The charge of 10,325,500 coulombs is needed to produce 53.5 mol of solid zinc.
What is the coulomb charge?The coulomb is the unit of electric charge in the International System of units and is represented by 'C'. In the S.I., it is equal to the electric charge delivered by a 1-ampere constant current in 1 second and to elementary charges, about 6.2×10¹⁸ e.
The coulomb in terms of the ampere and second can be described as 1 C = 1 A × 1 s. The SI base units fixed the numerical value of the elementary charge expressed in coulombs.
Solid zinc can be formed by chemical reactions:
Zn²⁺ + 2e⁻ → Zn (s)
One mole of zinc is produced by using two moles of electrons.
One mole of electrons is equal to one faraday electricity.
Then, the total electrons required = 2×53.5 = 107 F
The charge (in coulombs) on one mole of electrons = 96500 C
Amount of charge required to form zinc = 96500 × 107 = 10,325,500 C
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DUE IN 9 MINUTES HELP
The reaction written below has a ΔH of +2,962 kJ/mol
6CO2(g) + 6H2O(g) --> C6H12O6(g) +6O2(g)
How much energy must be input into this reaction to make 58.9 grams of C6H12O6(g) ?
The amount of heat energy that must be inputted into the reaction to make 58.9 grams of C₆H₁₂O₆ is 968.574 KJ
How to determine the amount of heat energyWe'll begin by obtainig the number of mole of 58.9 grams of C₆H₁₂O₆. This can bbe obtained as follow:
Mass of C₆H₁₂O₆ = 58.9 grams Molar mass of C₆H₁₂O₆ = (6 × 12) + (12 × 1) + (16 × 6) = 180 g/molMole of C₆H₁₂O₆ =?Mole = mass/ molar mass
Mole of C₆H₁₂O₆ = 58.9 / 180
Mole of C₆H₁₂O₆ = 0.327 mole
Finally, we shall determine thhe heat energy needed.
The balanced equation for the reaction is given below:
6CO₂(g) + 6H₂O(g) → C₆H₁₂O₆(g) + 6O₂(g) ΔH = +2962 KJ/mol
From the balanced equation for above,
1 moles of C₆H₁₂O₆ was produced by 2962 KJ of heat energy.
Therefore,
0.327 mole of C₆H₁₂O₆ will be produce by = (0.327 × 2962) / 1 mole = 968.574 KJ of heat energy
Thus, 968.574 KJ of heat energy is needed for the reaction
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Select the answer that correctly describes the masses the subatomic particles from lightest to having.
1) Subatomic particles. Atoms are made up of smaller parts called subatomic particles. Proton, neutron, and electron are some of them.
Electron: 9.11*10^-31 kg.
Proton: 1.672 18*10^-27 kg.
Neutron: 1.674 93*10^27 kg.
The lightest subatomic particle is the electron, then comes the protons, and finally the electron.
explain the process of photosynthesis with these
Words:
Photosynthesis,
light,
water,
energy,
Carbon Dioxide,
Oxygen,
xylem,
stomata,
Sugar(Glucose),
phloem,
chloroplasts,
leaves,
roots
Be legible and neat please and thank you
The process of photosynthesis used by plant in which they produce sugar ( glucose ).
Photosynthesis is the process in which plants produced sugar by using sun - light , water and carbon dioxide. In the process of photosynthesis plants use carbon dioxide ( CO₂ ) and water H₂O from the air and the soil then this carbon dioxide and water transforms to oxygen and sugar (glucose). the oxygen produced by plant back into the air and the sugar produces stores by the plant as the form of energy.
sunlight
carbon dioxide + water --------------> glucose + oxygen
In the leaf cell a part called chloroplast in it energy in sunlight used to break oxygen and hydrogen. T he water required in the process of photosynthesis taken by the roots from soil and then it transport with the help of xylem cell to the different parts of plant. phloem takes sugar from leaves to different parts of plant. The stomata is for the transpiration exchange that means it takes carbon dioxide and the release oxygen back to air after the photosynthesis end.
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Propane (C3H8) is a component of natural gas and is used in domestic cooking and heating. It burns according to the following reaction:
C3H8 + O2 → CO2 + H2O
a. Balance the equation representing the combustion of propane in air.
b. How many grams of carbon dioxide can be produced by burning 20.0 pounds of propane, the typical size of a BBG grill propane tank?
Assume that oxygen is the excess reagent in this reaction.
A. The balanced equation for the reaction is given as
C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O
B. The mass (in grams) of carbon dioxide that can be produced by burning 20.0 pounds of propane is 27216.49 g
A. Balance equation
The balanced equation for the combustion of propane is:
C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O
B. How to determin the mass (in grams) of CO₂ produced
The mass (in grams) of CO₂ produced from the reaction can be obtained as follow:
Molar mass of C₃H₈ = (12 × 3) +(8 × 1) = 44 g/molMass of C₃H₈ from the balanced equation = 44 × 1 = 44 g = 44 / 453.592 = 0.097 poundMolar mass of CO₂ = 12 + (16 × 2) = 44 g/molMass of CO₂ from the balanced equation = 3 × 44 = 132 gFrom the balanced equation above,
0.097 pound of C₃H₈ reacted to produce 132 g of CO₂
Therefore,
20 pound of C₃H₈ will react to produce = (20 × 132) / 0.097 = 27216.49 g of CO₂
Thus, the mass of CO₂ produced is 27216.49 g
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Find the molecular formula for a compound that contains 4.90 % N and 11.2 % O. The molecular mass of the compound is 92.0 g/mol.
The molecular formula for the compound that contains 4.90 g N and 11.2 g O is N₂O₄
How to determine molecular formulaWe'll begin by obtaining the empirical formula for the compound. This is illustrated below:
Nitrogen (N) = 4.90 gOxygen (O) = 11.2 gEmpirical formula =?Divide by their molar mass
N = 4.9 / 14 = 0.35
O = 11.2 / 16 = 0.7
Divide by the smallest
N = 0.35 / 0.35 = 1
O = 0.7 / 0.35 = 2
Thus, the empirical formula of the compound is NO₂
Finally, we shall determine the molecula formula. Details below
Molar mass of compound = 92 g/molEmpirical formula = NO₂Molecular formula =?Molecular formula = empirical × n = molar mass
[NO₂]ₙ = 92
[14 + (16×2)]ₙ = 92
46n = 92
Divide both side by 46
n = 92 / 46
n = 2
Molecular formula = [NO₂]ₙ
Molecular formula = [NO₂]₂
Molecular formula = N₂O₄
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Complete question:
Find the molecular formula for a compound that contains 4.90 g N and 11.2 g O. The molar mass of the compound is 92.0 g/mol.
Limestone is a sedimentary rock composed largely of the mineral calcite, (calcium carbonate) CaCO3. To test the purity of the calcium carbonate, a sample of the mineral is reacted with hydrochloric acid to produce calcium chloride, carbon dioxide and water If a 15.70 g sample of calcite is reacted with excess hydrochloric acid and 16.89 g of calcium chloride are produced, what is the percent by mass of the calcium carbonate in the limestone? A) 69.4% B)93.0 % C) 96.94% D)98,22 %
Answer:
[tex]C\text{ : 96.94 \%}[/tex]Explanation:
Here, we want to get the percentage by mass of calcium carbonate in the limestone
We start by writing an equation of chemical reaction
The reaction involves calcium carbonate reacting with hydrochloric acid to give calcium chloride, carbon dioxide and water
We have the equation as follows:
[tex]\text{CaCO}_{3(s)\text{ }}+2HCl_{(aq)}\rightarrow CaCl_{2(aq)\text{ }}+CO_{2(g)\text{ }}+H_2O_{(l)}[/tex]Now, let us work with the extra information
16.89 g of calcium chloride are produced
Let us get the number of moles of calcium chloride produced
We can get that by dividing the mass by the molar mass of calcium chloride
The molar mass of calcium chloride is 111 g/mol
So, the number of moles will be:
[tex]\frac{16.89}{111}\text{ = 0.1522 mole}[/tex]From the equation,
1 mole of calcite gave 1 mole of calcium chloride, then 0.1522 mole of calcium chloride was produced by 0.1522 mole of calcite
To get the mass of calcite that produced this, we have to multipply the number of moles by the molar mass of calcite
The molar mass of calcite is 100 g/mol
That means the mass of calcite that produced the calcium chloride will be:
[tex]0.1522\text{ }\times\text{ 100 = 15.22 g}[/tex]What this mean is that 15.22 g of calcite produced the given mass of calcium chloride
The percentage by mass of calcite in the limestone will be:
[tex]\frac{15.22}{15.70}\times\text{ 100\% = 96.94 \%}[/tex]Two different signs that indicate a chemical action has occurred. What time is showing in the picture on the left what sign is showing on the picture in the right?
The reaction that occurs on the left is called a single displacemt reaction
Light below the necessary critical frequency doesn't eject electrons from metal because
Light below the necessary critical frequency doesn't eject electrons from metal because no electrons will be emitted when the light shines on the metal.
What is Frequency?This is a term in physics which is used to describe the number of occurrences of a repeating event per unit of time.
The amount of energy which is present in each photon in the beam is determined by and proportional to the frequency of the beam. This therefore means that if there is light which is below the threshold frequency, there will be no electrons emitted when light shines on the metal thereby making it the correct choice.
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find the natural logarithm of7.56
Predict the shape of the molecule around the indicated atom.
Answer:
Linear (180 degrees)
Explanation:
Whenever you have a triple bond between two atoms, their shape is linear. This is because the density of the triple bond between them is heavy, causing the other things attached to the atom to be as far away as possible, creating a linear structure.
What volume of carbon dioxide (in L) will 2.00 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction?
CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)
The volume of carbon dioxide (in L) that can be made from the 2.00 g of the antacid is 5.09 L
How to determine the volume of CO₂We'll beging by obtaining the mole of CO₂ produced. This can be obtained as follow:
Mass of CaCO₃ = 2 gMolar mass of CaCO₃ = 100 g/mole Mole of CaCO₃ = 2 / 100 = 0.02 moleCaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)
From the balanced equation above,
1 mole CaCO₃ reacted to produce 1 mole of CO₂.
Therefore,
0.02 mole CaCO₃ will also react to produce 0.02 mole of CO₂.
Finally, we shall determine the volume of the CO₂ produced. Details below.
Number of mole (n) = 0.02 moles Pressure (P) = 1 atm Temperature (T) = 37 °C = 37 + 273 = 310 KGas constant (R) = 0.0821 atm.L/Kmol Volume (V) =?PV = nRT
1 × V = 0.02 × 0.0821 × 310
V = 5.09 L
Thus, the volume obtained is 5.09 L
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# 19. Write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.
(a) Write the correct formulas for the molecular equation (b) balance the equation (c) identify the spectator ions (d) Write the ionic equation and (e) Write the net ionic equation.
The general molecular equation is; [tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex] while the net ionic equation is; [tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]
What is a reaction?We can define the term reaction as the interaction that occurs between the reactants and helps us to be able to get a product as shown. Now we have a case in which we are asked to write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.
The task now is to make use of the ideas that we have from the question to be able to determine both the molecular reaction equation as well as the net ionic equation as required.
Let us no take the reaction individually. We can write the molecular reaction as;
[tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex]
After we have written the molecular reaction equation, then we can identify the spectator ions as acetate ion and the sodium ion as we can see from the balanced reaction equation.
The net ionic equation therefore is;
[tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]
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What volume of Cl2 gas, measured at 688 torr and 36 °C, is required to form 22 g of NaCl?Express your answer using two significant figures.
