If m/8 = 133°, find m/1.

The value of a polynomial function with the given zeros would be,

⇒ f (x) = x (x + 7) (x + 6)³

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

Functions have zeroes 0, - 6, - 7 with multiplicity 1, 3, 1

Hence, We can formulate;

The value of a polynomial function with the given zeros would be,

⇒ f (x) = (x - 0)¹ (x - (- 6))³ (x - (- 7))¹

⇒ f (x) = x (x + 6)³ (x + 7)

⇒ f (x) = x (x + 7) (x + 6)³

Thus, The value of a polynomial function with the given zeros would be,

⇒ f (x) = x (x + 7) (x + 6)³

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Answer:

an = 36 + -4(n - 1)

Step-by-step explanation:

Explicit formula:

[tex]a_n=a_1+(n-1)d[/tex]

Where:

Here, we are given the following:

The first term is 36

To get to the next term, 4 is subtracted from the previous term so the common difference is -4.

So we have:

By plugging this into [tex]a_n=a_1+(n-1)d[/tex]

We acquire : [tex]a_n=36+(n-1)(-4)[/tex]

Answer:

a) Two real solutions.

b) Solutions:  y = -6, y = 12

Step-by-step explanation:

The discriminant is defined as the expression b² - 4ac, which appears under the square root sign in the quadratic formula.

The value of the discriminant determines the nature of the solutions to the quadratic equation:

[tex]\boxed{\begin{minipage}{12 cm}\underline{Discriminant}\\\\$b^2-4ac$ \quad when $ax^2+bx+c=0$\\\\when $b^2-4ac > 0 \implies$ two real solutions.\\when $b^2-4ac=0 \implies$ one real solution.\\when $b^2-4ac < 0 \implies$ no real solutions (two complex conjugate solutions).\\\end{minipage}}[/tex]

To find the number and type of solutions of the given quadratic equation, first rewrite the equation in the form ax² + bx + c = 0.

[tex]\begin{aligned}(y-3)^2-10&=71\\y^2-6y+9-10&=71\\y^2-6y-1&=71\\y^2-6y-72&=0\end{aligned}[/tex]

Compare the coefficients:

Substitute the values of a, b and c into the discriminant formula:

[tex]\begin{aligned}b^2-4ac&=(-6)^2-4(1)(-72)\\&=36-4(-72)\\&=36+288\\&=324\end{aligned}[/tex]

As the discriminant of the given equation is greater than zero, there are 2 real solutions.

To solve the equation, we can use the quadratic formula:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\quad\textsf{when}\;\;ax^2+bx+c=0[/tex]

As we have already calculated that the discriminant is 324, we can substitute this, along with the values of a and b, into the formula:

[tex]\implies y=\dfrac{-(-6) \pm \sqrt{324}}{2(1)}[/tex]

[tex]\implies y=\dfrac{6 \pm \sqrt{324}}{2}[/tex]

Solve for y:

[tex]\implies y=\dfrac{6 \pm 18}{2}[/tex]

[tex]\implies y=3 \pm 9[/tex]

[tex]\implies y=-6, 12[/tex]

Therefore, the solutions of the given equation are:

The maximum profit that can be made is $1737.82

An equation is an expression showing the relationship between numbers and variables using mathematical operators.

The profit function is the difference between the revenue and cost of a commodity. Given that:

Revenue, R(x) = 700x - 11.3x²

Cost, C(x) = 8068 - 34.25x

Profit, P(x) = Revenue - Cost

P(x) = (700x - 11.3x²) - (8068 - 34.25x)

P(x) = 665.75x - 11.3x² - 8068

The maximum profit is at P'(x) = 0; hence:

P'(x) = 665.75 - 22.6x

665.75 - 22.6x = 0

22.6x = 665.75

x = 29.45

P(29.45) = 665.75(29.45) - 11.3(29.45)² - 8068

P(29.45) = 1737.82

The profit to be made is $1737.82

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The expression |x³| + 5 is 5 more than the absolute value of the cube of a number.

Option B is the correct answer.

We have,

The expression |x³| represents the absolute value of the cube of a number x.

This means that no matter what value x takes (positive, negative or zero), the result of the expression will always be positive.

For example, if x = 2, then |x³| = |2³| = |8| = 8.

If x = -2, then |x³| = |-2³| = |-8| = 8.

Adding 5 to the absolute value of the cube of x means adding 5 to the positive number that resulted from |x³|.

So, if we take the examples from above, if x = 2, then the expression becomes |2³| + 5 = 8 + 5 = 13.

If x = -2, then the expression becomes |-2³| + 5 = 8 + 5 = 13.

Therefore,

The expression |x³| + 5 is 5 more than the absolute value of the cube of a number.

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Answer:

48 square inches

Step-by-step explanation:

lxwxh

6x4x2

The amount of fabric used to make the number cube is given as follows:

C. 294 cm².

The amount of fabric used to make the number cube is represented by the surface area of the number cube.

The surface area of a cube of side length a is given by the equation presented as follows:

S = 6a².

The side length for this problem is given as follows:

a = 7 cm.

Hence the surface area of the cube is calculated as follows:

S = 6 x 7²

S = 294 cm².

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The total cost that Ellie would pay with 4 snacks is $59.

The total cost that Ellie would pay with x snacks is $29 + $5x.

The first step is to determine the total number of people going to the movies. There are 3 people going to the movies.

The total cost spent by Ellie is the sum of the tickets and the total cost of the snacks.

Total cost = total cost of the tickets + total cost of the snacks

= (cost of one ticket x number of people going to the movie) + (number of snacks bought x price of one snack)

= (13 x 3) + ($5 x 4)

$39 + $20 = $59

Total cost if x snacks is bought: (13 x 3) + ($5 x x) = $39  + $5x

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The inductive hypothesis is P₍ₐ₊₁₎ : 7 + 13 + 19 + ... + {6(a +1) +1} = (a + 1) {3(a + 1) + 4} is true for all (a+1) = n for the statement Pₙ : 7 + 13 + 19 + ... + (6n +1) = n(3n +4)

The statement is given as,

Pₙ : 7 + 13 + 19 + ... + (6n +1) = n(3n +4)

For n =1 we get,

P₁ : 6(1) + 1 =7

and,  1{3(1) + 4} = 7

Hence, 6n+ 1 = n(3n + 4) is true for n= 1.

Therefore assume that Pₐ is true for some a = n, we get,

Pₐ : 7 + 13 +19 +... + (6a +1 ) = a(3a + 4)

Let,  n =a+1 , we get,

P₍ₐ₊₁₎ : 7 + 13 + 19 + ... + (6a +1) + {6(a +1) +1}

= Pₐ +   (6a+ 7)

= a(3a + 4) + 6a + 7

=  3a² + 4a + 6a + 7

=  3a² +10a + 7

= 3a² + 7a + 3a + 7

= a( 3a + 7) + 1(3a + 7)

= (a + 1) ( 3a + 7)

= (a + 1) {3(a + 1) + 4}

Hence, (a +1) is true for all (a+1) = n by mathematical induction principle. Thus, the inductive hypothesis is true.

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Answer:

2.

Step-by-step explanation:

To find the slope of the line that passes through the points (2,-4) and (5,2), we can use the slope formula:

slope = (y2 - y1) / (x2 - x1)

where (x1, y1) = (2,-4) and (x2, y2) = (5,2)

slope = (2 - (-4)) / (5 - 2)

slope = 6 / 3

slope = 2

Therefore, the slope of the line that passes through the points (2,-4) and (5,2) is 2.

In the given sets, the values of A or B and B and C are:

A or B = {32, 35,36, 38, 40, 41, 44, 46, 48, 50}

B and C = {32, 48}

From the question, we are to determine the values of A or B and B and C in the given set.

From the question,

The universal set is

U = {31,32,33……,50}

and

A={35,38,41,44,46,50}

B={32,36,40,44,48}

C= {31,32,41,42,48,50}

A or B means we should find the union of A and B. That is, the elements present in A or B or both

A or B = {32, 35,36, 38, 40, 41, 44, 46, 48, 50}

B and C means we should find the intersect of B and C. That is, the elements that present both in B and C

B and C = {32, 48}

Hence,

A or B = {32, 35,36, 38, 40, 41, 44, 46, 48, 50}

B and C = {32, 48}

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The domain is all real numbers.

The range is {y|y ≤ 16}.

Option B is the correct answer.

We have,

The given parabola opens downwards and has a vertex at (-1,16).

So,

The parabola has a maximum value at y = 16.

Also, the y-intercept of the parabola is (0,15), which is below the vertex, and the parabola intersects the x-axis at (-5,0) and (3,0).

We can use the factored form of the equation of a parabola to find its equation in this case.

The factored form is:

y = a(x - h)² + k

where (h,k) is the vertex and "a" determines whether the parabola opens upwards or downwards.

Since the parabola opens downwards, "a" is negative.

Also, we know that the vertex is (-1,16), so we have:

y = a(x + 1)² + 16

To find "a", we can use one of the x-intercepts, say (-5,0).

Substituting these values into the equation gives:

0 = a(-5 + 1)² + 16

0 = 16a

a = 0

This indicates that the parabola is actually a line passing through (0,15) and (3,0). Therefore, the equation of the parabola is:

y = -x² - 2x + 15

The domain of this function is all real numbers because there are no restrictions on the values of x that can be plugged into the equation.

However, the range of the function is limited by the maximum value of y, which is 16.

Since the parabola opens downwards, all y values less than or equal to 16 are attainable.

Therefore, the domain is all real numbers, and the range is {y | y ≤ 16}.

Therefore,

The domain is all real numbers.

The range is {y|y ≤ 16}.

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There are 27.558 meters of wire does she have remaining after the first day.

We have to given that;

An electrician has 42.3 meters of wire to use on a job.

And, On the first day, she uses 14.742 meters of the wire.

Hence, We get;

The remaining wire does she have remaining after the first day is,

⇒ 42.3 - 14.742

⇒ 27.558 meters

Thus, There are 27.558 meters of wire does she have remaining after the first day.

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The radius of the circular mouse is 3.7 inches.

The area of the circular mouse pad 45 square inches. Therefore, the radius of the circle can be found as follows:

area of the circle = πr²

where

Therefore,

area of the circular mouse = 3.14 × r²

45 = 3.14r²

divide both sides by 3.14

r² = 45 / 3.14

r² = 14.3312101911

square root both sides

r = √14.331210911

r = 3.78565714243

r = 3.7 inches

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The maximum value of z = 28.  I occurs at (x, y) = 4

To solve thhis linear programming problem, we can use the graphical method..

Graph the feasible region defined   by the constraints.....

x >= 0 and y >= 0 represent the non-negative quadrants.

x + y < = 8   represents the area below the line passing through ( 8, 0) and (0, 8).

x + y >= 2 represents the area above the line passing through (  2 , 0) and (0 , 2).

Identify the corner points of the feasible region  .....

(0,  2)

 (  2, 0)

(   4, 4)

( 8, 0 )

Calculate tthe objective function at each corner point....

z(0,   2  ) = 3(0) + 4(2) = 8

z (2, 0  ) = 3(2) + 4(0) = 6

z(4, 4  ) = 3(4) + 4(4) = 28

z (  8, 0) = 3(8) + 4(0) = 24

Determine the    maximum value of the objective function and the values of x and y that give this maximum value

The maximum value of z is 28, which occurs at the corner point (4, 4).

So we c can be stated as follows --

Maximum value of z = 28

x = 4

y = 4

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The graph shown corresponds to someone who makes: C. $20 an hour.

In Mathematics and Geometry, a proportional relationship refers to a type of relationship that produces equivalent ratios and it can be modeled or represented by the following mathematical equation:

y = kx

Where:

Next, we would determine the constant of proportionality (k) by using various data points as follows:

Constant of proportionality, k = y/x

Constant of proportionality, k = 20/1 = 40/2 = 60/3 = 80/4

Constant of proportionality, k = 20.

Therefore, the required linear equation or function is given by;

y = kx

y = 20x

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The length of u to the nearest centimeter is about 30 cm.

We are given that;'

s = 730 cm, t = 270 cm and U=125°.

Now,

The Law of Cosines states that for any triangle with sides a, b and c and angle C opposite to side c, we have:

c2=a2+b2−2abcosC

To find c = u. Plugging in the values, we get:

u2=7302+2702−2×730×270×cos125°

Using a calculator, we get:

u2≈912.9

Taking the square root of both sides, we get:

u≈30.21

Rounding to the nearest centimeter, we get:

u≈30cm

Therefore, by the law of cosine the answer will be 30 cm.

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Answer:

z = 12.52 in.

Step-by-step explanation:

Because this is a right triangle, we can solve for z using on the trigonometric ratios.

If we allow 37° to be our reference angle, the 10 in. side is the adjacent side and z (directly across from the right angle) is the hypotenuse.

Thus, we can use the cosine ratio which is

[tex]cos(angle)=\frac{adjacent}{hypotenuse}[/tex]

Now, we can plug everything into the formula and solve for z, the hypotenuse:

[tex]cos(37)=10/z\\z*cos(37)=10\\z=10/cos(37)\\z=12.52135658\\z=12.52[/tex]

Beth could not join the club because the highest age which is allowed here is only 55 years

We know that;

A statistical expression obtained from a list of data that refers an abnormal gap from other values.

And, The statistical rules that instruct us to divides the data or observation values into four parts.

After analyzing the stem leaf diagram, we noticed the youngest age allowed to join the club is 10 years and the club allow highest 55 years old to join.

the plot also defines that the number of members is declined with the age. There is only person in the club who is 55 years. There are few members with the age over 40 years.

hence, Beth did not join the club because her age was above the highest age that allowed in this club.

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The binomial expansion is solved and the error in Dakota's statement is the incorrect substitution of 36g^2h^2 for the correct expression

Given data ,

Dakota made a mistake because the third term of the expansion of (2g + 3h) should have been 36g2h2. The binomial theorem asserts that the expansion of (2g + 3h) is as follows:

( x + y )ⁿ = ⁿCₐ ( x )ⁿ⁻ᵃ ( y )ᵃ

Here, x = 2g and y = 3h. Since term numbers begin at 0, since we are seeking for the third term, r = 2.

So , on simplifying the equation , we get

= nC2 * (2g)⁽ⁿ⁻²⁾ * (3h)²

= (n! / (2! * (n - 2)!)) * (2g)⁽ⁿ⁻²⁾ * (3h)²

= ((n * (n - 1)) / 2) * (2g)⁽ⁿ⁻²⁾ * (3h)²

Hence , the correct expression for the third term of the expansion of (2g + 3h) is ((n * (n - 1)) / 2) * (2g)^(n - 2) * (3h)², where n is the exponent in the binomial expansion.

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The other endpoint is (11, 1).

We have,

Midpoint = (6, 2) and endpoint = (1, 3).

and, ratio of m: n = 1 :1

Using section formula

6 = ( 1 + a) / (1+1)

6 = (1+a)/2

1 + a = 12

a = 11

and, 2 = (3 + b) / (1+1)

2 = (b + 3) /2

b +3 = 4

b = 1

Thus. the other endpoint is (11, 1).

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The value of the given expression in terms of i and j is -78i-12j.

Given that, v = - 8i+2j and w = -i-5j.

We need to find the value of 6w+9v.

Substitute v = - 8i+2j and w = -i-5j in 6w+9v, we get

6(-i-5j)+9(-8i+2j)

= -6i-30j-72i+18j

= -78i-12j

Therefore, the value of the given expression in terms of i and j is -78i-12j.

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Using the concept of similar triangles, the length of the other two sides of triangle B are: 20 cm and 25 cm

Similar triangles are  defined as triangles that possess the same shape, but then their sizes may very well vary. This means that, if two triangles are similar, then we can say that their corresponding angles are congruent and corresponding sides are in equal proportion.

Since the shortest side of triangle B is 10cm, it means that it corresponds to the shortest side of triangle A which is 8 cm.

Thus:

Ratio of corresponding sides of B:A = 10/8

Thus:

Second side of triangle B: (10/8) = (x/16)

x = 160/8

x = 20 cm

Third side of triangle B: 10/8 = y/20

y = 200/8

y = 25 cm

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The width of the worktable is 32 inches, and the length of the worktable is 82 inches.

Let's assume that the width of the worktable is "w" inches.

We are given that the length is 18 inches more than twice the width, which can be expressed as:

Length = 2w + 18

The perimeter of the worktable is the sum of the lengths of all four sides.

We know that the perimeter of the worktable is 228 inches, so we can write an equation:

Perimeter = 2 × (Length + Width)

228 = 2 × (2w + 18 + w)

228 = 2 × (3w + 18)

Dividing both sides by 2:

114 = 3w + 18

Subtracting 18 from both sides:

96 = 3w

Dividing both sides by 3:

w = 32

So, the width of the worktable is 32 inches.

Now we can use this value to find the length:

Length = 2w + 18

Length = 2 × 32 + 18

Length = 82

So, the length of the worktable is 82 inches.

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The linear equation outlining the entire volume of water (y) which has coursed through the hourglass following x days. is

The volume of water passed each which is the slope is

To ascertain the amount of water that is passing through the hourglass daily:

where:

Total water capacity: 2000 pounds

Time: 365 days

Water transpiring every day = Total water capacity / Time

Water pervading each day ≈ 200 / 365

Water pervading each day ≈ 5.48 pounds/day

the linear function of the water traveling through the hourglass.

Making x the number of days and y being the total quantity of water which has crossed through the hourglass after x days--as the fluid fluxes at a constant velocity--thus a linear relationship between x and y can be determined.

Every single day (x), the hourglass moves 5.48 pounds of water. This reveals the linear representation of:

y = 5.48x

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The calculated value of the area of the figure is 230.5 sq meters

From the question, we have the following parameters that can be used in our computation:

The composite figure

The area is the sum of the individual areas

Using the above and the area formulas as a guide, we have the following:

Area = 5 * 5 + (6 + 5) * 4 + 1/2 * 17 * (15 + 4)

Evaluate

Area = 230.5

Hence, the area is 230.5 sq meters

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Fwam and Eva are an equal distance of 69 miles away from the stadium when the time t = 3 hours

Given data ,

The formula for the distance (F) of Fwam from the stadium is:

F(t) = 327 - 42t

Since Fwam is travelling at a 42 mph pace, his distance from the stadium is reducing at a 42 mph rate.

The formula for Eva's separation from the stadium is:

E(t) = 396 - 65t

Eva's distance from the stadium also shrinks at a pace of 65 miles per hour as she drives at a speed of 65 mph.

Set F(t) = E(t) and solve for t to get the time at which Fwam and Eva are equally far from the stadium

On simplifying the equations , we get

327 - 42t = 396 - 65t

Adding 65t to both sides:

65t + 327 - 42t = 396

23t + 327 = 396

Subtracting 327 from both sides:

23t = 396 - 327

23t = 69

Dividing both sides by 23:

t = 69 / 23

t = 3 hours

Hence , at t = 3 hours after noon, both Fwam and Eva are an equal distance of 69 miles away from the stadium.

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The complete question is attached below :

Fwam and Eva are both driving along the same highway in two different cars to a stadium in a distant city. At noon, Fwam is gar miles away from the stadium and Eva is 396 miles away from the stadium. Fwam is driving along the highway at a speed of 42 miles per hour and Eva is driving at speed of 65 miles per hour. Let F represent Fwam's distance, in miles, away from the stadium t hours after noon. Let E represent Eva's distance, in miles, away from the stadium t hours after noon. Write an equation for each situation, in terms of t, and determine how far both Fwam and Eva are from the stadium at the moment they are an equal distance from the stadium.