Hello, do these calculations using table 1 look correct? Thank you

Table 1.
Sugar (Sucrose) Data
Mass of unchewed gum 3.7 (g)
Mass of chewed gum 2.0 (g)
Mass of sugar 1.7 (g)
Percent sugar
46%

Post-Lab Questions
1. What is the percent sugar? Show your calculations.
mass of sugar (1.7) ÷ mass of unchewed gum ( 3.7) × 100 = 45.94 (46%)
2. What is the molar mass of sugar (sucrose, C12H22O11)? Show your calculations.
C=12×12=144
H=1×22=22
O=16×11=176
To get the molar mass of the entire compound you, 144 + 22 + 176 = 342 g/mol
3. Convert the mass of dissolved sugar to moles. Show your calculations.
1.7 g ÷ 342 g/mol = 0.00497 moles
4. Convert the moles of sugar to molecules of sugar. Show your calculations.
0.00497 mole × 6.022 × 10^23 = 2.992934 × 10^21 molecules
5. Imagine that you used four pieces of gum instead of two. Calculate the number of moles. Show your calculations.
In theory, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double.
2 ÷ 342 g/mol × 1.7 = 0.00994 moles
6. How does the mass of the saliva alter the experimental data?
It is impossible to blot off all the saliva with a paper towel because the gum sticks to the paper, so it adds more mass to the chewed gum and therefore alters the amount and percent of sugar calculations.

Answers

Answer 1

Answer:

yes it does look correct. good job.

Answer 2

Post- lab the percent sugar 46%, and the molar mass of sugar is 342 g/mol,  the mass of dissolved sugar to moles is 0.00497 moles of sugar to molecules of sugar is  2.992934 × 10^21 molecules, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double  0.00994 moles.

What are moles?

moles is the unit of the molecule and it is defined as the number of molecules participating in a chemical reaction and value of one mole is equal to Avogadro constant that is 2.303 × 10²³

Sugar percentage = mass of sugar / mass of gum × 100  = 1.7 / 3.7 × 100 =  45.94 (46%)

Molar mass of sugar = C12H22O11 = C=12×12=144 + H=1×22=22  + O=16×11=176 = 342 g/mol  

Mass of dissolved sugar to moles = 1.7 g ÷ 342 g/mol = 0.00497 moles

The moles of sugar to molecules of sugar = 0.00497 mole × 6.022 × 10^23 = 2.992934 × 10^21 moleculesIn the given theory using four pieces of gum will exactly be the same to the mass of sugar.2 ÷ 342 g/mol × 1.7 = 0.00994 moles

The mass of the saliva alter the experimental data because it is not possible to remove all the saliva from the surface as it gets stick to the paper which changes the amount of sugar.

Therefore, the percent sugar 46%, and the molar mass of sugar is 342 g/mol, the mass of dissolved sugar to moles is 0.00497 moles of sugar to molecules of sugar is  2.992934 × 10^21 molecules, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double  0.00994 moles.

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Related Questions

The change in enthalpy that occurs in the process of converting reactants to products in a chemical reaction is called the _____ of reaction.

Answers

Answer:

∆H or Enthalpy of the reaction

Explanation:

If ∆H is +ve

Reaction is exothermicExample:-Combustion, mixing sodium/potassium in water

If ∆H is -ve

Reaction is endothermicEx:-Melting of ice

6Li + N2 → 2Li3N chemical word equation

Answers

Answer:

this is an Oxidation-reduction

Explanation:

like is w reducing agent, N2 is an oxidizing agent

Which jobs does the respiratory system do? Select all that apply. It brings oxygen into the blood. It removes carbon dioxide waste from the blood. It pumps blood throughout the body. It takes in oxygen from air or water.​

Answers

Answer:

probably the last one should hbthrbwhdee.

Answer:

it brings oxygen into the blood and removes carbon dioxide

Explanation:

In which pair do both compounds exhibit predominantly ionic bonding?
A. RbCl and CaO
B. Kl and O3
C. Na2SO3 and BH3
D. NaF and H2O
E. PCl5 and HF

Answers

Answer:

In pair NaF and H2O both compounds exibit predominantly ionic bonding.

NaF and H[tex]_2[/tex]O exhibit predominantly ionic bonding. Therefore, the correct option is option D among all the given options.

What is ionic bond?

Ionic bonding produces ionic, or electrovalent, combinations, which are best represented by compounds created between nonmetals and alkali as well as alkaline-earth metals.

The electrostatic attraction forces among opposing charges as well as repulsion between comparable charges position the ions in such a way that every positive charge is surround by negative ions as well as vice versa within ionic crystal structures of such a type.

In summary, the ions are organized in such a way that negative and positive charges alternate constantly balance one another, resulting in a total charge of zero for the entire material. NaF and H[tex]_2[/tex]O exhibit predominantly ionic bonding.

Therefore, the correct option is option D.

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N2+3H2 → 2NH3

A) How many grams of NH3 can be produced from the reaction of 28g of N2 and 25g of H2?
I need the steps to the answer 34g

B) How much of the excess reagent is left over?
I need steps to the answer 19 g

Answers

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.

What is Mole?

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of N₂ = 28g

Mass of H₂ = 25g

Moles of N₂ = mass / molar mass

                    = 28 / 28

                   = 1 mole

Moles of H₂ = 25 / 2

                     = 12.5 moles

Since the number of moles of N₂ is lesser, the amount of products formed depends on the moles of N₂.

From the reaction,

1 mole of N₂ gives 2 moles of NH₃

So, Mass of NH₃ in 2 moles = 2 × 17

                                              = 34g

B) From the reaction,

1 mole of N₂ reacts with 3 moles of H₂.

The number of Moles of H₂ left = 12.5 - 3

                                                    = 9.5 moles

Mass of excess reagent left = moles left × molar mass of H₂

                                             = 9.5 × 2

                                             = 19g

Therefore, 34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.

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Which of the following will oxygen react with to cause combustion?
O A. A hydrocarbon
O B. Heat
O C. Carbon dioxide
O D. Water
HELP

Answers

Answer:

hydrocarbon

Explanation:

it reacts with oxygen to produce water and carbon dioxide.

hope this helps.

Human colour vision is “produced” by the nervous system based on how three different cone receptors interact with photons of light in the eye. These three different types of cones interact with photons of different frequency light, as indicated in the following chart: Cone Type Range of Light Frequency Detected S 6.00-7.49 x 1014 s-1 M 4.76-6.62 x 1014 s-1 L 4.28-6.00 x 1014 s-1 What wavelength ranges (and corresponding colours) do the three types of cones detect?

Answers

The colors and the corresponding wavelengths the three types of cones detect are:

Blue: 450–495 nmGreen: 495–570 nmRed: 620–750 nm

What is the role of cones in Human vision?

Human vision refers to the ability of humans to see and visualize objects in the environment in terms in texture, color, pattern, etc.

The cells of the human eye responsible for vision are the rods and cones.

The cones are responsible for color-vision while rods are responsible for black and white vision.

The three types of cones detect blue, green, and red colors corresponding to wavelengths given below:

Blue: 450–495 nmGreen: 495–570 nmRed: 620–750 nm

Therefore, the cones in the eye detect blue, green and red colors.

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A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball is dropped from rest and falls along the principal axis of the mirror. How much time elapses before the ball and its image are at the same location?

Answers

The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.

Image distance

The position of the image formed is determined using the followimg mirror formula;

[tex]\frac{1}{f} = \frac{1}{v} + \frac{1}{u}[/tex]

where;

f is the focal length of the mirrorv is the image distanceu is the object distance

f = R/2

f = 1.5/2

f = 0.75 m

When the ball and its image is in the same position, u = v

The position of the ball is calculated as;

[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m[/tex]

Time of motion of the ball

The time taken for the ball to travel the caluclated distance is determined as;

h = ut + ¹/₂gt²

1.5 = 0  + ¹/₂(9.8)t²

1.5 = 4.9t²

t² = 1.5/4.9

t² = 0.306

t = 0.55 s

Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.

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which of the following has the smallest radius? A, Mg B, Na+ C, Na D, Mg+ ​

Answers

Answer:

Na+

Explanation:

it is least pull by the nuclear charge

Answer:

Na+

Explanation:

It is posetively charged and in the first column

How would you correctly prepare 125 mL of a 0.30M solution of copper(II) sulfate (CuSO4) from a 2.00M solution of CuSO4?

Answers

Answer:

see below

Explanation:

.3 M/L ( .125 L) = .0375 mole required

.0375 mole / 2 mole / l = .01875 l required

take 18.75 ml of the 2.0 solution then dilute it to 125 ml

2.0 L of Carbon dioxide is heated from -25.0 °C to Standard Temperature.
What is the final volume of the gas?

Answers

The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.

How to calculate volume?

The volume of a given gas can be calculated using the Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volumeV2 = final volumeT1 = initial temperatureT2 = final temperature

V1 = 2LV2 = ?T1 = -25°C + 273 = 248KT2 = 273K

2/248 = V2/273

273 × 2 = 248V2

546 = 248V2

V2 = 546/248

V2 = 2.2L

Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L

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What is the pH when the [H+] is 1 x 10^-3 M

A. 2
B. 3
C. -3
D. 4

Answers

Answer:

3

Explanation:

PH = -Log [H+]

PH = -Log [1 × 10^-3]

PH = -Log [10^-3]

Log (10) = 1

PH = -(-3) Log (10)

PH = 3 × 1

PH = 3

If I react 6 units of AB with 10 units of CD in the equation below, what is the limiting reactant? 3AB + 4CD --> 2AD + 6CB

Answers

If 6 units of AB were reacted with 10 units of CD in the described equation, the limiting reactant would AB

Limiting reactants

They are reactants that determine how far a reaction can go in terms of yield.

From the equation: 3AB + 4CD --> 2AD + 6CB

The mole ratio of AB to CD is 3:4

Thus, 6 units of AB will require 8 units of CD.

But 10 units of CD were reacted with only 6 units of AB. This means that CD is in excess by 2 units while AB will limit the yield of the reaction.

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An empty beaker has a measured mass of 27.234 g. When some salt is added to the beaker, the combined mass is 35.9564 g. Calculate the mass of the salt only (show work), reporting your answer to the correct number of significant figures.

Answers

The mass of the salt only if 35.9564g is the combined mass of the beaker and the salt is 8.7224g

How to calculate mass?

According to this question, an empty beaker has a measured mass of 27.234g. However, when some salt is added to the beaker, the combined mass is 35.9564g.

This means that to calculate the mass of the salt in the beaker, we have to subtract the mass of the empty beaker from the combined mass as follows:

mass of salt only = 35.9564g - 27.234g

mass of salt only = 8.7224g

Therefore, the mass of the salt only if 35.9564g is the combined mass of the beaker and the salt is 8.7224g.

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11. As early as 1938. the use of NaOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the following (unbalanced) reaction: NaOH +CO2-
Na2CO3 + H2O.
a. If the average human body discharges 925,0 g CO, per day, how many moles of NaOH are
needed each day for each person in the spacecraft?
b. How many moles of each product are formed?

Answers

For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as

a) Moles of NaOH =44.05

b)   Moles of Na2CO3=21.0

Moles of H2O= 21.0

What is the moles of NaOH and what moles of each product are formed?

Generally, the equation for the Chemical reaction  is mathematically given as

2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)

Therefore

Moles of CO2= 925/44

Moles of CO2=21.0

Hence

Moles of NaOH = 2 x Moles of CO2

Moles of NaOH = 2x925/44

Moles of NaOH =44.05

In conclusion

Moles of Na2CO3 925/44

Moles of Na2CO3=21.0

And

Moles of H2O= 925/44

Moles of H2O= 21.0

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The measurement 0.41006 gram, rounded to four significant figures, is expressed as... 1) 0.4100 g
2) 0.410 g
3) 0.41 g
4) 0.4101 g​

