help me please with algebra 72 points

Apologies for the limitations of a text-based interface. I'll describe the steps to answer your question instead.

To draw the graph of the first derivative of a function with the given information, follow these steps:

1. Mark a point at T on the x-axis, which represents the x-coordinate of the curve's vertex.

2. Draw a curve that starts at T and is concave up (opening upward).

3. Place x-intercepts at -E and +F on the x-axis, representing the points where the curve crosses the x-axis.

4. Locate the y-intercept at -D on the y-axis, which is the point where the curve intersects the y-axis.

To draw the graph of the first derivative, start with a vertex at T and sketch a curve that is concave up (cup-shaped). The curve should intersect the x-axis at -E and +F, representing the x-intercepts. Finally, locate the y-intercept at -D, indicating where the curve crosses the y-axis. These points provide the essential characteristics of the graph. Keep in mind that without a specific function, this description serves as a general guideline for drawing the graph based on the given information.

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The derivative of [tex]g(t) = ln|√(2t - 1)| + t(t^2 + 1)/8 is g'(t) = (t^2 + 1)/8 + 1/(2t - 1).[/tex]

Start with the function [tex]g(t) = ln|√(2t - 1)| + t(t^2 + 1)/8.[/tex]

Apply the chain rule to differentiate the natural logarithm term: [tex]d/dt [ln|√(2t - 1)|] = 1/(√(2t - 1)) * (1/(2t - 1)) * (2).[/tex]

Simplify the expression: [tex]d/dt [ln|√(2t - 1)|] = 1/(2t - 1).[/tex]

Differentiate the second term using the power rule:[tex]d/dt [t(t^2 + 1)/8] = (t^2 + 1)/8.[/tex]

Add the derivatives of both terms to get the derivative of [tex]g(t): g'(t) = (t^2 + 1)/8 + 1/(2t - 1).[/tex]

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The given curve is represented by the equation f(x) = √[tex](x^2 - 4)[/tex]. The domain of the curve is (-∞, -2] ∪ [2, +∞), and it has two intercepts: (-2, 0) and (2, 0).

To determine the domain of the curve, we need to consider the values of x for which the function f(x) is defined. In this case, the square root function (√) is defined only for non-negative real numbers. Therefore, we need to find the values of x that make the expression inside the square root non-negative.

The expression inside the square root, x^2 - 4, must be greater than or equal to zero. Solving this inequality, we get[tex]x^2[/tex]≥ 4, which implies x ≤ -2 or x ≥ 2. Combining these two intervals, we find that the domain of the curve is (-∞, -2] ∪ [2, +∞).

To find the intercepts of the curve, we set f(x) = 0 and solve for x. Setting √[tex](x^2 - 4)[/tex] = 0, we square both sides to get x^2 - 4 = 0. Adding 4 to both sides and taking the square root, we find x = ±2. Therefore, the curve intersects the x-axis at x = -2 and x = 2, giving us the intercepts (-2, 0) and (2, 0) respectively.

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If q is positive and increasing, for what value of q is the rate of increase of q3 twelve times that of the rate of increase of q is option a. 2.

Let's differentiate the equation q^3 with respect to q to find the rate of increase of q^3:

d/dq (q^3) = 3q^2

Now, we can set up the equation to find the value of q:

12 * d/dq (q) = d/dq (q^3)

12 * 1 = 3q^2

12 = 3q^2

4 = q^2

Taking the square root of both sides, we get:

2 = q

Therefore, the value of q for which the rate of increase of q^3 is twelve times that of the rate of increase of q is q = 2.

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Answer:

[tex]\huge\boxed{\sf n = 4}[/tex]

Step-by-step explanation:

6 + 8n + 2n = 4n + 30

6 + 10n = 4n + 30

6 + 10n - 4n = 30

6 + 6n = 30

6n = 30 - 6

6n = 24

n = 24 / 6

[tex]\rule[225]{225}{2}[/tex]

The series [tex]$\sum_{n=1}^{\infty} (-1)^{n-1}\frac{1}{13e^{1/hn}}$[/tex] converges. The given series can be written as [tex]$\sum_{n=1}^{\infty} (-1)^{n-1}\frac{1}{13}\cdot\frac{1}{e^{1/hn}}$[/tex].

