarks Solve the following system of equations graphically on the set of axes below 1 y 22 - 4 y = -X – 7 Plot two lines by clicking the graph. Click a line to delete il. y 10 9 8 7 6 5 4 3 2. 1 5 6 7 8 9 10
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Explanation:
For the first line :
1. Draw a line which has a slope of 1 /2
2. Adjust the line so that it has a y-intercept of -4.
For the second line:
1. Draw a line which has a slope of -1
2. Adjust this line so that it has a y-intercept of -7.
Finally, find the point where the two lines intersect.
The coordinates of the point of intersection are the solution to our system.
To get a line which has a slope 1/2, you start from (0, -4 ) and then move 2 units to the right and then 1 unit up.
Related Questions
Write an equation for the linear function f(x) using the given information. ———————————————Using the points 2,0 & 4,3
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To find the equation in the form
[tex]y=mx+b[/tex]the slope is defined by:
[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{3-0}{4-2} \\ m=\frac{3}{2} \end{gathered}[/tex]To find b you can replace any of the points on the equation an clear for b
(x,y)=(4,3)
[tex]\begin{gathered} y=\frac{3}{2}x+b \\ 3=\frac{3}{2}\cdot4+b \\ 3=6+b \\ 3-6=b \\ b=-3 \end{gathered}[/tex]to check if the answer is correct replace 2 as x in the equation.
[tex]\begin{gathered} y=\frac{3}{2}\cdot2-3 \\ y=3-3 \\ y=0 \end{gathered}[/tex]since the answer was 0 and point was 2,0 the equation is correct.
In a garden, there are 10 rows and 12 columns of mango trees. The distance between two trees is 2 meters and a distance of one meter is left from all sides of the boundary of the garden. What is the length of the garden?
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Answer:
20m
Step-by-step explanation:
(10-1)x2+1x2=20m
What is the equation of this graphed line?
Enter your answer in slope-intercept form in the box.
A graph with a line running through coordinates (-4, -6) and coordinates (2, 6)
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Answer:
12/6 or 1/2
Step-by-step explanation:
you just plug the coordinates into demos calculator and then look at rise over run.
How long does it take Tina to type 864 words, if she took 15 minutes to type out an assignment that comprised 720 words?
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Given data:
The given time taken by Tin to type 720 words is t=15 min.
The given expression can be wriiten as,
720 word=15 min
720 words= 15(60 sec)
720 words= 900 sec
1 word = 900/720 sec
=1.25 sec
Multiplying the above equation with 864 on both sides .
864 words= 864(1.25) sec
= 1080 sec
=1080/60 min
= 18 min.
Thus, the time taken bby Tine to type 864 words is 18 min.
determine the area of figure round to the nearest tenth if necessary..
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r is the midpoint of op and qr is perpendicular to op in the diagram below find the the length of qr
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Given:
OP = 20 in
QP = 26 in
Since R is the midpoint of OP, then, OR = RP
Thus
[tex]OR=RP=\frac{OP}{2}=\frac{20}{2}=10\text{ in}[/tex]To find the length of QR, use pythagoras theorem below:
[tex]\begin{gathered} a^2+b^2=c^2 \\ \\ RP^2+QR^2=PQ^2 \end{gathered}[/tex]Input values into the formula:
[tex]10^2+QR^2=26^2[/tex]Subtract 10² from both sides:
[tex]\begin{gathered} 10^2-10^2+QR^2=26^2-10^2 \\ \\ QR^2=26^2-10^2 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{QR^2}=\sqrt[]{26^2-10^2} \\ \\ QR=\sqrt[]{676-100} \\ \\ QR=\sqrt[]{576} \\ \\ QR=24 \end{gathered}[/tex]Therefore, the length of QR is 24 in
Solve for x. 8x-2x+7>21+10
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Answer: [tex]x > 4[/tex]
Step-by-step explanation:
[tex]8x-2x+7 > 21+10\\\\6x+7 > 31\\\\6x > 24\\\\x > 4[/tex]
Find the distance between the following points using the pythagorean theorem (5,10) and (10,12)
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Answer:
\sqrt[29]
Explanation:
Given the coordinate (5,10) and (10, 12). The formula for calculating the distance between two points is expressed as;
[tex]D\text{ =}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}^{}[/tex]Given that;
x1 = 5
y1 = 10
x2 = 10
y2 = 12
Substitute:
[tex]\begin{gathered} D\text{ = }\sqrt[]{(10-5)^2+(12-10)^2} \\ D=\text{ }\sqrt[]{5^2+2^2} \\ D\text{ =}\sqrt[]{25+4} \\ D\text{ =}\sqrt[]{29} \end{gathered}[/tex]Hence the distance between the points is \sqrt[29]
determine whether the equation defines y as function of x
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To answer this question, we need to solve the equation for y in the third case:
[tex]3x+2y=5\Rightarrow2y=5-3x\Rightarrow y=\frac{5}{2}-\frac{3}{2}x\Rightarrow y=-\frac{3}{2}x+\frac{5}{2}[/tex]We can see from this case that for every value of x, there must be a value in y, and this is the main condition for a relationship to be a function. Then, y is a function of x.
In the fourth case, we have a similar case, for every possible value of x, there must be a value for y. Then, y is a function of x.
As we can see, the red graph is for the linear equation and the black one is for the one with the radical ( y = -sqrt(x+1)).
If we pass a vertical line to either function (alone), we will have only a point that passes through this vertical line, and with this graphical information, we can also say that both are functions of y (for each case).
Find an angle θ with 0∘<θ<360∘that has the same:
Sine as 80∘ : θ = ______ degrees
Cosine as 80∘ : θ = _____ degrees
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Answer:
sin80° = sin100°
cos80° = cos280°
Step-by-step explanation:
In general, sin(a)° = sin (180-a)° and cos(a)° = cos(360-a)°
Simplify the following expression. Assume variables are positive. Express your answer using rational exponents.
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Let's simplify the expression:
[tex]\begin{gathered} (x^{-\frac{1}{2}}\cdot y^{-\frac{2}{3}}\cdot z^{-2})^{-\frac{1}{2}}=x^{(-\frac{1}{2})(-\frac{1}{2})}y^{(-\frac{2}{3})(-\frac{1}{2})}z^{(-2)(-\frac{1}{2})} \\ =x^{\frac{1}{4}}y^{\frac{1}{3}}z \end{gathered}[/tex]Therefore the answer is:
[tex]x^{\frac{1}{4}}y^{\frac{1}{3}}z[/tex]A is the incenter of Triangle FHG Find the length of AT. Explain your thinking.
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we have that
The incenter is the center of the triangle's incircle, the largest circle that will fit
AR=AT=AS -----> radius of the inscribed circle in the triangle
therefore
AT=3 units
Help I’m stuck ‼️‼️‼️ Hw due in a couple minutes
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The lines AD and BC cross at a point where we have two pairs of vertically opposite angles.
The angles labelled (2x +50) and 100 are vertically opposite angles.
Vertically opposite angles are equal. Therefore;
[tex]\begin{gathered} 2x+50=100 \\ \text{Subtract 50 from both sides} \\ 2x+50-50=100-50 \\ 2x=50 \\ \text{Divide both sides by 2} \\ \frac{2x}{2}=\frac{50}{2} \\ x=25 \end{gathered}[/tex]ANSWER:
The value of x is 25. The correct answer is option A
For the equation y = -2x + 1 A) complete the Table: X l Y -4 04B) Use the appropriate tool to graph the given equation
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ANSWER:
a)
b)
EXPLANATION:
Given:
[tex]y=-2x+1[/tex]a) When x = -4, let's go ahead and solve for y;
[tex]\begin{gathered} y=-2(-4)+1 \\ y=8+1 \\ y=9 \end{gathered}[/tex]When x = 0, let's go ahead and solve for y;
[tex]\begin{gathered} y=-2(0)+1 \\ y=0+1 \\ y=1 \end{gathered}[/tex]When x = 4, let's go ahead and solve for y;
[tex]\begin{gathered} y=-2(4)+1 \\ y=-8+1 \\ y=-7 \end{gathered}[/tex]b) Using the above values, we can go ahead and the equation as seen below;
Find sinif cos 0 = is in the first quadrant. 5 OA. OB. OC. 2/20 OD. 25/ M5 Reset Selection
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Answer: B. 3/5
This question can be solved by using trigonometric identities.
ITS NOT A REAL TEST! MY FRIENDS WANT TO SEE HOW SMART I AM.
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The given triangle is:
From the properties of triangle,
The sum of all angle in a triangle is equal to 180 degree
In triangle ABC,
Angle A + Angle B + Angle C = 180
70 + 50 + x = 180
120 +x = 180
x = 180 -120
x = 60
The missing angle is 60 degree
Part A: The Sun that produces 3.9 * 10^33ergs of a radiant energy per second. How many eggs of radiant energy does the Sun produce and 3.25 * 10^3 seconds?Part B: Which is more the reasonable measurement of the distance between the tracks on a railroad: 1.435 * 10^3mm or 1.435 * 10^3mm?
Answers
Part A
[tex]1.2675\times10^{37}ergs[/tex]Explanations:The sun can produce 3.9 * 10^33 ergs of radiant energy per second
[tex]\text{Amount of energy in 1 second = 3.9 }\times10^{33}ergs[/tex][tex]\text{Amount of energy produced in 3.25}\times10^3\sec \text{ = (3.9}\times10^{33}\times3.25\times10^3)[/tex][tex]\text{Amount of energy produced in 3.25}\times10^3\text{ seconds = }1.2675\times10^{37}ergs[/tex]How4 x 8 sheet ofmanyply wood do you need tocover a 24 x 24 deck?
Answers
Given
Dimensions of deck = 24 by 24
dimensions of ply wood = 4 by 8
Find
Number of sheets of ply wood needed to cover the deck
Explanation
number of sheets = area of deck divided by area of 1 ply wood
so ,
area of deck =
[tex]\begin{gathered} 24\times24 \\ 576 \end{gathered}[/tex]and
area of ply wood =
[tex]\begin{gathered} 4\times8 \\ 32 \end{gathered}[/tex]so ,
number of sheets needed =
[tex]\begin{gathered} \frac{576}{32} \\ \\ 18 \end{gathered}[/tex]Final Answer
Hence , the required number of sheets of ply wood is 18
The Muffin Shop makes no-fat blueberry muffins that cost $.70 each. The Muffin Shop knows that 15% of the muffins will spoil. If The Muffin Shop wants 40% markup on cost and produces 800 muffins, what should The Muffin Shop price each muffin?
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If The Muffin Shop wants a 40% markup on cost and produces 800 muffins, The Muffin Shop should price each muffin at $1.15.
How is the price determined?The total expected revenue is divided by the total unspoiled units sold to determine the selling price.
This is illustrated below.
Cost per unit of muffins = $0.70
The spoilage rate = 15%
Expected markup on cost = 40%
The total production units = 800 muffins
The total good units sold = 680 (800 x 1 - 15%)
Total cost for 800 units = $560 (0.70 x 800)
The markup on cost = $224 ($560 x 40%)
The total expected sales revenue = $784 ($560 + $224)
Seling price per unit = $1.15 ($784/680)
Thus, The Muffin Shop should price each muffin at $1.15 to meet its goals.
Learn more about pricing with the markup at https://brainly.com/question/1153322
#SPJ1
- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of the axis of symmetry and whether the function's graph is steeper than, flatter than, or the same shape as the graph of f(x)=x²
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EXPLANATION
Given the function f(x) = (x-6)^2 + 1
[tex]\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}[/tex]Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:
[tex]=x^2-12x+37[/tex][tex]\mathrm{The\: parabola\: params\: are\colon}[/tex][tex]a=1,\: b=-12,\: c=37[/tex][tex]x_v=-\frac{b}{2a}[/tex][tex]x_v=-\frac{\left(-12\right)}{2\cdot\:1}[/tex][tex]\mathrm{Simplify}[/tex][tex]x_v=6[/tex][tex]y_v=6^2-12\cdot\: 6+37[/tex]Simplify:
[tex]y_v=1[/tex][tex]\mathrm{Therefore\: the\: parabola\: vertex\: is}[/tex][tex]\mleft(6,\: 1\mright)[/tex][tex]\mathrm{If}\: a<0,\: \mathrm{then\: the\: vertex\: is\: a\: maximum\: value}[/tex][tex]\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}[/tex][tex]a=1[/tex][tex]\mathrm{Minimum}\mleft(6,\: 1\mright)[/tex][tex]\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}[/tex]Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:
[tex]y=x^2-12x+37[/tex][tex]\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}[/tex][tex]a=1,\: b=-12[/tex][tex]x=\frac{-\left(-12\right)}{2\cdot\:1}[/tex][tex]\mathrm{Refine}[/tex]Axis of simmetry : x=6
The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.
