If Thor throws his axe horizontally at a velocity of 50 m/s at and a height of 20 m, how long does it take before it hits the ground? (gravity is 9.8 m/s^2)

Answers

Answer 1

Answer:

The time taken before the axe hits the ground is 0.385 s.

Explanation:

Given;

initial velocity, u = 50 m/s

height above ground, h = 20 m

To determine the time taken before the axe hits the ground, apply the following kinematic equation;

h = ut + ¹/₂gt²

20 = 50t + ¹/₂(9.8)t²

20 = 50t + 4.9t²

4.9t² + 50t - 20 = 0

Solve this quadratic equation;

a = 4.9, b = 50, c = -20

t = 0.385 s

Therefore, the time taken before the axe hits the ground is 0.385 s.


Related Questions

A tennis racket strikes a tennis ball with a force of 100 N. With what force
does the ball strike the racket? *

Answers

Answer:

-100N

Explanation:

Newton's third law of motion states that to every force exerted on one body, there is an equal and opposite force. This means that if object A exerts an ACTION force on B, there is a force called REACTION FORCE, which is equal and opposite, exerted on A by B.

The action and reaction forces are equal in size/magnitude but opposite in direction. In this case where a tennis racket strikes a tennis ball with a force (action force) of 100N, the ball will strike the racket with a reaction force of -100N.

F(RB) = -F(BR)

A ball is thrown straight up from the ground. Where will the ball have its lowest velocity

Answers

Explanation:

i think it will be on the ground

Use the principle of superposition (Equation 1.3) to predict the electric field at the point 0.5 meters to the right and 1.5 meters above the 5 nC charge. Express your result both in terms of x and y components, and then in terms of total magnitude and direction.

Answers

Answer:

Explanation:

The x component of electric field Ex = k Q / R²

= 9 x 10⁹ x 5 x 10⁻⁹ / .5²

= 180 N .

The y component of electric field Ey = k Q / R²

The y component of electric field Ey

= 9 x 10⁹ x 5 x 10⁻⁹ / 1.5²

= 20 N

Total field = [tex]\sqrt{180^2+20^2}[/tex]

= 181.1 N .

Angle with x axis = Tanθ = Ey / Ex = 20 / 180 = .111

= 6.33⁰

Clouds in our atmosphere cause us to see the different phases of the moon.

True

False

Answers

Answer:

False

Explanation:

:)

Answer:

The answer is false

Explanation:

The clouds have nothing to do with the changes in the phases of the moon but, rather the postioning of the sun and the moon regarding revolution and the spinning of the earth on it axis.

I hope this helps you good luck and have a good day.

The temperature of a 5.0 kg block increases by 3 degrees C when 2,000 J of thermal energy are added to the block. What is the specific heat of the block? _____________

Answers

Sorry bro I just need points for my calculus exam

A distance of 2.5 meters separates two similar balls of mass 0.70 kg each. Calculate the force of gravity between the two balls.

Answers

Answer:

2

Explanation:

PLEASE HELP!! ILL MARK BRAINLYEST!!!

A chemical change occurs when a substance changes phase.


True
False

Answers

Answer:

False

Explanation:

Miguel added 150 grams of baking soda to a liter of water at 20 °C. No matter how long he keeps stirring the solution, he can’t get all of the baking soda to dissolve. Explain why.

Answers

Answer:

See the answer below

Explanation:

This is because, at 20 °C, the solution has become saturated with the baking soda.

The solubility of a substance is the maximum amount of that substance that will dissolve in a particular solvent at a given temperature. The solubility of a substance generally increases with an increase in temperature.

At 20 °C temperature, the maximum amount of baking soda that can dissolve in a liter of water has been exceeded by Miguel. Hence, no matter how hard he tries to stir the solution, the excess baking soda will not dissolve.

The reason he can’t get all of the baking soda to dissolve is; because at 20 °C, the solution has become saturated with the baking soda.

What is a saturated solution?

For us to say a substance is soluble, it means that the maximum amount of that substance will dissolve in a particular solvent at a given temperature. Thus, the solubility of a substance is said increase with a corresponding increase in temperature.

From the question, at 20 °C temperature, miguel has exceeded the maximum amount of baking soda that can dissolve in a liter of water. Therefore, no matter how hard he tries to stir the solution, it will not dissolve due to the excess soda.

Read more about saturated solution at; https://brainly.com/question/4529762

PLSSS HELP ITS URGENT ILL RATE YOU BRAINLIEST:) A truck whose bed is 4 m long, 2.2 m wide, and 1.0 m high is delivering sand for a sand-sculpture competition. About how many trips must the truck make to deliver 23 m^3 of sand?

Answers

Answer:

one truck load is 2.5*1.5*1 = 3.75m^3

7/3.75 = 1.86 loads,

so 2 trips must be made.

Explanation:

how does the initial velocity affect the final velocity

Answers

Answer:

Initial velocity is independent of the slope of the graph; that is, the acceleration. An object thrown downward still accelerates after release at the same rate as an object that is dropped.

!PLEASE HELP PLEASE!Why is wax the same suspense when it melts from a candle?
(Even though wax melts from a candle, it is still the same substance. Why is that?)

Answers

Answer:

it is the same substance because it didn't change the process of that it was it just changed its state for would to liquid

A rescue pilot wishes to drop a package of emergency supplies so that it lands as close as possible to a target. If the plane travels with a velocity of 18 m/s and is flying 225 m above the target, how far away (horizontally) from the target must the rescue pilot drop the package?

Answers

Answer:

x = 121.86 m

Explanation:

It is given that,

The vertical velocity of a plane, [tex]v_x=18\ m/s[/tex]

It is flying above the target, h = 225 m

First we will find the time taken by the plane to reach the ground. It can be calculated using the second equation of motion as follow :

[tex]h=ut+\dfrac{1}{2}at^2[/tex]

Here, u = 0 and a = g

[tex]h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 225}{9.81}} \\\\t=6.77\ s[/tex]

Let x is the horizontal distance from the target. It can be calculated as follows :

[tex]x=v_xt\\\\x=18\times 6.77\\\\x=121.86\ m[/tex]

So, the rescue pilot drop the package at a distance of 121.86 m from the target.

A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motion model, h = -16t2 + v … t +s, where y is the initial velocity in feet per second and s is the height in feet, to calculate the amount of time the baseball is in the air before it hits the ground.

Answers

Answer:

t = 3.25 seconds.

Explanation:

A person throws a baseball from a height of 7 feet with an initial vertical velocity of 50 feet per second is given by :

[tex]h=-16t^2+vt+h_0[/tex]

[tex]h=-16t^2+50t+7[/tex]

We need to find the amount of time the baseball is in the air before it hits the ground. ATQ,

h = 0

[tex]-16t^2+50t+7=0\\\\t=\dfrac{-50 \pm \sqrt{50^2-4\times (-16)(7)} }{2(-16)}\\\\t=\dfrac{-50 + \sqrt{50^2-4\times (-16)(7)} }{2(-16)}, \dfrac{-50- \sqrt{50^2-4\times (-16)(7)} }{2(-16)}\\\\t=-0.134\ s,3.25\ s[/tex]

Neglecting negative value, t = 3.25 s

So, the baseball will hit the ground at t = 3.25 seconds.

NEED HELP ASAP!!!

If 100 newtons of force are applied over a distance of 50 meters for 5 seconds, how much power is used
2,500 watts
1,000 joules
10 watts
1,000 watts

Answers

Answer:

2,500 watts

Explanation:

I got this answer right on a test. I hope it works for you to.

Answer:

2500 wats

Explanation:

does changing position of charges change the magnitude

Answers

Answer:

No, they will not change.

Explanation:

Help. Please! I really need help. It’s timed, and I’m loosing points.

Answers

Answer:

I think balanced

Explanation:

because there is a 2 on each arrow

Answer I'm thinking balanced as well

Explanation:

PLEASE HELP!!
A player punts a football at an angle of 30 degrees. The football has an initial
velocity of 20.0 m/s. Find the y-component of the ball's velocity.
17.3 m/s
O 10.0 m/s
O 30.0 m/s
0 25.1 m/s

Answers

Answer:

The y-component of the ball's velocity is 10 m/s

The second choice 10.0 m/s is correct

Explanation:

Projectile Motion

It's the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the magnitude of the initial velocity and θ the angle it makes with the horizontal, the components of the initial velocity are calculated as follows:

[tex]v_{ox}=v_o.\cos\theta[/tex]

[tex]v_{oy}=v_o.\sin\theta[/tex]

Since the football is kicked at vo=20 m/s and an angle of θ=30°:

[tex]v_{oy}=20.\sin 30^\circ[/tex]

[tex]v_{oy}=20*0.5=10[/tex]

The y-component of the ball's velocity is 10 m/s

The second choice 10.0 m/s is correct

A ball is thrown vertically upward with an initial velocity of 29.4 m/s². What is the maximum height reached by the ball? How long is the ball in the air? What is the final velocity of the ball before it goes back to its original position?​

Answers

Answer:

Most likely it will reach 29.4 up in the air before coming back down.

Explanation:

The force of the ball will be the same on how high it will go.

what is torricellian vaccum

Answers

Answer:

a vacuum formed above the column of mercury in a mercury barometer.

Answer:

An air-free space above the free surface of a liquid in a vessel that is closed above the liquid

1 point
An Arizona solar power plant is able to produce 24 megawatts, which
serves 6,000 homes. How many watts per home?
40 W
О
400 W
4,000 W
40,000 W

Answers

the answer is 4,000 because there are 1 million watts per mega wat so 24x1,000,000 = 24,000,000 / 6,000= 4,000

Which statement best expresses Newton's second law of motion?

A: The acceleration of an object depends on the balance between the net applied forces.

B: The acceleration of an object depends on the balance between friction and gravity.

C: The acceleration of an object depends on the object's mass and the net applied force.

D: The acceleration of an object depends on the object's mass and its velocity.

Answers

Answer:

option C

since F=ma

the acceleration of an object depends on the object's mass and the net applied force

why does nobody love me?

Answers

Answer: I’m sure theirs people out there that like you, and if there isn’t, you should just focus on yourself.

Explanation:

Answer:

Well, There are a couple reasons it could seem like nobody loves you...

Explanation:

One reason is that people really do love you, they just were never shown love and affection so they are unsure of how to show that to you. Another reason could be that it's god telling you that you are meant for much bigger and greater things. Maybe it's him reminding you that, yeah, people really suck, but that's life, and you're better than that. If you make the right decisions in life, you will be able to stand taller than they ever did. I hope this helps.. : )

Please help A.S.A.P
What would you expect to see on intrusive igneous rocks compared to extrusive igneous rocks?

Answers

Answer:

Intrusive igneous rocks cool from magma slowly because they are buried beneath the surface, so they have large crystals. Extrusive igneous rocks cool from lava rapidly because they form at the surface, so they have small crystals. Texture reflects how an igneous rock formed

Explanation:

F all of the energy in a falling object's gravitational potential energy store is transferred to its kinetic energy store by the time it lands, then the relationship shown below can be used. Which of the four options below it correctly shows how this relationship can be expressed in terms of height, h?

Answers

Answer:

The options are not shown, so let's derive the relationship.

For an object that is at a height H above the ground, and is not moving, the potential energy will be:

U = m*g*H

where m is the mass of the object, and g is the gravitational acceleration.

Now, the kinetic energy of an object can be written as:

K = (1/2)*m*v^2

where v is the velocity.

Now, when we drop the object, the potential energy begins to transform into kinetic energy, and by the conservation of the energy, by the moment that H is equal to zero (So the potential energy is zero) all the initial potential energy must now be converted into kinetic energy.

Uinitial = Kfinal.

m*g*H = (1/2)*m*v^2

v^2 = 2*g*H

v = √(2*g*H)

So we expressed the final velocity (the velocity at which the object impacts the ground) in terms of the height, H.

Will give brainliest, 25 points:
A cannonball is launched straight up from the ground at 13.5 m/s. How much time is the cannonball in the air (hangtime)?

Answers

Answer:

Time in air t = 1.38 second (Approx)

Explanation:

Given:

Initial speed u = 0 m/s

Final speed v = 13.5 m/s

Find:

Time in air t

Computation:

v = u + gt

g = 9.8 m/s²

13.5 = 0 + (9.8)(t)

13.5 = 9.8 t

t = 13.5 / 9.8

t = 1.3777 second

Time in air t = 1.38 second (Approx)

How plants are in the
Solora System

Answers

8 not counting Pluto 9 if counting Pluto, Pluto is technically not a planet anymore so best dentures 8.

Answer:

there was 9 but pluto got kicked out of the solar System so 8

A volcano erupts, and a chunk of hot magma is launched horizontally with a speed of 208\,\dfrac{\text m}{\text s}208 s m ​ 208, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction from a height of 94\,\text m94m94, start text, m, end text. We can ignore air resistance.

Answers

Answer:

a. 42.92 m/s b 4.4 s c. 915.2 m

Explanation:

Here is the complete question

A volcano erupts, and a chunk of hot magma is launched horizontally with a speed of  ​ 208 m/s, from a height of 94 m. We can ignore air resistance.

What is the vertical velocity of the magma when it hits the ground?

Solution

a. Using v² = u² - 2gy since it is motion under gravity, where u = initial vertical velocity = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and y =  height = 94 m.

Substituting these values into the equation, we have

v² = u² - 2gy

v² = 0² - 2 × (-9.8 m/s²) × 94 m

v² = 1842.4 m²/s²

v = √1842.4 m²/s²

v = 42.92 m/s

b. We also find the time it takes to drop from the height of 94 m from

y = ut - 1/2gt² , u = 0

So, t = √(2y/g)

= √(2 × 94 m ÷ 9.8 m/s²)

= √19.184 s²

= 4.4 s

c. The horizontal distance the chunk of hot magma covers is thus x = Vt where v = horizontal velocity = 208 m/s

x = 208 m/s × 4.4 s = 915.2 m

Answer:

that's wrong its 911

Explanation:

trust me

3- The velocity-time graph below shows the motion of a
ball in free fall. What is the acceleration of the ball from
0.5 to 0.7 seconds? Show your work:

Answers

Answer:

The acceleration of the ball from 0.5 to 0.7 seconds is 10 m/s²

Explanation:

The data from the given velocity-time graph are as follows;

Velocity (meters per second)       [tex]{}[/tex]                       Time (seconds)

0                                                    [tex]{}[/tex]                          0.4

0.5                                                   [tex]{}[/tex]                        0.45

1.                                                 [tex]{}[/tex]                             0.5

1.5                                                   [tex]{}[/tex]                         0.55

2.2                                                   [tex]{}[/tex]                        0.6

2.5                                                   [tex]{}[/tex]                        0.65

3.0                                                   [tex]{}[/tex]                        0.7

3.5                                                   [tex]{}[/tex]                        0.75

4.0                                                   [tex]{}[/tex]                        0.8

4.5                                                   [tex]{}[/tex]                        0.85

Therefore, the average acceleration of the ball from 0.7 to 0.7 seconds is given as follows;

Acceleration = (Change in velocity)/(Related change in time)

Acceleration = (3.0 - 1)m/s/(0.7 - 0.5)s = 2/0.2 m/s²  = 10 m/s²

The acceleration of the ball from 0.5 to 0.7 seconds = 10 m/s².


An object is dropped from rest.
Calculate its velocity after 2.5 seconds

Answers

Velocity = 9.8 x 2.5 = .... m/s

Which option is an example of a surface wave?
A. A light wave
B. A wave on top of water
C. A sound wave
D. A wave carried through a rope

Answers

The answer is B hope it helps

Surface waves are winds blowing through the  surface of ocean water. Therefore, option B is correct. All other options are just examples of waves and not wind.

What are surface waves ?

Ocean water flows in currents, much like air does in the atmosphere. A current is an oceanic current, or stream, of flowing water. The primary cause of surface currents is wind, although not daily winds.

The main wind belts are what produce surface currents. These winds always blow in the same direction. so that they can maintain the direction of the water's flow.

Three factors influence surface currents: global wind patterns, Earth's rotation, and the configuration of ocean basins. Because they disperse heat over the earth, surface currents are crucial. Global climate is significantly influenced by surface currents as well.

Find more on surface waves:

https://brainly.com/question/13779567

#SPJ5

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