If mZA = (8x + 6)° and m
ZB = (7x + 24)', then find the measure of ZB

Answers

Answer 1
i got x=18 i think u mistaken za for zb
If MZA = (8x + 6) And MZB = (7x + 24)', Then Find The Measure Of ZB

Related Questions

The coordinates of point T are (0,4). The midpoint of ST is (1,-5). Find the coordinates of point S.
The other endpoint is
(Type an ordered pair.)

Answers

The answer is (2,-15)

math 1 work it out please w-2+2w=6 + 5w

Answers

Answer:

w = -4

Step-by-step explanation:

w - 2 + 2w = 6 + 5w

Add 2 to both sides.

w + 2w = 8 + 5w

Subtract w from each side.

2w = 8 + 4w

Subtract 4w from each side.

-2w = 8

Divide.

w = -4

10 - 3x < 16
Can y’all help me pls

Answers

Answer:

x>-2

Step-by-step explanation:

first you subtract 10 from both sides to find x

10-3x-10<16-10

-3x<6

now here you divide both sides by -3

-3x/-3<6/-3

BUT since you are dividing by a negative number the sign will have to flip

so the answer will be

x>-2

2 x 10-6
times what number is equal to 6 x 10-4

Answers

Answer:

times -6

Explanation... 2 x 10-6 x -6=56

                      6 x 10-4=56      

                             

Hope this helps

Muna is making a scale drawing of a gecko. The gecko is 1··2inch wide and 5 inches long. A. She decides to make her drawing of the gecko 1 inch wide. How long will the drawing be? Show your work.

Answers

Answer:

[tex]L = 0.83\ in[/tex]

Step-by-step explanation:

Given

Width = 1.2 in when Length = 1 in

Required

Determine the length when width = 1 in

First, we need to determine the ratio:

[tex]Ratio = \frac{Width}{Length}[/tex]

[tex]Ratio = \frac{1.2}{1}[/tex]

[tex]Ratio = 1.2[/tex] --- (1)

Let the required Length be represented with L

So:

[tex]Ratio = \frac{Width}{Length}[/tex]

[tex]Ratio = \frac{1}{L}[/tex] --- (2)

Equate (1) and (2)

[tex]\frac{1}{L} = 1.2[/tex]

Multiply through by L

[tex]L * \frac{1}{L} = 1.2 * L[/tex]

[tex]1 = 1.2 * L[/tex]

Divide through by 1.2

[tex]L = \frac{1}{1.2}[/tex]

[tex]L = 0.83\ in[/tex] (Approximated)

-25 = 1/2 (10x - 2) + 3x what is x?

Answers

Answer:

x=[tex]-\frac{1+2i\sqrt{31} }{5}[/tex]

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

−25=  [tex]\frac{1}{2}[/tex]  (10x−2)+3x

−25=([tex]\frac{1}{2}[/tex])(10x)+( [tex]\frac{1}{2}[/tex] )(−2)+3x(Distribute)

−25=5x+−1+3x

−25=(5x+3x)+(−1)(Combine Like Terms)

−25=8x+−1

−25=8x−1

Step 2: Flip the equation.

8x−1=−25

Step 3: Add 1 to both sides.

8x−1+1=−25+1

8x=−24

Step 4: Divide both sides by 8.

8x  ÷ 8   =   −24  ÷ 8

4(5x – 9) = -2(x + 7) solve and justify each step

Answers

Step-by-step explanation:

4(5x-9)=-2(x+7)

4*5x-4*9=-2*x-2*7

20x-36=-2x-14

20x+2x=-14+36

22x=22

x=22/22

x=1

It is given that 1/5<n<1/4. Write down a decimal value of n that satisfies this in equality.

Pls help me!!! Will give brainliest.​

Answers

Answer:

0.20<n<0.25

Step-by-step explanation:

0.20<n<0.25

please help me on this

Answers

Answer:

12x+10

Step-by-step explanation:

Add up the lengths of all sides to find the perimeter

P = x + 2( x+5) + 6(x-1) + 3(x+2)

Distribute

  = x + 2x+10 +6x-6 + 3x+6

Combine like terms

 =x+ 2x+ 6x+3x    + 10 -6+6

 = 12x+10

find the initial value seventeen years from now, Ms. speedis car, which is depreciating at 20% per year, will be worth $500

Answers

Answer:

Around 22200 dollars

Step-by-step explanation:

Firstly, it was depreciating 20% per year for 17 years. So, if we were to go back in time, it would be appreciating by 25%. Therefore, after doing the plugging in, it is 500 * 1.25^17. The initial value is around 22200. It is around 22204, to be exact.

I need help on number 2 , 3 and 4

Answers

3. 0
4. 5/3, positive
I can’t see the instructions for 2

(-2)(7)(-75)(3)(-2)=?

Answers

equals -6300 fjesshehw

Answer:

-6300

Step-by-step explanation:

I just plugged it into my calculator, Google's works just fine :)

Solve for
16 – 2t = t +9

Answers

16 - 2t = t + 9
t = 7/3

What is 180(n-2)=s when solving for N​

Answers

Answer:

n = s/180 +2

Step-by-step explanation:

180(n-2)=s

Distribute

180n - 360 =s

Add 360 to each side

180n -360+360 = s+360

180n = s+360

Divide each side by 180

180n/180 = s/180 + 360/180

n = s/180 +2

Find the area.
A. 1818 sq cm
B. 1406 sq cm
C. 1246 sq cm
D. 141 sq cm
E. 146 sq cm​

Answers

Answer:

C

Step-by-step explanation:

39*34= 1326 (the area of the full square

8*10=80 (the area of the small square that is cut off)

1326-80= 1246

Answer:

C = 1246 sq. cm.

Step-by-step explanation:

finding the area is simply splitting the area into two (see image)

A1 = 26 x 39 = 1014

A2 = 8 x 29 = 232

total area = 232 + 1014

total area = 1246 sq. cm.

therefore, the answer is C = 1246 sq. cm.

Whats a prime number can you guys give me some examples pls

Answers

2 3 5 7 11 13 17 19 23

29 31 37 41 43 47 53 59 61 67

71 73 79 83 89 97 101 103 107 109

113 127 131 137 139 149 151 157 163 167

173 179 181 191 193 197 199 211 223 227

229 233 239 241 251 257 263 269 271 277

281 283 293 307 311 313 317 331 337 347

349 353 359 367 373 379 383 389 397 401

409 419 421 431 433 439 443 449 457 461

463 467 479 487 491 499 503 509 521 523

541 547 557 563 569 571 577 587 593 599

601 607 613 617 619 631 641 643 647 653

659 661 673 677 683 691 701 709 719 727

733 739 743 751 757 761 769 773 787 797

809 811 821 823 827 829 839 853 857 859

863 877 881 883 887 907 911 919 929 937

941 947 953 967 971 977 983 991 997   Thats all the prime numbers between 1 and 1000   Prime numbers can only be multiplied by its self ad one

Find the measure of angle C of △ABC, if m∠A = α, m∠B = 2α its not 10-3a(will mark brainliest!)

Answers

Answer:

[tex]C = 180 - 3a[/tex]

Step-by-step explanation:

Given

[tex]A = a[/tex]

[tex]B = 2a[/tex]

Required

[tex]Find\ C[/tex]

Since, ABC is a triangle, we have:

[tex]A + B + C = 180[/tex]

Substitute values for A and C

[tex]a + 2a + C = 180[/tex]

[tex]3a + C = 180[/tex]

Subtract 3a from both sides

[tex]C = 180 - 3a[/tex]

Answer:

180°-3α

Step-by-step explanation:

If you forgot to put the degree sign on 180, that's why you got it wrong!

A clementine weighs about 80 g What is the approximate weight of 48 clementines?

Answers

Answer:

3840g

Step-by-step explanation:

... ..... ......

Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tacoma's population be in 2010?

Answers

70000000 would be the answe

4x+2y=8 what is the y intercept

Answers

the y intercept is 4

explanation-
4x+2y=8 (you want to get y by itself, so subtract 4x)

2y=-4x+8 (now divide by 2)

y=-2x+4 so four is the y intercept

Could someone help me out, I’m not sure how to do these :,)

Answers

Answer:

1.) Reflection over y=1

2.) Translation rule: (x-5, y-3)

3.) Reflection over the y axis

4.)Translation rule: (x-4, y+1)

Step-by-step explanation:

Frank needs to fill juice cups for his sis there r 35 cups amd it holds 12 fluid ounces. The juice came in a 1 gallon bottle how many 1 gallon bottles of juice will he need to purchase?

Answers

Answer:

4 gallons

Step-by-step explanation:

He needs 105 over 3 to fill all the cups. 1 gallon would be 10 and 2 third cups or 32 over 3. 2 gallons would be 21 and 1 third cups or 64 over 3. 3 gallons would be 32 or 96 over 3. 4 gallons would be 42 and 2 third cups or 128 over 3. So 4 gallons would fill up all 35 of his sisters 12 ounces cups. That would leave 7 and 2 third cups that hold the same amount. His sister gets all 35 of her 12 ounces each cups filled and he gets 7 and 2 thirds of new and unused 12 ounces cups. Basically out of the 4 gallons there would be 512 ounces and his sister with all 35 cups that hold 12 ounces each she would get 420 ounces. Which would leave him with 92 ounces of juice for himself. Hope this understandable and helpful.

10. APPLICATION Inspector 47 at the Zap battery plant
keeps a record of which AA batteries she finds defective.
Although the battery numbers at right do not make an
exact sequence, she thinks they are close to an arithmetic
sequence
a. Write a recursive formula for an arithmetic sequence
that estimates which batteries are defective. Explain
your reasoning
b. Predict the numbers of the next five defective batteries.
c. How many batteries in 100,000 will be defective?
Defective
Batteries
255, 500, 773
998, 1227, 1510,
1721, 2010

Answers

2010 47 +ten thousand split decide and

Need help ASAP. Thanks!

Answers

Answer: 114

Step-by-step explanation:

To find the perimeter, you will find the distance around the shape by adding the numbers.

The is one missing side  and to find that side you will subtract  10 from 38.

38 - 10 = 28

Now add the them.

28 + 5 +  10 + 26 + 10 + 35 = 114

What is the value of x?
-7.5 (x-3)=3.75

Answers

Answer:

x= 2.5

Step-by-step explanation:

-7.5 (x-3) = 3.75

(divide both sides of the equation by -7.5)

x-3 = -0.5

(move the constant to the righthand side and change the sign)

x = -0.5+3

(calculate the sum)

x = 2.5

please don’t skip over me!

show all work

Answers

Answer:

a,c,d

Step-by-step explanation:

[tex]a. \\4i^9+4i^7\\=4i(i^2)^4+4i(i^2)^3\\=4i(-1)^4+4i(-1)^3\\=4i-4i\\=0\\b.\\2i^{18}-3i^{11}\\=2(i^2)^9-3i(i^2)^5\\=2(-1)^9-3i(-1)^5\\=-2+3i\\c.\\7i^{36}-11i^{11}-11i^9\\=7(i^2)^{18}-11i(i^2)^5-11i(i^2)^4\\=7(-1)^{18}-11i(-1)^5-11i(-1)^4\\=7+11i-11i\\=7\\d.\\8i^{22}-1\\=8(i^2)^{11}-1\\=8(-1)^{11}-1\\=-8-1\\=-9[/tex]

e.

[tex]2i^{27}+4\\=2i(i^2)^{13}+4\\=2i(-1)^{13}+4\\=-2i+4[/tex]

Points A, B, and C are collinear. Point B is the midpoint of AC. AB=12x-398. BC=22.
Solve for x. *

Answers

Answer:

         x = 35

Step-by-step explanation:

Collinear points A, B, and C and point B being midpoint of AC means:

AB = BC

12x - 398  =  22

   + 398      + 398

 12x = 420

  ÷12    ÷12  

    x = 35

Evaluate 12 - 6+ (14 – 8)^2=
. (1 point)

Answers

Answer:

the answer is 42

Step-by-step explanation:

12-6+(14-8)^2

12-6(6)^2

12-6+36

=42

Please help me to prove this!!!

Answers

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                    →    A + B = π - C

                                                    →    A + C = π - B

Use the Cofunction Identities:   sin (π - A) = sin A

                                                    sin (A - π/2) = cos A

                                                    cos (π/2 - A) = - sin A

Use the Power Reducing Identity:  sin ² A - sin² B = sin (A + B) · sin (A - B)

Use the Sum to Product Identity:

                                               sin A - sin B = 2 [cos (A + B)/2] · [sin (A - B)/2]

Proof LHS → RHS:

LHS:                                   sin² A - sin² B - sin² C

                                       = (sin² A - sin² B) - sin² C

Power Reducing:           sin (A + B) · sin (A - B) - sin² C

Given:                             sin (π - C) · sin (A - B) - sin² C

Cofunction:                    sin C · sin (A - B) - sin² C

Factor:                            sin C [sin (A - B) - sin C]

[tex]\text{Sum to Product:}\qquad \sin C\bigg[2\cos \bigg(\dfrac{(A-B)+C}{2}\bigg)\cdot \sin \bigg(\dfrac{(A-B)-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{(A+C)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(B+C)}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad \qquad 2\sin C\bigg[\cos \bigg(\dfrac{(\pi - B)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(\pi - A)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi -2B}{2}\bigg)\cdot \sin \bigg(\dfrac{2A-\pi}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi}{2} -B}\bigg)\cdot \sin \bigg(A-\dfrac{\pi}{2}\bigg)\bigg][/tex]

Cofunction:             2 sin C (-sin B) · (cos A)

                           = -2 sin C · sin B · cos A

                           = -2 cos A · sin B · sin C

LHS = RHS:   -2 cos A · sin B · sin C = -2 cos A · sin B · sin C  [tex]\checkmark[/tex]

NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE

Answers

Answer:

Q1:

[tex]-5\sqrt{27c^2}[/tex]

[tex]-5\sqrt{27}\sqrt{c^2}[/tex]

[tex]-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}[/tex]

[tex]-5\times3\sqrt{3}\sqrt{c^2}[/tex]

[tex]-5\times3\sqrt{3}c[/tex]

[tex]-15\sqrt{3}c[/tex]

Q2:

[tex]5\sqrt{72}-3\sqrt{32}[/tex]

[tex]5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}[/tex]

[tex]5\times6\sqrt{2}-3\times4\sqrt{2}[/tex]

[tex]30\sqrt{2}-12\sqrt{2}[/tex]

[tex]18\sqrt{2}[/tex]

Q3:

[tex]\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}[/tex]

[tex]\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}[/tex]

[tex]6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}[/tex]

[tex]16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}[/tex]

Q4:

[tex]\sqrt{15n^2}\sqrt{10n^3}[/tex]

[tex]\sqrt{15}n\sqrt{10n^3}[/tex]

[tex]\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}[/tex]

[tex]\sqrt{15}\sqrt{10}n^2\sqrt{n}[/tex]

[tex]\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}[/tex]

[tex]5\sqrt{3}\sqrt{2}n^2\sqrt{n}[/tex]

[tex]5\sqrt{6}n^2\sqrt{n}[/tex]

Q5:

[tex]\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}[/tex]

[tex]\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}[/tex]

Cancel off [tex]\sqrt{x}[/tex]:

[tex]\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}[/tex]

Cancel off [tex]y:[/tex]

[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}[/tex]

Cancel off [tex]\sqrt{y} :[/tex]

[tex]\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}[/tex]

Multiply [tex]\sqrt{5}[/tex] on the numerator and denominator:

[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}[/tex]

[tex]\frac{\sqrt{15}\sqrt{x}}{20}[/tex]

sorry i pushed add answer

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