Notice that the series involves alternating signs with a decreasing magnitude. When we consider the term [tex]$\frac{1}{e^{1/hn}}$[/tex], as n approaches infinity, the exponential term will tend to 1. Therefore, the series can be simplified to [tex]$\sum_{n=1}^{\infty} (-1)^{n-1}\frac{1}{13}$[/tex]. This is an alternating series with a constant magnitude, which allows us to apply the Alternating Series Test. According to this test, if the magnitude of the terms approaches zero and the terms alternate in sign, then the series converges. In our case, the magnitude of the terms is [tex]$\frac{1}{13}$[/tex], which approaches zero, and the terms alternate in sign. Hence, the given series converges.

In conclusion, the series [tex]$\sum_{n=1}^{\infty} (-1)^{n-1}\frac{1}{13e^{1/hn}}$[/tex] converges.

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We are given three limit problems and asked to determine whether the limits exist or not. The limits are:

lim (x, y) -> (0,0) of (x^2 + y^2)

lim (x, y) -> (0,0) of (x^2 - 2y^2)/(2 + y^2)

lim (x, y) -> (1,1) of (x - y)/(x + y - 2)

For the limit lim (x, y) -> (0,0) of (x^2 + y^2):

To determine if the limit exists, we consider different paths approaching the point (0,0). Since the expression x^2 + y^2 represents the distance from the origin, as (x, y) approaches (0,0), the distance will approach zero. Therefore, the limit exists and is equal to 0.

For the limit lim (x, y) -> (0,0) of (x^2 - 2y^2)/(2 + y^2):

To investigate the existence of this limit, we examine different paths. Approaching along the x-axis (y = 0), the limit simplifies to lim x -> 0 of (x^2)/(2) = 0/2 = 0. However, approaching along the y-axis (x = 0), the limit becomes lim y -> 0 of (-2y^2)/(2 + y^2) = 0/2 = 0. Since the limits along these two paths are different, the limit does not exist.

For the limit lim (x, y) -> (1,1) of (x - y)/(x + y - 2):

Again, we consider different paths. Approaching along the line x - y = 0, the limit becomes lim (x,y) -> (1,1) of 0/0, which is an indeterminate form. Therefore, further analysis is needed, such as using algebraic manipulation or polar coordinates, to determine the limit. Without additional information or analysis, we cannot conclude whether the limit exists or not.

In summary, the first limit exists and is equal to 0, the second limit does not exist, and for the third limit, we need additional analysis to determine its existence.

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As per the given data, the greatest common factor of 22 + 10x is 2.

To find the greatest common factor (GCF) of the terms in the expression 22 + 10x, we need to factorize each term and identify the common factors.

Let's start with 22. The prime factorization of 22 is 2 * 11.

Now let's factorize 10x. The GCF of 10x is 10, which can be further factored as 2 * 5. Since there is an 'x' attached to 10, we include 'x' as a factor as well.

Now, let's identify the factor pairs that share the greatest common factor:

Factor pairs of 22:

1 * 22

2 * 11

Factor pairs of 10x:

1 * 10x

2 * 5x

From the factor pairs, we can see that the common factor between the two terms is 2.

Therefore, the GCF of 22 + 10x is 2.

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The geometric transformation shown in the line of music is given as follows:

Glide reflection.

The glide reflection is a geometric transformation that is defined as a combination of a reflection with a translation.

On the line of music for this problem, we have that:

As there was both a reflection and a translation, the geometric transformation shown in the line of music is given as follows:

Glide reflection.

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The reduced fraction for 0.202222... is 1/5.

To express the repeating decimal 0.20222222... as a reduced fraction, follow these steps:

1. Let x = 0.202222...
2. Multiply both sides by 100: 100x = 20.2222...
3. Multiply both sides by 10: 10x = 2.02222...
4. Subtract the second equation from the first: 90x = 18
5. Solve for x: x = 18/90

Now, let's reduce the fraction:
18/90 can be simplified by dividing both the numerator and denominator by their greatest common divisor (GCD), which is 18. So, 18 ÷ 18 = 1 and 90 ÷ 18 = 5.

Therefore, the reduced fraction for 0.202222... is 1/5.

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The expression 800 - 600i in trigonometric form is approximately 1000 ∠ -36.87°.

To express a complex number in trigonometric form, we need to convert it into polar form with the magnitude (r) and argument (θ). The magnitude (r) is calculated using the formula r = √[tex](a^2 + b^2)[/tex], where 'a' is the real part and 'b' is the imaginary part. In this case, a = 800 and b = -600.

r = √[tex](800^2 + (-600)^2)[/tex] ≈ √(640000 + 360000) ≈ √(1000000) ≈ 1000

The argument (θ) can be found using the formula θ = arctan(b/a). Since a = 800 and b = -600, we have:

θ = arctan((-600)/800) ≈ arctan(-0.75) ≈ -36.87°

Therefore, the expression 800 - 600i in trigonometric form is approximately 1000 ∠ -36.87°, where 1000 is the magnitude (r) and -36.87° is the argument (θ).

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After 2 days without any deposits or withdrawals, the balance in Lin's sister's account would be -$14.57.

The bank will impose a $5.95 daily fee on Lin's sister if she doesn't make any deposits or withdrawals for each day that her account balance is less than zero.

Let's calculate the balance after two days starting with an account balance of -$2.67:

Account balance on Day 1: $2.67

Charged at: $5.95

New account balance: (-$2.67) - $5.95 = -$8.62

Second day: Account balance: -$8.62

Charged at: $5.95

New account balance: (-$8.62) - $5.95 = -$14.57

Therefore, after 2 days without any deposits or withdrawals, the balance in Lin's sister's account would be -$14.57.

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The number of people hearing the rumor for the first time will start to decline when the derivative of the function P(t) changes from positive to negative.

To determine when the number of people hearing the rumor for the first time starts to decline, we need to find the critical points of the function P(t). The critical points occur where the derivative of P(t) changes sign.

First, we find the derivative of P(t) with respect to t:

P'(t) = [10(0.19t + 1)ln(0.19t + 1) - 10ln(0.19t + 1)(0.19)] / (0.19t + 1)^2.

To determine the critical points, we set P'(t) equal to zero and solve for t:

[10(0.19t + 1)ln(0.19t + 1) - 10ln(0.19t + 1)(0.19)] / (0.19t + 1)^2 = 0.

Simplifying, we have:

[0.19t + 1]ln(0.19t + 1) - ln(0.19t + 1)(0.19) = 0.

Factoring out ln(0.19t + 1), we get:

ln(0.19t + 1)[0.19t + 1 - 0.19] = 0.

The critical points occur when ln(0.19t + 1) = 0, which means 0.19t + 1 = 1. Taking t = 0 satisfies this equation.

To determine when the number of people hearing the rumor for the first time starts to decline, we need to examine the sign changes of P'(t) around the critical point t = 0. By evaluating the derivative at points near t = 0, we find that P'(t) is positive for t < 0 and negative for t > 0.

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Answer:

The area of the parallelogram formed by the points is approximately 37.73 square units.

Step-by-step explanation:

To verify if the points A(2, -3, 1), B(6, 5, -1), C(7, 2, 2), and D(3, -6, 4) form a parallelogram, we can check if the opposite sides of the quadrilateral are parallel.

