if 1/3 of a gallon of paint covers 1/8 of a wall, how much paint is needed to cover the entire wall?

The equation of a circle in the xy-plane is found as (x + 2)² + (y - 1)² = 5.

A circle is a two-dimensional closed figure in which the set of all points with in plane is equidistant from the a given point known as the "centre."

Circle Formula: (x - h)² + (y - k)² = r² ;

Where, (h, k) is the centre & r is the radius of the circle.

Use the distance formula for(-2, 1) and (0,2)

[tex]\begin{aligned}&r=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2} \\&r=\sqrt{(0+2)^2+\left(2-1\right)^2} \\&r=\sqrt{(2)^2+\left(1\right)^2}\end{aligned}[/tex]

Further simplifying;

r = √(4 + 1)

r = √5

Centre (h, k) = (-2, 1)   Radius (r) = √5.

(x - h)² + (y - k)² = r²

(x + 2)² + (y - 1)² = √5²

(x + 2)² + (y - 1)² = 5 is the equation of the circle.

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Answer:

hold up

Step-by-step explanation:

عد اس مراس whats this mean??

Answer:

x = 4

Step-by-step explanation:

m = (y2-y1)/(x2-x1)

m = (10 - -2)/(4 - 4) = 12/0

so slope is undefined

therefore the line is a vertical line, which is x = 4

The results of the computation using the laws of exponents are 2^12 and 2401/256

When we have two numbers, one serving as the base and the other being the index, we could be able apply the laws of indices when we are solving the problem. There are several laws of indices such as; multiplying, dividing, power of 0, brackets, negative and fractional powers.

In order to solve these problems, we need to apply the statements of the laws of indices.

In the first case we have;

2^16 ÷ 2^4

2^16/2^4

Using the subtraction law;

2^16 - 4 = 2^12

Again;

(7/4)^4

By the power law

7^4/4^4 = 2401/256

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When each box cost $3.59, the cost per ounce will be $0.23 ounce.

In the box of Toasted O’s cereal, there are 15.4 ounces of cereal and each box cost $3.59.

Therefore, the cost per ounce will be:

= Total amount / Number of ounce

= $3.59 / 15.4

= $0.23 per ounces

Therefore, when each box cost $3.59, the cost per ounce will be $0.23 ounce.

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The statement "twice a number y increased by seven " can be expressed by the algebraic expression is 2y+7.

A mathematical construct called an algebraic expression is made up of integer constants, variables, and algebraic operations (addition, subtraction, multiplication, division, and exponentiation by a rational exponent).

Let us take an expression 5a²+2c+7 is an algebraic expression. Where

a,c are variables 5 and 2 are coefficients and 7 is the constant.

The given statement is "Twice a number y increased by seven". let us break it into smaller parts:

Twice a number y is represented by 2y , then it is increased by 7 . So the required expression comes out as 2y+7.

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The necessary expression for calculating the average rate of change inside the given function f(x) is given using :

f'(x) = (f(9) - f(2))/7

It quantifies how significantly the function changed per unit on average over that time interval. The slope of the single direction connecting every interval's ends on the function's graph is used to calculate it.

As we can see, slope is another way of calculating the average change rate. The average rate of change is calculated by dividing the difference in the dependent  (y-term) by the difference inside the independent variable (x-term). The slope, as well as average rate of change are the same thing.

The function is given to f(x)

The interval is given to be [2,9]

Let a = 2 and b = 9

The expression which is used to determine the average rate of change in f(x) is given by

f'(x) = (f(b) - f(a))/b - a

f'(x) = (f(9) - f(2))/7

The necessary expression for calculating the average rate of change inside the given function f(x) is given using :

f'(x) = (f(9) - f(2))/7

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Answer:

Step-by-step explanation:  Use Pythagorean Theorem

                              [tex]a^2 + b^2 = c^2\\[/tex]

                            [tex]15^2 + b^2 = 9^2\\[/tex]

                          [tex]225 + b^2 = 81[/tex]

                            [tex]- 255[/tex]        [tex]-255[/tex]

                             -------------------

                              [tex]b^2 = 174\\[/tex]

                             [tex]b^2 = \sqrt{-174}[/tex]    

When, the coordinate a and b are colinear, and b lies between a and c, if ac=36, ab= 2x+4 and bc=4x+2, then the value of x is 5

Given,

The coordinates a and b are colinear.

The point b lies between a and c

Therefore,

ac = ab + bc

ac= 36

ab= 2x+4

bc= 4x+2

Substitute the values

36= 2x+4 + 4x+2

36= 6x+6

6x= 36-6

6x=30

x=5

Hence, when the coordinate a and b are co-linear, and b lies between a and c, if ac=36, ab= 2x+4 and bc=4x+2, then the value of x is 5

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(-1, 2))

You just to make use of the Midpoint Formula to solve for the missing coordinate

Midpoint Formula

((x1 + x2)/2, (y1 + y2)/2)

Midpoint (0,-1) end point (1,-4)

Let x1 = 1, the x coordinate of the endpoint

Let x2 = the x coordinate of the unknown endpoint

Let y1 = -4, the y coordinated of the endpoint

Let y2 = the y coordinated of the unknown endpoint

Just plug in the values and do the calculations

For the x coordinate of the unknown endpoint

(x1 + x2)/2

(1 + x2)/2 = 0

1 + x2 = 0

x2 = -1

For the y coordinate of the unknown endpoint

(y1 + y2)/2

(-4 + y2)/2 = -1

-4 + y2 = -2

y2 = -2 + 4

y2 = 2

So the coordinates of the other endpoint are (-1,

The quotient of the quantity (30 × 10⁻²⁴)/(5 × 10⁻²⁴)  is found out to be 6 × 10⁰.

For writing exceptionally large or extremely small numbers, scientific notation is comparable to shorthand. A process is limited to a number multiplied by ten rather than written in decimal form.

Now, as per the expressed equitation;

= (30 × 10⁻²⁴)/(5 × 10⁻²⁴)

Divide the numerator (30 × 10⁻²⁴) by denominator (5 × 10⁻²⁴) by the quotient.

= 6 × 10⁰

Therefore, the quotient of the quantity (30 × 10⁻²⁴)/(5 × 10⁻²⁴)  is calculated as 6 × 10⁰.

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When out of the incoming freshman at a collage 2,268 of them are female and 58% are male then the total number of freshman is 5400

Given,

Number of females = 2268

Consider the total number students as x

Percentage of male = 58%

Then the equation will become

x-2268= x×[tex]\frac{58}{100}[/tex]

x-2268=0.58x

x-0.58x=2268

0.42x=2268

x=5400

Hence, when out of the incoming freshman at a collage 2,268 of them are female and 58% are male then the total number of freshman is 5400

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For given scenario the dependent variable would be the life of flowers.

For given question,

The variable that researchers are trying to explain or predict is called the

response variable. It is also sometimes called the dependent variable

because it depends on another variable.

The variable which is used to predict the response variable is known as the explanatory variable. It is also called as an independent variable because it does not depend on another variable.

The amount of sugar would be an independent variable and the life of flowers is a dependent variable.

Therefore, for given scenario the dependent variable would be the life of flowers.

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Answer -

[tex] \frac{61}{4} [/tex]

Step-by-step explanation:

Greetings !

Given expression( function )

[tex]h(x) = \frac{12}{2x} + 16[/tex]

Thus, plug in -8 in the variable x and solve as follows:-

[tex]h( - 8) = \frac{12}{2( - 8)} + 16[/tex]

Multiply the numbers 2.(-8) = -16

[tex] = \frac{12}{ - 16} [/tex]

Apply the fraction rule

[tex] \frac{a}{ - b} = - \frac{a}{b} [/tex]

[tex] = - \frac{12}{16} [/tex]

[tex] = - \frac{ 12}{16} + 16[/tex]

cancle

[tex] \frac{12}{16} = \frac{3}{4} [/tex]

Factor the number: 12 = 4.3

[tex] = \frac{4.3}{16} [/tex]

Factor the number 16 = 4.4

[tex] = \frac{4.3}{4.4} [/tex]

cancel the common factor =4

[tex] = \frac{3}{4} [/tex]

Thus,

[tex] = \frac{ - 3}{4} + 16[/tex]

Convert 16 to fraction :

Apply the fraction rule

[tex]a = \frac{ab}{b} [/tex]

[tex] = \frac{16.4}{4} [/tex]

Multiply the numbers 16.4=64

[tex] = \frac{64}{4} [/tex]

[tex] = - \frac{3}{4} + \frac{64}{4} [/tex]

Apply the fraction rule

[tex] \frac{a}{c} + \frac{b}{c} = \frac{a + b}{c} [/tex]

[tex] = \frac{ - 3 + 64}{4} [/tex]

Add the numbers -3+64 ==61

[tex] = \frac{61}{4} [/tex]

Hope it helps !!

