If the absolute temperature of a given quantity of gas is doubled and the pressure tripled, what happens to the volume of the gas?

Answer: okay, girl I got you . Chemical.

Nuclear.

Thermal.

Electromagnetic. The Electromagnetic Spectrum. The electromagnetic (EM) spectrum is the range of all types of EM radiation. Radiation is energy that travels and spreads out as it goes – the visible light that comes from a lamp in your house and the radio waves that come from a radio station are two types of electromagnetic radiation. This lesson will introduce electricity as the flow of electrons. In some cases, electricity can be the flow of positive charges or both positive and negative charges. This lesson will focus on the more typically defined flow of electrical current as that of electrons. Students should have some basic knowledge of atoms and their structure. However, as part of their online readings, students will investigate the basics of atomic structure (nucleus, protons, neutrons, electrons). Thus, this lesson provides a good opportunity to clarify misconceptions about atoms and to ensure that all students understand basic atomic structure. According to the Benchmarks for Science Literacy, students of all ages show a wide range of beliefs about the nature and behavior of particles. They lack an appreciation of the very small size of particles; attribute macroscopic properties to particles; believe there must be something in the space between particles; have difficulty in appreciating the intrinsic motion of particles in solids, liquids, and gases; and have problems in conceptualizing forces between particles. This misconception is important to keep in mind when talking about electricity as the flow of electrons. Students may think that the electrons are in the copper wire and not the copper atoms that make up the wire. It is important to stress this point with students so that they develop an understanding that substances are composed of atoms, rather than atoms residing as a separate entity within substances.

Explanation: hope this helped and please mark me brainiest.

Explanation:

Chlorophyll make food the plant can use from carbon dioxide, water, nutrients, and energy from sunlight. This process is called photosynthesis. During the process of photosynthesis, plants release oxygen into the air. People and animals need oxygen to breathe.

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Answer:

i not sure but i searched it up and it said Q=104525J

Explanation:

Answer:

It's not A, it's likely not C? I'm guessing B or D.

Answer:

D) 174 g/mol

Explanation:

Step 1: Given and required data

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 25.0°C + 273.15

K = 298.2 K

Step 3: Calculate the molecular weight (M) of the gas

We will use the following expression derived from the ideal gas equation.

ρ = P × M / R × T

M = ρ × R × T / P

M = 7.10 g/L × (0.0821 atm.L/mol.K) × 298.2 K / 1.00 atm

M = 174 g/mol

Given values:

We know the formula,

→ [tex]PV = nRT[/tex]

or,

→ [tex]PM = \frac{W}{V} RT[/tex]

or,

→ [tex]PM = dRT[/tex]

By substituting the values, we get

[tex]1\times M = 7.10\times 0.0821\times 298[/tex]

     [tex]M = 7.10\times 0.0821\times 298[/tex]

          [tex]=174[/tex]

Thus the answer i.e., "option D" is appropriate.

Learn more about molecular weight here:

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speed = distance / time

time = 12 m / 60 m/s

time = 0.20 seconds

Answer:

I believe the answer would be

b.) valence electrons, all thw electrons that surround the nucleus of an atom

Explanation:

You're welcome

Answer:

0.54 mole of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3OH + 3O2 —> 2CO2 + 4H2O

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Finally, we shall determine the number of mole of water (H2O) produced by the reaction of 0.27 moles of CH3OH. This can be obtained as follow:

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Therefore, 0.27 moles of CH3OH will react to produce = (0.27 × 4)/2 = 0.54 mole of H2O.

Thus, 0.54 mole of H2O is produced from the reaction.

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

Answer:

what grade so i can help

Explanation:

Answer:

I believe it’s Sn-Te > H-S > Si-F

Explanation:

Answer: e. 4.8 h

Explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

a) for rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]

[tex]k=\frac{0.693}{0.77hr}=0.9hr^{-1}[/tex]

b) for 160.0 g to decay to 2.07 g

[tex]t=\frac{2.303}{0.9}\log\frac{160.0}{2.07}[/tex]

[tex]t=4.8hr[/tex]

The time  required for a 160.0-g sample of 158Eu to decay to 2.07 g is 4.8 hours

Answer:

2.652 g/h.

Explanation:

Burn rate (in mg/min) = 44.2 mg/min

Burn rate (in m/h) =?

We'll begin by converting 44.2 mg/min to g/min. This can be obtained as follow:

1 mg/min = 0.001 g/min

Therefore,

44.2 mg/min = 44.2 mg/min × 0.001 g/min / 1 mg/min

44.2 mg/min = 0.0442 g/min

Finally, we shall convert 0.0442 g/min to g/h. This can be obtained as follow:

1 g/min = 60 g/h

Therefore,

0.0442 g/min = 0.0442 g/min × 60 g/h / 1 g/min

0.0442 g/min = 2.652 g/h

Therefore, 44.2 mg/min is equivalent to 2.652 g/h.

Thus, the burn rate (in m/h) is 2.652 g/h.

Answer:

4A

Explanation:

on the periodic table

Answer:

0.16mole

Explanation:

To solve this problem, we are going to assume that the number of moles of carbon to be determined is that at STP, standard temperature and pressure.

The number of moles of a substance at STP is given as;

 Number of moles  = [tex]\frac{volume}{22.4}[/tex]  

Given volume  = 3.5L

Now, insert the parameters;

     Number of moles  = [tex]\frac{3.5}{22.4}[/tex]   = 0.16mole

Answer:

5.4 g Na

Explanation:

Calculate the mass of sodium chloride from both reactants. The lesser value is the amount is the theoretical yield. Subtract the mass of the calculated mass of sodium chloride from the mass of the reactants.

Answer:

3.6132 * 10^24 atoms/molecules of 02

Explanation:

When we look at the balanced chemical equation, we can see that there are 6 moles of O2.

In order to convert from moles to formula units (atoms and molecules),

you need to multiply by avogadro's number.

6 moles * [tex]6.022*10^{23}[/tex]/1 mol = 3.6132 * 10^24 atoms/molecules of 02

Answer:

no effect

Explanation:

In an SN2 reaction, the mechanism is bi-molecular and first order in both the alkyl halide and the nucleophile.

Hence the rate of reaction is;

Rate = k [1-iodo-2-methylbutane] [cyanide ion]

Given that it is a bimolecular reaction, if we double the concentration of 1-iodo-2-methylbutane and the concentration of the cyanide ion is halved, the rate of reaction remains the same.

Answer:

H₂CO₃(aq) ⇄ H⁺(aq) + HCO₃⁻(aq)

HCO₃⁻(aq) ⇄ H⁺(aq) + CO₃²⁻(aq)

Explanation:

Carbonic acid (H₂CO₃) has 2 acidic protons. When is dissolved in water, it loses the protons (H⁺) in two sequential steps:

- First, it loses 1 proton to form the hydrogen carbonate ion (HCO₃⁻)

H₂CO₃(aq) ⇄ H⁺(aq) + HCO₃⁻(aq)

- Then, the acid carbonate anion loses its proton to form carbonate ion (CO₃²⁻):

HCO₃⁻(aq) ⇄ H⁺(aq) + CO₃²⁻(aq)

Answer:

salt (NaCl)

Explanation:

Pure substance is defined as the substance that consist of a single type of material and does not contain contaminants. A pure substance has uniform composition throughout the process.

sodium chloride (NaCl) also known as table salt is a pure substance because it has a uniform and definite composition that is  1:1 ratio of sodium and chloride ions.

Hence, the correct answer is "salt (NaCl)".

Answer:

A) They get oxidized into carbon monoxide and carbon dioxide by the oxygen molecules generated on the electrode.

Explanation:

In the electrolysis of Aluminium, the oxygen reacts with the carbon anodes forming carbon dioxide. That is, the anodes are oxidized. To ensure that the reaction completes, the anode must gradually be replaced as the reaction proceeds. The correct option is hence;

A) They get oxidized into carbon monoxide and carbon dioxide by the oxygen molecules generated on the electrode.

Answer:

2.41 * 10^24 atoms of carbon present in the products.

Explanation:

First, we need to find the moles of carbon in the products in order to find the number of atoms.

We see that in the chemical formula, carbon belongs to the compound known as glucose. To get the amount of moles of carbon, we need to divide my the amount of carbon within glucose (in grams) from the total amu ( or grams) of glucose to get the moles.

C6 = 72.066.

C6H12O6 = 180.156

72.066/180.156 = 0.4000199827 moles of Carbon within the Glucose compound

Now we will convert to atoms/molecules by multiplying the moles by avogadro's number..

0.4000199827 moles C * 6.022*[tex]10^{23}[/tex] = 2.408920336 *[tex]10^{24}[/tex] atoms of Carbon present in the products

*Note --> this can be estimated to 2.41 * [tex]10^{24}[/tex] atoms of Carbon

Answer: If the gold in the crown was mixed with a less-valuable metal such as bronze of copper then this affects its density by making it to weigh even more and if it weighs more then it has less of chance to float. Observe: Drag each of the crowns into the liquid.

Explanation:

Density can be defined as the compactness of any substance. It is the mass/volume of a substance.

Thus, if the gold crown is mixed with cheaper substances, such as bronze and copper, the density of the crown will decrease and it will become lighter.

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Answer:

9.26g of BaSO₄ are formed

Explanation:

The reaction of Ba(OH)₂ with H₂SO₄ is:

Ba(OH)₂ + H₂SO₄ → BaSO₄ + 2H₂O.

To solve this question we need to determine the moles of each reactant in order to find the limitng reactant. With the moles of limiting reactant we can find the theoretical moles of BaSO₄ produced and its mass, as follows:

Moles Ba(OH)₂:

50.0mL = 0.050L * (1.00mol / L) = 0.0500moles

Moles H₂SO₄:

83.5mL = 0.0835L * (0.475mol / L) = 0.0397moles

That means limiting reactant is H₂SO₄.

Based on the reaction, 1 mole of H₂SO₄ produce 1 mole of BaSO₄. The theoretical moles of BaSO₄ produced are 0.0397 moles.

The mass is (Molar mass BaSO₄: 233.38g/mol):

0.0397 moles BaSO₄ * (233.38g / mol) =

The formula of Silver (III) Sulfide is Ag2S3.

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The given question is incomplete, the complete question is:

A buffer is prepared by adding 24.6 mL of 0.65 M NaF to 49.6 mL of 0.28 M HF. What is the pH of the final solution?

Answer:

The correct answer is 3.23.

Explanation:

The calculations of pH in a buffer solution is determined with the help of Henderson-Hasselbalch equation, that is,

pH = pKa + log[conjugate base]/[acid]

= pKa + log[A⁻][HA]

Here Ka is the equilibrium constant.  

Based on the given information, the volume and concentration of NaF is 24.6 ml and 0.65 M. Now the millimoles of NaF can be determined by using the formula,  

millimoles = Molarity × Volume

= (0.65 M) (24.6 ml) (1 mmol/ml/1M)

= 16 mmol

Thus, the millimoles of NaF or F⁻ is 16 mmol.  

On the other hand, the volume and concentration given of HF is 49.6 ml and 0.28 M. Now the millimoles of HF will be,  

Millimoles = 0.28 M × 49.6 ml (1mmol/ml/1M)

Millimoles = 13.9 mmol

Thus, the millimoles of HF is 13.9 mmol.  

The value of Ka for strong acid is 6.8 × 10⁻⁴.  

Now the pH of the buffer solution can be determined by using the above mentioned Henderson-Hasselbalch equation,  

pH = pKa + log[F⁻]/[HF]

= -logKa + log[16 mmol]/[13.9 mmol]

= -log(6.8 × 10⁻⁴) + 0.06

= 3.17 + 0.06

= 3.23.  

Hence, the pH of the solution is 3.23.

Answer:

1) 18.91 mL

2) 2.35 %

Explanation:

1. The volume of base that was required is equal to the difference between the reading at the end of the titration and the reading at the beginning:

2. The mass percent can be written as:

For this problem:

We input the data and calculate the mass percent: