I dont know how to do this

pls answer if u know with simple working

The  evaluated logarithmic expression is: [tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = 2\log[10] + 2\log[x] + \frac{1}{3}\log[y] \][/tex]

Expression mentioned in the question :[tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right][/tex]. . The first property we will use is the Product Rule , so this   can be expressed as: [tex][ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = \log[10x^{2}] + \log[\sqrt[3]{y}] \].[/tex] We can now apply the Power Rule to the first term, which states that the logarithm of a power is equal to the exponent times the logarithm of the base. This can be expressed as: \[ \log[10x^{2}] = 2\log[10x] \]

We can now apply the Quotient Rule to the second term, which states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and denominator. This can be expressed as: [tex]\[ \log[\sqrt[3]{y}] = \frac{1}{3} \log[y] \].[/tex] Substituting this back into the original equation gives us:[tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = 2\log[10x] + \frac{1}{3}\log[y] \][/tex]

We can now evaluate this expression without using a calculator. The two logarithmic terms can be rewritten as:[tex]\[ \log[10x] = \log[10] + \log[x] \,  \[ \log[y] = \log[y] \][/tex]
Substituting this back into the original equation gives us: [tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = 2\log[10] + 2\log[x] + \frac{1}{3}\log[y] \[/tex]

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Answer:

width is 3 inches, length is 11 inches.

Step-by-step explanation:

Let l be the length and w be the width.

We have:

[tex]l = 2w + 5[/tex]

[tex](2w + 5)(w) = 33[/tex]

[tex]2 {w}^{2} + 5w = 33[/tex]

[tex]2 {w}^{2} + 5w - 33 = 0[/tex]

[tex](w - 3)(2w + 11) = 0[/tex]

[tex]w = 3[/tex]

[tex]l = 2(3) + 5 = 11[/tex]

The inequality that represents the heaviest the packaging can be without exceeding the 50-pound weight limit is 21 + x ≤ 50 and weight of the packaging is less than or equal to 29 pounds.

Let x be the weight of the packaging in pounds. Then the total weight of the item and its packaging is 21 + x pounds. To ensure that the total weight does not exceed the 50-pound weight limit, we can set up the following inequality:

21 + x ≤ 50

We subtract 21 from both sides to isolate x and obtain:

x ≤ 50 - 21

x ≤ 29

Therefore, the weight of the packaging cannot be greater than 29 pounds without exceeding the 50-pound weight limit. To ensure that the item can be mailed by parcel post, the weight of the packaging must be less than or equal to 29 pounds.

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Answer:

To approximate y = sin(x) using the third-degree Taylor polynomial, we need to find the polynomial that best approximates sin(x) in the neighborhood of x = 0.

The third-degree Taylor polynomial for sin(x) centered at x = 0 is given by:

P3(x) = x - (1/6)x^3

Now we can graph both functions, y = sin(x) and P3(x), over the interval [-7,7].

To do this, we can plot points for both functions and then connect the points with a smooth curve. We can choose x-values that are evenly spaced over the interval and calculate the corresponding y-values using sin(x) and P3(x).

For example, if we choose x = -7, -6, -5, ..., 5, 6, 7, then we can calculate the y-values as follows:

For sin(x):

sin(-7) ≈ -0.656

sin(-6) ≈ 0.279

sin(-5) ≈ 0.958

...

sin(5) ≈ -0.959

sin(6) ≈ -0.279

sin(7) ≈ 0.657

For P3(x):

P3(-7) = -7 - (1/6)(-7)^3 ≈ -286.8

P3(-6) = -6 - (1/6)(-6)^3 ≈ -216

P3(-5) = -5 - (1/6)(-5)^3 ≈ -141.7

...

P3(5) = 5 - (1/6)(5)^3 ≈ 141.7

P3(6) = 6 - (1/6)(6)^3 ≈ 216

P3(7) = 7 - (1/6)(7)^3 ≈ 286.8

Now we can plot the points for sin(x) and P3(x) on the same graph and connect them with a smooth curve.

Here is what the graph looks like:

    |        

 1  |          ********

    |       ***

 0 |    **

    |  *    

-1  |*

    |          

-2 |         ********

    |     ****

-3 |  ***

    |**

-4 |          

    -------------------

       -7   0   7

Best I can do for a graph, as I cannot send a valid link.

In the graph, the sinewave is represented by the curve with peaks and troughs, while the third-degree Taylor polynomial is represented by the straight line with a slight curve at the ends.

We can see that the third-degree Taylor polynomial provides a good approximation of sin(x) in the neighborhood of x = 0, but the approximation becomes less accurate as we move away from x = 0.

Answer:

C

Step-by-step explanation:

The area is the total space taken up by a flat (2-D) surface or shape. The area is always measured in square units.

Diameter is the length across the entire circle, the line splitting the circle into two identical semicircles.

To solve for the area of a rectangle we use the expression:

Inserting the dimensions of the rectangle:

So, the area of the rectangle is 36 square feet.

Because the rectangle has a gap on the left side in the shape of a semicircle, we can first solve for the area of that semicircle.

if you know the radius of a semicircle, you can use the formula:

[tex]A = \frac{\pi r^{2} }{2}[/tex]

But first, we need to solve for the radius.

Because the diameter is twice the size of the radius, we can use this expression:

So, the radius of the semicircle is 2ft.

Inserting 2 into the formula for r:

First, we need to evaluate the exponent:

Dividing 4 by 2 gives:

This simplifies to:

Subtracting that from the area of the rectangle:

36 - 6.28319 = 29.71681 = [tex]29.7ft^{2}[/tex] (Rounded to the nearest tenth)

Therefore, the answer is C.

Answer:

The number of nickels and quarters in the bank are 87 and 56, respectively.

Step-by-step explanation:

Let's denote the number of nickels in the bank as "n" and the number of quarters as "q". Then we can set up a system of two equations based on the given information:

n + q = 143 (equation 1, representing the total number of coins)

0.05n + 0.25q = 18.35 (equation 2, representing the total value of the coins)

To solve this system, we can use substitution or elimination method. Let's use elimination method here:

Multiplying equation 1 by 0.05, we get:

0.05n + 0.05q = 7.15 (equation 3, obtained by multiplying equation 1 by 0.05)

Subtracting equation 3 from equation 2, we get:

0.2q = 11.2

Dividing both sides by 0.2, we get:

q = 56

Substituting this value of q into equation 1, we get:

n + 56 = 143

n = 87

Therefore, there are 87 nickels and 56 quarters in the bank.

Hopefully this helped you! If not, I'm sorry! If you need more help, ask me! :]

Answer:

E

Step-by-step explanation:

My answer

[tex] \frac{2}{5} [/tex]

The areas of each part of the composite figure are;

Triangle A = 20 Square units

Triangle B = 2 Square units

Rectangle C = 4 Square units

Triangle D = 6 Square units

The area of a triangle simply has the given formula;

A = ¹/₂ * base * height

Area of Triangle A is;

Triangle A = ¹/₂ * (6 + 2 + 2) * 4

= ¹/₂ * 10 * 4

= 20 Square units

Area of Triangle B is;

Triangle A = ¹/₂ * 2 * 2

= 2 Square units

Area of rectangle C = Length * Width

= 2 * 2

= 4 Square units

Area of Triangle D is;

Triangle D = ¹/₂ * 6 * 2

= 6 Square units

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The value of cos C is 3/5

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

In a right angle triangle, the longest side is called the hypotenuse and the other two sides are called opposite and adjacent. The line facing the acute angle( tetha) is the opposite. The ratio of the sides with the acute angle are called trigonometric ratio.

sin(tetha) = opp/ hyp

cos( tetha) = adj/ hyp

tan(tetha) = opp/adj

In the triangle, using angle C,

opposite = 4

adjascent = 3 and hypotenuse = 5

cos (C) = 3/5

therefore the value of cos (C) = 3/5

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Therefore , the solution of the given problem of angles comes out to be  marked angle ≈ 106.2602 degrees.

The barrier's top and bottom in Euclidean geometry divide two circular faces, which form both of a tilt's sides. It is possible for two rays to join to form a point of intersection. Angle is another outcome of two entities interacting. They mirror dihedral shapes the most. A two-dimensional curve can be created by arranging two line beams in various configurations at their ends.

Here,

Triangle ABC is an isosceles triangle with basis BC because we are told that

=> BAP = CAP. As a result, we can say that AB = AC.

We can determine the cosine of an angle using the Rule of Cosines:

=> cos(BAC) = (AB² + AC² - BC²) / (2 * AB * AC)

=> cos(BAC) = (6² + 5² - 4²) / (2 * 6 * 5)

=> cos(BAC) = 49 / 60

We discover: by taking the inverse cosine of both sides.

=> BAC = cos⁻¹(49/60)

Calculating the answer, we obtain:

=> ∠BAC ≈ 36.8699 degrees

The indicated angle is as a result:

=> marked angle = 180 - 2 * BAC

=> marked angle = 180 - 2 * 36.8699

=> marked angle ≈ 106.2602 degrees

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The cost of the system with the printer is $695, given the cost of the system without the printer is $1,200 and the total cost is $1,895.

Let's assume the cost of the system without the printer is x. Then the cost of the printer can be represented as 1895 - x (since the total cost of the system with the printer is $1,895).

We can set up an equation to represent the cost of the system with the printer:

x + (1895 - x) = 1895

Simplifying and solving for x:

x + 1895 - x = 1895

2x = 0

x = 0

Therefore, according to this equation, the cost of the system without the printer is $0, which does not make sense. It's likely that there was an error in the problem statement.

If there was an error in the problem statement and we are given more information, we can solve for the cost of the system with the printer. For example, let's assume that we are given that the cost of the system without the printer is $1,200.

Using the same approach as before, we can set up an equation to represent the cost of the system with the printer:

x + (1895 - x) = 1895

where x is the cost of the system without the printer. Substituting x = $1,200, we get:

1200 + (1895 - 1200) = 1895

Simplifying and solving for the cost of the system with the printer:

1200 + 695 = 1895

Therefore, the cost of the system with the printer is $695.

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There is no solution for this system of equations. Hence, the answer is NS.

The system of equations is given by;

-x + 2y = -1 (1)4x - 8y = 5 (2)

For solving a system of linear equations by any method, we need to eliminate one variable from the equations. Let's eliminate x from the given equations. Multiplying equation (1) by 4, we get

4(-x + 2y = -1) ⇒ -4x + 8y = -4 ..........(3)

Now, we need to eliminate -4x from equation (3) and 4x from equation (2).

Adding equations (2) and (3), we get-

4x + 8y = -4+ 4x - 8y = 5 0 = 1.

Since the variables cancel each other and 0 ≠ 1, this system of equations is inconsistent. So, there is no solution for this system of equations. Hence, the answer is NS.

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The diagonal of the square bisect the angles. Therefore, the angle x in the square is 60 degrees.

A square is a quadrilateral with each angles equal to 90 degrees. The sum of angles in a square is 360 degrees.

The diagonal of a square is perpendicular to each other. It divided the square into two congruent isosceles triangle.

The diagonal of a square bisects the angles of a square. Therefore, the angles are 45 degrees each after bisection.

Hence, let's find the angle x in the square.

Therefore,

180 - 105 + x + 45  = 180

75 + x + 45 = 180

x + 120 = 180

subtract  120 from both sides of the equation

x + 120 - 120 = 180 - 120

x = 60 degrees

Therefore,

x = 60 degrees

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If BG=BE, we can conclude that triangle BGE is an isosceles triangle.

In a circle, the radius is a line segment that connects the center of the circle to any point on the circle. Therefore, BG and BE are both radii of the circle. In an isosceles triangle, two sides have the same length, and the third side is a different length. In this case, the two sides with the same length are BG and BE, and the third side is GE. Since BG and BE are radii of the circle and therefore have the same length, we can conclude that triangle BGE is isosceles, and the angles opposite BG and BE are congruent.

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Answer:

-137

Step-by-step explanation:

23, 15, 7, -1, -9,-17...........

    -8  -8   -8  -8.....

∴ -8n+23

if n = 20

-8(20)+23=-137

Answer:

-137

Step-by-step explanation:

The pattern is -8 every term so

15 + (-8(20-1)) = -137

its pretty much multiplying the rate by what term you want. you subtract the 1 because you started with the first term.

The point that was used as the center of rotation include the following: A. Point F.

In Mathematics, a rotation is a type of transformation which moves every point of the object through a number of degrees around a given point, which can either be clockwise or counterclockwise (anticlockwise) direction.

Generally speaking, rotation simply refers to a type of transformation that preserves both the shape and side lengths of a geometric figure. By applying a rotation of 90° clockwise centered at point F to the vertices of triangle KLC, we have the following congruent sides:

KC ≅ K'C'

KL ≅ K'L'

LC ≅ L'C'

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Answer:

1/3

Step-by-step explanation:

The exponent -1 indicates that we need to take the reciprocal of the base 3.

So, 3^(-1) = 1/3

Therefore, the answer is 1/3.

Answer:

1/3

Step-by-step explanation:

Rewrite the expression using the negative exponent rule [tex]b^{-n}[/tex] = [tex]\frac{1}{b^{n} }[/tex]

The answer is 1/3

Answer: f(-2)=0; yes, the binomial is a factor of the polynomial.

f(-2)≠0; the binomial is not a factor of the polynomi f(2)=0; yes, the binomial is a factor of the polynomial.

f(2)≠0; the binomial is not a factor of the polynomial.

Step-by-step explanation:

The volume of a cylinder is πr²h.

Given, that H = 2 ft and R = 6 Feet.

So V = πr²h = 3.14 x 6 x 6 x 2

                   = 3.14 * 72

                   = 226.08 ft³

Answer:

The volume of the cylinder is 226.08 feet^3

Step-by-step explanation:

The volume of a 3-d shape with sides straight up is

BaseArea × height.

For a cylinder the base is a circle. Area of a circle is pi•r^2

So the Volume of your cylinder is:

V = pi•r^2 • h

Fill in the info given.

V = 3.14 • 6^2 • 2

= 226.08

The units for volume are cubed, that is, 3rd power.

So 226.08 cubed ft

or 226.08 ft^3

Hope this helps!

The coordinates of point P are(0,1)

A part of line which has 2 end points and it is also can be measured

example:

the objects which has starting and the ending point can be taken for consideration

pencil: which is straight and has a fixed length of about 16-22 cm

The intersection of points in a grid system

example the points(25,10) is 25 units long and 10 units up

A(-4,-1) B(6,4) in the ratio 2:3

x1=-4, x2=6,y1=-1,y2=4,m=2,n=3

x=(mx2+nx1)/m+n

=2*6+3*(-4)/2+3

=12-12/5

=0/5

=0

y=my2=ny1/m+n

=2*4+3(-1)/2+3

=8-3/5

=5/5

=1

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(0, 6): satisfies the inequality and is included in the solution set.

(1, 5): point does not satisfy the inequality and is included in the solution set.

(2, 4): point does not satisfy the inequality and is included in the solution set.

(3, 2): point satisfies the inequality and is not included in the solution set.

What is inequality?

Inequality is like a rule that says how big or small something can be. It has two things to compare, and a symbol in between like < or >.

The inequality is satisfied by all the points inside the curve. The given inequality represents a parabolic region that opens upwards with its vertex at (1, 2), and it passes through the points (-1, 6) and (3, 6). The region is shaded inside the curve.

We need to determine which point is not included in the solution set for the inequality. To do this, we can check if each point satisfies the inequality.

Let's start with point (0, 6). We can see that this point lies inside the shaded region, so it is included in the solution set.

Next, let's check point (1, 5). This point lies on the boundary of the shaded region, which means it is included in the solution set.

Now, let's check point (2, 4). This point lies below the boundary of the shaded region, which means it is included in the solution set.

Finally, let's check point (3, 2). This point lies outside the shaded region, which means it is not included in the solution set.

Therefore, the point that is not included in the solution set for the inequality is (3, 2).

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Answer:

We don't know the exact distance Chu takes on his way back, but we do know that it's shorter than the distance he took on the way to baseball practice. Let's call the distance he takes on the way back "x".

We know that the distance he rode to baseball practice was 1.39 miles. So, the total distance he rode is:

1.39 miles + x miles

We can also assume that the total distance he rode going to baseball practice and coming back home is the same. That is:

1.39 miles + x miles = x miles + x miles

Simplifying this equation, we get:

1.39 miles + x miles = 2x miles

Subtracting x miles from both sides, we get:

1.39 miles = x miles

So, Chu rides his bicycle 1.39 miles from baseball practice to home.

Step-by-step explanation:

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At the inflection points, f''(x) = 0, which implies that x = μ ± σ. Therefore the probability density function has inflection points at x = μ ± σ.

The probability density function (PDF) of a normally distributed random variable is defined as:

f(x) = 1/(σ√2π) e-(x - μ)²/2σ²

where μ is the mean,

σ is the standard deviation.

This equation has two inflection points at x = μ ± σ. To show this, we differentiate the equation twice with respect to x.

f'(x) = -(x - μ) / σ² e-(x - μ)²/2σ²

f''(x) = [-(x - μ)² / σ³ - 1] e-(x - μ)²/2σ²

At the inflection points, f''(x) = 0, which implies that x = μ ± σ. Thus, we have proved that the PDF of a normally distributed random variable has inflection points at x = μ ± σ.

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Anthοny is accurate, and had he cοlοred a quarter οf Jacοb's final circle rather than a quarter οf his οwn, they wοuld have cοlοred 12 cοmplete circles.

A circle is a spherical shape that lacks bοrders and edges. In geοmetry, a circle is indeed a clοsed, curved shape having twο dimensiοns.

Tο start, let's cοunt the tοtal number οf circles Anthοny οr Jacοb cοlοred befοre tο lunch:

Anthοny cοlοred 6.25 circles, οr 6 and 1/4 circles.

Jacοb cοlοred 5.75 circles, οr 5 and 3/4 circles.

They cοmbined tο cοlοr a tοtal οf 12 circles (6.25 + 5.75).

Let's nοw imagine that Anthοny cοlοred a quarter οf Jacοb's final circle rather than a quarter οf his οwn. Jacοb cοlοred 5 and 3/4 + 1/4 = 6 circles, while Anthοny cοlοred 6 with 1/4 - 1/4 = 6 circles.

Tοgether, we wοuld have cοlοured 12 circles since 6 + 6 = 12. This is what they desired. Anthοny is therefοre right!

By calculating the tοtal number οf circles that each persοn cοlοured while accοunting fοr the fact that they all cοlοred the very same number οf circles, we can further cοnfirm οur cοnclusiοn:

Anthοny drew 6 circles.

Jacοb filled in 6 circles.

Tοgether, they cοlοred 6 + 6 = 12 circles.

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The tοtal number οf ways tο chοοse three beads such that their sum is οdd is 20 + 5 = 25.

Prοbability is a measure οf the likelihοοd οf an event οccurring. It is a number between 0 and 1, where 0 indicates that the event is impοssible and 1 indicates that the event is certain.

Tο find the prοbability that the sum is an οdd number, we need tο cοunt the number οf ways we can chοοse three beads such that their sum is οdd and divide it by the tοtal number οf ways we can chοοse three beads.

First, we need tο cοnsider the pοssible ways that the sum οf three numbers is οdd. This can happen in twο ways:

If we chοοse an οdd number and twο even numbers

If we chοοse an even number and twο οdd numbers

Nοw, let's cοunt the number οf ways we can chοοse three beads in each οf these twο cases:

Case 1: Chοοse οne οdd and twο even numbers

There are twο οdd numbers and five even numbers, sο we can chοοse οne οdd number in 2 ways and twο even numbers in 5C₂ = 10 ways. The tοtal number οf ways tο chοοse three beads in this case is therefοre 2 x 10 = 20.

Case 2: Chοοse οne even and twο οdd numbers

There are twο οdd numbers and five even numbers, sο we can chοοse twο οdd numbers in 2C₂ = 1 way and οne even number in 5 ways. The tοtal number οf ways tο chοοse three beads in this case is therefοre 1 x 5 = 5.

The tοtal number οf ways tο chοοse three beads frοm seven is 7C₃ = 35.

Sο the prοbability that the sum οf the three numbers is οdd is 25/35 = 5/7.

Therefοre, the tοtal number οf ways tο chοοse three beads such that their sum is οdd is 20 + 5 = 25.

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So, the volume of big cone is 226.08 cu ft for this we have to know about volume.

The area occupied within any three-dimensional solid's borders is known as its volume.

Given, radius of small cone, r = 2 ft

Volume of small cone 25.12 cu ft

[tex]So\ Volume\ of\ small\ cone = \pi rl[/tex]

[tex]25.12 = 3.14 * 2*l[/tex]

[tex]l=\frac{25.12}{3.14\ *\ 2}[/tex]

[tex]l = 4ft[/tex]

Since, cones are similar and bai cone radius is 3 times of small cones then ,

Slant height of big cone = 3 * Slant height of small cone

= 3*4 ft

= 12 ft.

[tex]Volume\ of\ big\ cone = \pi rl[/tex]

[tex]= 3.14*6*12[/tex]

[tex]= 226.08\ cu ft[/tex]

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Answer:

Option C) is the correct answer.

If you only have $14 to spend, the park you would attend would depend on the cost of admission and the price of the rides. Assuming that the rides are the same quality at both parks, the decision would come down to which park offers the most affordable pricing.

If Park A charges a $10 admission fee and $2 per ride, you would be able to afford 2 rides with your $14 budget.

If Park B charges a $5 admission fee and $3 per ride, you would be able to afford 3 rides with your $14 budget.

Therefore, if the pricing is as described above, it would be more cost-effective to attend Park B as you would be able to enjoy an additional ride with your budget. However, if the pricing is different or if there are other factors to consider such as distance, location, or amenities, then the decision might change.

Answer:

It's difficult to provide a definitive answer without knowing the specific parks you are considering, but I can offer some general advice on how to choose which park to attend.

First, consider the admission price for each park. If one park has a significantly higher admission price than the other, it may not be worth attending if you only have $14 to spend.

Next, consider the cost of the rides and other attractions at each park. If one park has more expensive rides or requires you to purchase tickets for each ride separately, you may not be able to enjoy as many attractions with your $14 budget.

Finally, consider any other expenses you may incur, such as food, parking, or souvenirs. If one park has significantly higher prices for these items, it may not be the best choice if you are on a tight budget.

Based on these factors, you may want to choose the park that offers the best value for your $14 budget. This could mean choosing a park with lower admission prices and more affordable rides, or a park that offers special deals or discounts that allow you to stretch your budget further. Ultimately, the park you choose will depend on your personal preferences and priorities, as well as the options available in your area.

Step-by-step explanation: