Kayla wants to have new doors installed.
The door company charges $125 as a one time fee.
They also charge $50 per window installed.
If the number of new windows installed is w, then it means that to install w new windows, they will charge an additional:
w * 50 = $50w
This will be in addition to the one time fee.
Let T be the total cost of installation.
Therefore, the total cost for installing w new windows (in dollars) is:
T = 125 + 50w
A committee must be formed with 5 teachers and 4 students. If there are 6 teachers to choose from, and 15 students, how many different ways could the committee be made?
There are 6 teachers and 15 students to choose from
To form a committee of 5 teachers and 4 students
The combination rule will be applied
From 6 teachers, The number of ways 5 teachers can be selected is
[tex]^6C_5[/tex]From 15 students, the number of ways 4 students can be selected is
[tex]^{15}C_{4^{}}[/tex]Therefore, the total number of ways a committee of 5 teachers and 4 students can be formed from 6 teachers and 15 students is
[tex]^6C_5\times^{15}C_{4^{}}[/tex]Simplifying this gives
[tex]^6C_5\times^{15}C_{4^{}}=\frac{6!}{(6-5)!\times5!}\times\frac{15!}{(15-4)!\times4!}[/tex]This further gives
[tex]\begin{gathered} ^6C_5\times^{15}C_{4^{}}=\frac{6!}{1!\times5!}\times\frac{15!}{11!\times4!} \\ ^6C_5\times^{15}C_{4^{}}=\frac{6\times5!}{1\times5!}\times\frac{15\times14\times13\times12\times11!}{11!\times4\times3\times2\times1} \end{gathered}[/tex]Cancel out common factors
[tex]\begin{gathered} ^6C_5\times^{15}C_{4^{}}=6\times\frac{15\times14\times13\times12}{4\times3\times2\times1} \\ ^6C_5\times^{15}C_{4^{}}=6\times\frac{32760}{24} \\ ^6C_5\times^{15}C_{4^{}}=6\times1365 \\ ^6C_5\times^{15}C_{4^{}}=8190 \end{gathered}[/tex]Therefore, the number of ways the committee can be formed is 8190 ways
can you please solve this practice problem for me I need assistance
The missing angle in the triangle of the left is:
51 + 74 + x = 180
x = 180 - 51 - 74
x = 55°
The missing angle in the triangle of the right is:
55 + 74 + x = 180
x = 180 - 55 - 74
x = 51°
Then, both triangles are similar. This means that their corresponding sides are in proportion. These sides are:
35 in
give a reason that justifies each statement for questions 4-9.
4.
The angles ∠6 and ∠8 are congruent because they are alternate interior angles.
5.
The angles ∠4 and ∠5 added are equal to 180° because they are supplementary angles.
6.
If ∠1 is equal ∠7, then they are alternate exterior angles, therefore the lines p and q need to be parallel.
7.
The angles ∠1 and ∠2 are congruent because they are vertically opposite angles.
8.
If ∠2 and ∠6 are supplementary, they are consecutive interior angles, therefore the lines p and q need to be parallel.
9.
The angles ∠6 and ∠9 are congruent because they are corresponding angles.
Construct a probability distribution for a discrete random variable uses the probability experiment of tossing a coin three times. Consider the random variable for the number of heads
Answer:
Explanation:
By building a tree diagram we can find the theoretical probability of each number of heads when tossing three coins.
PLEASE ITS URGENT I NEED HELP!!! I BEG YOU GUYS PLEEAASEEE THANKS..
