I NEED A SCIENCE EXPERT TO GIVE ME THE RIGHT ANSWERS TO THESE ASAP

Answer:

Explanation: actually for moving it in an CONSTANT velocity u need a zero accleration

F-f=ma,a=0 hence F=f=Nα=mgα=1,495.63 N

Answer:

The acceleration of the car was one meter per second squared.

Explanation:

We can use one of the kinematic equations:

[tex]\displaystyle v_f = v_i + at[/tex]

Where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time (in seconds).

The final velocity is 40 m/s, the initial velocity is 35 m/s, and the time is 5 s. Substitute and solve for a:

[tex]\displaystyle \begin{aligned}(40 \text{ m/s}) &= (35 \text{ m/s}) + a(5\text{ s}) \\ \\ 5 \text{ m/s} &= a(5\text{ s}) \\ \\ a &= 1\text{ m/s$^2$} \end{aligned}[/tex]

In conclusion, the acceleration of the car was one meter per second squared.

Answer:

6.66666 sec/m or 6 2/3 sec/m

Answer:

6.67 meters per second

Explanation:

120/18=6.67 meters per second

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 2 kg

velocity/speed = 3 m/s

We have

momentum = 2 × 3 = 6

We have the final answer as

Hope this helps you

Answer:

(Question) Which of these quantities is a vector?

(Answer) momentum

(Question) What is the representation of the momentum vector?

(Answer) an arrow

(Question) What is the formula for the momentum p?

(Answer) p=m⋅v

(Question) What happens to the total momentum in a system of two interacting objects when a net force is exerted upon the system?

(Answer) The total momentum is conserved.

(Question) What is the magnitude momentum of a 2 kg body that moves with a speed of 3 m/s?

(Answer) 6.0

Explanation:

just finished the quick check UwU

Answer:

If the work done by a resistive force is W then

W = F d = m a d where a is the acceleration of the object and d the distance traveled during this acceleration,

The object started with potential energy E = m g h

m g h = m a d

d = g h / a    where d is the distance traveled

We want to find at what angle a projectile is launched given that at the highest point, the speed is 6m/s.

The launch angle of the projectile is 60°.

Remember that the only acceleration will appear on the vertical axis, and this is the gravitational acceleration, this means that on the horizontal axis we will have a constant speed.

Also remember that when an object is on its highest point, the vertical velocity is equal to zero, then it only has horizontal velocity (which we know it is a constant).

Then we can conclude that the horizontal velocity is equal to 6m/s.

If the angle is measured from the horizontal axis, we will have that the horizontal velocity is a projection on the x-axis of the initial speed, this is:

12m/s*cos(θ) = 6m/s

Now we can solve this for theta.

cos(θ) = (6m/s)/(12 m/s) = 1/2

θ = Acos(1/2) = 60°

The launch angle of the projectile is 60°.

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Explanation:

mass

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4

4

4

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4

4

4

4

4

From the calculations and the free body diagram, the net force that acts on the body is 34.5 N

The net force refers to the force that is acting on a body. Let us note that the gravitational force and the normal force cancel out each other. Thus the two force that act on the body are the applied force and the frictional force.

Thus;

The  net force that acts on the body is;

40.2 N - 5.7 N = 34.5 N

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Explanation:

oh wait you ask what type of light on the electricity as the lowest energy per photo so is like taking a photo yet to be like make up your mind

V = IR

6 V = I × 15 Ohms

I = 6 V : 15 Ohms

I = 0,4 A

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Answer:

Displacement = 8.4m

Explanation:

Hope that this is helpful.

Have a great day.

[tex]v = 60.7m {s}^{ - 1} \: u \: = 5.26m {s}^{ - 1 } \: t = 15s \: \: \: \: \: \\ a \: = \frac{v - u}{t} \\ a \: = \frac{60 .7- 5.26}{15} \\ a = 3.7m {s}^{ - 28} \\ {v}^{2} = {u}^{2} + 2as \\ {60.7}^{2} = {5.26}^{2} + 2 \times 3.7 \times s \\ 60.7 =27 .7 + 2 \times 3.7s \\60.7 = 29.7 \times 3.7s \\ 60.7 - 29.7 = 3.7s \\ 31 = 3.7s \\ \frac{31}{3.7} = \frac{3.7s}{3.7} \\ s = 8.4m[/tex]

Answer:

C) the heat needed to boil some water

Explanation:

We have that  the final velocity of a ball thrown downward at 10 m/s after 2 seconds is

V=29.6m/s

From the question we are told

What is the final velocity of a ball thrown downward at 10 m/s after 2 seconds?

Where

Generally the Newton's equation for Motion   is mathematically given as

[tex]V=U+at\\\\V=U+gt\\\\V=10+9.8*2\\\\V=29.6m/s[/tex]

Therefore

the final velocity of a ball thrown downward at 10 m/s after 2 seconds is

V=29.6m/s

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Answer:

Answer:

Explanation:

A classic projectile motion question. Horizontal motion does not matter whatsoever in the context of this equation as we are looking at the vertical component of velocity only. Since the question states that it is fired horizontally, there is no vertical component of velocity. Thus, v0y = 0.

Assuming the projectile is on the Earth, we can use the free-fall acceleration, 9.8 m/s^2.

The question gives us Δy, which is 37.3m.

Using the second kinematics equation, Δy = v0t + (at^2)/2, we can substitute in the values.

37.3 = 0 + 0.5(9.8)t^2

37.3 = 4.9t^2

7.61224489796 = t^2

t = 2.75902970226 seconds.

Answer:

I can't see the pic so I cannot ans

Find the distance traveled by a car that travels with an average speed of 110 km/h for 3.5 h

To solve for distance:

d = v t

d = 110 × 3.5

d = 385 km

How long does it take a baseball moving with an average speed of 35 m/s to travel 18 m?

To solve for time:

t = d/v

t = 18 / 35

t = 0.514286

t = 0.5 s

What is the average speed of a car that travels 870 km in 14.5 h?

To solve for average speed:

v = d/t

v = 870 / 14.5

v = 60 km/h

Answer:

in a direction parallel to the direction that the wave moves

Explanation:

Answer:

parallel to the direction....

Answer:  15.9 m/s

Explanation:

KE = 1/2(mv^2)

190,000J = 1/2(3000kg)*v^2

1 J = 1 kg*m^2/s^2

190,000 kg*m^2/s^2 = 1/2(3000kg)*v^2

v^2 = (190,000 kg*m^2/s^2)/(1/2(3000kg))

v^2 = (190,000 kg*m^2/s^2)/(1500kg))

v^2 = 126.6667 m^2/s^2

v = 11.25 mm/s velocity of 3000kg vehicle

With the same kinetic energy, a vehicle of 1500kg would have a different velocity:

190,000 kg*m^2/s^2 = 1/2(1500kg)*v^2

190,000 kg*m^2/s^2 =(750kg)*v^2

v^2 = 253.33 m^2/s^2

v = 15.9 m/s

Answer:

7 feet because 2 feet and 5 feet make seven.

Answer:

Virchow

Explanation:

Rudolf Virchow

Answer:

It is Rudolf Virchow! Hope this help and if I could get brainliest that would be much appreciated.

Explanation:

The acceleration is approximately 4 m/s². Therefore, the correct answer is:

A. 4 m/s²

To determine the acceleration from the graph, we need to look at how the velocity changes over time. Acceleration is defined as the rate of change of velocity with respect to time. In other words, it is the slope of the velocity-time graph.

Looking at the graph, we can see that the velocity changes from 0 m/s to 4 m/s over a time interval of 2 seconds. To calculate the acceleration, we use the formula:

Acceleration (a) = Change in velocity / Change in time

Acceleration (a) = (4 m/s - 0 m/s) / (2 s) = 4 m/s²

So, the acceleration is approximately 4 m/s². Therefore, the correct answer is:

A. 4 m/s²

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Answer:

1.0147 rounded to the nearest thousandths place is 1.015

Answer:

1.015

Explanation:

If you put the number in place value, you have 1 in the ones place, 0 in the tenths place, 1 in the hundreds place, 4 in the thousandths place, and 7 in the ten thousandths place. In order to know how to round 4, you must look at the number directly after it. Since 7 is greater than five, round up to ten. This increases 4 by 1 which would give you the answer 1.015.

Answer:

55 km

pls give brainliest hope it help

Explanation:

Answer:

See Below

Explanation:

It is a change in the distribution of electric charge on one object because of  the influence a nearby object that has an electric charge.  So if an object with a negative charge is brought near to a neutral object, the neutral object will alter itself so that one side becomes more positive and the other side becomes more negative.

Electrostatic induction occurs whenever any object is placed in an electric field.

Answer:

C

Explanation:

Answer:

95

Explanation:

Answer:

put an X on the second one, the third one, the forth one, and the last one

Explanation:

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