I need help on this, please tell me what it is.

Answer:

Time = 11.60 seconds.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

[tex]Speed = \frac{distance}{time}[/tex]

Given the following data;

Speed = 0.711m/s

Distance = 8.25m

To find the time;

Making time the subject of formula, we have;

[tex]Time = \frac{distance}{speed}[/tex]

Substituting into the equation, we have;

[tex]Time = \frac{8.25}{0.711}[/tex]

Time = 11.60 secs.

Answer:

D

Explanation:

It does all three

Answer:

maximum height reach by rockect =970.2metre

Explanation:

Answer:

it wont be because the hand brake would be on

Answer:

98

Explanation:

We have that for the Question "Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material." it can be said that

From the question we are told

Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the  material.

Generally the equation for the  index of refraction  is mathematically given as

[tex]n=\frac{C}{v}\\\\Therefore\\\\n=\frac{3*10^8}{2.5 * 10 }\\\\n=12000000\\\\[/tex]

Therefore

The  index of refraction  of the material is

n=12000000

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Answer:

velocity is vector Quantity

Answer:

A.) a bicycle moving at a constant speed on a straight, level road.

Explanation:

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force measured in Newton.

m represents the mass of an object measured in kilograms.

a represents acceleration measured in meter per seconds square.

In Physics, when the net force acting on a body or an object is equal to zero (0); the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.

In this scenario, the situation in which the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.

The net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

The given problem is based on the Newton's second law to define net force. The net force on any object is an external effort by which the object change its speed with respect to time or tends to change the state of its motion. The mathematical expression for the net force is,

F = ma

Here, F is the net force, m is the mass of object and a is the acceleration of object.

Thus, we conclude that the net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

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Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

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Answer:

The correct false statement is;

As the stone rises, its potential energy decreases

Explanation:

When the stone is thrown straight up into the air, the initial velocity, u, progressively decreases according to the following equation;

v = u - g·t

Where;

v = The final velocity

g = The acceleration due to gravity = 9.81 m/s²

t = The time taken

Therefore whereby, the kinetic energy. K.E. is given by the equation , K.E. = 1/2 × m × u², as u reduces, the kinetic energy reduces

However, the potential energy, P.E. is given as P.E. = m × g × h

Where;

h = Height

m = The mass of the stone

Therefore, as the stone rises, the potential energy increases.

Answer:

a &c

Explanation:

>3

Attraction between the molecules of a liquid and the temperature at which the liquid changes state is "Strong attractions mean the liquid boils at a higher temperature". The correct option is C

Temperature is a physical quantity which measures hotness and coldness of a body. Temperature measures the degree of vibration of molecule in a body. Temperature is measured in centigrade (°C), Fahrenheit (°F) and Kelvin (K) in which Kelvin (K) is a SI unit of temperature. Absolute scale of temperature means Kelvin scale of temperature.

relation between Kelvin(K) and centigrade (°C),

°C= K - 273.15

from equation, 273.15 K means 0 °C, which is freezing point of water (ice).

when we give temperature to the body, its molecule or atom absorbs thermal energy and vibrate about their mean position. Amplitude of vibration get increases as we go on increasing temperature and for higher temperature force of attraction between molecules gets weaker. Hence for higher temperature, due to weaken the force of attraction between molecule, solid goes into liquid state. and further increase in temperature liquid goes into gaseous state.

Liquid has stronger force of attraction than gas and weaker than solid. Strong force of attraction means high temperature should be given to break molecular bonds. Therefore Strong attractions mean the liquid boils at a higher temperature.

Hence option C is correct.

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Answer:

10 m

Explanation:

PE = mgh

m = 50kg

g= 9.8 m/s^2

h=?

so,

4900= 50×9.8× h

50h = 4900/9.8

50h = 500

h = 10 m

Answer:

80 km is distance and 30km north is displacement

Explanation:

distance= 50+30=80km

displacement= 50-20=30

his displacement is 30km north

When Tyler drives 50 km north and then drives back 30 km south, we have:

1. The distance that he covers is 80 km.

2. Tylor's displacement is 20 km.  

1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:

[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]

Hence, the distance traveled by Tyler was 80 km.

2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:

[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]

Therefore, Tyler's displacement is 20 km.

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Answer:

The coefficient of friction between the block and the slope is 0.16.

Explanation:

We can find the coefficient of friction between the block and the slope by using Newton's second law:        

[tex] \Sigma F = ma [/tex]

[tex]P_{x} -\mu N = ma[/tex]

[tex] mgsin(\theta) - \mu mgcos(\theta) = ma [/tex]    (1)              

Where:

m: is the mass of the block = 5.0 kg

a: is the acceleration = 4.2 m/s²

θ: is the angle = 34°

μ: is the coefficient of friction =?

g: is the gravity = 9.81 m/s²

By entering the above values into equation (1) we have:

[tex] gsin(\theta) - \mu gcos(\theta) = a [/tex]                  

[tex] \mu = \frac{gsin(\theta) - a}{gcos(\theta)} = \frac{9.81 m/s^{2}*sin(34) - 4.2 m/s^{2}}{9.81 m/s^{2}*cos(34)} = 0.16 [/tex]

Therefore, the coefficient of friction between the block and the slope is 0.16.

I hope it helps you!        

The acceleration of the truck is obtained from the calculation done as  0.055 m/s^2.

We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.

Initial velocity =  1.8 km/h  or 0.5 m/s

Final velocity = 24.0 km/h or 6.67 m/s

Distance covered = 4.0 * 10^2 m

Then;

v^2 = u^2 + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

a = v^2 - u^2/2s

a = (6.67)^2 - (0.5)^2/2 *  4.0 * 10^2

a = 44.4 - 0.25/800

a = 0.055 m/s^2

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Answer:

you need to capitalize

Explanation:

When Grandpa Joe comes to visit, he tells us stories about when he was in the army with Colonel Jack S. Anderson.

Answer:

Condensation

Explanation:

Answer:

Condensation! Hope this helps!!!

Explanation:

Answer:

All i got to say is that he is dead dead

Explanation:

Answer:

AM(amplitude modulation) and FM(frequency modulation)

Explanation:

A radio frequency band is a small adjacent section of the radio spectrum frequencies, whereby channels are usually used or set aside to be used.

They are usually of two different bands called AM which is known as amplitude modulation and FM which is known as frequency modulation

Answer:

hey want you to separate the energy’s and put them in the categories they go in like why are They different what is chemically different about them? Etc.why do they act differently.. do they act the same in some ways? Think about that

Explanation:

Answer:

B- Gravitational Field

Explanation:

Have a nice day, hope you get a good grade!

The  generator converts mechanical energy to electrical energy by using a conducting metal loop turning in a gravitational field.

In terms of physics, a gravitational field represent the model that should be used for explaining the impact where the massive body should be extended into the space around it. Also, generating the force on the another massive body.

Therefore, based on the above explanation, the correct option is b.

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Answer:

The distance is 1.04 m and time is 0.16 seconds.

Explanation:

Initial speed, u = 6.75 m/s

Final speed, v = 5.91 m/s

Acceleration, a = -5.11 m/s²

We need to find the distance Rickey slides across the ground before touching the base and the time he sliding for before touching the base.

Let d is the distance. It can be calculated using third equation of motion as follows :

[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(5.91)^2-(6.75)^2}{2\times (-5.11)}\\\\d=1.04\ m[/tex]

Let t is the time he slides for before touching the base. Using first equation of motion as follows :

[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{5.91-6.75}{-5.11}\\\\t=0.16\ s[/tex]

So, the distance is 1.04 m and time is 0.16 seconds.