IM STUCK IN THIS ONES AND THEY KEEP DELETING THE ANSWERS

The probability helps us to know the chances of an event occurring. The probability of event n occurring is 0.3.

The probability helps us to know the chances of an event occurring.

[tex]\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

We know that for two independent events the probability of the two events occurring simultaneously is written as,

[tex]P(A \cap B) = P(A)\cdot P(B)[/tex]

Now, as we know the probability of event m occurring also we know the probability of both events occurring simultaneously, therefore, the probability of event n occurring can be written as,

[tex]P(A \cap B) = P(A)\cdot P(B)\\\\P(m \cap n) = P(m)\cdot P(n)\\\\0.138 = 0.46 \times P(n)\\\\P(n) = 0.3[/tex]

Hence, the probability of event n occurring is 0.3.

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Answer:

Delta does not have a relative extreme in the equation, so it is variable y It can not be true

Step-by-step explanation:

[tex]s = 5x + 3y[/tex]

There is an answer

The rest of the equation that has no substituted delta is not true, so the prime variables have relative extremes.

Answer:

[tex] \frac{ \alpha + \beta + \gamma }{ - d} [/tex]

Step-by-step explanation:

If we simplify that fraction, we get

[tex] \frac{ \alpha + \beta + \gamma }{ \alpha \beta \gamma } [/tex]

Keep that in mind.

If y, a ,b are zeroes of the cubic polynomial, then that means

[tex](x - \alpha )(x - \beta )(x - \gamma )[/tex]

make up the polynomial.

Notice that leading xoeffeicent will be 1, so the roots will multiply to

[tex] - d[/tex]

so

[tex] \alpha \beta \gamma = - d[/tex]

which gives us

[tex] \frac{ \alpha + \beta + \gamma }{ - d} [/tex]

Proof:

Consider the function

[tex](x - 2)(x - 3)(x - 5)[/tex]

The roots are 2, 3, 5.

D is -30 so we get

Using the value,

[tex] \frac{2 + 3 + 5}{ 30} = \frac{1}{3} [/tex]

If we use the orginal equation, we get

[tex] \frac{1}{6} + \frac{1}{10} + \frac{1}{15} = \frac{10}{30} = \frac{1}{3} [/tex]

Answer:

Hey,mate

Notice that leading xoeffeicent will be 1, so the roots will multiply to

The roots are 2, 3, 5.

[tex]\sqrt{2} \sqrt{3} \sqrt{5}[/tex]

D is -30

Answer: 83 degrees

Step-by-step explanation:

In order to find theta, you must take the arccosine of both sides. The arccosine eliminates the cosine, and extracts the argument. Therefore:

[tex]cos(x)=\frac{2}{16} =\frac{1}{8}[/tex]

[tex]arccos(cos(x))=arccos(\frac{1}{8} )=x[/tex]

Use a calculator the find the arccosine of 1/8. Its nearly impossible to find the exact answer without one:

[tex]x=arccos(\frac{1}{8} )[/tex]

[tex]x=83[/tex]

The difference between group 1 and group 2 is the species of group 1 are vertebrates and species of group 2 are invertebrates.

Vertebrates are those animals that have a spinal cord.

Invertebrates are those who do not have a spinal cord or vertebrae.

The animals, of group 1 are alligator, fish, frog, bird, and zebra, all are vertebrates.

The animals of group 2 are jellyfish, octopus, tarantula, and earthworms.

Thus, the correct option is C, group 1 are vertebrates, and group 2 is invertebrates.

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Answer:

P=67.38

Step-by-step explanation:

All three sides are given. You can use any one of the the three major functions on your calculator to g

Adjacent = PQ = 5

Hypotenuse = PR = 13

Cos(P)  = Adjacent / Hypotenuse

Cos(P) = 5/13

Cos(P) = .3846

Now you need to use the inverse cos to get P

P = cos-1(.3846)

P =67.38

=====================================

Now we'll try the tangent

Tan(P) = opposite / adjacent

Tan(P) = 12/5

Tan(P) =2.4

P = Tan-1(2.4)

P = 67.38

Both functions give the same thing

[tex]\\ \rm\Rrightarrow cosP=\dfrac{Base}{Hypotenuse}[/tex]

[tex]\\ \rm\Rrightarrow cosP=\dfrac{5}{13}[/tex]

[tex]\\ \rm\Rrightarrow cosP=0.38[/tex]

[tex]\\ \rm\Rrightarrow P=cos^{-1}(0.38)[/tex]

[tex]\\ \rm\Rrightarrow P=67.67°[/tex]

Answer:

c = 40degrees

Step-by-step explanation:

the sum of a triangle should be 180 degrees

you need to ad 80+60 which is 140 then minus 140 from 180 which is 40 so 40 degrees is the measurement of angle c

Answer:

$1.5

Step-by-step explanation:

12 x 1.75 + 6c = 30

21 + 6c = 30

6c = 30 - 21

6c = 9

c = 9/6

c = 1.5

Answer:

do face reveal

Step-by-step explanation:

we don't talk about bruno

Answer:

Add 509 and 476; The Roman Era lasted for a total of 985 years from 509 B.C to 476 A.D.

Step-by-step explanation:

Using it's concept, it is found that the domain and range of the function are given by:

D: [–4, ∞) and R: [0, ∞)

In this problem, the function is:

[tex]g(x) = \sqrt{x + 4}[/tex]

The square root function does not exist for negative values, hence the domain is represented by:

[tex]x + 4 \geq 0 \rightarrow x \geq -4[/tex]

The range of the square root function is [tex]x \geq 0[/tex], which remains the same as there are no vertical translations.

Hence the correct option is given by:

D: [–4, ∞) and R: [0, ∞)

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Answer: C) D: [–4, ∞) and R: [0, ∞)

Step-by-step explanation:

Answer:

[tex]\pi (\frac{diameter}{2} )^{2}[/tex]

Step-by-step explanation:

The formula is pretty similar to the standard equation, π·r², since the diameter is just the radius times two.

Hope that helps! :)

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations in a quick and efficient manner.

In this question we shall use the following Laplace transforms:

[tex]\mathcal {L} \{f(t) + g(t)\} = \mathcal {L} \{f(t)\} + \mathcal {L}\{g(t)\}[/tex]   (1)

[tex]\mathcal {L} \{\alpha\cdot f(t)\} = \alpha\cdot \mathcal {L} \{f(t)\}[/tex]   (2)

[tex]\mathcal{L} \left\{y^{(n)} \right\} = s^{n}\cdot \matcal {L}\{f(t)\}-s^{n-1}\cdot y(0) -...-y^{(n)}(0)[/tex]   (3)

[tex]\mathcal {L} \{e^{-a\cdot t}\} = \frac{1}{s+a}[/tex]   (4)

Now we proceed to derive an expression fo the Laplace transform of the solution of the differential equation:

[tex]y'' -5\cdot y' = 8\cdot e^{4\cdot t}-4\cdot e^{-t}[/tex]

[tex]s^{2}\cdot \mathcal {L}\{f(t)\}-5\cdot y(0) - y'(0) - 5\cdot s \cdot \mathcal {L} \{f(t)\} +5\cdot y(0) = \frac{8}{s-4}-\frac{4}{s+1}[/tex]

[tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]. [tex]\blacksquare[/tex]

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The Laplace transform Y'' − 5y' = 8e4t − 4e−t when y(0) = 1, y'(0) = −1 for f(t) = 8e4t − 4e−t would be  [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations quickly and efficiently.

The Laplace transform

L[ f(t) + g(t) ] = Lf(t) + Lg(t)

Also,

L [[tex]y^{n}[/tex]] = [tex]s^{n} . L[ f(t) ] - s^{n-1} .y(0) .....y^{n}(0)[/tex]

We have

Y'' − 5y' = 8 . e^4t − 4 . e−t

[tex]s^{2} . L[ f(t) ] - 5. y(0)- y'(0) .....y^{n}(0)[/tex]

y(0) = 1, y'(0) = −1  

for f(t) = 8e4t − 4e−t.

= [tex]\frac{8}{s-4} - \frac{4}{s+1}[/tex]

L [f(t)] = [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex]

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The cosine function for the ferris wheel ride is an illustration of a sinusoidial function

The equation of the Ferris wheel is y = -190cos(π / 120 t) + 195

A cosine function is represented as:

y = Acos(Bt - C) + D

From the complete question, the diameter of the ferris wheel is 380 feet.

The amplitude represents the radius, and this is calculated as:

A = 380/2

A = 190

The function becomes:

y = 190cos(Bt - C) + D

The period of the function is:

T = 2π / B

From the complete question, one full rotation is completed in 4 minutes.

Convert the time to seconds

T = 4 * 60

T = 240.

So, we have:

240 = 2π / B

Divide both sides by 2

120 = π / B

Make B the subject

B = π / 120

The function becomes

y = 190cos(π / 120 t - C) + D

From the question, the ferris wheel is 195 feet above the ground.

This represents the vertical shift.

So, we have:

D = 195

The function becomes

y = 190cos(π / 120 t - C) + 195

Also, we have:

The lowest point is at t = 0 and the function is a negative cosine function

So, we have:

C = 0

The function becomes

y = -190cos(π / 120 t) + 195

Hence, the cosine function is y = -190cos(π / 120 t) + 195

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Answer:

13.75 is your answer

Step-by-step explanation:

find area of whole triangle 5.5*7*1/2=19.25

Find area of blank spot 5.5*2*1/2=5.5

Subtract 19.25-5.5=13.75

Answer:

1. Find the circumference, then multiply that by 120 turns.

Formula for circumference;

C = 2πr

But, we need to find the radius which is 1/2(half) of the diameter, so,

D/2 = R

D = Diameter

R = Radius

20/2 = 10 is the radius.

Plug in values now:-

C = 2(3.14) x 10

C = 6.28 x 10

C = 62.8 is the circumference, now we multiply this by 120 to get the total amount of centimetres it'll go.

62.8(120)

= 7,536 cm it'll go.

2. Find the circumference, then multiply that by 750 turns/revolutions.

C = 2πr

Find radius,

D/2 = R

50/2 = 25 is the radius.

Plug in values now:-

C = 2(3.14) x 25

C = 6.28 x 25

C = 157 cm it'll go.

3. Same thing, find circumference then compare values.

Given that radius is 10,

Use the formula for circumference;

C = 2πr

Replace values:-

C = 2(3.14) x 10

C = 6.28 x 10

C = 62.8 cm is the circumference of the first circle.

Now the second circle, (use same formula)

C = 2πr

Find radius,

D/2 = R

10/2 = 5 is the radius.

Replace values:-

C = 2(3.14) x 5

C = 6.28 x 5

C = 31.4 cm is the circumference for the second circle.

Now subtract the second circle's circumference from the first:

62.8 - 31.4

= 31.4, 31.4 cm is how much greater the second circle is than the first.

4 - 5. Find circumference, (using circumference formula)

C = 2πr

Find radius,

D/2 = R

760/2 = 380

Replace values:-

C = 2(3.14) x 380

C = 6.28 x 380

C = 2,386.4 km is the distance he'll travel.

If he wants to travel around it with 2,000 km, he'll need to travel at least once.

Answer:

(6-5)/5=20% increase

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

the solution to the system is at the point of intersection of the linear equations.

the lines intersect at (- 4, 3 )

then solution is (- 4, 3 )

Answer:

0.1 or 10%

Step-by-step explanation:

Cost: 500

Sell: 550

550-500 = 50

50/500 = 0.1 OR 10%

Therefore, the percentage profit for each sale is 10% of the original wholesale price.

Answer:

10%

Step-by-step explanation:

profit=buyingpirce _selling price

550_500=50

%profit=profit\buyingprice×100

50\500×100=10%

Answer:

33.3333333333

Step-by-step explanation:

we see that there are 6 candies in total

we also see that there is a 50% chance that someone will take out 3 candies of the same color,

50/3 = 16.66666666666667

so the chance of getting 2 marbles of the same color is 16.66666666666667 + 16.66666666666667 which is 33.3333333333

I hope I could help

Answer:

Step-by-step explanation:

The radious is 7 inches, that means the diameter is 14 inches.

The height is 18 inches. so...

V=πr2h=π·72·18≈2770.88472

So hence, your answer is

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Always keep more than 2 smiles so that you can share! Me happy! You happy! EVERYONE HAPPY!

Thanks!

Have a great day!

:D

Answer: 25

Step-by-step explanation: because 50% of 50 is 25

Answer:

160 000

Step-by-step explanation:

400 000 - 240 000 = 160 000

Answer:

[tex]A_{Circle} \approx 39.24\: units^2[/tex]

Step-by-step explanation:

Square ABCD is inscribed in a circle with center P such that BC = 5 units.

BD will be diagonal of the square as well as diameter of the circle.

[tex]BD = BC\times\sqrt 2[/tex]

[tex]\implies BD = 5\sqrt 2[/tex]

-> Diameter of the circle [tex](d) = 5\sqrt 2[/tex]

-> Radius of the circle [tex](r) = 2.5\sqrt 2=3.535\: units[/tex]

[tex]A_{Circle} =\pi(r)^2[/tex]

[tex]\implies A_{Circle} =3.14(3.535)^2[/tex]

[tex]\implies A_{Circle} =3.14(3.535)^2[/tex]

[tex]\implies A_{Circle} =39.2381465[/tex]

[tex]\implies A_{Circle} \approx 39.24\: units^2[/tex]

Answer:

yes

Step-by-step explanation:

Answer: 12,888 in^2 (inches squared)

Step-by-step explanation:

The answer is: Reject H0. There is convincing evidence that the true mean weight of the chlorine tablets in the 50-pound buckets is less than 50 pounds.

Answer:

Step-by-step explanation:

29-9=20

9-(-11)=20

50×-20=-1000

-1000+29=-971