in triangle ABC, bisectors of angle A and angle C cross each other in point M. find angle ABC if it is half of AMC. (no shape given)

Answers

Answer 1

Answer:

[tex]\angle ABC=60[/tex]

Step-by-step explanation:

[tex][Kindly\ refer\ the\ image\ attachment.]\\We\ are\ given\ that,\\AM\ is\ the\ Angle\ Bisector\ of\ \angle BAC.\\Hence,\\\angle BAM= \angle MAC\\CM\ is\ the\ Angle\ Bisector\ of\ \angle BCA.\\Hence,\\\angle BCM= \angle MCA.\\Also,\\\angle AMC=2 \angle ABC[/tex]

[tex]Now,\\As\ we\ can\ observe\ that,\\\angle BCM + \angle MCA= \angle BCA\\\angle MCA+ \angle MCA= \angle BCA\ [\angle BCM = \angle MCA]\\Hence,\\2 \angle MCA= \angle BCA\\Or, \\\angle MCA=\frac{\angle BCA}{2} \\\\Similarly,\\\angle BAM + \angle MAC= \angle BAC\\\angle MAC + \angle MAC= \angle BAC\\2 \angle MAC = \angle BAC\\Or,\\\angle MAC=\frac{\angle BAC}{2}[/tex]

[tex]Through\ the\ Angle\ Sum\ Property\ of\ a\ Triangle,\ we\ know\ that:\\'The\ Sum\ of\ all\ interior\ angles\ of\ a\ triangle\ is\ 180.'\\Hence,\\In\ \triangle BAC,\\\angle ABC + \angle BCA + \angle CAB=180\\In\ \triangle MAC,\\\angle MAC+ \angle ACM + \angle AMC=180[/tex]

[tex]Hence,\\As\ \angle AMC= 2 \angle ABC, \angle MCA=\frac{\angle BCA}{2}, \angle MAC=\frac{\angle BAC}{2},\\2 \angle ABC+\frac{\angle BCA}{2}+\frac{\angle BAC}{2}=180\\By\ resolving\ the\ denominators,\\\frac{4 \angle ABC+\angle BCA+\angle BAC}{2}=180\\\\By\ comparing\ the\ Sum\ of\ angles\ in\ both\ the\ triangles,\\We\ find\ that\ the\ RHS\ of\ both\ the\ equations\ are\ equal\ i.e.180,\\The\ LHS\ of\ the\ equations\ are\ equal\ too.\\[/tex]

[tex]Hence,\\\angle ABC+ \angle BCA + \angle BAC=\frac{4 \angle ABC+\angle BCA+\angle BAC}{2}\\Hence,\\2(\angle ABC+ \angle BCA + \angle BAC)=4 \angle ABC+\angle BCA+\angle BAC\\Hence,\\2 \angle ABC+ 2 \angle BCA + 2 \angle BAC=4 \angle ABC+\angle BCA+\angle BAC\\Hence,\\2 \angle BCA + 2 \angle BAC-\angle BCA- \angle BAC=4 \angle ABC- 2 \angle ABC\\Hence,\\\angle BCA+\angle BAC= 2\angle ABC[/tex]

[tex]Lets\ get\ back\ to\ the\ Angle\ Sum\ of\ \triangle ABC,\\\angle ABC + \angle BAC + \angle ACB=180\\Hence,\\As\ \angle BCA + \angle BAC= 2 \angle ABC,\\\angle ABC + 2 \angle ABC=180\\Hence,\\3 \angle ABC=180\\\angle ABC=\frac{180}{3}=60[/tex]

 In Triangle ABC, Bisectors Of Angle A And Angle C Cross Each Other In Point M. Find Angle ABC If It

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Answers

Answer:

88*0.9= 79.2 (since it's 10% higher, multiply by .9 to find out what 90% of 88 is

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation: hope this helps

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

We know that n of the 10 goats are male.

The probability that in a random selection, the selected goat is a male, is equal to the quotient between the number of male goats (n) and the total number of goats (10)

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Answers

Answer:

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Step-by-step explanation:

A recipe code lasagna calls for 3 pounds of tomatoes to serve 5 people. A caterer wants to make enough lasagna to serve 110 people. How many pounds of tomatoes does he neeed

From the above question:

5 people = 3 pounds of tomatoes

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Cross Multiply

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Explanation:

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Answer:

see explanation

Step-by-step explanation:

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Line 1 is in this category.

A line sloping downwards from left to right has a negative slope.

Line 4 is in this category.

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Answers

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A summer camp cookout is planned for the campers and their families. There is room for 200 people. Each adult costs 4, and each camper costs4,and each camper costs3. There is a maximum budget of $750. Write the system of inequalities to represent this real-world scenario, where x is the number of adults and y is the number of campers.
A. \begin{gathered}x + y \leqslant 200 \\ 4x + 3y \leqslant 750\end{gathered}x+y⩽2004x+3y⩽750​
B. \begin{gathered}x + y \leqslant 750 \\ 4x + 3y \leqslant 200\end{gathered}x+y⩽7504x+3y⩽200​
C. \begin{gathered}x + y \leqslant 200 \\ 3x + 4y \leqslant 750\end{gathered}x+y⩽2003x+4y⩽750​
D. \begin{gathered} x + y \leqslant 750 \\ 3x + 4y \leqslant 200\end{gathered}x+y⩽7503x+4y⩽200​

Answers

Answer:

Option A

The system of inequalities

x + y ≤ 200

4x + 3y ≤ 750

Step-by-step explanation:

Let the

Number of Adults = x

Number of campers = y

A summer camp cookout is planned for the campers and their families.

There is room for 200 people.

x + y ≤ 200

Each adult costs $4, and and each camper costs $3. There is a maximum budget of $750.

Maximum means the total cost is equal to or less than $750

$4 × x + $3 × y ≤ $750

4x + 3y ≤ 750

The system of inequalities

x + y ≤ 200

4x + 3y ≤ 750

Option A is correct

Tyson is 6 feet 2 inches tall. There are 2.54 centimeters in 1 inch. What is Tyson's height in centimeters?

Answers

Answer:

187.96 cm

Step-by-step explanation:

Given hat

Tyson is 6 feet and 2 inches tall

Also

There is 2.54 cm in 1 inch

Now the tyson height in the centimeter is

= 6.16666 × 30.48

= 187.96

Hence, the Tyson height in the centimeter is 187.96

Answer:

187.96

Step-by-step explanation:

(answer d)

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