if instead the same ball is used and the rope is shortened; that is, if rope 3 is half the length of rope 1, what is the tension t1 in the rope compared to the tension t3 in the shorter rope?

Answers

Answer 1

The tension in the shorter rope is double the tension in the longer rope T1<T3.

What is tension?
In physics, tension is defined as the pulling force that is transmitted axially by a string, rope, chain, or similar object, or through each end of a rod, truss member, or other comparable three-dimensional object. Tension can also be defined as the activity pair of forces acting at every end of the aforementioned elements. The polar opposite of compression might be tension. When atoms or molecules have been pulled apart from one another at the atomic level and gain potential energy while a restoring force is still present, the restoring force may produce what is also known as tension. When a string or rod is under such tension, each end may pull on the thing it is attached to in an attempt to release the tension and return the string or rod to its relaxed length.

The relation between the tension in the string and the length of the tetherball is,
mol=T The length of the rope 3 is half of the length of the rope 1.
Therefore mw^2l=T T∝l
The length of the rope 3 is half of the length of the rope 1.
Therefore l1=l3/2T1=T3/2T1<T3
Hence, the answer is T1<T3

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Related Questions

An elevator uses 100 000J of electrical energy to raise a load of 800 N through a height of 40m in a time of 20s. What is the rate of conversion of the electrical energy to other forms?

Answers

[tex]W_{out}=F\cdot d=800\cdot40=32000[/tex][tex]P_{out}=\frac{W_{out}}{t}=\frac{32000}{20}=1600W[/tex][tex]\begin{gathered} P_{in}=\frac{W_{in}}{t}=\frac{100000}{20}=5000W \\ \end{gathered}[/tex]

Therefore:

[tex]P_{out}:P_{in}=\frac{P_{out}}{P_{in}}=\frac{1600W}{5000W}=0.32[/tex]

Answer:

1600W

Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.

Answers

The average intensities of the waves compare I1 = 9 x  I2.

The electric field of an electromagnetic wave points in the positive y direction. At the same time, the magnetic field of this wave points in the positive z direction. In the electromagnetic field, electric and magnetic fields exist in the form of waves in horizontal and vertical patterns. To exist in this pattern requires maximum amplitude. Charged particles create electric fields.

This electric field exerts forces on other charged particles. A positive charge accelerates in the direction of the electric field, and a negative charge accelerates in the direction of the electric field. Magnetic fields are generated when charged particles move. In electromagnetic waves, the electric and magnetic fields are perpendicular to each other and both are also perpendicular to the direction of wave propagation.

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A 6 kg object experiences a 5 m/s² acceleration? Find the force that
caused this acceleration.

Answers

Answer:

F=ma

F=6kg×5m/s^2

F=30kgm/s^2

F=30newton

Which statement best describes the process of alpha decay? (1 point)
O An unstable nucleus rearranges its particles and releases energy.
O An unstable nucleus releases a single positively charged particle.
O An unstable nucleus releases an electron.
O An unstable nucleus releases a particle containing two protons and two neutrons.

Answers

Two protons and two neutrons are both present in the particle that an unstable nucleus releases.

What does alpha decay mean?

The nuclear process known as  "alpha decay" results in the parent nucleus emitting an alpha particle. The alpha particle, represented by the Greek letter and physically similar to the helium atom's nucleus, is made up of two protons and two neutrons.

Which statement about alpha decay is accurate?

What statement about deterioration is true? It brings down the atomic number of the nuclide by 2. The daughter nuclide, which frequently doesn't undergo further decay since the parent nuclide is unstable, is created during radioactive decay.

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which body has more internal energy - a piece of ice at a temperature of 0 degrees or from the melting of this ice at the same temperature?

Answers

The melting ice at the same temperature will have greater internal energy as compared to the ice at 0° C.

What is internal energy?

In thermodynamics, the internal energy is a quantity or state function that characterizes a substance's energy when capillary effects and other external fields, such as electric and magnetic forces, are absent. The value of the energy depends on the substance's state, not the nature of the processes that brought it to that condition, just like any other state function.

The melting ice at the same temperature will have more internal energy as compared to the ice at 0° C because during the melting of ice the intermolecular particles will absorb energy while breaking their bond and because of this, the melting ice has greater kinetic energy as well.

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Fiber optic cable is available in 12 km lengths. How long will it take for a signal to travel that distance assuming that the speed of light in the cable is the same as in a vacuum?.

Answers

The Time it takes a signal to travel the length of the cable of 12 km if the speed of light in the cable and the vacuum are the same is  4×10⁻⁵ s.

