How many grams are present in 1. 75 moles of carbon dioxide, CO2?

True. Mixing aqueous solutions of Na2S (sodium sulfide) and MgCl2 (magnesium chloride) will result in the formation of a solid precipitate, which is MgS (magnesium sulfide).

This is because the reaction between Na2S and MgCl2 produces MgS, which is insoluble in water and forms a solid precipitate. The balanced chemical equation for the reaction is:

Na2S (aq) + MgCl2 (aq) → MgS (s) + 2 NaCl (aq)

So, the net ionic equation for the reaction is:

Mg2+ (aq) + S2- (aq) → MgS (s)

Therefore, a solid precipitate of MgS will be formed when aqueous solutions of Na2S and MgCl2 are mixed.

When Na2S and MgCl2 are mixed in water, they dissolve and dissociate into their respective ions, which are Na+, S2-, Mg2+, and Cl-. The Na+ and Cl- ions remain in solution as they do not react with each other. However, the Mg2+ and S2- ions react to form a precipitate of MgS because magnesium sulfide is insoluble in water.

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The output voltage of the device is 12 volts.

The transformer law states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage. Mathematically, we can express this as:

Vp/Vs = Np/Ns

where Vp is the input voltage (120 volts in this case), Vs is the output voltage (what we're trying to find), Np is the number of turns in the primary coil (200 turns in this case), and Ns is the number of turns in the secondary coil (20 turns in this case).

We can rearrange this equation to solve for Vs:

Vs = Vp * Ns/Np

Plugging in the given values, we get:

Vs = 120 volts * 20/200

Vs = 12 volts.

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The concentration of O₂(g) in the solution is 8 ppm. Option B is correct.

Parts per million (ppm) is a unit of concentration used to express the amount of a substance in a solution. It represents the number of parts of the substance per one million parts of a solution.

To calculate the concentration of O₂(g) in parts per million (ppm), we need to first determine the amount of O₂ dissolved in the solution per unit mass of the solution.

We are given that the solution contains 0.008 grams of O₂(g) dissolved in 1000 grams of H₂O(₂):

Concentration of O₂(g) = (mass of O₂(g) / mass of solution) x 10⁶

Concentration of O₂(g) = (0.008 g / 1000 g) x 10⁶

= 8 ppm

Hence, B. 8ppm is the correct option.

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--The given question is incomplete, the complete question is

"What is the concentration of O2(g), in parts per million, in a solution that contains 0. 008 gram of O2(g) dissolved in 1000. Grams of H2O(2)?A) 10. 8 ppm B) 8 ppm C) 80 ppm D) 800 ppm"--

Plane of symmetry is a plane through a crystal that divides the crystal into two parts that are mirror images of each other.

Enantiomers are a pair of stereoisomers that is the mirror image of the other, but may not be superimposed on this other stereoisomer.

Enantiomers have properties that make them unique to their mirror images. One of these properties is that they cannot have a plane of symmetry or an internal mirror plane i.e. cannot be divided into two identical and opposite halves.

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Answer:

The balanced chemical equation for the reaction of NaHCO3 and Ca(H2PO4)2 is:

2 NaHCO3(aq) + Ca(H2PO4)2(aq) → Na2HPO4(aq) + CaHPO4(aq) + 2 CO2(g) + 2 H2O(l)

From the equation, we see that 2 moles of NaHCO3 produce 2 moles of CO2. Therefore, 1 mole of NaHCO3 produces 1 mole of CO2. We can use the molar mass of NaHCO3 to convert from moles to grams.

The molar mass of NaHCO3 is:

Na: 1 x 22.99 g/mol = 22.99 g/mol

H: 1 x 1.01 g/mol = 1.01 g/mol

C: 1 x 12.01 g/mol = 12.01 g/mol

O: 3 x 16.00 g/mol = 48.00 g/mol

Total molar mass = 22.99 + 1.01 + 12.01 + 48.00 = 83.01 g/mol

One kilogram (1000 g) of baking powder contains 168 g of NaHCO3. Therefore, one kilogram of baking powder contains:

1000 g baking powder × (168 g NaHCO3 / 1000 g baking powder) = 168 g NaHCO3

To produce 2.2 L of CO2 at baking temperature, we need:

2.2 L CO2 × (1.20 g CO2 / 1 L CO2) = 2.64 g CO2

Since 1 mole of NaHCO3 produces 1 mole of CO2, we need 2.64 g of NaHCO3 to produce 2.64 g of CO2. This corresponds to:

2.64 g NaHCO3 × (1 mol NaHCO3 / 83.01 g NaHCO3) × (1 kg baking powder / 168 g NaHCO3) = 0.0198 kg baking powder

Therefore, we need 0.0198 kg, or 19.8 g, of baking powder to generate 2.2 L of CO2 at baking temperature.

