Jessica’s credit card is on a 30-day billing cycle, and it computes finance charges using the adjusted balance method. the following table details jessica’s use of her credit card in the month of october. date amount ($) transaction 10/1 1,240.55 beginning balance 10/2 36.43 purchase 10/10 75.00 payment 10/13 131.79 payment 10/20 41.52 purchase 10/22 25.00 purchase what is jessica’s adjusted balance for october? a. $1,136.71 b. $1,033.76 c. $1,140.55 d. $1,240.55

Answer:

Step-by-step explanation:

draw a market and place the point (4 ; 1)

then you go on your right : 4 units

and go down : 3 units

you place a second point

and now you can graph the line

Answer:

89.97

Step-by-step explanation:

5.99+79.99 = 85.98 + 3.99  = 89.97

#1

Area:-

#2

Area:-

#3

Area of the white part=Area of circle-Area of square

#4

Probability

#5

Probability

Answer:

1. 63.62 in².

2. 16 in².

3. 47.62 in².

4. 0.25 .

5. 0.74 .

Step-by-step explanation:

1.

Solution,

Given,

Diameter = 9 inch.

Now,

Area = πr²

Diameter = r²

Then,

Area = 1/4 πd²

= 1/4 π9²

= 63.62 in².

2.

Solution,

Given,

Length of a Side = 4 inch.

Now,

Area = L²

= 4²

= 16 in².

3.

Solution,

Given,

Area of the Circle = 63.62 in².

Area of the Square = 16 in².

Now,

Area of The White Part of the Circle = Area of Circle - Area of Square

= 63.62 in² - 16 in².

= 47.62 in².

4.

Solution,

Given,

Area of the Square = 16 in².

Area of the Circle = 63.62 in².

Now,

The probability of landing in the Square = Square Area / Circle Area

= 16 / 63.62

= 0.25 .

5.

Solution,

Given,

White Part of the Circle = 47.62 in².

Area of the Circle = 63.62 in².

Now,

The probability of landing in the white Part = White Area / Circle Area.

= 47.62 / 63.62

= 0.74 .

Answer:

14%

Step-by-step explanation:

lets whip out that EPIC CALCULATOR! alright so i hope that you have your calculator with you, whether it is a physical one or a digital one on your computer.

try this:

enter 14, then the division sign ( could be a ÷ or an / ) and then 100.

what do we get?

0.14

ok, now lets multiply this by 100 to get the PERCENT instead of the DECIMAL, and we get
14%

EPIC!

Answer

2199

Step-by-step explanation:

the perimeter of the circle:

3.14 x 175 x 2= 1099

there are 2 inches in one foot

1099x12 = 13188

13188/6 inches = 2198

2198+1=2199 flowers

Answer:

  (c)  The two quantities are equal.

Step-by-step explanation:

The sine of an angle is equal to the cosine of its complement. In a right triangle, the acute angles are complementary, which means ...

  sin(A) = cos(B)

The two quantities are equal.

Answer:

Step-by-step explanation:

Sin(A) = opposite / hypotenuse

opposite = 4

hypotenuse = 5

Sin(A) = 4/5 = 0.8

Cos(B) = adjacent / hypotenuse.

adjacent = 4

hypotenuse = 5

Cos(B) = 4/5 = 0.8

Believe it or not, this will always happen if you take Sin(A) and find that Cos(90 - A) are equal

Take a simpler case. Suppose you are working with a 30 60 90 triangle.

Cos(60) = Sin(90 - 60) = 1/2

Answer:

box 1 = 6,080

box 2 = 6,169

box 3 = 18,219

box 4 = 19,151

Step-by-step explanation:

Answer:

Simple, Just divide 15.00 by 3.58 to get the answer of 4.19

Step-by-step explanation:

15.00 ÷ 3.58 = 4.19

Answer:

  AA similarity postulate

Step-by-step explanation:

Triangles are similar if corresponding angles are congruent or if corresponding sides are proportional.