What is time?

Time is the measured or measurable period during which an action, process, or condition exists or continues.

To calculate how long it will take a signal to travel a distance the same as the lenght of the cable, we use the formula below.

Formula:

t = d/v.......... Equation 1

Where:

t = Time it takes a signal to travel the length of the cabled = Length of the cablev = Speed of the signal/ speed of electromagnetic wave.

From the question,

Given:

d = 12 km = 12000 mv = 3×10⁸ m/s

Substitute these values into equation 1

t = 12000/(3×10⁸ m/s)t = 4×10⁻⁵ s

Hence, the time its takes a signal to travel the length of the cable is 4×10⁻⁵ s.

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if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force. What is the reaction force in this situation?

A)Gravity from the ball pulls up on the Earth with 1.4 N of force.
B)Your fingers exerted an upward force of 1.4 N before they released the ball.
C)Once it hits the ground, normal force from Earth's surface will push up on the ball with 1.4 N
D)Air resistance pushes up on the ball with 1.4 N.

Answers

The reaction force in this situation occur once it hits the ground, and normal force from Earth's surface will push up on the ball with 1.4 N.

The correct answer is option (C)

What is Newton's third law of motion?

Newton's third law of motion states that for every action there is equal and opposite reaction.

Mathematically, this law is given as;

Fa = Fb

where;

Fa is the force applied by object AFb is the reaction experienced by object B

The force applied by object is equal and opposite the reaction experienced by object B.

When an object placed on the floor, the weight of the object acts downward while the normal reaction of the object acts upwards.

Thus, if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force, the reaction force will occur once it hits the ground, as the normal force from Earth's surface will push up on the ball with 1.4 N.

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145-g baseball is dropped from a tree 12.0 m above the ground. (a) with what speed would it hit the ground if air resistance could be ignored? (b) if it actually hits the ground with a speed of what is the average force of air resistance exerted on it?

Answers

The required speed is 15.35 m/s, if air resistance is ignored.

The magnitude of average force of air resistance is 1.0341N.

a) V = √2gh

The required speed is

V = √2(9.8)(12)

V = 15.35m/s

b) W = 1/2m([tex]v^{2}[/tex]-[tex]u^{2}[/tex])

    W = (mg - f)h

 ( (0.145)(9.8) - f)12 = 1/2(0.145)(([tex]8^{2}[/tex]))

(1.421 - f)12 = 4.64

Force of an air resistance  = 1.0341N

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1. A bike takes 9.0 seconds to decelerate to a stop over a distance of 30 meters. How fast was the bike traveling before the biker started to decelerate?

Answers

Answer:

Starting speed  Vo = 6.7 m/s

Explanation:

Given:

t = 9.0 s

S = 30 m

___________

V₀ - ?

The path is numerically equal to the area of  the figure lying under the velocity graph:

S = V₀* t / 2

Starting speed:

V₀ = 2*S / t = 2*30 / 9 ≈ 6.7 m/s

Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have ​four (4) total responses to this question (labeled A, B, C, and D).

Answers

The magnitude and direction of the net force are:

A: the net force is 3N in the downward direction,

B: the net force is zero,

C: The net force is 5N in the downward direction,

D: The net force is 4N in the right direction.

What is the net force?

The net force of an object can be described as the vector sum of all the forces acting on an object. The net force is a single force that shows the same effect as the original forces on the particle's motion.

The net force becomes the resultant force. The net force has the same effect on the rotational motion as all original forces together by the object.

The mathematical expression can be written for the net force as:

[tex]\vec F_{net} = \vec F_{x} + \vec F_{y}[/tex]

For figure (A), the net force is equal to :

F = (2N - 2N) + (2N - 5N) = - 3N

So the magnitude of the force is 3N in the downward direction.

For figure (B), the net force is equal to :

F = (2N - 2N) + (5N - 5N) =  0

So the magnitude of the net force is equal to zero.

For figure (C), the net force is equal to :

F = (5N - 5N) + (5 N) = 5 N

So the magnitude of the net force is 5N in the downward direction.

For figure (D), the net force is equal to :

F = (2N - 2N) + (7N - 3N) = 4N

So the magnitude of the net force is 4N towards the right direction.

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a cat slides down a slippery slanted roof at an acceleration of 2.2 m/s2 (it won't get hurt because it has nine lives). if it started at the top with zero initial speed, how far will the cat have slipped after 3 seconds? answer in meters and include two digits after the decimal point.

Answers

The cat will have slipped till the distance of 9.90 seconds in 3 seconds.

The acceleration of the cat is 2.2m/s², the initial velocity of the cat is 0m/s and the time take the cat takes to come down is 3 seconds.

Now, using equation of motion,

S = Ut + 1/2at²

Where,

U is initial velocity of the body,

t is the time period of the body,

S is the displacement of the body,

a is the acceleration of the body.

Putting all the values,

S = 1/2at²

S = 1/2(2.2)(3)²

S = 9.90 meters.

The distance to which the cat will fall is 9.90 meters.

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air is moving at a velocity of 8 m/s through a hoop with cross sectional area of 100.0 m2. if the density of the air is 1.2 kg/m3, what mass flow rate of air is moving through the hoop (in kg/s)?

Answers

In consideration of Henry's law the molar mass of organic compound is 0.24 grams.

What is molar mass?

The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound. What is the mass of water in grammes and how much Equis paper with a 12.5% sodium chloride content weighs at 55 degrees Celsius, according to Sol-One of three? His issue informs us that pure water has a specific gravity of 118 torr at 55 degrees Celsius. Therefore, the first task at hand is to determine the mole fraction of, I suppose, the thermal fractions of both water and sodium chloride.

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A force of 10 n stretches a particular spring by 2 cm. How far would a 20 n force stretch that same spring?.

Answers

For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law

so,  20 N force stretch 4 cm.

What is the Hooke's law ?Hooke's law is a law of elasticity discovered by the English scientist Robert Hooke in 1660 that states that the displacement or size of a deformation is directly proportional to the deforming force or load for relatively small deformations of an object.It is the fundamental principle underlying the manometer, spring scale, and clock balance wheel. Hooke's law is the underlying principle of seismology, acoustics, and molecular mechanics.Hooke's spring law usually applies to any elastic object of any complexity, as long as the deformation and stress can be expressed by a single number that can be both positive and negative.

For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law as :

F=kx

where

F = Force

k = is spring

constant  

x = stretches

here

10/ 2 = 20/ x

x -= 4 cm .

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a person threw a small bundle toward their friend on a balcony 10 meters above them. how fast did they throw it up?

Answers

The speed with which they threw the bundle is  14 m/s.

What is the speed of the bundle?

We know that the speed of the bundle can be obtained from the use of the equations of kinematics. Now we can use the equation of the upward motion under gravity here.

Using;

v^2 = u^2 - 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Now;

v = 0 m/s at the maximum height

u^2 = 2gh

We now have;

u = √2gh

u = √ 2 * 9.8 * 10

u = 14 m/s

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Physics Trajectory question.
I need help finding the answers on Vy.

Answers

The vertical component of the velocity after the given interval of time will be:

B: -9.8 m/s

D: -19.6 m/s

F: -29.4 m/s

H: -39.2 m/s

What is a projectile?

A projectile can be described as any object upon which the only force is gravity. The projectile travels with a parabolic trajectory because of the influence of gravity. No horizontal forces are acting upon projectiles so there is no horizontal acceleration.

The horizontal velocity of a projectile is constant and the vertical acceleration is caused by gravity. The vertical component of the velocity of a projectile changes by 9.8 m/s each second while the horizontal motion of a projectile is independent of its vertical motion.

Given, the initial horizontal velocity, vₓ = 18 m/s

The initial vertical velocity, Vy = 0 m/s

The time interval = 1 sec

The vertical component of the velocity is calculated as;

[tex]V_y = V_{0y} -gt[/tex]

[tex]V_y = 0- (9.8) (1)\\V_y = -9.8 m/s[/tex]

The vertical component when t = 2 sec and horizontal velocity, Vx = 18 m/s

[tex]V_y = 0- (9.8) (2)\\V_y = -19.6 m/s[/tex]

The vertical component of velocity when t = 3sec:

[tex]V_y = 0- (9.8) (3)\\V_y = -29.4 m/s[/tex]

The vertical component of velocity when t = 4sec:

[tex]V_y = 0- (9.8) (4)\\V_y = -39.2 m/s[/tex]

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Explain one recent idea that scientists have proposed for how the universe began. Consider the big bounce theory or the multiverse theory.

Answers

The most widely accepted theory about the universe is the big bang theory.

What is big bounce theory?

The Big Bounce theory refers to the universe that is expanding and contracting, move back and forth in a big-picture timeline. The Big Bang theory was happened about 13.8 billion years ago when the universe began as a tiny, dense, ball that exploded. Many astronomers use the Big Bang theory to show how the universe began. But what caused this explosion in the first thing that is still a mystery. It has passed through many stages, which can be considered cosmological theories. The flat Earth, the geocentric model, heliocentricity, galactic centricity, the Big Bang, and the Inflationary Big Bang. In the Big Bounce theory, the universe is expanding and contracting, seesawing back and forth in a massively big-picture timeline more specific theory called "Big Bounce" theory proposes that the universe could collapse to the state where it is first started and then initiate another Big Bang.

So we can conclude that The Big Bang theory says that the universe came into being from a single more than 13 billion years ago.

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jim leaves his house and begins walking to his car in a straight line. he goes 2.0 m then returns to his house to get his keys. next, he leaves his house and travels 6.0 m to his car. what is jim's displacement?

Answers

Jim's displacement if Jim leaves his house and begins walking to his car in a straight line and he goes 2.0 m then returns to his house to get his keys, next, he leaves his house and travels 6.0 m to his car is 6 m

Δx = x2 - x1

Δx = Displacement

x2 = Final position

x1 = Initial position

Considering the house as origin,

Final position = 6 m

Initial position = 0

Δx = 6 - 0

Δx = 6 m

Displacement is the vector quantity that describes position change in a motion. Its scalar quantity distance describes the overall distance travelled during the entire motion.    

Therefore, Jim's displacement is 6 m

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a football player runs from a location 5m from the left sideline and 5m from his/her goal line to a location 35m from the left sideline and 60m from the goal-line. displacement is 63m. the player did not run in a straight line. at the start there is 1-minute left on the clock; at the end there is 50 seconds left on the clock. knowing only this information, what kinematic variables can we calculate?

Answers

Knowing only this information, the kinematic variable we can calculate is  Vavg = 6.3 m/s. Option B - average velocity

velocity is the directional velocity of an object in movement as an illustration of its rate of trade in function as found from a selected body of reference and as measured by means of a specific standard of time.

The average velocity is defined because of the alternate in function or displacement (∆x) divided by the point durations (∆t) in which the displacement takes place. The common pace may be tremendous or negative relying upon the sign of the displacement.

As it is given that the player is not moving in a straight line then distance and Displacement will not same.

We know average velocity is the ratio of total displacement to the time and if both are known then it can find easily.

Hence average speed can't be found

Vavg = 63/(60-50)  m/s

Vavg = 6.3 m/s

Instantaneous velocity is the velocity at a certain point of time that can't be found because there is only given initial &  final locations

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a winter storm that blows cold wind at least 56 km/hr and has falling or blowing snow that reduces visibility to less than 400 m for at least three hours is classified as a(n) blank . multiple choice question.

Answers

Wind speeds of above 56 kilometers per hour (35 miles per hour) are common during blizzards. These winds reduce visibility by causing a lot of snow to blow around in the air and close to the ground.

What is Blizzards?A blizzard is a severe snowstorm that lasts for a long time—typically at least three or four hours—and is marked by strong sustained winds and low visibility. When snow is not falling but rather loose snow on the ground is lifted and blasted by strong winds, the weather is called a "ground blizzard." A blizzard, according to the National Weather Service, is a storm with heavy snowfall or snow that is blowing, winds that are greater than 35 mph (56 kph), and visibility that is less than 14 mile (0.4 km) for at least three hours. There is no snow falling during some blizzards, known as ground blizzards.

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A 33-N force is applied to a 7-kg object to move it with a constant velocity of 6.3 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)

Answers

Given:

The applied force is,

[tex]F=33\text{ N}[/tex]

The mass of the object is,

[tex]m=7\text{ kg}[/tex]

The constant velocity of the object is,

[tex]v=6.3\text{ m/s}[/tex]

To find:

The coefficient of friction between the object and the surface

Explanation:

The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.

If the coefficient of friction between the object and the surface is

[tex]\mu[/tex]

we can write the frictional force as,

[tex]f=\mu mg[/tex]

For equilibrium condition,

[tex]\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}[/tex]

Hence, the coefficient of friction between the object and the surface is 0.47.

Air is approximately 21% o2 and 78% n2 by mass. Calculate the root-mean-square speed of each gas at 273 k.

Answers

The root square method of the gas at 273 K is given as 493.15 for N2 and 461.3 for O2

How to solve for the root mean square method

We have to know that the root square method is dependent on the direct proportionality to the square root of absolute temperature as well as inverse of molar mass.

We have 1 j = 1 kgm²/s²

Vrms = √3rt/Mm

R = gas constant

T = temperature = 273

Mm is the molar mass

The molar mass of N₂ is = 0.02800 kg / mol

The mo;lar mass of o₂ = 0.03200 kg / mol

We have to solve first for N₂

= √3 (8.32447 * 273 / 0.028000

= √243,198.247

= 493.15

For 02

Vrms = √3 * 8.31447 * 273  / 0.03200

= √212798.466

= 461.3

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does increasing the magnitude of a uniform magnetic field through which a charge is traveling necessarily mean increasing the magnetic force on the charge? does changing the direction of the field necessarily mean a change in the force on the charge?

Answers

Since the magnetic force and velocity are orthogonal, the velocity only changes in direction but not in magnitude . Circular motion is the end consequence. The force is in the opposite direction from the right-hand rule and has a negative charge.

Uniform In circular motion, an object moves in two dimensions with a constant speed in a fixed circular direction; however, because the object's direction changes at every point, the velocity also changes, and the direction at each point is always the tangent.

In physics, magnetic force is referred to as an object's maximal size and direction. Both vector and scalar values use magnetic force as a common factor. We understand that by definition

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Answer: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal.

Explanation: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal. The resultant motion is circular. The force has a negative charge and is directed in the opposite direction from the right-hand rule.

Uniform In a circular motion, an item moves in two dimensions with a constant speed in a fixed circular direction; yet, because the object's direction varies at each point, the velocity also alters, and the direction at each point is consistently the tangent.

As an object's maximum size and direction, the magnetic force is referred to in physics. Magnetic force is a factor that is present in both scalar and vector values. We comprehend that by nature.

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a strechy material with a spring constant of 68.7 n/m is stretched 2.71 cm from its equilibrium length. what is the magnitude of the resulting spring force?

Answers

The magnitude of the resulting spring force when the material is stretched from its equilibrium position is -0.02522 N.

The spring force is a spring or a stretchy material is given by the formula,

F = -1/2Kx²

Where z

F is the spring force,

K is the spring constant,

x is the compression or extension in the material,

The negative sign represent that the force is restoring in nature.

We know, in our case,

The extension in the material is 2.71cm.

1 cm = 1/100m

So,

2.71 cm = 2.71/100m

The spring constant is 68.7N/m.

Now, putting all the values,

F = 1/2Kx²

F = -1/2(68.6)(2.71/100)²

F = -0.02522N.

So, the spring force is 0.02522N.

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A crate is at rest on an inclined plane. As the slope increases the crate remains at rest until the incline reaches an angle of 32.7° from the horizontal. At this angle the crate begins to slidedown the ramp.Draw a free body diagram of the crate just before it slides

Answers

The free body diagram of the crate can be shown as,

Here, N is the normal force acting on crate, mg is the weight of crate, f is the frictional force and theta is the angle of inclination of plane.

a ball is thrown upward with initial velocity of 20 m/s. (a) how long is the ball in the air? (b) what is the greatest height reached by the ball? (c) when is the ball 15 m above the ground?

Answers

a) t = 4.08 s

b) Response = 20.39m

c) t = 0.991 and 3.087 seconds.

Initially, the vertical speed was 20 m/s.

(a) how long is the ball in the air?

The ball is tossed upward, rises to its highest point, and then hits the ground again.

Consequently, the end height will be equal to the starting height.

h = h o = Om

Use the equation s= ut + -at.

2764 – An = 14

Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.

Om = t - 0.5 * 9.81 m/s * 20 m/s

0 = 20 *t - 0.5 * 9.81 *t

20 *t=0.5*9.81 *t

20 = 0.5 * 9.81 *t

20 0.5*9.81

Answer (a): t = 4.08 s

(b) what is the greatest height reached by the ball?

Vertical velocity for the ball decreases to zero when it reaches its highest point.

Use the equation 2-u=295

-2ghmas for - u

(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *

02 – 20= -2*9.81 *

-20% = -2 *9.81 *

202 = 2 * 9.81 *  

b) RESPONSE: H = 20.39m

(c) when is the ball 15 m above the ground?

The ball will be 15 meters above the earth on two separate occasions.

1. When climbing

2. When descending

Use the equation s= ut + -at.

2,264 – fn = 4

0.5 * 9.81 m/s * 15m = 20 m/s*t

15 = 20 *t - 0.5 * 9.81 *t

15 = 20t – 4.9057

4.905 – 20t + 15 = 0

Calculator-based quadratic equation solution

(c) t = 0.991 and 3.087 seconds.

Hence the answers are,

a) t = 4.08 s

b) RESPONSE: Hmar = 20.39m

c) t = 0.991 and 3.087 seconds.

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an object is launched from ground level with an initial speed of 24.6 meters/second at an upward angle of 0.595 radians above the horizontal (90 degrees is about 1.57 radians). how far will it travel horizontally before hitting the ground?

Answers

The object will travel 55.67 meters horizontally before hitting the ground.

The object is launched with speed 24.6 meters/second.

The angle at which the object is launched is 0.595 radians.

We know,

90° = 1.57 radians

1 radian = 90°/1.57

So,

0.595 radians = 90°(0.595)/1.57

0.595 radians = 34°

The horizontally distance R travelled by the projectile can be given by,

R = U²sin2A/g

Where, U is the initial speed,

A is the angle at which object is launched,

g is acceleration due to gravity,

Putting all the values,

R = (24.6)²sin(68°)/10

R = 55.67 meters.

The horizontal range is 55.67 meters.

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an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the three devices are in parallel when plugged into the same socket.) what current is drawn by the electric frying pan?

Answers

The current drawn by the electric frying pan is 27.295 A.

Power of toaster, P1 = 1800 W

Power of electric frying pan, P2 = 1400 W

Power of lamp, P3 = 75 W

Three devices are in parallel combination. So their Voltage difference is the same.

∆V = 120 Volt

Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A

Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A

Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A

Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A

Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.

The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.

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In an arena football game, the quarterback throws a pass so that it reaches the top of the stadium at the peak of its flight. If he threw the ball at an angle of 64 degrees and the stadium is 34 meters high, calculate the velocity with which he threw the ball and the distance the ball traveled.​

Answers

Formulas for projectile motion:

Maximum height of projectile, h = [tex](u sin(\alpha )^{2}[/tex] / 2g

Horizontal range of projectile, R = [tex]u^{2}[/tex] sin(2α) / g

where u is the initial velocity, α is the angle of projection, and g is the acceleration due to gravity.

Given:

Angle of projection, α = 64°

Maximum height of projectile, h = 34 m.

To find: Initial velocity (u), and horizontal distance travelled (R).

Rearrange 'h' equation for 'u',

u sin(α) = [tex]\sqrt{2gh}[/tex]

⇒ u = [tex]\frac{\sqrt{2gh} }{sin(\alpha )}[/tex]

Substitute given values.

⇒ u = [tex]\sqrt{2*(9.8m/s^{2}*34m }[/tex] / sin(64°)

⇒ u = 25.81 / 0.899 m/s

∴ u = 28.71 m/s

This is the velocity with which the ball was thrown.

The distance travelled by the ball can be calculated by using the equation,

R = [tex]u^{2}[/tex] sin(2α) / g

Substitute the given values.

⇒ R = ([tex]28.71^{2}[/tex]× sin (2×64°)) / 9.8

⇒ R = 649.53 / 9.8

∴ R = 66.27 m.

This is the distance travelled by the ball.

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a lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline and its light makes four revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p?

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A lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline is the beam of light moving along the shoreline when it is 1 km from p is 83.78 km/min

3*10/9*8pi = dx/dt

80pi/3 = dx/dt

dx/dt = 83.78 km/min

Thus, the beam of light is sweeping along the shore at the rate of 83.78 km/min when the beam is 1 km from the point P and light makes four revolutions per minute.

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what is the tension in a tow rope that is used to accelerate a 1700-kg car at 0.5 m/s2? (ignore the effects of friction.) a) assuming the tow rope is completely horizontal? b) assuming the tow rope is 400 above the horizontal?

Answers

The tension in a tow rope,

a ) If it is completely horizontal = 850 N

b ) If it is 40° above the horizontal = 1103.9 N

F = m a

F = Net force

m = Mass

a = Acceleration

m = 1700 kg

a = 0.5 m / s²

∑ [tex]F_{x}[/tex] = m a

T = m a

T = 1700 * 0.5

T = 850 N

b ) Assuming the tow rope is 40° above the horizontal,

θ = 40°

Resolving the tension force into its horizontal component,

Tx = T cos θ

∑ [tex]F_{x}[/tex] = m [tex]a_{x}[/tex]

Tx = 1700 * 0.5

T cos 40° = 850

T = 1103.9 N

Therefore, the tension in a tow rope,

a ) If it is completely horizontal = 850 N

b ) If it is 40° above the horizontal = 1103.9 N

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