Help me please, Im giving brainliest answer. ​

Answer:

To what temperature must a sample of helium gas be cooled from 22.2 degrees C to reduce its volume from 1.00L to 100cm3 ?

Explanation:

Answer:

  m

Explanation:

Answer:

CN is your answer.

Explanation:

Hope this helps!!!

The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol

Given data :

Volume of solution to be tested for I-ion = 10 mL

Volume of  Pb(NO₃)₂ = 0.2 mL

molarity of Pb(NO₃)₂ = 0.13 M

First step : calculate conc of PB²⁺ ions in the solution

conc of PB²⁺ ions =  ( molarity of Pb(NO₃)₂ * volume of  Pb(NO₃)₂ ) / ( total volume )

                              = ( 0.13 * 0.2 ) / ( 10 + 0.2 )

                              = ( 0.026 ) / ( 10.2 )  = 0.002549 M

Next step : determine the molarity of  I

using the dissociation reaction of PbI₂

PbI₂(s) ---> Pb²⁺ (aq)  + 2I (aq)

also;  Ksp = [ Pb²⁺ ] [ I ]²  ---- ( 1 )

From the question the given value of Ksp = 8.49 * 10⁻⁹

Therefore equation ( 1 ) becomes

8.49 * 10⁻⁹ = ( 0.002549 ) * [ I ]²

[ I ] = √ ( 8.49 * 10⁻⁹ ) / ( 0.002549 )

      = 0.0018 M

Final step : Determine the minimum number of grams of I

moles of I = molarity of I * total volume

                 = 0.0018 M * 10.2 mL

                 = 0.01836 * 10⁻³ mol

Hence we can conclude that The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol

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Answer: I think it’s enzymes

Explanation:

A

Explanation:

electrons flow in both directions

Answer: A I know it but I forgot how to explain it.

The compound is formed by addition reaction. The product is showed in the image attached.

The term addition reaction refers to a type of reaction in which a compound is added across the multiple bond. In this case, the iodine molecule is added to the olefinic bond as shown.

The structure of the product formed has been attached to this answer. The product is formed by addition across the double bond.

Learn more about addition reaction: https://brainly.com/question/1446583

Answer:

Calculate the pOH for a solution with a hydroxide ion, (OH-) of concentration of 6.49 X 10-11 M.

Calculate the pH.

Note: the answers should have three significant figures

The pOH is: Blank 1

The pH is: Blank 2

Explanation:

Answer:

Stacking bags and bundles.

Explanation:

Interlock them in rows to ensure they're secure.

Answer:

Material Storage Facilities means an uncovered area used on a permanent basis for outside

Explanation:

Material Storage Facilities means an uncovered area where bulk materials (liquid, solid, granular, etc.) are stored in piles, barrels, tanks, bins, crates, or other means.

Additional Benchmarks for Federal, State, or Municipal Facilities with Incidental Solid De-Icing Material Storage Facilities monitoring under the requirements of subparagraph (D)(ii) above shall not be subject to Benchmark requirements for Chloride or Cyanide.

Directors are fully briefed on all business related matters, risk assessment and new initiatives proposed by the Company.

Answer:

the enthalpy change of this is 5.02mol

Answer:

28ft

Explanation:

if it's a square then each side is equal

the square root of 49 is 7

each side is 7 ft

7 ft times 4 sides is 28ft

Hexasulfur Dichloride

Name: Hexasulfur Dichloride

Formula: S2Cl6

Molar Mass:276.848

Example Reactions:

• S2Cl6 + 4H2O = 2SO2 + 6HCl + H2

Answer:

That would be True

Explanation:

granite is a part of the crust layer.

Answer:21 moles of PbCl2 formed

Answer: O2

Explanation:

The balanced chemical equation is:

4 Cr + 3 O2 ---> 2 Cr2O3

4 mol of Cr reacts with 3 mol of O2 to form 2 mol of Cr2O3

For 14.8 mol of Cr, 11.1 mol of O2 is required

But we have 10.3 mol of O2

So, O2 is the limiting reagent

A high pressure system has higher pressure at its center than the areas around it

Scientists that work in Antarctica mostly refer to the majority of the continent as being a cold desert

Explanation:

Hi!

[tex]\\ \sf\rightarrow pH=-log[H^+][/tex]

[tex]\\ \sf\rightarrow -log[H^+]=6.1[/tex]

[tex]\\ \sf\rightarrow log[H^+]=-6.1[/tex]

[tex]\\ \sf\rightarrow [H^+]=10^{-6.1}[/tex]

[tex]\\ \sf\rightarrow [H^+]=7.94M[/tex]

The mass, in grams, of 5.2 x 10^28 atoms of manganese would be 0.0006833 grams

According to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^{23}[/tex] atoms.

Thus, how many moles would be in 5.2 x [tex]10^{28}[/tex]atoms of Mn:

         = 6.022 x [tex]10^{23}[/tex] /1 x 5.2 x [tex]10^{28}[/tex]

                       = 0.00001158 moles

Mass of 0.00001158 moles Mn = 0.00001158 x 54.9

                         = 0.0006833 grams

More on Avogadro's constant can be found here: https://brainly.com/question/21177668

For a 35.83 g sample of potassium chlorate,  the mass of potassium chloride is mathematically given as

M Kcl=21.62g

Generally, the equation for the Chemical Reaction  is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

[tex]Mole of KCl=\frac{35.57}{122.55}[/tex]

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

Read more about Chemical Reaction

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Explanation:

pOH=-log(2.6×10^(-6)

we get around 5.59

(using log)

Answer:

Alkali metals (Li, Na, K, Rb, Cs, and Fr)

Explanation:

Answer:

Group 1

Explanation:

Answer:

Bubonic plague is the correct answer!!!

Explanation:

mark me brainliest

Answer:

The answer is Bubonic Plague

Answer:

monkey see, monkey do

Explanation:

boom :)

Answer:

I think it's a game with me and I will knock out a bit and I hope you are u all the way you can get a little bit of a good time to come over here in a bit of the world

Answer:

what is picture 4 you need to show it

Answer:

Distillation can be used to separate and collect a liquid from a solution. Distillation can also be used to soften water as the water evaporates as it is heated and the ions are left behind. Hard water can be softened by adding sodium carbonate (washing soda) or by passing the water through an ion-exchange column.

Explanation:

Molar mass of NaHCO_3

Now

[tex]\\ \sf\longrightarrow No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}[/tex]

[tex]\\ \sf\longrightarrow No\:of\; moles=\dfrac{2.61}{84}[/tex]

[tex]\\ \sf\longrightarrow No\:of\:moles=0.0312mol[/tex]