if the speed of a car is increased by 50%, bywhat factor will its minimum braking distance be increased, assuming all else is the same?

Their combined speed will be 1m/s

Given the following parameters;

If the player collides and stick together, the combined speed is expressed as;

Hence their combined speed will be 1m/s

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hope it's help

Answer:

you ask or answer?

Explanation:

thanks for point

Answer:

not able to understand the question

This question involves the concepts of the equations of motion in vertical direction.

The height of the bridge is "116.8 m".

We will use the second equation of motion in vertical direction to find out the height of the bridge.

[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]

where,

h = hieght = ?

vi = initial speed = 0 m/s

t = time taken = 4.88 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]

h = 116.8 m

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The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:

The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:

Indicate in  the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.

Vector A.

         Aₓ = 100.0 m  

Vector B.

         B_y = -300.0 m  

The negative sign indicates that it goes in the negative direction of the y-axis

Vector C.

We use trigonometry.

The angle measured from the positive side of the x-axis counterclockwise is

        θ = 180 + 30 = 210

        sin 210 = [tex]\frac{C_y}{C}[/tex]

        cos 210 = [tex]\frac{C_x}{C}[/tex]

        C_y = C sin 210

        Cₓ = C cos 210

         C_y = 150.0 sin 210 = -75.0 m

         Cₓ = 150.0 cos 210 = -129.9 m

Vector D.

The angle from the positive side of the x-axis counterclockwise.

        θ = 180-60 = 120º

       sin 120 = [tex]\frac{D_y}{D}[/tex]  

       cos 120 = [tex]\frac{D_x}{D}[/tex]  

       D_y = D sin 120

       Dₓ = D cos 120

       D_y = 200.0 sin 120 = 173.2 m

       Dₓ = 200.0 cos 120 = -100.0 m

we add the component with algebraic sum.

       x = Aₓ + Cₓ + Dₓ

       y = B_y + C_y + D_y

       x = 100 - 129.9 -100 = -129.9 m

       y = -300 - 75.0 + 173.2 = -201.8 m

We construct the resulting vector.

We use the Pythagorean theorem for the Modulus.

       [tex]R+ \sqrt{x^2 +y^2}[/tex]  

       R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]  

       R = 239.99 m

We use trigonometry for the angle.

      tan  θ = [tex]\frac{y}{x}[/tex]

       θ = [tex]tan^{-1} \frac{y}{x}[/tex]  

       θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)

       θ = 57.2º

Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.

          θ = 270 - θ'

          θ = 270 - 57.2

          θ = 212.8º

In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:

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Answer:

1.67m

5m/s

Explanation:

Wavelength of the wave = 3m

Speed of the wave  = 5m/s

The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.

 To find the frequency ;

        V = f∧

V is the speed of the wave

f is the frequency

∧ is the wavelength

  Insert the parameters and find the frequency;

        f  = V/ ∧   = 5 / 3  = 1.67Hz

The rate at which the wave passed a given point is the speed of the wave and it is 5m/s

Answer: 300N

Explanation:

Impulse= Mass * Velocity

F.T = M * V

F= MV/T

F= (0.15*20)/ 0.01

F= 300N

Using Newton's second law

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow 300=2m[/tex]

[tex]\\ \sf\Rrightarrow m=150kg[/tex]

Hey there!

The formula of “mass” in physics is:

m = F/a

Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.

mass = 300 Net force/2 acceleration

300 Net force/2 acceleration = m

mass = 150

Therefore, your answer is: 150 kg

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

Scientific investigation is a quest to find the answer to a question using the scientific method.

Explanation:

the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.

the answer is c, inherited traits are controlled by genes, which are found in chromosomes

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]

[tex]\\ \sf\longmapsto s=55+121[/tex]

[tex]\\ \sf\longmapsto s=176m[/tex]

Answer:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

Answer:

Hello There!

It is Speed.

[tex]\Large\bold\red{Reason}[/tex]

Because in the question it is said that at which speed car is travelling.

Speed is a scalar quantity.

If it is velocity then first know this that it is a vector quantity.

It must include both magnitude and direction.

If it is velocity then it would be 40 mph east or west or north or south.

Answer:

1.1x10¹⁶ kg

Explanation:

Let m =  mass of asteroid y.

Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.

Given:

F = 6.2x10⁸ N

d = 2100 km = 2.1x10⁶ m

Note that

G = 6.67408x10⁻¹¹ m³/(kg-s²)

The gravitational force between the asteroids is

F = (G*m*(m/3))/d² = (Gm²)/(3d²)

or

m² = (3Fd²)/G

    = [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))

   = 1.229x10³² kg²

m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)

Answer:

So as two objects are separated from each other, the force of gravitational attraction between them also decreases. If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).

Explanation:

hope his helps

Answer:

Answer: B. Explanation: For an object to accelerate the force on it must be increased. According to Newton's second law of motion.

Explanation:

I do Accelerate to good luck

[tex]it \: was \: helpful \: to \: you[/tex]

# be careful#

Answer:1590 N

Explanation:

Impulse =  change in momentum/time

change in momentum = 0 - 50 x 35 = -1750

-1750/1.1 = 1590 (3s.f.) N

Answer:

373.15 Kelvin

Explanation:

Boiling Point of water

= 100 degree Celsius

= (100 + 273.15) Kelvin

= 373.15 Kelvin

Answer: D

Explanation: moogle helps lol.

Answer:

6 kg.m/s

Explanation:

Momentum is the product of mass and velocity. So,

Here,

→ p = 5 kg × 1.2 m/s

→ p = (5 × 1.2) kg.m/s

→ p = (5 × 12/10) kg.m/s

→ p = 12/2 kg.m/s

→ p = 6 kg.m/s

Therefore, momentum of the object is 6 kg.m/s.

The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

Momentum of a substance is the product of its mass and velocity. That is;

Momentum (p) = mass (m) × velocity (v)

According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:

Momentum = 5kg × 1.2m/s

Momentum = 6kgm/s.

Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

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Answer:

Well, I think you're talking about kinematics, especially uniform rectilinear motion. We know that there is a specific equation for that:

S = Vt + S0

With S being the distance, V the velocity, t the time and S0 the initial distance (initial displacement).

From this you can calculate t, if that's what you want.

Answer:

1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time

2. 36÷4= 9

(formula) Speed = distance ÷ time

3. Meter (M) centimeter (cm) kilometers (km)

4. Seconds , Hour, Minute

5. 65÷13=5 (object A)

125÷ 25= 5 (object B)

their both Equal of the amount of speed, so they are travelling at the same speed

Hope I helped

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

[tex]V_x = Vcos(\theta)[/tex]

Substituting the given parameters into the formula, we have;

[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]

Horizontal component, Vx = 15 m/s

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Answer:

Approximately [tex]6.59\times 10^{3}\; \rm m\cdot s^{-1}[/tex].

Explanation:

Look up the radius of the earth: approximately [tex]6.371 \times 10^{3}\; \rm km[/tex].

The radius of the orbit of this satellite is the of the radius of the earth (at ground level) plus the height of the satellite relative to ground level:

[tex]\begin{aligned}r &\approx 6.371 \times 10^{3}\; {\rm km} + 550\; {\rm km} \\ &= 6.921 \times 10^{3}\; \rm km\end{aligned}[/tex].

Convert the units of both distance and time to standard units:

Orbital radius:

[tex]\begin{aligned}r &\approx 6.921 \times 10^{3}\; {\rm km} \\ &= 6.921 \times 10^{3}\; {\rm km} \times \frac{10^{3}\; \rm m}{1\; \rm km} \\ &= 6.921 \times 10^{6}\; \rm m\end{aligned}[/tex].

Orbital period:

[tex]\begin{aligned}t &= 110\; \text{minute} \\ &= 110\; \text{minute} \times \frac{60\; \text{second}}{1\; \text{minute}} \\ &= 6.6 \times 10^{3}\; \text{second}\end{aligned}[/tex].

Calculate the circumference of this orbit:

[tex]\begin{aligned}& 2\, \pi\, r \\ \approx\; & 2 \, \pi \times 6.921 \times 10^{6}\; {\rm m} \\ \approx\; & 4.35 \times 10^{7}\; \rm m\end{aligned}[/tex].

Calculate the orbital speed (tangential) of this satellite:

[tex]\begin{aligned}v &= \frac{2\, \pi\, r}{t} \\ &\approx \frac{4.35 \times 10^{7}\; \rm m}{6.6 \times 10^{3}\; \rm s} \\ &\approx 6.6 \times 10^{3}\; \rm m \cdot s^{-1}\end{aligned}[/tex].

The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.

Given to us,

the charge [tex]q[/tex] =  [tex]5\times 10^{-7}[/tex] C,

the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex]  m/sec,

the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,

angle between the direction of v and B [tex]\theta[/tex] = 0,

Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by

[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]

Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N

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Hi there!

We can begin by solving for the velocity in which the ball was thrown at using the following:

[tex]v_f^2 = v_i^2 + 2ad[/tex]

At the top of the trajectory, the ball's velocity is equal to 0 m/s, so:

[tex]0 = v_i^2 + 2ad\\\\vi^2 = 2ad \\\\[/tex]

'a' = acceleration due to gravity and 'd' is the max height, so:

[tex]v_i^2 = 2(10)(5)\\\\v_i^2 = 10 m/s[/tex]

Now, we can use the same equation to calculate the final speed at 4.5 m. Remember, the acceleration is NEGATIVE in this instance (taking the negative direction to be in the direction of gravity).

[tex]v_f^2 = 10^2 - 2(10)(4.5)[/tex]

[tex]v_f^2 = 10^2 - 2(10)(4.5)\\\\v_f^2 = 100 - 90 \\\\v_f^2 = 10 \\\\v_f = \boxed{3.1 m/s}[/tex]