Answers

Answer:

option B = 0.410 g

Explanation:

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Noah is conducting a science experiment and needs to analyze iron and sulfur. Which of the following will he compare to determine the amounts of each substance?


movement of the atoms in each substance
movement of the atoms in each substance

molecular mass of each substance
molecular mass of each substance

mass of each substance
mass of each substance

vibration of the atoms in each substance
vibration of the atoms in each substance

Answers

Answer:

molecular mass of each substance

molecular mass of each substance

Explanation:

HelpHelpHelpHelpHelpHelp

Answers

Answer: b
A closed system is when energy cannot pass through or pass out of something. With the lid being closed around the jar, the energy cannot be passed through. While with the other answers like d, the shell around a hermit crab is still opened a little, so energy can pass through it, not making it a closed system

When you exercise strenuously, your body produces excess heat. Describe what your body does to help prevent your temperature from rising excessively and
explain why your body's response effective.

Answers

Answer:

Your body can cool itself by sweating. When sweat evaporates, it lowers your temperature

Explanation:

A 0.563 M solution of the salt NaA has a pH of 11.56. Calculate the Ka value for the acid HA. Record your answer in scientific notation to 3 sig figs.

Answers

Answer:

[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]

Explanation:

Write the base reaction of NaA with water:

[tex]\displaystyle \text{A}^-_\text{(aq)}+\text{H$_2$O}_\text{($\ell$)}\rightleftharpoons \text{HA}_\text{(aq)} + \text{OH}^-_\text{(aq)}[/tex]

Hence, the equilibrium constant expression for the reaction is:
[tex]\displaystyle K_b = \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]}[/tex]

Thus, to find Ka, we can find Kb and use the fact that Ka × Kb = Kw.

From the reaction and initial concentration of NaA, create an ICE chart:

[tex]\begin{tabular}{llllll} & A^- &\text{H$_2$O} & \rightleftharpoons & HA & OH^- \\I & 0.563 M & \---- & & 0 M & 0 M \\C & -\text{ $ x$} & \---- & & +\text{ $x$ M} & + \text{$x$ M} \\E & \text{(0.563 - $x$) M} & \---- & & \text{$x$ M} & \text{$x$ M} \end{tabular}[/tex]

Find [OH⁻] from the given pH:
[tex]\displaystyle \begin{aligned} \text{pH} +\text{pOH} & = 14.00 \\ \\ \text{pOH} & = 14.00 - \text{pH} \\ \\ & = 14.00 - (11.56) \\ \\ & = 2.44 \\ \\ -\log[\text{OH}^-] & = 2.44 \\ \\ [\text{OH}^-] &= 10^{-2.44} \\ \\ & =0.00363 \text{ M}= 3.63\times 10^{-3} \text{ M} = x\text{ M}\end{aligned}[/tex]

Solve for all species concentrations at equilibrium from the found x value:

[tex]\displaystyle [\text{HA}] = [\text{OH}^-] = 3.63\times 10^{-3} \text{ M}[/tex]

And:

[tex]\displaystyle \begin{aligned} \ [\text{A}^-] & = 0.563 - 3.63\times 10^{-3} \text{ M}\\ \\ & = 0.559\text{ M}\end{aligned}[/tex]

Find Kb:

[tex]\displaystyle \begin{aligned} \displaystyle K_b &= \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]} \\ \\ & = \frac{(3.63\times 10^{-3})(3.63\times 10^{-3})}{(0.559)}\\ \\ & = 2.36\times 10^{-5}\end{aligned}[/tex]

Find Ka:

[tex]\displaystyle \begin{aligned} K_a\cdot K_b & = K_w \\ \\ K_a & = \frac{K_w}{K_b} \\ \\ & = \frac{(1.00 \times 10^{-14})}{(2.36\times 10^{-5})} \\ \\ &= 4.24\times 10^{-10} \end{aligned}[/tex]

In conclusion:
[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]

PLEASE john travoltage is safe from getting a static electricity zap right now. there are two things that could change to increase his chances from getting zapped tell me what both if those things are

Answers

If he rubs his foot on the carpet or touches the metal doorknob it would increase his chances of being zapped.