Here, the missing reason in the proof follows a step in which two angles are shown congruent. That means you can claim similarity by the AA similarity postulate.

__

Additional comment

The similarity postulates include ...

  AA -- two corresponding angles (the third angle is determined by these two)

  SSS -- three proportional corresponding sides

  AAS -- two congruent angles and a proportional corresponding side

  ASA -- a variation of AAS

  SAS -- proportional corresponding sides flanking a congruent angle

With the exception of AA, these are the same postulates as used to prove triangle congruence when the corresponding sides are congruent, rather than proportional.

Answer: High quality services cause customers to return for additional meals.

Step-by-step explanation:  The 90% crosses out the first option. Because it's 90% we don't know if all the customers reported their service. The last one just to me wouldn't make sense.

Answer:

  17.34 years

Step-by-step explanation:

The equation you wrote in the first part of the problem can be solved for the value of t that makes the population be 5000.

  [tex]P(t)=\dfrac{10000}{1+11.5e^{-0.1408614477t}}[/tex]

Setting this equal to 5000 and multiplying by the denominator, we have ...

  [tex]5000=\dfrac{10000}{1+11.5e^{-0.1408614477t}}\\\\5000+57500e^{-0.1408614477t}=10000\\\\e^{-0.1408614477t}=\dfrac{5000}{57500}\qquad\text{subtract 5000, divide by 57500}\\\\-0.1408614477t = \ln{\dfrac{1}{11.5}}=-\ln(11.5)\qquad\text{take logs}\\\\t=\dfrac{\ln(11.5)}{0.1408614477}\approx17.3386[/tex]

For the population to reach 5000, it will take about 17.34 years.

_____

Additional comment

The value -0.14086... is the natural log of the ratio 1818/2093. This means the "exact answer" is ln(11.5)/(ln(2093) -ln(1818)), an irrational number.

A graphing calculator can answer the question easily.

fractional number equivalent of 2.888 is

Answer:

[tex]\frac{26}{9}[/tex] or [tex]2 \frac{8}{9}[/tex]

Step-by-step explanation:

Let x equal the decimal. Set up two equations such that the digits after the decimal point are identical.

10x = 28.8888...

x = 2.8888...

Subtracting the two equations, we have:

9x = 26

Answer:

First of all multiply 5 in three times

graphed below:

[tex]\sf f(x)=3x^2-6x+5[/tex]

Answer:

Given function:    [tex]f(x)=3x^2-6x+5[/tex]

Vertex form:  [tex]y=a(x-h)^2+k[/tex]  

(where [tex](h, k)[/tex] is the vertex)

Expand vertex form:

[tex]y=ax^2-2ahx+ah^2+k[/tex]

Compare coefficients of given function with expanded vertex form

Comparing coefficient of [tex]x^2[/tex]:

[tex]3=a[/tex]

Comparing coefficient of [tex]x[/tex]:

[tex]\ \ \ \ \ -6=-2ah\\\implies-6=-2 \cdot 3h\\\implies -6=-6h\\\implies h=1[/tex]

Comparing  constant:

[tex]\ \ \ \ \ \ 5=ah^2+k\\\implies5=3(1)^2+k \\\implies 5=3+k\\\implies k=2[/tex]

Therefore, the vertex is (1, 2)

As the leading coefficient is positive, the parabola will open upwards.

Additional plot points:

[tex]f(0)=3(0)^2-6(0)+5=5[/tex]

[tex]f(2)=3(2)^2-6(2)+5=5[/tex]

(0, 5) and (2, 5)

Answer:

r≈12mi

Step-by-step explanation:

mark brainiest and Im 100% correct

The square miles that was burned if one square mile is 640 acres is 840.625 square miles.

Division is the process of grouping a number into equal parts using another number. The sign used to denote division is ÷. Division is one of the basic mathematical operations.

