if A/B and C/D are rational expressions,then which of the following is true?*PHOTO*

If A/B And C/D Are Rational Expressions,then Which Of The Following Is True?*PHOTO*

Answers

Answer 1

In general,

[tex]\begin{gathered} \frac{w}{x}*\frac{y}{z}=\frac{w*y}{x*z} \\ x,z\ne0 \end{gathered}[/tex]

Therefore, in our case, (Notice that since A/B and C/D are rational expressions, B and D cannot be equal to zero)

[tex]\frac{A}{B}*\frac{C}{D}=\frac{A*C}{B*D}[/tex]

Notice that the left side of each option includes the term

[tex]\frac{A}{B}*\frac{D}{C}[/tex]

However, we cannot assure that C is different than zero because it is only stated that C/D is rational.

Furthermore,

[tex]\frac{A}{B}*\frac{D}{C}=\frac{A*D}{B*C}[/tex]

And (A*D)/(B*C) is not included among the options.

Therefore, the answer has to be option D as it is the only one that correctly expresses the multiplication of two fractions.Remember that there is a mistake in each option, the left side has to be A/B*D/C


Related Questions

9. The Elite Vacuum Company has determined its cost for making vacuums to beC = 24V + 1000, where C is the cost in dollars and V is the number of vacuums.If the cost must be between $49,000 and $121,000, how many vacuums can they makeper week? (You must set up and solve an inequality.)

Answers

We are given the relationship between the cost in dollars (C) and the number of vacuums (V) to be:

[tex]C\text{ = 24V + 1000}[/tex]

From the constraint, we have that the cost(C) must be greater than $49000 and less than $121000

Writing this as inequality:

[tex]\begin{gathered} 24V\text{ + 1000 }\ge\text{ 49000 } \\ 24V\text{ + 1000 }\leq\text{ 121000} \end{gathered}[/tex]

Solving the linear inequalities for V:

[tex]\begin{gathered} 24V\text{ + 1000 }\ge\text{ 49000} \\ 24V\text{ }\ge\text{ 49000 - 1000} \\ 24V\text{ }\ge\text{ 48000} \\ \text{Divide both sides by 24} \\ \frac{24V}{24}\text{ }\ge\text{ }\frac{48000}{24} \\ V\text{ }\ge\text{ 2000} \end{gathered}[/tex]

Similarly for the second inequality:

[tex]\begin{gathered} 24V\text{ + 1000 }\leq\text{ 121000} \\ 24V\text{ }\leq121000\text{ - 1000} \\ 24V\text{ }\leq\text{ 120000} \\ \text{Divide both sides by 24} \\ \frac{24V}{24}\text{ }\leq\text{ }\frac{120000}{24} \\ V\text{ }\leq5000 \end{gathered}[/tex]

Hence, the number of vacuums they can make per week can be between 2000 and 5000 or in inequality:

[tex]2000\text{ }\leq\text{ V }\leq\text{ 5000}[/tex]

Answer:

Between 2000 and 5000 vacuums

In AUVW, VW = UV and mZU = 74º. Find mZV.

Answers

We will find the measure of angle V as follows:

*From theorem we have that angles that are opposite to congruent sides are congruent. So, Angle W will also have a measure o 74°. Now, we also have that the sum of all internal angles of a triangle add 180°, so the following is true:

[tex]U+V+W=180\Rightarrow74+V+74=180[/tex]

Now, we solve for V:

[tex]\Rightarrow V=32[/tex]

So, the measure of angle V is 32°.

Given the following information about events A, B, and C, determine which pairs of events, if any, are independent andwhich pairs are mutually exclusive.

Answers

Let's begin by identifying key information given to us:

[tex]\begin{gathered} P(A)=0.39 \\ P(B)=0.42 \\ P(C)=0.19 \\ P(A|B)=0 \\ P(C|B)=0.19 \\ P(A|C)=0.39 \end{gathered}[/tex]

When two events A and B are independent we have it thus:

[tex]undefined[/tex]

An ice cream truck began its daily route with 95 gallons of ice cream. The truck driver sold 58% of the ice cream. How many gallons of ice cream were sold? round to nearest gallon

Answers

Start making the percentage as a fraction

[tex]\begin{gathered} 58\text{\%}=\frac{58}{100} \\ \end{gathered}[/tex]

multiply the fraction by the total of the daily routine

[tex]95\cdot\frac{58}{100}=55.1\approx55gallons[/tex]

Use the formula for n^P_r to evaluate the following expression.

Answers

Use the following formula:

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

Then, for 11P6:

[tex]\begin{gathered} _{11}P_6=\frac{11!}{(11-6)!}=\frac{11!}{5!}=\frac{5!\cdot6\cdot7\cdot8\cdot9\cdot10\cdot11}{5!} \\ _{11}P_6=6\cdot7\cdot8\cdot9\cdot10\cdot11=332640 \end{gathered}[/tex]

Hence, the result is 332640

A vase is in the shape of a cone. The height is 12 inches and the diameter is 4.4 inches.
What is the lateral surface area to the nearest tenth of a square inch?
O
O
24.3 square inches
149.1 square inches
168.6 square inches
99.5 square inches

Answers

84.27 square inch is the lateral surface area of cone.

Define lateral surface area.

All of an object's sides, excluding its base and top, are considered its lateral surface. The size of the lateral surface is referred to as its area. This must be distinguished from the total surface area, which consists of the base and top areas as well as the lateral surface area. A figure's lateral area consists solely of the non-base faces. The lateral surface area of several forms, such as a cuboid, cube, cylinder, cone, and sphere, is discussed in this article.

Given,

Height = 12 inches

Diameter = 4.4 inches

Radius = 2.2 inches

Lateral surface area:

πr√h² + r²

3.14 × 2.2 √(12)² + (2.2)²

3.14 × 2.2 √144 + 4.84

3.14 × 2.2 √148.84

3.14 × 2.2(12.2)

3.14 × 26.84

84.27

84.27 square inch is the lateral surface area of cone.

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If the inflation has been 2.7%, how much more do you have to pay this year foran item that cost $11.50 last year?

Answers

Given data:

The cost of the item is $11.50.

The inflation percentage is 2.7%.

Increase in the price is,

[tex]\begin{gathered} =11.50\times(\frac{2.7}{100}_{}) \\ =11.50\times0.027 \\ =0.3105 \end{gathered}[/tex]

Total amount to be paid last year,

[tex]\begin{gathered} =11.50+0.3105 \\ =11.8105 \end{gathered}[/tex]

Therefore you will have to pay $ 0.3105 more.

Find the perimeter of the rectangle. Write your answer in scientific notation.Area = 5.612 times 10^14 cm squared9.2 times 10^7cm is one side of the perimeter

Answers

Answer: Perimeter = 1.962 x 10^8 cm

Explanation:

The first step is to calculate the width of the rectangle. Recall,

Area = length x width

width = Area /length

From the information given,

Area = 5.612 times 10^14 cm squared

Length = 9.2 times 10^7cm

Thus,

width = 5.612 times 10^14 /9.2 times 10^7

width = 6.1 x 10^6

The formula for calculating the perimeter is

Perimeter = 2(length + width)

Thus,

Perimeter = 2(9.2 x 10^7 + 6.1 x 10^6)

Perimeter = 1.962 x 10^8 cm

Write a equation that passes through the points (2,5) (-3,5)

Answers

Line equation: y = 5

Slope: 0

Intercept: 5

Formule:

. Equation : y = mx + b

. Slope: m = () / ()

Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this section to solve the following exercise.A shirt and a tie together cost $68. The shirt costs $30 more than the tie. What is the cost of the shirt (in dollars).

Answers

Let x and y be the cost of a shirt and a tie, respectively; therefore, the two equations are

[tex]\begin{gathered} x+y=68 \\ \text{and} \\ x=30+y \end{gathered}[/tex]

We have two variables and two equations; we need to solve the system of equations to find the values of x and y.

Solve using the substitution method.

Use the second equation into the first equation, as shown below

[tex]\begin{gathered} x=30+y \\ \Rightarrow(30+y)+y=68 \\ \Rightarrow30+2y=68 \\ \Rightarrow2y=68-30=38 \\ \Rightarrow y=\frac{38}{2} \\ \Rightarrow y=19 \end{gathered}[/tex]

Now, use this value of y in the second equation

[tex]\begin{gathered} y=19 \\ \Rightarrow x=30+y=30+19 \\ \Rightarrow x=49 \end{gathered}[/tex]

Remember that x is the cost of a shirt and y is the cost of a tie. Therefore, the answers are

Cost of a shirt: $49

Cost of a tie: $19

One can verify the answer by noticing that a shirt and a tie cost $49+$19=$68, and that a shirt costs $30+$19=$49

Which equation represents a line that passes through the two points in thetable?O A. y+3= (x+3)OB. y-3-(x-3)O G. y+3=(x+3)C.OD.y-3-(x-3)X36y35

Answers

The first step is to choose one option and rewrite it in the explicit form

I will choose the second option:

[tex]y-3=\frac{2}{3}(x-3)[/tex][tex]y=\frac{2}{3}(x-3)+3[/tex][tex]y=\frac{2}{3}x-2+3[/tex][tex]y=\frac{2}{3}x+1[/tex]

Now replace the x points in the equation to verify if it satisfies their respective value in y

For x=3

[tex]y=\frac{2}{3}(3)+1=\frac{6}{3}+1=2+1=3[/tex]

For x=3 satisfy y=3

Now x=6

[tex]y=\frac{2}{3}(6)+1=\frac{12}{3}+1=4+1=5[/tex]

For x=6 satisfy y=5

So the answer is b.

given the tableau, circle the pivot and explain how you found it

Answers

The equations are

[tex]2x_1+3x_2+6x_3+S_2=22[/tex][tex]3x_1+5x_2+3x_3+S_1=20_{}[/tex][tex]-3x_2-1x_3+S_1+Z\text{ = 24}[/tex]

The smallest negative number is the pivot column

so the smallest negative number is -3 and hence the pivot column is

3

5

-3

The row pivot hence = 5

so pivot will be (x= -3 and S = 5)

writing equations in slope-intercept form common core algebra 1question 1

Answers

The equation of the line in the slope-intercept form is y = mx + b, where "m" is the slope and "b" is the y-intercept.

"b" is the point (0, yi).

"m" can be found using 2 points P₁ (x₁, y₁) and P₂ (x₂, y₂), according to the formula below:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

So, to solve this question, follow the steps below.

(a) First graph

Step 01: Find the y-intercept and another point in the graph.

To find the points in the graph, choose a x-value and find its corresponding y-value.

Choosing x = 0, y = 2.

P₁ = (0, 2).

Choosing x = -3, y = -2.

P₂ = (-3, -2).

Step 02:

2. The area of the arena is 2160 in.2 a) Will the arena fit on the rug? Show your work and explain your answer below. b) If the length of the arena is 60 inches, what is the width? c) If the arena fits, and is placed exactly in the middle of the rug, how much standing room on the rug could a drive have? Use your measurements from above to help you. ? 3. If 15 robots can fit on the arena floor at one time, how much space does each robot take up?

Answers

Answers:

2a. The arena will fit on the rug

b. Width = 36 in

c. Standing room: 4 in

3. 144 in²

Explanation:

2. Part a.

First, we need to convert the measures of the rug to inches, so taking into account that 1 ft = 12 in, we get

Length = 6 ft x 12 in/ 1ft = 72 in

Width = 4 ft x 12 in/ 1 ft = 48 in

Then, the area of the rug will be

Area = Length x Width

Area = 72 in x 48 in

Area = 3456 in²

Therefore, the area of the arena, which is 2160 in² is lower than the area of the rug. It means that the area will fit on the rug.

Part b.

The area of the arena is equal to

Area = Length x Width

To find the width of the area, we need to solve the equation for the width, so

Width = Area/Length

So, replacing Area = 2160 in² and Length = 60 in, we get

Width = 2160 in² / 60 in

Width = 36 in

Therefore, the width of the area is 36 in.

Part c.

The measures that we get from parts a and b can be represented as

Therefore, the missing length can be calculated as:

(48 in - 36 in)/2 = 12 in/ 2 = 6 in

Therefore, a drive will have 6 in of standing room.

3.

Finally, to know how much space each robot take up, we need to divide the area of the arena by 15, so

2160 in²/ 15 = 144 in²

Therefore, each robot take 144 in²

Rosa receives money from her relatives every year on her birthday. Last year, she received a total of $350. This year, she received $441. What is the percent of increase in Rosa’s annual birthday money?

Answers

Answer:

26%

Step-by-step explanation:

use a online percentage calculator

find the coordinates of point P that lies on the line segment MQ, M(-9,-5) , Q(3,5), and partitions the segment at a ratio of 2 to 5

Answers

[tex]\begin{gathered} Th\text{e point P are,} \\ \lbrack-9+\frac{2}{7}(3+9),-5+\frac{2}{7}(5+5)\rbrack \\ \lbrack-9+\frac{24}{7},-5+\frac{20}{7}\rbrack \\ \lbrack-\frac{39}{7},-\frac{15}{7}\rbrack \end{gathered}[/tex]

Which statement describes how the reasonable domain
compares to the mathematical domain?

Answers

A statement which best describes how the reasonable domain compares to the mathematical domain is that: C. the mathematical domain includes all real numbers, while the reasonable domain includes only real numbers greater than 2.

What is a domain?

In Mathematics, a domain can be defined as the set of all real numbers for which a particular function is defined. This ultimately implies that, a domain is the set of all possible input numerical values or numbers to a function and the domain of any graph comprises all the input numerical values or numbers which are primarily shown on the x-axis.

Next, we would evaluate the function which represents the perimeter of this rectangle by substituting the value of 2 as follows:

f(w) = 6w – 8

f(2) = 6(2) – 8

f(2) = 12 – 8

f(2) = 4.

For the length of this rectangle, we have:

Length = 2w - 4

Length = 2(2) - 4

Length = 4 - 4

Length = 0

Therefore, the width of this rectangle must be real numbers that are greater than 2.

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Complete Question:

A rectangle has a length that is equal to 4 less than twice the width. The function for the perimeter depending on the width can be expressed with the function f(w) = 6w – 8, where w is the width of the rectangle in centimeters.

Which statement describes how the reasonable domain compares to the mathematical domain?

Both the mathematical and reasonable domains include only positive real numbers.

Both the mathematical and reasonable domains include only positive whole numbers.

The mathematical domain includes all real numbers, while the reasonable domain includes only real numbers greater than 2.

The mathematical domain includes all real numbers, while the reasonable domain includes only whole numbers greater than 2.

Use the functions f(x) = 8x + 11 and g(x) = 4x² + 7x - 2 to evaluate the following:a. f(8) =b. f(-8)=c. g(6) =d. g(-7)=e. g(a) =

Answers

Given:

f(x) = 8x + 11

g(x) = 4x² + 7x - 2

We are asked to evaluate using the following:

(a) f(8)

f(8) = 8(8) + 11

f(8) = 64 + 11

f(8) = 75

(b) f(-8)

f(-8) = 8(-8) + 11

f(-8) = -64 + 11

f(-8) = -53

(c) g(6)

g(6) = 4(6)² + 7(6) - 2

g(6) = 4(36) + 42 - 2

g(6) = 144 + 42 - 2

g(6) = 184

(d) g(-7)

g(-7) = 4(-7)² + 7(-7) - 2

g(-7) = 4(49) - 49 - 2

g(-7) = 196 - 49 - 2

g(-7) = 145

(e) g(a)

g(a) = 4(a)² + 7(a) - 2

g(a) = 4a² + 7a - 2

write the following comparison as a ratio reduced to lowest terms. 21 quarters to 13 dollars

Answers

In order to calculate the ratio of these values, let's divide them, using the fraction form:

[tex]\text{ratio}=\frac{21}{13}[/tex]

Since the numbers 21 and 13 don't have any common factor, the fraction is already in the lowest terms.

So the ratio is 21:13

Write an expression for the sequence of operations described below.1)) multiply 7 by 8, then divide f by the resultDo not simplify any part of the expression.Submit

Answers

We need to write an expression for the operations:

[tex]\begin{gathered} \text{ multiply 7 by 8} \\ \\ \text{dived f by the result} \end{gathered}[/tex]

The first operation (multiplication) can be represented as:

[tex]7\cdot8[/tex]

The second operation (the division of f by the previous result) can be represented as:

[tex]f\div(7\cdot8)[/tex]

Notice that we need the parenthesis to indicate that the product is the first operation to be done.

Answer:

[tex]f\div(7\cdot8)[/tex]

What is the equation of the line that passes through the point (8,-6) and has a
slope of o?

Answers

A slope of 0 means the line is horizontal and every point on the line has the same value of y
The equation is y = -6

Sofia ordered sushi for a company meeting. They change plans and increase how many people
will be at the meeting, so they need at least 100 pieces of sushi in total.
Sofia had already ordered and paid for 24 pieces of sushi, so she needs to order additional sushi.
The sushi comes in rolls, and each roll contains 12 pieces and costs $8.
Let R represent the number of additional rolls that Sofia orders.
1) Which inequality describes this scenario?
Choose 1 answer:
B
12 + 24R ≤ 100
12+24R 100
24+12R 100
24+12R 100

Answers

Answer:

24 + 12R ≥ 100

Step-by-step explanation:

List the conditions as per question:

Number of pieces of sushi ordered = 24,Number of pieces required in total at least 100,Number of rolls to be ordered = R,Each roll contains = 12 pieces.

Inequality to represent the total number of pieces of sushi is:

24 pieces and R rolls of 12 pieces to get at least 100 pieces, or 24 + 12R ≥ 100

Graph the inequality on a number line

Answers

Here you go!
Hope this helps :)

The shorter leg of a right triangle is 9cm shorter than the longer leg. The hypotenuse is 9cm longer than the longer leg. Find the side lengths of the triangle.Length of the shorter leg: _ cmLength of the longer leg:__ cmLength of hypotenuse __ cm

Answers

Explanation:

let the longer leg = x

The shorter leg = 9cm shorter than the longer leg

The shorter leg = x - 9

hypotenuse = 9cm longer than the longer leg

hypotenuse = x + 9

Using pythagoras theorem:

hypotenuse² = shorter leg² + longer leg²

(x + 9)² = x² + (x - 9)²

Expanding:

x² + 9x + 9x + 81 = x² + x ² - 9x -9x + 81

x² + 18x + 81 = 2x² -18x + 81

collect like terms:

18x + 18x + 81 - 81 = 2x² - x²

36x + 0 = x²

x² - 36x = 0

x(x - 36) = 0

x = 0 or (x - 36) = 0

x = 0 or x = 36

if x = 0

shorter side = x - 9 = 0 - 9 = -9

Since the length cannot be negative, x = 36

The longer leg = x = 36 cm

The shorter leg = x - 9 = 36 - 9

The shorter leg = 27cm

The hypotenuse = x + 9 = 36 + 9

The hypotenuse = 45 cm

I solved the attached equation as 7000 but it seems to ask for a “solution set” did I answer properly?

Answers

[tex]\begin{gathered} 0.12y+0.04(y+8000)=1440 \\ 0.12y+0.04y+320=1440 \\ 0.16y=1440-320 \\ 0.16y=1120 \\ y=\frac{1120}{0.16} \\ y=7000 \end{gathered}[/tex]

The solution set does have only one element: {7000}

Write 0.000000000054 in scientific notation

Answers

Answer:

5.4 × 10^-11

Step-by-step explanation:

8% of the students at Jemerson Middle School are absent because of illness. If there are 150 students in the school, how many are absent? 12015128

Answers

12 students

Explanation

when you have 8% , it means 8 of every 100 students are absent

find the decimal form

[tex]8\text{ \% = }\frac{8}{100}=0.08[/tex]

then, to find the 8% of any number, just multiply the number by 0.08

Step 1

If there are 150 students in the school, how many are absent?

[tex]\begin{gathered} \text{absent}=\text{total}\cdot0.08 \\ \text{absent}=150\cdot0.08 \\ \text{absent}=12 \end{gathered}[/tex]

so, 12 students are absent

write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the equation(-3, -5); y = -5x+2

Answers

The equation is y = -5x-20.

GIven:

The equation is, y = -5x + 2.

A point on the line is (-3, 5).

The objective is to write an equation that passes throught the point and parallel to the given equation.

For parallel lines the product of slope values will be equal.

From the given equation, consider the slope of the equation as, m1 = -5.

Then, the slope of the parallel line will also be, m2 = -5.

Then, the equation of parallel line can be written as,

[tex]\begin{gathered} y=m_2x+b \\ y=-5x+b \end{gathered}[/tex]

Here b represents the y intercept of the parellel line.

To find the value of b, substitute the given points in the above equation.

[tex]\begin{gathered} -5=-5(-3)+b \\ -5=15+b \\ b=-5-15 \\ b=-20 \end{gathered}[/tex]

Now, substitute the value of b in the equation of parellel line.

[tex]y=-5x-20[/tex]

Hence, the equation of parellel line is y = -5x-20.

I'm graphing and I need to find out how mutch it costs for 4.5 inches of the construction. and the construction is $25.50 per inch

Answers

You have to determine the cost for 4.5 inches of the construction using the graph.

The height is on the y-axis, and the cost is on the x-axis.

First, locate 4.5 in the y-axis, which is the value in the midpoint between 4 and 5.

Draw a horizontal line until you intersect with the line, then draw a vertical line from the function until the x-axis:

The line crosses the x-axis at the midpoint between values 102 and 127.5 to determine the value at this point you have to average both costs:

[tex]\frac{127.5+102}{2}=\frac{229.5}{2}=114.75[/tex]

The cost of 4.5 inches of construction is $114.5

Can u please help me solve ? I'm reviewing for a final, ty

Answers

Part A

we have that

Both students verify the identity properly

student A ----> expand the left side of the identity

student B ----> expand the right side of the identity

but the result is the same

both students proved that the given equation is an identity

Part B

Identities

[tex]\begin{gathered} sin^2x+cos^2x=1\text{ ----> identity N 1 in step 3} \\ cos^2x=1-sin^2x \end{gathered}[/tex]

and

[tex]cscx=\frac{1}{sinx}\text{ -----> identity N 2 step 5}[/tex]

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