If a car is at rest, which of the following is correct?
A.not enough information

B.more than 3 forces are acting on the car

C.no force acts on the car

D.The net force on the car is zero​

Answers

Answer 1

Answer:

D

Unbalanced or net forces acting on the car will cause it to move

Answer 2

The correct answer is option D. The net force on the car is zero​.

What forces act on a car at rest?

Since the car is not accelerating, the force of air resistance and the friction force must add to give the exact opposite of the applied force. The net force here would be zero, as well.

When an object is at rest no gravitational force is acting on it?

Newton's First Law is the law of inertia. An object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity.

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Related Questions

Suppose measure the mass of an orange. Then you peel the orange and separate out the slices. If you measure the orange peel and all the slices, will that mass equal the mass of the whole orange?

Answers

Answer:

Yes

Explanation:

It's still the same orange with the same amount of stuff.

what is the chemical and physical changes if making a starchs

Answers

Answer:

Chemical modification of starch is based on the chemical reactivity of the constituent glucose monomers which are polyhydroxyl and can undergo several reactions. Starch can undergo reactions such as hydrolysis, esterification, etherification and oxidation.

Explanation:

Hope this helps!

1 point
A roller coaster is 20 m high and traveling 11 m/s. If the roller coaster has a
mass of 150 kg, what is its total energy? (only put the number, no units or
commas)

Answers

Answer:

ETotal=38505J

Explanation:

Known values:

m=150kg

h=20m

v=11m/s

KE=mv^2/2

PE=mgh

ETotal=PE+KE

KE=(150(11^2))/2

KE=9075

PE=150(9.81)(20)

PE=29430

ETotal=9075+29430

ETotal=38505J

A wrecking ball has a mass of 650 kg. It swings from a cable that is 21 m long. The centripetal force on the ball is 56 N. What is the tangential speed of the wrecking ball? 1. 3 m/s 1. 8 m/s 46 m/s 870 m/s.

Answers

Hi there!

For an object moving in a circle:

Centripetal force = ∑F = mv²/r

Thus:

56 = mv²/r

Rearrange to solve for velocity:

√(56r/m) = v

√(56 × 21)/650 = 1.345 m/s

Answer:

A

Explanation:

have a good day

solve for the BMI weight 58kg Height 1.61​

Answers

Answer:

Explanation:

BMI= weight/(height × height)          ; weight in kilogram and height in metter

     = 58kg / (1.61m  × 1.61m )

     = (58/ 2.5921) kg/[tex]m^{2}[/tex]

     = 22.375  kg/[tex]m^{2}[/tex]

     ≈ 22.4 kg/[tex]m^{2}[/tex]

A 3.00 kg toy falls from a height of 10.0 m. Just before hitting the ground, what will its kinetic energy be? (Disregard air resistance; g = 9.81 m/s2.)

Answers

The kinetic energy of the toy before hitting the ground is 294.3 J

From the question given above, the following data were obtained:

Mass (m) = 3 Kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.81 m/s²

Kinetic energy (KE) =?

Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.

KE = PE = mgh

KE = 3 × 9.81 × 10

KE = 294.3 J

Therefore, the kinetic energy of the toy is 294.3 J

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Anna used a rock to drive a peg into the ground to put up her tent. If the rock applied a 9. 5 N force in 0. 50 s, what is the impulse on the peg? 4. 8 N • s 9. 5 N • s 10 N • s 19 N • s.

Answers

Answer:

4.8 N*s

Explanation:

P = F*t

P = Impulse/ momentum

F = force (Newtons)

t = time (seconds)

P = 9.5N*0.5s

P = 4.75 N*s

Hi there!

[tex]\large\boxed{I = 4.8 N}[/tex]

Impulse = Force (N) × Time (s)

We can also express this as:

I = Δp = Ft

Plug in the given values:

I = 9.5(.50) = 4.75 ≈ 4.8 Ns

1. A rocket is launched from a 300 cm rail. The upper Launch Lug is placed 1 point 150 cm from the bottom of the rocket. What is the effective distance of the Launch Rail? 300 cm 150 cm 3 m 300 m O 1m O 1.5 m​

Answers

Answer:

i think its going to be 150 because its half of 300

Explanation:

Part B
Based on the information in the article, how could plants be used in the future to help counteract some human
emissions?

Answers

Answer:

Having more plants performing photosynthesis could help reduce the amount of carbon dioxide in the atmosphere.

Explanation:

sample answer

The plants can be used in the future to help counteract some human

emissions they absorb carbon dioxide from the air and release oxygen.

What is photosynthesis?

It is a process carried out by photosynthetic autotrophic organisms, such as plants, algae and some prokaryotes. These organisms capture sunlight, convert it into chemical energy, which will be used to produce organic compounds, based on water and carbon dioxide.

Trees, like other plants, in the process called photosynthesis, absorb carbon dioxide from the air and release oxygen. They also make the air wetter and cooler. In this way, plants contribute to the good quality of the air we breathe.

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How is "speed" defined in terms of physics?

Answers

Explanation:

In everyday use and in kinematics, the speed of an object is the magnitude of the rate of change of its position with time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

A long-distance runner runs at a constant speed of 4.8 m/s. How long does it take them to run 1.5 km?

Answers

Convert km to meters:

1km = 1000 m

1.5 km x 1000 = 1500 m

1500m / 4.8 m/s = 312.5 seconds

312.5 seconds / 60 seconds per minute =5.2 minutes = 5 minutes 12.5 seconds

We are able to walk toward because…

a) we push on the air
b) we push on the ground
c) the air pushes on us
d) the ground pushes on us

Answers

The answer is C because of gravity

We are able to walk toward because b) we push on the ground.

_

_

_

[tex] 😘 \: 😉 \: 😈 \; 😫 \: 😤 \: 😡 \: 😘[/tex]

What is the only force that can overcome the repulsion between two positively charged nuclei to bind them into an atomic nucleus

Answers

Answer:

Nuclear Fusion

Explanation:

At large distances, two nuclei repel one another because of the repulsive electrostatic force between their positively charged protons. If two nuclei can be brought close enough together, however, the electrostatic repulsion can be overcome by the attractive nuclear force, which is stronger at close distances.

60W light bulb is left on for 5mins. How much energy does it use in KWH

Answers

Answer:

Energy = Power × Time

time must be hoursPower must be in kilowatts

[tex]{ \tt{E = ( \frac{60}{1000} ) \times ( \frac{5}{60}) }} \\ \\ { \tt{E = 0.005 \: kwh {}^{ } }}[/tex]

What is the correct definition of rarefaction

Answers

Answer:

Explanation:

A decrease in the density of something is rarefaction. ... Most of the time, rarefaction refers to air or other gases becoming less dense. When rarefaction occurs, the particles in a gas become more spread out. You may come across this word in the context of sound waves.

5. SEP Construct Explanations If the line on
a distance-versus-time graph and the line on
a speed-versus-time graph are both straight
lines going through the origin, can the two
graphs be displaying the motion of the same
object? Explain.

Answers

Answer:

If and only if the object has 0 speed. Any other case is a no.

Explanation:

In increasing math complexity:

If the graph of a distance/time is a straight line with a non-zero slope it means that the velocity-time graph is an horizontal line where every point has the same second coordinate, equal to the value of the slope of the first line (ie, if the first line has equation [tex]y=2t[/tex] the second line will have equation [tex]y=2[/tex] - I'm using y to denote either the distance or the speed, read it as "the non-time variable")

If the graph of a speed/time is a straight line, the graph of the distance/time is the area of the region of space beneath the straight line in the first graph, ie a triangle. And as you increase the sides of that triangle keeping the angles fixed, you get a parabolic curve.

Bonus case: if [tex]v(t)= 0; d(t) = 0[/tex], they are both straight lines, they both pass through the origin, and they are the exact same line.

With calculus (or: math becomes fun after you add the alphabet to it)

You are asking if the answer of the IVP

[tex]\left \{ {{x'=x} \atop {x(0)=0}} \right.[/tex]

is a linear function. The answer is: besides the obvious [tex]x(t)'=x(t)=0 \ \forall t[/tex] there are no other solutions, linear or otherwise.

A teacher has two radioactive sources, A and B.
Source A has a longer half-life than source B.
What can be deduced about the nuclei in source A compared with the nuclei
in source B?
Do not refer to isotopes in your answer.

Answers

Answer:

The nuclei of source have greater stability than those of source B.

How much force is needed to accelerate a 70 kg rider and the 200kg motorcycle the
rider is on at 4m/s?

Answers

Answer:   F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N

Answer:

F = 1080 N

Explanation:

A balloon with a volume of 2. 0 L at 25°C is placed in a hot room at 35°C. The pressure on the balloon is constant at 1. 0 atm. How does the volume of the balloon change after moving it to the hot room?.

Answers

Answer:

25A°C=2L

35A°C=? More

=35/25×2L

=7/5×2L

=14L/5

=2.8L

Balanced forces are forces that have equal amount of ________. (word choices: force, repel, attract, motion)

Answers

Answer:

a

Explanation:

if forces on an object are balanced a moving object continues to move at the same speed and in the same direction

Calculate the force applied if 100 N/m² pressure is exerted over the area of 0.2m²​

Answers

Answer: 100 pascals times 0.2 m^2= 20 N force is applied.

Explanation:

The ______________ is all the surroundings of a living organism.

genetics
environment
temperature
heredity

Answers

The environment is all the surroundings of a living organism

Consider the schematic of the molecule shown, with two hydrogen atoms, H, bonded to an oxygen atom, O. The angle between the two bonds is 106°. If the bond length r = 0.103 nm long, locate the center of mass of the molecule. The mass mH of the hydrogen atom is 1.008 u, and the mass mO of the oxygen atom is 15.9999 u. (Use a coordinate system centered in the oxygen atom, with the x-axis to the right and the y-axis upward. Give the coordinates of the center of mass in nm.)

Answers

The definition of the center of mass allows to find the result for the position of the mass center of more than the H₂O molecule is;

         [tex]x_{cm} = 0 \ and \ y_{cm} = 6.9 10^{-3 } nm[/tex]  

the concept of center of mass of a system is the point where external forces are applied, it is given by the expression

             [tex]\frac{x}{y} =\frac{1}{M_{total}} \sum m_i r_i[/tex]  

Where M is the total mass of the systemr_i and m_i sums the position and masses of the element i of the system

In the attachment we have a diagram of the system where the axis and coordinates of the molecules are shown, in this case it is indicated that the origin is in the oxygen atom, so its distance is zero.

           [tex]r_{cm} = \frac{1}{2 m + M} \ (2 m r )[/tex] )

They indicate the mass of the hydrogen atom m = 1.008 amu, the bond length r = 0.103 nm and there is an angle 106º between the two hydrogens, therefore the angle from the vertical is:

           θ = 106/2 = 53º

Let's find the position of the center of mass for each axis.

x-axis

           [tex]x_{cm} = \frac{1}{2m+ M} \ ( m x_1 - m x_2)[/tex]  

y-axis

          [tex]y_{cm} = \frac{1}{2m + M} \ ( m y_1 + m_2)[/tex]

Let's use trigonometry to find the components of the bond length.

         cos θ = [tex]\frac{y}{L}[/tex]  

         sin θ = [tex]\frac{x}{L}[/tex]  

         y = L cos θ

         x = L sin θ  

We substitute.

          [tex]x_{cm} = \frac{1}{2m+M} \ (mL (sin 53 + sin (-53)) \\y_{cm} = \frac{1}{2m + M} \ ( mL cos 53 + mL sin 53)[/tex]

we use.  

          sin θ = - sin -θ

          cos θ = cos -θ

Let's calculate.

        [tex]x_{cm} = 0 \\y_{cm} = \frac{1}{2 \ 1.008 + 15.9999} \ ( 2 \ 1.008 \ 0.103 cos 53)[/tex]

       

We see that the center of mass is on the x axis and at a distance from the y-axis of 6.9 10-3 nm

In conclusion using the definition of the center of mass we can find the result for the position of the center of mass of the H₂O molecule is;

          [tex]x_{cm}=0[/tex]  and [tex]y_{cm}[/tex]cm = 6.9 10⁻³ nm

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3. If John leaves his house to walk his dog and he walks around the block, what is
his distance?
180 Meters
180 Meters
180 Meters
180 Meters

Answers

Answer:

180 meters

Explanation:

Find the velocity of a body of mass 100 g having kinetic energy of 20 J.​

Answers

Answer:

Explanation:

Let v be the velocity of object ,

Given that mass of object , m=100 g=  

1000

100

kg=0.1 kg

& kinetic energy of object =20 J

K.E  =  

2

1

 mv  

2

 

20=  

2

1

×0.1v  

2

 

⟹v  

2

=400

⟹v=20 m/s

I need help making a chart (preferably a line graph) with this data. I'm not sure how to show that it will be a linear line in a graph. If you don't have excel can you explain to me how to do it.


note: these datasets are separate and arent related

Spring Constant (N/m) Displacement (m)
100 0.5m
300 0.167m
500 0.1m
700 0.071m

Applied force (N) Displacement (m)
20 0.2m
30 0.3m
50 0.5m
70 0.7m

Answers

Answer:

the graph plotted based on your data, you did not mention what are the variables on the x-axis and y- axis . and the graphs can be three small graphs of different material of one quality i.e. thickness or length

hope it helps

Explanation:

If a train travels 25 miles in 2 hours 15 minutes, what is its average speed in miles per hour? 11. 1 mph 12. 5 mph 10 mph 9. 1 mph.

Answers

Answer:

11.1

Explanation:

2 hours 15 mins = 2 1/4 hours

2 1/4 hours = 25 miles

1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles

If a 5.00 kg box slides down a ramp inclined at 60.0° above the horizontal, what is the

acceleration of the box

Answers

Answer:

A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding

a force that is at rest or moves in at a constant speed and in a constant direction is called a what force

Answers

The question is fishing for "balanced force".

But the description in the question is terrible.

Part IV Objects on an incline w/ Tension + Friction
1. A small 63 kg sleigh is pulled by a rein attached to horse up a 15'angle hill to the
horizontal. The tension of the rein is 510 N. The coefficient of kinetic friction is
0.25
a. What is the normal force that the sleigh exerts on the hill?
b. What are the magnitude and direction of the sleigh's acceleration?

Answers

(a) The normal force on the sleigh is 596.36 N.

(b) The magnitude and direction of acceleration of the sleigh is 3.2 m/s² upwards.

The given parameters;

mass of the sleigh, m = 63 kginclination of the hill, θ = 15⁰tension on the rein, F = 510 Ncoefficient of friction, μ = 0.25

The normal force on the sleigh is calculated as follows;

[tex]F_n = mg \times cos(\theta)\\\\F_n = 63 \times 9.8 \times cos(15)\\\\F_n = 596.36 \ N[/tex]

The magnitude and direction of acceleration of the sleigh is calculated as follows;

[tex]\Sigma F= ma\\\\F - mgsin(\theta) - F_f = ma\\\\F - mgsin(\theta) - \mu F_n = ma\\\\510\ - \ 63 \times 9.8 \times sin15 \ -\ 0.25\times 596.36 = 63a\\\\201 .11 = 63a\\\\a = \frac{201.11}{63} \\\\a = 3.2 \ m/s^2 \ upwards[/tex]

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