i don’t understand this question

Option (4) all real numbers greater than or equal to -3

Step-by-step explanation:

Domain: Domain of function is defined by the x-values (Input values) on the graph.

Range: Range of a function is defined by the y-values (output values) on the graph.

x-values are starting from (-3) to infinity.

Therefore, domain of the function will be all real numbers greater than equal to (-3). Option (4) will be the answer.

The domain of the function are all real numbers greater than or equal to -3.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given is a graph, we need to find domain of the function on the graph,

Domain is the set of all possible inputs or x-values, for which the given function is defined.

The given graph is defined form -3 to positive infinity. The point -3 included in the set of input because there is a closed circle at x=-3.

So, domain of the function are all real numbers greater than or equal to –3.

Hence, the domain of the function are all real numbers greater than or equal to -3.

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Answer:

x=4, y=9

Step-by-step explanation:

Solve with substitution.

Answer:

1 solution

Step-by-step explanation:

3(2x-7)=9

dustribute: (3)(2)+(3)(-7x)=9

6+-21x=9

subtract 6 from both sides: -21x=3

Divide both sides by -21: x=-1/7

so your 1 solution is x = - 1/7

Answer:

5/7.

Step-by-step explanation:

The rise = 5 and the corresponding run si 7.

Answer:

5/7

Step-by-step explanation:

so we start at the point (0,0). the slope is essentially

Rise/Run

so in this graph we see a point of (7,5)

the rise was 5 along the y axis and the run was 7 along the x axis.

so 5/7 is correct

Step-by-step explanation:

Displacement = 576 m

Time taken = 32s

Now

[tex]average \: speed = \frac{distance \: travelled}{time \: taken} \\ = \frac{576}{32} \\ = 18 m/s[/tex]

Answer:

[tex]x= \dfrac 45[/tex]

Step by step explanation:

[tex]-2(20x+2) = -36\\\\\implies 20x +2 = \dfrac{-36}{-2} = 18\\\\\implies 20x = 18 - 2=16\\\\\implies x = \dfrac{16}{20}=\dfrac{4}5[/tex]

Answer and explanation:

Take the area formula:

A = L * W

Then manipulate it to fit the context of which unknown you are finding:

Problem 1

[tex]\dfrac{36 = 4 * W}{4}[/tex]

[tex]9 = W[/tex]

So, the length of side c is 9 mm.

Problem 2

[tex]\dfrac{21 = W * 21}{21}[/tex]

[tex]1 = W[/tex]

So, the length of side a is 1 m.

Problem 3

[tex]\dfrac{49 = 7 * W}{7}[/tex]

[tex]7=W[/tex]

So, the length of side t is 7 cm.

To use the Pythagorean theorem:
  ⇒ define Pythagorean theorem

     (look at the diagram attached for a better understanding)

Information Given:

Information Wanted:

Solve:

   [tex]5^2+9^2=hypotenuse^2\\hypotenuse^2 = 5^2 +9^2 = 25 + 81 = 106\\hypotenuse = 10.29[/tex]

Rounded to nearest tenth:

 Answer: Length of hypotenuse is 10.3

Hope that helps!

Answer:

50 - 4x = 154;

Step-by-step explanation:

50 - 4x = 154

154 - 50 = 104

104 / 4 = 26

x = 26

As both left side is same

There is no solutions .

Answer:

no solutions

Step-by-step explanation:

Given equations:

Rewrite the given equations to make y the subject:

Equation 1

[tex]-x+y=8[/tex]

[tex]\implies y=x+8[/tex]

Equation 2

[tex]2x-2y=-14[/tex]

[tex]\implies 2y=2x+14[/tex]

[tex]\implies y=x+7[/tex]

Slope-intercept form of a linear equation:  [tex]y=mx+b[/tex]

(where m is the slope and b is the y-intercept)

As both equations have the same slope, the lines are parallel and therefore there is no solution to the system of equations as the lines do not intersect.

Area of triangle:-

Area of rectangle (Including semicircle)

Area of semicircle

TOTAL area:-

Answer:

231.48 cm²

Step-by-step explanation:

Formulae

Area of a rectangle = width × length

Area of a triangle = 1/2 × base × height

Area of a semicircle = 1/2 πr²

To find the shaded area:

Find the area of the rectangle. Subtract the area of the semicircle from the rectangle. Add this to the area of the triangle.

Area of the rectangle:

= 12 x 21

= 252 cm²

Area of the semicircle:

= 1/2 π(12 ÷ 2)²

= 1/2 · 3.14 · 6²

= 1/2 · 3.14 · 36

= 56.52 cm²

Area of the triangle:

= 1/2 x 6 x 12

= 36 cm²

Shaded area:

= area of rectangle - area of semicircle + area of triangle

= 252 - 56.52 + 36

= 194.48 + 36

= 231.48 cm²

Answer: 25

Step-by-step explanation:

Answer:

2.924

Step-by-step explanation:

First you'll solve the parenthesis:

...- (5.5-5.5)

...-(0)

Now solve the equation:

[tex]\sqrt[3]{5^{2} - 0}[/tex]

[tex]\sqrt[3]{25}[/tex]

Now solve fully

I hope this helps :)

Answer:

the answer is 3 times the square root of 27

Step-by-step explanation:

Answer:

6a=42

Step-by-step explanation:

This equation would be used to find a because we don't know how many assists are for each match. And multiplying the a by the 6 games would be equivalent to 42 assists for the entire match.

Answer:

(0,0)

Step-by-step explanation:

x value of vertex = -b/2a

ax^2+bx+c

-2x^2+0x+0 sinc you have no value of b & c in your quadratic function

-b = 0

2a = (2)(-2)

-b/2a = (0/-4) = 0

x value of the vertex = 0

plug 0 in for all values of x in the function to find y coordinate value

-2(0)^2 = 0

(x,y) = (0,0)

Answer:

x = 8, y = 6/√3.

Step-by-step explanation:

The smaller triangle and the larger triangle are similar.

4 / 4√3 = (x - 6) / y

1/√3  =  (x - 6) / y

Also

y/6 = 1/√3

⇒ √3y = 6

⇒ y = 6/√3

Substitute for y in the first equation:

1/√3  =  (x - 6) / 6/√3

⇒ 1/√3 * 6/√3 = x - 6

⇒ x - 6 = 2

⇒ x = 8

Answer:

5

Step-by-step explanation:

Simplification:

[tex]\sqrt{2^3-7} + |-4|[/tex]

[tex]\sqrt{1} + 4[/tex]

1 + 4

5

Answer:

8.09

rounded to the nearest tenth ; 8.1

Step-by-step explanation:

Mean is adding all the data together than dividing by the number of data points

7.9 + 7.8 =

15.7 + 7.7 =

23.4 + 8.8 =

32.2 + 9.2 =

41.4 + 8.7 =

50.1 + 7.3 =

57.4 + 8.0 =

65.4 + 7.9 =

73.3 + 7.6 =

80.9

80.9 / 10 = 8.09

rounded to the nearest tenth = 8.1

Answer:

3(x+z+y)=k

Step-by-step explanation:

One of the strategies that would eliminate a variable in the system of equations is by subtracting both equations to eliminate the variable "x"

System of equations consists of a different set of equations with unknown variables.

Given the system of equations

2x+3y=-5

2x-3y=10

Since the coefficient of x from both equations are the same, we will subtract both equations to eliminate the variable "x"

(2x-2x)+(3y+3y) = -5 + 10
6y  = 5

Hence we can conclude that one of the strategies that would eliminate a variable in the system of equations is by subtracting both equations to eliminate the variable "x"

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Answer:

53 units

Step-by-step explanation:

Let [tex](x_1,y_1)\rightarrow(8,3)[/tex] and [tex](x_2,y_2)\rightarrow(53,31)[/tex] to use the distance formula:

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(31-3)^2+(53-8)^2}\\\\d=\sqrt{(28)^2+(45)^2}\\\\d=\sqrt{784+2025}\\\\d=\sqrt{2809}\\\\d=53[/tex]

Thus, the distance between the two points is 53 units

Answer:

Step-by-step explanation:

The student used the commutative property of addtion on the right hand side, which is correct because reordering the addends doesn't affect the value of the expression.

The student used additive commutative property for the first step.

According to this property, when two numbers or integers are added, the sum remains the same even if we change the order of numbers/integers. This property is also applicable in the case of multiplication. It can be represented as; a + b = b + a.

The student used a + b = b + a

3a + b = 2 + 7 - 5a = 2 - 5a + 7

Because add two numbers, exchange the position of the addend, and sum of them remain same.

This is a additive commutative property.

Hence, the student used additive commutative property for the first step.

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Answer:

Sample Space = {(ABC), (ACB), (BAC), (BCA), (CAB), (CBA)}

= 6

Instances when A is besides C {(ACB),( BAC),( BCA), ( CAB)}

=4

P( A is besides C)= 4/6

Answer:

-a^2-a+12

Step-by-step explanation:

Answer:

Option C.

[tex]-a^{2}-a+12[/tex]

Step-by-step explanation:

1.  Distributive multiply

[tex]-a*(a+4)+3*(a+4)[/tex]

2.  Distributive multiply

[tex]-a*a-a*4+3*(a+4)[/tex]

3.  Multiply terms to exponential form

[tex](-1) *a^{2}-a*4+3*(a+4)[/tex]

4.  Multiply constants

[tex]-a^{2}-4*a+3*(a+4)[/tex]

5.  Distributive multiply

[tex]-a^{2}-4a+(3*a+3*4)[/tex]

6.  Multiply constants

[tex]-a^{2}-4a+(3a+12)[/tex]

7.  Reorder terms

[tex]-a^{2} -4a+(12+3a)[/tex]

8.  Add terms

[tex]-a^{2}-a+12[/tex]