Which of the following is only true sometimes? A. The sum of a rational number and a rational number is rational. B. The sum of a rational number and an irrational number is irrational. C. The product of an irrational number and an irrational number is irrational. D. The product of a nonzero rational number and an irrational number is irrational.
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The sum of a rational number and a rational number is rational. ALWAYS
The sum of a rational number and an irrational number is irrational.
The product of an irrational number and an irrational number is irrational. SOMETIMES
For example, the product of multiplicative inverses like √2 and 1/√2 will be 1
The product of a nonzero rational number and an irrational number is irrational.
Paula will make fruit punch for a party she will mix 1 1/2 gallons of orange juice with 5/8 of a gallon of pineapple juice how many 1/8 gallon servings will Paula have
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First let's find the total number of gallons of the fruit punch. To do so, we just need to sum the gallons of orange juice (1 1/2) ith the gallons of pineapple juice (5/8):
[tex]1\frac{1}{2}+\frac{5}{8}=\frac{3}{2}+\frac{5}{8}=\frac{12}{8}+\frac{5}{8}=\frac{17}{8}[/tex]Now, in order to find how many 1/8 servings can be made, we need to divide the total number of gallons of the fruit punch by the number of gallons of a serving:
[tex]\frac{\frac{17}{8}}{\frac{1}{8}}=\frac{17}{8}\cdot\frac{8}{1}=17[/tex]So Paula can have 17 servings.
Answer:
17
Step-by-step explanation:
5/8 - 5
1 1/2 - 12
The graph used Is below ill attach a picture of the question and options after
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Using the triangle sum theorem:
[tex]\begin{gathered} m\angle L+m\angle K+20=180 \\ 2m\angle L=180-20 \\ 2m\angle L=160 \\ m\angle L=\frac{160}{2} \\ m\angle L=80 \end{gathered}[/tex]Using the exterior angle theorem:
[tex]\begin{gathered} m\angle E=m\angle L+m\angle J \\ m\angle E=80+20 \\ m\angle E=100 \end{gathered}[/tex]Answer:
100
What is the product of 0.976 and 1.2
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Fill in the blank with the correct inequality symbol. State which property of inequalities is being utilized.If x-8>10, then x_18.
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GIVEN
The inequality:
[tex]x-8>10[/tex]SOLUTION
The inequality is to be solved.
Add 8 to both sides of the inequality. This follows the Addition Property of Inequalities:
[tex]if\text{ }xTherefore:[tex]\begin{gathered} x-8+8>10+8 \\ x>18 \end{gathered}[/tex]ANSWER
[tex]x>18[/tex]All the formation your name is on the picture picture provided
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The range of the data is the difference between the maximum data value and the minimum.
In a box plot, the maximum and the minimum are indicated by the dots at the end of the horizontal line.
Here,
Maximum = 10
Minimum = 4.5
Thus, the range of the data is:
[tex]Range=10-4.5=5.5[/tex]Please help, algebra 1, i dont know how to begin to solve it :/ thank you thank you.Simplify:
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Given the expression:
[tex](x^2-4x^3)+(5x^3+3x^2)[/tex]You can simplify it as follows:
1. Distribute the positive sign. Since the sign between the parentheses is positive, it does not change the signs of the second parentheses:
[tex]=x^2-4x^3+5x^3+3x^2[/tex]2. Add the like terms.
By definition, like terms have the same variables with the same exponent.
In this case, you need to add the terms with exponent 3 and add the terms with exponent 2. Notice that:
[tex]\begin{gathered} -4x^3+5x^3=x^3 \\ \\ x^2+3x^2=4x^2 \end{gathered}[/tex]Then, you get:
[tex]=x^3+4x^2[/tex]Hence, the answer is:
[tex]=x^3+4x^2[/tex]Find the area of the compound shapes on the coordinate plane below.
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Answer
Part A: 100 square units
Part B: 39 square units
Part C: 48 square units
Explanation
Part A
Scale: 1cm represent 2 units on x-axis and 1cm represents 5 units on y-axis.
Firstly, we convert the figure into two composite plane shapes, that is, a rectangle and a triangle.
Area of composite shapes = area of rectangle + area of triangle
= Length x Width + 1/2(base x height)
= 10 x 8 + 1/2(10 x 4)
= 80 + 20
= 100 square units
Part B
Scale: 1cm represent 3 units on x-axis and 1cm represents 1 unit on y-axis.
Convert the figure into two composite plane shapes, that is, a rectangle and a trapezium.
Area of composite shapes = area of rectangle + area of trapezium
= Length x Width + 1/2(sum of parallel sides)(perpendicular height)
= 3 x 9 + 1/2(3 + 9)(2)
= 27 + 1/2(24)
= 27 + 12
= 39 square units
Part C
Scale: 1cm represent 2 units on x-axis and 1cm represents 2 units on y-axis.
Convert the figure into two composite plane shapes, that is, a trapezium and a triangle.
Area of composite shapes = area of trapezium + area of triangle
= 1/2(sum of parallel sides)(perpendicular height) + 1/2(base x height)
= 1/2(4 + 8)(6) + 1/2(4 x 6)
=1/2(12 x 6) + 1/2(24)
= 36 + 12
= 48 square units
m(x)=-x^2+4x+21. prove the zeros and determine the extreme value algebraically
Answers
The zeros of the function are:
[tex]\begin{gathered} -(x+3)(x-7)=0 \\ x=-3 \\ or \\ x=7 \end{gathered}[/tex]The vertex is a point V(h,k) on the function. It's either at the base or the top of the function, depending upon wether it opens, upward or downward respectively.
For a function of the form:
[tex]\begin{gathered} y=ax^2+bx+c \\ \text{The vertex(extreme value) is:} \\ h=\frac{-b}{2a} \\ k=y(h) \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} m(x)=-x^2+4x+21 \\ a=-1 \\ b=4 \\ c=21 \\ h=\frac{-4}{2(-1)}=\frac{-4}{-2}=2 \\ k=m(h)=-(2)^2+4(2)+21=-4+8+21=25 \end{gathered}[/tex]Hence, the extreme value is 25 at x = 2
That's it, do you have any question?
Element X decays radioactively with a half life of 14 minutes. If there are 460 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 35 grams?
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Step 1
Given;
[tex]\begin{gathered} Intially\text{ y}_0=460g \\ Half\text{ life, h=14 minutes} \\ y=\frac{460}{2}=230g,\text{ when t=h=14 min} \\ \end{gathered}[/tex]Putting these values in, we have;
[tex]\begin{gathered} 230=a(0.5)^1 \\ a=\frac{230}{0.5}=460g \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} y=460(0.5)^{\frac{t}{14}}---(1) \\ when\text{ y=35} \\ 35=460(0.5)^{\frac{t}{14}} \end{gathered}[/tex][tex]\begin{gathered} 35=460(0.5)^{\frac{t}{14}} \\ \frac{460\cdot \:0.5^{\frac{t}{14}}}{460}=\frac{35}{460} \\ 0.5^{\frac{t}{14}}=\frac{7}{92} \\ \frac{t}{14}\ln \left(0.5\right)=\ln \left(\frac{7}{92}\right) \\ t=\frac{14\ln\left(\frac{7}{92}\right)}{\ln\left(0.5\right)} \\ t=52.02689 \\ t\approx52.0\text{ minutes to the nearest tenth of a minute} \end{gathered}[/tex]Answer;
[tex]52.0\text{ minutes to the nearest tenth of a minute}[/tex]