heyyyy! can some tell me if im right?​

Answer:

It is A, B, and C

Explanation:

I just took the test!

The three characteristics mechanical waves and electromagnetic waves share are:

A. The waves begin with a disturbance.

B. The waves transfer energy from its source.

C. The waves and their energy move outward from the source.

       Usually, waves transfer energy from one place to another. Mechanical waves transfers via matter where as electromagnetic waves transfers via light. Both mechanical waves and electromagnet (light) waves measured through amplitude, wavelength, frequency and both will get transmitted, refracted, reflected, absorbed, diffracted when they react with matter. Both the electromagnetic waves and mechanical waves are transverse in nature but the mechanical waves can also be in longitudinal.

So, many characteristics were similar for mechanical waves and electromagnetic waves.

Hence, Option A, B, C are the three characteristics.

Learn more about the waves,

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Answer:

I nEeD heLp

Explanation:

HelP

Answer:

Radiation wave

Explanation:

weeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee true eeeeeeeeeeeeeeeeeeeee

Answer:

true

Explanation:

sorry if im wrong

Answer:120j

Explanation:

The amount of work must a 60 kg runner do to accelerate from rest to a velocity of 2 m/sec is 120 joules.

To find the work done, the given values are,

Mass = 60 kg

Velocity = 2 m/sec.

The amount of work can be expressed by the Kinetic energy of the runner. Energy can be defined as the capacity of an object or physical body to perform work. Thus, energy is typically measured in Joules (J).

Kinetic energy can be regarded as form of energy posses by an object when it's in motion.

Total energy = kinetic energy + potential energy

Thus, Kinetic Energy, KE = (1/2) (m) (v²)

KE =1/2 (60 kg) (2² m²/s²)

KE = 120 Joules.

That's the amount of energy that has to come from somewhere, in order to boost him to that speed.

The amount of work must a 60 kg runner do to accelerate from rest to a velocity of 2 m/sec is 120 joules.

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The total (PE+ KE) before an event is equal to the total (PE+ KE) after the event.

Hence, the correct option is C.

If the total (PE + KE) before an event is equal to the total (PE + KE) after the event, this means that the total energy of the system is conserved. This is known as the principle of conservation of energy.

It is not necessary for the potential energy to remain constant or for the potential energy before the event to equal the kinetic energy before the event. Rather, the total energy (the sum of potential and kinetic energy) of the system must be conserved.

Similarly, it is not necessary for the momentum to remain constant in this case. The conservation of momentum is a separate principle that applies when there are no external forces acting on the system.

Hence, the correct option is C.

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Answer:

800 pixels

Explanation:

400*200=800

Answer: True

Explanation: Light enters your eye through the lens which then hits the retina which is located in the back of your eye.

Answer:

The distance covered along the horizontal axis is [tex]s = 360 \ m[/tex]

The distance covered along the vertical  axis is  [tex]h = 78.4 \ m[/tex]

Explanation:

From the question we are told that  

    The horizontal velocity is  [tex]u_x = 90 \ m/s[/tex]

     The time considered is  [tex]t = 4 \ s[/tex]

Generally the distance which the bullet will cover in the horizontal direction for the given time is  mathematically represented as

    [tex]s = u_xt + \frac{1}{2}* at^2[/tex]

Here a is the acceleration along the horizontal direction and the value is  [tex]a = 0 \ m/s^2[/tex]

So

     [tex]s = 90 * 4 + \frac{1}{2}* * 0 * 4^2[/tex]

=>  [tex]s = 360 \ m[/tex]

Generally the distance which the bullet will cover in the vertical  direction for the given time is  mathematically represented as

            [tex]h= u_y t + \frac{1}{2}* gt^2[/tex]

Here  [tex]u_y[/tex] is the initial  velocity of the bullet along the vertical axis and the value is  [tex]u_y = 0 \ m/s[/tex]

             [tex]h = 0 * 4 + \frac{1}{2}* 9.8 *4^2[/tex]

=>          [tex]h = 78.4 \ m[/tex]

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

v is the velocity

m is the mass

From the question we have

[tex]k = \frac{1}{2} \times 1300 \times {20}^{2} \\ = 650 \times 400 \\ = 260000[/tex]

We have the final answer as

Hope this helps you

Answer:

atomic weight 20.180

protons 10

neutrons 2,8

Explanation:

Answer:

Correct choice: b 4H

Explanation:

Conservation of the mechanical energy

The mechanical energy is the sum of the gravitational potential energy GPE (U) and the kinetic energy KE (K):

E = U + K

The GPE is calculated as:

U = mgh

And the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

g = gravitational acceleration

h = height of the object

v = speed at which the object moves

When the snowball is dropped from a height H, it has zero speed and therefore zero kinetic energy, thus the mechanical energy is:

[tex]U_1 = mgH[/tex]

When the snowball reaches the ground, the height is zero and the GPE is also zero, thus the mechanical energy is:

[tex]\displaystyle U_2=\frac{1}{2}mv^2[/tex]

Since the energy is conserved, U1=U2

[tex]\displaystyle mgH=\frac{1}{2}mv^2 \qquad\qquad [1][/tex]

For the speed to be double, we need to drop the snowball from a height H', and:

[tex]\displaystyle mgH'=\frac{1}{2}m(2v)^2[/tex]

