Kevin works 2 hours more than emily each time they work together. Using this information, complete the table
Answers
If Kevin works two more hours than Emily, the correct number of hours that complete the table are 6, 5, 8, and j.
How many hours do Kevin and Emily work?The number of hours can be expressed as:
The number of hours Emily works = K - 2 or the number of hours Kevin works minus 2.The number of hours Kevin works = E + 2 or number of hours Emily works plus 2.What are the missing numbers?Emily = Kevin4 hours = 6 hous (E+2)5 hours (K-2) = 7 hours 6 hours = 8 hours (E+2)h= j (E+2)Learn more about mathematics in: https://brainly.com/question/15209879
Related Questions
Which expressions are equivalent to In e?
Answers
Answer:
lne = log(e)e = 1
Step-by-step explanation:
I hope this helps!
What is the value of c in the equation below?
2^-4 x 2^2 = a^b = c
Answers
Answer:
[tex]\frac{1}{64}[/tex]
The third option.
Step-by-step explanation:
Hello ! Here's a calculus question!
Find that value of
[tex]\\ \rm\Rrightarrow {\displaystyle{\int\limits_{\pi}^{2\pi}}}\dfrac{sin^6x+cos^6x}{sin^3xcos^3x}[/tex]
Note:-
Answer must include all steps properly .
Kindly don't waste time here if you don't know the answer .
All the best !
Answers
Answer:
Undefined.
Formula's used:
[tex]\longrightarrow \bold{sec(x) = \dfrac{1}{cos(x)} }[/tex]
[tex]\longrightarrow \bold{cosec(x) = \dfrac{1}{sin(x)} }[/tex]
[tex]\longrightarrow \bold{cot(x) = \dfrac{1}{tan(x)} }[/tex]
[tex]\longrightarrow \bold{tan(x) = \dfrac{sinx}{cos(x)} }[/tex]
[tex]\longrightarrow \bold{sin^2x + cos^2 x = 1 }[/tex]
[tex]\longrightarrow \sf \bold{Sum \ Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx}[/tex]
[tex]\longrightarrow \bold{ \int \:{sec^2(ax+b) = \dfrac{1}{a}tan(ax+b)+c }}[/tex]
[tex]\longrightarrow \bold{\int \:\dfrac{1}{ax+b} =\dfrac{1}{a} ln|ax+b|+c}[/tex]
Explanation:
[tex]\sf \Longrightarrow \int _{\pi }^{2\pi }\:\dfrac{sin^6(x)+cos^6(x)}{sin^3(x) \ * \ cos^3\left(x)}[/tex]
[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)} +\dfrac{cos^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)}[/tex]
[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^3\left(x\right)}{\:cos^3\left(x\right)} +\dfrac{cos^3\left(x\right)}{sin^3\left(x\right)}[/tex]
[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\ tan^3(x)+ cot^3(x)[/tex]
[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi } \tan ^3(x)dx+\int _{\pi }^{2\pi } \cot ^3 (x)dx[/tex]
[tex]\Longrightarrow \sf \bold{ [ }-\ln |\sec \left(x\right) |+\dfrac{\sec ^2(x)}{2}-\dfrac{\cot ^2 (x)}{2}-\ln |\sin(x)| \bold{ ] }^{2\pi }_\pi[/tex]
apply limits
[tex]\sf \Longrightarrow \sf -\ln \left|\sec \left(2\pi \right)\right|+\dfrac{\sec ^2\left(2\pi\right)}{2}-\dfrac{\cot ^2\left(2\pi\right)}{2}-\ln \left|\sin \left(2\pi\right)\right|-(-\ln \left|\sec \left(\pi \right)\right|+\dfrac{\sec ^2\left(\pi\right)}{2}-\dfrac{\cot ^2\left(\pi\right)}{2}-\ln \left|\sin \left(\pi\right)\right|)[/tex]
simplify using trigonometric basic functions
[tex]\Longrightarrow \sf -\ln \left|\dfrac{1}{\cos \left(2\pi \right)}\right|+\dfrac{\left(\dfrac{1}{\cos \left(2\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(2\pi \right)}{2}-\ln \left|\sin \left(2\pi \right)\right|- ( -\ln \left|\dfrac{1}{\cos \left(\pi \right)}\right|+\dfrac{\left(\frac{1}{\cos \left(\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(\pi \right)}{2}-\ln \left|\sin \left(\pi \right)\right|)[/tex]
The value of cot(2π) is not defined. [ cot(2π) = ∞ ]⇒ Undefined
Answer:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \boxed{\text{un} \text{de} \text{f}}[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationIntegration
IntegralsIntegration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Integration Methods: U-Substitution + U-Solve
Step-by-step explanation:
Step 1: Define
Identify given.
