We have the following functions:
[tex]\begin{gathered} g\mleft(x\mright)=-x^2+4x \\ h\mleft(x\mright)=-4x-1 \end{gathered}[/tex]And we need to find:
[tex](3g-h)(-3)[/tex]Step 1. Find 3g by multiplying g(x) by 3:
[tex]\begin{gathered} g(x)=-x^2+4x \\ 3g=3(-x^2+4x) \end{gathered}[/tex]Use the distributive property to multiply 3 by the two terms inside the parentheses:
[tex]3g=-3x^2+12x[/tex]Step 2. Once we have 3g, we subtract h(x) to it:
[tex]3g-h=-3x^2+12x-(-4x-1)[/tex]Here we have 3g and to that, we are subtracting h which in parentheses.
Simplifying the expression by again using the distributive property and multiply the - sign by the two terms inside the parentheses:
[tex]3g-h=-3x^2+12x+4x+1[/tex]Step 4. Combine like terms:
[tex]3g-h=-3x^2+16x+1[/tex]What we just found is (3g-h)(x):
[tex](3g-h)(x)=-3x^2+16x+1[/tex]Step 5. To find what we are asked for
[tex]\mleft(3g-h\mright)\mleft(-3\mright)[/tex]We need to evaluate the result from step 4, when x is equal to -3:
[tex](3g-h)(-3)=-3(-3)^2+16(-3)+1[/tex]Solving the operations:
[tex](3g-h)(-3)=-3(9)^{}-48+1[/tex][tex](3g-h)(-3)=-27^{}-48+1[/tex][tex](3g-h)(-3)=-74[/tex]Answer:
[tex](3g-h)(-3)=-74[/tex]Nayeli bought Jamba juice smoothies for herself and Evelyn after school one day. The smoothies cost $4.95 each plus 8.5% tax. how much change did she receive from a $20 bill
Explanation
Step 1
remember
[tex]8.5\text{ \%}\Rightarrow\frac{8.5}{100}=0.085[/tex]then, to find the value of the tax, multiply 4.95 0 0.085
[tex]\text{tax}=4.95\cdot0.085=0.42075\text{ per smoothie}[/tex]so, the total cost is
total =2 smoothies +(taxes for 2 smoothies)
total=(2*4.95)+(2*0.42075)
total=9.9+0.8415
total=10.7415
so, Nayebi paid $10.7415
Tara makes and sells scarves for children and adults. She is able to sell the scarves for $18 per unit. Materials for the scarves cost $4 each. She has fixed cost per month of $280 and estimates that she can make and sell 80 scarves each month. How many scarves does Tara need to sell to break even?
Tara needs to sell 20 scarves to break even.
What is the break-even point?The break-even point is the sales level that the seller must attain to make the total revenue equal to the total costs (fixed and variable).
There is no profit or loss at the break-even point (either in units or dollar values).
Selling price per unit = $18
Product cost per unit = $4
Contribution margin per unit = $14
Fixed cost per month = $280
Estimated production and sales units per month = 80 scarves
Break-even sales units = fixed costs/contribution margin per unit
= 20 ($280/$14)
Check:
Total revenue at 20 units = $360 (20 x $18)
Total costs at 20 units = $360 ($280 + $4 x 20)
Thus, for Tara to break even, she needs to sell 20 scarves per month.
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Hi how do I graph these? I don't understand how I'm supposed to graph fractions?
To plot in the plane points with fraction number coordinates (x or y) you can rewrite the fractions as decimal numbers:
[tex]\begin{gathered} \frac{-5}{2} \\ \\ -5\text{ divided into 2} \\ \\ -\frac{5}{2}=-2.5 \\ \\ \\ \\ \\ \frac{-1}{4} \\ \\ -1\text{ divided into 4:} \\ -\frac{1}{4}=-0.25 \end{gathered}[/tex]Then, you have the next coordinates;
(- 2.5, 2) and (1, -0.25)
And the next graph:
Use a line to link the points
Solve the inequality and how do i graph ?
The most appropriate choice for linear inequation will be given by-
[tex]m > \frac{1}{2}[/tex] is the correct solution
What is linear inequation?
At first it is important to know about algebraic expressions.