Rubbing his feet would be friction.

Touching the doorknob would be potential energy.

Side note: I love the format for this question, was not expecting to see John Travolatge on here today >O< !!!  

A small rock with a mass of 13 g is dropped into a graduated cylinder containing 12 mL of water.
The water rises to 35 mL. What is the density of the rock?

Answers

The density of the rock with a mass of 13 g and is dropped into a graduated cylinder containing 12 mL of water is 0.57g/mL.

How to calculate density?

The density of a substance can be calculated using the following formula:

Density = mass ÷ volume

According to this question, a small rock with a mass of 13 g is dropped into a graduated cylinder containing 12 mL of water. The water rises to 35 mL.

This means that the volume of the rock is 35 - 12 = 23mL

Density of the rock = 13g ÷ 23mL

Density = 0.57g/mL

Therefore, the density of the rock with a mass of 13 g and is dropped into a graduated cylinder containing 12 mL of water is 0.57g/mL.

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How much work, , must be done on a system to decrease its volume from 19.0 L to 11.0 L by exerting a constant pressure of 6.0 atm?

w = ________ kJ

Answers

Answer:

Explanation:

w = 16.0KJ

your welcome for the answer let me know ifyou need anymore help.

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HCl(?) + H2O(?) → H3O+(?) + Cl-(?)

What is the phase label on Cl-?

Answers

Answer:

H30,+ion is known as Hydroniom Ion

Explanation:

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brainless this answer is correct

Question 6 (2 points) If 100.0 mL ethyl alcohol weighs 78.5 g, determine the volume in litres occupied by 1.59 kg of ethyl alcohol. Answer Instructions:​

Answers

The volume in litres occupied by 1.59 Kg of ethyl alcohol given the data from the question is 2.03 L

How to determine the mole of 78.5 g of ethyl alcohol Mass of ethyl alcohol = 78.5 gMolar mass of ethyl alcohol = 46.07 g/molMole of ethyl alcohol =?

Mole = mass / molar mass

Mole of ethyl alcohol = 78.5 / 46.07

Mole of ethyl alcohol = 1.7 mole

How to determine the mole of 1.59 Kg of ethyl alcohol Mass of ethyl alcohol = 1.59 Kg = 1.59 × 1000 = 1590 gMolar mass of ethyl alcohol = 46.07 g/molMole of ethyl alcohol =?

Mole = mass / molar mass

Mole of ethyl alcohol = 1590 / 46.07

Mole of ethyl alcohol = 34.5 moles

How to determine the new volume Initial volume (V₁) = 100 mL = 100 / 1000 = 0.1 LInitial mole (n₁) = 1.7New mole (n₂) = 34.5 moles New Volume (V₂) =.?

V₁ / n₁ = V₂ / n₂

0.1 / 1.7 = V₂ / 34.5

Cross multiply

1.7 × V₂ = 0.1 × 34.5

Divide both side by 1.7

V₂ = (0.1 × 34.5) / 1.7

V₂ = 2.03 L

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what is the pH of a solution that has a [H+]=1.75x10^-11

Answers

[tex]pH = - \log[\text{H}^{+}] = -\log \left(1.75 \times 10^{-11} \right) = 10.757[/tex]

Why are polar and non polar liquids immiscible?

Answers

Answer:

When both liquid molecules are polar then they can attract one another - which leads to mixing (miscibility).

When the molecular liquid is nonpolar, then the water molecules attract only one another while ignoring the nonpolar liquid. the result is that the two liquids are immiscible.

Explanation:

I hope it helps mark me brainliest^^

Answer:

They lack lack inter-molecular forces to disolve in the polar liquids.

Explanation:

Miscibility is the property of two substances to mix in all proportions (that is, to fully dissolve in each other at any concentration). Polar molecules like water will mix well with some other polar molecules but things like oil which are non polar do not mix well with polar molecules. This is because the oil and water lack inter-molecular forces to keep them mixed.

A firework is fired from the ground straight up on a planet with an acceleration due to gravity of 6.82 m/s/s. The firework will not explode until the moment where it would have started to move back down again. The initial speed of the firework is 69.5 m/s. Use this information to find the height at which the firework explodes and the time it will be traveling upward.

Answers

Answer:

h = 384.4 m

t = 8.5 s

Explanation:

The firework will explode at the highest point. Because it would start to move downward at the highest point. Using 3rd equation of motion:

2ah = Vf² - Vi²

where,

a = acceleration due to gravity at that planet = -10.56 m/s²

h = maximum height = ?

Vf = Final velocity = 0 m/s (since, firework stops at highest point)

Vi = Initial Velocity = 90.1 m/s

Therefore,

2(-10.56 m/s²)(h) = (0 m/s)² - (90.1 m/s)²

h = 384.4 m

Now, we use 1st equation of motion:

Vf = Vi + at

0 m/s = 90.1 m/s + (-10.56 m/s²)(t)

t = 8.5 ss

What are the extensive and intensive properties described in this experiment? Which properties would change and which would stay the same if you ran the experiment sing 7.5-ounce cans instead of 12- ounce cans?

Answers

No because the amount of the water stays the same

Intensive properties do not change as the size of an object changes but Extensive properties change as the size of an object changes; here the properties can not change because the amount of the water stays the same

What are the difference between Extensive property and Intensive Property ?

The physical properties of matter can be divided into  intensive and extensive properties and the terms are introduced in 1917 by Richard C Tolman.

Intensive properties are independent of the presence of number of substance and they are bulk properties, here the Characteristic doesn’t change.

The size of intensive properties cannot change, examples are Density, temperature, pressure etc. It can not depend on the amount of matter and also intensive properties are fixed, countable.

Extensive properties are dependent on the presence of  number of substance, easily identified, Size of Extensive properties changes and  It can be computed.

extensive properties depend on the amount of matter, often changes and are not countable; For example Volume, size, mass, length, weight

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1.) Explain the difference between weather and climate.
2.) Why is latitude a factor in the uneven heating of Earth's surface?
3.) A particular air mass contains extremely cold, dry air. Based on this information, how would this air mass most likely be classified?
4.) What's the intertropical convergence zone (ITCZ)?
5.) How do polar jet streams differ from tropical jet streams?

:::::::::::::::::::::::::::::::::::::::::::::::: Answers::::::::::::::::::::::::::::::::::::::::::::::
1.) Weather refers to temporary atmospheric conditions that are occurring at a given point and time. Climate refers to the average weather conditions that occur in an area over an extended period.
2.) Regions nearer the equator receive sunlight more directly than regions located farther from the equator. As a result, regions near the equator experience warm temperatures all year. Regions located farther from the equator experience more temperature fluctuations.
3.) An air mass containing extremely cold, dry air would likely be classified as a continental arctic (cA) air mass.
4.) The ITCZ is the point at which trade winds from the Northern Hemisphere converge with trade winds from the Southern Hemisphere. This area typically experiences calm weather.
5.) Polar jet streams occur at higher latitudes. They separate the polar easterlies from the prevailing westerlies. Tropical jet streams occur at lower latitudes. They separate the trade winds from the prevailing westerlies.

Answers

why did u gave answer before

Explanation:

1) Weather refers to temporary atmospheric conditions that are occurring at a given point and time. Climate refers to the average weather conditions that occur in an area over an extended period.

2) Regions nearer the equator receives sunlight more directly than regions located farther from the equator. As a result, regions near the equator experience warm temperatures all year. Regions located farther from the equator experience more temperature fluctuations.

3) An air mass containing extremely cold, dry air would likely be classified as a continental arctic air mass.

4) The ITCZ is the point at which trade winds from the Northern Hemisphere converge with trade winds from the Southern Hemisphere. This area typically experiences calm weather.

5) Polar jet streams occur at higher latitudes. They separate the polar easterlies from the prevailing westerlies. Tropical jet streams occur at lower latitudes. They separate the trade winds from the prevailing westerlies.

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