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integrand] Rewrite:[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \frac{\sin^6 x}{\sin^3 x \cos^3 x} + \frac{\cos^6 x}{\sin^3 x \cos^3 x}[/tex][Integrand] Simplify:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \tan^3 x + \cot^3 x[/tex][Integrand] Rewrite:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \tan x (\sec^2 x - 1) + \cot x (\csc^2 x - 1)[/tex]
Step 3: Integrate Pt. 2
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{2 \pi}_{\pi} {\tan x (\sec^2 x - 1) + \cot x (\csc^2 x - 1)} \, dx[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{2 \pi}_{\pi} {\tan x (\sec^2 x - 1)} \, dx + \int\limits^{2 \pi}_{\pi} {\cot x (\csc^2 x - 1)} \, dx[/tex]
Step 4: Integrate Pt. 3
Identify variables for u-solve.
1st Integral
Set u:[tex]\displaystyle u = \sec x[/tex][u] Apply Trigonometric Differentiation:
[tex]\displaystyle du = \sec x \tan x \, dx[/tex][du] Rewrite:
[tex]\displaystyle dx = \frac{1}{\sec x \tan x} \, du[/tex]
2nd Integral
Set v:[tex]\displaystyle v = \csc x[/tex][v] Apply Trigonometric Differentiation:
[tex]\displaystyle dv = - \cot x \csc x \, dx[/tex][dv] Rewrite:
[tex]\displaystyle dx = \frac{-1}{\cot x \csc x} \, dv[/tex]
Step 5: Integrate Pt. 4
[Integrals] Apply Integration Method [U-Solve]:[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{x = 2 \pi}_{x = \pi} {\frac{\tan x (\sec^2 x - 1)}{\sec x \tan x}} \, du + \int\limits^{x = 2 \pi}_{x = \pi} {\frac{- \cot x (\csc^2 x - 1)}{\cot x \csc x}} \, dv[/tex][Integrals] Simplify:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{x = 2 \pi}_{x = \pi} {\frac{u^2 - 1}{u}} \, du - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{v^2 - 1}{v}} \, dv[/tex][Integrals] Apply Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{u^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{1}{u}} \, du - \Bigg( \frac{v^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{1}{v}} \, dv \Bigg)[/tex][Integrals] Apply Logarithmic Integration:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{u^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \ln | u | \bigg| \limits^{x = 2 \pi}_{x = \pi} - \Bigg( \frac{v^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \ln | v | \bigg| \limits^{x = 2 \pi}_{x = \pi} \Bigg)[/tex]Back-Substitute variables u and v:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{\sec^2 x}{2} \bigg| \limits^{2 \pi}_{\pi} - \ln | \sec x | \bigg| \limits^{2 \pi}_{\pi} - \Bigg( \frac{\csc^2 x}{2} \bigg| \limits^{2 \pi}_{\pi} - \ln | \csc x | \bigg| \limits^{2 \pi}_{\pi} \Bigg)[/tex]Simplify:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \bigg( \ln | \csc x | - \ln | \sec x | + \frac{\sec^2 x - \csc^2 x}{2} \bigg) \bigg| \limits^{2 \pi}_{\pi}[/tex]Apply Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \boxed{\text{un} \text{de} \text{f}}[/tex]
∴ we have found the value of the given integral.
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Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
The circumference of a circular ice
skating rink is 408.2 m.