Explanation:

The reaction of cyclohexene with osmium tetroxide results in the formation of two products, cis-cyclohexane-1,2-diol and trans-cyclohexane-1,2-diol.

Both of these compounds have a cis arrangement of hydroxyl groups on the carbon chain, meaning that the two hydroxyl groups are on the same side of the carbon chain. The reaction of these diols with sodium bisulfite results in a racemic mixture of the epoxide and dithiane derivatives.

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The mole ratio of NaNO₃ to Pb(NO₃)2 is 2:1. Therefore, 6.75 g of Pb(NO₃)₂ will produce 2 x 6.75 g = 13.5 g of NaNO₃.

Mole is a unit of measurement used in chemistry to measure the amount of a substance, usually expressed in terms of the number of atoms, molecules, or other units in a given mass of that substance. The mole, also known as Avogadro's number, is a very large number equal to 6.022 x 10^23. This means that a mole of a substance contains 6.022 x 10^23 atoms or molecules, depending on the substance. The mole is used to measure the amount of a substance in a given sample, and is essential to many chemical calculations.

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Answer:

Explanation:

the formula for Iron(I) nitride is  : Fe2N

the formula for tin(II) bromide ; SnBr₂

The field lines around a positively charged pair of jeans would extend outward in all directions from the jeans, with evenly spaced lines becoming weaker as they move away from the jeans.

If a pair of jeans becomes positively charged, it will create an electric field around it. The electric field will be directed away from the jeans, since positive charges repel each other. The field lines will spread out in all directions from the jeans, becoming weaker as they move further away.

To draw field lines around the jeans, we can use a simple diagram. The diagram should show the jeans in the center, with field lines extending outwards in all directions. The field lines should be drawn perpendicular to the surface of the jeans, since this is the direction in which the electric field will be strongest.

The field lines should be evenly spaced and should become weaker as they move further away from the jeans. The length of the field lines can be arbitrary, but it is common to make them longer near the jeans to indicate the stronger electric field.

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Energy cannot be created or destroyed; it can only be changed from one form to another, according to the rule of conservation of energy.

A fundamental tenet of physics is the law of conservation of energy, which holds that energy can only be changed from one form to another and cannot be created or destroyed. Hence, the overall energy level in a closed system is constant across time. Many tests and observations, such as the energy changes that take place when an object falls from a table to the ground, have demonstrated the accuracy of the rule. The object loses potential energy owing to the change in height while gaining kinetic energy from its motion as it falls. The rule of conservation of energy is demonstrated by the fact that the total amount of energy is the same before and after the fall.

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The empirical formula of Sample R0103 is [tex]C_{12}H_{24}O_6[/tex].

This is the molecular formula for a type of sugar called sucrose, which is commonly found in fruits, vegetables, and honey. It is a disaccharide, which Sucrose, a type of sugar that is found naturally in plants and is used as a sweetener in food and beverages. It is made up of 12 Carbon atoms, 24 Hydrogen atoms and 6 Oxygen atoms.The R0103 formula is an empirical formula used to calculate the amount of energy released in a given reaction. The formula uses the known energy content of the reactants and products to predict the energy released. The amount of energy released is determined by the difference between the energy content of the products and the energy content of the reactants.

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2.55 moles of magnesium oxide will produce 2.55 moles of magnesium hydroxide.

What is magnesium hydroxide ?

Magnesium hydroxide (Mg(OH)2) is an inorganic compound that is commonly used as an antacid and laxative to treat heartburn, indigestion, and constipation. It is a white, odorless, and tasteless powder that is slightly soluble in water.

The balanced chemical equation for the reaction between magnesium oxide and water to form magnesium hydroxide is:

MgO + H2O → Mg(OH)2

From the equation, we can see that 1 mole of MgO reacts with 1 mole of H2O to produce 1 mole of Mg(OH)2.

Therefore, if 2.55 moles of MgO react with excess water, then the number of moles of Mg(OH)2 produced will also be 2.55 moles.

So, 2.55 moles of magnesium oxide will produce 2.55 moles of magnesium hydroxide.

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a) Using Lennard-Jone's potential energy for a diatomic molecule the equilibrium separation is r = [tex](2B/A)^{(1/6)}[/tex].

b) At the equilibrium separation, the force on each atom is zero.

The Lennard-Jones potential energy for a diatomic molecule is given by:

V(r) = A/[tex]r^{12}[/tex] - B/[tex]r^6[/tex]

Where r is the separation between the two atoms of the molecule, and A and B are positive constants.

To find the equilibrium separation, we need to find the value of r at which the potential energy is at a minimum. We can do this by taking the derivative of the potential energy concerning r and setting it equal to zero:

dV/dr = -12A/[tex]r^{13}[/tex] + 6B/[tex]r^7[/tex] = 0

Solving for r, we get:

r = [tex](2B/A)^{(1/6)}[/tex]

This is the equilibrium separation between the two atoms of the molecule.

If the separation between the atoms is smaller than the equilibrium separation, then the force between them is attractive. If the separation is larger than the equilibrium separation, then the force is repulsive. At the equilibrium separation, the force on each atom is zero.

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The system is losing heat to the surroundings. The approximate value for the heat exchange is 36770 J.

What is Equilibrium?

In general, equilibrium refers to a state of balance or stability in a system. In the context of physics, specifically thermodynamics, equilibrium is a state in which there is no net flow of heat or matter between a system and its surroundings. In other words, the system and surroundings have reached the same temperature and pressure, and there is no longer any exchange of heat or matter between them.

To solve this problem, we can use the equation for heat exchange:

Q = mcΔT

where Q is the heat exchange, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For aluminum, the specific heat capacity is 0.903 J/g°C, and for ethyl alcohol, it is 2.44 J/g°C. We can also assume that the heat exchange between the aluminum and the ethyl alcohol is equal and opposite.

A) To find the equilibrium temperature, we can use the equation:

mcΔT = mcΔT

(100.0 g)(0.903 J/g°C)(T - 450.0°C) = (100.0 g)(2.44 J/g°C)(T - 80.0°C)

Solving for T, we get:

T = 198.15°C

Therefore, the equilibrium temperature of the mixture is approximately 198°C.

B) To find the heat exchange, we can use the same equation:

Q = mcΔT

The heat exchange for aluminum is:

Q₁ = (100.0 g)(0.903 J/g°C)(450.0°C - 198.15°C) ≈ 21260 J

The heat exchange for ethyl alcohol is:

Q₂ = (100.0 g)(2.44 J/g°C)(198.15°C - 80.0°C) ≈ 15510 J

The total heat exchange for the system is:

Q = -(Q₁ + Q₂) ≈ -36770 J

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At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. The quantity of dissociation of water molecules to form hydronium and hydroxide ions is indicated by the autoionization constants of water.

It should be remembered that the autoionization constant rises as the temperature rises. Kw equals 1.0 x 10-14 [H+][OH-]. Hence, one may determine the [H+] or [OH-] as needed for any liquid at 25°C in any given aquatic condition. Indicate if the substance is acidic, basic, or neutral.

Kwh of electricity are units of energy that represent one megawatt of electricity for one hour (unit symbol: kWh or kWh; frequently abbreviated as kWh). It represents 3.6 megajoules (MJ) in SI-derived units with specific names.

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At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. Water's pOH at 75 degrees Celsius is 6.85 as a result.

Using the relationship between the amounts of hydrogen ions (H+) and hydroxide ions (OH) and the ion product constant for water (Kw), we can begin to solve this issue:

Kw = [H⁺][OH⁻]

Kw = [H⁺][OH⁻]

1.995 x 10⁻¹³ = [H⁺][OH⁻]

Since water is neutral, the concentration of hydrogen ions and hydroxide ions must be equal.

[H⁺] = [OH⁻]

Hence, the equation can be rewritten as follows:

1.995 x 10⁻¹³ = [OH⁻]²

When we solve for [OH], we get:

[OH⁻] = √(1.995 x 10⁻¹³) = 1.414 x 10⁻⁷

We can now apply the correlation between pOH and [OH]:

pOH equals -log[OH]

By entering [OH] as the value, we obtain:

pOH is equal to -log(1.414 x 107) = 6.85.

Water's pOH at 75 degrees Celsius is 6.85 as a result.

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Explanation:

The pH of the mixture of acids is 0.62, the pH of the mixture of acids is 0.63, the pH of the mixture of acids is 0.39, the pH of the mixture of acids is 1.00.

To find the pH of a mixture of acids, we need to first calculate the total concentration of H⁺ ions in the solution, and then use that value to calculate the pH using the formula pH = -log[H⁺].

The chemical formulas for the two acids are:

HBr - hydrobromic acid

HCHO₂ - formic acid

The dissociation reactions for these acids are:

HBr → H⁺ + Br⁻

HCHO₂ → H⁺ + CHO₂⁻

The concentrations of the two acids are given as:

[HBr] = 0.115 M

[HCHO₂] = 0.125 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from HBr] + [H⁺ from HCHO₂]

[H⁺] = [HBr] + [HCHO₂]

[H⁺] = 0.115 M + 0.125 M

[H⁺] = 0.24 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.24)

pH ≈ 0.62

The chemical formulas for the two acids are:

HNO₂ - nitrous acid

HNO₃ - nitric acid

The dissociation reactions for these acids are:

HNO₂ → H⁺ + NO₂⁻

HNO₃ → H⁺ + NO₃⁻

The concentrations of the two acids are given as:

[HNO₂] = 0.150 M

[HNO₃] = 0.085 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from HNO₂] + [H⁺ from HNO₃]

[H⁺] = [HNO₂] + [HNO₃]

[H⁺] = 0.150 M + 0.085 M

[H⁺] = 0.235 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.235)

pH ≈ 0.63

The chemical formulas for the two acids are:

HCHO₂ - formic acid

HC₂H₃O₂ - acetic acid

The dissociation reactions for these acids are:

HCHO₂ → H⁺ + CHO₂⁻

HC₂H₃O₂ → H⁺ + C₂H₃O₂⁻

The concentrations of the two acids are given as:

[HCHO₂] = 0.185 M

[HC₂H₃O₂] = 0.225 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from HCHO₂] + [H⁺ from HC₂H₃O₂]

[H⁺] = [HCHO₂] + [HC₂H₃O₂]

[H⁺] = 0.185 M + 0.225 M

[H⁺] = 0.410 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.410)

pH ≈ 0.39

The chemical formulas for the two acids are:

CH₃COOH - acetic acid

HCN - hydrocyanic acid

The dissociation reactions for these acids are:

CH₃COOH → H⁺ + CH₃COO⁻

HCN → H⁺ + CN⁻

The concentrations of the two acids are given as:

[CH₃COOH] = 0.050 M

[HCN] = 0.050 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from CH₃COOH] + [H⁺ from HCN]

[H⁺] = [CH₃COOH] + [HCN]

[H⁺] = 0.050 M + 0.050 M

[H⁺] = 0.100 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.100)

pH = 1.00

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Aqueous solutions of aluminum chloride and sodium carbonate are combined to form carbon dioxide and sodium chloride.

When chemicals are combined, a chemical change known as a balanced chemical reaction takes place. The reactants, or the chemicals that are combined, are on the left side of the equation. The reaction's byproducts are on the right side.

Aluminum oxide, sodium chloride, and carbon dioxide gas bubbles are created when aluminum chloride and sodium carbonate combine.

When dissolved substances react, one (or more) solid products are produced, which is known as a precipitation reaction. These kinds of reactions, which are also occasionally known as double displacement, double replacement, or metathesis reactions, frequently involve the exchange of ions between ionic compounds in aqueous solutions.

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The complete question is

Write a balanced chemical equation: aqueous solutions of aluminium chloride and sodium carbonate are combined, producing aluminium carbonate.

Answer:

gasoline

Explanation:

The right response is gasoline

Because the ingredients are evenly distributed and do not settle over time, homogeneous combinations include tomato soup, sugar-water solution, and salt-water solution. Contrarily, gasoline is a heterogeneous mixture since it contains a variety of hydrocarbons and additives that may separate or settle over time.

The correct answer is "D - All of the above will dissolve in 1M HNO3". Magnesium carbonate (MgCO3), barium sulfate (BaSO4), and silver bromide (AgBr) all dissolve in 1M HNO3 solution.

This is because the nitric acid (HNO3) is a strong acid that dissociates completely in solution and is able to break down the ionic compounds of MgCO3, BaSO4, and AgBr. The correct answer is "D - All of the above will dissolve in 1M HNO3". Magnesium carbonate (MgCO3), barium sulfate (BaSO4), and silver bromide (AgBr) all dissolve in 1M HNO3 solution.

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When the concentration (absorbance) of reactants is doubled, the reaction rate and slope of the reaction will increase.

This is due to the increased availability of reactants, leading to more successful collisions between molecules. This in turn results in a faster reaction rate, and therefore a steeper slope. The reaction rate and slope of a reaction depend on the concentration of reactants. When the concentration (absorbance) of the reactants is doubled, the reaction rate increases, and the slope of the graph increases accordingly.

The rate of a reaction is the speed at which the reactants change into products.  If the reaction rate is high, the reaction will occur quickly, whereas if the reaction rate is low, the reaction will take longer to occur. When the concentration (absorbance) of the reactants is doubled, the reaction rate and slope of the graph increase. It occurs because the number of reactant particles available for collision increases.