Let's consider the vectors formed by the points:

Vector AB = B - A = (6, 5, -1) - (2, -3, 1) = (4, 8, -2)

Vector CD = D - C = (3, -6, 4) - (7, 2, 2) = (-4, -8, 2)

Vector BC = C - B = (7, 2, 2) - (6, 5, -1) = (1, -3, 3)

Vector AD = D - A = (3, -6, 4) - (2, -3, 1) = (1, -3, 3)

If the opposite sides are parallel, the vectors AB and CD should be parallel, and the vectors BC and AD should also be parallel.

Let's calculate the cross product of AB and CD:

AB x CD = (4, 8, -2) x (-4, -8, 2)

        = (-16, -8, -64) - (-4, 8, -32)

        = (-12, -16, -32)

The cross product of BC and AD:

BC x AD = (1, -3, 3) x (1, -3, 3)

        = (0, 0, 0)

Since the cross product BC x AD is zero, it means that BC and AD are parallel.

Therefore, the points A(2, -3, 1), B(6, 5, -1), C(7, 2, 2), and D(3, -6, 4) form a parallelogram.

To find the area of the parallelogram, we can calculate the magnitude of the cross product of AB and CD:

Area = |AB x CD| = |(-12, -16, -32)| = √((-12)^2 + (-16)^2 + (-32)^2) = √(144 + 256 + 1024) = √1424 ≈ 37.73

Therefore, the area of the parallelogram formed by the points is approximately 37.73 square units.

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Answer:

The standard form for linear equations in two variables is Ax+By=C. For example, 2x+3y=5 is a linear equation in standard form. When an equation is given in this form, it's pretty easy to find both intercepts (x and y).

If your teacher wrote f(x) = 0, x = 3, but graph of the function f(x) shows that it is always equal to 2, regardless of the approach, there may be error. It is crucial to clarify this discrepancy with your teacher to ensure.

Based on your description, there seems to be a discrepancy between the given equation f(x) = 0, x = 3 and the observed behavior of the graph, which consistently shows f(x) as 2. It is possible that there was a mistake in the equation provided by your teacher or in your interpretation of it.

To resolve this discrepancy, it is essential to communicate with your teacher and clarify the intended equation or expression. They may provide further explanation or correct any misunderstandings. Open dialogue with your teacher will help ensure that you have accurate information and a clear understanding of the function and its behavior.

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Consider the position function below: r(t) = (1 - 2t, 3 - 2t) for t ≤ 20.a. Find the velocity and the speed of the object.

The velocity of the object is given as:v(t) = r'(t)where r(t) is the position vector of the object at any given time, t.The velocity, v(t) is thus:v(t) = r'(t) = (-2, -2)The speed of the object is given as the magnitude of the velocity vector. Therefore,Speed, S = |v(t)| = √[(-2)² + (-2)²] = √[8] = 2√[2].Therefore, the velocity of the object is v(t) = (-2, -2) and the speed of the object is S = 2√[2].b. Find the acceleration of the object.The acceleration of the object is given as the derivative of the velocity of the object with respect to time. i.e. a(t) = v'(t).v(t) = (-2, -2), for t ≤ 20.v'(t) = a(t) = (0, 0)Therefore, the acceleration of the object is given as a(t) = v'(t) = (0, 0).

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a. The final discount date is 20 days after the end of the month. b. The net payment date is 30 days after the end of the month. c. If the invoice is paid on January 20th, the amount to be paid is $866.70.

a. The terms "2/20 EOM" mean that a 2% discount is offered if the invoice is paid within 20 days, and the EOM (End of Month) indicates that the 20-day period starts from the end of the month in which the invoice is issued. Therefore, the final discount date would be 20 days after the end of January.

b. The net payment date is the date by which the invoice must be paid in full without any discount. In this case, the terms state "EOM," which means that the net payment date is 30 days after the end of the month in which the invoice is issued.

c. If the invoice is paid on January 20th, it is within the 20-day discount period. The discount amount would be 2% of $885, which is $17.70. Therefore, the amount to be paid would be the invoice amount minus the discount, which is $885 - $17.70 = $866.70.

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(a) The argument, arg(ζ) = arctan(imaginary part / real part)

= arctan[b(√3 - a) / (6a(√3 - 1) - b(a√3 + b))]

(b) The cube roots, z^(1/3) = 64^(1/3)[cos((π/6)/3) + isin((π/6)/3)]

= 4[cos(π/18) + isin(π/18)]

(a) To find the argument of the complex number ζ = (-a + ai)(6 + b√3i), we can expand the expression and simplify:

ζ = (-a + ai)(6 + b√3i)

= -6a - ab√3i + 6ai - b√3a + 6a√3 + b√3i²

= (-6a + 6a√3) + (-ab√3 + b√3i) + (6ai - b√3a - b√3)

= 6a(√3 - 1) + b(√3i - a√3 - b)

Now, let's separate the real and imaginary parts:

Real part: 6a(√3 - 1) - b(a√3 + b)

Imaginary part: b(√3 - a)

To find the argument, we need to find the ratio of the imaginary part to the real part:

arg(ζ) = arctan(imaginary part / real part)

= arctan[b(√3 - a) / (6a(√3 - 1) - b(a√3 + b))]

(b) Let's find the cube roots of the complex number z = 32√3 + 32i. We'll use the polar form of a complex number to simplify the calculation.

First, let's find the modulus (magnitude) and argument (angle) of z:

Modulus: |z| = √[(32√3)² + 32²] = √[3072 + 1024] = √4096 = 64

Argument: arg(z) = arctan(imaginary part / real part) = arctan(32 / (32√3)) = arctan(1 / √3) = π/6

Now, let's express z in polar form: z = 64(cos(π/6) + isin(π/6))

To find the cube roots, we can use De Moivre's theorem, which states that raising a complex number in polar form to the power of n will result in its modulus raised to the power of n and its argument multiplied by n:

z^(1/3) = 64^(1/3)[cos((π/6)/3) + isin((π/6)/3)]

= 4[cos(π/18) + isin(π/18)]

Since we want to find all three cube roots, we need to consider all three cube roots of unity, which are 1, e^(2πi/3), and e^(4πi/3):

Root 1: z^(1/3) = 4[cos(π/18) + isin(π/18)]

Root 2: z^(1/3) = 4[cos((π/18) + (2π/3)) + isin((π/18) + (2π/3))]

= 4[cos(7π/18) + isin(7π/18)]

Root 3: z^(1/3) = 4[cos((π/18) + (4π/3)) + isin((π/18) + (4π/3))]

= 4[cos((13π/18) + isin(13π/18)]

Now, let's sketch these cube roots in the complex plane:

Root 1: Located at 4(cos(π/18), sin(π/18))

Root 2: Located at 4(cos(7π/18), sin(7π/18))

Root 3: Located at 4(cos(13π/18), sin(13π/18))

The sketch will show three points on the complex plane representing these cube roots.

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The function f(x) is defined differently for different values of x.
For x less than 0, f(x) is equal to -x + 1.

For values of x between 0 and 1 (inclusive), f(x) is equal to 1.
For values of x greater than 1, f(x) is equal to -*+2
So overall, the function f(x) is a piecewise function with different definitions for different intervals of x.
Let f(x) be a piecewise function defined as follows:
1. f(x) = -x + 1 for x < 0
2. f(x) = 1 for 0 ≤ x ≤ 1
3. f(x) = -x + 2 for x > 1
This function behaves differently depending on the input value (x). For x values less than 0, the function follows the equation -x + 1. For x values between 0 and 1 inclusive, the function equals 1. And for x values greater than 1, the function follows the equation -x + 2.

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The solution to the given Inequality expression is: s ≥ -8

Inequalities could be in the form of greater than, less than, greater than or equal to and less than or equal to.

We are given the inequality expression as:

s/-2 ≤ 4

Divide both sides by -1/2 and this changes the inequality sign to give us:

s ≥ 4 * -2

s ≥ -8

Thus, all values greater than or equal to -8 are possible values of s in the inequality.

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Complete question is:

Select the values that make the inequality s/-2 ≤ 4 true. Then write an equivalent inequality, in terms of s.

After considering the given data we conclude that the center (x, y, z) is (-4, 4, -3), and the radius is 4, under the condition that sphere is in standard form.

To present the condition of the circle in standard shape(sphere ), we have to apply summation of the square in terms of including x, y, and z.

The given condition of the sphere is:

[tex]x^2 + y^2 + z^2 + 8x - 8y + 6z + 37 = 0[/tex]

To sum of the square for x, we include the square of half the coefficient of x:

[tex]x^2 + y^2 + z^2 + 8x -8y + 6z + 37 = 0( x^2 = 8x + 16 ) + y^2 +z^2- 8y + 6z+ 37 = 16(x + 4)^2 + y^2 +z ^2 + z^2 - 8y + 6z + 37 - 16 = 16(x + 4)^2 + ( y^2 -8y) + (z^2 + 6z) + 21 = 16 ( x+ 4)^2 + (y^2 - 8y +16) + ( z^2 + 6z +9) = 16( x+ 4)^2+(y -4)^2 +(z=3)^2 =16[/tex]

Hence, the condition is in standard shape:

[tex](x - h)^2 + ( y - k)^2 + ( z - l)^2 = r^2[/tex]

Here,

(h, k, l) = center of the circle,

r = the span.

Comparing the standard frame with the given condition, we are able to see that the center of the sphere is (-4, 4, -3), and the sweep is the square root of 16, which is 4.

Therefore, the center (x, y, z) is (-4, 4, -3), and the sweep is 4.

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Area between the curves is -43/3 square units, which is approximately -14.333 square units. To find the area between the curves y = 5 and y = (x - 1)² + 1 with x ≥ 0, we need to calculate the definite integral of the difference between the upper and lower curves with respect to x.

First, let's find the x-values at which the curves intersect:

For y = 5:

5 = (x - 1)² + 1

4 = (x - 1)²

±2 = x - 1

x = 1 ± 2

The lower curve is y = 5, and the upper curve is y = (x - 1)² + 1.

To find the area between the curves, we integrate the difference between the upper and lower curves: A = ∫[1-2 to 1+2] ((x - 1)² + 1 - 5) dx

Simplifying the integrand:

A = ∫[1-2 to 1+2] (x² - 2x + 1 - 4) dx

A = ∫[1-2 to 1+2] (x² - 2x - 3) dx

Integrating:

A = [x³/3 - x² - 3x] evaluated from 1-2 to 1+2

A = [(1+2)³/3 - (1+2)² - 3(1+2)] - [(1-2)³/3 - (1-2)² - 3(1-2)]

Simplifying further:

A = [(27/3) - 9 - 9] - [(-1/3) - 1 + 3]

A = [9 - 9 - 9] - [-1/3 - 1 + 3]

A = -9 - 7/3

A = -36/3 - 7/3

A = -43/3

The area between the curves is -43/3 square units, which is approximately -14.333 square units. Note that the negative sign indicates that the area is below the x-axis

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If decimal scaling normalization is applied to the given data set, the normalized value of the first reading, 9, would be 0.09.

To normalize the first reading, 9, we divide it by 100. Therefore, the normalized value of 9 would be 0.09.By applying the same normalization process to each value in the data set, we would obtain the normalized values for all readings. The purpose of normalization is to scale the data so that they fall within a specific range, often between 0 and 1, making it easier to compare and analyze different variables or data sets.

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Let x represent the number of nickels and y represent the number of dimes that Angel possesses.

Equation 1: There are exactly 20 nickels and dimes in circulation Equation 2: The total value of the coins is $1.85; 0.05x + 0.1y = 1.85

Eq. 1 for x must be solved:

x = 20 - y

Add x to equation 2, then figure out y:

0.05(20 - y) + 0.1y = 1.85 1 - 0.05y + 0.1y = 1.85 0.05y = 0.85 y = 17

To find x, substitute y into equation 1:

x + 17 = 20 x = 3

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The solution to differential equation (9) is y = [tex]2e^{(x-1)[/tex]. The solution to differential equation (11) is y = (x + 1)² / 2 which is not a solution.

Given differential equations arey = x - y; y' = y²(1 - x)

N 9. y = [tex]2e^{(x-1)[/tex] solves y = x - y

Here the given differential equation is y = x - y.

We need to find whether y = [tex]2e^{(x-1)[/tex] is a solution to the given differential equation or not.

Substituting y = 2e^(x-1) in y = x - y, we get

y = x - [tex]2e^{(x-1)[/tex]

Now we need to verify if y = x - 2e^(x-1) is a solution to the given differential equation or not.

Differentiating y w.r.t. x, we gety' = 1 -  [tex]2e^{(x-1)[/tex]

On substituting these values in the given differential equation we get

y = y'1 - x - y² ⇒ y' = y²1 - x - y

Thus, we can conclude that y = 2e^(x-1) is indeed a solution to the given differential equation.

N 11. y = (x + 1)² / 2 solves y' = y²(1 - x)

Here the given differential equation is y' = y²(1 - x).

We need to find whether y = (x + 1)² / 2 is a solution to the given differential equation or not.

Differentiating y w.r.t. x, we gety' = x + 1

Substituting y = (x + 1)² / 2 and y' = x + 1 in y' = y²(1 - x), we get

x + 1 = (x + 1)² / 2 × (1 - x) ⇒ (x + 1)(2 - x) = (x + 1)² ⇒ (x + 1)(x + 3) = 0

Thus, the possible values of x are -1 and -3.On substituting x = -1 and x = -3, we get

y = (x + 1)² / 2 = 0 and y = (-2)² / 2 = 2

Therefore, y = (x + 1)² / 2 is not a solution to the given differential equation.

The solution to differential equation (9) is y =  [tex]2e^{(x-1)[/tex]). The solution to differential equation (11) is y = (x + 1)² / 2 which is not a solution.

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The position vector of point P, denoted as [tex]\(\overrightarrow{OP}\)[/tex], can be found by subtracting the position vector of the origin O from the coordinates of point P.

Given that the coordinates of point P are (1.2, 5), and the origin O is (0, 0, 0), we can calculate [tex]\(\overrightarrow{OP}\)[/tex] as follows:

[tex]\[\overrightarrow{OP} = \begin{bmatrix} 1.2 - 0 \\ 5 - 0 \\ 0 - 0 \end{bmatrix} = \begin{bmatrix} 1.2 \\ 5 \\ 0 \end{bmatrix} = 1.2\mathbf{i} + 5\mathbf{j} + 0\mathbf{k} = 1.2\mathbf{i} + 5\mathbf{j}\][/tex]

The position vector of point Q, denoted as [tex]\(\overrightarrow{OQ}\)[/tex], can be found similarly by subtracting the position vector of the origin O from the coordinates of point Q. Given that the coordinates of point Q are (9.4, 11), we can calculate [tex]\(\overrightarrow{OQ}\)[/tex] as follows:

[tex]\[\overrightarrow{OQ} = \begin{bmatrix} 9.4 - 0 \\ 11 - 0 \\ 0 - 0 \end{bmatrix} = \begin{bmatrix} 9.4 \\ 11 \\ 0 \end{bmatrix} = 9.4\mathbf{i} + 11\mathbf{j} + 0\mathbf{k} = 9.4\mathbf{i} + 11\mathbf{j}\][/tex]

a) Therefore, the position vector of point P in the form (a, b, c) is (1.2, 5, 0), and in the form [tex]\(ai + bj + ck\)[/tex] is [tex]\(1.2\mathbf{i} + 5\mathbf{j}\)[/tex].

b) The magnitude of [tex]\(\overrightarrow{OP}\)[/tex], denoted as [tex]\(|\overrightarrow{OP}|\)[/tex], can be calculated using the formula [tex](|\overrightarrow{OP}| = \sqrt{a^2 + b^2 + c^2}\)[/tex], where a, b, and c are the components of the position vector [tex]\(\overrightarrow{OP}\)[/tex]. In this case, we have:

[tex]\[|\overrightarrow{OP}| = \sqrt{1.2^2 + 5^2 + 0^2} = \sqrt{1.44 + 25} = \sqrt{26.44} \approx 5.14\][/tex]

Therefore, the magnitude of [tex]\(\overrightarrow{OP}\)[/tex] is approximately 5.14.

c) To find two unit vectors parallel to [tex]\(\overrightarrow{OP}\)[/tex], we can divide [tex]\(\overrightarrow{OP}\)[/tex] by its magnitude. Using the values from part a), we have:

[tex]\[\frac{\overrightarrow{OP}}{|\overrightarrow{OP}|} = \frac{1.2\mathbf{i} + 5\mathbf{j}}{5.14} \approx 0.23\mathbf{i} + 0.97\mathbf{j}\][/tex]

Thus, two unit vectors parallel to [tex]\(\overrightarrow{OP}\)[/tex] are approximately [tex]0.23\(\mathbf{i} + 0.97\mathbf{j}\)[/tex]  and its negative, [tex]-0.23\(\mathbf{i} - 0.97\math.[/tex]

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a) To eliminate the parameter t, we can solve for t in the equation x = t + 2 to get t = x - 2. Substituting this expression for t into the equation y = t^2 + 3 yields y = (x - 2)^2 + 3.

Simplifying this equation gives y = x^2 - 4x + 7, which is a parabola. The vertex of this parabola can be found by completing the square: y = (x - 2)^2 + 3 = (x - 2)^2 + (sqrt(3))^2 - (sqrt(3))^2 = (x - 2)^2 + 3.

Therefore, the vertex of the parabola is at (2, 3).

b) To sketch the curve described by the parametric equations, we can plot points by choosing values of t between 1 and 2. When t = 1, we have x = 3 and y = 4.

When t = 1.5, we have x = 3.5 and y = 5.25. When t = 1.75, we have x = 3.75 and y = 6.0625. When t = 1.9, we have x ≈ 3.9 and y ≈ 7.21.

The curve starts at the point (3,4) and moves towards the right as t increases, reaching its minimum point at the vertex (2,3), before moving upwards as t continues to increase towards infinity.

Therefore, the curve described by the parametric equations is a parabolic curve with vertex at (2,3), opening upwards.

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∂z/∂s = 3cos(t)/y, ∂z/∂t = 3s*cos(t)/y - sin(s)/x (using the chain rule to differentiate each term and substituting the given expressions for x and y)

To find ∂z/∂s and ∂z/∂t using the chain rule, we start by finding the partial derivatives of z with respect to x and y, and then apply the chain rule.

First, let's find ∂z/∂x and ∂z/∂y.

∂z/∂x = ∂/∂x [ln(5x^3y)]

= (1/5x^3y)  ∂/∂x [5x^3y]

= (1/5x^3y) 15x^2y

= 3/y

∂z/∂y = ∂/∂y [ln(5x^3y)]

= (1/5x^3y) ∂/∂y [5x^3y]

= (1/5x^3y)  5x^3

= 1/x

Now, using the chain rule, we can find ∂z/∂s and ∂z/∂t.

∂z/∂s = (∂z/∂x)  (∂x/∂s) + (∂z/∂y)  (∂y/∂s)

= (3/y)  (cos(t)) + (1/x)  (0)

= 3cos(t)/y

∂z/∂t = (∂z/∂x)  (∂x/∂t) + (∂z/∂y)  (∂y/∂t)

= (3/y) * (scos(t)) + (1/x)  (-sin(s))

= 3scos(t)/y - sin(s)/x

Therefore, ∂z/∂s = 3cos(t)/y and ∂z/∂t = 3s*cos(t)/y - sin(s)/x.

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