ANSWER
Volume of the gas 5.3L
EXPLANATION;
Given that
The pressure of the chlorine gas is 688 torr
The temperature of the chlorine gas is 36 degrees Celcius
The mass of NaCl is 22 grams
Follow the steps below to find the volume of chlorine gas
Step 1; Write a balanced equation for the reaction
[tex]\text{ 2Na + Cl}_2\text{ }\rightarrow\text{ 2NaCl}[/tex]In the above reaction, 2 moles of Na react with 1 mole of chlorine to form 2 moles of NaCl
Step 2; Find the number of moles of NaCl using the below formula
[tex]\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of NaCl is 58.44 g/mol
[tex]\begin{gathered} \text{ mole = }\frac{22}{\text{ 58.44}} \\ \text{ moles = 0.376 mole} \end{gathered}[/tex]Step 3; Find the number of moles of Cl2 using a stoichiometry ratio
Let x represents the number of moles of Cl2
[tex]\begin{gathered} 1\text{ mole Cl}_2\text{ }\rightarrow\text{ 2 moles NaCl} \\ \text{ x moles Cl}_2\rightarrow\text{ 0.376 moles NaCl} \\ \text{ cross multiply} \\ \text{ x moles Cl}_2\text{ }\times2\text{ moles NaCl }=\text{ 1 mole Cl}_2\text{ }\times\text{ 0.376 mole NaCl} \\ \text{ Isolate x} \\ \text{ x = }\frac{\text{ 1 mole Cl}_2\times0.376moles\cancel{NaCl}}{2moles\cancel{NaCl}} \\ \\ \text{ x = }\frac{1\text{ }\times\text{ 0.376}}{2} \\ x\text{ = }\frac{0.376}{2} \\ \text{ x = 0.188 mol} \end{gathered}[/tex]The number of moles of Cl2 is 0.188 mol
Step 4; Find the volume of the gas using the ideal gas equation
[tex]\text{ PV = nRT}[/tex]Convert the temperature to degree kelvin
[tex]\begin{gathered} \text{ t = 36}\degree C \\ \text{ T = 36 + 273.15} \\ \text{ T = 309.15 K} \end{gathered}[/tex]Step 5; Find the volume of the gas
[tex]\begin{gathered} \text{ PV = nRT} \\ \text{ Recall, that R = 62.363 L. torr mol}^{-1}K^{-1} \\ \text{ 688}\times\text{ V =}^{\text{ }}0.188\text{ x 62.636 }\times\text{ 309.15} \\ \text{ 688 V = 3624. 500} \\ V\text{ = }\frac{\text{ 3645, 500}}{688} \\ \text{ v = 5.3 L} \end{gathered}[/tex]Therefore, volume of the gas 5.3L
A 25.0 mL solution of HNO₃ is neutralized with 31.4 mL of 0.250 M Ba(OH)₂. What is the concentration of the original HNO₃ solution?
The concentration of the 25ml of original HNO₃ solution that was neutralized with 31.4 mL of 0.250 M Ba(OH)₂ is 0.628 M HNO3
The neutralization reaction involved with HNO₃ and Ba(OH)2 is
Ba(OH)₂ + 2HNO₃---> Ba(NO₃) + 2H₂O.
From the balanced equation of the reaction, we can say that to neutralize barium hydroxide (Ba(OH)₂) we would require 2 moles of Nitric acid (HNO₃)
By multiplying concentration of barium hydroxide by volume its volume, and then multiplying by 2 as twice is required we would get the moles of HNO3 that is equivalent to 2 moles based on the values
Moles of HNO₃ = 2 (0.0314 * 0.250) = 0.0157 moles
Concentration of the original HNO₃ solution = 0.0157 moles / 0.025 L = 0.628 M HNO₃
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PLEASE HELP, IT’S DUE TODAY!
Isotopes of certain ___ elements that spontaneously emit ____ and ____ from the _____.
Isotopes of certain __radioactive__ elements that spontaneously emit __radiation__ and _rays___ from the __nuclei____
What causes isotopes to emit radiation ?Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.
Isotopes are identical elemental atoms with differing quantities of neutrons. Numerous elements have one or more radioactive isotopes. Due to the instability of their nuclei, they decay and release radiation.Many of the radioisotopes in the uranium, thorium, and actinium natural radiation decay series, as well as the naturally occurring radioisotopes potassium-40 and carbon-14, generate gamma radiation.Learn more about Isotopes here:
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a sample of argon has a volume of 4.95 L and the pressure is 0.92 atm if the final temperature is 30 C the final volume is 5.7 L and the final pressure is .092 atm what was the initial temperature of the argon
The initial temperature of the argon is 2678 K
Given that,
Initial volume (V1) = 4.95 L
Initial pressure (P1) = 0.92 atm
Final temperature (T2) = 30 C = 303.15 K
Final volume (V2) = 5.7 L
Final pressure (P2) = 0.092 atm
We need to find the Initial temperature of the argon represented as T1
We Know that, In ideal gas law: PV = nRT
It can be written as, P1V1 / T1 = P2V2 / T2
(0.92 * 4.95) / T1 = (0.092 * 5.7) / 303.15
4.554 / T1 = 0.5244 / 303.15
4.554 / T1 = 0.0017
T1 = 4.554 / 0.0017
T1 = 2678 K
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In the following equation, how many grams of CO2 are produced if 2 moles of O2 react completely with methane (CH4)? CH4 + 2O2 -> CO2 + 2H2OHELPFUL INFO: molar mass of CO2=44g/mol, molar mass of O2=32g/mol, molar mass of CH4=16g/mol, and molar mass of water = 18g/mol
Step 1 - "Reading" the equation
The given chemical equation is:
[tex]CH_{4(g)}+2O_{2(g)}\to CO_{2(g)}+2H_2O_{(l)}[/tex]The bigger numbers, those that come before the formulas of the substances, indicate the quantity in moles of each substance required in this rection.
We can "read" this reaction thus as :
one mole of CH4 reacts with 2 moles of O2 thus producing one mole of CO2 and two moles of H2O
As the exercise is specifically asking about the proportion between O2 and CO2, we can further simplify this statement to:
two moles of O2 produce one mole of CO2
Step 2 - Obtaining the "recipe" for the reaction
In order to obtain a relation in grams, we need to multiply the number of moles of each substance by its respective molar mass. Let's remember that:
two moles of O2 produce one mole of CO2
Therefore, converting to grams (molar masses: 32 g/mol for O2; 44 g/mol for CO2)
[tex]\begin{gathered} O_2\to2\text{ moles }\times32\text{ g/mole = 64g} \\ CO2\to1\text{ mole }\times44\text{ g/mole = 44g} \end{gathered}[/tex]We have now obtained the "recipe" for this reaction:
64g of O2 produce 44g of CO2
Pretty much as we would with a cake recipe, we can use this to predict how much CO2 is formed.
Since the reaction of two moles of O2 is exactly what we have already calculated, 44g of CO2 would be formed in this reaction.
How many pounds in 16.1lbmol of pure HCl
Answer:
586.846 lbs
Explanation:
the molar mass of HCl is 1 + 35.45 = 36.45
this means you can do 16.1 lbmol * 36.45 lb/lbmol = 586.845
500 ml of an unknown concentration of KOH solution and 250 ml of 0.01 ml were mixed KOH solution.
The pH of the resulting solution is 12.7. Calculate the concentration of the first KOH solution.
Answer:
262
Explanation:
Which of the listed species have the following electron configuration?
(See attached)
Answer:
Al 3+
Na+
Mg2+
F-
Explanation:
The element with the given electron that isn't an ion is Neon. It has 10 electrons in total.
Looking at the periodic table attached will help to see how the elements below are related to the one circled in red (Ne).
Al 3+ lacks 3 (because it has a 3+ charge) of its normal electrons so it has 10 and will have the same electron configuration as shown.
Na+ lacks one electron so it will also have 10 electrons instead of its normal 11.
Mg 2+ lacks two electrons so it will also have 10 total electrons.
F- has gained an extra electron so it now has 10 instead of 9.
Al3+, Na+, F-, and Mg2+ will have the given electronic configuration.
The electronic configuration given in the question is:
2p6, 2s2, 1s2
If it was a stable atom, the answer would have been Neon.
And if that would have been negative ion or anion (to be precise),
the answer would have been either F- or O2-.
But in the case of positive ions or we can say cations,
Al3+, Na+, and Mg2+ have the given electronic configurations.
Because the atom of Aluminum loses three electrons to achieve another state which is responsible for the formation of Al3+.
Similarly,
The atoms of Sodium and Magnesium also lose one and two electrons respectively to form Na+ and Mg2+.
So, we can conclude that Al3+, Na+, F- and Mg2+ will have the given electronic configuration.
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how many grams of CO2 are in 5.67 moles of CO2
The International System of Units uses the mole (symbol: mol) as the unit of substance amount.
In 5.67 moles of CO2 there exists 249.48 grams of CO2.
How to calculate grams in moles?Start by dividing the number of atoms by the atomic weight of each component of the compound to convert grams to moles. After that, tally up all of your responses to determine the compound's molar mass. The final step is to calculate the number of moles by dividing the number of grams of the compound by its molar mass.
The International System of Units uses the mole (symbol: mol) as the unit of substance amount. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that substance.
Let the equation be
Mass = relative atomic mass × mole number
substitute the values in the above equation, we get
= 5.67 × (12 + 16 + 16)
= 249.48 g
Therefore, there exists 249.48 grams of CO2 are in 5.67 moles of CO2.
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Which two types of information are written in an element's box in the periodic
table?
A. Atomic mass
B. Number of electron shells
C. Nuclear composition
D. Chemical symbol
Answer:
b d my good mannnnnnnnnnnn
Terrance found a small hair on the victim’s shirt. What type of evidence does this BEST represent?
A.
trace evidence
B.
biological evidence
C.
ammunitions evidence
D.
impression evidence
Answer:
Biological evidence, since it was a hair, which forms part of the human
Calculate the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy (Note => 16.0 um = 16.0 * 10^6 m & 2.3KJ = 2300 J)
The number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹
What are photons?Photons are defined as a basic particle that is both the force carrier for the electromagnetic force and a quantum of the electromagnetic field, which includes electromagnetic radiation like light and radio waves.
It can also be defined as a discrete bundle of electromagnetic energy is what is known as a light particle.
Energy = 2.3 KJ
Wavelength = 16.0 x 10⁶ m
Energy = hc / ∧
= 6.63 x 10²⁴ x 3 x 10³ / 16.0 x 10⁶
= 1.24 x 10¹⁹ J
Number of photons used = 2.3 KJ / 1.24 x10¹⁹
= 1.85 x 10¹⁹
Thus, the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹
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Given the following equation, if I make 18.5G of iron (III) sulphate, what is the percent yield? I picked B but I’m not sure if I’m correct
Answer:
B. The percent yield is 55.9%.
Explanation:
From the balanced reaction we know that 2 moles of FePO4 produce 1 mole of Fe2(SO4)3.
1st) It necessary to convert moles into grams, using the molar mass of FePO4 (151g/mol) and the molar mass of Fe2(SO4)3 (400g/mol):
- FePO4 conversion:
[tex]2moles*\frac{151g}{1mole}=302g[/tex]- Fe2(SO4)3 conversion:
In this case, it is not necessary the conversion, because there is 1 mole, so it is equal to 400g.
Now we know that 302g of FePO4 produce 400g of Fe2(SO4)3.
2nd) Now we have to calculate the Theoretical yield of Iron (III) sulfate, that is, the amount of Iron (III) sulfate that we must produce from 25g of Iron (III) phosphate:
[tex]\begin{gathered} 302gFePO_4-400gFe_2(SO_4)_3 \\ 25gFePO_4-x=\frac{25gFePO_4*400gFe_2(SO_4)_3}{302gFePO_4} \\ x=33.11gFe_2(SO_4)_3 \end{gathered}[/tex]So, the Theoretical yield is 33.11g.
3rd) Finally, we can calculate the Percent yield using the Theoretical yield (33.11g) and the Actual yield (18.5g):
[tex]\begin{gathered} PercentYield=\frac{ActualYield}{TheoreticalYield}*100\% \\ PercentYield=\frac{18.5g}{33.11g}*100\% \\ PercentYield=55.9\% \end{gathered}[/tex]So, the percent yield is 55.9%.
need help on chem homework
What is the relationship between n, ℓ, and the total number of nodes?
The number of planar nodes = ℓ.
The number of spherical nodes = n - ℓ - 1.
The relationship between the number nodes, the energy level n and the azimuthal quantum number l is (n-l -1) + l. Thus the total number of nodes is n-1.
What is node?Node is the region or point in the orbital where the probability of finding an electron is zero. Electrons are revolving around circular paths of fixed energy levels.
The principal quantum number n represents the number of main shells or the energy level of the electrons. Whereas, azimuthal quantum number represents the number of orbitals denoted as l.
The point where there is a probability of finding an electron is called antinode. The total node in an orbital is the sum of number of planar nodes and number of spherical nodes.
Thus total number of nodes = (n-l-1) + l
= n - 1.
Therefore, the total number of nodes is n-1. For example for n=3 level there will be two nodes.
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balanced chemical equation for .1 M barium nitrate and .1 m sodium sulfate
The balanced chemical equation for 0.1 M barium nitrate and 0.1 M sodium sulfate is -
2 Ba(NO₃)₂ + 2 Na₂SO₄ → 2 Ba(SO₄) + 2 NaNO₃
Balanced chemical equation are the equations having equal amount of reactants and the products formed. The reactants are placed on the left and products are placed on right forming a balanced chemical equation.
When 0.1 M barium nitrate reacts with the 0.1 M sodium sulfate, it gives an insoluble salt of barium sulfate and soluble salt of sodium nitrate as the product. This reaction is a type of precipitation reaction as precipitate is formed in the reaction. It is a double displacement reaction because the sulfate ions replace the nitrate ions to give the product.
Barium sulfate is known to be the most insoluble compound. It is formed as a precipitate.
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For the following equations you will be given the names of reactants and products. In the space below each reaction provide theformulas of each reactant and product along with coefficients.
Explanation:
First, let's write the formulas:
Potassium chlorate: KClO3
Oxygen: O2
Potassium chloride: KCl
So the reaction will be:
KClO3 -> O2 + KCl
Now let's balance it.
To balance the equation it is necessary to have the same number of atoms of each element on both sides of the equation (reactant side and product side). Let's count the number of atoms of each element for the unbalanced equation: KClO3 -> O2 + KCl
Reactant side:
K - 1
Cl - 1
O - 3
Product side:
O - 2
K - 1
Cl - 1
As you can see, oxygen number of atoms is not equal on both sides of the equation. Let's balance it by changing the stoichiometric coefficient.
2KClO3 → 2KCl + 3O2
Let's count the number of atoms of each element for the balanced equation.
Reactant side:
K - 2
Cl - 2
O - 6
Product side:
K - 2
Cl - 2
O - 6
Now the equation is balanced.
Answer: 2KClO3 → 2KCl + 3O2
Coefficients are: 2, 2 and 3.
0.650 moles of O₂(g) are added to 1.00 L flask and the internal pressure ismeasured at 20.00 atm. What is the temperature of the gas under theseconditions (in *C)? ________ °C?
1) List the known and unknown quantities.
Sample: O2
Amount of substance: 0.650 mol O2.
Volume: 1.00 L.
Pressure: 20.00 atm.
Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)
Temperature: unknown.
2) Set the equation.
Ideal gas law.
[tex]PV=nRT[/tex]3) Plug in the known quantities and solve for T.
[tex](20.00\text{ }atm)(1.00\text{ }L)=(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(T)[/tex][tex]T=\frac{(20.00atm)(1.00L)}{(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}[/tex][tex]T=374.97\text{ }K[/tex]4) Convert K to ºC.
[tex]ºC=K-273.15[/tex][tex]ºC=374.94-273.15[/tex][tex]ºC=101.81\text{ }ºC[/tex]The temperature of the gas under these conditions is 101.81ºC.
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According to the label on a soft drink, one serving provides 185 kcal. If all of this energy is used to lift 1.0-kg blocks, how many blocks can be lifted 7.0 meters? Note: 1 J is approximately equal to the energy required to raise a 1-kg block a distance of 10 cm against Earth’s gravity.
The number of blocks that can be lifted through this height is 11563 blocks.
How many blocks can be lifted?We know that we define the term energy as the ability to do work, Now we have to consider the fact that we are told that one serving provides 185 kcal. Then we are told that all of this energy is used to lift 1.0-kg blocks through a distance of 7.0 meters.
Given that the energy exerted in lifting each block is;
mgh
m = mass of the block
g = acceleration due to gravity
h = height lifted through
E = 1.0-kg * 9.8 m/s^2 * 7.0 meters = 68.6 J or 0.016 kcal
The number of blocks that can be lifted = 185 kcal/ 0.016 kcal
= 11563 blocks
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