In the diagram below, two of the three rays used to find the image position are shown. Which of the following best describes the third (missing) ray?A.A ray incident parallel to the axis refracts outward, as if it came from the focus on the left hand side.B.A ray incident through the vertex continues through the lens without refracting.C.A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side.D.A ray incident on a path that would take it through the right focus refracts parallel to the axis.

If Victor starts measurements 100 m from the disposal site, he needs to stand 50 m from the source if he hopes to measure soil with 4 times the radiation.

I = 1 / r²

I = Intensity

r = Distance

At a distance of 100 m from the source,

I = 1 / 100²

I = 1 / 10000

I = [tex]10^{-4}[/tex] J / m² s

Four times this radiation will have an intensity of,

I = 4 * [tex]10^{-4}[/tex] J / m² s

4 * [tex]10^{-4}[/tex] = 1 / d²

d² = 1 / 4 * [tex]10^{-4}[/tex]

d² = 0.25 * [tex]10^{4}[/tex]

d = √ 25 * 10²

d = 5 * 10

d = 50 m

Therefore, he needs to stand 50 m from the source

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The phone can be 8.35cm small.

Frequency is the variety of occurrences of a repeating occasion in line with a unit of time. it is also from time to time referred to as temporal frequency to emphasize the assessment of spatial frequency, and regular frequency to emphasize the evaluation of angular frequency.

Frequency is an expression of ways regularly a periodic wave shape or signal repeats itself at a given amplitude. it is able to be expressed in hertz (Hz), kilohertz (kHz), megahertz (MHz), and so on.

Frequency is a vital parameter used in technological know-how and engineering to specify the temporal rate of trade discovered in oscillatory and periodic phenomena, such as mechanical vibrations, audio alerts (sound), radio waves, and mild.

GSM 900 band corresponds to a wavelength (\lambda) of

λ= c/f

where c is the speed of light and frequency is f which is 900 MHz

This gives \lambda=33.4cm

Antenna length   L=\lambda/4=8.35cm

So the phone should at least be 8.35cm long.

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a) Yes the ball clear it. Through, equation of motion is 1.104 m > 0.9 m

b) The distance between the center of the ball and the top of the net is 0.204 m

a) As we know the equation of motion,

  y = 1/2(at^2)

   y= 1/2 (9.81)(0.508)^2

  y = 1.266 m

height = Y net - y

h = 2.37m - 1.266m

h = 1.104m

b)

 height in y direction - net height

 = 1.104m - 0.9m

 = 0.204m

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Given Data:

The applied acceleration is constant.

speed of the car after time,t1 = 20s, is V1=  54 km/h = 15 m/s

speed of the car after time,t2 =  60s, is V2= 108 km/h = 30m/s

we use the formula, V = Vo + a x t

where, Vo is the initial speed, a is the acceleration(constant),

t is the time taken by the object.

a) Acceleration = rate of change of speed with time = V2 - V1 / t2 - t1

a = 30-15/60-20

a = 15/40 = 0.375 m/[tex]{s^{2} }[/tex]

b) Initial speed, Vo = V1 - a x t1

                                = 15 - 0.375 x 20

                                 = 7.5 m/s

c) Speed after 40 s, V = Vo + a x t, t = 40s

                                     = 7.5 + 0.375 x 40

                                      = 22.5 m/s

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It is distinguished from the other planets by the presence of liquid water on its surface, the presence of life, and active plate movement. It rotates on its axis once every 24 hours (a day) and orbits the Sun once every 365 days (a year). The Earth has a single moon.

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Current is dwindling at 0.125 , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms

Voltage = Current * Resistance ,

The Ohm's law is given by

V = IR eq. 1

Where V is the voltage across Resistance R and I is the current flowing through the Resistance R

Taking outgrowth of eq. 1 with respect to time t yields

dV/ dt = I * dR/ dt dI/ dt * R

dI/ dt * R = - I * dR/ dt dV/ dt

dI/ dt = (- I * dR/ dt dV/ dt)/ R eq. 2

Now substitute the given values into eq. 2

dI/ dt = (-0.02 *0.04(-0.02)) 300

dI/ dt = (-0.0008-0.02)/ 300

dI/ dt = -0.0208/ 300

Charge will go via the external circuit if the two conditions of an electrical circuit are satisfied. Flow of charge is appertained to as a current. In this case, the word" current" simply means that" charge is moving," indicating that commodity is taking place in the cables. The physical property of current, still, may be measured and quantified. The quantum of charge that moves past a point on a circuit at a given time is called current as a physical volume. The quantum of charge Q travelling through a line's cross section in a given quantum of time, as shown in the illustration below, can be measured to determine the current in a circuit.

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The ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the centre of the circle: 1.29

Centripetal acceleration is given by :

a = ω2R

where,

ω is the angular speed

R is the distance of the point from the centre

Let the point at the tip be A and that at distance 6.16 m from centre be B

Distance of point A from centre (RA) = 7.99 m

Distance of point B from centre (RB) = 6.16 m

Centripetal acceleration at A (aA) = ω2RA = 7.99ω2

Centripetal acceleration at B (aB) = ω2RB = 6.16ω2

The ratio (aA/aB) = 7.99/6.16 = 1.29

centripetal acceleration is defined as the motion characteristic of an object moving along a circular path. Any object moving in a circle whose acceleration vector points towards the centre of that circle is called centripetal acceleration. You must have seen various examples of medium acceleration in your daily life. When you drive a car around a circle, your car experiences an average acceleration, and the average acceleration is also observed by a satellite orbiting the Earth. Middle means towards the centre.

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Answer:

there are the three basic

first law also called the law of inertia

the second one is the second law of motion and its equation is

F = ma

where m is the mass and a is the acceleration

its SI units are mass is kg and Acceleration is m/[tex]s^{2}[/tex]

the third law is called the action-reaction law

also the law of gravitation in which we survive our own earth-like plane due to the basic concept of the law of gravitation because the idea of gravitation is deal with this important law

F=GmMe/[tex]R^{2}[/tex]

The G value is 6.673*10^-11

m is the mass of an object

Me is the mass of the earth in our case we consider the object and the earth.

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Torque Formula:

T = d * F * sin angle

a) if the force is doubled, torque is doubled ( directly proportional)

For example, if force is 2 N, and distance is 2 m ,

T= 2*2* sin 90 = 4 Nm

If force is doubled:

T= 2*4 * sin90 = 8 Nm

b) If the distance of the center of rotation is doubled , Torque is also doubled ( same as "a")

c) If angle decreases 45° (90 - 45 = 45 )

T= 2*2*sin45 = 2.82 Nm

Torque also decreases

Scientists suspect that mars once had abundant liquid water on its surface. For this to have been true, early mars must have had a significantly greater atmospheric pressure and a far bigger greenhouse impact than mars today

The greenhouse effect describes how "greenhouse gases" trap heat at the Earth's surface. These heat-trapping gases act like a blanket wrapped around Earth, keeping it warmer than it would be without them. Carbon dioxide, methane, nitrous oxides, and water vapor are examples of greenhouse gases. Scientists have discovered that the warming effect of carbon dioxide aids in the stabilization of the Earth's atmosphere. The terrestrial greenhouse effect would collapse if carbon dioxide were removed. Without CO2, the Earth's surface would be 33°C (59°F) colder.

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Based on this knowledge,he is  most justified in concluding that the   originates between the Sun and the asteroid belt.

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ices. They variety from a few miles to tens of miles wide, however as they orbit in the direction of the sun, they warmth up and spew gases and dirt right into a sparkling head that can be large than a planet. This cloth bureaucracy a tail that stretches thousands and thousands of miles.

Asteroids lack the magnetic area and atmosphere that shield us on earth from harm. Living internal an asteroid is one way to defend your self from harmful radiation, it is expected that by tunneling 100 meters deep beneath an asteroid, people would be sufficiently shielded from radiation.

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The magnitude of the least acceleration the monkey must have if it is to lift the package off the ground: is 9.8 m/[tex]s^2[/tex]

From free body diagram,

The minimum acceleration of the monkey of mass (m) to lift the package off the ground is

[tex]m_{1}a_{min} = m_2g -m_1g\\a_{min} = \frac{m_2 - m_1}{m_1} g \\a_{min} = \frac{28 - 14}{14} 9.8 m/s^2 \\ \\a_{min} = 9.8 m/s^2 \\\\\\[/tex]

Mass is the amount of matter in a physical body. It  also measures the body's inertia, the resistance to acceleration when a net force is applied. The mass of an object also determines  its gravitational force on other objects. The basic SI  unit of mass is the kilogram. Mass is best understood as the amount of matter  in any object or body. Everything we see around us has mass. For example, a table, a chair, a bed, a football, a glass, and even air have mass.

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Given data

*The given mass of the car is m = 1475 kg

*The maximum tension is T = 2551 N

The formula for the maximum possible acceleration of the truck is given by Newton's second law as

Substitute the known values in the above expression as

Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2

The possible density of the iceberg from the options that have been given in the question is 0.88 g/mL.

We know that the term density has to do with the ratio of the mass to the volume of an object. Now when we find that an object is denser than another, the denser object would tend to sink on the one that has a lesser density.

In accordance with the floatation principle which states that an object would displace only its own volume of the fluid. We can see that even if an object has an equal density as the other then it can float on the other liquid.

Here we have been shown the image of an iceberg which is close to what we have known as the "tip of the iceberg". We are now being asked to be able to obtain what should be the accurate density of the iceberg.

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The speed of the beam of light moving along the shoreline when it is 1 km from p 62.83 km/min revolution.

A revolution is the motion of 1 object around a center or some other object, a forceful overthrow of a government by using the people, or any sudden or grand trade. An example of revolution is the movement of the earth around the solar.

dθ/dt = 3 rev/min

         = 3×2π = 6π rad/min

tanθ = x/3

[tex]\frac{d}{dt}[/tex] tanθ = [tex]\frac{d}{dt}[/tex] (x/3)

sec²θ dθ/dt = 1/3 dx/dt

dx/dt = 3sec²θdθ/dt

At x = 1km; tanθ =x/3 =1/3

sec²θ = 1 + tan²θ = 1+(1/3)²

sec²θ =10/9

dx/dt = 3sec²θ dθ/dt

dx/dt = 3×10/9×6π

dx/dt = 62.83 km/min

Hence, the beam of light along the shoreline when it is 1 km away from point P is 62.83 km/min

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The wavelength released during photoelectric effect is 353 nm.

We need to know about the photoelectric effect to solve this problem. The photoelectric effect is electron ejected from metal because of light source. The kinetic energy of the ejected electron is

K = (hc / λ) - (hc /λo)

where K is kinetic energy, h is Max Planck constant (6.6 x 10¯³⁴ Js), λ is the wavelength of light source and λo is the wavelength released from the metal.

From the question above, we know that

λ = 257 nm = 257 x 10¯⁹ m

c = 3 x 10⁸ m/s

v = 6.8 x 10⁵ m/s

me = 9.1 × 10¯³¹ kg

Find the wavelength released

K = hc . (1/λ - 1/λo)

1/2 . me .v² = 6.6 x 10¯³⁴ x  3 x 10⁸ . (1/257 x 10¯⁹ - 1/λo)

1/2 . 9.1 × 10¯³¹ . (6.8 x 10⁵)² = 6.6 x 10¯³⁴ x  3 x 10⁸ . (1/257 x 10¯⁹ - 1/λo)

2.10 x 10¯¹⁹ = 1.98 x 10¯²⁵ . (1/257 x 10¯⁹ - 1/λo)

2.10 x 10¯¹⁹ = (7.70 x 10¯¹⁹) - (1.98 x 10¯²⁵ / λo)

(1.98 x 10¯²⁵ / λo) = 5.60 x 10¯¹⁹

λo = 0.353 x 10¯⁶ m

λo = 353 nm

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1.926kg is the maximum book mass you can hold this way and keep from slipping.

This book with 27 N, so Normal rection force N = 27N.  

let mass of brook =  m Kg

here gravitational force acting downwards which tend book to more downwards and frictional force moving  is acting vertically upwards to held

frictional force a must be equal to gravitational force here frictional force

fr = μN

so for body to be rest fr = mg

                                     μN =  mx 9.81

                                      m =     μN / 9.81

here maximum value of coefficient static friction   μ = 0.70

                                      m = 0.70x  27/9.81

                                     m = 1.926kg

Friction is the force that opposes motion when the surface of one object comes into contact with the surface of another. The mechanical advantage of the machine is reduced by friction,  in other words, the ratio of power to input decreases due to friction. A car uses a quarter of its energy to limit friction. However, the friction of the tires also allows the car to stay on the road, and the friction of the clutch allows it to drive. From matches to machines and molecular structures, friction is one of the most important phenomena in the physical world.

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The minimum distance in which car will stop is  256m.

What is distance?

distance is the length of the space between two points.

distance is a numerical or its  the occasionally qualitative measurement of how to far apart objects or points .

Sol-here we can apply Newton’s second law to the  car of to determine of the maximum static friction to the force acting on the car:

€Fy=ma^y+ n-mg=0

Fs≤us mg

This maximum magnitude of static friction acts so long as the tires roll without skidding.

€Fx=ma^x-----> -fs=ma

The maximum acceleration is

a=-u^s g

The initial and final conditions are- xi=0, vi=50.0mi/h =22.4 m/s and vf =0.Then,

v^2=v^2+2a(xf-xi)---->v^2

     f          i                                       I

Xf=(22.4m/s)^2/2(0.100)(9.80m/s^2)=256

Thus through the minimum distance in which car will stop is 256m.

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First, we need to do a type conversion. Because the types of the two given quantities are different. One is in minutes. The other is in hours. A vehicle that travels [tex]45[/tex] kilometers in an hour travels how many meters in a second?

A vehicle that travels [tex]12.5[/tex] meters in a second travels how many meters in [tex]20[/tex] minutes?

If a batter can apply the same amount of maximum force from their hands to each bat to swing it ,  the speed of the bat swing decrease as the mass of the bat increases because of greater moment of inertia .

Moment of inertia is directly proportional to the mass , hence if mass of the bat increased , moment of inertia will also increase and it will be more difficult to swing the bat .

hence , the speed of the bat swing decrease as the mass of the bat increases

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If Alex throws a 0.25-kg rubber ball down onto the floor, the ball's speed just before impact is 4.5 m/s, and just after is 2.9 m/s.The change in the magnitude of the ball's momentum is 1.85 [tex]kg \frac{m}{s}[/tex]

Calculation

Change in momentum= [tex]mv_{1} -mv_{2}[/tex]

where, m is mass of the object, m= 0.25 kg

[tex]v_{1}[/tex] is velocity before collision, [tex]v_{1}[/tex] = 4.5 m/s

[tex]v_{2}[/tex] is velocity after collision, [tex]v_{2}[/tex] = 2.9 m/s

therefore, [tex]mv_{1} -mv_{2} =m(v_{1}-v_{2} )[/tex]

⇒0.25(4.5-(-2.9)) = 0.25(4.5 + 2.9) = 0.25* 2.4

= 1.85 [tex]kg\frac{m}{s}[/tex]

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The friction force ratio between navy blue car and mint green car due to the centripetal force is 10/9.

We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is

Fc = m . v²/R

where Fc is the centripetal force, m is mass, v is velocity and R is the radius.

The friction force is proportional to the centripetal force

From the question, we know that

mblue = 1616 kg

mgreen = 1818 kg

Rblue = 4/5 Rgreen

vblue = vgreen

Find the centripetal force ratio

Fcblue / Fcgreen = (mblue . vblue² / Rblue) / (mgreen . vgreen² / Rgreen)

Fcblue / Fcgreen = (1616 / 4/5 Rgreen ) / (1818 / Rgreen)

Fcblue / Fcgreen = 10 / 9

Hence, the tension in the cord is 32 newton.

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From Newton's second law of motion,

F = ma

We know m = 65 kg. Next, we have to find a through this formula:

v² = v₀² + 2ad

0² = (18 m/s)² + 2(a)(1 m)

Solving for a,

a = -162 m/s²

So,

F = (65 kg)(-162 m/s²) = -10,530 Newtons.

A crumpled zone in the front of the car gradually slows the car down and increases the braking time. A safety cell is a rigid cage that prevents passengers from becoming trapped. Inside the car seat belts and airbags prevent the driver from hitting the windshield steering wheel and dashboard.

Crumple zones are typically found in the front and rear of a vehicle and are designed to crumple and crush under high-force impacts. The Crumple Zone transfers a portion of the vehicle's kinetic energy during impact to a controlled crash while maintaining the integrity of the occupant cell.

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The statement is incorrect about the light year .

What is a light year ?

A Light year is the distance that light travels in a vacuum in one year.

The fastest thing we know is light, which travels through empty space at 186,000 miles or 300,000 kilometers per second. To give you an idea of ​​how fast it is, light can circle the Earth about seven times in one second. Astronomers use the speed of light to measure distance in space. A light year (ly) is the distance that light can travel in one year. In one year, light travels approximately 5,880,000,000,000 miles or 9,460,000,000,000 kilometers. So this distance is 1 light year. For example, our closest star is about 4.3 light years away. Our galaxy, the Milky Way, is about 150,000 light-years across, and the nearest large galaxy, the Andromeda Galaxy, is 2.3 million light-years away from her.

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Mass m = 73kg

Vertical height in each stage h = 10 m

A). Initial speed u = 0

Final speed v = 4.3m / s

Work done W= mgh + ( 1/ 2) m[v 2 - u 2 ]

= 7063.2 +665.64

= 7728.84 J

B).Work done W = mgh

= 7063.2J

C).Work done W  = mgh + ( 1/ 2) m [ V 2 - v 2 ]

Where  V = final speed

= 0

v =4.3m / s

Substitute the values we get  W =7063.2 - 665.64

= 6397.56 J

To slow down a vehicle The vehicle slows down when it sees a police car. Thesaurus synonyms, antonyms, and examples. slow down. Slowing down The car slowed down and stopped next to her. A motionless object has zero velocity. If an object has zero acceleration its velocity must be constant.

Whenever an object's acceleration is in the same direction as its velocity, the car is accelerating and is said to be accelerating. If the acceleration is simultaneously opposed to the speed, the car is said to be slower and slower. Delay slows down: An unexpected slowdown in your car could mean you're running out of gas.

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The mass of the truck is 12,974.4kg .

As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force.

Measures a substance's resistance to acceleration in physics. A measure of an object's mass is roughly equivalent to counting the atoms that make up the object. The kilogram serves as the fundamental mass unit. Mass multiplied by the gravitational acceleration equals weight.

50km/h =50×5/18 m/s= 13.88 = 13.9

momentum (p)=180,345 kg.m/s

P=mv

180,345= m X 13.9

m = 180345/13.9

m = 12,974.46

m = 12,974.4

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As a result of the law of conservation of momentum, the man will recoil as far as 0.034 m.

The law of conservation of momentum:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Where:

u₁ , u₂ = initial velocity of object 1 and object 2

v₁ , v₂ = final velocity of object 1 and object 2

Since both the player and the puck are initially at rest, hence  u₁ = 0, u₂ = 0.

Therefore,

m₁v₁ + m₂v₂ = 0

Parameters given:

m₁ = 80 kg

m₂ = 0.150 kg

v₂ = 47 m/s

Plug the parameters into the equation,

80 . v₁ + 0.15 . 47 = 0

v₁ = - 0.088 m/s

Time the puck reach 18 m goal:

t = distance / velocity = 18 / 47 = 0.38 s

The player will recoil:

distance = velocity x t = 0.088 x  0.38 = 0.034 m = 3.4 cm

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Given:

The mass of the system is m' =m/2

The net force acting on it is F' = 2F

To find the acceleration.

Explanation:

The acceleration will be

Thus, the acceleration would be quadrupled(x4).

Answer:

micronutrients.

Explanation: