Answers
1) Indium and aluminum belong to the same group.
2) Barium belongs to groups 2 and 6
The periodic table is what?The compounds' names are;
Tetrachloro phosphorus chloride
Calcium bromide
Hexasulfur nitrogen
The following molecules balance the charges:
K3P, CaS, Al2O3
Chlorine and fluorine are elements of group 17
Magnesium and salt are the components that make up period 3.
The data are used to create the balanced equations;
Sn + 2H2O = SnO2 + H2
3O2 + 4Al = 2Al2O3
2Au + 3H2S = Au2S3 + 3H2
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Related Questions
Please name this compound.
Answers
Answer:
The chemical name for this compound is 4-ethyl-2-methylhex-2-ene.
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1. (16 points) Shown below are IR and MS data for a compound with a molecular formula of C3H₂O
a) Identify the functional groups
responsible for the labeled
absorptions in the IR spectrum.
i) 1601 cm¹
ii) 1691 cm¹
Relative Intensity
100-
80-
m/z
rel. Intensity
22.6
73.1
105 100.0
120
26.2
$1.0
77.0
50 60
TRATT
100 110 120
1601 cm
1691 cm³
iii) From the parent,
what mass is lost to form
the base peak at m/z =
105?
iv) What is the likely
structure of that
fragment that is lost
to form m/z 105?
70
m/z
v) From the parent, what mass is lost to form the m/z = 77 peak?
Answers
Answer:
i) 1601 cm¹ - This absorption is likely from a C=O stretching vibration indicative of an aldehyde or ketone functional group.
ii) 1691 cm¹ - This absorption is likely from an O-H stretching vibration indicative of an alcohol functional group.
iii) From the parent, the mass lost to form the base peak at m/z = 105 is 17 amu.
iv) The likely structure of the fragment that is lost to form m/z 105 is C2H2O.
v) From the parent, the mass lost to form the m/z = 77 peak is 28 amu.
vi) The likely structure of the fragment that is lost to form m/z 77 is C2H3O.
Explanation:
Assuming that the mass defect originates solely from the interactions of protons and neutrons in the nucleu, estimate the nuclear binding energy of Li given yhe following data.observee atomic mass (a.m.u) of Li is 7.01600u
1u=1.66054×10^-27kg
Electron rest mass= 9.10939×10^-31kg
Proton rest mass=1.67262×10^-27kg
Neutron rest mass=1.67493×10^-27kg
C=2.998×10^8
Answers
The mass lost in the formation of a nucleus is converted into energy in accordance with the Einstein's mass energy relationship and released, thereby tending to impart stability to the nucleus.
An input of the same amount of energy referred to as the binding energy would be required to decompose the nucleus into its component nucleons. So the energy released from the nucleons during the formation of a nucleus is called the binding energy.
No: of protons in 'Li' = 3
No: of neutrons in 'Li' = 4
Total mass of nucleons = 3(1.67262×10⁻²⁷) + 4 (1.67493×10⁻²⁷) = 1.171 × 10⁻²⁶ kg
Mass defect = 1.171 × 10⁻²⁶ - 1.165 × 10⁻⁻²⁶ = 6 × 10⁻²⁹
Binding energy = Δmc² = 6 × 10⁻²⁹ × (2.998×10⁸)² = 5.392 × 10⁻¹² J
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Given the following equations and H° values, determine the heat of reaction at 298 K for the reaction: C(s) + 2 H2(g) -> CH4(g)
H2 (g) + 1/2 02 (g) -> H20 (l)
CO2 (g) + 2 H20 (l) -> CH4 (g) + 2 02 (g)
C(s) + O2(g) -›CO2(g)
H kJ = - 393.5
H kJ = -285.8
H kJ = +890.3
Answers
The heat of reaction for the reaction C(s) + 2 H2(g) -> CH4(g) at 298 K can be calculated by using the following equation: ΔH = (ΔHf products - ΔHf reactants).
Applying this equation to the given reaction, we get ΔH = (-890.3 + 393.5 + 285.8) kJ = -210.0 kJ.
This is the heat of reaction at 298 K for the reaction C(s) + 2 H2(g) -> CH4(g).
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Can someone please help? And quickly if you can thank you!
Answers
The concept ideal gas equation is used here to determine the number of moles. The ideal gas law is the equation of state of a hypothetical ideal gas. Here the number of moles of gas is 0.17.
The equation which is formed by the combination of Boyle's law, Charles's law and Avogadro's law is called the ideal gas equation. An ideal gas is a theoretical gas composed of a set of randomly moving point particles which interact through elastic collisions.
The ideal gas equation is:
PV = nRT
n = PV / RT
10°C = 283 K
Number of moles is:
n = 1.2 × 3.4 / 0.0821 × 283 = 0.17
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You have 400,000 atoms of a radioactive substance. After 2 half-lives have past, how many atoms remain?
Remember that you cannot have a fraction of an atom, so round the answer to the nearest whole number.
Answers
After 2 half-lives, 100,000 atoms of the radioactive substance will remain.
If two half-lives have passed, the number of remaining atoms will be one-fourth (1/2 x 1/2 = 1/4) of the original number of atoms.
Therefore, the number of remaining atoms will be:
400,000 x (1/4) = 100,000 atoms
Rounding this to the nearest whole number, we get:
100,000 atoms
Therefore after 2 half-lives, 100,000 atoms of the radioactive substance will remain.
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Hydrogen bonding activity drawings
Answers
Answer:UIHIU
A small amount of chemical splashes in Frank’s eye. What should Frank do immediately?
Explanation:A small amount of chemical splashes in Frank’s eye. What should Frank do immediately?
Which compound represents fe+3 o-2
Answers
Answer:
The compound that represents Fe+3 O-2 is Fe2O3 (iron oxide or rust)
3 CO + Fe₂O3 --->2 Fe + 3 CO2
what is the mole ratio of carbon monoxide reacting to the amount of
carbon dioxide being produced?
Answers
A student's sample of Alka Seltzer (0.350 g) contained 0.207 g of sodium bicarbonate (NaHCO3). How many moles of NaHCO3 are in their sample?
Group of answer choices
Answers
The number of moles of the sodium bicarbonate is 0.0025 moles
What is the number of moles?We know that the moles is the amount of the substance that is contained and that we can get the moles as the ratio of the mass to the molar mass of the substance and that is what we are going to do in the case of the sodium bicarbonate that we have in the question that is here.
Now we have from the question that;
Mass of the sodium bicarbonate = 0.207 g
Number of moles of the sodium bicarbonate can now be gotten in this case by the use of the formula;
Number of moles
0.207 g/84 g/mol
= 0.0025 moles
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The nitrogen pressure at the Venusian surface is 2050 torr and the atmosphere of Venus is 3.0 mole% N2. What is the surface pressure on Venus in atm?
Answers
P = nRT/V
where P is the pressure, n is the number of moles, R is the gas constant, T is the temperature, and V is the volume.
First, we'll find the number of moles of nitrogen in the atmosphere:
n(N2) = 3.0/100 x n(total)
where n(total) is the total number of moles in the atmosphere.
Next, we'll rearrange the ideal gas law to solve for P:
P = nRT/V
We can assume that the volume is 1 mole of gas at STP, which is 22.4 L. The temperature on Venus is around 735 K. The gas constant is 0.08206 L atm/mol K.
Plugging in the values, we get:
P = (0.03)(0.08206)(735)/22.4
P = 0.679 atm
Therefore, the surface pressure on Venus is approximately 0.679 atm.
the upstairs in a house is usually warmer than downstairs. this is to to this type of heat transfer
Answers
Convection currents. Convection currents. allow hot air balloons to rise and explain why it is generally hotter upstairs than downstairs in dwellings.
What is heat transfer?Heat transfer is a thermal engineering subject that deals with the generation, consumption, conversion, and exchange of thermal energy between physical systems.
Heat transmission is categorized into several methods, including thermal conduction, thermal convection, thermal radiation, and energy transfer via phase shifts.
The Transfer of Heat Energy
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S8 + 12O2 -------> 8SO3
If you start with 873.2 g of S8 and 859.3 g of O2, what mass of SO3 will be produced?
Answers
The balanced chemical equation is:
S8 + 12O2 → 8SO3
The molar mass of S8 is 256.52 g/mol. Therefore, the number of moles of S8 is:
n(S8) = mass / molar mass = 873.2 g / 256.52 g/mol = 3.4 mol
The molar mass of O2 is 32.00 g/mol. Therefore, the number of moles of O2 is:
n(O2) = mass / molar mass = 859.3 g / 32.00 g/mol = 26.85 mol
According to the balanced chemical equation, the stoichiometric ratio of S8 to O2 is 1:12. Therefore, the number of moles of O2 needed to react with all of the S8 is:
n(O2) needed = n(S8) × 12 = 3.4 mol × 12 = 40.8 mol
Since the number of moles of O2 available (26.85 mol) is less than the number of moles of O2 needed (40.8 mol), O2 is the limiting reactant.