Explanation
remember some properties of the exponents
[tex]\begin{gathered} a^m\cdot a^n=a^{m+n} \\ (a^m)^n=a^{m\cdot n} \\ a^{-m}=\frac{1}{a^m} \end{gathered}[/tex]then, to solve this solve each option and compare
Step 1
[tex]6^{-5}\cdot6^2[/tex]solve
[tex]\begin{gathered} 6^{-5}\cdot6^2=6^{-5+2}=6^{-3} \\ \end{gathered}[/tex]so, this is not an answer
Step 2
[tex](\frac{1}{6^2})^5[/tex]solve
[tex]\begin{gathered} (\frac{1}{6^2})^5=(6^{-2})^5=6^{(-2\cdot5)}=6^{-10} \\ \end{gathered}[/tex]so, this is an answer
Step 3
[tex]\begin{gathered} (6^{-5})^2 \\ \text{solve} \\ (6^{-5})^2=6^{-5\cdot2}=6^{-10} \end{gathered}[/tex]so, this is an answer
Step 4
[tex]\begin{gathered} \frac{6^{-3}}{6^7} \\ \text{solve} \\ \frac{6^{-3}}{6^7}=\frac{1}{6^3\cdot6^7}=\frac{1}{6^{3+7}}=\frac{1}{6^{10}}=6^{-10} \end{gathered}[/tex]so, this is an answer
Step 5
[tex]\begin{gathered} \frac{6^5\cdot6^{-3}}{6^{-8}} \\ \text{solve} \\ \frac{6^5\cdot6^{-3}}{6^{-8}}=\frac{6^{5-3}}{6^{-8}}=\frac{6^2}{6^{-8}}=6^2\cdot\frac{1}{6^{-8}}=6^2\cdot6^8=6^{10} \end{gathered}[/tex]so, this is not an answer
I hope this helps you
Prof. Glatt likes 2% milk (2% fat) for her cereal in the morning. Her parents only buy wholemilk (3.5% fat) and non-fat milk (0% fat). While she is visiting her parents, how much of eachtype of milk does she need to mix to get 3 cups of 2% milk. The answer can be rounded to thenearest tenth.linear systems solving algebraically
It is given that there are two types of milk.
One is 3.5% and one is 0%.
Let the number of cups of 3.5% milk be x and the number of cups of 0% milk used be y.
The total should be 3 cups so it follows:
[tex]x+y=3\ldots(i)[/tex]It is also known that the resulting milk is 2% so it follows:
[tex]\begin{gathered} \frac{3.5}{100}x+\frac{0}{100}y=\frac{2}{100}(x+y) \\ \frac{3.5}{100}x=\frac{2}{100}(x+y) \end{gathered}[/tex]Multiply by 100 on both sides to get:
[tex]\begin{gathered} 3.5x=2(x+y) \\ 3.5x=2x+2y \\ 1.5x=2y \\ x=\frac{2}{1.5}y \\ x=\frac{2\times2}{1.5\times2}y \\ x=\frac{4}{3}y \end{gathered}[/tex]Substitute the value of (ii) in (i) to get:
[tex]\begin{gathered} x+y=3 \\ \frac{4}{3}y+y=3 \\ \frac{4+3}{3}y=3 \\ \frac{7}{3}y=3 \\ \frac{3}{7}\times\frac{7}{3}y=\frac{3}{7}\times3 \\ y=\frac{9}{7} \end{gathered}[/tex]Hence the quantity of 0% milk is 9/7 cups.
The quantity of 3.5% milk is given by:
[tex]\begin{gathered} x=\frac{4}{3}y \\ x=\frac{4}{3}\times\frac{9}{7} \\ x=\frac{12}{7} \end{gathered}[/tex]Hence the quantity of 3.5% milk is 12/7 cups.
what is the slope intercept form of the line passing through the point (2,1) and having a slope of 4?
The equation of a line has the form:
[tex]y=mx+b[/tex]if the slope is equal to 4 then we know that: m = 4 and now we can replace the slope and the coordinate ( 2,1 ) to find b so:
[tex]\begin{gathered} 1=4(2)+b \\ 1-8=b \\ -7=b \end{gathered}[/tex]So the final equation will be:
[tex]y=4x-7[/tex]Three lakes lost water during a drought. Lake Jensen lost one ninth of its water, Lake Parlow lost 10% of its water, and Lake Stockton lost twenty one two hundredths of its water. Which lake lost the least amount of water?
Lake Jensen
Lake Parlow
Lake Stockton
All three lakes lost the same amount of water.
The lake that lost the least amount of water during the drought is Lake Parlow.
Which lake lost the least amount of water?The amount of water lost by Lake Jensen is written as a fraction. A fraction is a non-integer that is made up of a numerator and a denominator. An example of a fraction is 1/8.
The amount of water lost by Lake Parlow is written as a percentage. Percentage is the fraction of an amount that is written as a number out of 100.
The amount of water lost by Lake Stockton is written as a decimal. A decimal is the standard form used to write non-integers.
twenty one two hundredths = 21 / 200 = 0.105.
In order to compare the water lost by the three lakes, convert the fraction and the decimal to percentage.
1/9 x 100 = 11.11%
0.105 x 100 = 10.5%
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I inserted a picture of the question Check all that apply
Recall that the line equation is of the form
[tex]y=mx+c\ldots\ldots\text{.}(1)[/tex]The points lie in the line are (2,5) and (-2,-5).
Setting x=2 and y=5 in the equa
The following are the annual salaries of 15 chief executive offers of major companies. The salaries are written in thousands of dollars.
The original data is:
405, 1108, 84, 315, 495, 609, 362, 428, 224, 338, 700, 790, 814, 767, 633
To find the required percentiles, we need to sort the dataset from lowest to highest.
84, 224, 315, 338, 362, 405, 428, 495, 609, 633, 700, 767, 790, 814, 1108
The total number of data is 15.
a) The 25th percentile is the element located at the position:
25/100 * 15 = 3.75
Rounding down, the position is 3, so the 25th perc
All of the following ratios are equivalent except 8 to 12 15/102/36:9
False
1) Let's examine those ratios, and simplify them whenever possible:
[tex]\begin{gathered} \frac{15}{10}=\frac{3}{2} \\ \frac{2}{3} \\ \frac{6}{9}=\frac{2}{3} \\ \frac{8}{12}=\frac{2}{3} \end{gathered}[/tex]2) Simplifying those ratios, all the following but 15/10 are equivalent to 8/12
3) So this is a false statement to say that all of those are equivalent except 8 to 12.
I need help on this calculus practice problem, I’m having trouble on it.
From the question
We are given
[tex]\lim _{x\to-7}g(x)[/tex]We are to determine if the table below is appropriate for approximating the limit
From the table
The value of the limit as x tends to -7
Can be found using
[tex]x=-7.001\text{ and x = 7.001}[/tex]Hence, from the values given in the table
The table is appropriate
4. Use the graph below to answer the following questions.
By the concept of set builder notification
(b) 4
(c) 6
(d) -6
What is the set builder notification?In mathematics, the set-builder notation is used to express a set's elements or specify the conditions that each member of the set must meet. for instance The notation for the set builder is A = x Z | x 4 for the supplied set A =..., -3, -2, -1, 0, 1, 2, 3, 4. Sets can also be expressed using an interval or an equation by using the set-builder notation. In many cases, sets with an infinite number of elements have their elements written and represented in this way. These include integers, real numbers, and natural numbers, among other popular forms of numbers. One (or more) variables from these categories are utilized in this.
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the pie chart below shows how the annual budget for general Manufacturers Incorporated is divided by department. use this chart to answer the questions
You can read a pie chart as follows
Looking at the given pie chart.
The budget for Research is arounf 1/6
The budget for Engineering is around 2/6
The budget for Support is around 1/8
The budget for media and marketing are 1/16 each
The budget for sales is around 3/16
a) The department that has one eight of the budget is Support.
b) The budgets for sales and marketing together add up to
[tex]\frac{3}{16}+\frac{1}{16}=\frac{4}{16}=\frac{1}{4}[/tex]Multiply it by 100 to express it as a percentage
[tex]\frac{1}{4}\cdot100=25[/tex]25% of the budget correpsonds to sales and marketing
c) The budget for media looks around one third the budget for research, to determine the percentage of budget that corresponds to media, divide the budget of research by 3
[tex]\frac{18}{3}=6[/tex]The budget for media is 6%
Express 2x-3y=-6 into y=mx+b
For this problem, we are given a certain expression and we need to write it in the "y=mx+b" form.
We need to isolate the "y" variable on the left side to solve this problem. We have:
[tex]\begin{gathered} 2x-3y=-6\\ \\ 2x-3y-2x=-6-2x\\ \\ \frac{-3y}{-3}=\frac{-6}{-3}-\frac{2x}{-3}\\ \\ y=2+\frac{2}{3}x\\ \\ y=\frac{2}{3}x+2 \\ \\ \end{gathered}[/tex]The expression is y = (2/3)x+2.
A child has an empty box that measures 4 inches by 6 inches by 3 inches. View the figure.What is the length of the longest pencil that will fit into the box, given that the length of the pencil must be a whole number of inches? Do not round until your final answer.
Solution
For this case we can do the following:
We can find the value of s on this way:
[tex]s=\sqrt[]{6^2+4^2}=\sqrt[]{52}=7.21[/tex]And solving for r we got:
[tex]r=\sqrt[]{6^2+3^2}=\sqrt[]{45}=6.71[/tex]Then the answer for this case would be:
[tex]\sqrt[]{52}=7.21[/tex]mrs Middleton makes a solution to Clean her windows she uses 2:1 ratio for every two cups of water she uses one cup of vinagar if ms middleton uses a gallon of water how mant cups of vinagara. 12 cups b. 2 quartz c. 2 pints d. 1 gallon
To answer this question we have to find (among the options) the amount that represents half the amount of water used.
Since the ratio of water to vinegar is 2:1, half of the amount of water will be used of vinegar.
In this case we have to find the answer that represents half a gallon.
That answer is 2 quarts. 2 guarts are 0.5 gallons, it means they are half the amount of water used.
It means that the answer is b. 2 quarts.
Plot the complex number, then write the complex number in polar form. You may express the argument in degrees.
DEFINITIONS
To represent a complex number we need to address the two components of the number.
Consider the complex number:
[tex]a+bi[/tex]Complex numbers are the points on the plane, expressed as ordered pairs (a, b), where a represents the coordinate for the horizontal axis and b represents the coordinate for the vertical axis.
Note that the imaginary part is plotted out on the vertical axis while the real part is on the horizontal axis.
QUESTION
The complex number is given to be:
[tex]4\sqrt[]{3}-4i[/tex]This means that the ordered pair representing the complex number is given to be:
[tex](a,b)=(4\sqrt[]{3},-4)[/tex]This means that the point will be positive on the real axis and negative on the imaginary axis. Therefore, the point will be in the 4th quadrant.
The correct option is OPTION B.
Use Pythagorean theorem to find right triangle side lengthsFind the value of c in the triangle shown below.682Choose 1 answer:A = 28B= 64=9= 10
EXPLANATION
Given the Right Triangle, we can apply the Pythagorean Theorem in order to get the value of x as shown as follows:
[tex]\text{Hypotenuse}^2=Short_-leg^2+Long_-leg^2[/tex]Replacing terms:
[tex]x^2=6^2+8^2[/tex][tex]x^2=36+64=100[/tex]Applying the square root to both sides:
[tex]x=\sqrt[]{100}=10[/tex]Hence, the solution is x=10
You deposit $5000 in an account earning 6% interest compounded continuously. How much will you have in the account in 5 years?
For us to determine how much the account will be in 5 years at compounded continuously, we will be using the following formula:
[tex]\text{ A = P}_0e^{rt}[/tex]Where,
P = Principal amount (Initial Value)
A = Final amount (Future Value)
r = interest rate (in decimal)
t = time (in years)
e = mathematical constant approximately 2.7183
Given:
P = $5,000
r = 6% = 6/100 = 0.06
t = 5 years
We get,
[tex]\text{ A = P}_0e^{rt}[/tex][tex]\text{ A = (5,000)(2.7183)}^{(0.06)(5)}[/tex][tex]\text{ A = (5,000)(2.7183)}^{0.3}[/tex][tex]\text{ A = (5,000)(}1.34986151469)[/tex][tex]\text{ A = }6,749.30757343\text{ }\approx\text{ \$6,749.30}[/tex]Therefore, in 5 years, at 6% compounded continuously, your account will be $6,749.30
Find the value of x to make this equation true. 6x + 1 = 6 + 2x.
6x + 1 = 6 + 2x.
collect the like term
6x - 2x = 6-1
4x = 5
divide both-side of the equation by 4
4x/4 = 5/4
x=1.25
1.25
At a college basketball game, the ratio of the number of freshmen who attended to the number of juniors who attended is 3:4. The ratio of the number of juniors who attended to the number of seniors who attended is 7:6. What is the ratio of the number of freshmen to the number of seniors who attended the basketball game?
A) 7:8
B) 3:4
C) 2:3
D) 1:2
The ratio of the number of freshmen to the number of seniors who attended the basketball game is 7 : 8.
What is the ratio?Ratio is used to show the relationship between two or more numbers. Ratio provides information on the frequency of one value within other values. The sign that is used to represent ratio is :.
The ratio of freshmen to juniors is 3 : 4.
The ratio of juniors to seniors is 7 : 6.
In order to determine the required values, let us make some assumptions.
The number of freshmen is 21
The number of juniors is 28.
Given the two above assumption, the number of seniors = (28 x 6) / 7 = 24
The ratio of freshmen to seniors = number of freshmen : number of seniors
21 : 24
Express the ratio in its simplest form - 7 : 8.
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What is the slope of a line perpendicular to the line whose equation is 3x-5y=45. Fully simplify your answer
The slope of a line perpendicular to the line whose equation is 3x-5y=45 is -5/3.
So first of all, we have to find the slope of the given line. Convert it into Slope-Intercept Form.
The Slope - Intercept Form is : y = mx + c
Converting the given equation, we get :
3x - 5y = 45
5y = 3x + 45
y = (3/5)x + 15
Perpendicular Lines
The lines having opposite reciprocal slopes are perpendicular. That means you flip the sign (+/-) and flip the numerator and denominator. The slope of the line perpendicular to this one is -5/3.
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Answer the questions below about the quadratic function.g(×)=2×^2-12×+19Does the function have a minimum or maximum? minimum or maximum what is the functions minimum or maximum value?Where does the minimum or maximum value occur?x=?
Given the function:
[tex]g(x)=2x^2-12x+19[/tex]Let's determine if the function has a minimum or maximum.
The minimum and maximum of a function are the smallest and largest value of a function in a given range or domain
The given function has a minimum.
Apply the general equation of a quadratic function:
[tex]y=ax^2+bx+c[/tex]To find the minimum value, apply the formula:
[tex]x=-\frac{b}{2a}[/tex]Where:
b = -12
a = 2
Thus, we have:
[tex]\begin{gathered} x=-\frac{-12}{2(2)} \\ \\ x=-\frac{-12}{4} \\ \\ x=3 \end{gathered}[/tex]To find the function's minimum value, find f(3).
Substitute 3 for x in the function and evaluate:
[tex]\begin{gathered} f(x)=2x^2-12x+19 \\ \\ f(3)=2(3)^2-12(3)+19 \\ \\ f(3)=2(9)-36+19 \\ \\ f(3)=18-36+19 \\ \\ f(3)=1 \end{gathered}[/tex]Therefore, the function's minimum value is 1
Therefore, the functions minimum value occurs at:
x = 3
ANSWER:
• The function has a minimum
• Minimum value: 1
• The minimum occurs at: x = 3
Find the volume of the figure. Round to the nearest hundredths place if necessary.
The volume of a Pyramid
Given a pyramid of base area A and height H, the volume is calculated as:
[tex]V=\frac{A\cdot H}{3}[/tex]The base of this pyramid is a right triangle, with a hypotenuse of c=19.3 mm and one leg of a=16.8 mm. The other leg can be calculated by using the Pythagora's Theorem:
[tex]c^2=a^2+b^2[/tex]Solving for b:
[tex]b^{}=\sqrt[]{c^2-a^2}=\sqrt[]{19.3^2-16.8^2}=9.5\operatorname{mm}[/tex]The area of the base is the semi-product of the legs:
[tex]A=\frac{16.8\cdot9.5}{2}=79.8\operatorname{mm}^2[/tex]Now the volume of the pyramid:
[tex]V=\frac{79.8\operatorname{mm}\cdot12\operatorname{mm}}{3}=319.2\operatorname{mm}^3[/tex]The volume of the figure is 319.2 cubic millimeters
which describes the solution of the inequality y>-15? a) solid vertical line through (0,-15) with shading to the left of the line. b) dashed vertical line through (0,-15) with shading to the left of line. c) solid horizontal line through (0,-15) with shaing below line. d) dashed horizontal line through (0,-15) with shaing above line.
The solution to the inequality y > - 15 is all values of y greater than -15. This means the number -15 itself is not included; therefore, the line is a dashed line that passes through (0, -15). Furthermore, the > sign implies that the shaded region is found above the dashed line. Hence, the solution to our inequality is a dashed horizontal line through (0, -15), with shading above the line.
16. Given the graph below, write the equation of the line graphed. Equation:
We have the following:
The equation has the following form
[tex]y=mx+b[/tex]where m is the slope and b is y-intercept
The slope formula is as follows
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]The point are (-4, 8) and (6, -4)
replacing:
[tex]m=\frac{-4-8}{6-(-4)}=\frac{-12}{10}=-\frac{6}{5}[/tex]In the graph we can see that the y-intercept is equal to 4, therefore, the equation would be
[tex]y=-\frac{6}{5}x+4[/tex]hello I need help answering this homework question please thank you
Solution:
Case: Area
Given: A house to be painted
Method/ Final answers
a) Find the area of the garage to be painted.
(i) Front.
A = l X w - Garage door area
l= 15 ft, b= 10-4 gives 6ft
A= 15 X 6 - (10 X 7)
A= 90 - 70
A= 20 square feet
ii) Side
A= l X w
A= 6 X 5
A= 30 square feet
iii) The sum of areas
A= 20 + 30
A= 50 square feet
b) Area of the painted region around windows 5 and 6.
Since 12 in = 1 ft
Area of front door converted to feet is (20/3) ft by 3 ft
Areas of windows 5 and 6 converted to feet is 3 ft by (5/3) ft each
A= Area of space - (Area of front door + window 5 + window 6)
A= (30 X 10) - [(20/3) X 3 + 3 X (5/3) + 3 X (5/3)]
A= 300 - [20 + 5 + 5]
A= 300 - 30
A= 270 square feet.
c) Area of the painted region around windows 3
A= Total face - Area of window 3
A= (Rectangle + Parallelogram + Triangle) - Area of window 3
A= [(10 X 4) + (5 X 4) + (0.5 X 4 X 3)] - [1 X (5/3)]
A= [40+20+6] - [5/3]
A= 66 - (5/3)
A= 193/3 square feet
A= 63.33 square feet
d) Area of the region on the second floor with 2 rectangles and the region around window 4
i) region with rectangle 1 from left to right
A= 10 X (15- 6)
A= 10 X 9
A = 90
ii) region with rectangle 2 from left to right
A= 10 X (15- 6)
A= 10 X 9
A = 90
iii) Area of region around window 4
Area of space - area of window
A= 10 X (30-9-12) - [3 X (5/2)]
A= 10 X 9 - (15/2)
A= 82.5.
Total area= 90 + 90 + 82.5
= 262.5 square feet
e) Total area of the painted region (white)
262.5 + 63.33+ 270 + 50
= 645.83 square feet.
f) Additional question
The total cost if it cost $8 per sq ft
645.83 square feet X $8 per sq ft
=$5166.64
in 3 years Donald wants to buy a bicycle that costs 600.00 if he opens a savings account that earns 4% interest compounded quarterly how much will he have to despoit as principal to have enough money in 3 years to buy the bike
We want the future value to be $600. With an interest of 4% quarterly in 3 years, we have the following information:
[tex]\begin{gathered} FV=600 \\ i=0.04 \\ t=3 \\ n=4 \end{gathered}[/tex]Then we apply the following formula:
[tex]PV=\frac{FV}{(1+\frac{i}{n})^{n\cdot t}}[/tex]therefore, we have that:
[tex]PV=\frac{600}{(1+\frac{0.04}{4})^{4\cdot3}}=\frac{600}{(1.01)^{12}}=532.46[/tex]therefore, Donald would have to deposit $532.46 as principal.
I need geometry help please.
Lets remember the property "alternative-interior angles" when we have parallels lines:
Given two paralles lines, the following is true:
In our question, we have:
We know that the angles J + P + K=180
So, the triangles have all the angles the same, so they are similar by angle-angle-angle, and they have one side congruent, AC=CD, so the triangles are congruents.