Katie invested a total of ​$4000​, part at 2​% simple interest and part at 3​% simple interest. At the end of 1​ year, the investments had earned ​$90 interest. How much was invested at each​ rate?

Answer:

is a. D.

Step-by-step explanation:

I hope you serve my answer and goodluck ^^

Solution :

Initial population, P = 752,000 .

Rate of decrease, r = 1.4 % .

Now, population decrease in 1st year :

[tex]P_1 = P( 1 - 0.014 )[/tex]

Also, population decrease in 2nd year :

[tex]P_2 = P_1( 1 -0.014 )\\\\P_2 = P( 1 - 0.014)^2[/tex]

Similarly for each next x year, population will be :

[tex]P_x = P( 1-0.014)^x[/tex]

Therefore, population after x years is given by :

[tex]P_x = 752000 ( 1-0.014)^x[/tex]

Answer: y(0.5+7)

= 0.5y+7y

7.5y

Step-by-step explanation:

Answer:

System of Equations is given as:

c = 2h - 1...... Equation 1

1.8c + 3h = 288.60....Equation 2

Step-by-step explanation:

Let us represent

The number of Cold lunch = c

The number of Hot lunch = h

The number of cold lunches the teacher bought was 1 fewer than twice the number of hot lunches the teacher bought.

Hence:

c = 2h - 1

At a school cafeteria a cold lunch costs $1.80, and a hot lunch costs $3.00. During one school year a school year a teacher spent a total of $288.60 on cold lunches and hot lunches.

Hence:

$1.80 × c + $3.00 × h = $288.60

1.8c + 3h = 288.60....Equation 2

The system of equations can be used to find c, the number of cold lunches, and h, the number of hot lunches, the teacher taught during the school year is given as:

c = 2h - 1...... Equation 1

1.8c + 3h = 288.60....Equation 2

The system of equations that can be used to calculate the number of hot and cold lunches is [tex]\mathbf{1.80c +3.00h = 288.60}[/tex] and [tex]\mathbf{c = 2h - 1}[/tex]

Let h represents hot lunch, and c represents cold lunch.

So, we have:

[tex]\mathbf{1.80c +3.00h = 288.60}[/tex]

[tex]\mathbf{c = 2h - 1}[/tex]

Substitute [tex]\mathbf{c = 2h - 1}[/tex] in [tex]\mathbf{1.80c +3.00h = 288.60}[/tex]

[tex]\mathbf{1.80(2h -1) +3.00h = 288.60}[/tex]

Expand

[tex]\mathbf{3.60h -1.80 +3.00h = 288.60}[/tex]

Collect like terms

[tex]\mathbf{3.60h +3.00h = 288.60 + 1.80}[/tex]

[tex]\mathbf{6.60h = 290.4}[/tex]

Divide both sides by 6.60

[tex]\mathbf{h = 44}[/tex]

Substitute 44 for h in [tex]\mathbf{c = 2h - 1}[/tex]

[tex]\mathbf{c = 2(44) - 1}[/tex]

[tex]\mathbf{c = 83}[/tex]

Hence, the system of equations that can be used to calculate the number of hot and cold lunches is [tex]\mathbf{1.80c +3.00h = 288.60}[/tex] and [tex]\mathbf{c = 2h - 1}[/tex]

Read more about simultaneous equations at:

https://brainly.com/question/16763389

Answer: I'm pretty sure it's the 3rd one

Step-by-step explanation:

1. 74 tens

2. 3, 7, 11

3. 4 2 5

4. 23

5. 560

6.440

7. Sum

8. 1 dollar and 40 cents

9. 84 cents

Hope this helps plz mark brainly :)

Answer:

1. 74

2. 3, 7, and 11

3. 4, 2, and 5

4. 20.2307692308

5. 560

6. 440

7. sum

8.  Chloe

9. 84 cents

Answer:

a decrease by 5/11 I beleive.

Complete question :

Carly purchased 9 1/2 pints of ice cream for a party. If each guest will be served exactly 3/5 pint of ice cream, what is the greatest number of gusts that Carly can serve

Answer:

15 guests

Step-by-step explanation:

Given that:

Total pints of icecream = 9 1/2

Fraction of ice cream pints per guest = 3/5 pints

Number of guest that can be served :

Total pints / fraction per guest

9 1/2 ÷ 3/5

19/2 * 5/3

95 / 6

= 15.8 guest

Hence, greatest Number of guest that can be served = 15

Answer:

answer of XnY where Y is an even no and X is a whole number less than 10 is

A {0,2,4,6,8}

Answer:

Step-by-step explanation:

Answer:

a.)2 b.)6

Step-by-step explanation:

a.) solve 7x+4=18 because EC bisects making FEC = CEG

b.) solve 12y+18=90 because AED is 90 degrees

[tex]( {n}^{2} - 6n) + 6 = - 2[/tex]

[tex]( {n}^{2} - 6n + 9) + 6 - 9 = - 2 \\ {(n - 3)}^{2} - 3 = - 2 \\ {(n - 3)}^{2} = 1[/tex]

[tex] \sqrt{ {(n - 3)}^{2} } = + \sqrt{1} \\ \sqrt{ {(n - 3)}^{2} } = - \sqrt{1} \\ n - 3 = 1 \\ n - 3 = - 1[/tex]

[tex]n - 3 = 1 \: \: \: or \: \: \: n - 3 = - 1 \\ n = 1 + 3 \: \: \: or \: \: \: n = - 1 + 3 \\ n = 4 \: \: \: or \: \: \: n = 2[/tex]

[tex] \large \boxed {n = 4,2}[/tex]

Answer:

$272

Step-by-step explanation:

We're going to make an equation

we'll make x hours

5x=80

solve for x and you get 16 dollars an hour

16 times 17 is 272

Answer:

I don't drive r8s I don't like those I drive a Daytona and I tinted the windows

Answer:

c

Step-by-step explanation:

Answer: it would be 24.8ft

Answer:

-8

Step-by-step explanation:

substitute x with 3

-4(3) + 4

simplify (multiply)

-12+4

simplify

-8

Answer:

g(3) =  -8

Step-by-step explanation:

g(3) = -4x + 4 Substitute 3 for X:

g(3) =  -4(3) + 4

-4 * 3 = -12

g(3) = -12+4

g(3) =  -8

Answer:10

Step-by-s First of all, note that 15 is the same as 15/1 since 15 divided by 1 is 15. Therefore, start by setting up the problem like this

Step 2: Multiply

Multiply the numerators together (15 x 2 = 30) and multiply the denominators together (1 x 3 = 3) and make it into one fraction like so:

Step 3: Minimize

The greatest common factor of 30 and 3 is 3. Minimize the fraction by dividing the numerator and the denominator by its greatest common factor to get:

Step 4: Convert

Convert the improper fraction above to a whole number to get the answer:

That's it! Now you know how to calculate 15 times 2/3.

Answer:

c

Step-by-step explanation:

Answer:

Step-by-step explanation:

Domain has all values of x ( think X marks the spot on your domain) so the restrictions come in those cases from the fact that a fraction can NOT have the denominator 0 because dividing by 0 is not allowed.

5.

here x+1 [tex]\neq[/tex] 0 and x+3 [tex]\neq[/tex] 0 so the domain restrictions are x [tex]\neq[/tex] -1 and x[tex]\neq[/tex] -3

to solve you need to factor x^2 -6x-27

you can do it by using  

x^2 - Sx +P = 0 where S= root 1 +root 2 and P = root 1*root2

so in our case Sum has to be 6 and Product -27, what 2 numbers add to 6 and their product is -27? ....-3 and 9; S= -3+9 = 6 and P= -3*9 = -27

it will factor in (x-root 1) (x-root 2)  

x^2 -6x-27 = (x+3)(x-9)

[tex]\frac{(x+3)(x-9)}{x+1} * \frac{x+1}{x+3} =\\[/tex]

simplify x+1 and x+3

x-9

Answer:

1) E and F

Step-by-step explanation:

So width is x

legth Is 3x+3

Perimeter is

3x+3+3x+3+x+x

Now simplify

8x+6

Now go through each choice that equals 8x+6

Only e and f

Answer:

47C + 9

Step-by-step explanation:

arrange the like terms so you can combine them (5c + 42c) (-3 + 12)

Answer: -3 + 47C +12

Step-by-step explanation:

Answer:

ASA angle side angle

Step-by-step explanation:

DE=JH(given)

angle E= angle H (given)

angle D=angle J (given)

Answer:

-1n + 1 = 11

subtract 1 both sides

-1n = 10

-n = 10

n= -10

Step-by-step explanation:

Answer:

It is C

Step-by-step explanation:

Answer:

d. -4 <= x - 5

Step-by-step explanation:

I think youre asking about question 5.

First replace the x with the -2 in every problem.

Now solve:

a. 6 × -2 < 10

6 times -2 is -12, and -12 is less than -10, so that ones true and not the answer

b. -2 × -2 > -3

-2 times -2 is 4, and 4 is greater than -3, so that ones true and not the answer

c. -2/4 <= 0

-2 divided by 4 is -1/2, and -1/2 is less than 0. so that ones true and not the answer

So obviously the answers d, but we're gonna check anyway

d. -4 <= -2 - 5

-2 minus 5 is -7, and -7 is not less than -4, so its not true and the answer

Answer:

1. renegade

2. tap in

3. blinding lights

4. say so

5. wap

6. what you know about love

7. savage love

8. party girl

9. all about cake

10. go daddy go,

[tex]\tt{PQ=TS }[/tex]

[tex]\tt{ PW=TW }[/tex]

[tex]\tt{ QW=SW }[/tex]

SO,

it is S-S-S

side-side-side

Answer:

$76.51

Step-by-step explanation:

I found how much the calculator cost on clearance first. Then I found the sales tax and added them together.

Answer:

Step-by-step explanation:

We start at (-7, 7).  A translation of 1 unit to the right results in (-6, 7).  A translation down from there results in (-6, 4).  This is the desired image point.