Hence  increase in the number of reactant particles available for collision leads to more collisions per unit of time, and this increases the reaction rate.

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12.5 mol of the substance contains 7.53 x 10²⁴ formula units of calcium carbonate.

Calcium carbonate (CaCO₃) is a compound that consists of one calcium atom, one carbon atom, and three oxygen atoms. The formula unit of calcium carbonate contains one Ca atom, one C atom, and three O atoms. To calculate the number of formula units in 12.5 mol of calcium carbonate, we need to use Avogadro's number, which relates the number of particles (atoms, molecules, or formula units) in a given amount of substance.

Avogadro's number (Nₐ) is 6.022 x 10²³ particles/mol. Therefore, the number of formula units of calcium carbonate in 12.5 mol can be calculated as:

n = Nₐ * 12.5 mol

n = 6.022 x 10²³ particles/mol * 12.5 mol

n = 7.53 x 10²⁴ particles

Therefore, there are 7.53 x 10⁴ formula units of calcium carbonate in 12.5 mol of the compound.

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Answer: theres a 1 in 4 chance of that happening

Explanation:

The temperature in the atmosphere will rise as humidity rises. Only in the case of an exothermic chemical reaction will an increase in temperature slow down the reaction and thus reduce the percentage yield.

Energy is involved in all chemical reactions. When reactants break bonds, energy is released, and when products form new bonds, energy is released. Endothermic reactions are those in which less energy is released when new bonds form in the products than is required to break bonds in the reactants. Exothermic reactions are the polar opposite. In an exothermic reaction, breaking bonds in the reactants requires less energy than the energy released when new bonds form in the products.

The amount of water vapor in the air is referred to as humidity. The humidity will be high if there is a lot of water vapor in the air. The higher the humidity, the wetter the weather feels outside. Humidity is usually described as relative humidity in weather reports.

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Answer:

n = 0.012 moles

Explanation:

Recall that;

n = V note: V in dm³

22.4

V = 26.5 mL = 0.265 dm³

n = 0.265

22.4

n = 0.012 moles

\

1. Tetraphosphorus pentasulfide : P4S5

2. Dinitrogen monoxide: N2O

3. carbon monoxide: CO

4. Carbon disulfide : CS2

5. Hydrogen: H2

6. Phosphorus pentabromide: PBr5

7. Silicon hexabromide: SiBr6

8. Carbon tetrachloride: CCl4

9. Sulfur monoxide:  SO

10. Sulfur dioxide: SO2

A compound whose atoms are bonded via a covalent bond is known as a covalent compounds.

A covalent bond is described as a chemical bond that involves the sharing of electrons to form electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs.

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The amount of the original sample remaining would be between 1.50 and 3.00 grams. Option I.

To solve this problem, we can use the half-life formula:

N = N0 x (1/2)^(t/T)

where:

We are given N0 = 12.0 grams, T = 3.6 days, and t = 10 days. We can plug these values into the formula and solve for N:

N = 12.0 grams x (1/2)^(10/3.6)

N ≈ 1.50 grams

Therefore, about 1.50 grams of the original sample remains after 10 days. The answer is between 1.50 and 3.00 grams.

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The response is C. 400mL of 5% glucose solution requires 20g of glucose to make.

To prepare 400mL of 5% glucose solution, we need to determine the amount of glucose required.

5% glucose solution means that 5g of glucose is present in 100mL of the solution.

Therefore, for 400mL of the solution, the amount of glucose required can be calculated as:

5g glucose/100mL solution = x g glucose / 400mL solution

x = (5g glucose/100mL solution) x (400mL solution) = 20g glucose

Therefore, the answer is D. 20g of glucose is needed to prepare 400mL of 5% glucose solution.

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Answer:

o solve this problem, we need to first write a balanced chemical equation for the reaction between C₂H6 and O₂:

C₂H6 + O₂ → CO₂ + H₂O

From the equation, we can see that for every mole of C₂H6 that reacts, one mole of water is produced.

Next, we need to determine how many moles of C₂H6 we have:

15.9 g C₂H6 × (1 mol C₂H6 / 30.07 g C₂H6) = 0.529 mol C₂H6

Finally, we can use the mole ratio between C₂H6 and H₂O to calculate the number of moles of water produced:

0.529 mol C₂H6 × (1 mol H₂O / 1 mol C₂H6) = 0.529 mol H₂O

Therefore, the answer is A) 0.667 mol (rounded to three significant figures).

Explanation: