hello and thank you for helping me and this is a trigonometry question bit for the question has give exact value and it won't accept decimals as an answer and thank you for your time.
Answers
1) In this question let's calculate the sin(θ) and cos(θ)
Given that
[tex]\begin{gathered} \text{If }\sin (\theta)=\frac{5\pi}{4} \\ \sin (\theta)\text{ }\Rightarrow\sin (\frac{5\pi}{4})\text{ }=-\frac{\sqrt[]{2}}{2} \\ \cos (\frac{5\pi}{4})=-\frac{\sqrt[]{2}}{2} \end{gathered}[/tex]2) In this question, we're calculating the value of the sine and the cosine in radians.
We must remember that 5π/4 ⇒ to 225º, and that it's in the Quadrant III
If we subtract
225 -180 =45 So the sine of 5π/4 is -√2/2 and the cosine (5π/4 ) = -√2/2
2.3) The sign of the Quadrant
Since 225º is in Quadrant III both results are negative ones.
Related Questions
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100 POINTS!!!!!
Answers
Answer:
True.
area of green square + area of purple square = area of red square
[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]
For the simple harmonic motion equation d=5sin (pi/4^+), what is the period?
Answers
the period is 8
Explanation
the function sin has the form
[tex]\begin{gathered} y=Asin(B(x+c))+D \\ where \\ Period=\frac{2\pi}{B} \end{gathered}[/tex]so
Step 1
a) identify B in the given function
given
[tex]d=5\text{ sin\lparen}\frac{\pi}{4}t)[/tex]hence
[tex]\begin{gathered} \frac{\pi}{4}t\Rightarrow B(t+c) \\ so \\ c=0 \\ \frac{\pi}{4}t=Bt \\ therefore \\ B=\frac{\pi}{4} \end{gathered}[/tex]b) now, replace in the formula to find teh period
[tex]\begin{gathered} Per\imaginaryI od=\frac{2\pi}{B} \\ Period=\frac{2\pi}{\frac{\pi}{4}}=\frac{2\pi *4}{1*\pi}=\frac{8\pi}{\pi}=8 \\ so \\ Period=8 \end{gathered}[/tex]therefore, the period is 8
I hope this helps you
Answer:
8
Step-by-step explanation:
A
P
E
X
Which of the following is a perfect cube?118481
Answers
From the options given we will have that a perfect cube is:
[tex]1^3=1\ast1\ast1=1[/tex]So, 1 is the perfect cube.
Use the Pythagorean Theorem to find the missing side length. *A. 12B. 144C. 10D. 24
Answers
We use the Pythagorean theorem formula to find the missing side length.
[tex]\begin{gathered} a^2+b^2=c^2 \\ \text{ Where} \\ a\text{ and }b\text{ are the sides} \\ c\text{ is the hypotenuse} \end{gathered}[/tex]Then, we have:
[tex]\begin{gathered} a=x \\ b=16 \\ c=20 \end{gathered}[/tex][tex]\begin{gathered} a^{2}+b^{2}=c^{2} \\ x^2+16^2=20^2 \\ x^2+256=400 \\ \text{ Subtract 256 from both sides} \\ x^2+256-256=400-256 \\ x^2=144 \\ $$\text{ Apply square root to both sides of the equation}$$ \\ \sqrt{x^2}=\sqrt{144} \\ x=12 \end{gathered}[/tex]AnswerThe length of the missing side is 12.
A cake is cut into 12 equal slices. After 3 days Jake has eaten 5 slices. What is his weekly rate of eating the cake?
5
36
35
36
cakes/week
cakes/week
1 cakes/week
35
01 cakes/week
Answers
The cake is divided into 12 equal slices. Jake had eaten 5 slices after 3 days. The weekly cake consumption rate is 11.6
What is algebraic expression?An algebraic expression is one that is composed of integer constants, variables, and algebraic operations. 3x2 2xy + c, for example, is an algebraic expression. Algebraic expressions have at least one variable and one operation (addition, subtraction, multiplication, division). 2(x + 8y) is an algebraic expression, for example. An algebraic expression is one that contains constants, variables, and algebraic operations. 3x2 2xy + d, for example, is an algebraic expression. Thus, an algebraic expression is composed of three types of fundamental elements: Coefficient (i.e. numbers) (i.e. numbers)Therefore,
The weekly cake consumption rate is 11.6
we have 7 days.
