Answer:
by rotating the filter
Explanation:
Rayleigh's scattering is given by the process of the scattering of light by molecules. This is very important physical phenomenon. Polarization is also an effect of light scattering.
A photographer wishes to capture photos of some cloud formation by using the polarizing filter. So the photographer will have to rotate the polarizing filter until the intensity of the light becomes maximum such that the light polarization is acts along the axis of the filter.
A steam catapult applies a very large force to supplement the engine thrust of a jet fighter as it takes off from an
aircraft carrier. The jet has a mass of 4000 kg and must reach its take off speed of 70 m/s at the end of the 220
m flight deck. What is the combined force of the catapult and engines? (Use the work-energy theorem)
Answer:
The combined force of the catapult and engines is 44545.455 newtons.
Explanation:
Let suppose that platform of the aircraft carrier is horizontal, such that changes in gravitational potential energy can be neglected. In addition, effects of non-conservative forces are neglected. By using Principle of Energy Conservation and Work-Energy Theorem we find that steam catapult-jet aircraft is represented by:
[tex]K_{1}+W_{1\rightarrow 2} = K_{2}[/tex] (1)
Where:
[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final translational kinetic energies of the jet fighter, measured in joules.
[tex]W_{1\rightarrow 2}[/tex] - Work done on the jet fighter due to the combined force of the catapult and engines, measured in joules.
By applying definitions of translational kinetic energy and work, we expand and simplify the equation above as follows:
[tex]F\cdot \Delta s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex]
[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot \Delta s}[/tex] (2)
Where:
[tex]F[/tex] - Combined force of the catapult and engines, measured in newtons.
[tex]m[/tex] - Mass of the jet fighter, measured in kilograms.
[tex]\Delta s[/tex] - Length of the catapult, measured in meters.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the jet aircraft, measured in meters per second.
If we know that [tex]m = 4000\,kg[/tex], [tex]v_{1} = 0\,\frac{m}{s}[/tex], [tex]v_{2} = 70\,\frac{m}{s}[/tex] and [tex]\Delta s = 220\,m[/tex], then the combined force of the catapult and engines is:
[tex]F = \frac{(4000\,kg)\cdot \left[\left(70\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (220\,m)}[/tex]
[tex]F = 44545.455\,N[/tex]
The combined force of the catapult and engines is 44545.455 newtons.
The combined force of the catapult and engines is 44,545.5 N.
The given parameters;
mass of the jet, = 4000 kgspeed of the jet, v = 70 m/slength of the deck, d = 220 mThe combined force of the catapult and engines is determined by applying work energy theorem as shown below;
[tex]W = \Delta E\\\\Fd = \frac{1}{2}m(v^2 -u^2) \\\\220F = \frac{1}{2}(4000)(70^2 - 0^2) \ \\\\220 F = 9,800,000\\\\F = \frac{9,800,000}{220} \\\\F = 44,545.5 \ N[/tex]
Thus, the combined force of the catapult and engines is 44,545.5 N.
Learn more here:https://brainly.com/question/10063455
Based on the measured force between objects that are 10 meters apart, how can you find the force between objects that are any distance apart ?
Answer:
F' = 100 F/r²
Explanation:
The gravitational force of attraction between two objects is given by the Newton's Gravitational Formula. The Newton's Gravitational Formula is as follows:
F = Gm₁m₂/r²
where,
F = Force between objects
G = Universal Gravitational Constant
m₁ = mass of first object
m₂ = mass of second object
r = distance between objects = 10 m
Therefore,
F = Gm₁m₂/10²
Gm₁m₂ = 100F --------------------- equation (1)
Now, we consider these objects at any distance r apart. So, the force becomes:
F' = Gm₁m₂/r²
using equation (1), we get:
F' = 100 F/r²
So, if the force (F) between objects 10 m apart is known, we can find it at any distance from the above formula.
The force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
According to the gravitational law, the force acting on an object is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Mathematically,
[tex]P=\frac{GMm}{r^2}[/tex]
M and m are the masses
r is the distance between the masses
If the force between objects that are 10 meters apart, hence;
[tex]P=\frac{GMm}{10^2}\\P=\frac{GMm}{100}\\GMm = 100P[/tex]
To find the force between objects that are any distance apart, we will use the same formula above to have;
[tex]P'=\frac{GMm}{r^2}\\[/tex]
Substitute the result above into the expression to have:
[tex]P'=\frac{100P}{r^2}[/tex]
Hence the force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
Learn more on gravitational law here: https://brainly.com/question/11760568
Which describes an image that a concave mirror can make?
A. The image is always virtual.
B. The image can be either virtual or real.
C. The image is never upside down.
D. The image can only be the same size as the object.
Answer:
A
Explanation:
The image formed by the concave mirror is always virtual. An enlarged image is caused when the concave mirror is positioned too near to the object.
What is a concave mirror?When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.
A concave mirror is a name for this sort of mirror. An enlarged and fake image is caused when the concave mirror is positioned too near to the object.
When the distance between the item and the mirror is increased, however, the size of the image decreases, and a true picture is generated.
The picture created by the concave mirror may be manipulated. The image formed by the concave mirror is always virtual.
Hence, option A is correct.
To learn more about the concave mirror, refer to the link;
https://brainly.com/question/25937699
#SPJ2
1500 POINTS TO WHOEVER ANSWERS THIS FIRST!!!!!!!!!!
1. You drop a bowling ball 15m from the top of the science building. What is its
velocity as it impacts the ground?
2. A cheetah accelerates from 0 to 13m/s in 3 seconds. How far does it travel
during that time?
3. Your foolish friend shoots a bullet straight in the air at a muzzle velocity of
380 m/s. How high does the bullet go (neglecting air resistance)?
4. Your foolish friend shoots a bullet straight in the air at a muzzle velocity of
380 m/s. What is the bullets velocity when it falls back down and hits your
friend?
Answer: Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.
Explanation:
Help !! I hate science
Answer:
iron nail rusting
Explanation:
things that affects the demand for electricity
Which of the following is NOT a correct statement?*
As the volume of a contained gas increases, the pressure in the container will
decrease.
As the temperature decreases, the kinetic energy of the particles decreases.
As pressure increases with a constant temperature, the volume decreases.
O As temperature increases, the kinetic energy of the particles decreases.
AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:
Explanation:
If the torque required to loosen a nut on a wheel has a magnitude of 40.0 N·m and the force exerted by a mechanic is 133 N, how far from the nut must the mechanic apply the force?
Question 7 options:
1.) 0.15 m
2.) 0.6 m
3.) 0.3 m
4.) 1.2 m
Answer:
3.) 0.3 m
Explanation:
Given parameters:
Torque = 40Nm
Force = 133N
Unknown:
Distance from the nut that the mechanic must apply the force = ?
Solution:
Torque is the force that causes an object to rotate on its axis;
Torque = force x distance
Distance = [tex]\frac{40}{133}[/tex] = 0.3m
What type of numbers in a measurement are always significant?
Answer:
Non-zero digits
Explanation:
umm (ꏿ﹏ꏿ;)
Answer:
There's three rules on determining how many important quantities are in a number: Non-zero digits are always predominant. Any zeros between two significant digits are always major. The final zero or dangling zeros in the decimal segment are really only important.
I hope this answered your question, have a nice day!
a. A remote-control car with a constant velocity drives off the top of a wall that is 10.0 m high and lands 4.60 m from the base of the wall. Draw a diagram of the problem. Label the known and unknown quantities. b. What is the car's speed before it drives off the top of the wall? c. What is the car's vertical speed just before impact? d. How far from the base of the wall would the remote-control car have landed if it had been subject to the gravitational field on the Moon (1.7 N/kg) ?