What is the
approximate are of the skating rink? Use
3.14 for Pi. (10 points)
Answers
Answer:
13259.77 meters squared
Step-by-step explanation:
Substitute the given values
408.2= 2*3.14*r
R is 65
Now that we know that the radius is 65, the formula for the area of a circle is a=3.14*r^2
Substitute the given values
3.14*65^2
Therefore, the area of the circle is 13266.5 metres squared
What are the solutions to the quadratic equation (x + 4)(3x - 5) = 0?
Answers
Answer:
x = 4x = 5/3Step-by-step explanation:
Given :
⇒ (x + 4)(3x - 5) = 0
The solutions will make the answer 0.
Therefore,
x + 4 = 0 3x - 5 = 0⇒ x = 4
⇒ 3x = 5 ⇒ x = 5/3
Twice a number added to their half of itself equals 20 find the number
Answers
Answer:
[tex]x(2) + 5\\[/tex]
The number is 8 because [tex]8 * 2 = 16[/tex]
And if you add 4, you get 20
Hence, the number is 8
Answer:
8
Step-by-step explanation:
let the number be x
=> 2x+(x/2) = 20
=> 4x+x/2 = 20
=> 5x/2 = 20
=> 5x = 20*2
=> 5x = 40
=> x = 40/5
=> x = 8
can i get brainliest
i do not know this answer
Answers
Answer:
9 millimeters is the answer.
1/15 ÷ 8 what is the answer to this question
Answers
Hey there!
1/15 ÷ 8
= 1/15 ÷ 8/1
= 1/15 × 1/8
= 1 × 1 / 15 × 8
= 1 / 120
Therefore, your answer is: 1/120
Good luck on your assignment & enjoy your day!
~Amphirite1040:)
kevin completed 10 problems of his homework during lunch this is 2/7 of the total assignment how many problem was Kevin assigned for homework
Answers
Answer:
35 problems
Step-by-step explanation:
We know that 10 problems are 2/7 of his total assignment, so we can set up the following equation,
[tex]\frac{10}{x\\} = \frac{2}{7}[/tex]
(side note: x is the denominator because we don't know how many problems it is out of yet)
We can cross multiply which gives us: (7x10) and 2(x)
70 = 2x (set them equal)
x = 35 (divide 70 by 2)
Hope this helps!
Find the value of x. (25 points!)
Answers
Answer:
22.5
Step-by-step explanation:
By the angle bisectors theorem,
30/32 = x/24
x=24(30/32) =22.5
someone please answer these 3 questions
Answers
Answer:
5 prism all have same volume
Step-by-step explanation:
Determine if the two triangles are necessarily congruent. If so, fill in a flowchart proof to prove that they are. N A B M
Answers
Answer:
Step-by-step explanation:
Use DeMoivre's Theorem to find the square roots of 4(cos90+ i sin 90). Show your work.
Answers
Answer:
Procedure 6.3. 1:Finding Roots of a Complex Number
Express both z and w in polar form z=reiθ,w=seiϕ. ...
Solve the following two equations: rn=s. ...
The solutions to rn=s are given by r=n√s.
The solutions to einθ=eiϕ are given by: nθ=ϕ+2πℓ,forℓ=0,1,2,⋯,n−1. ...
Using the solutions r,θ to the equations given in (6.3.
Step-by-step explanation:
Answer:-1.79229446 + 3.57598665 i
Step-by-step explanation:
I will honest this how much I can help you
Bella is typing a 400 word essay. She types 50 words in 2 minutes.
Enter an equation in the form of y=mx+b, that represents the number of words (y) remaining to type after x minutes.
Answers
Answer:
[tex]y=25x[/tex]
Step-by-step explanation:
If Bella types 50 words in 2 minutes, we can divide 50 by 2 to see how many words she types in 1 minute.
[tex]50/2=25[/tex]
So, Bella types 25 words per minute. When she first began writing her essay, she did not have words to start with, so there is no y-intercept ([tex]b[/tex]).
Therefore, the equation that represents this relation is [tex]y=25x[/tex].
Solving the equation
We can divide 400 by 25 to determine how many minutes it would take her to finish her essay.
[tex]\frac{400}{25} =16[/tex]
Therefore, it will take her 16 minutes to complete her essay.
#LearnWithBrainly
A radioactive compound with mass of 260 grams decays at a rate of 3.8% per hour. Which equation represents how many grams of the compound will remain after 8 hours?
A: C=260(1.038)^8C=260(1.038)^8
B: C=260(0.962)^8C=260(0.962)^8
C: C=260(0.038)^8C=260(0.038)^8
D: C=260(1-0.38)^8C=260(1−0.38)^8
Answers
The exponential equation that represents how many grams of the compound will remain after 8 hours is:
B: C=260(0.962)^8
What is an exponential function?A decaying exponential function is modeled by:
[tex]A(t) = A(0)(1 - r)^t[/tex]
In which:
A(0) is the initial value.r is the decay rate, as a decimal.A radioactive compound with mass of 260 grams decays at a rate of 3.8% per hour, hence the equation for the mass after t hours is given by:
[tex]A(t) = 260(1 - 0.038)^t[/tex]
[tex]A(t) = 260(0.962)^t[/tex]
After 8 hours, the amount is given by:
[tex]A(t) = 260(0.962)^8[/tex]
Hence option B is correct.
More can be learned about exponential equations at https://brainly.com/question/25537936
please someone do number 9
Answers
Answer:
2 4/5 kg.
Step-by-step explanation:
Multiply 7/2 (3 1/2) by 4/5
A tank in the shape of a hemisphere has a radius of 3 feet. If the liquid that fills the tank has a density of 88.2 pounds per cubic foot, what is the total weight of the liquid in the tank, to the nearest full pound?
Answers
Answer:
4988 pounds
Step-by-step explanation:
Volume of Hemisphere
4/3 x π x r^3 = 4/3 x 3^3 x π = 4/3 x 27π = 36π = Volume of Sphere
To calculate volume of Hemisphere = 36π / 2 = 18π foot^3
Weight of the liquid
88.2 pounds / foot^3 means that every cubic foot weighs 88.2 pounds so
88.2 pounds x 18π = 4987.5925 which to the nearest pound = 4988 pounds.
What is x. Please show *all* the steps.
Answers
The equation 5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0 is a quadratic equation
The value of x is 8 or 1
How to determine the value of x?The equation is given as:
5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0
Rewrite as:
-5/x - 2 + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0
Take the LCM
[-5(x + 2) + (x -5)(x- 2)]\[x^2 - 4 + [3x + 8]/[x^2 - 4] = 0
Expand
[-5x - 10 + x^2 - 7x + 10]/[x^2 - 4] + [3x + 8]/[x^2 - 4] = 0
Evaluate the like terms
[x^2 - 12x]/[x^2 - 4] + [3x + 8]/[x^2 - 4 = 0
Multiply through by x^2 - 4
x^2 - 12x+ 3x + 8 = 0
Evaluate the like terms
x^2 -9x + 8 = 0
Expand
x^2 -x - 8x + 8 = 0
Factorize
x(x -1) - 8(x - 1) = 0
Factor out x - 1
(x -8)(x - 1) = 0
Solve for x
x = 8 or x = 1
Hence, the value of x is 8 or 1
Read more about equations at:
https://brainly.com/question/2972832
ACTIVITY 2: Apply Pythagorean Theorem to complete the data below and write your answers on your answer sheet. Refer to the given examples. (2 points each number) A 1. 8 15 b 2. 18 24 3. 24 40 a C B 4. 16 20 5. 4 9 a² + b2 or Formulas: If c is unknown: c2 = If a is unknown: a2 = Ifb is unknown: b2 = c² - b2 or c= Va2 + b 2 a= vc2-b2 b = c2 - a2 = a² C2 - a2 or
Answers
To completely complete the data use the formula a2 + b2 = c2 in order to find the value of the missing side.
What is the pytagorean theorem?This is a general formula that can be used to find out the lenght of one of the sides in a right-angle triangle by knowing the other sides.
The general formula is:
a^2 + b^2 = c^2side a = base of the triangleside b = altitudeside c= hipotenuse (diagonal line)How to use the theorem?Replace the known sides and find the third side. For example:
a^2 + b^2 = c^25^2+6^2 = c^215 + 36 = c^251 = c^2c = √51c = 7.14Learn more about Pythagorean Theorem in: https://brainly.com/question/14504604
Find the solution set of the inequality
4.7 -1 <11.
Answers
Answer:
4x-1<11
4x<11+1
4x<12
x<12/4
x<3
Solve for x. Leave your answer in simplest radical form.
SOMEONE PLEASE HELP ME ILL GIVE YOU BRAINLIST ANSWER
Answers
Answer:
x = 7
Step-by-step explanation:
I used the formula c^2 = a^2 + b^2
if you need further explanation,let me know
There are 25 white tiles in a box. what percent of tiles what percent of tiles will ally use to tile her laundry room floor (6ft by 6ft)
Answers
Answer: 100%
Step-by-step explanation:
Scott has 6 T-shirts and 10 dress shirts in his wardrobe. What is the probability of selecting a dress shirt from his wardrobe?
a-3/8
b-3/5
c-5/8
d-8/5
Answers
Answer:
B
Step-by-step explanation:
6 divided by 10 = 0.6
0.6 = 6/10
6/10 = 3/5
a water tank holds 256 gallons but is leaking at 3 gallons per week. A second water tank holds 384 gallons but is leaking at a rate of 5 gallons per week . After how many weeks will the amount of water in the two tanks be the same
Answers
the two tanks wi equal 64
x=64
Answer:
w = 64 weeks
Step-by-step explanation:
From the information, we have two equations that we will need to set equal to each other to find the number of weeks, w, it takes for both tanks to hold the same amount:
[tex]-3w+256=-5w+384\\(-3w+256=-5w+384)-256\\(-3w=-5w+128)+5w\\(2w=128) /2\\w=64[/tex]
Hello, can u help me out please i will give brainlist :)
Answers
Answer:
$5.75
Step-by-step explanation:
Find the difference between the weeks as this will give you the difference hence the amount deposited each week
0->1
is 12.00->17.75
diffrence is $5.75
1->2
is 17.75->23.50
diffrence is $5.75
the amount saved each week is $5.75
6 a =24
Help me please
Answers
The Ferris wheel shown makes 14 revolutions per ride. How far would someone travel during one ride? Round your final answer to the nearest whole number. Use 3.14 for π.
diameter 67 feet
Someone would travel about
feet during one ride on the Ferris wheel.
Answers
Answer:
2,945 feet
Step-by-step explanation:
Find the circumference.
C = dπ
C = 67(3.14)
C = 210.38
Since there are 14 revolutions, multiply the circumference by 14.
210.38 x 14 = 2945.32
Round
2,945
Is 2x + 6x equivalent to 9x when x=0?
Answers
Answer:
Yes
Step-by-step explanation:
Anything muliplied by zero end up equalling zero. So with this in mind we can put 0 in for x and find out what each eqautian equals.
2(0) + 6(0) = 0; Once we multiply both sides we end up adding 0 and 0, so it equals 0
9(0) = 0
Since, 0 = 0 they are both equal.
Hope this helps!
Which answer choice correctly represents 0.4121212…?
A. 0.412
B.
C.
D.
Answers
The one in the second picture
The bar on top of the numbers 12 means that the 12 keeps on re-occurring
the on with the line over the 2 only
Step-by-step explanation:
I need help with Function Operations please
Answers
Answer:
30
Step-by-step explanation:
The ring operator signifies a composition of functions. The composition is evaluated right-to-left. That means the composition ...
[tex](f\circ g)(x)[/tex]
should be interpreted to mean ...
[tex]f(g(x))[/tex]
___
To evaluate f(g(6)), we first evaluate g(6):
g(6) = 6² -5 = 31
Then we evaluate the function f using that as its argument:
f(31) = 31 -1 = 30
f(g(x)) = 30