7days-3days =4
in 3 days he has eaten 5 slices
again 4-3 days=1
so in 6 days, he has eaten 10 slices
we have 1 day left.so if he eats 5 slices in 3 days, how many does he eat slices in 1 day?
5/3=1.6
10+1.6= 11.6
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Using this formula and other formulas, find Q1,Q2, Q3 the midquartile, and the interquartile range for the data set.51, 62, 73, 92, 97, 100, 104
Answers
Given:
The given set of data is 51, 62, 73, 92, 97, 100, 104.
The objective is to find Q1,Q2, Q3 the midquartile, and the interquartile range.
Explanation:
The given set of data is already arranged in increasing oder.
To find Q2:
The quartile Q2 represents the middle term of the set of data arranged in increasing order.
The number of terms in the set of data is N = 7.
Then, the middle term of the set of data is 92, which is Q2.
To find Q1:
The quartile 1 represents the middle term of the left side of the Q2.
The left side of Q2 contains 51, 62, 73.
Thus, the middle term of the left side of Q2 is 62, which is Q1.
To find Q3:
The quartile 3 represents the middle temr of the right side of the Q2.
The right side of Q2 contains 97, 100, 104.
Thus, the middle term of the right side of Q2 is 100, which is Q3.
To find midquartile:
The midquartile is termed as the average of highest and lowest value of the set of data.
The highest value in the given set of data is 104 and the lowest value in the given set of data is 51.
Then, the midquartile can be calculated as,
[tex]\begin{gathered} \text{Midquartile}=\frac{104+51}{2} \\ =77.5 \end{gathered}[/tex]To find interquartile:
The
A leaking pond loses 16 gallons of water in 47 hours. How many gallons of water will it lose in 33 hours?
Answers
A leaking pond loses 16 gallons of water in 47 hours.
How many gallons of water will it lose in 33 hours?
To solve this question we can use a rule of three:
16 gallons is to 47 hours as x gallons is to 33 hours:
[tex]\frac{16}{47}=\frac{x}{33}\Longrightarrow x=\frac{33\cdot16}{47}=\frac{528}{47}=\text{ 11.23}[/tex]Answer:
11.23 gallons
Suppose a person is standing on the top of a building and that she has an instrument that allows her tomeasure angles of depression. There are two points that are 100 feet apart and lie on a straight line that isperpendicular to the base of the building. Now suppose that she measures the angle of depression from thetop of the building to the closest point to be 34.5 and the angle of depression from the top of thebuilding to the furthest point to be 27.8°. Determine the height of the building. (Round your answer to thenearest tenth of a foot.)
Answers
see the figure below to better understand the problem
In the right triangle ABC
tan(34.5)=h/x -----> by TOA
h=x*tan(34.5) -----> equation 1
In the right triangle ABD
tan(27.8)=h/(100+x) -----> by TOA
h=(100+x)*tan(27.8) -----> equation 2
Equate equation 1 and equation 2
x*tan(34.5)=(100+x)*tan(27.8)
solve for x
x*tan(34.5)=100*tan(27.8)+x*tan(27.8)
x*[tan(34.5)-tan(27.8)]=100*tan(27.8)
x=329.4 ft
Find out the value of h
h=x*tan(34.5)
h=329.4*tan(34.5)
h=226.4 ft
therefore
the answer is
the height of the building is 226.4 ftSuppose it is believed that the probability a patient will recover from a disease following medication is 0.8. In a group of twenty such patients, the number who recover would have mean and variance respectively given by (to one decimal place):
Answers
Based on the number of patients and the probability that a patient will recover from the disease, the mean 16 patients would be and the variance would be 1.79
How to find out mean and the variance?The mean can be found by the formula:
= Number of patients in group x Probability that patient will recover
= 20 x 0.8
= 16 patients
The Variance is:
= Number of people x probability of recovery x (1 - probability of recover)
= 20 x 0.8 x (1 - 0.8)
= 3.2
So the standard deviation is:
= √3.2
= 1.79
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Help me due is tomorrow
Answers
Step-by-step explanation:
5.3g+9=2.3g+15
5.3g-2.3g=15-9
3g=6
3g/3=6/3
g=2
B,5.3(2)+9=2.3(2)+15
10.6+9=4.6+15
19.6=19.6
g = 2
Step-by-step explanation:5.3g + 9 = 2.3g + 15
Subtract 9 from both sides.
