Answer:
1. a) SR = 23
b) QV = 25
c) QT = 20
d) PQ = 40
e) VS = 4·√6
2. a) LH = 16
b) EL = 2·√185
c) JG = 30
d) EK = 22
e) KG = 30
3. a) XT = 37
b) TZ = 34
c) ZW = 17
d) XZ = 21
e) SY = 69
Step-by-step explanation:
The circumcenter ΔPQR is the center of the circle that circumscribes ΔPQR
The length of the radius of the circle ≡ VR = VP = QV = 25
a) Given that VR ≅ VP - Radius of circumcircle
VS ≅ VS Reflective property
∠VPS ≅ ∠VRS - Base angles of an isosceles triangle
Right triangle VPS ≅ Right triangle VRS -Hypotenuse and one Leg HL congruency
Therefore, SR ≅ PS -Corresponding parts of congruent triangles are congruent CPCTC
SR + PS = PR = 46
SR + PS = SR + SR = 2·SR = 46
∴ SR = 46/2 = 23
b) QV = VR = 25 = Radius of circumcircle of ΔPQR -Given V = center and Q = vertices of the triangle circumscribed by the circle referred to in the question
c) QT = √(QV² - TV²) = √(25² - 15²) = √400 = 20
d) TV ≅ TV - Reflexive property of congruency
ΔTQV ≅ ΔTVP - Hypotenuse and one Leg (HL) congruency
QT ≅ TP -Corresponding parts of congruent triangles are congruent CPCTC
PQ = QT + TP Given
∴ PQ = QT + QT since QT = TP
PQ = 2·QT = 2 × 20 = 40
e) VS = √(VR² - SR²) = √(25² - 23²) = √96 = 4·√6
2. The incenter is the center of the incircle of ΔEFG
a) LH = LK = JL = 16 -Radius of incircle of ΔEFG
b) EL = Hypotenuse of right triangle LHE = √(LH² + EH²) = √(16² + 22²) = √740 = 2·√185
c) JG = Leg length of right triangle JGL = √(LG² - JL²) = √(34² - 16²) = √900 = 30
d) EK = Leg length of right triangle LKE = √(EL² - LK²) = √(740 - 256) = 22
e) KG = Leg length of right triangle LKG = √(LG² - LK²) = √(34²- 16²) = √900 = 30
3. Point Z id the centroid of ΔRST
a) XT = XS - point X on ST bisected by median line RX
ST = XT + XS = XT + XT = 2.XT = 74
XT = 74/2 = 37
b) TZ = 2/3×TW - Length from a vertex to the centroid on a median line is equal to two third the length of the median line
TZ = 2/3×51 = 34
c) TZ + ZW = TW
∴ ZW = TW - TZ = 51 - 34 = 17
d) RZ = 42 = 2/3×RX - Length from a vertex to the centroid on a median line is equal to two third the length of the median line
∴ RX = 3/2×42 = 63
RZ + XZ = RX - Given
XZ = RX - RZ = 63 - 42 = 21
e) SZ = 2/3×SY - Length from a vertex to the centroid on a median line is equal to two third the length of the median line
SZ + ZY = SY
∴ ZY = SY - SZ = SY - 2/3×SY = 1/3×SY = 23
Which gives;
SY = 3 × 23 = 69.
I went to the store with $20. After buying all my groceries, I spent $15.87. How much money do I have left?
you would have 4.13 left
20-15.87=4.13
Answer:
The answer is $4.13
Step-by-step explanation:
It is easier to do this if we add two zeros at the end of 20 to make it 20.00 so the decimal places line up. Lets take it one place at a time. first is the hundreths, which is 0-7. This is not possible, so we borrow from the tenths, but the tenths is also a zero. The tenths zero has to borrow from the ones zero. Basically, the 2 in 20 becomes 1, and the zeros in the ones and tenths place become nines, and the last zero becomes 10. 10 minus 7 is 3, 9 minus 8 is 1, 9-5 is 4, and 1-1 is 0.
Hope this helps!
Shane found a website that gives the daily weather report from mars. for 4 days, shane recorded the daily high and low temperatures on mars.use the dropdowns to complete each statement. table of daily high and low temperatures in degrees celsius. on day 1, the low was negative eighty-two; the high was negative twenty-four. on day 2, the low was negative eighty-three; the high was negative twenty-six. on day 3, the low was negative eighty-four; the high was negative twenty-seven. on day 4, the low was negative eighty-four; the high was negative twenty-eight.a. the average temperature on day 2 was blank.b. the difference of the average high temperature and the average low temperature for all four days is blank.c. the day with the greatest average temperature was blank.
The average temperature on day 2 was -54.5.
What is Average?This is usually calculated with the sum of the numbers divided by how many numbers are present.
The average temperature on day 2 = -83-26 /2 = -54.5The difference of the average high temperature and the average low temperature for all four days include the following:Day one = -82-(-24) = -58
Day two = -83-(-26) = -57
Day three = -84-(-27) = -57
Day four = -84-(-28) = -56
The day with the greatest average temperature was Day one = -82-24/2 = -53.
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Answer:
Step-by-step explanation:
hello evryone. please help if you know the answer. donr help if u dont know the answer. ill give brailest to the first person that answers
a WHOLE is always simplified to "1", namely 100/100 = 1, 57/57 = 1 and so on. Well, in this case we have a total of 21 students, so 21/21 is all of them, their "whole", but we also know that 6 of them read about animals and the rest about plants, so
[tex]\stackrel{whole}{\cfrac{21}{21}}\qquad \qquad \cfrac{\stackrel{animals}{6}~~ + ~~\stackrel{plants}{15}}{21}\implies \cfrac{6}{21}~~ + ~~\stackrel{plants}{\cfrac{15}{21}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{15}{21}\implies \cfrac{3\cdot 5}{3\cdot 7}\implies \cfrac{3}{3}\cdot \cfrac{5}{7}\implies 1\cdot \cfrac{5}{7}\implies \boxed{\cfrac{5}{7}}[/tex]
Answer:
I think its 5 over 7
Step-by-step explanation:
because 6-21 equals 15 so 15 is how many read about plants out of the total students at the library which is 21.if you divide 15 over 21 by 3 you get 5 over 7
PLEASE HELP MEEEEE PLEASE ASAP
Twelve people apply for a teaching position in mathematics at a local college. Six have a PhD and six have a master’s degree. If the department chairperson selects three applicants at random for an interview, find the probability that all three have a PhD
Using the hypergeometic distribution, it is found that there is a 0.0175 = 1.75% probability that all three have a PhD.
The applicants are chosen without replacement, hence the hypergeometric distribution is used to solve this question.
What is the hypergeometric distribution formula?The formula is:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.N is the size of the population.n is the size of the sample.k is the total number of desired outcomes.In this problem, the values of the parameters are as follows: N = 20, k = 6, n = 3.
The probability that all three have a PhD is P(X = 3), hence:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 3) = h(3,20,3,6) = \frac{C_{6,3}C_{14,0}}{C_{20,3}} = 0.0175[/tex]
0.0175 = 1.75% probability that all three have a PhD.
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1. a) Solve the following linear-quadratic system of equations graphically.
y + 2x²– 8x – 1= 0
y+ 2x – 9= 0
b.) GRAPH
c.) Verify your solution (s) algebraically.
Answer:
please see explanation
Step-by-step explanation:
look at the photo
How much, in total, did Noel spend to cash her three most recent paychecks?
The total amount of money that was spent by Noel to cash her three (3) most recent paychecks is equal to $10.99.
What is a paycheck?A paycheck can be defined as a financial document that is issued by an employer to an employee as payment for the work done over a period of time.
How to calculate the amount spent.From the table, we can see that the amount of money charged by the bank as check processing fee is equal to $1.99, as well as 1.99% (0.0199) of the amount being cashed by a customer.
Thus, we would compute the amount of money spent by Noel as follows:
Noel = (0.0199 × 100.53) + (0.0199 × 119.38) + (0.0199 × 122.52) + (1.39 × 3)
Noel = 2.00 + 2.38 + 2.44 + 4.17
Noel = $10.99.
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PLEASE HELP A.S.A.P.!
Solve the equation:
|x-1|+|x-2|=3
Consider the system and find the eigenvalues and the eigenvectors
Eigenvalues are the special set of scalar values which is associated with the set of linear equations in matrix equations.
What are Eigenvalues?
Your information is incomplete. Therefore, an overview will be given. An eigenvector of a linear transformation is a nonzero vector that changes by a scalar factor when the linear transformation is applied to it.
The eigenvectors of matrix A are those vectors X for which multiplication by A will result in a vector in thesame direction or opposite direction to X.
Since the zero vector 0 has no direction, 0 is never allowed to be an eigenvector.
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An eigenvector of a linear transformation and eigenvectors of a system
Ax = Bx can be determined where B is an eigenvalue of A.
What are Eigenvalues?An eigenvector of a linear transformation is a nonzero vector that changes by a scalar factor when the linear transformation is applied to it.
The eigenvectors of matrix A are those vectors X for which multiplication by A will result in a vector in the same direction or opposite direction to X.
The basic equation is
Ax = Bx
here B is an eigenvalue of A.
Since the zero vector has no direction, zero is never allowed to be an eigenvector.
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#SPJ4
In what year did the nfl vote to create a $430 million pool of money, funded by the top 15 clubs by revenue to be distributed to the bottom 15 clubs?.
The year in which the NFL voted to create a $430 million fund to help the bottom 15 clubs was 2007.
When did the NFL vote to implement this fund?The NFL voted by a margin of 30-2 in 2007 to create a pool of funds over 3 years that would amount to $430 million.
This money would then be used to help the bottom 15 clubs who might be struggling financially. The hope was that this would make things more competitive in the NFL.
Find out more on the NFL at https://brainly.com/question/7579515.
The vertices of a quadrilateral drawn in a coordinate plane are (-6,6), (4,6), (2,-5), and (-6,-9). what is the length of the side joining the vertex in quadrant i to the vertex in quadrant 11? a) 2 b) 8 c) 10 d) 12
Using the formula for the distance between two points, it is found that the length of the side joining the vertex in quadrant i to the vertex in quadrant ii is given by:
c) 10
What is the distance between two points?Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
In quadrant I, both coordinates are positive, hence the vertex is (4,6). In quadrant II, x is negative while y is positive, hence the vertex is (-6,6). Thus, the distance is given by:
[tex]D = \sqrt{(-6 - 4)^2+(6 - 6)^2} = 10[/tex]
Which means that option C is correct.
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if log7=a and log…
help me solve ths math problem on picture
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: log_{4}(39.2) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{4}( {2}^{3} \times {7}^{2} \times 10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{4}( {2}^{3} ) + log_{4}( {7}^{2} ) + log_{4}(10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{ {2}^{2} }( {2}^{3} ) + log_{ {2}^{2} }( {7}^{2} ) + log_{ {2}^{2} }(10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: \frac{3}{2} log_{2}(2) + \frac{2}{2} log_{2}(7) - \frac{1}{2} log_{2}(10) [/tex]
[tex]\qquad \sf \dashrightarrow \: \frac{3}{2} + a - \frac{b}{2} [/tex]
That's the required result ~
also you can take it's LCM and write it as :
[tex]\qquad \sf \dashrightarrow \: \dfrac{2a - b + 3}{2} [/tex]
A pair of fair dice is cast. What is the probabiliy that one of the numbers falling uppermost is a 5, given that the two numbers falling uppermost are different?.
Using it's concept, it is found that there is a 0.3333 = 33.33% probability that one of the numbers falling uppermost is a 5.
What is a probability?A probability is given by the number of desired outcomes divided by the number of total outcomes.
The outcomes are given as follows:
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
From the list, we have that:
There are 30 outcomes in which the numbers are different.In those, there are 10 in which one 5 appears.Hence, the probability is given by:
p = 10/30 = 0.3333 = 33.33%.
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I need help with this
Answer:
You are correct with B!!
Step-by-step explanation:
(x⁹)²
We have to multiply 9 x 2, regardless of the parenthesis for this one.
9 × 2 is 18.
We cannot simply 18 further.
Carry the x in front of 18.
x¹⁸
Bobby's cat runs x mph. Bobby's dog runs twice as fast as his cat.
If cat and dog start running away from each other how far away from each other will they be after 30 minutes?
The distance they(Bobby's cat and dog) will be from each other after 30 minutes is 0.5x miles.
Calculation of distanceThe dog runs twice as fast as the cat. Therefore,
Bobby's cat speed = x
Bobby's dog speed = 2x
Therefore,
speed = distance / time
30 minutes = 0.5 hours
Therefore,
distance = speed × time
distance covered by the cat = x × 0.5 = 0.5x
distance covered by the dog = 2x × 0.5 = x
Therefore, the distance they will be from each other after 30 minutes is as follows:
distance = x - 0.5x = 0.5x
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Suppose that 25 inches of wire costs 75 cents.
At the same rate, how much (in cents) will 21 inches of wire cost?
Answer:
73 cents
Step-by-step explanation:
first multiply 75×21 and you will get 1575 then divide 1575 by 25 and you get 73 which is 73 cents
Use the graphing calculator to graph the quadratic function y = x2 − 5x − 36. Which value is a solution of 0 = x2 − 5x − 36?
−9
−4
4
6
Answer: -4
Step-by-step explanation:
Once you graph it, the solutions are where the graph meets the x axis.
This is at -4 and 9.
(За + 2b) (2а — b) HELP ME PLEASE
Answer:
6a^2 + ab - 2b^2
Step-by-step explanation:
[insert something smart]
X 12. Find the volume of the composite solid. Use 3.14 for . 5.5 ft Find the volume of the cone using the formula.
Answer: 74.61 ft^3
Step-by-step explanation:
Find the missing coordinate.
x = cos t
y = sin t
(-1, [?])
What is the x to help me
Answer:
116 degrees
Step-by-step explanation:
the shape is 360 degrees in total
64+64 = 128
360-128 = 232
232/2 = 116
This composite figure is created by placing a sector of a circle on a rectangle. What is the area of this composite figure? Show your work.
Answer:
area of the figure: 29.92 m²
formula's:
area of rectangle: length * widtharea of sector: ∅/360 * πr²solving steps:
area of rectangle + area of sector
5.5 * 4 + 30/360 * π(5.5)²
22 + 7.919
29.92 m²
Answer:
Calculate the area of the sector and the area of the rectangle separately, then add them together to determine the area of the composite figure.
Rectangle
Area of a rectangle = width × length
= 4 × 5.5
= 22 m²
Sector
[tex]\textsf{area of sector}=\dfrac{\theta\pi r^2}{360} \textsf{ (when } \theta \textsf{ is measured in degrees)}[/tex]
[tex]=\dfrac{30 \cdot\pi\cdot5.5^2}{360}[/tex]
[tex]=\dfrac{121}{48}\pi \textsf{ m}^2[/tex]
Total area
total area = area of rectangle + area of sector
[tex]=22 +\dfrac{121}{48}\pi[/tex]
= 29.91943148...
= 29.9 m² (nearest tenth)
what is the value of the expression (-2) to the third power (-2) to the second power
Answer:
-2 to the third power is -8
-2 to the second power is -4
Step-by-step explanation:
-2 to the 3 power = -2× -2×-2
-2 to the second power is -2×-2
For what value of x does 3^4x=27^x-3?
0 -9
O-3
O 3
O 9
Answer:
the answer to the value of X is 0-3
Given that lines b and c are parallel, select all that apply.
Which pairs of angles are congruent?
3 and 7
2 and 8
3 and 5
1 and 4
Answer:
3 and 7
1 and 4
Step-by-step explanation:
[3 and 7]
These two angles are prooved congruent by corresponding angles
[1 and 4]
These two angles are prooved congruent by opposite vertical angles.
Which lines are parallel?
red and green
they go in the same direction, side by side, and will never touch
let f(x)=3x+4 and g(x)=2x-5 find (f-g)(x)
Step-by-step explanation:
find; (f-g)(x)
(f(x) - g(x))
f(x) = 3x + 4, g(x) = 2x - 5
3x + 4 - 2x + 5
x +9
A triangle has two sides of length 4 and 2. What is the smallest possible whole-number length for the third side?
Answer:
19
Step-by-step explanation:
**WILL GIVE BRAINLIEST** please help me
Answer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
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ANSWER
Chloe has taken four tests this semester. Her scores on the three tests are 87, 78, and 61. If her test average is 78.5, what is her grade on her 4th test?
n = last test
(87 + 78 + 61 + n) : 4 = 78,5
87 + 78 + 61 + n = 78,5 x 4
n = 314 - 226
n = 88