Answer:

[tex]A = \frac{a+b}{2} + h[/tex]

Step-by-step explanation:

A is the area. a and b are the lengths of the two bases. h is the height of the trapezoid.

Answer:

Step-by-step explanation:

A=[tex]\frac{base1+base2}{2}height[/tex]

The value of the angle DCH is 72 degrees

The given parameters are

m = 11x+1,

DCH = 8x,

DCB = 172°.

The above means that:

11x + 1 + 8x = DCB

This gives

11x + 1 + 8x = 172

Evaluate the like terms

19x = 171

Divide both sides by 19

x = 9

Substitute x = 9 in DCH = 8x,

DCH = 8 * 9

Evaluate

DCH = 72

Hence, the value of the angle DCH is 72 degrees

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Answer: 5m

Step-by-step explanation: multiply the numbers.

Answer:

Julia would have spent 41 minutes.

Step-by-step explanation:

We know that the equation is 2m - 9, and that m is equal to 25.

So all we have to do is solve.

2m - 9

= 2(25) - 9

= 50 - 9

= 41

So Julia practiced 41 minutes that day.

Hope this helped! :D

Answer:

I believe I did it right. I solved it with distance formula.

Answer : D =

[tex] \sqrt{104} [/tex]

= 10.2

The sampling process used by the school newspaper is convenience sampling.

Convenience sampling is the most popular kind of sampling that concentrates on gathering data from individuals (the sample) who are 'convenient' for the researcher to reach. With this sample strategy, researchers can choose subjects at random who are receptive to being contacted and participating in the study rather than selecting participants at random based on any set of criteria (such as demographic variables). This implies that one can locate your sample at any time and any place, such as among individuals in a mall, on the street, at work, or in an online community.

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An advantage of a cumulative frequency polygon over a histogram or frequency polygon is that: it can directly compare two or more frequency distributions.

Now,

Hence, an advantage of a cumulative frequency polygon over a histogram or frequency polygon is that: it can directly compare two or more frequency distributions.

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Answer:

10 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (3, - 6 ) and (x₂, y₂ ) = (3, 4 )

d = [tex]\sqrt{(3-3)^2+(4-(-6))^2}[/tex]

  = [tex]\sqrt{0^2+(4+6)^2}[/tex]

  = [tex]\sqrt{0+10^2}[/tex]

  = [tex]\sqrt{0+100}[/tex]

  = [tex]\sqrt{100}[/tex]

  = 10

The lower quartile of the data is said to fall between  1.5 and 2.5 respectively in the box plot that we have here.

The lower quartile is the lower 1/4th of the data distribution. It is the 25th percentile of the distribution that we have in the question.

This point is what is marked at the starting point of the box that we have in this question.

The lower quartile is given by 2 and we can see that that it is bounded by the two numbers of 1.5 and 2.5.

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Answer:

.50 = equally likely as unlikely

1 = certain

.25 = unlikely

0 = impossible

.75 = likely

Step-by-step explanation:

Think of these as percentages, it'll help you figure out.

.50 is 50%

1 is 100%

.25 = 25%

0 is 0%

.75 = 75%

Answer: 99 x 76= 7524

Step-by-step explanation:

Answer:

7524

Step-by-step explanation:

Answer:

cluster estimation is to estimate sums when the numbers being added cluster near in value to a single number. it is 100 in this case.

estimate sum = 100x4 = 400

Step-by-step explanation:

Answer:

440

Step-by-step explanation:

Round all of the numbers, and then add them.

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It arrives 1 hour early in Kathmandu, if its average speed is increased by 5 km/h;

Average speed = 45 km/h;

Total time taken to arrive Kathmandu from Biratnagar = 10 hours

∴ Distance between Kathmandu and Biratnagar = Speed × Time

                                                                                    = 45 × 10

                                                                                    = 450 km;

If average speed is increased by 5 km/h, new average speed = 50 km/h;

New time to reach Kathmandu = Distance/ Time

                                                   = 450/50

                                                   = 9 hours;

It arrives 10 - 9 = 1 hour early in Kathmandu;

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The result of moving 9 units to the left and 3 units up is (2,11) in the 1st quadrant.

Refer to the graph given below:

Therefore, the result of moving 9 units to the left and 3 units up is (2,11) in the 1st quadrant.

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The time taken before the two automobiles meet is determined as 1.33 hours.

Apply the principle of relative velocity as shown below;

Vat + Vbt = D

(Va + Vb)t = D

where;

(20 + 25)t = 60

45t = 60

t = 60/45

t = 1.33 hours

Thus, the time taken before the two automobiles meet is determined as 1.33 hours.

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