The amount compounded is given by the formula ;
[tex]A=P\lbrack1+\frac{r}{100n}\rbrack^{nt}[/tex]Here, P = $3500, r = 1.75%, n = 52 , t = 18 years.
[tex]\begin{gathered} A=3500\lbrack1+\frac{1.75}{100\times52}\rbrack^{52\times18} \\ A=4795.65 \end{gathered}[/tex]Therefore, the interest the account will earn is 4795.65-3500 = $1295.65, Option A
Simplify this equation −(4x−4)+4x−4
The equation -(4x - 4) + 4x - 4 is simplified as: -8.
How to Simplify an Equation?An equation can be simplified using the necessary properties of equalities where possible to give an expression that is simplified compared to the original equation.
Given the equation, -(4x - 4) + 4x - 4, to simplify, start by applying the distributive property of equality to open the parentheses:
-(4x - 4) + 4x - 4 = -(4x) -(+4) + 4x - 4 [distribution property of equality]
-(4x - 4) + 4x - 4 = -4x - 4 + 4x - 4
Combine like terms
-(4x - 4) + 4x - 4 = -4x + 4x - 4 - 4
Simplify the equation
-(4x - 4) + 4x - 4 = 0 - 8
= -8
Therefore, -(4x - 4) + 4x - 4 = -8.
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I have tried multiple times but still could not get the correct answer or at least accurate answers
Given:
R is the midpoint of QS.
[tex]RS=5\text{,RT}=13[/tex]The midpoint is the point on a line segment equally distant from the two endpoints.
It gives,
[tex]\begin{gathered} QR=RS\ldots\ldots\text{. R is midpoint of QS} \\ \Rightarrow QR=5 \end{gathered}[/tex]Also,
[tex]\begin{gathered} RS+ST=RT \\ 5+ST=13 \\ ST=13-5 \\ ST=8 \end{gathered}[/tex]So, QT is calculated as,
[tex]\begin{gathered} QT=QR+RE+ST \\ QT=5+5+8=18 \end{gathered}[/tex]Answer: QT = 18
Write an equation in the form r(x) = p(x) / q(x) for each function shown below.Pls see pic for details
c.
The line equation is of the form
[tex]y=mx+c\ldots(1)[/tex]From the graph, we observe and find these points
(1,5) and (0,4) lie on the given line.
Substituting x=1, y=5 in equation (1), we get
[tex]5=m(1)+c[/tex][tex]m+c=5\ldots\text{.}(2)[/tex]Substituting x=0, y=4 in equation (1), we get
[tex]4=m(0)+c[/tex][tex]c=4[/tex]Substituting c=4 in equation (2), we get
[tex]m+4=5[/tex][tex]m=5-4[/tex][tex]m=1[/tex]Substituting c=4,m=1 in equation (1), we get
[tex]y=x+5[/tex]We need to write this equation in the form of r(x) = p(x) / q(x).
[tex]r(x)=\frac{p(x)}{q(x)}\ldots(3)[/tex]Let r(x)=x+5, q(x)=x, and subsitute in the equation , we get
[tex]x+5=\frac{p(x)}{x}[/tex]Using the cross-product method, we get
[tex]x(x+5)=p(x)[/tex][tex]x\times x+x\times5=p(x)[/tex][tex]x^2+5x=p(x)[/tex]Substitute values in equation (3), we get
[tex]x+5=\frac{x^2+5x}{x}[/tex]Hence the required equation is
[tex]x+5=\frac{x^2+5x}{x}[/tex]A random sample of 41 people is taken. What is the probability that the main IQ score of people in the sample is less than 99? Round your answer to four decimal places if necessary(See picture )
Solution:
Given:
[tex]\begin{gathered} \mu=100 \\ \sigma=15 \\ n=41 \\ x=99 \end{gathered}[/tex]From the Z-scores formula;
[tex]\begin{gathered} Z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}} \\ Z=\frac{99-100}{\frac{15}{\sqrt{41}}} \\ Z=-0.42687494916 \\ Z\approx-0.4269 \end{gathered}[/tex]From Z-scores table, the probability that the mean IQ score of people in the sample is less than 99 is;
[tex]\begin{gathered} P(xTherefore, to 4 decimal places, the probability that the mean IQ score of people in the sample is less than 99 is 0.3347
1) find the value of AC
2) find the measure of
1) The value of AC = 116
2) The measure of ∠BEF = 53°
What is Bisector?
When anything is divided into two equal or congruent portions, usually by a line, it is said to have been bisected in geometry. The line is then referred to as the bisector. Segment bisectors and angle bisectors are the sorts of bisectors that are most frequently taken into consideration.
Given,
BD is a perpendicular bisector
A is an angle bisector
BD is a perpendicular bisector then AD = DC
2n + 18 = 4n - 22
4n - 2n = 18 + 22
2n = 40
n = 40/2
n = 20
AD = 2(20) + 18
= 40 + 18
AD = 58
Now,
1) Length of AC
AC = 2AD
Here, AD = 58
AC = 2(58)
AC = 116
Hence, The value of AC is 116
2) A is an angle bisector
∠BAE = ∠DAE = 37°
∠DAE = 37°
Δ ADE is a right angle triangle
∠DEA = 90 - ∠DAE
= 90 - 37
= 53°
Since, ∠DEA = ∠BEF
∠BEF = 53°
Hence, The measure of ∠BEF = 53°
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A rectangular board is 1200 millimeters long and 900 millimeters wide what is the area of the board in square meters? do not round your answer
Answer: Area of the rectangular board is 1.08 square meters
The length of the rectangular board = 1200 milimeters
The width of the rectangular board = 900 milimeters
Area of a rectangle = Length x width
Firstly, we need to convert the milimeter to meters
1000mm = 1m
1200mm = xm
Cross multiply
x * 1000 = 1200 x 1
1000x = 1200
Divide both sides by 1000
x = 1200/100
x = 1.2 meters
For the width
1000mm = 1m
900mm = xm
cross multiply
1000 * x = 900 * 1
1000x = 900
Divide both sides by 1000
x = 900/1000
x = 0.9m
Length = 1.2 meters
Width = 0.9 meter
Area = length x width
Area = 1.2 x 0.9
Area = 1.08 square meters
In mid-2019, Coca-Cola Company had a share price of $39. Its dividend was $1.00 per year, and you expect Coca-Cola to raise this dividend by approximately 7% per year in perpetuity. If Coca-Cola’s equity cost of capital is 8%, what share price would you expect based on your estimate of the dividend growth rate?
The share price I would expect based on the estimate of the dividend growth rate is $10.70.
What is the share price?In order to determine the share price, the constant growth dividend model would be used. According to the model, the share price is a function of the cost of equity, dividend paid and growth rate.
Share price = next dividend / (cost of equity - growth rate)
Next dividend = current dividend x (1 + growth rate)
$1 x (1 + 0.07)
$1 x 1.07 = $1.07
Share price = $1,07 / (0.08 - 0.07)
$1.07 / 0.01 = $10.70
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I need help solving this and figuring out the plotting points.
SOLUTION
It is gien that the monthly salary is $2200
It is given that Keren receives additional $80 for every copy of English is fun she sells.
Let the number of English is fun she sells be n and let the total amount earned in the month be s
Thus the equation representing the total amount earned is:
[tex]s=2200+8n[/tex]The graph of the equation is shown:
Which of these tables doesn't show a proportional relationship? MY 2 B 4 12. 18 X 1 2 2 4 3 6 X Y 0 - 2 1 에 1 2 4 X Y 0 0 1 1 2 2
Answer:
The third table.
Explanation:
In a proportional relationship, the and y values are in a constant ratio.
Which expression simplifies to 5. A. 27/3 - 14. B. 27/3+4. C. -27/3-4. D. -27/3+14
Which of the following functions is graphed below?
So, y is a system two distinct exponential functions.
The function on the bottom is a cubic function with a y-intercept of -3, and the full dot means that point is included in the domain.
y = x^3 - 3, x ≤ 2
The other function is a quadratic function with a currently unknown y-intercept. The hollow dot on point 2 means that the point is not included in the domain of the function.
y = x^2 + b, x > 2
So, given that there is only one option that matches this, even with the unknown b value, we know:
[tex]y = \left \{ {{x^3 - 3, x\leq 2} \atop {x^2 + 6, x > 2}} \right.[/tex]
So the answer is C.
Special right trianglesFind the exact values of the side lengths c and a
Since it is a right triangle, we can use the trigonometric ratio cos(θ) to find the length c.
[tex]\cos(\theta)=\frac{\text{ Adjacent side}}{\text{ Hypotenuse}}[/tex]So, we have:
[tex]\begin{gathered} \cos(\theta)=\frac{\text{ Adjacent side}}{\text{ Hypotenuse}} \\ \cos(45°)=\frac{c}{7} \\ \text{ Multiply by 7 from both sides} \\ \cos(45\degree)\cdot7=\frac{c}{7}\cdot7 \\ 7\cos(45\degree)=c \\ \frac{7\sqrt{2}}{2}=c \end{gathered}[/tex]Second triangleSince it is a right triangle, we can use the trigonometric ratio cos(θ) to find the length a.
So, we have:
[tex]\begin{gathered} \cos(\theta)=\frac{\text{ Adjacent side}}{\text{ Hypotenuse}} \\ \cos(60°)=\frac{a}{2} \\ \text{ Multiply by 2 from both sides} \\ \cos(60°)\cdot2=\frac{a}{2}\cdot2 \\ 2\cos(60\degree)=a \\ 2\cdot\frac{1}{2}=a \\ 1=a \end{gathered}[/tex]Answer[tex]\begin{gathered} c=\frac{7\sqrt{2}}{2} \\ a=1 \end{gathered}[/tex]What is the slope of the line below? If necessary, enter your answer as afraction in lowest terms, using the slash (/) as the fraction bar. Do not enteryour answer as a decimal number or an equation.
To find the slope of a line use two points (x,y) in the next formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In the given line you have the points: (-4, -9) and (-2, -3)
[tex]m=\frac{-3-(-9)}{-2-(-4)}=\frac{-3+9}{-2+4}=\frac{6}{2}=3[/tex]Then, the slope of the given line is 3Miguel Valdez sells appliances. He is paid an 8% commission on the first $5,000 worth of sales, 10% on the next $5,500, and 15% on all sales over $10,500. What is his commission on $14,910 worth of sales?
Total Sales = 14910
8% on 5000
10% on 5500
15% on
14910 - 10500 = 4410
So,
15% on 4410 [this is the excess of 10,500]
Converting percentages to decimal:
8% = 8/100 = 0.08
10% = 10/100 = 0.1
15% = 15/100 = 0.15
Total Commission
[tex]0.08(5000)+0.1(5500)+0.15(4410)=1611.5[/tex]$1611.50Write this algebraic expression into a verbal expression: 1/3 ( h - 1 )
Answer:
One-third of the difference of h and 1
42. If a pipe can drain a tank in t hours, what part of the tank does foes it drain in 3 hours? A. 3t B. t/3C. t + 3D. 3/t
Let us assume that the volume of a full tank is 1
If the tank can drain the full tank in t hours, it means that
1 = t
Let x represent the volume of the tank that would be drained in 3 hours. It means that
x = 3
We would solve both equations for x
1 = t
x = 3
By crossmultiplying,
xt = 3
x = 3/t
Thus, the correct option is D
If f(x) = sin(x ^ 5) , find f^ prime (x)
Solution
Step 1
Write the function.
[tex]f(x)\text{ = sin\lparen x}^5)[/tex]Step 2
Use the chain rule to find f'(x)
[tex]\begin{gathered} f^{\prime}(x)\text{ = }\frac{df}{du}\times\frac{du}{dx} \\ \\ u\text{ = x}^5 \\ \\ \frac{du}{dx}\text{ = 5x}^4 \\ f(x)\text{ = sinu} \\ \\ \frac{df}{du}\text{ = cosu} \end{gathered}[/tex]Step 3
[tex]\begin{gathered} f^{\prime}(x)\text{ = 5x}^4\text{ }\times\text{ cosu} \\ \\ f^{\prime}(x)\text{ = 5x}^4cos(x^5) \end{gathered}[/tex]Step 4
Substitute x = 4 to find f'(4).