The theoretical yield of SO3 is based on the number of moles of O2 used. Since 12 moles of O2 are required to produce 8 moles of SO3, the number of moles of SO3 produced is:
n(SO3) = n(O2) × (8/12) = 26.85 mol × (8/12) = 17.90 mol
The molar mass of SO3 is 80.06 g/mol. Therefore, the mass of SO3 produced is:
mass(SO3) = n(SO3) × molar mass = 17.90 mol × 80.06 g/mol = 1433 g
Therefore, the mass of SO3 produced is 1433 g.
please can someone fill the blanks, and/or tell me if this information SO FAR is accurate
it's just about pH levels, bases and acids
Answers
The acid base indicators or neutralization indicators are the substances which are employed for the visual detection of the end point in acid base titrations on account of their ability to change colour during the pH change that occurs in vicinity of the end point.
The characteristic pH range in which an acid-base indicator changes colour is called the colour change interval. This varies widely with different indicators. For water pH = 7, acidic solution has pH < 7 and basic solution has pH > 7.
The correct order of pH is:
13 > 10 > 9 > 6 > 4 > 3
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N₂ +
H₂O →>>
NH, -
+
0₂
Answers
The balanced chemical equation for the reaction is:
N₂ + 3H₂O → 2NH₃ + O₂
The equation shows that nitrogen gas (N₂) and water (H₂O) react to form ammonia (NH₃) and oxygen gas (O₂). The coefficients in the balanced equation indicate that one molecule of N₂ reacts with three molecules of H₂O to produce two molecules of NH₃ and one molecule of O₂.
What is the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound? (Na2CO3 = 106)
Answers
Answer:
To calculate the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound , you can use the formula:
Amount (in moles) = Mass of substance / Molecular mass
The molecular mass of sodium trioxocarbonate (IV) (Na2CO3) is 106 g/mol, as given in the question. Substituting the values in the formula, we get:
Amount (in moles) = 5.3 g / 106 g/mol = 0.05 mol
Therefore, the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound is 0.05 mol.
Note that the given molecular mass of Na2CO3 must be used to obtain the correct answe12 .
Explanation:
The empirical formula of caffeine is C4H5N2O. If the molar mass of caffeine is 194.19 g/mol, what is the molecular formula of caffeine?
Answers
The molecular formula of caffeine is C₈H₁₀N₄O₂
To find the molecular formula of caffeine, we need to determine the ratio of the empirical formula to the actual molecular formula. The empirical formula gives us the smallest whole-number ratio of atoms in a compound, while the molecular formula gives us the actual number of atoms of each element in a molecule.
First, we need to calculate the empirical formula mass of caffeine:
Empirical formula mass = (4 x atomic mass of carbon) + (5 x atomic mass of hydrogen) + (2 x atomic mass of nitrogen) + (1 x atomic mass of oxygen)
Empirical formula mass = (4 x 12.01 g/mol)+ (5 x 1.01 g/mol) + (2 x 14.01 g/mol) + (1 x 16.00 g/mol)
Empirical formula mass = 96.09 g/mol
Next, we can calculate the ratio of the molar mass of caffeine to the empirical formula mass:
Ratio = Molecular mass / Empirical formula mass
Ratio = 194.19 g/mol / 96.09 g/mol
Ratio = 2.02
This ratio tells us that the molecular formula of caffeine is approximate twice the size of the empirical formula. To find the molecular formula, we can multiply the subscripts in the empirical formula by the ratio:
C₄H₅N₂O × 2 = C₈H₁₀N₄O₂
Therefore, the molecular formula of caffeine is C₈H₁₀N₄O₂.
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Measurements show that the energy of a mixture of gaseous reactants increases by 190 kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined easurements show that the energy of a mixture of gaseous reactants increases by during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that 143kJ of work is done on the mixture during the reaction.that of work is done on the mixture during the reaction.
Answers
The enthalpy or heat content of a system can be defined as the sum of the internal energy and the pressure volume energy of the system. It is denoted by H. The energy change of mixture is 47 kJ.