Square miles that was burned = 538,000 / 640 = 840.625 square miles

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There are 840.625 square miles did the fire burn.

Division is the process of sharing a collection of items into equal parts and is one of the basic arithmetic operations in maths.

The wallow fire of 2011 burned 538,000 acres in eastern Arizona.

The area of square miles did the fire burned is;

[tex]\rm Area =\dfrac{538,000}{640}\\\\Area =840.625 \ square \ miles[/tex]

Hence, there are 840.625 square miles did the fire burn.

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Answer:

I don't know I'm trying my best and I'm late

Step-by-step explanation:

Answer: 3/2

Step-by-step explanation:

Let's consider the points (6,9) and (4,6).

The difference in the y coordinates is 3, and the diffeence in the x coordinates is 2.

So, the slope is 3/2.

Answer:

(a)

Step-by-step explanation:

the equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

x² + y² = 20 ← is in this form , then

centre = (0, 0 ) and r = [tex]\sqrt{20}[/tex] = [tex]\sqrt{4(5)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{5}[/tex] = 2[tex]\sqrt{5}[/tex]

[tex]tan(\theta )=\sqrt{3}\implies tan(\theta )=\cfrac{\sqrt{3}}{1}\implies tan(\theta )=\cfrac{\sqrt{3}}{1}\cdot \cfrac{2}{2} \implies tan(\theta )=\cfrac{\sqrt{3}}{2}\cdot \cfrac{2}{1} \\\\\\ tan(\theta )=\cfrac{~~\stackrel{sin(\theta )}{\frac{\sqrt{3}}{2}} ~~}{\underset{cos(\theta )}{\frac{1}{2}}}\implies \theta =tan^{-1}\left( \cfrac{~~\frac{\sqrt{3}}{2} ~~}{\frac{1}{2}} \right)\implies \theta = \begin{cases} \stackrel{I~Quadrant}{60^o}\\\\ \stackrel{III~Quadrant}{240^o} \end{cases}[/tex]

Check the picture below.

The solution to the problem expressed  2358.

Significant figure It is defined as the minimum number of digit us needed to express a number in scientific notation.

Therefore we get,

[tex]15.11+(142\times16.5)[/tex]

First we have to multiply the given digits as per rule.

[tex]=15.11+2343[/tex]

Now we will add both the digits, we get

[tex]=2358.11[/tex]

As per given expression, we conclude that the number of significant figure is 4.

So, the answer will be, 2358.

Therefore, the correct option is, 2358.

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From calculations, the given integral ∫c x sin(y)ds is equal to [tex]20\left(-\frac{1}{3}\cos \left(4\right)+\frac{1}{9}\sin \left(4\right)-\frac{1}{9}\sin \left(1\right)\right)=0.806[/tex].

The integrals are the opposite of derivatives. They are used in several applications, like: calculations of areas, volumes and others.

For solving an integration, you should know its rules. For this question will be necessary to apply the following integration rules:

First, you should calculate the segment from the points (0, 1) and (4, 4).

segment=(4-0,4-1)=(4,3).

After that you should parametrize the segment:

r(t)=(0,1)+(4t,3t)= (4t,3t+1), where 0≤t≤1

Now, you can find dr/dt.

r'(t)=(4,3)

Consequently, the magnitude of |r'(t)| will be:

|r'(t)|  =[tex]\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25} =5[/tex]

Finally you can evaluate the integral: ∫c x sin(y)ds. From r(t), you know that x=4t and y=3t+1.

[tex]\int _0^1\:xsin\left(y\right)\:ds=\int _0^1\:4t\cdot sin\left(3t+1\right)\:\cdot 5ds=\int _0^1\:20t\cdot sin\left(3t+1\right)\:\cdot ds[/tex]

Applying the Rule Integration for a Constant.

[tex]\int _0^1\:20t\cdot sin\left(3t+1\right)\:\cdot dt\\ \\ 20\cdot \int _0^1t\sin \left(3t+1\right)dt\\ \\[/tex]

Applying the Rule Integration by Parts.

