I am completely braindead on how to calculate the time first.

A flowerpot falls from a window sill 31.3m from a sidewalk. What is the velocity of the flowerpot when it hits the ground? (hint: Use d=1/2at^2 to find "t" first, then find velocity using v=at. Remember, ay= -9.8 m/s2).

Answers

Answer 1

24.8 m/s

Explanation:

You don't have to solve for time first. You can use the equation below to solve for the velocity before impact:

[tex]v_y^2 = v_{0y}^2 + 2a_yy[/tex]

We know that [tex]v_{0y} = 0[/tex] so the equation above becomes

[tex]v_y^2 = 2a_yy \Rightarrow v_y = \sqrt{-2a_yy}[/tex]

Plugging in the numbers, we get

[tex]v_y = \sqrt{-2(-9.8\:\text{m/s}^2)(31.3\:\text{m})}[/tex]

[tex]\:\:\:\:\:=24.8\:\text{m/s}[/tex]

METHOD 2:

If you insist on using that equation for d, we can do that too. So solving for t from the equation for d. we get

[tex]t = \sqrt{\dfrac{2d}{g}} = \sqrt{\dfrac{2(31.3\:\text{m})}{9.8\:\text{m/s}^2}}[/tex]

[tex]\:\:\:\:= 2.53\:\text{s}[/tex]

So using the equation [tex]v_y = gt,[/tex] we get

[tex]v_y = (9.8\:\text{m/s}^2)(2.53\:\text{s}) = 24.8\:\text{m/s}[/tex]

So you get the same result regardless of the method you use.


Related Questions

• An artery in a certain patient has been reduced to half its original inner diameter by bad cholesterol deposits on the inner artery wall. By what factor will the blood flow through the artery be reduced if the pressure differential across the artery has remained unchanged? (a) 0.065 (b) 0.625 (c) 0.622 (d) 0.0625 ​

Answers

Answer:

C.

Hope it's helpful

brainlest and follow me thank you

1. A 6-volt battery produces a current of 0.5 amps. What is the power in the circuit?

Answers

Answer:

hope this will help you

have a great day

Explanation:

please mark me as the brainliest

!!! , ? ? ? (no silly answers please).

Answers

Answer:

hellooo

Explanation:

i think ummm

. . .

…,,,???!!! I am confused. What?

Which area of study involves how mechanics and motion affect sports performance?
1.) Momentum. 2.) Velocity. 3.) Biomechanics. 4. )Centripetal force.

Answers

Answer:

biomechanics

Explanation:

Biomechanics is part of the larger field of kinesiology, specifically focusing on the mechanics of the movement. 1 It is both a basic and applied science, encompassing research and practical use of its findings.

PLEASE HELP ASAPPPPPPPPPPPPPPPPPPP

Answers

Answer:

Basketball

Explanation:

Im asuming basketball because a basketball has the least movement out of the rest of the answers.

In the free-body diagram, the magnitude of the normal force is 40 N, the friction force is
25N, the net force is 80N: What is the magnitude of the applied force?

Answers

Answer:

Explanation:

F = 80 + 25 = 105 N

David was driving at a velocity of 5 m/s. He accelerates to a velocity of 8 m/s in 4 seconds. What is the acceleration?

Identify the given variables and the unknown
x distance


t time


Vi initial velocity


Vf final velocity


a acceleration


F force

Answers

If David was driving at a velocity of 5 m/s and accelerates to a velocity of 8 m/s in 4 seconds, David's acceleration is 0.75 [tex]m/s^2[/tex].

Given the following data:

Initial velocity, Vi = 5 m/sFinal velocity, Vf = 8 m/sTime, t = 4 seconds.

To find David's acceleration:

Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]Acceleration = \frac{V_f\; - \;V_i}{t}[/tex]

Where:

Vf is the final velocity.Vi is the initial velocity.t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]Acceleration = \frac{8\; - \;5}{4}\\\\Acceleration = \frac{3}{4}[/tex]

Acceleration = 0.75 [tex]m/s^2[/tex].

Therefore, the David's acceleration is 0.75 [tex]m/s^2[/tex].

Read more: https://brainly.com/question/8898885

A ball is thrown at a speed of 40m/s. If the ball has a mass of 0.33kg, what is the ball’s momentum?

Answers

Answer:63745.6573

Explanation:

The mass of an object is 100mg. What is the object's mass in kg? Show your work

Answers

Answer:

0.0001 kg

Explanation:

The weight in Kilograms is equal to the milligrams divided by 1,000,000.

100 ÷ 1,000,000

31) what is the energy required to change 20g of copper, whose specific heat is 0.39j/gc,
change from 20 to 40 degrees?

Answers

Explanation:

given :

m = 20 g

sh = 0.39 J/g°C

∆T = 40-20 = 20°C

Find the Energy!

solution :

E =m. sh. ∆T

= 20 × 0.39 × 20

= 156 J

♪Answer : mass = 20g sh = 0.39j/g°c∆T = 40° - 20° = 20°

So, energy required is

Energy = mass*sh*∆T

Energy = 20g*0.39j/g°c*20°

Energy = 156joule

~Physics#1

A plane moves 599 m northeast along a runway.
If the northern component of this displacement
is 89 m, how large is the eastern component?

Answers

The eastern component of the plane's displacement is 592.35 m.

The given parameters;

the resultant of the plane displacement = 599 mthe northern component of this displacement, Y = 89 mLet the eastern component of this displacement = X

The eastern component of the plane's displacement is calculated by applying Pythagoras theorem as follows;

X²  + Y² = 599²

X² + 89² = 599²

X² = 599²  - 89²

X² = 350880

X = √350880

X = 592.35 m

Thus, the eastern component of the plane's displacement is 592.35 m

Learn more here:https://brainly.com/question/17033407

On a hike you walk 5000 m east, 3000 m north and 1000 m west at a constant speed of 1m/s calculate your velocity

Answers

Answer:

0.44 EST + 0.33 NTH

Explanation:

if this is incorrect and brainly removes the comments to try and sabotage you guys please report this for the sake of learning

The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.

Answers

The frequency of rotation of Mars is 0.0000113 Hertz.

Given the following data:

Period = 1 day and 37 minutes.

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

Conversion:

1 day = 24 hours

24 hours to minutes = [tex]60[/tex] × [tex]24[/tex] = [tex]1440[/tex] minutes

[tex]1440 + 37 = 1477 \; minutes[/tex]

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

[tex]X = 60[/tex] × [tex]1477[/tex]

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

[tex]Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}[/tex]

Frequency of rotation = 0.0000113 Hertz

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

Read more: https://brainly.com/question/14708169

If the ambient temp. is 75 F, what is it Centigrade?

Answers

Explanation:

We know

C/5 = F -32/9C/5 = 75 -32/9C/5 = 43/9C ≈ 25°C

help me besties ok thx

Answers

Answer:

[tex]1 \\ 0.5 \times 500 \times 20 \times 20 \\ \ 2 \\ 0.5 \times 0.6 \times 100 \times 100 \\ 3 \\ 1000 \times 0.5 \times 10 \times 10 \\ 1000 \times 0.5 \times 20 \times 20 \\ 1000 \times 0.5 \times 30 \times 30 \\ 4 \\ 0.5 \times 40000 \times 30 \times 30 \\ 5 \\ \sqrt{ \frac{2}{0.1 \times 0.5} } [/tex]

What is the acceleration of a car that maintains a constant velocity of 24 m/s for 10 seconds?

a.
24 m/s2

b.
240 m/s2

c.
2.4 m/s2

d.
0 m/s2

Answers

djdjdjdjdjdjdjdjd ddsdds

answer the question below

Answers

First one is 1. The second one is 3 and the third one is 2

Answer:

1. Shield volcano

Runny,basaltic magma with low silica and low gas content. Has a broad,low profile.

2. Cinder cone volcano

Thick viscosity andesitic magma with high silica content and high gas content. Rapidly solidifying lava forms high,steep-sided cones.

3. Composite volcano

Medium viscosity rhyolitic magma with medium silicon content and medium gas content.Have flatter domes called cones.

Explanation:

Hope it helps you..

Your welcome in advance..(◍•ᴗ•◍)

draw the diagram of third class lever showing fulcrum, effort and load​

Answers

Answer:

In a third class lever, the effort is located between the load and the fulcrum. If the fulcrum is closer to the load, then less effort is needed to move the load. If the fulcrum is closer to the effort, then the load will move a greater distance. ... These levers are useful for making precise movements.

Would you expect the spectrum of a blackbody radiator to have peaks and valleys like the spectrum of WF4-358? Why or why not? Define blackbody radiators in your answer.

Answers

The Planck model for the black body and the emission spectrum of the atoms allows to find the results for the peaks in the spectrum of stars is:

The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.

The stars are very hot celestial bodies by nuclear fusion processes, in a good approximation they approximate an ideal body that absorbs or emits all the radiation called black body.

A black body is a cavity in thermal equilibrium at a dated temperature with a small hole, this hole is the so-called black body and its emission spectrum was explained by Planck, with the assumption that the energy is

             E = h νν

Where h is Planck's constant and ν is the frequency of the radiation. In the attachment we see the emission spectrum of a black body for various temperatures.

If in the material under study we have in addition the emission characteristics of some elements, it is energy appears as peaks in the emission spectrum and as black bands o valley in an absorption spectrum, therefore the existence of the structure is in a test of the existence of chemical elements within the stars.

In the attachment we can see the spectrum of a dwarf star where we can appreciate the spectrum of the black body and the emission and absorption lines of the chemical elements inside the star.

In conclusion using the Planck model for the black body and the emission spectra of the atoms we can find the results for the peaks in the spectrum of stars is:

The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.

Learn more here: https://brainly.com/question/16229821

How strong is a neutron star's gravity.

Answers

Answer:

About a thousand billion times! Because neutron stars are so dense, they have intense gravitational and magnetic fields. The gravity of a neutron star is about a thousand billion times stronger than that of the Earth. Thus the surface of a neutron star is exceedingly smooth; gravity does not permit anything tall to exist.

It's crazy strong.

What are the similarities between coral reefs and costal ecosystems

Answers

Answer:

A coral reef is an underwater ecosystem characterized by reef-building corals. Reefs are formed of colonies of coral polyps held together by calcium carbonate. ... Unlike sea anemones, corals secrete hard carbonate exoskeletons that support and protect the coral.

Coastal oceans are commonly defined as the areas from the shoreline to the outer edge of the continental margin. They connect the continents to the open ocean and serve as a link for transporting organic and inorganic, natural and anthropogenic material from land to sea.

Coastal oceans in tropical areas have similar characteristics to their temperate counterparts. ... Coral reefs are biologically diverse and rich habitats that occur in relatively nutrient-poor environments along coastlines. Areas that have too many nutrients often harbor too much algal growth to sustain coral growth.,

Explanation:

In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively charged particle that moves from A to B along path 1 is W1.

How much work is done on this particle if it later goes from A to B along path 2? Express your answer in terms of W1.

W2=??​

Answers

Answer:

W2 = W1

Explanation:

work is independent of the path taken between the points.

Which statement best explains how a planet affects the orbit of a comet as the comet passes by the planet?

Answers

Comets orbit the sun just like planets do. Except a comet usually has a very elongated orbit. Thanks to the laws of gravity comets obey the same laws. A comets orbit takes it very close to the sun and then far away again.

what is the force the when does when Gravity pushes you​

Answers

Answer:

Image result for what is the force the when does when Gravity pushes you​

The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.

Explanation:

Image result for what is the force the when does when Gravity pushes you​

The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.

Answer:

It is called gravitational force.

Explanation:

[tex]{ \boxed{ \rm{F = \frac{GM_{a} m _{a}}{ {r}^{2} } }}}[/tex]

F is the gravitational forceMa is the mass of a planetary bodyma is mass lf body being attractedr is the separation distanceG is the universal gravitational constant

→ Assume you are in space and you have a mass of ma, and you are r metres from the Earth of mass Ma. The force F will be experienced and you will tend to be pulled towards the Earth when you are in its gravitational field.

pleease help me please!!!​

Answers

Answer:

4 filter funnel 7 round bottom flask sorry but that is all I know

A golf ball is hit with an initial velocity of 20m/s at an angle of 30° to the horizontal. calculate;

the time of flight​

Answers

Answer:

tcucugxojfjgfojcigxuogoudyifodtufukdutfuocyjxuogu

What is the Normal CSF for:

Leukocytes (per mm³)

% Neutrohils

Glucose (mg/dL)

Protein (mg/dL)

Please provide source if possible.

Answers

1. 5 WBC's per cubic millimeter.

3. 50 to 80 mg/100 mL

4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)

If a test were to be performed here are normal results:

Normal values typically range as follows:

Pressure: 70 to 180 mm H2O

Appearance: clear, colorless

CSF total protein: 15 to 60 mg/100 mL

Gamma globulin: 3% to 12% of the total protein

CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)

CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells

Chloride: 110 to 125 mEq/L

(Source: https://medlineplus.gov/ency/article/003428.htm)

a stone is dropped down an empty mine shaft. it takes 3 seconds to reach the bottom. assuming that the stone falls from rest and accelerates at 10m/s^2, calculate.
a) the maximum speed reached by the stone before hitting the bottom.
b) the average speed of the stone in flight.
c) the depth of the mine shaft.

Answers

Answer:

I think A. I had a similar question

Explanation:

in loading a long lorry a man lifts boxes each of weight 100N and height of 1.5M.how much energy is transfered when one box is lifted​

Answers

Explanation:

energy=100×1.5=150 joules

Select the correct answer.
What does the expression “75 meters per second southeast” best describe?
A.
acceleration
B.
distance
C.
speed
D.
velocity

Answers

Answer:

my answer would be A I'm not sure about that

Answer: The answer would be D. Velocity

Explanation: Velocity is measured in meters per second.

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