The transference of energy may take place in the form of work if the system and surroundings have different pressures. According to international conventions, work done on the system is positive and work done by the system is negative.
The enthalpy change is:
ΔH = ΔU + PΔV
190 = ΔU + 143
ΔU = 47 kJ
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Calculate the percent ionization of 0.115 M lactic acid in a solution containing 7.0×10−3 M sodium lactate.
Answers
The percent ionization of 0.115 M lactic acid in a solution containing 7.0×[tex]10^-^3[/tex] M sodium lactate is 1.22% as percent ionization of a weak acid in solution is a measure of how much of the acid has dissociated into its ions.
The chemical equation for the dissociation of lactic acid is:
HC₃H₅O₃ ⇌ H+ + C₃H₅O₃−
The Ka value for lactic acid is 1.4×10^−4 at 25°C.
Initial: [HC₃H₅O₃]] = 0.115 M, [NaC₃H₅O₃] = 7.0×[tex]10^-^3[/tex] M, [H+] = 0 M, [C₃H₅O₃−] = 0 M
Using the Ka expression for lactic acid,
Ka = [H+][C₃H₅O₃−]/[HC₃H₅O₃]]
Substituting the equilibrium concentrations into the equation and solving for x,
1.4×[tex]10^-^4[/tex]= [tex]x^2[/tex]/(0.115−x)
Solving for x using the quadratic formula,
x =1.4×[tex]10^-^3[/tex] M
Now the percent ionization of lactic acid:
% Ionization = [H+]/[HC₃H₅O₃] × 100%
% Ionization = (1.4×[tex]10^-^3[/tex] M)/(0.115 M) × 100%
% Ionization = 1.22%
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A saturated solution of a salt was made by adding 36.00 g to 150.0 g water. There was 5.00 g of salt on the bottom that didn't dissolve. What is the % solubility of the salt ?
Answers
Answer:
The mass of the salt that dissolved is:
36.00 g - 5.00 g = 31.00 g
The % solubility of the salt can be calculated using the formula:
% solubility = (mass of solute dissolved ÷ mass of saturated solution) × 100%
The mass of the saturated solution is:
36.00 g + 150.0 g = 186.00 g
Therefore, the % solubility of the salt is:
(31.00 g ÷ 186.00 g) × 100% = 16.67%
The % solubility of the salt is 16.67%.
Explanation:
Question 3 of 10
How can the effect of heat on a reaction be determined?
A. Heat will increase reaction rate, but not equilibrium position.
B. Heat always shifts a reaction toward reactant formation.
C. Heat always shifts a reaction toward product formation.
D. Heat is treated as a reactant or a product.
SUBMIT
Answers
Calculate the final temperature (in Celsius) of HCI gas if 0.500 L at 42°C and 0.950 atm is heated
until the volume reaches 1.81 L at 0.950 atm. (deg C)
Answers
T1 = 42 + 273.15 = 315.15 K
T2 = ? (to be determined)
Next, we can plug in the values given in the problem:
(P1 * V1) / T1 = (P2 * V2) / T2
(0.950 atm * 0.500 L) / 315.15 K = (0.950 atm * 1.81 L) / T2
Simplifying:
0.475 atmL / K = 1.7175 atmL / T2
Multiplying both sides by T2:
T2 * 0.475 atmL / K = 1.7175 atmL
Dividing both sides by 0.475 atm*L / K:
T2 = 1.7175 atmL / (0.475 atmL / K)
T2 = 362.63 K
Finally, we can convert the temperature back to Celsius by subtracting 273.15:
T2 = 362.63 K - 273.15 = 89.48°C
Therefore, the final temperature of HCl gas is 89.48°C.
How many moles of KF are contained in 180.0 mL of a 0.250 M solution?
Answers
Answer:
To calculate the number of moles of KF in a solution, we can use the formula:
moles = concentration x volume
where concentration is in units of moles per liter (M), and volume is in liters (L).
First, we need to convert the volume from milliliters (mL) to liters (L):
180.0 mL = 0.1800 L
Next, we can plug in the values we have:
moles = 0.250 M x 0.1800 L = 0.0450 moles
Therefore, there are 0.0450 moles of KF in 180.0 mL of a 0.250 M solution.
Explanation:
At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. You may want to reference (pages 641 - 644) section 15.6 while completing this problem. Part a if the initial concentration of no is 0.175 m, what is the equilibrium concentration of no? how is the quadratic equation set up i cannot get the right values
Answers
2NO(g) ⇌ N2(g) + O2(g)
The equilibrium constant expression is:
Kc = [N2][O2] / [NO]2
We are given that Kc = 2.4 × 10^3 at 2000°C.
If the initial concentration of NO is 0.175 M, then we can assume that the change in concentration of NO is "x" at equilibrium.
The equilibrium concentrations of N2 and O2 can be calculated as follows:
[N2] = x
[O2] = x
Substituting these values into the equilibrium constant expression and solving for "x" gives:
2.4 × 10^3 = (x)(x) / (0.175 - x)^2
This equation is quadratic in nature and needs to be solved using the quadratic formula:
x = [-b ± sqrt(b^2 - 4ac)] / 2a
where a = 1, b = -0.7, and c = -2.4 × 10^3.
Solving for "x" gives:
x = 0.021 M
Therefore, the equilibrium concentration of NO is 0.175 - 0.021 = 0.154 M.
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Combustion analysis of a 6.8253 g sample of an unknown organic compound produces 18.520 gof COzand 3.7905 gofH2O. The molar mass of the compound is 324.38 g/mol.Calculate the number of grams of C, H, and O in the original sample.
Answers
Saccharin (HNC7H4SO3) is a weak acid with pKa = 2.32 at 298 K.
a. Write a hydrolysis equation for the reaction of saccharin with water.
b. Calculate the pH of 0.10 M solution of saccharin.
c. Calculate the %ionization of the acid in this solution.
Answers
The pka or molarity of a solution may be used to calculate its pH. The saccharin solution in this area has a pH of 1.65.
The pH for a solution determines how acidic or basic it is. It refers to the opposite of the positive logarithm of the H+ ion concentration in maths. A solution that is acidic has a pH below 7, while a basic solution has a pH above 7.
Ka of an acid = [A-] [H+] / [HA]
ka = antilog (-pka)
= antilog (- 2.32)
= 0.0047
Ka = [H+]²/[HA]
[H+]² = Ka × [HA]
= 0.0047 × 0.11
= 0.00051
[H+] = 0.022.
pH = -log [H+]
= -log (0.022)
= 1.65
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Heat absorbed or released by a substance can be calculated with the equation _____________.
q = m × Cs × ∆T
q = m × Cs ÷ ∆T
q = m + Cs + ∆T
q = m + Cs
Answers
• q is the amount of heat (in joules or calories)
•m is the mass of the substance (in grams or kilograms)
•Cs is the specific heat capacity of the substance (in joules per gram per degree Celsius or per Kelvin)
•∆T is the change in temperature of the substance (in degrees Celsius or Kelvin)
Reversible reactions allow products to create the reactants after a chemical reaction has gone from reactants to products. Which of the following is an example of a reversible reaction?
A) Oxygen combining with hemoglobin in red blood cells in our body, and then the red blood cells delivering the oxygen to needed locations\
B) Ammonium chloride separating into ammonia and hydrogen chloride gas
C)Hydrogen and oxygen combining to form water, and then water being broken down by a cell to be used in cellular respiration
D)All of the above
Answers
Which of these terms best describe an urban community? Select the two
correct responses..
A. Open country
B. Very few shops and restaurants
C. Well-connected to natural systems
D. High-density human population
E. Tall buildings
SUBMIT
Answers
The two terms that best describe an urban community are D) high-density human population and E) tall buildings. Open country is typically associated with rural areas, and well-connected natural systems are often found in areas with lower levels of human activity.
Urban communities are characterized by a high concentration of people living in a relatively small area. This means that the population density in urban areas is significantly higher than in rural areas. This high density of population is what drives the development of tall buildings and other types of urban infrastructure. Urban communities are also characterized by the presence of tall buildings. The tall buildings are built to accommodate the high density of human population in urban areas, as they allow a larger number of people to occupy a smaller area of land.
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A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass percent?
.
Answers
A soft drink contains 33g of sugar in 349g of H[tex]_2[/tex]O. 14.3% is the concentration of sugar in the soft drink in mass percent.
One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.
In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.
Mass percent = (mass of solute/mass of solute+ mass of solvent)×100
= ( 33/ 33+ 349)×100
=14.3%
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