[tex]\begin{gathered} f^{\prime}(4)\text{ = 5}\times4^4\times cos(4^5) \\ \\ f^{\prime}(4)=\text{ 1280}\times cos1024 \\ \\ f^{\prime}(x)\text{ = 715.8} \end{gathered}[/tex]Final answer
In terms of trigonometry ratios for triangle BCE what is the length of line CE. Insert text on the triangle to show the length of line CE.When you are done using the formula for the triangle area Area equals 1/2 times base times height write an expression for the area of triangle ABC Base your answer on the work you did above
CE can be written as:
[tex]\frac{BE}{CE}=\frac{CE}{AE}[/tex]Solve for CE:
[tex]\begin{gathered} CE^2=BE\cdot AE \\ CE=\sqrt[]{BE\cdot AE} \end{gathered}[/tex]The area is:
[tex]\begin{gathered} A=\frac{b\cdot h}{2} \\ _{\text{ }}where\colon \\ _{\text{ }}b=AB \\ h=CE=\sqrt[]{BE\cdot AE} \\ so\colon \\ A=\frac{AB\cdot\sqrt[]{BE\cdot AE}}{2} \end{gathered}[/tex]p(x) = x + 4; Find p(2) evaluate function
Given:
The function is,
[tex]p(x)=x+4[/tex]Explanation:
Substitute 2 for x in the function to determine the value of p(2).
[tex]\begin{gathered} p(2)=2+4 \\ =6 \end{gathered}[/tex]So answer is p(2) = 6
Subtract the following polynomials 1) (2x + 43) - (-3x-9)2) (f+9) - (12f 79)3) (75 X²)+ 23 + 13) - (15 X² - X + 40)
for 1.
2x+43+3x+9=5x+52
2.
f+9-12f+9=f-12f+9-9=-11f
3.
75x^2 +23x+13-15x^2+x-40=
=60x^2+24x-27
for 2)
23d^3+(7g^9)^13
remember that power to the power means that you need to multipy the exponents
=23d^3+7^13g^117
34x(2x-11)=68x^2-374x
2m(m+3n)=2 m^2+6mn
we have lenght
l=2x+5
w=x+7
area, A= lxw
A= (2x+5)(x+7)
this is the polynomial for the area
if we have x=12
l= (2*12)+5=24+5=29
w=12+7=19
A=29*19=551 ft^2
how do I solve (4w+3x+5)-(4w-3x+2)
Answer:
6x + 3
Explanation:
To solve the initial expression, we need to write it without the parenthesis as:
( 4w + 3x + 5 ) - ( 4w - 3x + 2)
4w + 3x + 5 - 4w + 3x - 2
Then, we need to identify the like terms as:
4w and -4w are like terms
3x and 3x are like terms
5 and -2 are like terms
Now, we can organize the terms as:
4w - 4w + 3x + 3x + 5 - 2
Adding like terms, we get:
(4w - 4w) + (3x + 3x) + (5 - 2)
0 + 6x + 3
6x + 3
Therefore, the answer is 6x + 3
Suppose the graph of
y
=
f
(
x
)
is stretched vertically by a factor of
3
, reflected across the
x
-axis, then translated left
7
units, and up
2
units.
The new graph will have equation y=
Answer:
[tex]y=-3(x+7)+2[/tex]
Step-by-step explanation:
Alright, so the first mistake people make is to try to visualize this graph. For the sake of the problem, it does not matter in the slightest.
To start, we have y=f(x).
The first change is a vertical stretch. These are represented outside the parentheses. Meaning, the new stretched equation would be y=3(x). The three does not replace the "f", just no one would write the f into the equation as it is implied.
Next, the graph is reflected across the x-axis. This means that there is a negative outside of the parentheses. The new equation would be -3(x). As stretches are always greater than 1 and shrinks are between 0 and 1, it is clear the negative denotes a reflection.
Translations to the left are denoted as positives inside parentheses. In this case, left 7 would be -3(x+7).
Finally, upwards translations are positive numbers shown following the parentheses. Up two would make your final equation -3(x+7)+2.
find the measures of the angles of a right triangle where one of the acute angles is *3.5* times the other
Lets draw a picture of our problem:
where x denotes the measure of the base angle.
