Answers
Answer:
Yes, the shark's weight or mass is what causes the bottom string to break. The weight of the shark creates tension on the bottom string, which can cause it to snap if the tension becomes too great.
Related Questions
Comment on energy conservation in this diagram.
Answers
Energy conservation refers to the principle that energy cannot be created or destroyed; it can only be converted from one form to another or transferred between different systems.
This principle is based on the law of conservation of energy, also known as the first law of thermodynamics. In order to comment on energy conservation in a diagram.
Energy conservation refers to the practice of reducing energy consumption and using energy resources efficiently in order to minimize waste and environmental impact. It involves making conscious choices and adopting behaviors and technologies that aim to conserve energy and reduce energy-related costs.
Energy conservation is an important aspect of sustainable development and plays a vital role in mitigating climate change and promoting environmental sustainability.
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Part 3: Energy Conversions 7. Record your data in the chart and include at least 5 potential-kinetic energy conversions shown in your device's construction. Example Item Description of potential-kinetic energy conversion Example Book The book had gravitational potential energy when it was on the table. Then as the book fell off the table, it was in motion and had kinetic energy. 1 2 3 4 5
Answers
Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.
Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.
As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.
Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.
As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.
Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.
Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.
Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.
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A 2.0 cm tall object is placed 25 cm in front of a converging lens. The image is found 64 cm on the other side of the lens.
The focal length of the lens is ________.
0.011 cm
0.024 cm
41 cm
0.056 cm
18 cm
15 cm
Answers
Since focal length cannot be negative for a converging lens, we take the positive value: f ≈ 41 cm Option C
To determine the focal length of the lens, we can use the lens formula, which relates the object distance (u), image distance (v), and focal length (f) of a lens. The lens formula is given by:
1/f = 1/v - 1/u
In this case, the object distance (u) is 25 cm and the image distance (v) is 64 cm. We can substitute these values into the lens formula to solve for the focal length:
1/f = 1/v - 1/u
1/f = 1/64 cm - 1/25 cm
To simplify the equation, we can find a common denominator:
1/f = (25 - 64) / (64 * 25)
1/f = -39 / (64 * 25)
Now, we can invert both sides of the equation to solve for the focal length:
f = (64 * 25) / -39
f ≈ -41.03 cm
Since focal length cannot be negative for a converging lens, we take the positive value:
f ≈ 41 cm
Therefore, the correct answer is option C) 41 cm.
It's important to note that in the lens formula, distances are measured with respect to the lens, with positive values indicating distances on the opposite side of the incident light. The negative value obtained for the focal length indicates that the lens is a converging lens, as expected. Option C
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a vector is given by R = i+2j+4k Find The angles between R and the X , Y and Z axes.
Answers
The angles between X, Y, and Z are θx = θy = 63.6, θz = 27.2 with the resultant vector R = i + 2j + 4k.
From the given,
the resultant vector, R = i+2j+4k
Rx = 1
Ry = 2
Rz = 4
R² = Rx² + Ry² + Rz²
= (1)² + (2)² + (4)²
= 1+4+16
= 21
R = √21
= 4.5
Thus, the resultant vector, R is 4.5.
The angles between x, y, and z.
cosθx = Rx/R = 1/4.5
θx = cos⁻¹ (0.22) = 77.1° in X- axis.
cosθy = Ry/R = 2/4.5
θy = cos⁻¹(0.44) = 63.6° in Y-axis.
cosθz = Rz/R = 4/4.5
θz = cos⁻¹(0.88) = 27.2 in Z-axis.
The angles are θx = 77.1°, θy =63.6°, and θz = 27.2° along X, Y, and Z axis.
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Find the current flowing out of the battery.
Answers
Answer:
5A
Explanation:
In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?
Answers
According to the diagram the equivalent resistance of the group is
40.05 ohms
How to find the equivalent resistanceThe equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1
Resistors in parallel is solved by
Resistors in parallel = 1/25.4 + 1/70.8
Resistors in parallel = 0.0535 ohms
Equivalent resistance
Equivalent resistance = Resistors in parallel + Resistor in series
Equivalent resistance = 0.0535 + 40
Equivalent resistance = 40.0535
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A virtual satellite orbits the earth at an altitude h = 1600km with an altitude v = 7.1km / s. The amperage of the centrifugal force is F ’= 3151N. Calculate the satellite mass. It is known that the radius of the earth R = 6400 / km.
Answers
F' = (m * v^2) / r
Where F' is the centrifugal force, m is the mass of the satellite, v is the velocity of the satellite, and r is the distance between the center of the earth and the satellite, which is the sum of the radius of the earth and the altitude of the satellite.
r = R + h = 6400 + 1600 = 8000 km
Substituting the given values, we get:
3151 = (m * 7.1^2) / 8000
Solving for m, we get:
m = (3151 * 8000) / (7.1^2)
m ≈ 2.64 x 10^3 kg
Therefore, the mass of the satellite is approximately 2.64 x 10^3 kg.
An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
Answers
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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An astronaut has a total mass of 110 kg.
On the moon, he climbs into his spacecraft, 5 m up a ladder.
His GPE increases by 880 J.
What is the strength of gravity on the moon?
Answers
The strength of gravity on the moon is approximately 1.6 J/kg.
The change in gravitational potential energy (GPE) is given by the equation:
ΔGPE = m * g * Δh
where ΔGPE is the change in gravitational potential energy, m is the mass of the object, g is the strength of gravity, and Δh is the change in height.
In this case, the astronaut's GPE increases by 880 J as he climbs up the ladder by 5 m. We can rewrite the equation as:
880 J = (110 kg) * g * (5 m)
To find the strength of gravity on the moon (g), we can rearrange the equation:
g = 880 J / (110 kg * 5 m)
g = 1.6 J/kg
Therefore, the strength of gravity on the moon is approximately 1.6 J/kg.
It's important to note that the value of gravity on the moon is significantly lower than that on Earth. The moon has about one-sixth the gravity of Earth, which means objects weigh less on the moon compared to Earth. This lower gravity is due to the moon's smaller mass and smaller radius compared to Earth.
As a result, astronauts experience a different gravitational environment on the moon, which affects their movements and the energy required to perform tasks such as climbing.
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400g of cold water is added to 200g of water at 70 degree celsius if they are properly mixed and the temperature is mixed and it is 30 degrees Celsius calculate the initial temperature of the cold water.
Answers
The initial temperature of the cold water is 10°C.
Mass of the cold water, m₁ = 400 g = 0.4 g
Mass of the water to which the cold water is added, m₂ = 200 g = 0.2 g
Temperature of the water to which the cold water is added, T₂ = 70°C
Temperature of the mixture, T = 30°C
According to the principle of calorimetry,
m₁T₁ + m₂T₂ = (m₁ + m₂)T
(0.4 x T₁) + (0.2 x 70) = (0.4 + 0.2) x 30
0.4T₁ + 14 = 18
0.4T₁ = 18 - 14
0.4T₁ = 4
Therefore, the initial temperature of the cold water is,
T₁ = 4/0.4
T₁ = 10°C
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Kari walks 10m up the stairs. Sandra runs up the same flight of stairs. What is true about the amount of work each did?
Group of answer choices
Kari did more work
the amount of work is the same
Sandra did more work
I cannot determine an answer from the information given
Answers
Without knowing the forces exerted by Kari and Sandra, as well as the specific details about the stairs, we cannot determine who did more work. Option D
The amount of work done depends not only on the distance traveled but also on the force applied and the direction of the force. Without information about the force applied by both Kari and Sandra, we cannot determine who did more work.
Work is defined as the product of force and displacement in the direction of the force. In this case, the force exerted by Kari and Sandra while climbing the stairs is unknown.
If Kari and Sandra exerted the same amount of force while moving up the stairs, then the work done would be the same. However, if Sandra exerted a greater force compared to Kari, then Sandra would have done more work.
Additionally, the presence of stairs implies a vertical displacement. If Kari and Sandra were climbing stairs at the same height, the work done would be the same. However, if the stairs had different heights or slopes, the vertical displacement would differ, and that could affect the work done. Option D
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Gas and plasma are phases of matter, yet gas runs a car and plasma is part of your blood. Compare and contrast these terms and offer an explanation for the use of similar names.
Answers
Plasma lacks a precise form or volume, much like gas. It completes the empty space. Even though it is in the gaseous form, there is a difference because some of the particles are plasma-ionized.
High-energy particles are free to move around and fill the area they inhabit in the state of matter known as gas.
Neutral atoms or molecules often make up gaseous substances like air.
The ionised gas known as plasma, on the other hand, contains both positively and negatively charged particles.
It develops when a gas is subjected to an intense electric field or heated to incredibly high temperatures.
Plasma is a substance that may be found in stars, lightning, and fluorescent lights. It is also an essential component of many modern technology, like plasma TVs and fusion reactors.
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A war-wolf or trebuchet is a device used during the Middle Ages to throw rocks at castles and now sometimes used to fling large vegetables and pianos as a sport. A simple trebuchet is shown in the figure below. Model it as a stiff rod of negligible mass, d = 2.60 m long, joining particles of mass m1 = 0.115 kg and m2 = 68.5 kg at its ends. It can turn on a frictionless, horizontal axle perpendicular to the rod and 13.0 cm from the large-mass particle. The operator releases the trebuchet from rest in a horizontal orientation.
Find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally.
Answers
The maximum speed that the small-mass object attains when it leaves the trebuchet horizontally is approximately 28.3 m/s.
To find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally, we can apply the principle of conservation of mechanical energy.
Initially, the trebuchet is at rest, so its total mechanical energy is zero. As the small-mass object leaves the trebuchet horizontally, it gains kinetic energy. At this point, all of the potential energy of the system is converted into kinetic energy.
The potential energy of the system can be calculated as the sum of the gravitational potential energies of the two masses:
PE = m1 * g * h1 + m2 * g * h2
Since the trebuchet is released from rest in a horizontal orientation, the initial height h1 is zero. The height h2 can be calculated as the perpendicular distance between the pivot point and the center of mass of the larger mass m2:
h2 = 13.0 cm = 0.13 m
Therefore, the potential energy simplifies to:
PE = m2 * g * h2
The kinetic energy of the small-mass object can be calculated as:
KE = (1/2) * m1 * v^2
where v is the maximum speed of the small-mass object.
Since the total mechanical energy is conserved, we have:
PE = KE
m2 * g * h2 = (1/2) * m1 * v^2
Plugging in the given values, such as g = 9.8 m/s^2, m1 = 0.115 kg, m2 = 68.5 kg, and h2 = 0.13 m, we can solve for v:
(68.5 kg * 9.8 m/s^2 * 0.13 m) = (1/2) * 0.115 kg * v^2
Solving for v, we find:
[tex]v^2 = (68.5 kg * 9.8 m/s^2 * 0.13 m) / (0.115 kg)[/tex]
[tex]v^2 = 800[/tex]
v ≈ 28.3 m/s
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a hand pump is used to inflate a ball, the pump piston does 24 J of work on the air to compress it. the air in the pump loses 7 J of heat to the surroundings. what is the change in thermal energy of the air??
Answers
A Thermal energy of the air is 17 J of heat to the surroundings.
Thus, Thermal energy is produced by materials whose molecules and atoms vibrate more quickly as a result of a rise in temperature.
The atoms and molecules that make up matter are always in motion. The increase in temperature caused by heating a substance causes these particles to accelerate and collide.
The energy that arises from a heated substance is referred to as thermal energy. The more the substance's thermal energy and the more its particles travel at higher temperatures.
Thus, A Thermal energy of the air is 17 J of heat to the surroundings.
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Two batteries, A and B are connected in parallel, an 80 ohm resistor is connected across the battery terminals. The e.m.f and the internal resistance of battery A are 100 volts and 5 ohms respectively, and the corresponding values of battery B are 95 volts and 3 ohms respectively. Find the value and direction of the current on each battery and the terminal voltage.
Answers
Let's call the current through battery A I_A and the current through battery B I_B. Then the total current through the circuit is:
I = I_A + I_B
Using Ohm's Law, we can find the current through each battery in terms of the terminal voltage and internal resistance:
I_A = (V_A - V_R) / R_A
I_B = (V_B - V_R) / R_B
where V_A and V_B are the terminal voltages of batteries A and B, V_R is the voltage across the 80 ohm resistor, R_A and R_B are the internal resistances of batteries A and B, and I_A and I_B are the currents through batteries A and B, respectively.
Since the voltage across the 80 ohm resistor is the same as the voltage across the batteries, we can write:
V_R = V_A = V_B
Substituting this into the equations for I_A and I_B, we get:
I_A = (V_A - V_R) / R_A = (V_B - V_R) / R_A
I_B = (V_B - V_R) / R_B = (V_A - V_R) / R_B
Adding these equations, we get:
I = I_A + I_B =[(V_A - V_R) / R_A] + [(V_B - V_R) / R_B]
Substituting V_R = V_A = V_B, we get:
I = [(V_A - V_A) / R_A] + [(V_A - V_A) / R_B] = 0
This means that there is no net current flowing through the circuit, and the currents through batteries A and B are equal and opposite.
To find the terminal voltage of the batteries, we can use Ohm's Law again:
V_A = I_A * (R_A + R) = (V_A - V_R) / R_A * (R_A + R)
V_B = I_B * (R_B + R) = (V_B - V_R) / R_B * (R_B + R)
Substituting V_R = V_A = V_B and I_A = -I_B, we get:
V = V_A = V_B = I_A * (R_A + R) / 2 = -I_B * (R_B + R) / 2
Plugging in the given values, we get:
V = (-5 + 3)/(5+3+80) * 100 Volts = -0.74 Volts (approximate)
The negative sign indicates that the direction of the voltage is opposite to the direction of the current flow in the circuit.
Therefore, the current through each battery isapproximately zero, and the terminal voltage of each battery is approximately -0.74 volts.
The answer to these please
Answers
Ohm's law is defined as the applied voltage (V) is directly proportional to the current flow (I) in the circuit. V =IR, where R is the resistance of the circuit that resists the current flow in the circuit, and the unit of resistance is the ohm.
From the given,
1) a) resistors in the circuit are connected in parallel, then the voltage in the circuit remains the same. The voltage across each resistor is 9V.
b) the current in each resistor is given by, V=IR
I₁ = V/R₁ = 9/10kΩ=0.9mA.
I₂ = V/R₂ = 9/2kΩ = 4.5mA
I₃ = V/R₃ = 9/1kΩ = 9mA.
2) a) the resistances are connected in parallel, the effective resistance is 1/R(eff) = 1/R₁ + 1/R₂
1/R(eff) = 1/(100) + 1/(250)
= 250+100/25000
= 350/25000
= 7/500
R₁(eff) = 500/7
1/R(eff) = 1/R₁ + 1/R₂
= 1/350 + 1/200
= 200+350/70000
= 550/70000
= 11/1400
R₂(eff) = 1400/11
Thus, the two effective resistances are connected in series,
R(e) = R₁(eff) + R₂(eff)
= 500/7 + 1400/11
= (500×11) + (1400×7)/77
= 5500 + 9800 / 77
= 15300/77
R(e) = 198 Ω.
B) total current, I = V/R
I = 24 /198
= 121mA.
3) a) the resistances are connected in series, the total resistance,
R(eff) = R₁ + R₂
= 3+3
R(eff) = 6Ω
b)Current, I = V/R
I = 12/6
= 2A
c)Power, P = I²R = 2×2×6
P = 24W is the power in each bulb.
d) Power, P = VI = 12×2 = 24 W, is the power in battery.
4) a) the resistances are connected in parallel,
1/R(eff) = 1/R₁ + 1/R₂
= 1/3 + 1/3
= 2/3
R(eff) = 3/2Ω
b) In a parallel circuit, the voltage remains unchanged.
Voltage = 12V
c) Current, I = V/R
I₁ = V/R₁ = 12/3 = 4A
I₂ = V/R₂ = 12/3 = 4A.
d) power, P = I²R =4²3=48W.
e) Total current in the circuit, I = I₁+I₂
I = 4 + 4
= 8A
f) power supplied by a battery, P = VI
P = 12×4 = 48 W.
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QUESTION ❗️❗️❗️❗️❗️❗️
How could you measure the flow rate of various liquid
a.Place each one on a scale and measure its weight versus its volumes
b.Place them in a beaker and se which one floats to the top
c.Pour them down an incline and time how long it takes each one to reach the bottom
d.Burn each sample to create a deposit than can be analyzed
Answers
We can measure the flow rate of various liquid by pouring the liquid down an incline and time how long it takes each one to reach the bottom.
option C.
What is the flow rate of a liquid?
The flow rate of a liquid is how much fluid passes through an area in a particular time.
Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume. As liquids are incompressible, the rate of flow into an area must be equivalent to the rate of flow out of an area.
Generally, the best equipment to measure the flow rate of a liquid is flow meters. In the absence of flow meters, we can other methods such as the one given in the options.
We can pour the various liquid down an incline and time how long it takes each one to reach the bottom.
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A freighter needs to travel up the savannah River to the port, moving against the flow of the water. if theriver flows at 3 m/s relative to the shore, and the maximum speed of the freighter relative to the river is 7 m/s, what is the maximum velocity of the freighter relative to the shore
Answers
The maximum velocity of the freighter relative to the shore is 4 m/s.
To determine the maximum velocity of the freighter relative to the shore, we need to consider the velocities of the river and the freighter separately and then combine them. Since the freighter needs to travel against the flow of the water, we subtract the velocity of the river from the maximum speed of the freighter relative to the river.
Given that the river flows at 3 m/s relative to the shore, and the maximum speed of the freighter relative to the river is 7 m/s, we can subtract the river's velocity from the maximum speed of the freighter:
Max velocity of freighter relative to shore = Max velocity of freighter relative to river - Velocity of river
Max velocity of freighter relative to shore = 7 m/s - 3 m/s
Max velocity of freighter relative to shore = 4 m/s
This means that the freighter can travel upstream at a maximum speed of 4 meters per second relative to the stationary shore while overcoming the 3 m/s current flowing downstream in the Savannah River.
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Alice throws a ball on the ground,and it bounces back to her hand, there is no net change in the kinetic energy. What is the type of collision
Answers
Answer: the type of collision is elastic collision because both momentum and kinetic energy are conserved.
hope this helped!
Type the correct answer in the box. Spell all words correctly.
Mention the term
refers to having a generalized (and biased) belief about a particular group of people.
Answers
In social psychology, a stereotype is a generalized belief about a particular category of people.
What is stereotype ?A stereotype can be described as the accepted, condensed, and essentialist opinion with regards to certain population.
I should be nted hat his can be related to gender identity, race as well as ethnicity, country, however there are other things that an be used frequently used to stereotype groups. Stereotypes are pervasively present in both the larger social structure and culture.
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Please tell me the answer ASPA
Answers
Answer:
both objects are negatively charged.
What can be said about the speed ofa particle if the net work done on it is zero?
Answers
If the net work done on a particle is zero, the particle will move with a constant speed.
The principle of work and kinetic energy, often known as the work-energy theorem, states that the change in kinetic energy of a particle is equal to the sum of the entire work done by all of the forces acting on it.
So,
W = ΔKE
Thus, we can say that the kinetic energy of the particle will not change if the net work done on it is equal to zero.
As a result, the state of motion of the particle will not change, and thus the speed of the particle will also remain constant.
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When a solid object is subjected to a tension
force, T on both ends it will stretch by a distance
denoted AL. A quantity called the strain,
denoted by & is the distance stretched, AL
divided by the original length of the object, Lo,
i.e. & = AL/Lo. For many materials, the
applied tension force is measured to be linearly
proportional to the strain times the cross-
sectional area, A of the object i.e.
ΤαεΑ
The figure shows an object with a circular cross-
section of diameter d and original length Lo. If
object 2 has twice the diameter and twice the
starting length of object 1 (and is made of the
same material), what must be the ratio T₂/T₁ so
that the two objects have the same strain.
Answers
The tension force on object 2 must be one-fourth the tension force on object 1. The correct option is D.
How to explain the valueThe cross-sectional area is directly proportional to the square of the diameter, or A = πd²/4.
The Young's modulus is a constant for a given material.
Therefore, the change in length is proportional to the tension force and the square of the diameter.
For the two objects to have the same change in length, they must also have the same tension force.
The tension force is inversely proportional to the cross-sectional area, or F = EA/L0.
Therefore, the tension force is inversely proportional to the square of the diameter.
If object 2 has twice the diameter of object 1, then it will have four times the cross-sectional area.
Therefore, the tension force on object 2 must be one-fourth the tension force on object 1.
In other words, T2/T1 = 1/4.
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What is the result of two displacement vectors having opposite directions? Question 6 options: The resultant is the sum of the two displacements, having the same direction as the smaller vector. The resultant is the sum of the two displacements, having the same direction as the larger vector. The resultant is the difference of the two displacements, having the same direction as the smaller vector. The resultant is the difference of the two displacements, having the same direction as the larger vector.
Answers
The resultant of two displacement vectors having opposite directions is the difference of the two displacements, having the same direction as the smaller vector.
When two displacement vectors have opposite directions, it means they are pointing in opposite ways. In other words, one vector is in the opposite direction of the other. To find the resultant of these vectors, we need to subtract one vector from the other.
If we consider two displacement vectors, let's say vector A and vector B, and they have opposite directions, we can represent them as A and -B.
To find the resultant, we subtract vector B from vector A: A - (-B) or A + B.
The resultant will have the same direction as the smaller vector. This is because when we subtract a larger vector from a smaller vector, the resultant will have the direction of the smaller vector.
Therefore, the correct option is: "The resultant is the difference of the two displacements, having the same direction as the smaller vector."
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What is the value of acceleration in the following conditions
when a body comes at its initial position after motion
Answers
When a body comes to its initial position after motion, its velocity becomes zero, but the value of acceleration can vary depending on the specific conditions of the motion.
If the body comes to rest smoothly and gradually, the acceleration is zero. This means that there is no net force acting on the body, and it is not experiencing any acceleration. The body's velocity decreases over time until it reaches zero, and it returns to its initial position without any further acceleration.
However, if the body comes to its initial position abruptly, the situation is different. In this case, the body experiences a sudden change in velocity, and the acceleration can be nonzero.
For example, if a body is moving with a certain velocity and suddenly hits an obstacle or encounters a collision that brings it to a stop, the acceleration during the collision will be nonzero. The body experiences a rapid deceleration as it comes to rest, and this deceleration represents a negative acceleration.
In general, when a body comes to its initial position after motion, the value of acceleration can vary depending on the specific circumstances of the motion. It can be zero if the body comes to rest smoothly and gradually, or it can be nonzero if there is a sudden change in velocity leading to deceleration or acceleration.
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Find the position and velocity of a particle at t = 1.98 s if the particle is initially moving east at a speed of 20.4 m/s and experiences an acceleration of magnitude 4.40 m/s2, directed west.
Magnitude and direction of the position.
magnitude ---blank---
direction ---Select---
Magnitude and direction of the velocity.
magnitude ---blank---
direction ---select---
Answers
To find the position and velocity of a particle at a specific time, we can use the equations of motion.
Given:
Initial velocity (u) = 20.4 m/s (east)
Acceleration (a) = -4.40 m/s² (west)
Time (t) = 1.98 s
To find the position (displacement) of the particle at time t, we can use the equation:
s = ut + (1/2)at²
s = (20.4 m/s)(1.98 s) + (1/2)(-4.40 m/s²)(1.98 s)²
s = 40.392 m + (1/2)(-4.40 m/s²)(3.9204 s²)
s = 40.392 m - 8.6914 m
s ≈ 31.7006 m
To find the velocity of the particle at time t, we can use the equation:
v = u + at
v = (20.4 m/s) + (-4.40 m/s²)(1.98 s)
v = 20.4 m/s - 8.712 m/s
v ≈ 11.688 m/s
Therefore, the velocity of the particle at t = 1.98 s is approximately 11.688 m/s to the east.
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Seeing the light from these distant words and watching the life cycle of the universe unfold is breathtaking reminder that light is the ultimate
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From the distant stars to the smallest particles, light allows us to perceive the world and unravel its mysteries. It is through light that we gather information about our surroundings, explore the cosmos, and make scientific discoveries.
Light not only illuminates our physical environment, but it also carries the stories of the past. When we look at distant objects in space, we are actually observing light that has traveled vast distances over millions or even billions of years. By analyzing the light emitted or reflected by celestial bodies, astronomers can study their composition, temperature, and movement. This information provides invaluable insights into the nature of our universe and its evolution.
Moreover, light plays a crucial role in many areas of scientific research. In fields such as optics, photonics, and quantum mechanics, scientists harness the properties of light to develop advanced technologies. From lasers to fiber optics, these innovations have revolutionized communication, medicine, and countless other industries.
Light is not only a carrier of information, but it also embodies the electromagnetic spectrum, which encompasses various types of radiation, each with its own characteristics and applications. For instance, visible light allows us to see the world around us, while infrared light reveals heat signatures and ultraviolet light exposes hidden details. X-rays and gamma rays, on the other hand, help us explore the microscopic realm and unravel the secrets of atomic and subatomic particles.
Beyond its scientific significance, light has metaphorical and symbolic meanings as well. It is often associated with knowledge, enlightenment, and wisdom. The phrase "seeing the light" is used to describe moments of realization or understanding. Light is a universal symbol of hope, guidance, and truth.
In summary, light is indeed the ultimate source of knowledge. Its ability to illuminate, reveal, and transmit information has profound implications for our understanding of the universe and our place within it. Whether we contemplate the wonders of the cosmos or appreciate the metaphorical significance of light, it remains an awe-inspiring force that continues to inspire and expand our horizons.
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What was Gan De's contribution to astronomy?
A.
He developed the world's first star catalogue.
B.
He was the first to record a lunar eclipse.
C.
He was the first to observe planets.
D.
He invented the telescope.
Answers
Answer: A. He developed the world's first star catalogue.
Explanation: Gan De's contribution to astronomy was the development of the world's first star catalogue , along with his colleague Shi Shen. He also made observations of the planets, particularly Jupiter, and may have been the first to describe one of Jupiter's moons. Unfortunately, all of Gan De's writings have been lost, but fragments of his works' titles and quoted fragments are known from later texts.
Organisms belonging to the same species can have______traits
Answers
Answer:
similar or identical traits.
52754.1683 to the nearest thousand,hundredth,hundred,tenth,
whole number
Answers
Answer:
To round 52754.1683 to the nearest:
Thousand: 53000
Hundredth: 52754.17
Hundred: 52700
Tenth: 52754.2
Whole number: 52754
Explanation: