How to I write 1 2/3 as an improper fraction help ASAP

A. $ 58.50

B. $ 80

C. No, it did not mark up 30%.

Step-by-step explanation:Since,

A. We have,

Mark up percentage = 30%

Actual price = $ 45,

B. We have,

SP = $ 104,

C.  We have,

AP = $ 75,

SP = $100,

Thus, mark up percentage =

= 33.33 %

Hence, store did not mark up the price by 30%.

Answer:

Store A = 3.17

Store B = 3.25

Step-by-step explanation:

Hope this helps!

Answer:

Are directly proportional

Answer:

3.6 = a

Step-by-step explanation:

5.4 = a - ( -1.8)

5.4 = a + 1.8

5.4 - 1.8 = a

3.6 = a

Answer:

Step-by-step explanation:

Answer:

1/3 of the school in 5 minutes or in 15 minutes he will mop the whole entire school.

Step-by-step explanation:

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Work Shown:

1/3 of a classroom = 5 minutes

3*(1/3 of a classroom) = 3*5 minutes

1 classroom = 15 minutes

It takes the janitor 15 minutes to mop a full classroom.

The rate is expressed in units of classrooms per minute. This means we'll need to divide both sides by 15 to get

1 classroom = 15 minutes

1/15 classroom = 15/15 minutes

1/15 of a classroom = 1 minute

The janitor's rate is 1/15 of a classroom per minute.

Answer:

a.) 36

b.) 18

c.) 27

Step-by-step explanation:

Answer:

uhhh

Step-by-step explanation:

Answer:

3.82 x 10

Step-by-step explanation:

divide 4 x 10^4 by 1.1 x 10^3

4 divided by 1.1 is 3.81818181... and you subtract exponents to get 1

Answer:  The Answer Is A Because if u just add the numbers then divide them

Answer:

252 sq. in.

Step-by-step explanation:

divide it into sections like this

12*15=180

3*6=18

6*9=54

then add it all together. sometimes it is more complicated, but as long as none of the divided parts overlap this will be correct for any shape, as long as you account for the whole shape.

Answer:

C

Step-by-step explanation:

there would have to be one more zero between 0 and 8 for both of them

Answer

a. 0.856

b. 0.78071

c. It is not unusual

d. 13.65 years old

Step-by-step explanation:

The life span of a domestic cat is normally distributed with a mean of 15.7 years and a standard deviation of 1.6 years.

We solve this question using z score formula:

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

a. Find the probability that a cat will live to be older than 14 years.

For x > 14 years

z = 14 - 15.7/1.6

z = -1.0625

Probability value from Z-Table:

P(x<14) = 0.144

P(x>14) = 1 - P(x<14) = 0.856

b. Find the probability that a cat will live between 14 and 18 years.

For x = 14 years

z = 14 - 15.7/1.6

z = -1.0625

Probability value from Z-Table:

P(x = 14) = 0.144

For x = 18 years

z = 18 - 15.7/1.6

z= 1.4375

Probability value from Z-Table:

P(x = 18) = 0.92471

The probability that a cat will live between 14 and 18 years is calculated as:

P(x = 18) - P(x = 14)

0.92471 - 0.144

= 0.78071

c. If a cat lives to be over 18 years, would that be unusual? Why or why not?

For x > 18 years

z = 18 - 15.7/1.6

z= 1.4375

Probability value from Z-Table:

P(x<18) = 0.92471

P(x>18) = 1 - P(x<18) = 0.075288

Converting this to percentage:

0.075288 × 100 = 7.5288%

Hence, 7.5288% of the cats live to be over 18 years. Hence, it is not unusual.

d. How old would a cat have to be to be older than 90% of other cats?

From the question above, 10% of the cats would be older than 90% of other cats.

Hence, we find the z score of the 10th percentile

= -1.282

Hence,

-1.282 = x - 15.7/1.6

Cross Multiply

-1.282 × 1.6 = x - 15.7

- 2.0512 = x - 15.7

x = 15.7 -2.0512

x = 13.6488 years old

Approximately = 13.65 years old

Answer:

Step-by-step explanation:

U={3,6,9,12,15,18}

M={3,12,18}

M'={6,9,15}

The answer is,

U={3,6,9,12,15,18}

M={3,12,18}

M'={6,9,15}

A set is the mathematical model for a collection of different things; a set contains elements or members, which can be mathematical objects of any kind: numbers, symbols, points in space, lines, other geometrical shapes, variables, or even other sets.

here. given that,

U is the set of all multiples of 3 less than 20,

i.e. U={3,6,9,12,15,18}

and M={3,12,18},

Mc (the complement of M),

i.e. M'={6,9,15}.

Hence, we get, U={3,6,9,12,15,18} ,  M={3,12,18} & M'={6,9,15}.

To learn more on set click:

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Answer:

Step-by-step explanation:

 U bot. Nub

Answer:

An equation is a math sentence that DOES contain an equals sign (=).

The inverse of addition is subtraction.

The inverse of subtraction is addition.

The inverse of multiplication is division.

The inverse of division is multiplication.

Step-by-step explanation:

I'm sorry if I got the first one incorrect.

Answer:

49

Step-by-step explanation:

49 + 14 = 63

so that means:

x = 49

Answer: C

Step-by-step explanation:

i’m pretty sure the answer is A:

A. 5/16

because 1/4 of 1 1/4 is 0.3125 which is 5/16 as a fraction.

0.3125 = 5/16

Answer:

(195 - 286) ± 1.992 * sqrt((46^2/45) + (58^2/40))

Step-by-step explanation:

Given that:

NEWER CARS:

Sample size = n1 = 45

Standard deviation s1 = 46

Mean = m1 = 195

OLDER CARS:

Sample size = n2 = 40

Standard DEVIATION s2 = 58

Mean = m2 = 286

Confidence interval at 95% ; α = 1 - 0.95 = 0.05 ; 0.05 / 2 = 0.025

Confidence interval is calculated thus : (newer--older)

(m1 - m2) ± Tcritical * standard error

Mean difference = m1 - m2; (195 - 286)

Tcritical = Tn1+n2-2, α/2 = T(45+40)-2 = T83, 0.025 = 1.99 (T value calculator)

Standard error (E) = sqrt((s1²/n1) + (s2²/n2))

E = sqrt((46^2/45) + (58^2/40))

Hence, confidence interval:

(195 - 286) ± 1.992 * sqrt((46^2/45) + (58^2/40))

The 95% confidence interval for estimating the difference in the mean dollar cost of the routine maintenance between newer and older cars is given by:

[tex]CI=(\overline{x_1} - \overline{x_2}) \pm t_{critical} \sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}}[/tex]

The first sample consists of owners of newer cars

The second sample consists of owner of older cars.

95% confidence interval for difference between both samples' means.

Since the sample sizes are > 30, thus we can use the z table for finding the Confidence interval.

The CI is given as:

[tex]CI=(\overline{x_1} - \overline{x_2}) \pm t_{critical} \sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}}[/tex]

For 0.95 probability confidence, we have t at 40+45-3= t at 83 at 0.05/2 is 1.992 (from T tables)

Thus,

[tex]CI=(195-268) \pm 1.992 \sqrt{\dfrac{46^2}{45} + \dfrac{58^2}{40}}[/tex]

Learn more about confidence interval here:

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Answer:

Following are the solution to this question:

Step-by-step explanation:

For this set, the correlation coefficient is = -0.015.

It shows that financial variables have trust issues. Once a price rises, the other one is decreasing the value of -0,015 shows, that there are several fewer associations in the set of data among x and y and between y values. This interaction also can range between -1 to 1, to 0 being completely unrelated. But you'd never be sure, in this situation, 0.015 is very similar to 0.

It means that your prediction is nothing better than just a wild choice. Its odds of an estimated value being relatively close to the actual result are therefore much smaller as the points are it's hardly the best match.

Answer:

b = 4

Step-by-step explanation:

you must divide both sides of the equation by -5 to get b by itself. division cancels out multiplication but also keeps both sides equal

b = -20/-5

b = 4

Answer:

? please explain

Step-by-step explanation:

Answer:128 I think is the answer

Step-by-step explanation:

Answer:

exponential expression:

8ᵇ = 2

log8(2) = 0.333333333 or 1/3

Answer:

log8(2) = 1/3

Step-by-step explanation:

I don't know if they mean this by an exponential expression but:

set x = log8(2), then

8^x = 8^(log8(2))

By logarithmic properties:

8^x = 2.

notice that 8 = 2^3.

By exponential properties:

8^x = (2^3)^x = 2^(3x)

So 2^(3x) = 2 = 2^1.

Comparing exponents gives:

3x = 1 <=> x = 1/3.

So log8(2) = 1/3.

Answer:

F = 9 over 5C + 32

Step-by-step explanation:

Let's consider the following equation that shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F.

C = 5 over 9(F − 32)

C = 5/9 (F − 32)

To solve for F, first, we will multiply both sides by 9/5.

C × 9/5 = 5/9 (F − 32) × 9/5

9/5 C = F − 32

Now, we add 32 to both sides.

9/5 C + 32 = F − 32 + 32

9/5 C + 32 = F

F = 9 over 5C + 32

Answer:

F = 9 over 5C + 32

Step-by-step explanation:

Answer:

y = 3x + 5

Step-by-step explanation:

The zero seems to be a place holder to mess you up. Just ignore that it doesn't do anything. Add -3x and -5 to the both sides to create y = 3x + 5

Answer:

Width  = 166.7 ft

Length = 250 ft.

Step-by-step explanation:

From the diagram at the ATTACHMENT

Let us denote the the length of the rectangular area as "x" and

the width of the rectangular area as "y"

Since, cost of the fence on the western side is shared with a neighbor, we can say  it is $7 per foot. Otherwise, it is $14 per foot. The northern length is not fenced.

From the question, we know that the  cost is not to exceed $7000, therefore we can expressed it as

7y + 14x + 14y = 7000

14x + 21y = 7000

Divide through by 14, we have

(x + 1.5) = 500  ------------- eqn (*)            

But the area of the fenced

= A = (x×y)      -------------- eqn  (**)                    

Substitute (*) into (**) we have

A = (500 - 1.5y)*y

= 500y - 1.5y²

In other to maximize the Area, we can find the differential of A

A'(y) = 500 - 3y

At A'(y) = 0.

500-3y= 0

3y=500

y= 166.67 ft

From eqn(*)

(x+ 1.5) = 500

x = 500 - 1.5y

500-1.5(166.67)

= 250ft

Therefore, the dimensions for the plot that would enclose the most area are

Width  of 166.67 ft and Length = 250 ft.

Answer:

x=3y-6

Step-by-step explanation:

x−3y=−6

Step 1: Add 3y to both sides.

x−3y+3y=−6+3y

x=3y−6

Answer:

x=3y−6