If c + d = 16 and d = 6, what is c- d?

Answer:

120 kg of 30% fat-content chocolate and 30 kg of 40% fat-content chocolate.

Step-by-step explanation:

We are given that a candy distributor needs to mix a 30% fat-content chocolate with a 40% fat-content chocolate to create 150 kilograms of a 32% fat-content chocolate.

Let the amount of 30% fat-content chocolate be 'x' and the amount of 40% fat-content chocolate be 'y'.

So, according to the question;

x + y = 150 ------------ [equation 1]

and [tex]30\% \text{ of } x + 40\% \text{ of } y=32\% \text{ of } 150[/tex]

[tex]30x+40y= 32 \times 150[/tex]

[tex]30x+40\times (150-x)= 4800[/tex]

[tex]30x+6000-40x= 4800[/tex]

[tex]10x = 6000-4800[/tex]

[tex]x=\frac{1200}{10}[/tex]

x = 120 kg

Now, putting the value of x in equation 1, we get;

x + y = 150

120 + y = 150

y = 30 kg

Hence, 120 kg of 30% fat-content chocolate and 30 kg of 40% fat-content chocolate.

We will use the segment addition postulate.

PQ + QR = PR

4x - 1 + 3x - 1 = 54

7x - 2 = 54

7x = 56

x = 8

So QR is 3(8) - 1 or 24 - 1 which is 23.

Answer:

QR is 23

Step-by-step explanation:

Answer:

x = 1

Step-by-step explanation:

I hope this helps!

Answer:

D

Step-by-step explanation:

Yw UVU

Answer:

Step-by-step explanation:

We have 6 numbers, the mean is the average of all 6, so adding all 6 numbers together and dividing by 6 will give you 3. Because of this we know the 6 numbers will have to add up to 18.

The median is the middle number, but we have an even number so the median is found by adding the 2 middle numbers and dividing by 2.

Because the mean is low, we can guess the first 2 numbers will be small, so let's try 1.  

1 + 1 + _ + _ + _ + _

The remaining 4 numbers will have to add up to 16, and the next 2 numbers need to add up to 12. There would not be any possible combination where this would work. Now we know our first 2 numbers are too big.

Now we try 0.

0 + 0 + _ + _ + _ + _

Now our remaining 4 numbers neet to be 18, but the middle 2 need to add to 12 (so when we divide by 2 we get 6) so 0 is still too big!

-2 + -2 + _ + _ + _ + _  

If we try -2 now the next 4 numbers need to add to 22, but that's still not going to work because 22-12 = 10 and the last 2 numbers have to be the same, or larger than the middle 2.

-3 + -3 + _ + _ + _ + _  

With -3 then our total of the remaining 4 numbers needs to be 24 and 24-12 = 12 so this could be an option!

Our numbers could be:

-3, -3, 6, 6, 6, 6

Let's check:

-3 + -3 + 6 + 6 + 6 + 6 = 18   18/6 = 3    and our middle 2 numbers are 6 so our median would be 6.

If the numbers all have to be different we can come up with a different solution by making our first 2 numbers smaller.

-9, -5, 5, 7, 9, 11  

Let's check

-9 + -5 + 5 + 7 + 9 + 11

-14 + 32 = 18  mean  18/6 = 3      median 5+7 = 12 and 12/2 = 6

So that could also work! There are actually many options that would be correct!

One of the set of numbers whose mean is 3 and median is 6 is 0, 1, 5, 7, 2 and 3.

Mean of a set of numbers is the average value of the numbers. Mean is calculated by taking the sum of the given numbers divided by the total number of numbers.

Let x₁, x₂, x₃, x₄, x₅ and x₆ be the six numbers.

We have mean = 3

⇒ (x₁ + x₂ + x₃ + x₄ + x₅ + x₆) / 6 = 3

⇒ x₁ + x₂ + x₃ + x₄ + x₅ + x₆ = 18

Median is the midpoint of the set of numbers arranged in ascending or descending orders.

If the number of set of numbers are odd, then median is the midpoint of the set and if the number of the set is even, then median is the average of the middle two elements.

Median = 6

Since there are 6 numbers here median = (x₃ + x₄) / 2

(x₃ + x₄) / 2 = 6

(x₃ + x₄) = 12

So x₁ + x₂ + x₅ + x₆ = 18 - 12 = 6

Lets just say x₁ = 0, x₂ = 1, x₅ = 2 and x₆ = 3, the sum of which equals 6.

Now, let x₃ = 5 and x₄ = 7, such that x₃ + x₄ = 12

So one of the set which satisfies the given conditions is x₁, x₂, x₃, x₄, x₅ and x₆ = 0, 1, 5, 7, 2 and 3 respectively.

Hence, one of the list of 6 numbers whose mean equals 3 and median equals 6 is 0, 1, 5, 7, 2 and 3.

To learn more about Mean, click:

https://brainly.com/question/26509052

#SPJ2

Answer:

BD = 72

Step-by-step explanation:

C is the midpoint of BD.

Therefore,

BD = 2BC

13x - 6 = 2*6x

13x - 6 = 12x

13x - 12x = 6

x = 6

BD = 2*6X = 12*6= 72

Answer:

9

Step-by-step explanation:

13-4=9

9+4=13

Hey there!☺

[tex]Answer:\boxed{x=9}[/tex]

[tex]Explanation:[/tex]

[tex]x+4=13[/tex]

To find x, subtract 13 by 4.

[tex]13-4=9[/tex]

Let's try substituting 9 for x to see if we get 13.

[tex]x+4=13\\9+4=13[/tex]

[tex]x=9[/tex]

Hope this helps!

Answer:

1) ∫₀¹ 2π x (x − x²) dx

4) ∫₀¹ π ((√y)² − y²) dy

Step-by-step explanation:

The solid formed is a hollow, upside down cone.  We can either use washer method or shell method to find the volume.

If we use washer method, the thickness of the washers is dy.  The outside radius is R = x₂ = √y, and the inside radius is r = x₁ = y.

Therefore, the volume of each washer is:

dV = π (R² − r²) t

dV = π ((√y)² − y²) dy

The total volume is the sum of all washers from y=0 to y=1.

V = ∫ dV

V = ∫₀¹ π ((√y)² − y²) dy

If we use shell method, the thickness of each shell is dx.  The radius of each shell is r = x.  The height of each shell is h = y₂ − y₁ = x − x².

Therefore, the volume of each shell is:

dV = 2π r h t

dV = 2π x (x − x²) dx

The total volume is the sum of all shells from x=0 to x=1.

V = ∫ dV

V = ∫₀¹ 2π x (x − x²) dx

Answer:

2

Step-by-step explanation:

out of 10 that were taking math 8 of them were also taking english. 10-8=2

Answer:

Step-by-step explanation:

You know that lines PQ and RS are parallel and line XY is a transverse line. This means that XMP and QMN are equal because they are vertical angles. Now set the equations equal to each other because they are.

10x-7=6x+21 and solve for x

4x-7=21

4x=28

x=7 boom

Answer:

erxytfgnb

Step-by-step explanation:

Answer and Step-by-step explanation:

The volume of the resulting solid is shown below:-

The lines in for

y can be y = sqrt(x) using square root

and y = x ÷ 5

In this, the intersect is done when sqrt(x) = x ÷ 5  using square root

Now

x = x^2 ÷ 25

x = 0

or

x = 25

so outermost is x ÷ 5 innermost is sqrt(x)  using square root

Therefore A is

= integral of pi ( (x ÷ 5-5)^2 - (sqrt(x)-5)^2)  using square root

from 0 to 25

= 625 pi ÷ 6

Answer:

[tex](x - 3)^{2} = 17[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 6x = 8 \\ {x}^{2} - 6x + 9 = 8 + 9 \\ (x - 3)^{2} = 17[/tex]

Answer: the value would be 90

Step-by-step explanation:

Answer: 0

Step-by-step explanation: To make this easier, ignore the addition sign (for this one, at least), so just do 5-5

Answer: 0

Step-by-step explanation:

Answer:

52,920

Step-by-step explanation:

Answer:

52,920^^

Step-by-step explanation:

brains plss

Answer:

={b,c,d,e,f,g}

Step-by-step explanation:

={b,c,d,e,f,g}

Answer:

PUR= b, d, f, g, c, e

Step-by-step explanation:

To fid the answer you unite the sets together. When uniting the sets you only write the letter once even if it appears in both sets.

So when we combine p and r the answer we get is:

PUR= b, d, f, g, c, e

HOPE IT HELPED

Answer:

I'm Sorry, do you have a question you need help with?

Step-by-step explanation:

Answer: [tex]f^{-1}(x)=\sqrt{x+49}[/tex]

Step-by-step explanation:

To find the inverse of a function, you want to switch the x with y and y with x. After that, you solve for y.

y=x²-49                            [switch x with y and y with x]

x=y²-49                            [add both sides by 49]

x+49=y²                           [square root both sides]

[tex]y=\sqrt{x+49}[/tex]

Now, we know that [tex]f^{-1}(x)=\sqrt{x+49}[/tex].

Answer:

No solution

Step-by-step explanation:

Step 1: Write equation

-6(3 + x) + 2(3x + 5) = 0

Step 2: Solve for x

Distribute: -18 - 6x + 6x + 10 = 0

Combine like terms: -8 ≠ 0

∴ No solution

No answer

Step-by-step explanation:

-6(3+x) Multiply -6 by 3=-18. -18+-6x     2(3x+5) 6x+10

(-18+-6x) + (10+6x) = (-8 = 0).

Answer:

it is the answer here copy and paste

Step-by-step explanation:

adding and subtracting decimals are different from adding and subtracting whole number because of the values are not going to be the same any more.      

          extra; example 40.04 has hundredths and 4004 has hundreds.

Answer:

The answer is:

In both types of problems you rewrite the problem vertically, line up the decimals, and add zeros or rename where needed.

Step-by-step explanation:

Edge 2021

Answer:f(g(0))= 1/5

              g(f(0))= 7

Step-by-step explanation:

for f(g(0))=you solve for g(x) but you plug in 0 for x so g(0)= 8(0)+3

                                                                                                    =3

 so now you plug in the answer of the function of g(x) witch is 3 and plug it in as the x for F(x) so f(3)= 1/(3)+2

                                     = 1/5

so f(g(0)) is equal to 1/5

Now for G(f(0)) you solve for f(x) by pluging 0 for x so F(0)= 1/(0)+2

                                                                                               =1/2

now you plug in 1/2 for the x of g(x) so g(1/2)= 8(1/2)+3

                                                                         = 4+3

                                                                         =7

so g(f(0)) is equal to 7

Hope this helps:)

Exact answer: 8.5

Rounded Answer: 9

Answer:

7.5 Hours

Step-by-step explanation:

48x + 256 = 616

      - 256 = -256

-----------------------------------

48x =  360 divide both side by 48

-----     -------

48        48

x = 7.5

Answer:

p = 2L + 2W

total fencing = 100 feet

we have w = 20

then

100 = 2L + 2W

100 = 2L + 2*20

100 -40 = 2L

2L = 60

L= 60/2 = 30

Answer:

[tex] \boxed{ \sf{length \: of \: a \: rectangle = 21 \: in.}}[/tex]

[tex] \boxed{ \sf{width \: of \: a \: rectangle = 10.5 \: in.}}[/tex]

Step-by-step explanation:

Let the length of a rectangle be ' l '

Width of a rectangle ( w ) = [tex] \sf{ \frac{1}{2} l}[/tex]

Perimeter of a rectangle ( P ) = 63 in.

First, finding the length of a rectangle ( l )

[tex] \boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + b)}} \:[/tex]

[tex] \dashrightarrow{ \sf{63 = 2(l + \frac{1}{2} l}})[/tex]

Distribute 2 through the parentheses

[tex] \dashrightarrow{ \sf{63 = 2l + 2 \times \frac{1}{2} l}}[/tex]

[tex] \dashrightarrow{ \sf{63 = 2l + l}}[/tex]

Add the like terms : 2l and 3l

[tex] \dashrightarrow{ \sf{63 = 3l}}[/tex]

Swap the sides of the equation

[tex] \dashrightarrow {\sf{3l = 63}}[/tex]

Divide both sides by 3

[tex] \dashrightarrow{ \sf{ \frac{3l}{3} = \frac{63}{3}}} [/tex]

Calculate

[tex] \dashrightarrow{ \sf{l = 21 \: in.}}[/tex]

Length of a rectangle = 21 in.

Now, replacing / substituting the value of l in 1/2 l in order to find the width of a rectangle

[tex] \dashrightarrow{ \sf{width = \frac{1}{2} l}}[/tex]

[tex] \dashrightarrow{ \sf{width = \frac{1}{2} \times 21}}[/tex]

[tex] \dashrightarrow{ \sf{width = 10.5 \: in.}}[/tex]

Width of a rectangle = 10.5 in.

Hope I helped!

Best regards! :D