If the perimeter of the triangle shown below is 48x + 9, what is the length of the missing side? 4x+2 3x – 9 NEED ANSWER ASAP​

Answer:

1080 seconds.

Step-by-step explanation:

There are 60 seconds in a minute. As provided in the question, Lillian spent eighteen minutes, so 18x60=1080.

Answer:

1,080 seconds

Step-by-step explanation:

Answer:

it would range between 11.28379... to 13.819765...

Step-by-step explanation:

the circle's area formula is pi * radius^2

so you make to equation, plugging the 100 and 150 into the circle's area

you get square root of (100/pi) which gets 11.28379... for the area of 100

you do the same with 150 to get square root of (150/pi) which gets 13.819765...

those are the diameter of the circle since the diameter is double the radius which i already multiplied afterwards. so if you need the radius divide the number ive given you

The distance of AB is 42.04 units, BC is 35.77 units and CA is 34.5 units.

We have,

The length along a line or line segment between two points on the line or line segment.

The coordinates of A are (-18, -18)

coordinates of B are (20, 0)

coordinates of C are (-12, 16)

The formula for distance is Distance=√(x₂-x₁)²+(y₂-y₁)²

Distance AB=√(20-(-18))²+(0-18)²

=√(20+18))²+(0-18)²=√38²+18²

AB=√1444+324

    =√1768

    =42.04 units

Distance BC=√(-12-20)²+(16)²

=√(-32)²+(16)²=√1024+256

=√1280

=35.77

Distance CA=√(-12-(-18))²+(16+18)²

=√(6)²+(34)²

=√36+1156=34.5

Hence, the distance of AB is 42.04 units, BC is 35.77 units and CA is 34.5 units.

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complete question:

PLease help me find the distance between AB BC and CA please help

Answer:

Step-by-step explanation: first one way that you can answer this question is to use a numberline, so you start at zero and go to the left of the numberline and the numbers behind -7 would be -8,-9, and or ,-10 they are all less than negative seven

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{5 \dfrac{5}{8}\times 4\dfrac{5}{6}}\\\\\mathsf{= \dfrac{5\times6+5}{8}\times\dfrac{4\times6+5}{6}}\\\\\mathsf{= \dfrac{45}{8}\times \dfrac{29}{6}}\\\\\mathsf{= \dfrac{45\times29}{8\times6}}\\\\\mathsf{= \dfrac{1,305}{48}}\\\\\mathsf{= \dfrac{1,305\div3}{48\div3}}\\\\\mathsf{= \dfrac{435}{16}\approx 27 \dfrac{3}{16}}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{27\dfrac{3}{16}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer: x = 2/23

Step-by-step explanation:

[tex]46x-23x=2[/tex]

[tex]\mathrm{Add\:like\:terms:}\:46x-23x=23x[/tex]

[tex]23x=2[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}23[/tex]

[tex]\frac{23x}{23}=\frac{2}{23}[/tex]

[tex]$$Simplify[/tex]

[tex]\bold{x=\frac{2}{23}}[/tex]

Answer:

Step-by-step explanation:

Inthis question we are given with one equation that is 46x - 23x = 2 and we have asked to find the value of x or solve for x .

So , from here we are solving :

[tex] \longmapsto \: 46x - 23x = 2[/tex]

Step 1 : Taking 23x common at left hand side :

[tex] \longmapsto \: 23x(2 - 1) = 2[/tex]

Step 2 : Subtracting 1 with 2 :

[tex] \longmapsto \:23x = 2[/tex]

Step 3 : Transposing 23 to right hand side :

[tex] \longmapsto \: \red{ \boxed{x = \frac{2}{23} }}[/tex]

Verifying the answer :

We are verifying our answer by substituting the value of x in the given equation .

[tex] \longmapsto \: 46(\frac{2}{23}) - 23( \frac{2}{23} ) = 2[/tex]

Now , calculating :

[tex] \longmapsto \: \cancel{46}(\frac{2}{ \cancel{23}}) - \cancel{23}( \frac{2}{ \cancel{23}} ) = 2[/tex]

[tex] \longmapsto \: 4 - 2 = 2[/tex]

[tex] \longmapsto \: 2 = 2[/tex]

[tex] \longmapsto \: L.H.S = R.H.S[/tex]

[tex] \longmapsto \: Hence, \: Verified . \: [/tex]

Answer: here

Step-by-step explanation:

−21−24

Answer: negative 21 Negative 224

-21-24

A straight line is 180 degrees in measure

The straight line is made up of three angles

           --> angle 1

           --> angle 2

           --> angle with a little square on it

                     (angle with a little square means it is 90 degrees in measure)

Let's set up an equation

    [tex]angle1 + angle2 + 90 = 180\\angle1 + 87 + 90 = 180\\angle1 = 3[/tex]

Thus angle 1 is 3 degrees or the second choice

Hope that helps!

The volume of the three-dimensional figure is 3.75 yd³, and it can hold 7500 pounds of soil

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of the three dimensional shape is:

Volume = length * width * height = 1 1/4 * 1 1/2 * 2 = 3.75 yd³

1 yd³ = 2000 pounds

3.75 yd³ = 2000 pounds * 3.75 yd³ = 7500 pounds

The volume of the three-dimensional figure is 3.75 yd³, and it can hold 7500 pounds of soil

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Answer:

[tex]x-2y+3=0[/tex]

Step-by-step explanation:

Equation of a circle:  [tex](x-h)^2+(y-k)^2=r^2[/tex]

(where (h, k) is the centre, and r is the radius)

Given equation: [tex](x-3)^2+(y+2)^2=20[/tex]

Therefore, the centre is (3, -2) and the radius is √20

To find the equation of the tangent

The tangent of a circle is perpendicular to the radius at the point.

Therefore, first find the gradient (slope) of the line that passes through the centre of the circle and the given point.

[tex]\textsf{let}\:(x_1,y_1)=(1,2)[/tex]

[tex]\textsf{let}\:(x_2,y_2)=(3,-2)[/tex]

[tex]\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-2-2}{3-1}=-2[/tex]

If two lines are perpendicular to each other, the product of their gradients will be -1.

Therefore, the gradient of the tangent is:  

[tex]m_t \cdot-2=-1\implies m_t=\dfrac12[/tex]

Now use the point-slope formula of a linear equation to find the equation of the tangent:

[tex]\implies y-y_1=m_t(x-x_1)[/tex]

[tex]\implies y-2=\dfrac12(x-1)[/tex]

[tex]\implies 2y-4=x-1[/tex]

[tex]\implies x-2y+3=0[/tex]

Answer:

[tex]x= \dfrac 72, ~~y= -2[/tex]

Step by step explanation:

[tex]4x+5y=4~~~...(i)\\\\2x-y=9~~~...(ii)\\\\\text{Multiply eq (ii) by 2 to isolate x:}\\\\4x-2y=18~~~.....(iii)\\\\(iii)-(i):\\\\4x-2y-4x-5y=18-4\\\\\implies -7y=14\\\\\implies y = -\dfrac{14}7 = -2\\\\\text{Substitute}~ y=-2~ \text{in equation (iii):}\\\\4x-2(-2) = 18\\\\\implies 4x +4 = 18\\\\\implies 4x = 18-4\\\\\implies 4x = 14\\\\\implies x = \dfrac{14}4 = \dfrac 72\\\\\text{Hence}~ (x,y) =\left(\dfrac 72 , -2 \right)[/tex]

Step-by-step explanation:

4x+5y=4 (equation 1)

2x-y=9 (equation2)

solving equation 1 and 2 and multiplying equation 2 by 2

4x+5y=4

4x-2y=18

- + -

________

7y= -14

y= -2

putting the value of y in equation 2

2x-y=9

2x+2=9

2x=7

x=3.5

Answer:

1 Shirt and 185cm remaining cloth

Step-by-step explanation:

2m and 15cm = 215cm

40m = 400cm

400/215=1.860465116

A shirt cant be in decimal so we remove the decimals, and take the as the answer. For the decimals, they are the remaining cloth.. to calculate the amount of remaining cloth we do:

1.860465116-1

=860465116

215*860465116=185cm

Answer:

3286714

Step-by-step explanation:

Let the digits of the number be :

Our given conditions :

Solving :

Solution :

So, the number is :

Answer:

692ft3

Step-by-step explanation:

Surface area of the rectangular prism;

SA = lw(2) + wh(2) + hl(2)

SA = 15(5)(2) + 5(8)(2) + 8(15)(2)

SA = 150 + 80 + 240 =

SA = 470ft3

Surface area of the triangular prism

SA = (S1 + S2 + S3) l + bh

SA = (9 + 9 + 11) 5 + 11(7)

SA = (29) 5 + 11(7)

SA = 145 + 77

SA = 222ft3

Add both the SA's

470ft + 222ft = 692ft3

Presumably you mean the second derivative of y with respect to x, d²y/dx².

Compute the first derivative. By the chain rule,

[tex]\dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{dy}{dt}}{\frac{dx}{dt}}[/tex]

Differentiate the two parametric equations with respect to t :

[tex]x = \sin(t) \implies \dfrac{dx}{dt} = \cos(t)[/tex]

[tex]y = \cos(t) \implies \dfrac{dy}{dt} = -\sin(t)[/tex]

Then the first derivative is

[tex]\dfrac{dy}{dx} = \dfrac{-\sin(t)}{\cos(t)} = -\tan(t)[/tex]

Now, dy/dx is a function of t, so we can denote it by, say, dy/dx = f(t). Then by the chain rule, the second derivative will be

[tex]\dfrac{d^2y}{dx^2} = \dfrac{df}{dx} = \dfrac{df}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{df}{dt}}{\frac{dx}{dt}}[/tex]

Differentiating f(t) :

[tex]f(t) = -\tan(t) \implies \dfrac{df}{dt} = -\sec^2(t)[/tex]

Then the second derivative is

[tex]\dfrac{d^2y}{dx^2} = \dfrac{-\sec^2(t)}{\cos(t)} = \boxed{-\sec^3(t)}[/tex]

and since y = cos(t), we can go on to say

[tex]\dfrac{d^2y}{dx^2} = -\dfrac1{y^3}[/tex]

Step-by-step explanation:

Is this helpful to you

support me

Answer:

40

Step-by-step explanation:

Answer:

Step-by-step explanation:

2x + 3y = -7

7x + 9y = -14

-3(2x+3y= -7) = -6x - 9y = 21

-6x - 9y = 21

7x + 9y = -14

add columns (y values cancel)

1x + 0y = 7

x = 7

plug 7 into the x value in either equation to find y

2(7) + 3y = -7

14 + 3y = -7

3y = -21

y = -7

(x,y) = (7,-7)

Answer:

there would be around 40,000 colony of bats

There to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.

An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.

y = a(1+r)ˣ,

where a is the initial population and r is the rate in decimals and x is the time period.

To solve this problem, we need to use the formula for exponential growth:

N = N₀ (1 + r)ˣ

where:

N is the final number of bats after x years

N₀ is the initial number of bats

r is the annual growth rate (expressed as a decimal)

x is the number of years.

We can use the information given in the problem to find the values of N0, r, and t for the first two time periods:

For the first 4 years:

2025 = N₀(1 + r)⁴

For the next 2 years (6 years in total):

18225 = N₀ (1 + r)⁶

To solve for N₀ and r, we can divide the second equation by the first equation:

18225/2025 = (N₀ (1 + r)⁶) / (N₀(1 + r)⁴)

9 = (1 + r)²

Taking the square root of both sides, we get:

1 + r = 3

r = 2 (since r is expressed as a decimal)

Now that we know r, we can use either of the two original equations to find N₀. Let's use the first equation:

2025 = N₀(1 + 2)⁴

2025 = N₀(81)

N₀ = 25

So the initial number of bats was 25, and the annual growth rate is 200% (or 2 as a decimal).

Now we can use the formula to find the number of bats after 12 years:

N = 25 (1 + 2)¹²

N = 25 (531441)

N = 13,286,025

Therefore, we can expect there to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.

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Answer:

Parallel lines never intersect. Perpendicular lines are lines that intersect.

Step-by-step explanation:

Hope this helps.

Answer:

Perpendicular lines meet at a 90 degree angle while parallel lines will never touch

Step-by-step explanation:

Answer:

A. x=3 2.3

B . x=8

C. x=i do not know.

D. x=26

Step-by-step explanation:

A. -3+2/3=2

-3+2/3=-2 1/3

-2 1/3+3 2/3.=2

B. -3-3n=1

-3-3=-6n

-6n+8=1

C i do not understand.

D. -3-v21=2

21√5

Decimal Form:

1.0796532

or -24=2

-24+26=2

Answer:

  yes; 2 m = 200 cm

Step-by-step explanation:

The SI prefix "centi-" signifies 1/100. That is 300 cm = 300/100 m = 3 m.

If the ceiling is 3 meters high, a sculpture that is 2 meters tall will have no difficulty fitting into the room.

Answer:

648 cubic centimeters

Step-by-step explanation:

6×9×12=648

Answer:

648 cubic centimeters

Step-by-step explanation:

All you need to do is multiply all of the measures that they show you.

6 x 9 x 12 which equals 648

It can be inferred that H0: ? = 15, Ha: ? = 15 doesn't comply because both hypothesis use an equal sign.

From the information, H0: p = 0.5, Ha: p > 0.6 doesn't comply because the two hypothesis use different numbers.

Furthermore, H0: ? = 121, Ha: ? < 121 shows that the pair complies. Also, H0: ? = 123, Ha: ? = 125 doesn't comply as they use the equal sign and different numbers.

Lastly, H0: p? = 0.2, Ha: p? ? 0.2 doesn't comply because p is not a population characteristic.

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Answer:

y=[tex]5^{8}[/tex]

Step-by-step explanation:

An exponential equation is in the form y=[tex]a^{x}[/tex] where a is the base and x is the exponent.

If 5 is the base then it would replace a, and if it 8 was the exponent it will replace x.

The mode is 78

Mode: The digit that has been repeated the most in a specific data.

To determine the mode of the data, let's arrange the data in ascending order.

Arranging the data in ascending form, we get:

In the ascending data, we can see that: (Refer to underlined and bolded text)

Since 78 has been repeated the most, 78 is the mode of the data.

The town should be located 13.4 units from each other

The formula for calculating the distance between two points is expressed as:
√(x2-x1)²+(y2-y1)²

The midpoint of two coordinates is expressed as:
[tex]m(x, y)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )[/tex]

Substitute the given coordinate

[tex]m(x, y)=(\frac{3+15}{2}, \frac{1+7}{2} )\\m(x,y)=(9,4)[/tex]

Hence the town should be located at coordinate (9, 4)

Calculate the distance

D =  √(15-3)²+(7-1)²

D =  √(12)²+(6)²

D = 13.4units

Hene the town should be located 13.4 units from each other

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Answer:

A. 5/1

C. -0.02

D. 4.177777....

Step-by-step explanation:

Rational numbers can be written as a ratio of numbers, such as 5/1. As decimals, the numbers either

*** "terminate" the decimal has a certain number of digits and then stops, such -0.02, this can be written as a ratio -2/100 which is -1/50

OR

*** "repeats" , such as 4.17777... which can also be written as a ratio, 4.1777... = 188/45

7/0 is undefined and the pi numbers are irrational, the digits of the decimal do not repeat and do not ever end, therefore NOT rational.

                          Q1            Q2       IQR   Mean      Median         MAD

Class 1            76.25         81.75    5.5      79.35         79.50       3.12

Class 2             84             88        4           84.60         86           3.85

The first step is to arrange the grades in the classes in ascending order.

Class 1: 70, 72, 74, 75, 76, 77, 77,77, 78, 79, 80, 80, 80, 81, 81, 82, 84, 86, 88, 90

Class 2: 70, 77, 79, 82, 84, 84, 84, 84, 86, 86, 86, 86, 86, 87, 88, 88, 88, 88, 89, 90

Q1 for class 1= 1/4(n + 1) = 21/4 = 5.25 = 76.25

Q2 for class 2 = 1/4(n + 1) = 5.25 = 84

Q3 for class 1= 3/4(n + 1) = 15.75 = 81.75

Q3 for class 2 = 3/4(n + 1) = 15.75 = 88

IQR for class 1 = Q3 - Q1 = 81.75 - 76.25 = 5.50

IQR for class 2 = Q3 - Q1 = 88 - 84 = 4

Mean for class 1 = sum of grades / total number of grades = 1587 / 20 = 79.35

Mean for class 2 = sum of grades / total number of grades= 1692 / 20 = 84.6

Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 79.50

Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 86

MAD = [tex]\frac{1}{n}[/tex]∑ l x - m(x) l

Where: n = number of observations

x = number in the data set

m = mean

Mean absolute deviation for class 1 = 62. 3/ 20 = 3.12

Mean absolute deviation for class 2. = 77/ 20 = 3.85

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Answer: Your answer is X=-63

Hope this helps!