Answer:
1 -- Triangle
Step-by-step explanation:
Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!
Suppose $f(3) = 4$. Name a point that must be on the graph of $y=f(x)+4.$
Enter your answer as an ordered pair.
Answer:
(x, y) = (3, 8)
Step-by-step explanation:
The graph for y is a translation upward 4 units of the graph of f(x).
__
A point on the graph of f(x) is given as ...
(x, f(x)) = (3, f(3)) = (3, 4)
Then a point on the graph of y will be ...
(x, y) = (x, f(x) +4)) = (3, f(3)+4) = (3, 4 +4)
(x, y) = (3, 8)
Expand binomial (x+1)1
Answer:
x + 1Step-by-step explanation:
Given binomial
(x + 1)¹Use the property
a¹ = aThe binomial remains same without brackets
(x + 1)¹ = x + 1Please help with this thanks! God bless you
Answer:
n=23
Step-by-step explanation:
a right angle measures 90
67+n=90
subtract 67 on both sides
n=23
Use angle addition postulate:
m∠ABD + m∠DBC = m∠ABCSubstitute values to get the required equation and solve it for n:
m∠ABD = 67°, m∠DBC = n°, m∠ABC = 90°67 + n = 90n = 90 - 67n = 232. When plotting a point on a coordinate grid using an ordered pair, the
first number tells you to go up.
O True
False
Explanation:
Any point is of the form (x,y)
The first coordinate is x which tells us to go either left or right depending on whether x is negative or positive.
Example: (-2,3) means we go left 2 units
Another example: (5,7) means we go to the right 5 units.
The starting point is the origin where the x and y axis meet up.
Answer:
False
Step-by-step explanation:
I need the answer to this as well
Answer:
Option C.
Step-by-step explanation:
Perimeter = 2L + 2h
[tex]P=2(5x^{2}y) +2(3y^{3} )=10x^{2} y+6y^{3}[/tex]
Hope this helps
what would be the best response to the question in the picture above please respond soon. (will give brainliest)
Now consider the product of a nonzero rational number and an irrational number. Again, assume x = where a and b are integers and b#0. This time lety be an irrational number. If we assume the product x.y is rational, we can set the product equal to where mand n are integers and n = 0. The steps for solving this equation for y are shown. Statement Reason cy= 02 72 D.y= substitution 8 y = multiplication property of equality a mb na Simplify Based on what we established about the classification of y and using the closure of integers, what does the equation tell you about the type of number y must be for the product to be rational? What conclusion can you now make about the result of multiplying a rational and an irrational number?
Answer:
The product of a rational number with an irrational number is an irrational number. To see this assume that x is a rational number and y an irrational number. Then let us assume that the product xy is rational, which means that there are integers a,b such that xy=a/b. But then we obtain y=(1/x)(a/b) which is also rational since the set of rational numbers is closed under multiplication. But this is a contradiction since y was assumed to be an irrational number.
Step-by-step explanation:
Question:Now consider the product of a nonzero rational number and an irrational number. Again, assume x =a/b , where a and b are integers and b ≠ 0. This time let y be an irrational number. If we assume the product x · y is rational, we can set the product equal to m/n, where m and n are integers and n ≠ 0. The steps for solving this equation for y are shown. Based on what we established about the classification of y and using the closure of integers, what does the equation tell you about the type of number y must be for the product to be rational? What conclusion can you now make about the result of multiplying a rational and an irrational number?
Answer:2
SOMEONE PLEASE HELP!!!! ILL GIVE BRAINLIEST
Answer:
Your Answer is A.
Step-by-step explanation:
Looking at the picture the LM is the original and wants to translate it to L'M'.
So Right 5 and 2 up.
Answer:
A
Step-by-step explanation:
LM is 5 units away from LM'
LM is 2 units down from LM'
BRAINLIEST please if this helped!20. You may already use algebra in your daily life. How do you imagine that you will use basic algebraic equations in your healthcare career? Explain.
Depending on the path that we decide to take, the algebra can help us in many forms.
As an example in the pharmaceutical/medical area, the nurses and doctors use basic algebra formulas to calculate dosages on different drugs depending on variables such as the weigh of each patient (commonly expressed as X or Y).
They used to have some paper sheets with formulas for different drug preparations (liquid ones particularly) within hospitals to avoid errors in medication.
As a healthcare provider, it is important to be able to read vital signs. Many of these are expressed as algebraic equations. Such equations can also be important when it comes to administering the right doses of medicine or converting different units of measurement.
calculus, question 5 to 5a
5. Let [tex]x = \sin(\theta)[/tex]. Note that we want this variable change to be reversible, so we tacitly assume 0 ≤ θ ≤ π/2. Then
[tex]\cos(\theta) = \sqrt{1 - \sin^2(\theta)} = \sqrt{1 - x^2}[/tex]
and [tex]dx = \cos(\theta) \, d\theta[/tex]. So the integral transforms to
[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \int \frac{\sin^3(\theta)}{\cos(\theta)} \cos(\theta) \, d\theta = \int \sin^3(\theta) \, d\theta[/tex]
Reduce the power by writing
[tex]\sin^3(\theta) = \sin(\theta) \sin^2(\theta) = \sin(\theta) (1 - \cos^2(\theta))[/tex]
Now let [tex]y = \cos(\theta)[/tex], so that [tex]dy = -\sin(\theta) \, d\theta[/tex]. Then
[tex]\displaystyle \int \sin(\theta) (1-\cos^2(\theta)) \, d\theta = - \int (1-y^2) \, dy = -y + \frac13 y^3 + C[/tex]
Replace the variable to get the antiderivative back in terms of x and we have
[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\cos(\theta) + \frac13 \cos^3(\theta) + C[/tex]
[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\sqrt{1-x^2} + \frac13 \left(\sqrt{1-x^2}\right)^3 + C[/tex]
[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\frac13 \sqrt{1-x^2} \left(3 - \left(\sqrt{1-x^2}\right)^2\right) + C[/tex]
[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \boxed{-\frac13 \sqrt{1-x^2} (2+x^2) + C}[/tex]
6. Let [tex]x = 3\tan(\theta)[/tex] and [tex]dx=3\sec^2(\theta)\,d\theta[/tex]. It follows that
[tex]\cos(\theta) = \dfrac1{\sec(\theta)} = \dfrac1{\sqrt{1+\tan^2(\theta)}} = \dfrac3{\sqrt{9+x^2}}[/tex]
since, like in the previous integral, under this reversible variable change we assume -π/2 < θ < π/2. Over this interval, sec(θ) is positive.
Now,
[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \int \frac{27\tan^3(\theta)}{\sqrt{9+9\tan^2(\theta)}} 3\sec^2(\theta) \, d\theta = 27 \int \frac{\tan^3(\theta) \sec^2(\theta)}{\sqrt{1+\tan^2(\theta)}} \, d\theta[/tex]
The denominator reduces to
[tex]\sqrt{1+\tan^2(\theta)} = \sqrt{\sec^2(\theta)} = |\sec(\theta)| = \sec(\theta)[/tex]
and so
[tex]\displaystyle 27 \int \tan^3(\theta) \sec(\theta) \, d\theta = 27 \int \frac{\sin^3(\theta)}{\cos^4(\theta)} \, d\theta[/tex]
Rewrite sin³(θ) just like before,
[tex]\displaystyle 27 \int \frac{\sin(\theta) (1-\cos^2(\theta))}{\cos^4(\theta)} \, d\theta[/tex]
and substitute [tex]y=\cos(\theta)[/tex] again to get
[tex]\displaystyle -27 \int \frac{1-y^2}{y^4} \, dy = 27 \int \left(\frac1{y^2} - \frac1{y^4}\right) \, dy = 27 \left(\frac1{3y^3} - \frac1y\right) + C[/tex]
Put everything back in terms of x :
[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac1{\cos^3(\theta)} - \frac3{\cos(\theta)}\right) + C[/tex]
[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac{\left(\sqrt{9+x^2}\right)^3}{27} - \sqrt{9+x^2}\right) + C[/tex]
[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \boxed{\frac13 \sqrt{9+x^2} (x^2 - 18) + C}[/tex]
2(b). For some constants a, b, c, and d, we have
[tex]\dfrac1{x^2+x^4} = \dfrac1{x^2(1+x^2)} = \boxed{\dfrac ax + \dfrac b{x^2} + \dfrac{cx+d}{x^2+1}}[/tex]
3(a). For some constants a, b, and c,
[tex]\dfrac{x^2+4}{x^3-3x^2+2x} = \dfrac{x^2+4}{x(x-1)(x-2)} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac c{x-2}}[/tex]
5(a). For some constants a-f,
[tex]\dfrac{x^5+1}{(x^2-x)(x^4+2x^2+1)} = \dfrac{x^5+1}{x(x-1)(x+1)(x^2+1)^2} \\\\ = \dfrac{x^4 - x^3 + x^2 - x + 1}{x(x-1)(x^2+1)^2} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac{cx+d}{x^2+1} + \dfrac{ex+f}{(x^2+1)^2}}[/tex]
where we use the sum-of-5th-powers identity,
[tex]a^5 + b^5 = (a+b) (a^4-a^3b+a^2b^2-ab^3+b^4)[/tex]
Help I don't understand this math. Whoever gets the right answer gets Brainlist! :)
Do part B please! :)
Answer:
1=32
2=44
3=56
4=70
Step-by-step explanation:
if need working please ask
Rewrite the parametric equations in Cartesian form: X(t) = -3sin t, y(t) = 3 cos t
Answer:
[tex]( \frac{x}{3} ) {}^{2} + ( \frac{y}{3}) {}^{2} = 1[/tex]
or x² +y²= 9
Step-by-step explanation:
In Cartesian form, the equation is expressed only in terms of y and x.
x= -3sin(t) -----(1)
y= 3cos(t) -----(2)
I've written x instead of x(t) as in the later part of the working, we will be having an equation of only x and y, thus x will no longer be a function of t. This applies to equation 2, where I have replaced y(t) with y.
Relating sine to cosine:
sin²(t) +cos²(t)= 1
[sin(t)]² +[cos(t)]²= 1 -----(3)
From (1):
[tex] \frac{x}{ - 3} = \sin(t) [/tex]
[tex] \sin(t) = - \frac{x}{3} [/tex] -----(3)
From (2):
[tex] \frac{y}{3} = \cos(t) [/tex]
[tex] \cos(t) = \frac{y}{3} [/tex] -----(4)
Substitute (4) &(5) into (3):
[tex]( - \frac{x}{3} )^{2} + ( \frac{y}{3}) {}^{2} = 1[/tex]
[tex]( \frac{x}{3} ) {}^{2} + ( \frac{y}{3} ) {}^{2} = 1[/tex]
The steps below are optional as the above is already considered to be the Cartesian form.
[tex] \frac{ {x}^{2} }{9} + \frac{y {}^{2} }{9} = 1[/tex]
Multiplying both sides by 9:
x² +y²= 9
A flower garden is shaped like a circle. Its diameter is 40yd. A ring-shaped path goes around the garden. Its outer edge is a circle with diameter 48yd.
The gardener is going to cover the path with sand. If one bag of sand can cover 6yd^2, how many bags of sand does the gardener need? Note that sand comes only by the bag, so the number of bags must be a whole number. (Use the value 3.14 for pi number .)
Answer:
About 5 bags of sand
Step-by-step explanation:
1. Create Equation
[(48x3.14)-(40x3.14)]/6
2. Solve
[(48x3.14)-(40x3.14)]/6
[150.72-125.6]/6
25.12/6
Now if you use a calculater you will get
4.1866666667
So lets just round the number to 5 instead of
4 beacuse if we round it to 4 it won't be enough
to cover the whole path.
so your answer is 5
For circle B, BG = BE, BG is perpendicular to DC, and BE is perpendicular to FA. What conclusion can be made? a circle with center B and chords DC and FA, a segment from B to chord DC intersect chord DC at G, and a segment from B to chord FA intersects chord FA at E segment DC is parallel to segment FA segment CD is congruent to segment EB segment GB is parallel to segment EB segment DC is congruent to segment FA
Base on the equidistant chords theorem, chords FB and DA are congruent because they are equidistant from C.
What is the Equidistant Chords Theorem?The equidistant chords theorem states that two chords in the same circle are congruent to each other, if they are equidistant from the center of the circle.
Thus, based on the information given we can conclude that chords FB and DA are congruent because they are equidistant from C based on the equidistant chords theorem.
Learn more about the equidistant chords theorem on:
https://brainly.com/question/7511582
Answer:
Its D The one at the top is incorrect.
Step-by-step explanation:
I got A 100% which means i got it right...
If v = X + 4t, v is the velocity and X is the displacement, how to find X in terms of t?
[tex]x = vt\\\\\implies x= (x+4t)t\\\\\implies x=xt+4t^2\\\\\implies x -xt= 4t^2\\\\\implies x (1-t) =4t^2\\\\\implies x = \dfrac{4t^2}{1-t}[/tex]
eter and Area
5
Annita is sewing a lace edge around a rectangular quilt. She will need 160 inches of lace to do the entire quilt. If the quilt is 46
inches wide, how long is the quilt?
A. 32 inches
B. 34 inches
C. 80 inches
D.
68 inches
Reset
Submit
Answer:
b 34
Step-by-step explanation:
its 34 because if you do 46×2 because of the both sides you will get 92 then subtract 92 from 160 and you will get 68 then do 68÷2 to find out the second side and you will get 34
pls help ill give brainliest
Answer:
y = -3x + 2
Step-by-step explanation:
use the slope formula to find the slope
replace x and y into slope intercept form with the slope you just found
Question 5
Select the option that best describes the relationship
between the variables on the scatter plot.
Answer:
positive, leaner association
Step-by-step explanation:
last year a company made a profit of one and a quarter million dollars.Each year the company reinvests 1/3 of the profit How much of this profit eill they reinvest
Answer:
$83,333
Step-by-step explanation:
1 000 000*1/4
250 000
250 000*1/3 = 83 333.33
Which angles are supplementary to each other?
PLS HELP!
Answer: Angles 6 and 7
Step-by-step explanation:
These angles form a linear pair, and angles that form a linear pair are supplementary.
find out 6c+4dc when c=4.5 and d=6.6
show how to do it step by step
Answer:
145.8
Step-by-step explanation:
6c+4dc, where c=4.5 d=6.6
6(4.5) + 4(6.6) (4.5)
27 + 118.8
=145.8
-3(p-4)=-2p+1 what is p
Answer: p=11
Step-by-step explanation:
-3(p-4) = -2p+1
-3p+12=-2p+1
+2p +2p
-p+12=1
-12 -12
(-1)-p=-11 (-1)
p = 11
Check answer:
-3(11-4)=-2(11)+1
-3(7)=(-22)+1
-21 = -21
Kathryn’s new ball has a diameter of 4 inches (in.). What is the surface area of Kathryn’s ball? Use 3.14 for π .
Drag each expression to show whether it is equivalent to 54x + 18 or
(6 · 9x) + (6 · 1).
Answer:
The first one should belong in the 54x+18 due to multiplication
The second answer choice has distributive property which has to belong in the 54x+18 category
The third answer choice fits into the 6 times 9x + 6 times one category due to multiplication like the first answer choice.
The last one should be in the 54x+18 category because of the distributive property
Step-by-step explanation:
The Objectives: 54x+18 and (6(9x) + 6
The first one should belong in the 54x+18 due to multiplication
The second answer choice has distributive property which has to belong in the 54x+18 category
The third answer choice fits into the 6 times 9x + 6 times one category due to multiplication like the first answer choice.
The last one should be in the 54x+18 category because of the distributive property
What causes a heart attack?
A. When the arteries increase
B. When LDL metabolizes cholesterol
C. When the heart is starved of oxygen
D. When HDL returns cholesterol to the heart
Answer:
C.When the heart is starved of oxygen
Find the slope of the line 11x - 4y = 21.
Answer: 11/4
Step-by-step explanation: no need :”)
A nonstop train travels between Pearl River and Hoboken. On its trip south, traveling at a constant speed, it makes it from Pearl River to Hoboken in 1 hour and 6 minutes. On its return trip north, the train increases its speed by 10 miles per hour, and takes 42 minutes to reach Pearl River from Hoboken.
What was the train's original speed (on its trip south) in miles per hour?
Based on the information provided about the return trip, the train's speed on its trip south was 6.36 miles per hour.
What is the distance between Pearl River and Hoboken?Distance = speed x timeDistance = 10 miles per hour x 0.7 hours (42 minutes)Distance = 7 milesWhat is the speed on the trip south?Speed = distance / timeSpeed= 7 miles / 1.1 (66 minutes)Speed= 6.36 miles per hourLearn more about speed in: https://brainly.com/question/6280317
given sin0= 2/3 and angle 0 is in quadrant 2, what is the exact value of cos0 in simplest form? simplify all radicals if needed
Answer: ( -[tex]\sqrt{5}[/tex] / 3)
Step-by-step explanation:
sin(angle) = opposite/hypotenuse
opposite =2
hypotenuse = 3
solve for adjacent side with pythagorean theorum
opposite^2 + adjacent^2 = hypotenuse^2
2^2 + adjacent^2 = 3^2
4 + adjacent^2 = 9
adjacent^2 = 9 - 4
adjacent^2 = 5
adjacent = [tex]\sqrt{5}[/tex]
-[tex]\sqrt{5}[/tex] since it is in the second quadrant
cosx = (adjacent/hypotenuse)
cosx = (-[tex]\sqrt{5}[/tex]/3)
(-[tex]\sqrt{5}[/tex]/3)
How many flowers, spaced every 6 inches, are needed to surround a circular garden with a 20-foot radius?
The function f(t) = 3 cos(pi over 6t) + 5 represents the tide in Blastic Sea. It has a maximum of 8 feet when time (t) is 0 and a minimum of 2 feet. The sea repeats this cycle every 12 hours. After nine hours, how high is the tide? 12 feet 5 feet 4.5 feet 2.5 feet
Answer:
5 feet
Step-by-step explanation:
[tex]f(t) = 3 cos \bigg( \frac{\pi}{6} t\bigg) + 5 \\ \\ plug \: t = 9 \\ \\ \implies \: f(9) = 3 cos \bigg( \frac{\pi}{6} \times 9 \bigg) + 5 \\ \\\implies \: f(9) = 3 cos \bigg( \frac{3\pi}{2}\bigg) + 5 \\ \\\implies \: f(9) = 3 cos \bigg( \pi + \frac{\pi}{2}\bigg) + 5 \\ \\\implies \: f(9) = - 3 cos \bigg( \frac{\pi}{2}\bigg) + 5 \\ [ \because \: cos ({\pi}+\theta) = -\cos \theta]\\\\\implies \: f(9) = - 3 (0) + 5 \\ ( \because \: cos \frac{\pi}{2} = 0) \\ \\ \implies \: f(9) = 0 + 5 \\ \\ \implies \: \huge{ \orange{f(9) = 5 }}[/tex]
(x+35)(2x + 1). How do I do this
Answer:
Split brackets method see below
Step-by-step explanation:
(x+35)(2x + 1)x(2x + 1)+35(2x + 1)2[tex]x^{2}[/tex] + x + 70x + 352[tex]x^{2}[/tex] + 71x +35