if the cos 30° = sqrt 3/2, then sin 60° =

a. 0
b. 1/2
c. sqrt of 3 /2
d. 1​

Answers

Answer 1

Answer:

C

Step-by-step explanation:

it's well known that the value of sin60 is sqrt 3/2

it's also the same as cos 30


Related Questions

What causes a heart attack?
A. When the arteries increase
B. When LDL metabolizes cholesterol
C. When the heart is starved of oxygen
D. When HDL returns cholesterol to the heart

Answers

Answer:

C.When the heart is starved of oxygen

Drag each expression to show whether it is equivalent to 54x + 18 or
(6 · 9x) + (6 · 1).

Answers

Answer:

The first one should belong in the 54x+18 due to multiplication

The second answer choice has distributive property which has to belong in the 54x+18 category

The third answer choice fits into the 6 times 9x + 6 times one category due to multiplication like the first answer choice.

The last one should be in the 54x+18 category because of the distributive property

Step-by-step explanation:

The Objectives: 54x+18 and (6(9x) + 6

The first one should belong in the 54x+18 due to multiplication

The second answer choice has distributive property which has to belong in the 54x+18 category

The third answer choice fits into the 6 times 9x + 6 times one category due to multiplication like the first answer choice.

The last one should be in the 54x+18 category because of the distributive property

calculus, question 5 to 5a​

Answers

5. Let [tex]x = \sin(\theta)[/tex]. Note that we want this variable change to be reversible, so we tacitly assume 0 ≤ θ ≤ π/2. Then

[tex]\cos(\theta) = \sqrt{1 - \sin^2(\theta)} = \sqrt{1 - x^2}[/tex]

and [tex]dx = \cos(\theta) \, d\theta[/tex]. So the integral transforms to

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \int \frac{\sin^3(\theta)}{\cos(\theta)} \cos(\theta) \, d\theta = \int \sin^3(\theta) \, d\theta[/tex]

Reduce the power by writing

[tex]\sin^3(\theta) = \sin(\theta) \sin^2(\theta) = \sin(\theta) (1 - \cos^2(\theta))[/tex]

Now let [tex]y = \cos(\theta)[/tex], so that [tex]dy = -\sin(\theta) \, d\theta[/tex]. Then

[tex]\displaystyle \int \sin(\theta) (1-\cos^2(\theta)) \, d\theta = - \int (1-y^2) \, dy = -y + \frac13 y^3 + C[/tex]

Replace the variable to get the antiderivative back in terms of x and we have

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\cos(\theta) + \frac13 \cos^3(\theta) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\sqrt{1-x^2} + \frac13 \left(\sqrt{1-x^2}\right)^3 + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\frac13 \sqrt{1-x^2} \left(3 - \left(\sqrt{1-x^2}\right)^2\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \boxed{-\frac13 \sqrt{1-x^2} (2+x^2) + C}[/tex]

6. Let [tex]x = 3\tan(\theta)[/tex] and [tex]dx=3\sec^2(\theta)\,d\theta[/tex]. It follows that

[tex]\cos(\theta) = \dfrac1{\sec(\theta)} = \dfrac1{\sqrt{1+\tan^2(\theta)}} = \dfrac3{\sqrt{9+x^2}}[/tex]

since, like in the previous integral, under this reversible variable change we assume -π/2 < θ < π/2. Over this interval, sec(θ) is positive.

Now,

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \int \frac{27\tan^3(\theta)}{\sqrt{9+9\tan^2(\theta)}} 3\sec^2(\theta) \, d\theta = 27 \int \frac{\tan^3(\theta) \sec^2(\theta)}{\sqrt{1+\tan^2(\theta)}} \, d\theta[/tex]

The denominator reduces to

[tex]\sqrt{1+\tan^2(\theta)} = \sqrt{\sec^2(\theta)} = |\sec(\theta)| = \sec(\theta)[/tex]

and so

[tex]\displaystyle 27 \int \tan^3(\theta) \sec(\theta) \, d\theta = 27 \int \frac{\sin^3(\theta)}{\cos^4(\theta)} \, d\theta[/tex]