Operating:

[tex]\displaystyle mgH'=4\frac{1}{2}m(v)^2 \qquad\qquad [2][/tex]

Dividing [2] by [1]

[tex]\displaystyle \frac{mgH'}{mgH}=\frac{4\frac{1}{2}m(v)^2}{\frac{1}{2}m(v)^2}[/tex]

Simplifying:

[tex]\displaystyle \frac{H'}{H}=4[/tex]

Thus:

H' = 4H

Correct choice: b 4H

Answer:

5 years worth of work (aka all of the homework i currently have)

Answer:

B

Explanation:

in comparison, the sun is a soccer ball, and the earth is a head of a needle, and the moon is a speck of salt

Answer:

B. [tex]F = -k*x[/tex]

Explanation:

The force of a spring can be easily calculated using Hooke's law which tells us that the force applied on a spring is equal to the product of the constant of a spring by the compressed or stretched distance of the spring.

That is:

[tex]F = k*x[/tex]

k = spring constant [N/m]

x = distance [m]

Answer:

increased by a factor of 4

Explanation:

Answer:

The value is  [tex]h = 13.2 \ m[/tex]

Explanation:

From the question we are told that

    The speed of the rope with hook is [tex]u = 24 .1 \ m/s[/tex]

     The angle is  [tex]\theta = 65.0^o[/tex]

      The speed at which it hits top of the wall is  [tex]v = 16.3 m/s[/tex]

Generally from kinematic equation we have that

      [tex]v_y^2 = u_y ^2 + * 2 (-g)* h[/tex]

Here h is the height of the wall so

      [tex][16.3 sin (65)]^2 = [24.1 sin (65)] ^2+ 2 (-9.8)* h[/tex]

=>    [tex]h = 13.2 \ m[/tex]

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{p}{v} \\ [/tex]

p is the momentum

v is the velocity

From the question we have

[tex]m = \frac{10}{20} = \frac{1}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

a=(v-u)/t is how you find acceleration.

Answer: volume of an object???

Explanation:

Answer:

Beryllium chloride

Explanation:

I hope this helps!

Can I get branliest?!

Answer:

Solids have a definite shape and volume, its particles vibrate slowly.

Liquids have no definite shape, the particles move randomly around its container, and they have a fixed volume.

Answer:

49N

Explanation:

F=ma

We know the mass is 5kg, and since the ball is suspended on one cable, the acceleration is g, 9.8m/s^2

F=5kg*9.8m/s^2

 = 49N

Hope this helps!

Answer:

La magnitud de la velocidad con la que Mjonir golpea el suelo es 93.2 m/s.

Explanation:

Podemos encontrar la velocidad con la que el martillo golpea el suelo usando la siguiente ecuación:

[tex] v_{f} = v_{0} - gt [/tex]   (1)

En donde:

[tex] v_{f}[/tex]: es la velocidad final =?

[tex] v_{0}[/tex]: es la velocidad inicial = 0 (lo deja caer)

g: es la gravedad = 9.81 m/s²

t: es el tiempo = 9.5 s

Al reemplazar los valores anteriores en la ecuación (1), tenemos:

[tex] v_{f} = 0 - 9.81 m/s^{2}*9.5 s = -93.2 m/s [/tex]                

El signo negativo se debe a que el vector velocidad está dirigido hacia abajo en el eje vertical (y).

Por lo tanto, la magnitud de la velocidad con la que Mjonir golpea el suelo es 93.2 m/s.

Espero que te sea de utilidad!

Answer:

Genetic engineering

Explanation:

Genetic engineering or also called genetic modification is the direct manipulation of an organism's genome in order to bring about a desirable trait in such organism. In genetic engineering procedure, the organism manipulated is called TRANSGENIC or GENETICALLY MODIFIED (GM) organisms.

In this case, a researcher is said to change the DNA (genetic material) in a soybean plant so that it produces offspring with a resistance to weed killer. This describes a genetic engineering procedure in which the soybean plant is manipulated to yield a desired trait, which is resistance to weed killer.

Answer:

A. genetic engineering

Explanation:

I took the quiz

Answer: 121.2 m/s

Explanation:

Here we will use the conservation of energy.

We can write the total energy of an object as:

E = K + U

For this particular case we have:

K = kinetic energy = (m/2)*v^2

U = potential energy = m*g*h

where:

m = mass of the object.

g = gravitational acceleration = 9.8m/s^2

h = height at which the object is dropped, in this case 750m

v = velocity of the object.

Right when the packet is dropped, it's velocity is equal to zero, this means that there is no kinetic energy and only potential energy, then we have:

Ei = Ui = m*9.8m/s^2*750m = m*(7350m^2/s^2)

And when the object is about to hit the ground, h will be almost equal to zero, this will mean that we will have only kinetic energy, and because of the conservation of energy, this final energy must be the same as the initial energy, then we will have

Ei = Ef

m*(7350m^2/s^2) = Ef = Kf

m*(7350m^2/s^2) = (m/2)*v^2

We can divide by m in both sides to get:

(7350m^2/s^2) = (1/2)*v^2

√( 2*(7350m^2/s^2)) = v = 121.2 m/s

Then the velocity of the packet when it reaches the ground is 121.2 m/s

Answer:

Explanation:

I think this answer would be 1m to the left.