5.3g + 9 - 9 = 2.3g + 15 - 9
5.3g = 2.3g + 6
Subtract 2.3g from both sides
5.3g - 2.3g = 2.3g - 2.3g + 6
3g = 6
Divide both sides by 3
g = 2
To check if the value of g is correct, substitute the value of g in the equation above and remember that the both sides should be equal because of the equal sign (=) in the equation.
5.3g + 9 = 2.3g + 15
5.3(2) + 9 = 2.3(2) + 15
10.6 + 9 = 4.6 + 15
19.6 = 19.6
See photo for problem
Answers
a. the amount of liquid in the tank: 5580 liters
b. The amount of liquid should be added to fill the tank 100% capacity : 450 liters
We have been given a right circular conical tank.
h = 4 m and r = 1.20 m
We know that the formula for the volume of cone is,
V = πr²h/3
The volume of the tank would be,
V = (π × r² × h)/3
V = (π × 1.20² × 4)/3
V = 18.09/3
V = 6.03 m³
Let h1 be the height of liquid level in the tank and V1 be the volume of the liquid in the tank.
h1 = 3.70 m
V1 = (π × r² × h1)/3
V1 = (π × 1.20² × 3.70)/3
V1 = 16.74 / 3
V1 = 5.58 m³
V1 = 5580 liters
The amount of liquid need to added to fill the tank 100% of capacity.
V2 = V - V1
V2 = 6.03 m³ - 5.58 m³
V2 = 0.45 m³
V2 = 450 liters
Therefore, a. the amount of liquid in the tank: 5580 liters
b. The amount of liquid should be added to fill the tank 100% capacity : 450 liters
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O GRAPHS AND FUNCTIONSGraphically solving a system of linear equations
Answers
(-3,4)
Explanationhere we have a system of 2 linear functions, To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect.
so
Step 1
graph the function (1)
a)
[tex]y=-\frac{1}{3}x+3[/tex]to graph the line we need 2 poins, so
i) P1, when x=0
[tex]\begin{gathered} y=-\frac{1}{3}x+3 \\ y=-\frac{1}{3}(0)+3=3 \\ so \\ P1=(0,3) \end{gathered}[/tex]ii) P2; when x= 3
[tex]\begin{gathered} y=-\frac{1}{3}(3)+3=-1+3=2 \\ so \\ P2;\text{ \lparen3,2\rparen} \end{gathered}[/tex]iii) now, draw a line that passes trought P1 and P2
Step 2
now, graph line 2 ( function 2)
i) P3, when x= 0
[tex]\begin{gathered} 3x+y=-5 \\ replace\text{ and solve for y} \\ 3(0)+y=-5 \\ y=5 \\ so,P3=(0,-5) \end{gathered}[/tex]ii) P5, when x= 2
[tex]\begin{gathered} 3x+y=-5 \\ replace\text{ and solve for y} \\ 3(2)+y=-5 \\ 6+y=-5 \\ subtract\text{ 6 in both sides} \\ y=-6-5=-11 \\ y=-11 \\ so,\text{ P4=\lparen2,-11\rparen} \end{gathered}[/tex]iii) now, draw a line that passes trought P3 and P4
Step 3
finally, the solution is the orderede pair where the lines intersect each other
therefore, the solution is
(-3,4)
I hope this helps you
Q1 of the numbers 5, 8, 10, 11, 12, 15, 19, 20, 20, 24, 25
Answers
Answer
Q1 = 10
Explanation
To ontain the Q1, we need to first make sure the numbers are arranged in ascending or descending order.
5, 8, 10, 11, 12, 15, 19, 20, 20, 24, 25
Q1 is the number that occurs at the (N + 1)/4 position for the distribution.
N = Number of variables = 11
Q1 = (N + 1)/4
Q1 = (11 + 1)/4 = (12/4) = 3rd variable.
5, 8, 10, 11, 12, 15, 19, 20, 20, 24, 25
The 3rd variable = 10
Hope this Helps!!!
Answer:
10
Step-by-step explanation:
i'm drinking boba and am to lazy to explain.
A real estate agent has 18 properties that she shows. She feels that there is a 50% chance of selling any one property during a week. The chance of selling any one property is independent of selling another property. Compute the probability of selling more than 4 properties in one week. Round your answer to four decimal places.
Answers
The probability of selling more than 4 properties in one week is 0.985.
What is probability?A probability formula can be used to calculate the likelihood of an occurrence by simply dividing the favorable number of possibilities by the entire number of possible outcomes.
The binomial distribution is a discrete probability distribution in probability theory and statistics that gives only two possible outcomes in an experiment: success or failure.
In this case, the real estate agent has 18 properties. Therefore, n = 18. p = 50% = 0.5.
The probability will be:
= P(X > 4)
= 1-0.0154 by using Excel command
= 0.985
The probability is 0.985.
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The cost of 15 toys is $225. Identify the equation that represents this situation.
Answers
Question:
Solution:
Let us denote by c the cost of each toy. Then, according to the problem, the cost of 15 toys would be:
[tex]15c\text{ = 225}[/tex]So, we can conclude that the correct answer is:
[tex]15c\text{ = 225}[/tex]10 ftA4 ftThe following are the dimension of four rectangles. Which rectangle has the same area as the triangle above?a 1.6 ft by 25 ftC. 3.5 ft by 4 ftb. 5 ft by 16 ftd. 0.4 ft by 50 ft
Answers
step 1: Find the area of the triangle
The area of the triangle given is:
[tex]\begin{gathered} \text{Area = }\frac{1}{2}\times base\times height \\ =\frac{1}{2}\times4\times10 \\ =20ft^2 \end{gathered}[/tex]step 2: Find the dimension of rectangles that will give the same area as the triangle
The area of a rectangle is given by:
[tex]\text{Area}=\text{ length x width}[/tex][tex]\begin{gathered} \text{ option a: }1.6ftx25ft=40ft^2 \\ \text{option b: 5 ft x 16 ft =}80ft^2 \\ \text{option c: }3.5ftx4ft=14ft^2 \\ \text{option d: }0.4\text{ ft x 50 ft=}20ft^2 \end{gathered}[/tex]Therefore, the dimension of the rectangle with the same area as the triangle is
[tex]0.4\text{ ft}\times50\text{ ft}[/tex]OptionD is correct
What is the driving distance from the police station to an animal shelter
Answers
The coordinates of the Police station is (0, -4)
The coordinates of Animal shelter is (6,- 2)
The distance between the Police station and the Animal shelter is given by the formoula;
[tex]\begin{gathered} \text{Distance}=\sqrt[]{(x_2-x_1)^2+(y}_2_{}-y_1)^2_{} \\ \text{Distance}=\sqrt[]{(6-0)^2+(-2--4)^2}=\text{ }\sqrt[]{6^2+2^2} \end{gathered}[/tex][tex]\text{Distance}=\sqrt[]{36+4}\text{ = }\sqrt[]{40}=\text{ 6.325}\approx6.33[/tex]An extrasolar planet is observed at a distance of
4.2 × 10⁹ kilometers away. A group of scientists
has designed a spaceship that can travel at the
speed of 7 × 108 kilometers per year. How many
years will the spaceship take to reach the extrasolar
planet? Enter the answer in the box.
Answers
After conducting some mathematical operations, we can conclude that it would take the spaceship 5555556 years to reach the extrasolar planet.
What do we mean by mathematical operations?A mathematical function known as an operation converts zero or more input values into a precisely defined output value.The quantity of operands affects the operation's arity.The four mathematical operations are functions that change one number into another by taking input values, or numbers, as inputs.They are addition, subtraction, multiplication, and division.So, years were taken by the ship to reach the extrasolar planet:
Distance of the planet: 4.2 × 10⁹ kmSpeed of the spaceship: 7 × 108 per/yearNow, calculate the number of years as follows:
= (4.2 × 10⁹)/(7 × 108)= (4.2 × 1000000000)/756= 4,20,00,00,000/756= 5555555.56Rounding off: 5555556 years
Therefore, after conducting some mathematical operations, we can conclude that it would take the spaceship 5555556 years to reach the extrasolar planet.
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Fine all the missing side lengths and angle measured of each triangle.
Answers
Answer:
[tex]\begin{gathered} AT=8\sqrt[]{3} \\ AC=8 \\ mStep-by-step explanation:To find the missing lengths of the triangle, use trigonometric ratios for right triangles, which are represented by the following equations:
[tex]\begin{gathered} \sin (\text{angle)=}\frac{\text{ opposite}}{\text{ hypotenuse}}_{} \\ \cos (\text{angle)}=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \tan (\text{angle)}=\frac{\text{ opposite}}{\text{ adjacent}} \end{gathered}[/tex]Then, find the opposite and adjacent side given the 60 degrees angle:
[tex]\begin{gathered} \sin (60)=\frac{AT}{16} \\ AT=16\cdot\sin (60) \\ AT=8\sqrt[]{3} \\ \\ \cos (60)=\frac{AC}{16} \\ AC=16\cdot\cos (60) \\ AC=8 \end{gathered}[/tex]Now, since the intern angles of a triangle must add up to 180 degrees, given two of the angles find the missing angle:
[tex]\begin{gathered} mA painting is worth $9000 in 2007. The value of the painting increases by 12% eachyear.Estimate the length of time it takes for the value of the painting to double.
Answers
Step 1
State the formula for exponential growth
[tex]P(0)=P(1+r)^t[/tex]where;
[tex]\begin{gathered} P=\text{ worth in 2007=\$9000} \\ r=rate=\frac{12}{100}=0.12 \\ t=\text{ time for growth in years} \\ P(0)=\text{ Required value of growth in t years} \end{gathered}[/tex]Step 2
Find double the value of the painting.
[tex]2P=9000\times2=\text{ \$18000}[/tex]Step 3
Estimate the length of time it takes for the value of the paint to double
[tex]\begin{gathered} 18000=9000(1+0.12)^t \\ \frac{18000}{9000}==\frac{9000(1+0.12)^t}{9000} \\ 2=(1+0.12)^t \end{gathered}[/tex][tex]\begin{gathered} \ln 2=\ln (1.12)^t \\ \ln 2=t\ln (1.12) \\ \frac{t(\ln1.12)}{\ln1.12}=\frac{\ln2}{\ln1.12} \\ t=6.116255374\text{ years} \\ t\approx6.1163years\text{ approxi}mately\text{ to 4 decimal places} \end{gathered}[/tex]Hence, it will take approximately 6.1163 years for the value of the paint to double.
I need help in math can you please help me
Answers
We have the following:
[tex]\begin{gathered} \sin \theta=-\frac{8}{17} \\ \theta=\sin ^{-1}(-\frac{8}{17}) \\ \theta=-28.07 \end{gathered}[/tex]now, in Quadrant III (180° to 270°):
[tex]\theta=180+28.07=208.7[/tex]now, for cosine:
[tex]\cos 2\theta=\cos (2\cdot208.7)=0.538=\frac{539}{1000}[/tex]The answer is 539/1000
Find the distance between the pair of parallel lines with the given equations.y = -5xy = -5x + 26O A) 5 unitsO B) 14.14 unitsC) C) 5.10 unitsO D) 6 units
Answers
Solution:
Consider two lines with the following equations:
[tex]y_1=mx+c[/tex]and
[tex]y_2=mx+c_2[/tex]the distance d between these two parallel lines is given by the following equation:
First, we need to take one of the lines and convert it to standard form. For example, take the line:
y = -5x + 26
then, we obtain:
-5x-y+26=0
in this case, we get that
A = -5
B= -1
C = 26
Now we can substitute A, B, and C into our distance equation along with a point, (x1,y1) from the other line. We can pick any point on the line y2. Just plug in a number for x, and solve for y. I will use x = 2, to obtain:
y = -5(2) = -10
then
(x1,y1) = (2,-10)
Replacing these values into the distance equation, we obtain:
[tex]d\text{ = }\frac{|-5(2)+(-1)(-10)+26|}{\sqrt[]{(-5)^2+(-1)^2}}[/tex]that is:
[tex]d\text{ = }\frac{|-10+10+26|}{\sqrt[]{(-5)^2+(-1)^2}}=\frac{26}{\sqrt[]{26}}=5.09\approx5.10[/tex]so that, the correct answer is:
[tex]5.10\text{ units}[/tex]D is the midpoint of AC, BA ≅BC and ∠EDA ≅ ∠FDC. Prove ΔAED ≅ ΔCFD
Answers
We are asked to prove that triangles AED and CFD are congruent. To do that we will prove that we can use the ASA (Angle Side Angle) rule of congruency.
First, we are given that D is a midpoint of segment AC, therefore:
[tex]\bar{AD}=\bar{AC}[/tex]Also, we are given that:
[tex]\bar{BA}=\bar{BC}[/tex]This means that triangle ABC is an isosceles triangle and therefore, its base angles are equal. This means that:
[tex]\angle BAC=\angle BCA[/tex]And, since we are given that angles EDA and FDC are equal, then by ASA we can conclude that:
[tex]\Delta AED\cong\Delta CFD[/tex]If I am in San Juan, then
I am in Puerto Rico.
State whether the following
statement is inverse, converse,
contrapositive.
If I am not in San Juan,
then I am not in Puerto
Rico.
Answers
The statement "If I am not in San Juan, then I am not in Puerto Rico." is the inverse and contrapositive statement because it is inverse of "If I am in San Juan, then I am in Puerto Rico."
What is inverse?The inverse function of a function f in mathematics is a function that reverses the operation of f. If and only if f is bijective, then the inverse of f is true. A function that "undoes" another function is called an inverse. In other words, if f(x) produces y, then y entered into the inverse of f produces x. An invertible function is one that has an inverse, and the inverse is represented by the symbol f⁻¹.
What is contrapositive?When you reverse the hypothesis and the conclusion in a statement and reject both of them, you have a contrapositive statement. When the hypothesis and the conclusion are switched in this example and both are negated, the outcome is: If it is not a triangle, then it is not a polygon.
Here,
The statement is "If I am in San Juan, then I am in Puerto Rico."
So the contrapositive and inverse will be:
"If I am not in San Juan, then I am not in Puerto Rico."
Because it is the opposite of "If I am in San Juan, then I am in Puerto Rico," the statement "If I am not in San Juan, then I am not in Puerto Rico" is the inverse and contrapositive statement.
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Express the answer in simplest formIf A die is rolled one time find the probability of
Answers
Solution
If A die is rolled one time find the probability of getting an even number
The total number in a die rolled once = 6
number of even number = 3
Probability = number of required outcome / number of possible outcome
[tex]\begin{gathered} Pr(evene\text{ number\rparen = number of even / total number} \\ Pr(even)\text{ = 3/6} \\ =\frac{1}{2} \end{gathered}[/tex]Therefore the probability of getting an even number = 1/2
In gym class, a student can do 40 sit-ups in 60 seconds and 100 sit-ups in 150 seconds.
Graph the proportional relationship.
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 60
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 30
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 50
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 30
Question 6 (Essay Worth 4 points)
Answers
By using the linear equation y=3x we draw the graph for proportional relationship.
What is Graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
A proportional relationship graph between two variables is a relationship where the ratio between the two variables is always the same
the graph of any proportional relationship is characterized by a straight line with data points passing through the origin (0, 0).
By the definition of proportional relationship of graph, we can reduce relationship between the values on the x-coordinate and y-coordinate of the given graph
As they are proportional and represented by euation
y = 3x
Where, x represent the time and y represent the number of sit-ups.
Hence by using the linear equation y=3x we draw the graph for proportional relationship.
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Use the x and y intercepts to sketch a graph of each equation.
Answers
The given equation is expressed as
x + 4y = 8
4y = 8 - x
y = 2 - x/4
The first step is to input values for x into the equation and determine the corresponding y values. These values are then plotted on the graph.
For x = 0, y = 2 - 0/4 = 2
For x = 1, y = 2 - 1/4 = 1.75
For x = 2, y = 2 - 2/4 = 1.5
We would plot these points on the graph
I need help with this practice Having trouble solving it The subject is trigonometry
Answers
To solve the problem, we will make use of the identity:
[tex]\cos (\alpha-\beta)=\cos (\alpha)\cos (\beta)+\sin (\alpha)\sin (\beta)_{}[/tex]ANGLE α
The angle lies in the second quadrant. The only positive ratio is the sine.
If we have that:
[tex]\tan \alpha=-\frac{12}{5}[/tex]Displaying this on a triangle for ease of working, we have:
Therefore, the length of the hypotenuse will be:
[tex]\begin{gathered} x=\sqrt[]{12^2+5^2}=\sqrt[]{144+25}=\sqrt[]{169} \\ x=13 \end{gathered}[/tex]Therefore, we have that:
[tex]\begin{gathered} \sin \alpha=\frac{12}{13} \\ \cos \alpha=-\frac{5}{13} \end{gathered}[/tex]ANGLE β
This angle lies in the fourth quadrant. Only the cosine ratio is positive in this quadrant.
We are given in the question:
[tex]\cos \beta=\frac{3}{5}[/tex]Displaying this on a triangle for ease of working, we have:
Therefore, using the Pythagorean Triplets, we have that:
[tex]y=4[/tex]Therefore, we have that:
[tex]\sin \beta=-\frac{4}{5}[/tex]SOLVING THE IDENTITY
Applying the identity quoted earlier, we have:
[tex]\begin{gathered} \cos (\alpha-\beta)=\cos (\alpha)\cos (\beta)+\sin (\alpha)\sin (\beta)_{} \\ \cos (\alpha-\beta)=(-\frac{5}{13})(\frac{3}{5})+(\frac{12}{13})(-\frac{4}{5}) \\ \cos (\alpha-\beta)=-\frac{63}{65} \end{gathered}[/tex]What is the equation of the line that passes through the origin and is perpendicular to the line 4x+3y=6
Answers
The Equation of a Line
The slope-intercept form of a line can be written as:
y = mx + b
Where m is the slope of the graph of the line and b is the y-intercept.
In the specific case where the line passes through the origin (0,0), we can find the value of b by substituting x=0 and y=0:
0 = m(0) + b
Solving for b:
b = 0.
Thus, the equation of the line reduces to:
y = mx
We only need to find the value of the slope.
That is where we need the second data. Our line is perpendicular to the line of equation 4x + 3y = 6.
Solving for y:
[tex]y=-\frac{4}{3}x+2[/tex]The slope of the second line is -4/3.
We must recall that if two lines of slopes m1 and m2 are perpendicular, then:
[tex]m_1\cdot m_2=-1[/tex]Substituting the value of m1 and solving for m2:
[tex]\begin{gathered} -\frac{4}{3}\cdot m_2=-1 \\ m_2=\frac{3}{4} \end{gathered}[/tex]The slope of our line is 3/4 and the required equation is:
[tex]y=\frac{3}{4}x[/tex]From this last equation, we need to find the general form of the line.
Multiply both sides of the equation by 4:
4y = 3x
Subtract 3x on both sides:
4y - 3x = 0
Reorder:
-3x + 4y = 0
Suppose you have 40 shirts and 15 pairs of pants to choose from in your wardrobe. Using the fundamental counting principle, how many outfit combinations are possible?
Type the correct answer in the box. Use numerals instead of words.
Answers
By taking the product between the number of shirts and pants, we coclude that there are 600 different outfit combinations.
How many outfit combinations are possible?
The total number of outfit combinations is given by the product between the numbers of each type of clothes that you have.
you have 40 shirts.
Yo have 15 pairs of pants.
Then the number of different combinations is 40*15 = 600
Learn more about combinations:
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