Answer:
a. Please see the attached graph and drawing combined created with Microsoft Excel
b. Approximately 3.2217 m/s
c. Approximately 14.0 m/s
d. Approximately 11.05 meters
Explanation:
a. The given parameters are;
The height of the wall, h = 10.0 m
The distance from the base of the wall the car lands = 4.60 m
The time, t, it takes the car to land is given by the equation for free fall as follows;
h = 1/2·g·t²
Where;
g = The acceleration due to gravity = 9.81 m/s²
From the equation for free fall, we have;
h/(1/2·g) = t²
∴ t = √(h/(1/2·g) ) = √(10/(1/2·9.81) ) ≈ 1.4278
The time it takes the car to land, t ≈ 1.4278 seconds
b. The horizontal speed of the car = Horizontal distance/(Time) = 4.6/1.4278 ≈ 3.2217 m/s
The horizontal speed of the car before it drives off the wall ≈ 3.2217 m/s
c. The car's vertical speed just before impact is given by the following equation;
v = u + gt
Where;
u = The initial vertical speed = 0
t = The time it takes before impact ≈ 1.4278 seconds
∴ v = 9.81 × 1.4278 ≈ 14.0 m/s
The car's vertical speed just before impact, v ≈ 14.0 m/s
d. Whereby the car is subject to the gravitational field of the moon, we have;
Gravitational force per kilogram = 1.7 N/kg
∴ Gravitational acceleration = 1.7 m/s².
The time it takes the car to land whilst subject to the gravitational field of the moon is therefore;
[tex]t_{Moon}[/tex] = √(h/(1/2·g)) = √(10/(1/2 × 1.7)) ≈ 3.43
[tex]t_{Moon}[/tex] ≈ 3.43 seconds
The horizontal distance covered, at the car's horizontal speed in the time of free fall ≈ 3.2217 m/s × 3.43 seconds ≈ 11.05 meters
The horizontal distance covered, at the car's horizontal speed in the time of free fall = The distance the car will land from the base of the wall ≈ 11.05 meters
The distance the car will land from the base of the wall ≈ 11.05 meters.
if two objects masses 8kg and 24 kg are dropped from top of a building. Which one reaches the ground first
pls answer this
quick as possible
Answer:
The answer is the 4th one
Explanation:
Good luck man
What question did use of a telescope by hubble answer A) Is earth the center of the universe B) Is the sun the center of the universe C) How do the planets move in the solar system D) Are there more galaxies beyond the milky way
Answer: C
Explanation:
The characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helps to answer is:
D) Are there more galaxies beyond the milky way
Telescopes are instruments that can perceive very small amounts of light and have very large magnifications, in general to be able to see objects increasingly weak in intensity, telescopes become larger and the observation times of the object increase.
When we increase the observation times, the problem is that atmospheric movement changes the observation conditions and makes it difficult to obtain good images. One way to solve the problem was with telescopes in near space, the environmental disturbance is eliminated.
When the Hubble telescope was placed in space, there were already many answers but they continue to wonder what the limit of the universe is, this telescope allowed us to observe a body much farther away than ground-based telescopes, which is why it answered the question how many and to where there are galaxies out of the milky way.
Let's review the statements given to see the correct ones;
A) False. Copernicus clarified that the Sun is the center of the solar system
B) False. The center of the universe is not known, but the sun is a star in one of the arms of the milky way that is not the center of the universe either.
C) False. It has been known for a century what the movement of the planets in the solar system
D) True. The telescope in space allowed us to expand the limit of vision of the universe and respond to where there are galaxies outside the Milky Way.
In conclusion with the characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helped to answer is:
D) Are there more galaxies beyond the milky way
Learn more here: brainly.com/question/16319804
Light travels fastest through which of the following?
A.
air
B.
glass
C.
vacuum
D.
water
What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.
We are given:
Mass of the Paint bucket (with paint) = 7000 grams
Mass of the paint bucket (without paint) = 500 grams
Volume of Paint in the Bucket = 5000 cm³
Mass of Paint in the Bucket:
To get the mass of the paint in the bucket, we will subtract the mass of the bucket from the mass of the paint bucket (with paint)
Mass of Paint = Mass of Paint bucket (with paint) - Mass of the paint Bucket (without paint)
Mass of Paint = 7000 - 500
Mass of Paint = 6500 grams
Density of the Paint:
We know that density = Mass / Volume
Density of Paint = Mass of Paint / Volume occupied by Paint
Density of Paint = 6500/5000
Density of Paint = 1.3 grams / cm³
In general, how do you find the average velocity of any object falling in a vacuum?
The measurement of length and time is calculated the average speed with the expression
[tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]
Average velocity is defined as the change in displacement between the interval time
[tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]
where [tex]v_{avg}[/tex] is the average velocity, Δx is the displacement in the interval, and Δt the time.
To carry out this measurement, it must be taken into account that the velocity is a vector, for which we define a reference system, it can be a vertical axis with the upward direction as positive, therefore the downward displacement is negative.
A tape measure is placed and the interval during which the scalar distance measurement is performed is defined, the most as is to use time as an independent variable (controlled by the researcher) that is measured with a stopwatch.
The displacement is measured for each given time interval and these two quantities are divided. The sign of the velocity is negative because it goes down
Using the measurements of length and time, the average velocity is calculated with the expression
[tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]t
learn more about average speed here: brainly.com/question/17277454
Moderate injuries are generally __________.
A.
life-threatening
B.
soft tissue injuries
C.
bumps and bruises
D.
too serious for first aid
Please select the best answer from the choices provided.
A
B
C
D
Answer:
B. soft tissue injuries
Explanation:
i took the test on edge and its really the only one that would make sense if you payed attention to the lesson :)
a golf ball with a velocity 40 at an angle 45 degree speed of bthe ball after 2 sec
Answer:
Vertical velocity = 8.28 m/s
Horizontal velocity = 28.3 m/s
__________________________________________________________
We are Given:
Initial velocity of the ball = 40 m/s
Angle of elevation of the ball = 45°
Time interval = 2 seconds
__________________________________________________________
Vertical and Horizontal Components:
Vertical Component:
The vertical component of the ball can also be written as:
40*Sin(45°)
40*(1/√2) [since Sin(45°) = 1/√2]
40/√2 m/s
Horizontal Component:
The horizontal component of the ball can also be written as:
40*Cos(45°)
40*(1/√2) [Since Cos(45°) = 1/√2]
40/√2 m/s
__________________________________________________________
Speed of the Ball after 2 seconds:
Horizontal Velocity:
Since the horizontal velocity is not affected by any force during the flight, the horizontal velocity after 2 seconds will also be 40/√2 m/s
Since √2 = 1.41:
Horizontal velocity = 28.3 m/s
Vertical Velocity:
v = u + at [First equation of motion]
v = 40/√2 + (-10)(2)
[g is negative because it is acting against the direction of motion]
v = 40/√2 - 20
v = [tex]\frac{40-20\sqrt{2} }{\sqrt{2} }[/tex] [taking the LCM]
v = 8.28 m/s [√2 = 1.41]
HELP PLEASE I need to finish this asap
Answer:
I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.
Explanation:
pls vote brainliest
Why must the difference between the water level in the eudiometer tube and the water level in the beaker be measured
Answer:
Explanation:
The difference between the water level in the eudiometer tube and the water level in the beaker must be measured because we have to put into consideration, the pressure of the gases in the eudiometer tube. This said pressure of gas in the eudiometer must equal the atmospheric pressure. If or by chance, the water levels happens not to be at the same height, then this is not the case. And then, as a result, in order to account for the difference between both, while also being able to get accurate results, you have to find the difference or subtract the water levels and then go ahead in converting them to mmHg.
If the brakes are applied and the speed of the car is reduced to 13 m/s in 14 s, determine the constant deceleration of the car.Express your answer to three significant figures and include the appropriate units. Assume ais negative if it acts in the opposite sense to the positive velocity.
Answer:
Explanation:
v = u + at
v is final velocity , u is initial velocity , a is acceleration and t is time .
here v = 0 , u = 13 m /s , t = 14 s
putting the values
0 = 13 + 14 a
a = 13 / 14 m /s²
= - .9286
= - 0.929 m /s²
Explain the "war of the currents"
Answer:
the war of currents is
Explanation:
The war of currents was a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s.
Answer:
a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s
Explanation:
You tie the loose end of a 0.1 kg yo-yo string to your finger and then release the yo-yo so that it spins down toward the ground (the yo-yo is released from rest and the end of the string tied to your finger remains motionless). After the yo-yo falls a distance of 0.9 m, it has a translational speed of 4 m/s and an angular speed of 180 rad/s. What is the moment of inertia of the yo-yo
Answer:
The answer is "[tex]5.06 \times 10^{-6} \ kg \ m^2[/tex]"
Explanation:
[tex]\to E_1=0..............(i)\\\\\to E_2= \frac{mV^2}{2} +\frac{Iw^2}{2} - mgh.............(ii)\\\\ \Delta E=0\\\\\to mgh= \frac{mV^2}{2} +\frac{Iw^2}{2} \\\\ \to 2 \ mgh= mV^2 +Iw^2\\\\ \to 2 \ mgh- mV^2 =Iw^2\\\\ \to m(2gh- V^2) =Iw^2\\\\ \to I= \frac{m(2gh- V^2)}{w^2}[/tex]
[tex]= 5.06 \times 10^{-6} \ kg \ m^2[/tex]
A car starts from rest and reaches a velocity of 30 m/s in 10 s. If the car
has a mass of 1500 kg, what net force is exerted upon the car?
Answer:
f= ma
Explanation:
v-u/ t
30-0/10
3m/s
maas 1500
1500*3
4500
Does electric and magnetic objects both have north and south poles
Explanation:
hope this answer was helpful
A water molecule is made up of one oxygen and two hydrogen atoms. Why is water considered a pure substance?
Answer:
A mixture is when two or more substances combine physically together.
However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone.
Explanation:
How much tension must a rope withstand if it is used to accelerate a 1200-kg car vertically upwards at 0.8m/s2?
Answer:
T = 12732 [N]
Explanation:
To solve this problem we must use newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
By means of the attached free body diagram, we can better understand the solution to this problem.
As we see in the diagram the tension Force T lifts the car upwards so the movement is upwards. Therefore we have two forces one upward (positive) of the force T and the other negative downward due to the weight of the vehicle.
As the movement is up the acceleration is also up (with a positive sign).
ΣF = m*a
where:
F = forces [N] (units of Newtons)
m = mass = 1200 [kg]
a = acceleration = 0.8 [m/s²]
T - 1200*9.81 = 1200*(0.8)
T = 12732 [N]
Answer:
12,720
Explanation:
A lead fishing weight of mass 0.20 kg is tied to a fishing line that is 0.50 m long. The weight is then whirled in a vertical circle. The finishing line will break if its tension exceeds 100.0 N. (a) If the weight is whirled at higher and higher speeds, at what point in the vertical circle will the string break (top, bottom, or random position)
Answer:
Following are the solution to this question
Explanation:
please find the complete question in the attached file.
In point a:
The answer is "bottom".
In point b:
Using formula:
[tex]T= mg + \frac{m V^2}{2}[/tex]
[tex]\to 100= 0.2 \times 9.81 + \frac{0.2 \times V^2}{0.5}[/tex]
[tex]\to 100= 1.962+ \frac{0.2 + V^2}{0.5}\\\\\to 100- 1.962= \frac{0.2 + V^2}{0.5}\\\\\to 98.038= \frac{0.2 + V^2}{0.5}\\\\\to 49.019=0.2+V^2\\\\\to 48.819=V^2\\\\ \to 6.987 \ \frac{m}{s}[/tex]
During the slowing down process, there is a time when the angular speed is 0.5 rev/s. The fan arm is 0.8 m long. What is the speed of a point on the end of the fan arm at this time
Answer:
2.51 m/s
Explanation:
Given that,
Angular speed of a fan, [tex]\omega=0.5\ rev/s = 3.14\ rad/s[/tex]
Length of the fan arm, r = 0.8 m
We need to find the speed of a point on the end of the fan arm at this time. Let v is the speed. It is given in terms of angular speed is given by :
[tex]v=r\omega\\\\v=0.8\times 3.14\\\\v=2.51\ m/s[/tex]
So, the required speed is 2.51 m/s.
asheed and Sofia are riding a merry-go-round that is spinning steadily (uniform circular motion). Sofia is twice as far from the axis as is Rasheed. Sophia's acceleration is _________ that of Rasheed. *
Answer:
The same as
Explanation:
First of all, they are in a merry go round, which is a circular one. And thus, we would be dealing with circular motions.
The angular velocity of a merry go round, in this instance, is given by
w = Δ/Δt
The formula has nothing whatsoever to do with distance, and as such, both Rasheed and Sofia would have the same angular velocity.
Transferring this further, the angular acceleration is given as
α = Δw/Δt
Remember I said the velocity has nothing to do with distance, well, so does the acceleration as we can see from the formula stated. And therefore, both Rasheed and Sofia would have the same angular acceleration