# I need help with my python code, it won't work, and no matter what I try, I can't get it to run properly. Every time I try top run it, it gives me an error saying:

# syntaxError, bad input on line 43, I am not very good at programming, and I just started. I wanted to ask if you guys could help me.
# Here's my code, the purpose of it is to be a rock paper scissors game:

```
import random

def welcome_prompt():
print ("Rock paper Scissors game")
print ("Rules: Rocks beats Scissors, Scissors beats Paper, Paper beats Rock")

def get_player_move():
print ('Round ' + str(round))
print ("Please play one of the following")
move = raw_input(" 1) [R]ock, 2) [P]aper, 3) [S]cissors:")

if get_player_move == ("R"):
print ("You used Rock!")
return 1
elif get_player_move == ("P"):
print ("You used Paper!")
return 2
elif get_player_move == ("S"):
print ("You used Scissors!")
return 3
else:
print "Invalid input, please use capitalized initial (R,P,S)"
return get_player_move()

def get_computer_move():
get_computer_move = random.randint(1,3)

if get_computer_move == 1:
print ("Computer used Rock!")
return 1
elif get_computer_move == 2:
print ("Computer used Paper!")
return 2
elif get_computer_move == 3:
print ("Computer used Scissors!")
return 3

def compare_moves(get_player_move, get_computer_move):

if (get_player_move == 1 and get_computer_move == 1) or (get_player_move
== 2 and get_computer_move == 2) or (get_player_move == 3 and
get_computer_move == 3):
print ("It's a tie!")
return 0

elif (get_player_move == 1 and get_computer_move == 3) or
(get_player_move == 2 and get_computer_move == 1) or (get_player_move ==
3 and get_computer_move == 2):
print ("You win the round!")
return 1

elif (get_player_move == 1 and get_computer_move == 2) or
(get_player_move == 2 and get_computer_move == 3) or (get_player_move ==
3 and get_computer_move == 1):
print ("You lose the round!")
return -1

elif (get_player_move == 4):
print ("You didn't put in correct input, computer gets a free win")
return -1

player_score = 0
comp_score = 0
round = 0

welcome_prompt()

('Round ' + str(round))
while round< 10:
round = round + 1
get_player_move()
get_computer_move()
compare_moves(get_player_move, get_computer_move)

if compare_moves == 1:
player_score = player_score + 1
print 'Player Score'+ str(player_score)
print 'Computer Score'+ str(player_score)
elif compare_moves == -1:
comp_score = comp_score + 1
print 'Player Score'+ str(player_score)
print 'Computer Score'+ str(player_score)

print ("Game Over")

Answers

Answer 1

Answer:

hmm i would assume your syntax code has a hidden error that's messing up your code that you are trying to input inside your computers field matrix to do the game. question is where is that error?

Explanation:


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Answer:

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Answers

Answer:

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Explanation:

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Answers

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Explanation:

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PLS HELP ASAP ILL GIVE BRAINLKEST PLS THANKS 20 POINTS

Answers

Scroll Down to See Answer ↓

∧-∧ But Read the Explanation to Make Sure ∧-∧

Answer/Explanation:

These algorithms have undergone extensive security analysis and are continually tested to ensure that they provide adequate security. Cryptographic algorithms will usually use cryptographic keys and when these algorithms need to be strengthened, it can often be done by using larger keys.

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Knowing that these 2 Choices Don't really look Right...

Because it our job = Wrong

Because encryption algorithm are always weak = Wrong

So It leads us to these...

To Prevent all Decryption = ?

To protect online Information = ?

But Base on the Information below:

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You could Read the Explanation Above If you want to Check.

[RevyBreeze]

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Answer:

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Answer:

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Explanation: q posted

Answer: Anwer is correctly shown!!!!!!!!

Explanation:

HOPE IT HELPS Y'ALL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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What code would add a new array item named "home" to the array below?

var titles = ["score", "points"];

titles.put("home");
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titles.set("home");
array.push("home");

Answers

Answer:

titles.push("home");

Explanation:

        It depends on if you want to change the original array or not, but since you are just adding on I think this is the correct option.

        "... 5 ways to add an item to the end of an array. Push, splice, and length will mutate the original array. Whereas concat and spread will not and will instead return a new array. Which is the best depends on your use case" (www.samanthaming.com)

[] Attached is from the same source

-> I think this is correct

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Answer:

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Explanation:

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Answer

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Explanation:

Try buying a new windows or resetting your laptop/pc

or your service failed to register/start

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Answers

Answer:

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Explanation:

please mark me brainlisted answer please

Explanation:

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Answers

Answer:

filters

Explanation:

you use filters to specify what you want to find

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Web maintenance plays a vital role in a website's development. It helps ensure
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Need help can someone answer plz

Answers

Answer:

Prevents lagging

Explanation:

This prevents the website from being slow and upto shape so those who access it dont have difficulties

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Plzzz solve this problem ​

Answers

Answer:

You should concentrate yourself

Explanation:

1=x

2=y

x<y

hence proved solved thank me later

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Answers

Answer:

new_list = play_list[0:4]

Explanation:

new_list = play_list[0:4] is an expression that evaluates to a new list containing the elements at index 0 through index 4 in play_list.

What do you mean by an expression?

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Complete a flowchart and a Python program to calculate grade of a student based on marks using the following criteria:

Ask a student for their marks and if their marks are:

More than 90 – print “A*”

Between 80 and 90 – print “A”

Between 70 and 80 – print “B”

Between 60 and 70 – print “C”

Between 50 and 60 – print “D”

Between 40 and 50 – print “E”

Under 40 – print “Fail”

Answers

Answer:

grade = int(input("Enter grade: ")

if grade > 90:

   print("A*")

elif grade > 80 and grade < 90:

   print("A")

elif grade > 70 and grade < 80:

   print("B")

elif grade > 60 and grade < 70:

   print("C")

elif grade > 40 and grade < 50:

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else:

   print("Fail")

Explanation:

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Answers

Web designers need to be proficient in Front-end coding languages in addition to good design sense.

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