Answer:
m = .45
p = .45w
______
.45 = 9/20
Explanation:
m is the rate of change equal to the price over the weight or p/w.
Because this relationship is proportional, each weight divided by its corresponding price must equal the same fraction because it is constant.
We can prove this by dividing each price by its weight to find this proportion.
1.35/3 = 2.7/6 = 27/60 = 9/20 = 0.45
1.71/3.8 = 171/380 = 9/20 = 0.45
2.34/5.2 = 234/520 = 117/260 = 9/20 = 0.45.
Since equal the same value, this means that 9/20 or .45 is our proportion.
in terms of p = mw
p/w = 9/20.
p = mw → p/w = m → m = p/w = .45 .
Thus, p = .45w,
so m = .45.
Which means that for every .45 or 9/20 w or weight, there is a price of $1.
What is the probability of picking a yellow marble and a blue marble of the yellow marble is replaced ?
Answer:
50%
Step-by-step explanation:
In the diagram the radius of the outer circle is 2x cm and the radius of the inner circle is 6 cm. The area of the shaded region is 160
let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
2h+y/9h^2-y^2 - 4h^2/3h+y what is the least common denominator in this expression
Answer: It is 9
Step-by-step explanation:
There are 946 milliliters in a quart. There are 2 pints in a quart.
How many milliliters are in a pint?
Answer:
473
Step-by-step explanation:
I divided 946 and 2 and got 473. I'm not 100 percent this is correct but whatever
Mr. Cohen used 25 kilograms of fertilizer on his lawn. The fertilizer contained 4 kilograms of nitrogen. What percent of the nitrogen was in the fertilizer that Mr. Cohen used?
Answer:
The answer to this question is the percentage of the nitrogen is 17%
ben made 14 field goal he made about 74% how many did he try
Please help
Part b is how much farther would she have to walk if she stopped at randis house before continuing on to the store
Answer:
10 units
Step-by-step explanation:
Distance from Sarah's house to Randi's house = 6 units.
Distance from Randi's house to store = 8 units.
By using Pythagoras theorem:
Distance from Sarah's house to store
[tex] = \sqrt{ {6}^{2} + {8}^{2} } \\ \\ = \sqrt{36 + 64} \\ \\ = \sqrt{100} \\ \\ = 10 \: units[/tex]
Is it the 1st one. I’m not to sure.
Answer:
Yes, it's the first one
Step-by-step explanation:
Since the number line is from 0 to 1 and it's divided into 6 sections, the correct answer is 1
Mr. Hunterhad 25 students in his 4th period math class. The next day, he has
only 20 students. What is the percent decrease in the number of students in
Mr. Hunter's class?
Answer:20 percent
Step-by-step explanation:correct me if I’m wrong
In 1850, there were 564 textile mills in New England states with a total of 61,893 workers. The average wmployment per textile mill was ?
Answer Choices
109
110
108
111
You have $9.30 plus 6 percent of tax what is the total costs
Answer:
$ 9.86
Step-by-step explanation:
Tax = 6% of 9.30
= 0.06 * 9.30
= $ 0.558
Total costs = 9.30 + 0.558
= 9.858
= $ 9.86
Write an equation in slope-intercept form for the line.
slope: 0.8, y-intercept: 10
Group of answer choices
y = –0.8x + 10
y = 0.8x – 10
y = 0.8x + 10
y = 5/7x + 10
Answer:
y = 0.8x – 10
This is the correct answer.
Step-by-step explanation:
It'll be a life saver if you guys can actually help me with this problem.. Please.
There are 500 cars in Frank's junkyard; 350 blue and 150 red. If Joe randomly selects 25 cars from his yard, what's the probability he'll get from 14 to 20 blue cars, inclusive? Could this be considered an almost binomial event?
A. P(x=14) + P(x=15) + P(x=16) + P(x=17) + P(x=18) + P(x=19) This is an almost binomial event.
B. binomcdf(25,.7,20) - binomcdf(25,.7,14) This is almost binomial event.
C. (25/14)(.7)^14(.3)^11 + (25/15)(.7)^15(.3)^10 + ... + (25/19) (.7)^19(.3)^6 + (25/20)(.7)^20(.3)^5 This is an almost binomial event
D. P(14 < x <20) Not an almost binomial event.
E. binompdf(25,.7,20) - binompdf(25,.7,14) Not an almost binomial event
Answer:
C. (25/14)(.7)^14(.3)^11 + (25/15)(.7)^15(.3)^10 + ... + (25/19) (.7)^19(.3)^6 + (25/20)(.7)^20(.3)^5 This is an almost binomial event
Step-by-step explanation:
I think
HELP with this problem please
Answer: 2
Step-by-step explanation:that is the one that is used the most?
what is the degree of x^6+4x-3
Answer:
1.2599
Step-by-step explanation:
Giving brainliest. 7th grade math
Evaluate 3x-(5x-1)-3(2x-10)
Answer:
-8x + 31
Step-by-step explanation:
Hope it helps, have a great day
(a) Write 1.04 x 10as an ordinary number.
(b) Write 0.06 in standard form.
4.62 x 10% tins of beans were sold last year.
These tins of beans cost a total of £300.3 million.
(c)Work out the average cost per tin of beans.
Answer: here are your answers, Add 3.45 X 1010 and 2.75 X 108. The first number is the same as 345 X 108. Note how as the decimal point moves, the exponent changes. Adding them, we get 347.75 X 108 or – less accurately – 3.48 X 1010.
Add 4.00 X 1012 and 7.55 X 1012. The answer is 11.55 X 1012 or 1.16 X 10 13.
Step-by-step explanation: here are your answers, Add 3.45 X 1010 and 2.75 X 108. The first number is the same as 345 X 108. Note how as the decimal point moves, the exponent changes. Adding them, we get 347.75 X 108 or – less accurately – 3.48 X 1010.
Add 4.00 X 1012 and 7.55 X 1012. The answer is 11.55 X 1012 or 1.16 X 10 13.
Can Someone Please Help Me!!!
If f(x) = -6x + 1, what is f(1/2x-1) equal to
By substituting [tex]x = \(\frac{1}{2}x-1\)[/tex] , the given function f(x) = -6x + 1 can be simplified to [tex]f(x) = \(f(\frac{1}{2}x-1) = -3x + 7\)[/tex].
To find [tex]\(f(\frac{1}{2}x-1)\)[/tex], substitute [tex]\(\frac{1}{2}x-1\)[/tex] into the function f(x):
[tex]\(f(\frac{1}{2}x-1) = -6(\frac{1}{2}x-1) + 1\)[/tex]
Now, simplify the expression:
[tex]\(f(\frac{1}{2}x-1) = -3x + 6 + 1\)\\\\\(f(\frac{1}{2}x-1) = -3x + 7\)[/tex]
So, [tex]\(f(\frac{1}{2}x-1) = -3x + 7\)[/tex].
To know more about function, refer here:
https://brainly.com/question/13007893
#SPJ2
Carmen deposits $4000 into an account that pays simple interest at a rate of 3% per year. How much interest will she be paid in the first 3 years?
Answer:
$360
Step-by-step explanation:
I = Prt
I = 4000 * 3 * 3%
I = 12000 * 3% (Convert 9000 and 3% into fractions.)
I =12000/1 * 3/100 (100 and 12000 have a GCF of 100)
I = 120/1 * 3/1 (Disregard the over 1 portion.)
I = 120 * 3 (Multiply 120 by 3 to get 360.)
I = $360
Graph the equation.
y =2x-2
Answer:
Okay so
y = mx + b
m is the slope
b is the y intercept
Step-by-step explanation:
Step-by-step explanation:
I hope this helps I used desmos
How far is `10\%` of a `2,000`-kilometer trip?
1-27
What is the simplified version of Square root of -27
Answer:
3√3
Step-by-step explanation:
Item 1
One February day, the low temperature in St. Paul, MN was -17°F. Over a period of three hours, the temperature rose 5 °F per hour. After three hours, what was the temperature?
°F
PLEASE HELP What is the x value. (Remember to round to the nearest tenth.)
Answer:
the answer might be 71.9
Step-by-step explanation:
add 12.8 and 5.3 =18.1 then
90-18.1=71 9
Does this graph show a function? Explain how you know.
Answer:
A
Step-by-step explanation:
It may look like it failed but it didn't. Nun of the points duplicate
f(x)= −2x^2 + 8x − 10
{Find } f(-4)
Answer:
simply you have to substitute (-4) for all the (x) terms-2x²+8x -10-2(-4)²+8×(-4)-10-2(16) - 32 -10-32 -32 - 10-74
The chair of the operations management department at Quality University wants to construct a p-chart for determining whether the four faculty teaching the basic P/OM course are in control with regard to the number of students who fail the course. Accordingly, he sampled 100 final grades from last year for each instructor, with the following results Instructor Number of Failures Prof. A 13 Prof. B 0 Prof. C 11 Prof. D 16 What are the .95 (5 percent risk of Type I error) upper and lower control limits for the p-chart
Answer:
Prof B and Prof D
Step-by-step explanation:
Step-by-step explanation:
From the question we are told that
Sample size 100
Instructor Number of Failures
Prof. A 13
Prof. B 0
Prof. C 11
Prof. D 16
Confidence level= 0.95
From Z table
Z=1.96
Generally proportion for failure is mathematically given as
[tex]Proportion\ of\ Failure\ P=\frac{Number\ of\ Failure\ N}{Sample\ size\ S}[/tex]
[tex]P=\frac{N}{S}[/tex]
For Prof A
[tex]P_A=\frac{N_A}{S}[/tex]
[tex]P_A=\frac{13}{100}[/tex]
[tex]P_A=0.13[/tex]
For Prof B
[tex]P_B=\frac{N_B}{S}[/tex]
[tex]P_B=\frac{0}{100}[/tex]
[tex]P_B=0[/tex]
For Prof C
[tex]P_C=\frac{N_C}{S}[/tex]
[tex]P_C=\frac{11}{100}[/tex]
[tex]P_C=0.11[/tex]
For Prof D
[tex]P_D=\frac{N_D}{S}[/tex]
[tex]P_D=\frac{16}{100}[/tex]
[tex]P_D=0.16[/tex]
Generally the average proportional failure is mathematically given as
[tex]P_a_v_g=\frac{0.13+0+0.11+0.16}{4}[/tex]
[tex]P_a_v_g=0.10[/tex]
Therefore having this we calculate for the control limits
Generally the upper control limit UCl is mathematically given as
Upper control limits:
[tex]UCL =P_a_v_g +Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }[/tex]
[tex]UCL =0.1 +1.96\sqrt{\frac{0.1(1-0.1) }{100}}[/tex]
[tex]UCL =0.1 +1.96*0.03[/tex]
[tex]UCL =0.1 +0.0588[/tex]
[tex]UCL =0.1588[/tex]
Generally the upper control limit UCl is mathematically given as
Lower limit control limits:
[tex]UCL =P_a_v_g _Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }[/tex]
[tex]UCL =0.1 -1.96\sqrt{\frac{0.1(1-0.1) }{100}}[/tex]
[tex]UCL =0.1 -1.96*0.03[/tex]
[tex]UCL =0.1 -0.0588[/tex]
[tex]UCL =0.0412[/tex]
Therefore the Range is 0.0412 to 0.1588
Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options
I need help asap I’m confused