The equation for the given downward parabola is:
y = -x²+1
What is a parabola?
Any point on a parabola is located at an equal distance from both a fixed point and a fixed straight line. It is a U-shaped plane curve. The parabola's fixed line and fixed point are together referred to as the directrix and focus, respectively. The topic of conic sections includes a parabola, and all of its principles are discussed here. A parabola's general equation is either y = a(x-h)² + k or x = a(y-k)²+ h, where (h,k) signifies the vertex.
The given graph is a downward parabola.
The parabola equations are second-degree equations.
So we can eliminate options 1 and 2.
Now we can substitute the coordinate values and check for the correct equation.
One of the points on the parabola is (2,-3).
Taking equation y = -x²+1
y = -2²+1 = -4+1 = -3
Let us check for one more point.
Taking the point (-1,0).
y = -(-1)²+1 = -1+1 = 0
Therefore the equation for the given downward parabola is:
y = -x²+1
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Determine whether the integral is convergent or divergent. If it
is convergent, evaluate it. (If the quantity diverges, enter
DIVERGES.) ∫0 to [infinity] e^−7x dx
Convergent
The given integral is ∫0 to [infinity] e^−7x dx. Determine whether the integral is convergent or divergent. If it is convergent, evaluate it. (If the quantity diverges, enter DIVERGES.)Given integral is ∫0 to [infinity] e^−7x dx. To check the convergence or divergence of the given integral, we can use the following formula;∫a to [infinity] e^−x dx = e^−aGiven integral ∫0 to [infinity] e^−7x dx can be written as;∫0 to [infinity] e^−7x dx = e^−0...[as lower limit is zero]∫0 to [infinity] e^−7x dx = 1/7 [1/e^0 - 1/e^∞]∫0 to [infinity] e^−7x dx = 1/7 [1 - 0]∫0 to [infinity] e^−7x dx = 1/7 [1] = 1/7Since the integral is a finite value, the given integral is Convergent.The answer is Convergent.
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Jacky is installing a rectangular swimming pool in her back yard. It measures 25 feet by 50 feet. What is the area of her pool?
The area of the pool is 1250 ft².
What is an Area?
In mathematics, area is the measure of the size of a two-dimensional surface or region. It is usually expressed in square units, such as square meters (m²) or square feet (ft²). The area of a shape or region is calculated by multiplying its length by its width, or by using a specific formula depending on the shape.The concept of area is used in many areas of mathematics, science, and everyday life, such as geometry, physics, engineering, and architecture.
Given : length of pool = 25 ft
Breadth of pool = 50 ft
We know that area of a rectangle = length × Breadth
So, Area of Rectangular pool
= length × Breadth
= 25 × 50
= 1250 ft²
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11. A school is going on a field trip to the Bronx Zoo. It costs $34 for a group guided tour and
each student has to pay $8 admission. If the school has at most $450 to spend on the trip,
how many students can go on this trip?
Write and solve an inequality.
2
Inequality:
Answer:
25 POINTSSSSS!!!
The number of students who travel for the field trip is at most 52 students.
How many students can go on this trip?An inequality is a statement that of two quantities one is specifically less than or greater than another.
Cost of group guided tour = $34
Cost of each student admission = $8
Total amount spent by the school = at most $450
Number of students = x
The inequality:
34 + 8x ≤ 450
8x ≤ 450 - 34
8x ≤ 416
divide both sides by 8
x ≤ 416/8
x ≤ 52
Hence, x ≤ 52 students travel for the field trip.
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Please help me
4(2×5)-20÷5
3(4+2)×3
20÷5×2+19
15×2+30÷4
14+3×2-12÷3
Answer:
Step-by-step explanation:You do the brackets first 2X5= 10
10X4 = 40 - 20 / 5 . 20 divided by 5 = 4
40 - 4 = 36
B) 4+2= 6 X3 =18X3= 54
c) 20/5=4 X2 =8+19= 27
D)37.5
E) 3X2=6 12/3 = 4 14+6=20 20-4=16
A flower garden is shaped like a circle. Its diameter is 30 yd. A ring-shaped path goes around the garden. Its outer edge is a circle with diameter 36 yd.
The gardener is going to cover the path with sand. If one bag of sand can cover 6 yd, how many bags of sand does the gardener need? Note that sand comes
only by the bag, so the number of bags must be a whole number.
A ring-shaped path goes around the circle shaped flower garden. The gardener will need total 52 bags of sand to cover the ring-shaped path with sand.
We have a circle shaped flower garden. Also, Diameter of inner circle = 30 yd
radius of inner circle, r = 30/2 = 15 yd
Diameter of outer circle = 36 yd
So radius of outer circle, R = 36/2 = 18 yd
Area of inner circle = πr²
= π(15)² = 225π yd²
Area of Outer circle = πR²
= π(18)² = 324π yd²
A ring-shaped path goes around the garden. Thus, Area of shaded region
= Outer circle area - inner circle area that is πR² - πr²
= 325 π - 225π = π(324 - 225)
= 3.14× 99 = 310.86 yd²
Since we have a bag of sand can cover 6 yard. So, number of the requirements of bags of sand is calculated as = 310.86/6
= 51.81 ~ 52
since we want whole sand bags, so total Sandbags needed is equals the 52.
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help me on this ixl pls
Answer:
x = 120
Step-by-step explanation:
A regular polygon for something that has 3 sides (triangle) will have equal angles and sides, making this an equilateral and equiangular triangle. Because of this, the angles on the inside of the triangle are each 60 degrees. Angle x and the angle of the triangle make a straight line, x+60=180. This makes x equal to 120.
What is the percent of students who took PE?
*
1 point
43%
54%
47%
57%
[tex] \sf43\% \implies \: answer[/tex]
Lap Pool A has lanes for 3 swimmers and Lap Pool B has lanes for 10 swimmers. The lap pools have the same uniform depth. Lap Pool B contains approximately 6. 6 x 10 to the fifth power gallons of water
the volume of water in Lap Pool A is 1.33 x 10 to the fifth power gallons, and the volume of water in Lap Pool B is 6.6 x 10 to the fifth power gallons.
To calculate the amount of gallons of water in each lap pool, you will need to know the dimensions of each pool. Lap Pool A has 3 lanes and Lap Pool B has 10 lanes. We will assume that each lane is the same width and length and that both pools have the same uniform depth. Therefore, we can calculate the volume of water in each pool by multiplying the length and width of each lane and multiplying that by the number of lanes and the uniform depth of the pools. For example, if each lane is 10 feet long and 4 feet wide, then the volume of water in Lap Pool A is 10 x 4 x 3 x the uniform depth, and the volume of water in Lap Pool B is 10 x 4 x 10 x the uniform depth. The uniform depth is multiplied by both calculations to account for the depth of the pool. Therefore, the volume of water in Lap Pool A is 1.33 x 10 to the fifth power gallons, and the volume of water in Lap Pool B is 6.6 x 10 to the fifth power gallons.
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Determine the values of m and n for ????(x) = mx3 +12x2 +????x−3 giventhat the remainder when dividing by (x + 3) is zero, and whendivided by (x − 2) the remainder is 85.
The values of m and n for the polynomial [tex]p(x) = 3x^3 + 12x^2 - 15x - 3,[/tex] satisfying the given conditions, are m = 3 and n = -15.
To determine the values of m and n in the polynomial[tex]p(x) = mx^3 + 12x^2 + nx - 3[/tex], use the Remainder Theorem. According to the theorem, if a polynomial p(x) is divided by (x - a), the remainder is equal to p(a).
Given that when dividing p(x) by (x + 3) is zero, substitute -3 for x in the polynomial and set it equal to zero:
[tex]m(-3)^3 + 12(-3)^2 + n(-3) - 3 = 0[/tex]
Simplifying this equation gives us:
-27m + 108 + (-3n) - 3 = 0
-27m - 3n + 105 = 0
Next, we are given that the remainder when dividing p(x) by (x - 2) is 85. Using the same logic, we substitute 2 for x in the polynomial and set it equal to 85:
[tex]m(2)^3 + 12(2)^2 + n(2) - 3 = 85[/tex]
Simplifying this equation gives us:
8m + 48 + 2n - 3 = 85
8m + 2n + 45 = 85
Now we have a system of two equations with two variables:
-27m - 3n+ 105 = 0
8m + 2n + 45 = 85
Solving this system of equations will give us the values of m and n. By solving these equations, we find that m = 3 and n = -15.
Therefore, the values of m and n for the polynomial [tex]p(x) = 3x^3 + 12x^2 - 15x - 3,[/tex] satisfying the given conditions, are m = 3 and n = -15.
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Find the area of isosceles triangle 13cm height 10 cm base
The isosceles triangle has a surface area of 65 square centimetres. We may use the following formula to get the area of an isosceles triangle: Area is equal to (1/2) x base * height. If we substitute the values provided, we get: Area: 10 x 13 x (1/2) cm
65 square cm is the area.
As a result, the isosceles triangle with a base of 10 cm and a height of 13 cm has a surface area of 65 square cm.
The height of an isosceles triangle is perpendicular to the base, and it has two equal sides. An isosceles triangle's area may be calculated by multiplying the base and height of the triangle and dividing the result by two. The triangle's base in this instance is 10 cm, while its height is 13 cm. These values are substituted into the calculation, and the result is that the triangle's area is 65 square cm. As a result, the isosceles triangle has a 65 square centimetre area.
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What is the area of an isosceles triangle with a height of 13 cm and a base of 10 cm?
Jane sees 5 pandas in a nature magazine.
Jane sees 7 fewer pandas than Quinn.
How many pandas does Quinn see?
Jane sees 5 pandas in a nature magazine. Jane sees 7 fewer pandas than Quinn. Quinn sees 12 pandas.
Let's assume that Quinn sees x pandas.
We are told that Jane sees 7 fewer pandas than Quinn. Therefore, Jane sees x - 7 pandas.
We know that Jane sees 5 pandas. So we can set up an equation:
x - 7 = 5
To solve for x, we add 7 to both sides of the equation:
x - 7 + 7 = 5 + 7
x = 12
Therefore, Quinn sees 12 pandas.
We can check our answer by verifying that Jane sees 7 fewer pandas than Quinn:
12 - 7 = 5
The answer is consistent with the information given in the problem, and we can conclude that Quinn sees 12 pandas.
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Laila needs a new bike mirror. Her old mirror was a square with a side length of 7 cm. She wants
the new mirror to have approximately the same area as her old bike mirror.
Which circular bike mirror should Laila buy?
4 cm
7 cm
8 cm
In a case whereby Laila needs a new bike mirror. Her old mirror was a square with a side length of 7 cm the circular bike mirror Laila should buy is 4 cm.
How can the circular bike mirror be determined?Given that the side length = 7 cm
Then we can know the Old mirror's area using the formula
Area = (S X S)
Where S is the side
=( 7 x 7 )
= 49cm2
Then from the information from the question, we can equate the area of the old and the new as
(Area of old mirror = Area of new mirror)
where Area of new mirror = πr^2
(49 = πr^2)
49 = (22/7 * r^2)
r^2 = 49 *7/22
r= 3.948 cm
r = 4cm
If we approximate it , hence option A is correct.
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In a population of scores, x = 83 corresponds to z = -0. 05 and x = 0. 93 corresponds to. Z = 2. 0. What are the values for the population mean and standard deviation?
The pοpulatiοn mean is apprοximately 84.93 and the pοpulatiοn standard deviatiοn is apprοximately 38.54.
What is the mean and standard deviatiοn?The standard deviatiοn is a summary measure οf the differences οf each οbservatiοn frοm the mean. If the differences themselves were added up, the pοsitive wοuld exactly balance the negative and sο their sum wοuld be zerο. Cοnsequently, the squares οf the differences are added.
We can use the fοrmula fοr standardizing a variable using z-scοres:
z = (x - μ) / σ
where z is the z-scοre, x is the cοrrespοnding raw scοre, mu is the pοpulatiοn mean, and sigma is the pοpulatiοn standard deviatiοn.
We have twο pairs οf (x, z) values:
x = 83, z = -0.05
x = 0.93, z = 2.0
We can use these tο create twο equatiοns with twο unknοwns ( and sigma):
-0.05 = (83 - μ) / σ
2.0 = (0.93 - μ) / σ
We can sοlve this system οf equatiοns by first sοlving οne οf the equatiοns fοr οne οf the unknοwns, and then substituting that expressiοn intο the οther equatiοn. Fοr example, we can sοlve the first equatiοn fοr mu:
mu = 83 + 0.05 * σ
Then we substitute this expressiοn fοr mu intο the secοnd equatiοn:
2.0 = (0.93 - (83 + 0.05 * σ)) / σ
Simplifying this equatiοn, we get:
2.0 = (0.93 / σ) - (83 / σ) - 0.05
2.05 = 0.93 / σ - 83 / σ
2.05 = (0.93 - 83) / σ
σ = (0.93 - 83) / 2.05
σ = 38.5366
Nοw we can use this value tο find the pοpulatiοn mean μ:
μ = 83 + 0.05 * σ
μ = 83 + 0.05 * 38.5366
μ = 84.9278
Therefοre, the pοpulatiοn mean is apprοximately 84.93 and the pοpulatiοn standard deviatiοn is apprοximately 38.54.
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The intersection of the two paths shown forms two similar triangles. If AC is 50 yards, MP is 35 yards, and the fountain is 5 yards from the intersection, about how far from the intersection is the stadium entrance? Round to the nearest yard.
The square root of 2275 is 47.71, so the distance from the intersection to the entrance of the stadium is about 48 yards. Rounding to the nearest yard, we get 48 yards.
What is a right triangle?A right triangle is a type of triangle that has one 90 degree angle. The other two angles are acute angles and their sum adds up to 90 degrees. The two sides that are not the right angle are called the legs and the longest side is called the hypotenuse. The Pythagorean Theorem is used to find the lengths of the sides of a right triangle.
This problem can be solved using the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Using this theorem, we can calculate the length of PC, which is then the same as the distance from the intersection to the stadium entrance.
First, we can calculate the length of CM by subtracting MP from AC, which gives us 50 - 35 = 15. We can then apply the Pythagorean Theorem to the triangle ACM to calculate the length of PC. The hypotenuse, AC, is 50, one of the other sides, CM, is 15, and the last side, the one we are trying to solve for, is PC. We can rearrange the Pythagorean Theorem to solve for PC, which gives us PC = √(AC2 - CM2). Plugging in the numbers, we get PC = √(502 - 152), which equals √(2500 - 225), or √2275. The square root of 2275 is 47.71, so the distance from the intersection to the entrance of the stadium is about 48 yards. Rounding to the nearest yard, we get 48 yards.
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the sum of the areas of two squares on the legs (a and b) equals the area of the square on the hypotenuse (c)??????
This is known as the Pythagorean Theorem and states that the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b).
What is area?Area is a measure of the size of a surface or space. It is typically measured in two-dimensional units such as square meters, square kilometers, and acres. Area is also used to measure the size of three-dimensional objects such as cubes and spheres. Area is a fundamental concept in mathematics and is often used to calculate the perimeter, circumference, and volume of shapes. In physics, area is used to measure the amount of energy an object absorbs or releases.
This theorem is one of the most famous theorems in mathematics, and is found in several ancient mathematical texts, including those from the Babylonians and Chinese. The theorem is attributed to the Greek mathematician Pythagoras, who lived in the 6th century BC.
The theorem can be expressed in the equation [tex]a^{2}+ b^{2} = c^{2}[/tex], where a and b are the lengths of the two legs of the right triangle and c is the length of the hypotenuse. This equation can be used to calculate the length of the hypotenuse if the lengths of the two other sides are known. For example, if the two legs of a right triangle have lengths of 3 and 4, the length of the hypotenuse can be calculated using the equation [tex]3^{2} + 4^{2}[/tex] = [tex]c^{2}[/tex], which results in c = 5.
The Pythagorean Theorem can be used to solve many mathematical problems related to triangles, as well as to solve problems in other areas such as geometry, physics, and engineering. In addition, the theorem is often used to prove theorems in mathematics, such as the law of cosines.
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Complete question is:
In pythagoras theorem, the sum of the areas of two squares on the legs (a and b) equals the area of the square on the hypotenuse (c) that is . discuss.
5. NEIGHBORS Amy, Barry, and Chris live on the same block. Chris lives up the street and around the corner from Amy, and Barry lives at the corner between Amy and Chris. The three homes are the vertices of a right triangle.
a. Give two trigonometric expressions for the ratio of Barry's distance from Amy to Chris' distance from Amy.
b. Give two trigonometric expressions for the ratio of Barry's distance from Chris to Amy's distance from Chris.
c. Give a trigonometric expression for the ratio of Amy's distance from Barry to Chris' distance from Barry.
The expression for the ratio will be AB/BC = sin(∠BAC)/sin(∠CAB).
What is Expression?
An expression is mathematical phrase that can contain numbers, variables, operators, and functions, but does not have equal sign. It represents value or mathematical operation that can be evaluated or simplified.
we can use the Pythagorean theorem to find the distances between the houses, and then use trigonometric ratios to find the ratios between them.
Let's assume that Amy's house is located at point A, Barry's house is located at point B, and Chris's house is located at point C, as shown in the diagram below.
C
|
|
---A--------
|
|
B
a. To find the ratio of Barry's distance from Amy to Chris' distance from Amy, we can use the following trigonometric expressions:
tan(∠BAC) = AB/AC (opposite/adjacent)
tan(∠CAB) = AC/AB (opposite/adjacent)
Therefore,
AB/AC = 1/tan(∠BAC)
AC/AB = 1/tan(∠CAB)
b. To find the ratio of Barry's distance from Chris to Amy's distance from Chris, we can use the following trigonometric expressions:
tan(∠ACB) = AB/BC (opposite/adjacent)
tan(∠ABC) = AC/BC (opposite/adjacent)
Therefore,
AB/BC = tan(∠ACB)
AC/BC = tan(∠ABC)
c. To find the ratio of Amy's distance from Barry to Chris' distance from Barry, we can use the following trigonometric expression:
sin(∠BAC) = AB/BC (opposite/hypotenuse)
sin(∠CAB) = AC/BC (opposite/hypotenuse)
Therefore,
AB/BC = sin(∠BAC)
AC/BC = sin(∠CAB)
So,
AB/BC = sin(∠BAC)/sin(∠CAB).
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From 1950 and projected to 2050, the percent of women in the workforce can be modeled by w(x) = 9.42 + 8.70 ln(x) where x is the number of years past 1940.† If this model is accurate, at what rate will the percent be changing in 2039? (Round your answer to three decimal places.) %
The percent of women in the workforce is expected to increase by 0.0879% in 2039, according to the given model.The given function is w(x) = 9.42 + 8.70 ln(x), where x represents the number of years past 1940.
To find the rate of change of the percent in 2039, we need to find the derivative of the function with respect to x.
w(x) = 9.42 + 8.70 ln(x)
Differentiating both sides with respect to x, we get:
dw/dx = 8.70 / x
Substituting x = 99 (since 2039 is 99 years past 1940), we get:
dw/dx = 8.70 / 99
Therefore, the rate of change of the percent in 2039 is approximately 0.0879%, rounded to three decimal places.
Therefore, the percent of women in the workforce is expected to increase by 0.0879% in 2039, according to the given model.
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A student is equally likely to select pizza, nachos or, chicken for lunch. what is the probability the student DOES NOT select chicken?
1/3, 1/2, 1/3 or 1?
Answer:
Since the student is equally likely to select pizza, nachos, or chicken for lunch, the probability of selecting each of these options is 1/3.
The probability that the student does not select chicken is the probability of selecting pizza or nachos, which are the two options other than chicken. Since these two options are equally likely, the probability of selecting pizza or nachos is 1/2.
Therefore, the probability that the student does not select chicken is 1/2.
if anyone that actually understands, could help, would be much appreciated
Answer:
a. -1
b. 1
c. 6
Step-by-step explanation: f(any value) just means plug in the value given inside of the f and see what y value comes out. for the first on, go to where four it on the x-axis and you will see that the y-value is -1. Repeat the same thing for f(0) where you can look directly on the y-axis and get 1 as the answer. Lastly, look where -4 meets the y-axis and it will be 6.
Find an equation of the line with gradient 1 and that passes through the point
(1,-4)
Submit Answer
Answer:
y = x - 5
Step-by-step explanation:
Using the 'y=mx+c' form,
Since m = 1,
y = x + c
Substituting (1, -4) into the above equation:
-4 = 1 + c
c = -5
Hence,
y = x - 5
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Janelle is packing a suitcase that currently weighs 22 kg22kg22, start text, k, g, end text. She has one more item to pack that weighs xxx kilograms. She wrote this equation to think about the total weight of the suitcase (t)(t)left parenthesis, t, right parenthesis given the weight of the final item (x)(x)left parenthesis, x, right parenthesis:
x+22=tx+22=tx, plus, 22, equals, t
Identify the dependent and independent variables
Answer:
1. independent 2. dependent
Step-by-step explanation:
The female population of NYC is about 13/25 of the total city population. About what percent of the population in NYC is female.
Answer:
52%
Step-by-step explanation:
We first divide the numerator by the denominator
13/25 we get 0.52. Then we would multiply 0.52 by 100 giving us 52, The percentage.
The two sides of a rectangle are 15cm and 20cm. Find the length of its diagonal
The length of the diagonal of the rectangle is 25cm.
The diagonal of a rectangle is the line segment that connects the two opposite vertices. It can be calculated using the Pythagorean Theorem, which states that the square of the hypotenuse (the longest side of a right triangle) is equal to the sum of the squares of the other two sides.
In this case, the length of the two sides of the rectangle are 15cm and 20cm. To calculate the diagonal of the rectangle, we need to use the Pythagorean Theorem to solve for the hypotenuse, which is the diagonal of the rectangle.
The formula is: a² + b² = c²
Using the sides of the rectangle, we get: 15² + 20² = c²
Simplifying the equation, we get: 225 + 400 = c²
Then, we take the square root of both sides of the equation to find the length of the diagonal:
√625 = c
The length of the diagonal of the rectangle is 25cm.
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hello math question!!!!!!!!!!
Answer:
The answer would be D
Hope this helps!
Scale Items Work Engagement Items – measured on a 1-7 scale (1-Never, 7-Always) At my work, I feel bursting with energy At my job, I feel strong and vigorous When I get up in the morning I feel like going to work I am enthusiastic about my job I am proud of the work I do I feel happy when I am working intensely I am immersed in my work I get carried away when I am working Job Tension Items – measured on 1-7 scale (1-Strongly disagree, 7-Strongly agree) My job is extremely stressful Very few stressful things happen to me at work I feel a great deal of stress because of my job I almost never feel stressed because of my work Career Satisfaction Items – measured on 1-7 scale (1-strongly disagree, 7-strongly agree) I am satisfied with the Success I have achieved in my career Success I have made toward meeting my overall career goals Progress I have made toward meeting my goals for income Progress I have made toward meeting my goals for advancement Progress I have made toward meeting my goals for developing new skills Perceived Internal Mobility Items – measured on 1-5 scale (1-strongly disagree, 5-strongly agree) My organization views me as an asset to the organization Given my skills and experience, my organization views me as a value-added resource There are many opportunities available for me in my organization Perceived Supervisory Support Items – measured on1-7 scale (1-Strongly disagree, 7- Strongly agree) My supervisor strongly considers my goals and values Help is available from my supervisor when I have a problem My supervisor really cares about my well-being My supervisor would forgive an honest mistake on my part My supervisor is willing to help me when I need a special favor If given the opportunity, my supervisor would take advantage of me My supervisor shows very little concern for me My supervisor cares about my opinions
The my supervisor cares about my opinions.
Scale Items Work Engagement Items – measured on a 1-7 scale (1-Never, 7-Always): At my work, I feel bursting with energy; at my job, I feel strong and vigorous; when I get up in the morning I feel like going to work; I am enthusiastic about my job; I am proud of the work I do; I feel happy when I am working intensely; I am immersed in my work; I get carried away when I am working.
Job Tension Items – measured on 1-7 scale (1-Strongly disagree, 7-Strongly agree): My job is extremely stressful; very few stressful things happen to me at work; I feel a great deal of stress because of my job; I almost never feel stressed because of my work.
Career Satisfaction Items – measured on 1-7 scale (1-strongly disagree, 7-strongly agree): I am satisfied with the success I have achieved in my career; success I have made toward meeting my overall career goals; progress I have made toward meeting my goals for income; progress I have made toward meeting my goals for advancement; progress I have made toward meeting my goals for developing new skills.
Perceived Internal Mobility Items – measured on 1-5 scale (1-strongly disagree, 5-strongly agree): My organization views me as an asset to the organization; given my skills and experience, my organization views me as a value-added resource; there are many opportunities available for me in my organization.
Perceived Supervisory Support Items – measured on 1-7 scale (1-Strongly disagree, 7- Strongly agree): My supervisor strongly considers my goals and values; help is available from my supervisor when I have a problem; my supervisor really cares about my well-being; my supervisor would forgive an honest mistake on my part; my supervisor is willing to help me when I need a special favor; if given the opportunity, my supervisor would take advantage of me; my supervisor shows very little concern for me; my supervisor cares about my opinions.
Answer: The question asks about scale items measuring Work Engagement, Job Tension, Career Satisfaction, Perceived Internal Mobility, and Perceived Supervisory Support, all measured on different scales. Work Engagement is measured on a 1-7 scale (1-Never, 7-Always), Job Tension is measured on a 1-7 scale (1-Strongly disagree, 7-Strongly agree), Career Satisfaction is measured on a 1-7 scale (1-strongly disagree, 7-strongly agree), Perceived Internal Mobility is measured on a 1-5 scale (1-strongly disagree, 5-strongly agree), and Perceived Supervisory Support is measured on a 1-7 scale (1-Strongly disagree, 7- Strongly agree). In terms of Work Engagement, the items are: At my work, I feel bursting with energy; at my job, I feel strong and vigorous; when I get up in the morning I feel like going to work; I am enthusiastic about my job; I am proud of the work I do; I feel happy when I am working intensely; I am immersed in my work; I get carried away when I am working. For Job Tension, the items are: My job is extremely stressful; very few stressful things happen to me at work; I feel a great deal of stress because of my job; I almost never feel stressed because of my work. For Career Satisfaction, the items are: I am satisfied with the success I have achieved in my career; success I have made toward meeting my overall career goals; progress I have made toward meeting my goals for income; progress I have made toward meeting my goals for advancement; progress I have made toward meeting my goals for developing new skills. For Perceived Internal Mobility, the items are: My organization views me as an asset to the organization; given my skills and experience, my organization views me as a value-added resource; there are many opportunities available for me in my organization. Finally, for Perceived Supervisory Support, the items are: My supervisor strongly considers my goals and values; help is available from my supervisor when I have a problem; my supervisor really cares about my well-being; my supervisor would forgive an honest mistake on my part; my supervisor is willing to help me when I need a special favor; if given the opportunity, my supervisor would take advantage of me; my supervisor shows very little concern for me; my supervisor cares about my opinions.
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Let the density function of a continuous random variable X be f(x) = 0 if x<0 . 2x/bc if 0≤x≤c
. 2(b-x)/b(b-c) if c≤x≤b
. 0 if x>b
a) Find the CDF of X
b) Find E[X]
c) Find Var(X)
d) What is the range of X?
(X) = (c² - bc + b²)/9d)
a) CDF of X:To calculate the cumulative distribution function of X, we must break the problem into two parts: from 0 to c and from c to b.Case 1: 0≤x≤cThe cumulative distribution function of X from 0 to c is given by:F(x) = ∫f(x)dx = ∫(2x/bc)dx (evaluated from 0 to x)= 2x²/2bcevaluated from 0 to c= c²/bc = c/bCase 2: c≤x≤bThe cumulative distribution function of X from c to b is given by:F(x) = ∫f(x)dx = ∫(2(b-x)/b(b-c))dx (evaluated from c to x)= (2(b-x)(x-c))/(b(b-c))evaluated from c to b= 1- (2(b-c)²)/(2b(b-c))= 1 - (b-c)/b= c/bTherefore, the cumulative distribution function of X is:F(x) = {0, if x < 0;c/b, if 0 ≤ x ≤ c;1 - (b-c)/b, if c ≤ x ≤ b;0, if x > b}b) E[X]:To find the expected value of X, we must find the mean of the distribution. For 0≤x≤c, the expected value isE[X] = ∫x.f(x)dx = ∫x(2x/bc)dx (evaluated from 0 to c)= c²/bFor c≤x≤b,E[X] = ∫x.f(x)dx = ∫x(2(b-x)/b(b-c))dx (evaluated from c to b)= (b+c)/3Therefore, the expected value of X isE[X] = (c²+ b²+ c.b)/(3b) = (b+ c/3)²c) Var(X):To calculate the variance of X, we must first calculate the expected value squared of X. E[X²]For 0≤x≤c,E[X²] = ∫x².f(x)dx = ∫x²(2x/bc)dx (evaluated from 0 to c)= c³/3bFor c≤x≤b,E[X²] = ∫x².f(x)dx = ∫x²(2(b-x)/b(b-c))dx (evaluated from c to b)= (2c² + b²)/3Therefore, the expected value squared of X isE[X²] = (c³/3b) + (2c² + b²)/3Now we can calculate the variance using the formula:Var(X) = E[X²] - [E[X]]²= [(c³/3b) + (2c² + b²)/3] - [(b+ c/3)²]= (c² - bc + b²)/9Therefore, the variance of X isVar(X) = (c² - bc + b²)/9d) Range of X:The range of X is [0,b], as given in the density function of X. The range of a continuous random variable is the set of values that the variable can take on. The range of X is from 0 to b because the function f(x) is only defined on this interval. Therefore, X cannot take on any values outside this range.
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The answer to the question please
The decimal 0.222... rewritten as a fraction is; 2/9
How to convert decimal to fraction?To convert a specific decimal to a particular fraction, what we will do is to place the decimal number all over its place value. For example, in 0.8, the eight is in the tenths place, and as such we place 8 over 10 to generate the equivalent fraction, 8/10. However, if required, then we can simplify the fraction.
We want to convert the decimal 0.222... to fraction. Thus, we have;
222/1000
Divide both the numerator and the denominator by 2 to get;
111/500
Now, 0.2222… is equal to the fraction with 2 in its numerator (since that’s the single number after the decimal point that’s repeating over and over again) and 9 in its denominator. In other words, 0.2222… = 2/9.
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Please help mee in question 11
There are 18 different chairs in total.
Describe Multiplication?Multiplication is an arithmetic operation that involves combining two or more numbers to get a product. The numbers being multiplied are called factors, and the result of multiplication is called the product.
Multiplication can also be represented using symbols, such as the multiplication sign (x) or a dot (.). For example, 2 x 3 can also be written as 2 . 3.
Multiplication is a fundamental operation in mathematics and is used in many different areas, including algebra, geometry, and calculus. It has numerous applications in science, engineering, economics, and many other fields.
There are a total of 24 different chairs that are available.
3 finishes: dark, light, or oak
3 seat cover colors: tan, black, or cream
2 heights: regular or tall
Therefore, the total number of different chairs is calculated as:
3 (finishes) x 3 (seat cover colors) x 2 (heights) = 18
So, there are 18 different chairs in total.
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There are 18 different chairs in tοtal.
Describe Multiplicatiοn?Multiplicatiοn is an arithmetic οperatiοn that invοlves cοmbining twο οr mοre numbers tο get a prοduct. The numbers being multiplied are called factοrs, and the result οf multiplicatiοn is called the prοduct.
Multiplicatiοn can alsο be represented using symbοls, such as the multiplicatiοn sign (x) οr a dοt (.). Fοr example, 2 x 3 can alsο be written as 2 . 3.
Multiplicatiοn is a fundamental οperatiοn in mathematics and is used in many different areas, including algebra, geοmetry, and calculus. It has numerοus applicatiοns in science, engineering, ecοnοmics, and many οther fields.
There are a tοtal οf 24 different chairs that are available:
3 finishes: dark, light, οr οak
3 seat cοver cοlοrs: tan, black, οr cream
2 heights: regular οr tall
Therefοre, the tοtal number οf different chairs is calculated as:
3 × 3 × 2 = 18
So, there are 18 different chairs in total.
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OMG I HAVE ONLY TODAY TO SUBMIT THIS AND I REALLY NEED HELP!! PLEASE
Answer:
The constant of proportionality is 2.5. The equation that represents this proportional relationship is y=2.5x.
Step-by-step explanation:
to find the constant of proportionality -> for every time x goes up, what does y go up by? when x goes up by 2, y goes up by 5. difference of y/difference of x = 5/2 =2.5.
to find the equation -> y=?x. plug in the constant of proportionality in the question mark. so, y=2.5x.
Show that the two triangles are similar.
11. The triangles are similar to each other by SAS rule of congruency.
12. The triangles are similar to each other by ASA rule of congruency.
13. The triangles are similar to each other by SSS rule of congruency.
Define similar triangles?Triangles that resemble one another but may not be precisely the same size are said to be comparable triangles. If two objects are similar in shape but have different sizes, they are considered to be comparable.
This indicates that comparable shapes superimpose one another when amplified or demagnified. The term "Similarity" refers to this characteristic of like shapes.
Now in the 1st given figure,
One pair of angles are equal to each other, and the sides of the triangle ACE and BCD are in proportion to each other.
So, we can say that the triangles are similar to each other.
In the 2nd figure,
One pair of angles are equal to each. Another pair is equal to each other as the lines are dissecting each other.
And the side is in equal proportion to each other. So, the triangles are congruent to each other.
In the last figure,
One side of the triangle are parallel to each other.
The other sides are in proportion to each other.
Hence, all the three cases triangles are similar to each other.
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