Algebraic expressions consists of variables and numbers connected with addition, subtraction, multiplication and division.
Inequation shows the comparision between two algebraic expressions by connecting the two algebraic expressions by > , < , [tex]\geq, \leq[/tex]
A one degree inequation is known as linear inequation.
Here,
The given inequation is [tex]\frac{1}{2} - \frac{m}{4} < \frac{3}{8}[/tex]
Now,
[tex]\frac{1}{2} - \frac{m}{4} < \frac{3}{8}\\\\\frac{m}{4} > \frac{1}{2} - \frac{3}{8}\\\\\frac{m}{4} > \frac{4 - 3}{8}\\\\\frac{m}{4} > \frac{1}{8}\\\\m > \frac{1}{8} \times 4\\m > \frac{1}{2}[/tex]
The number line has been attached here.
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how do I find the decimal value of the fraction 11/16?
You divide 11 by 16, as follow:
0.6875
16 l 110
-96
140
-128
120
-112
80
-80
0
As you can notice, the result of the division is 0.6875 (here you have used the rules for the division of a number over a greater number, which results in a decimal)
Bc is included between
Answer:
A. angle B and angle C
Step-by-step explanation:
Line segments are named after the two points where they begin and end.
W L is tangent to circle O at point W. If mW H A = 260 degrees , find m< AWL
Answer:
[tex]m\angle AWL\text{ = 130}\degree[/tex]Explanation:
Here, we want to get the measure of the angle marked AWL
The measure of this angle is simply half the measure of the big arc WHA
Mathematically, we have the measure of the angle as:
[tex]\begin{gathered} m\angle AWL\text{ = }\frac{1}{2}\text{ }\times\text{ mWHA} \\ \\ =\text{ }\frac{1}{2}\times\text{ 260 = 130}\degree \end{gathered}[/tex]Consider the function f(x) = 6 - 7x ^ 2 on the interval [- 6, 7] Find the average or mean slope of the function on this interval , (7)-f(-6) 7-(-6) = boxed |
Answer:
• Mean Slope = -7
,• c=0.5
Explanation:
Given the function:
[tex]f\mleft(x\mright)=6-7x^2[/tex]Part A
We want to find the mean slope on the interval [-6, 7].
First, evaluate f(7) and f(-6):
[tex]\begin{gathered} f(7)=6-7(7^2)=6-7(49)=6-343=-337 \\ f(-6)=6-7(-6)^2=6-7(36)=6-252=-246 \end{gathered}[/tex]Next, substitute these values into the formula for the mean slope.
[tex]\begin{gathered} \text{ Mean Slope}=\frac{f(7)-f(-6)}{7-(-6)}=\frac{-337-(-246)}{7+6}=\frac{-337+246}{13} \\ =-\frac{91}{13} \\ =-7 \end{gathered}[/tex]The mean slope of the function over the interval [-6,7] is -7.
Part B
Given the function, f(x):
[tex]f\mleft(x\mright)=6-7x^2[/tex]Its derivative, f'(x) will be:
[tex]f^{\prime}(x)=-14x[/tex]Replace c for x:
[tex]f^{\prime}(c)=-14c[/tex]Equate f'(c) to the mean slope obtained in part a.
[tex]-14c=-7[/tex]Solve for c:
[tex]\begin{gathered} \frac{-14c}{-14}=\frac{-7}{-14} \\ c=0.5 \end{gathered}[/tex]The value of c that satisfies the mean value theorem is 0.5.
Bella drove her car 81 km and used 9 liters of fuel. She wants to know how many kilometers (x) she can drive on 22 liters of fuel. She assumes her car will continue consuming fuel at the same rate.
Find the proportion between liters of fuel
that is find 22/9 = 2.444
thats how much liters have more to consume
now multiply 2.444 by 81 , the kilometers she has drived
It gives as result 2.444 x 81 = 198 kilometers
Ana has $75 and saves an additional $13 per week. Which equation can be used to findhow many weeks it will take until she has $452?75 + w = 4520 75 + 13w = 45213w = 75 = 452452 + 13w = 75
Here, we want to get an equation
Firstly, since we do not have the number of weeks, we can represent it with a variable (a letter)
In this case, we shall be representing it with w
Since she saves $13 in a week, in w weeks, the amount saved will be;
13 * w = $13w
Now, recall that she has $75 before she started saving. What this mean is that at the end of the w weeks, the amount she will have will be ;
[tex]13w\text{ + 75}[/tex]We now proceed to equate this to the total she wants to save and we finally have the complete equation below;
[tex]13w\text{ + 75 = 452}[/tex]
A Labrador Retriever puppy named Milo weighed 11 pounds and gained 2 pounds per week.
After how many weeks did Milo weigh 39 pounds? Weeks?
After 15 weeks Milo's weight is 39 pounds.
According to the question,
We have the following information:
Weight of Milo = 11 pounds
Milo gained weight at the rate of 2 pounds per week.
So, we have the following progression:
11, 13, 15, ....
Now, we will subtract the previous term from the next term to check whether it is an arithmetic progression or not.
15-13 = 2
13-11 = 2
So, it is an A.P.
We know that following formula is used to find the nth term:
an = a+(n-1)d where a is the first term, n is the number of term and d is the common difference
We have weight of Milo as 39 pounds.
11+(n-1)2 = 39
11+2n-2 = 29
2n+9 = 39
2n = 39-9
2n = 30
n = 30/2
n = 15
Hence, it will take 15 weeks to reach Milo's weight at 39 pounds.
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An integer is chosen at random from 1 to 50. find the probability that the chosen integer is not divisible by 2, 7 or 9a)13/50b)16/25c)9/25
There are a total of 50 numbers that are between 1 and 50. Halft of these numbers are even (divisible by 2 ) and half of then odd.
There are 25 integers that are not even and in total there are 50 integers; thereofre, the probablity of finding an even integer is
25/50 = 1/2
helpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
(f o g)(x) = 8x³ + 2x - 6
(g o f)(x) = 2x³ + 2x - 12
Step-by-step explanation:
f(x) = x³ + x - 6; g(x) = 2x
(f o g)(x) = f(g(x))
f(g(x)) = (2x)³ + (2x) - 6
f(g(x)) = 8x³ + 2x - 6
(g o f) = g(f(x))
g(f(x)) = 2(x³ + x - 6)
g(f(x)) = 2x³ + 2x - 12
I hope this helps!
explain pleaeeeeeeez
Answer:
So first we can assume x= 1 bc there is no number for x
Step-by-step explanation:
So we Evaluate for x=1
1+|2−1|−5
1+|2−1|−5
=−3
Evaluate for x=1
So x+|x-5|+9
1+|1−5|+9
1+|1−5|+9
=14
find the height of the trapezoidA=51CM2b=10cmb=7cmH?
we must find b one of the parallel sides before proceeding to find h
from the diagram b = 7cm
[tex]\begin{gathered} \text{Area = }\frac{10\text{ +7}}{2}\times h \\ 51\text{ = }\frac{17}{2}\times h \end{gathered}[/tex][tex]\begin{gathered} 51\text{ x 2 = 17h} \\ h\text{ =}\frac{51\times2}{17} \\ h\text{ =6cm} \end{gathered}[/tex]solving right triangle find the missing side. round to the nearest tenth
Apply trigonometric functions:
Cos a = adjacent side / hypotenuse
Where:
a = angle = 59°
adjacent side = 34
Hypotenuse = x
Replacing:
Cos 59 = 34 / x
Solve for x:
x = 34 / cos 59
x = 66
90 minutes for 3 typed pages; 60 minutes for a a typed pages write a proportion for each phrase and solve it
90 minutes for 3 typed pages; 60 minutes for a a typed pages write a proportion for each phrase and solve it
we have that
90/3=60/a
solve for a
a=(60*3)/90
a=2 pagesI need help for my assignment I need to submit today
The general equation of a circle is expressed as
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2\text{ ----- equation 1} \\ \text{where} \\ (a,\text{ b)}\Rightarrow\text{ center of the circle} \\ r\Rightarrow radius\text{ of the circle} \end{gathered}[/tex]Given that a circle having equation
[tex]\begin{gathered} (x-2)^2+(y-5)^2\text{ = 16} \\ \Rightarrow(x-2)^2+(y-5)^2\text{ = }4^2 \end{gathered}[/tex]is moved up 3 units and 1 unit to the left. Thus, we have
[tex]\begin{gathered} (x-2+1)^2+(y-5-3)^2\text{ = }4^2 \\ \end{gathered}[/tex]This gives
[tex](x-1)^2+(y-8)^2\text{ = }4^2\text{ ----- equation 2}[/tex]Comparing equations 1 and 2, we have
[tex]a\text{ = 1, b = 8, r = 4}[/tex]Hence,
the center (a, b) of the circle is (1, 8),
the radius r of the circle is 4,
the equation of the circle is
[tex](x-1)^2+(y-8)^2=4^2[/tex]From the table below, determine whether the data shows an exponential function. Explain why or why not. x31-1-3y1234a.No; the domain values are at regular intervals and the range values have a common sum 1.b.No; the domain values are not at regular intervals.c.Yes; the domain values are at regular intervals and the range values have a common factor 2.d.Yes; the domain values are at regular intervals and the range values have a common sum 1.
Solution:
Given:
The table of values is given:
From the table,
We see the data is a linear function. This is because a linear function has domain values at regular intervals.
Also, the linear equation can be formed as shown below, indicating it is a linear function.
Considering two points, (3,1) and (1,2)
where,
[tex]\begin{gathered} x_1=3 \\ y_1=1 \\ x_2=1 \\ y_2=2 \\ \\ \text{Then,} \\ \text{slope, m is given by;} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \\ \text{Substituting the values into the formula above,} \\ m=\frac{2-1}{1-3} \\ m=\frac{1}{-2} \\ m=-\frac{1}{2} \end{gathered}[/tex]A linear equation is of the form;
[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope} \\ b\text{ is the y-intercept} \\ \\ To\text{ get the value of the y-intercept, we use any given point} \\ U\sin g\text{ point (3,1)} \\ y=mx+b \\ 1=-\frac{1}{2}(3)+b \\ 1=-\frac{3}{2}+b \\ 1+\frac{3}{2}=b \\ 1+1.5=b \\ b=2.5 \\ \\ \\ \text{Thus, the linear equation is;} \\ y=-\frac{1}{2}x+2.5 \end{gathered}[/tex]From the above, has confirmed it is a linear function and not an exponential function, we can deduce that;
a) The function is not an exponential function.
b) The domain values (x-values) are at regular intervals
c) The range values (y-values) have a common difference of 1
Therefore, the correct answer is OPTION A
Suppose Set A contains 48 elements and Set B contains 16 elements. If the total number elements in either Set A or Set B is 54, how many elements do Sets A and B have in common?
Considering the Set A and B given, Applying inclusion - exclusion principle the number of elements common to both Sets is 10
What is inclusion - exclusion principle?This is a counting techniques that ensures that elements are not counted twice
It is achieved by the formula:
(A ∪ B) = n(A) + n(B) - n(A ∩ B)
Finding the elements Sets A and B have in commonThe information from the question include the following
Set A contains 48 elements
Set B contains 16 elements
The total number elements in either Set A or Set B is 54
Applying inclusion - exclusion principle gives the formula
Set A + Set B - ( Set A ∩ Set B ) = Set A ∪ Set B
substituting the values gives
48 + 16 - ( Set A ∩ Set B ) = 54
48 + 16 - 54 = ( Set A ∩ Set B )
10 = ( Set A ∩ Set B )
( Set A ∩ Set B ) = elements Sets A and B have in common
Therefore the number of the elements common to Sets A and B is 10
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A person invested $3,700 in an account growing at a rate allowing the money to double every 6 years. How much money would be in the account after 14 years, to the nearest dollar?
Given :
The principal = 3,700
Assume a simple interest
The account growing at a rate allowing the money to double every 6 years.
So,
[tex]\begin{gathered} I=P\cdot r\cdot t \\ I=P \\ 3700=3700\cdot r\cdot6 \\ r=\frac{1}{6} \end{gathered}[/tex]How much money would be in the account after 14 years, to the nearest dollar?
So, we will substitute with r = 1/6, t = 14 years
So,
[tex]\begin{gathered} I=3700\cdot\frac{1}{6}\cdot14=8633.33 \\ \\ A=P+I=8633.33+3700=12333.33 \end{gathered}[/tex]Rounding to the nearest dollar
So, the answer will be $12,333
creat an espression that includes the zero property of exponents the multiplication property of exponents and the power of a power property of exponents
All in one, or one expression for each property?
a) Zero property
[tex]\text{ (x + y)}^0\text{ = 1}[/tex]b) Multiplication property
[tex]\text{ x}^2\cdot x^5=x^{2+5}=x^7[/tex]c) Power property
[tex]\text{ (x}^2)^3=x^{2\cdot3}=x^6[/tex]d) All in one (this is the expression)
[tex]\mleft\lbrace\text{(x}^0)(x^3)\mright\rbrace\text{ }(x^2)^5[/tex][tex]\text{ }\mleft\lbrace1(x^3\mright)\}(x^{10})[/tex]
a scuba diver descended 19 5/12 feet blow sea level. Then he descended another 3 3/5 feet. Which of the following is true about the scuba diver after both descents?
The position of the scuba diver is 23 1/60 feet.
How to calculate the fraction?From the information, the scuba diver descended 19 5/12 feet blow sea level and then he descended another 3 3/5 feet.
The position of the diver will be. the addition of the fraction for descending. This will be:
= 19 5/12 + 3 3/5
= 19 25/60 + 3 36/60
= 22 61/60
= 23 1/60
Note that your information is incomplete as the question was answered based on information given.
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Write the equation for the quadratic function in vertex form & standard form with the given vertex that passes through the given point.Vertex (2, -8) through the point (4, 3)
We will have the following:
[tex]\begin{gathered} y=a(x-2)^2-8\Rightarrow3=a(4-2)^2-8 \\ \\ \Rightarrow3=4a-8\Rightarrow4a=11 \\ \\ \Rightarrow a=\frac{11}{4} \end{gathered}[/tex]So, the equation in vertex form is:
[tex]y=\frac{11}{4}(x-2)^2-8[/tex]And in standard form:
[tex]\begin{gathered} y=\frac{11}{4}(x^2-4x+4)-8\Rightarrow y=\frac{11}{4}x^2-11x+11-8 \\ \\ \Rightarrow y=\frac{11}{4}x^2-11x+3 \end{gathered}[/tex]***Explanation***
We know that the quadratic expression in vertex form follows:
[tex]y=a(x-h)^2+k[/tex]Where (h, k) is the vertex of the expression. Now, we know that the vertex is (2, -8), so we replace those values and we obtain:
[tex]y=a(x-2)^2+(-8)\Rightarrow y=a(x-2)^2-8[/tex]Now, in order to determine "a" we must replace one point (That is not the vertex) in the expression and solve for "a", and we are told that the point (4, 3) is in one of the solutions, so:
[tex]\begin{gathered} 3=a(4-2)^2-8\Rightarrow3=a(2)^2-8 \\ \\ \Rightarrow11=4a\Rightarrow a=\frac{11}{4} \end{gathered}[/tex]Thus, the expression in vertex form is then:
[tex]y=\frac{11}{4}(x-2)^2-8[/tex]And to determine the standard form, we simply expand the equation in vertex form:
[tex]y=\frac{11}{4}(x^2-4x+4)-8\Rightarrow[/tex]A bird sits on top of a Lamppost. The angle made by the lamp-post and a line from the feet of the bird to the feet of the Observer standing away from the Lamppost is 55°. the distance from the Lamppost and the Observer is 25 ft. estimate the height of the lamp post
A bird sits on top of a Lamppost. The angle made by the lamp-post and a line from the feet of the bird to the feet of the Observer standing away from the Lamppost is 55°. the distance from the Lamppost and the Observer is 25 ft. estimate the height of the lamp post
we have that
see the attached figure to better understand the problem
so
tan(55)=h/25
solve for h
h=25(tan(55))
h=35.7 ftFind the quotient of these complex numbers.(4 + 4i) (5 + 4i) =A.B.C.D.
Find the quotient given below:
[tex]\frac{4+4i}{5+4i}[/tex]When managing complex numbers, we must recall:
[tex]\begin{gathered} i^2=-1 \\ \text{ Or, equivalently:} \\ i=\sqrt{-1} \end{gathered}[/tex]Multiply and divide the expression by the conjugate of the denominator:
[tex]\frac{4+4i}{5+4i}\cdot\frac{5-4i}{5-4i}[/tex]Multiply the expressions in the numerator and in the denominator. We can apply the special product formula in the denominator:
[tex](a+b)(a-b)=a^2-b^2[/tex]Operating:
[tex]\frac{(4+4i)(5-4i)}{5^2-(4i)^2}[/tex]Operate and simplify:
[tex]\frac{20-16i+20i-16i^2}{25-16i^2}[/tex]Applying the property mentioned above:
[tex]\frac{20-16i+20i+16}{25+16}[/tex]Simplifying:
[tex]\frac{36+4i}{41}[/tex]The following are the standard equation of a circle with center at the origin and radius of 2, except: a. x^2-4=-y^2b. x^2+4=-y^2c. x^2+y^2=2^2d. x^2+y^2=4
The equation of a circle is defined as
[tex]\begin{gathered} x^2+y^2=r^2 \\ \text{where} \\ r\text{ is the radius} \end{gathered}[/tex]Given that the radius of the circle is 2, then the equation of the circle is
[tex]x^2+y^2=2^2\text{ (option C)}[/tex]Which can then be simplified to
[tex]x^2+y^2=4\text{ (option D)}[/tex]And we can rearrange the equation
[tex]x^2-4=-y^2\text{ (option A)}[/tex]Which means that it cannot be the equation
[tex]x^2+4=-y^2[/tex]her player O oo Find the amount of simple interest that $400 would earn at 8% per year by the end of 3 years. O A. $96 OB. $11,200 O c. $3200 OD. D. $112 O E. $32
To answer this question, we need to use the next formula for simple interest:
[tex]FV=PV\cdot(1+in)[/tex]Where:
FV is the future value we need to find (in this case).
PV is the present value, that is, $400 (in this case).
i is the interest rate. In this case, we have 8% (0.08).
n is the number of periods (n = 3, in this case).
Then, we have:
[tex]FV=400\cdot(1+(0.08)\cdot3)\Rightarrow FV=496[/tex]That is, the FV is $496. Therefore, the simple interest is $(496-400 = 96).
Thus, the amount of simple interest that $400 would earn at 8% per year by the end of 3 years is $96 (option A).
In other words, the result can be obtained also if we have is $400 * (0.08)*3 = $96.
which statement is true
We have to analyze the given options to solve this problem.
Option 1.
The absolute value of -12 is larger than the absolute value of 12.
The absolute value is always a positive number:
[tex]undefined[/tex]what is the LCM of 4 and 6 ?
LCM stands for Least Common Multiple.
And it is defined as the product of the two numbers divided by the GCD (greatest common divisor)
In our case, the product of 4 and 6 is 24, , and the greatest common divisor of 4 and 6 is "2". Therefore, the LCM of 4 and 6 is 24/2 = 12
Let me also use the Venn diagram that your teacher provided:
In the diagram we enter the factors that correspond to both numbers (4 and 6), and in the intersection of the two sets (intersection of the circle) we type a "2" which is the ONLY factor 4 and 6 have in common (the greatest common divisor of the two given numbers) So complete a diagram as follows:
We typed a 2in the area common to both numbers. Then your LCM is the product of 2 times 2 times 3 = 12
Notice the blue set (circle) contains the two factors for 4 (2 * 2) and the orange circle contains the two factor for 6 (2 * 3)
We set in the intersection of the two circles the factor that is common to both.
Do you want me to complete the second question with a Venn diagram as well? Perfect.
The second question is about the LCM of the numbers 12 and 8
Then we create a Venn diagram like the following, considering that the factor in common between 12 and 8 is 4, because 12 = 4 * 3 and 8 = 4 * 2
Again here, the factors 3 and 4 (that give 12) are typed in the blue circle. and the factors that form 8 (4 * 2) are typed inside the orange circle.
The factor that both share is in the middle "4". Therefore, now to find the LCM you simply multiply the three numbers shown in the Venn diagtam: 3 * 4 * 2 = 24
Then 24 is your LCM.