∫u v dx = uv -∫v du

u=t

dv= sin(3t +1 )dt, then v=

[tex]=20\left[-\frac{1}{3}t\cos \left(3t+1\right)-\int \:-\frac{1}{3}\cos \left(3t+1\right)dt\right]^1_0\\ \\=20\left[-\frac{1}{3}t\cos \left(3t+1\right)+\frac{1}{9}\sin \left(3t+1\right)\right]^1_0\\ \\ =20\left(-\frac{1}{3}\cos \left(4\right)+\frac{1}{9}\sin \left(4\right)-\frac{1}{9}\sin \left(1\right)\right)\\ \\ =0.806[/tex]

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The value of the integral  ∫c x sin(y)ds where c is the curve is 0.806 if the line segment is from (0,1) to (4,4).

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

First, we have to calculate line segment (0,1 ) to (4, 4)

= (4-0, 4-1) = (4, 3)

Parametric form of the segment:

P(t) = (0+4t, 3t)   where 0 ≤ t ≤ 1

Now differentiate the segment:

P'(t) = (4, 3)

The magnitude of the P'(t)

[tex]\rm P'(t) = \sqrt{4^2+3^2}[/tex]

P'(t)  = 5

Now the integration can be evaluated from the P(t)

[tex]\rm \int\limits^1_0 {xsin(y)} \, ds = \int\limits^1_0 {4tsin(3t+1)} \, 5ds[/tex]    ( x= 4t, y = 3t+1)

[tex]\rm \int\limits^1_0 {xsin(y)} \, ds = 20\int\limits^1_0 {tsin(3t+1)} \, ds[/tex]

The value of the integration:

[tex]\rm \int \limits^1_0 {tsin(3t+1)} \, ds = 0.040[/tex]

[tex]\rm \int\limits^1_0 {xsin(y)} \, ds = 20(0.04)[/tex]

[tex]\rm \int\limits^1_0 {xsin(y)} \, ds =0.806[/tex]

Thus, the value of the integral  ∫c x sin(y)ds where c is the curve is 0.806 if the line segment is from (0,1) to (4,4).

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Answer:

[tex]403.06 cm^2; 100.77cm^2[/tex]

Step-by-step explanation:

Ok, step 1. What's the measure of the internal angle of a dodecagon? After some splitting in triangles you get that's [tex](n-2)\pi = 10\pi[/tex]. That makes each angle measure [tex]\frac{10}{12}\pi[/tex].

That allows us to split the whole figure in 12 isosceles triangles with (congruent) angles of [tex]\frac5{12}\pi[/tex]. Consider just one, red in my picture. The height of that triangle - orange "vertical" line -  can be found with some trigonometry as [tex]3tan \frac5{12}\pi \approx 11.2 cm[/tex]

At this point one triangle has area [tex]\frac12 \cdot 6\cdot 11.2 = 33.6 cm^2[/tex] and the whole cookie has area as 12 triangles [tex]403.06 cm^2[/tex].

After her eating spree, you're left with 3 triangles, for a grand total of [tex]100.77 cm^2[/tex]

I'll do the first two questions of each activity to get you started. The remaining unanswered questions will follow similar steps compared to the other questions in the same activity group.

=======================================================

Activity 5, Problem 1

To find the mean, we first add up the values

4+8+2+8+5+9 = 36

Then we divide over n = 6 because there are 6 values in this data set.

36/n = 36/6 = 6

=======================================================

Activity 5, Problem 2

Follow the same idea as the previous problem.

Add the values:  9+8+8+13+12 = 50

Divide by the number of values: 50/n = 50/5 = 10

=======================================================

Activity 6, Problem 1

The median is the middle-most number. Think of a median of a highway or freeway.

In order to find the median, we first need to sort the data values from smallest to largest.

The original set {7,3,9,9,2,5,8} sorts to {2, 3, 5, 7, 8, 9, 9}

If we erased the first and last items, we get this smaller subset

{3, 5, 7, 8, 9}

repeat again to get

{5,7,8}

At this point its clear the middle most value is 7

But if you wanted, you could cross the first and last values from the list to end up with {7}

=======================================================

Activity 6, Problem 2

We could do the same trick as the previous problem, but I'll use a slightly different route this time.

We'll need to sort {10,8,4,11,9} into {4, 8, 9, 10, 11}

There are n = 5 items in that set. The middle slot would be at slot n/2 = 5/2 = 2.5 = 3

The value 9 is in slot 3 of the sorted items.

=======================================================

Activity 7, Problem 1

The mode is the most frequent value of a set. It repeats the most often.

The set {5,6,7,3,5,4} sorts to {3,4,5,5,6,7}

The value "5" shows up the most. It shows up twice when everything else shows up exactly once only.

=======================================================

Activity 7, Problem 2

Using the same idea in the previous problem, the set {7,4,11,9,7,3} has the mode 7 because it shows up the most of any other value.

Here's the sorted set: {3,4,7,7,9,11}

Sorting is optional with finding the mode in contrast to being mandatory when it comes to finding the median.

Answer:

As Per Provided Information

A cylinder has a volume of 320 pi cubic inches and a height of 5 inches.

We have been asked to determine the radius of the cylinder .

Using Formulae

[tex] \purple{\boxed {\bf\: Volume_{(Cylinder)} = \pi {r}^{2}h}}[/tex]

Substituting the value and let's solve for radius .

[tex] \sf \qquad \longrightarrow \: 320 \pi \: = \pi \: \times r {}^{2} \: \times 5 \\ \\ \\ \sf \qquad \longrightarrow \:320 \cancel{\pi} = \cancel{ \pi} \times r {}^{2} \: \times 5 \\ \\ \\ \sf \qquad \longrightarrow \:320 = r {}^{2} \: \times 5 \\ \\ \\ \sf \qquad \longrightarrow \:r {}^{2} \: = \cfrac{320}{5} \\ \\ \\ \sf \qquad \longrightarrow \: {r}^{2} = \cancel\cfrac{320}{5} \\ \\ \\ \sf \qquad \longrightarrow \: {r}^{2} = 64 \\ \\ \\ \sf \qquad \longrightarrow \:r \: = \sqrt{64} \\ \\ \\ \sf \qquad \longrightarrow \:r \: = 8 \: inch[/tex]

Therefore,

This [tex]\rm P(Z\geq 1.7)[/tex]  is equivalent to  [tex]\rm 1-P(Z\leq 1.7)[/tex]

It is given that the  [tex]\rm P(Z\geq 1.7)[/tex]

It is required to find which statement is equivalent to [tex]\rm P(Z\geq 1.7)[/tex]

The statements are:

[tex]a) \ \rm P(Z\geq -1.7)\\b) \ \rm 1-P(Z\geq -1.7)\\c) \ \rm P(Z\leq 1.7)\\d) \ \rm 1-P(Z\leq 1.7)[/tex]

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

We have the [tex]\rm P(Z\geq 1.7)[/tex]

We know that:

[tex]\rm P(Z\leq a)=P(Z\geq -a)\\\rm P(Z\geq a)=P(Z\leq -a)[/tex]

If we compare statement (a) and statement (c), we will see these options are not equivalent to  [tex]\rm P(Z\geq 1.7)[/tex]

For statement (b) if we plot the graph for the given statement we will get the negative area of the bell curve hence it is also incorrect.

For statement (d) if we plot the graph for the given statement we will get the positive area which is equivalent to the [tex]\rm P(Z\geq 1.7)[/tex]

Thus, the [tex]\rm P(Z\geq 1.7)[/tex]  is equivalent to  [tex]\rm 1-P(Z\leq 1.7)[/tex]

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