Rewrite sin³(θ) just like before,

[tex]\displaystyle 27 \int \frac{\sin(\theta) (1-\cos^2(\theta))}{\cos^4(\theta)} \, d\theta[/tex]

and substitute [tex]y=\cos(\theta)[/tex] again to get

[tex]\displaystyle -27 \int \frac{1-y^2}{y^4} \, dy = 27 \int \left(\frac1{y^2} - \frac1{y^4}\right) \, dy = 27 \left(\frac1{3y^3} - \frac1y\right) + C[/tex]

Put everything back in terms of x :

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac1{\cos^3(\theta)} - \frac3{\cos(\theta)}\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac{\left(\sqrt{9+x^2}\right)^3}{27} - \sqrt{9+x^2}\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \boxed{\frac13 \sqrt{9+x^2} (x^2 - 18) + C}[/tex]

2(b). For some constants a, b, c, and d, we have

[tex]\dfrac1{x^2+x^4} = \dfrac1{x^2(1+x^2)} = \boxed{\dfrac ax + \dfrac b{x^2} + \dfrac{cx+d}{x^2+1}}[/tex]

3(a). For some constants a, b, and c,

[tex]\dfrac{x^2+4}{x^3-3x^2+2x} = \dfrac{x^2+4}{x(x-1)(x-2)} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac c{x-2}}[/tex]

5(a). For some constants a-f,

[tex]\dfrac{x^5+1}{(x^2-x)(x^4+2x^2+1)} = \dfrac{x^5+1}{x(x-1)(x+1)(x^2+1)^2} \\\\ = \dfrac{x^4 - x^3 + x^2 - x + 1}{x(x-1)(x^2+1)^2} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac{cx+d}{x^2+1} + \dfrac{ex+f}{(x^2+1)^2}}[/tex]

where we use the sum-of-5th-powers identity,

[tex]a^5 + b^5 = (a+b) (a^4-a^3b+a^2b^2-ab^3+b^4)[/tex]

20. You may already use algebra in your daily life. How do you imagine that you will use basic algebraic equations in your healthcare career? Explain.

Answers

Depending on the path that we decide to take, the algebra can help us in many forms.

As an example in the pharmaceutical/medical area, the nurses and doctors use basic algebra formulas to calculate dosages on different drugs depending on variables such as the weigh of each patient (commonly expressed as X or Y).

They used to have some paper sheets with formulas for different drug preparations (liquid ones particularly) within hospitals to avoid errors in medication.

As a healthcare provider, it is important to be able to read vital signs. Many of these are expressed as algebraic equations. Such equations can also be important when it comes to administering the right doses of medicine or converting different units of measurement.

For circle B, BG = BE, BG is perpendicular to DC, and BE is perpendicular to FA. What conclusion can be made? a circle with center B and chords DC and FA, a segment from B to chord DC intersect chord DC at G, and a segment from B to chord FA intersects chord FA at E segment DC is parallel to segment FA segment CD is congruent to segment EB segment GB is parallel to segment EB segment DC is congruent to segment FA

Answers

Base on the equidistant chords theorem, chords FB and DA are congruent because they are equidistant from C.

What is the Equidistant Chords Theorem?

The equidistant chords theorem states that two chords in the same circle are congruent to each other, if they are equidistant from the center of the circle.

Thus, based on the information given we can conclude that chords FB and DA are congruent because they are equidistant from C based on the equidistant chords theorem.

Learn more about the equidistant chords theorem on:

https://brainly.com/question/7511582

Answer:

Its D The one at the top is incorrect.

Step-by-step explanation:

I got A 100% which means i got it right...

Which angles are supplementary to each other?
PLS HELP!

Answers

Answer: Angles 6 and 7

Step-by-step explanation:

These angles form a linear pair, and angles that form a linear pair are supplementary.

Kathryn’s new ball has a diameter of 4 inches (in.). What is the surface area of Kathryn’s ball? Use 3.14 for π .

Answers

Answer:

50.24 in^2

Explanation:

The formula for the area of a sphere is
4πr^2, where r is the radius.

Please mark brainliest

(x+35)(2x + 1). How do I do this

Answers

Answer:

Split brackets method see below

Step-by-step explanation:

(x+35)(2x + 1)x(2x + 1)+35(2x + 1)2[tex]x^{2}[/tex] + x + 70x + 352[tex]x^{2}[/tex] + 71x +35

A nonstop train travels between Pearl River and Hoboken. On its trip south, traveling at a constant speed, it makes it from Pearl River to Hoboken in 1 hour and 6 minutes. On its return trip north, the train increases its speed by 10 miles per hour, and takes 42 minutes to reach Pearl River from Hoboken.

What was the train's original speed (on its trip south) in miles per hour?

Answers

Based on the information provided about the return trip, the train's speed on its trip south was 6.36 miles per hour.

What is the distance between Pearl River and Hoboken?Distance = speed x timeDistance = 10 miles per hour x  0.7 hours (42 minutes)Distance = 7 miles

What is the speed on the trip south?Speed = distance / timeSpeed= 7 miles / 1.1 (66 minutes)Speed= 6.36 miles per hour

Learn more about speed in: https://brainly.com/question/6280317

last year a company made a profit of one and a quarter million dollars.Each year the company reinvests 1/3 of the profit How much of this profit eill they reinvest​

Answers

Answer:

$83,333

Step-by-step explanation:

1 000 000*1/4

250 000

250 000*1/3 = 83 333.33

The function f(t) = 3 cos(pi over 6t) + 5 represents the tide in Blastic Sea. It has a maximum of 8 feet when time (t) is 0 and a minimum of 2 feet. The sea repeats this cycle every 12 hours. After nine hours, how high is the tide? 12 feet 5 feet 4.5 feet 2.5 feet

Answers

Answer:

5 feet

Step-by-step explanation:

[tex]f(t) = 3 cos \bigg( \frac{\pi}{6} t\bigg) + 5 \\ \\ plug \: t = 9 \\ \\ \implies \: f(9) = 3 cos \bigg( \frac{\pi}{6} \times 9 \bigg) + 5 \\ \\\implies \: f(9) = 3 cos \bigg( \frac{3\pi}{2}\bigg) + 5 \\ \\\implies \: f(9) = 3 cos \bigg( \pi + \frac{\pi}{2}\bigg) + 5 \\ \\\implies \: f(9) = - 3 cos \bigg( \frac{\pi}{2}\bigg) + 5 \\ [ \because \: cos ({\pi}+\theta) = -\cos \theta]\\\\\implies \: f(9) = - 3 (0) + 5 \\ ( \because \: cos \frac{\pi}{2} = 0) \\ \\ \implies \: f(9) = 0 + 5 \\ \\ \implies \: \huge{ \orange{f(9) = 5 }}[/tex]

given sin0= 2/3 and angle 0 is in quadrant 2, what is the exact value of cos0 in simplest form? simplify all radicals if needed

Answers

Answer: ( -[tex]\sqrt{5}[/tex] / 3)

Step-by-step explanation:

sin(angle) = opposite/hypotenuse

opposite =2

hypotenuse = 3

solve for adjacent side with pythagorean theorum

opposite^2 + adjacent^2 = hypotenuse^2

2^2 + adjacent^2 = 3^2

4 + adjacent^2 = 9

adjacent^2 = 9 - 4

adjacent^2 = 5

adjacent = [tex]\sqrt{5}[/tex]

-[tex]\sqrt{5}[/tex] since it is in the second quadrant

cosx = (adjacent/hypotenuse)

cosx = (-[tex]\sqrt{5}[/tex]/3)

(-[tex]\sqrt{5}[/tex]/3)


pls help ill give brainliest

Answers

Answer:

y = -3x + 2

Step-by-step explanation:

use the slope formula to find the slope

replace x and y into slope intercept form with the slope you just found

If v = X + 4t, v is the velocity and X is the displacement, how to find X in terms of t?​

Answers

[tex]x = vt\\\\\implies x= (x+4t)t\\\\\implies x=xt+4t^2\\\\\implies x -xt= 4t^2\\\\\implies x (1-t) =4t^2\\\\\implies x = \dfrac{4t^2}{1-t}[/tex]

Help I don't understand this math. Whoever gets the right answer gets Brainlist! :)

Do part B please! :)​

Answers

Answer:

1=32

2=44

3=56

4=70

Step-by-step explanation:

if need working please ask

eter and Area
5
Annita is sewing a lace edge around a rectangular quilt. She will need 160 inches of lace to do the entire quilt. If the quilt is 46
inches wide, how long is the quilt?
A. 32 inches
B. 34 inches
C. 80 inches
D.
68 inches
Reset
Submit

Answers

Answer:

b 34

Step-by-step explanation:

its 34 because if you do 46×2 because of the both sides you will get 92 then subtract 92 from 160 and you will get 68 then do 68÷2 to find out the second side and you will get 34

I need the answer to this as well

Answers

C. 10x^2y + 6y^3
Due to you have two sides of 5x^2y and two sides of 3y^3

Answer:

Option C.

Step-by-step explanation:

Perimeter = 2L + 2h

[tex]P=2(5x^{2}y) +2(3y^{3} )=10x^{2} y+6y^{3}[/tex]

Hope this helps

2. When plotting a point on a coordinate grid using an ordered pair, the
first number tells you to go up.
O True
False

Answers

Answer:  False

Explanation:

Any point is of the form (x,y)

The first coordinate is x which tells us to go either left or right depending on whether x is negative or positive.

Example: (-2,3) means we go left 2 units

Another example: (5,7) means we go to the right 5 units.

The starting point is the origin where the x and y axis meet up.

Answer:

False

Step-by-step explanation:

Seven more than a number is less than 18

Answers

Answer:

The first thing to do is translate the sentence into mathematical notation.

"no more than" means "less than or equal to" which is written as ≤

"seven less than a number" means we are subtracting 7 from a number. We don't know what the number is, so we can use a variable (like n) for the number. So "seven less than a number" becomes n - 7.

The whole thing becomes 12 ≤ n - 7.

To solve for n, we can add 7 to both sides.

19 ≤ n.

19 is less than or equal to n, which means the smallest (minimum) value of the number is 19.

We could also do it without an inequality:

If 12 is 7 less than a number, then the number is 19, because 19-7=12. If we chose a smaller number, like 18, then 7 less than 18 is smaller than 12, which is not allowed (12 is no more than 7 less than the number). So the smallest possible value of the number is 19.

hello!

Let the number be p.

Next, "seven times p" can be written like so:-

[tex]\pmb{7p}[/tex]

This expression is less than 18:-

[tex]\bigstar{\boxed{\pmb{7p < 18}}}[/tex]

note:-

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

Please help with this thanks! God bless you

Answers

Answer:

n=23

Step-by-step explanation:

a right angle measures 90

67+n=90

subtract 67 on both sides

n=23

Use angle addition postulate:

m∠ABD + m∠DBC = m∠ABC

Substitute values to get the required equation and solve it for n:

m∠ABD = 67°, m∠DBC = n°,  m∠ABC = 90°67 + n = 90n = 90 - 67n = 23

Find the slope of the line 11x - 4y = 21.

Answers

Answer: 11/4

Step-by-step explanation: no need :”)

Suppose $f(3) = 4$. Name a point that must be on the graph of $y=f(x)+4.$

Enter your answer as an ordered pair.

Answers

Answer:

  (x, y) = (3, 8)

Step-by-step explanation:

The graph for y is a translation upward 4 units of the graph of f(x).

__

A point on the graph of f(x) is given as ...

  (x, f(x)) = (3, f(3)) = (3, 4)

Then a point on the graph of y will be ...

  (x, y) = (x, f(x) +4)) = (3, f(3)+4) = (3, 4 +4)

  (x, y) = (3, 8)

-3(p-4)=-2p+1 what is p

Answers

Answer: p=11

Step-by-step explanation:

-3(p-4) = -2p+1

-3p+12=-2p+1

+2p +2p

-p+12=1

-12 -12

(-1)-p=-11 (-1)

p = 11

Check answer:

-3(11-4)=-2(11)+1

-3(7)=(-22)+1

-21 = -21

Expand binomial (x+1)1

Answers

Answer:

x + 1

Step-by-step explanation:

Given binomial

(x + 1)¹

Use the property

a¹ = a

The binomial remains same without brackets

(x + 1)¹ = x + 1


Question 5
Select the option that best describes the relationship
between the variables on the scatter plot.

Answers

Answer:

positive, leaner association

Step-by-step explanation:

SOMEONE PLEASE HELP!!!! ILL GIVE BRAINLIEST

Answers

Answer:

Your Answer is A.

Step-by-step explanation:

Looking at the picture the LM is the original and wants to translate it to L'M'.

So Right 5 and 2 up.

Answer:

A

Step-by-step explanation:

LM is 5 units away from LM'

LM is 2 units down from LM'

BRAINLIEST please if this helped!

Rewrite the parametric equations in Cartesian form: X(t) = -3sin t, y(t) = 3 cos t​

Answers

Hi the answer is 9sin ur welcome Hope this helps have a great day

Answer:

[tex]( \frac{x}{3} ) {}^{2} + ( \frac{y}{3}) {}^{2} = 1[/tex]

or x² +y²= 9

Step-by-step explanation:

In Cartesian form, the equation is expressed only in terms of y and x.

x= -3sin(t) -----(1)

y= 3cos(t) -----(2)

I've written x instead of x(t) as in the later part of the working, we will be having an equation of only x and y, thus x will no longer be a function of t. This applies to equation 2, where I have replaced y(t) with y.

Relating sine to cosine:

sin²(t) +cos²(t)= 1

[sin(t)]² +[cos(t)]²= 1 -----(3)

From (1):

[tex] \frac{x}{ - 3} = \sin(t) [/tex]

[tex] \sin(t) = - \frac{x}{3} [/tex] -----(3)

From (2):

[tex] \frac{y}{3} = \cos(t) [/tex]

[tex] \cos(t) = \frac{y}{3} [/tex] -----(4)

Substitute (4) &(5) into (3):

[tex]( - \frac{x}{3} )^{2} + ( \frac{y}{3}) {}^{2} = 1[/tex]

[tex]( \frac{x}{3} ) {}^{2} + ( \frac{y}{3} ) {}^{2} = 1[/tex]

The steps below are optional as the above is already considered to be the Cartesian form.

[tex] \frac{ {x}^{2} }{9} + \frac{y {}^{2} }{9} = 1[/tex]

Multiplying both sides by 9:

x² +y²= 9

find out 6c+4dc when c=4.5 and d=6.6
show how to do it step by step​

Answers

Answer:

145.8

Step-by-step explanation:

6c+4dc, where c=4.5 d=6.6

6(4.5) + 4(6.6) (4.5)

27 + 118.8

=145.8

A flower garden is shaped like a circle. Its diameter is 40yd. A ring-shaped path goes around the garden. Its outer edge is a circle with diameter 48yd.
The gardener is going to cover the path with sand. If one bag of sand can cover 6yd^2, how many bags of sand does the gardener need? Note that sand comes only by the bag, so the number of bags must be a whole number. (Use the value 3.14 for pi number .)

Answers

Answer:

About 5 bags of sand

Step-by-step explanation:

1. Create Equation

[(48x3.14)-(40x3.14)]/6

2. Solve

[(48x3.14)-(40x3.14)]/6

[150.72-125.6]/6

25.12/6

Now if you use a calculater you will get

4.1866666667

So lets just round the number to 5 instead of

4 beacuse if we round it to 4 it won't be enough

to cover the whole path.

so your answer is 5

How many​ flowers, spaced every 6​ inches, are needed to surround a circular garden with a 20​-foot ​radius?

Answers

First convert the 20 ft into inches by doing 20x12 (12 inches/ft), giving you 240 inches. Then you would solve for 240/6 since you’re trying to space them by every 6 inches, leaving you with needing 40 flowers total.
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