Since interior angles of any triangle add up to 180, we have
[tex]x+3.5x+90=180[/tex]which gives
[tex]4.5x+90=180[/tex]By subtracting 90 to both sides, we have
[tex]\begin{gathered} 4.5x=180-90 \\ 4.5x=90 \end{gathered}[/tex]Finally, by dividing both sides by 4.5, we get
[tex]\begin{gathered} x=\frac{90}{4.5} \\ x=20 \end{gathered}[/tex]Then, the base angle measures 20 degrees and the upper angle measure
[tex]3.5\times20=70[/tex]Therefore, the searched angles measure
[tex]20,70\text{ and 90}[/tex]
(1) Which of the following statements are true? Select all that apply.
A. The data suggest that a linear model would be appropriate.
B. The data increase by a fixed amount each year.
Relative Change
XXXXX
C. The data suggest that an exponential model would be appropriate.
D. The data show a constant growth rate.
E. No model can be inferred from the data provided.
find the equation of the line?
Let's calculate the straight line equation
To do this we will take two points from the graph
A = (0,3)
B= (2,0)
For them we will first calculate the slope of the curve
[tex]m=\frac{y2-y1}{x2-x1}[/tex][tex]\begin{gathered} m=\frac{0-3}{2-0} \\ m=\frac{-3}{2} \end{gathered}[/tex]Now let's calculate the y-axis intersection
[tex]\begin{gathered} b=y-mx \\ b=3-m\cdot0 \\ b=3 \end{gathered}[/tex]The equation of the line in the slope-intercept form is
[tex]y=-\frac{3}{2}x+3[/tex]follow the order of operations and evaluate the exponential expression (5+1)^2-(9-5)^2x3
5000 + 300 + 8 in standard form
The given arithmetic expression is:
5000 + 300 + 8
This sum can be computed as shown below:
Therefore, 5000 + 300 + 8 = 5308
Convert 5308 to standard form
[tex]5308\text{ = 5.308 }\times10^3[/tex]
HELP PLEASE!!!!!!!!!!! ILL MARK BRAINLIEST
The rational number - 91 / 200 is a number between the decimal numbers - 0.45 and - 0.46.
How to determine a rational number between two decimal numbers
In this problem we find two decimal numbers, of which we need to find a rational number between these numbers. Please notice that the decimal numbers are also rational numbers. First, we transform each decimal number into rational numbers:
- 0.45 = - 45 / 100
- 0.46 = - 46 / 100
Second, find a possible rational number between the two ends by the midpoint formula:
x = (1 / 2) · (- 45 / 100) + (1 / 2) · (- 46 / 100)
x = - 45 / 200 - 46 / 200
x = - 91 / 200
Then, the rational number - 91 / 200 is a number between - 0.45 and - 0.46.
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12. Find DC.
A
20
54°
B
D
28°
C
The measure of the DC is 30.43 units after applying the trigonometric ratios in the right-angle triangle.
What is the triangle?In terms of geometry, a triangle is a three-sided polygon with three edges and three vertices. The triangle's interior angles add up to 180°.
It is given that:
A triangle is shown in the picture.
From the figure:
Applying sin ratio in triangle ADB
sin54 = BD/20
BD = 20sin54
BD = 16.18
Applying the tan ratio in triangle CDB
tan28 = 16.18/DC
DC = 30.43 units
Thus, the measure of the DC is 30.43 units after applying the trigonometric ratios in the right-angle triangle.
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Given that 1 inch = 2.54 centimeters how many centimeters are in 6 feet?
Answer:
182.88 centimeters are in 6 feet!
Step-by-step explanation:
I hope this helped! c:
Answer:
182.88 centimetersStep-by-step explanation:
If
1 in. = 2.54 cm.
and
12 in. = 1 ft.
lets convert cm into feet
1 * 12 = 12 (how many inches are in a foot )
2.54 * 12 = 30.48 (how many centimeters are in a foot)
so now that we know how many centimeters are in a foot, we can find out how many centimeters are in 6 feet
30.48 * 6 = 182.88
182.88 centimeters are in 6 feet