H H H O H O N C C N C C H O H H O H H C H H H ALANINE GLYCINE

What is the difference between these two amino acids?

The charge on each particles which are 1 m apart and feeling a repulsive force of 1 N is 1.05×10¯⁵ C

Let the charge on each particles be q

The charge on each particle can be obtained by using the Coulomb's law equation as shown below:

F = Kq₁q₂ / r²

F = Kq² / r²

1 = (9×10⁹ × q²) / 1²

1 = 9×10⁹ × q²

Divide both side by 9×10⁹

q² = 1 / 9×10⁹

Take the square root of both side

q =  √(1 / 9×10⁹)

q = 1.05×10¯⁵ C

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Answer:

friction

Explanation:

Answer:

Since the second quadrant ends at 180 deg,

205 will be 25 deg into the third quadrant (-x and -y)

y = -.888 sin 25 = -.375

One can also write y = .888 sin 205 = -.375

Answer:

Step by step explanation:

What the equation given?

Maximum velocity occurs at the equilibrium position

So

Now

Now

As we know the formula

[tex]\\ \rm\rightarrowtail V_max=A\omega[/tex]

These expressions can be used

The maximum speed of the oscillating object will be given by [tex]V_{max}=Aw[/tex]

An oscillation is defined as the repitative periodic motion of any object about its mean or equilibrium position.

The given equation is as follows:

x(t)=Acost

Maximum velocity occurs at the equilibrium position x=0

x(0)=Acos0

x(0)=A

Hence the maximum velocity will be  [tex]V_{max}=Aw[/tex]

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Answer:

1.2 is the correct answer due to the graph

Explanation:

math teacher

Answer:

0.035

Explanation:

7÷1000

=0.007m

0.007/0.2

=0.035

Mechanical strain of an elastic substance is the ratio of its change in length to the original length. The strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.

Strain is a physical quantity used to express the change in dimension of an elastic material. It is the ratio of change in length to the original length. Stress is the force that causing the deformation.

According to Hook's law of elasticity, the strain is directly proportional to the strain. They show a linear relation. Let L be the original length of a string and its change in length be ΔL.

Thus, strain = ΔL / L

Given that, the change in length = 7 mm = 0.7 cm

original length of the string = 20 cm

strain = 0.7 cm/ 20 cm

         = 0.035

Therefore, the strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.

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#SPJ2

Explanation:

formula is ˠ=vf

f=1/T

1/7

f=0.14

wavelength=27Ⅹ0.14

=3.78m

OR

7Ⅹ27

=189m

Answer:

The answer should be choice B.

Answer:

number 3

Explanation:

3 represents runoff

Runoff is the water collected after rainfall that drains from the surface area of land. It will be tricky to choose 4 which is likely a smaller waterbody draining to a bigger waterbody

hope it helped

[tex]1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\[/tex]

[tex]4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J[/tex]

Hi there!

We can begin by summing the forces acting on the car.

Along the axis of the incline, the forces of friction and gravity are working. The force of friction points towards the top of the ramp, while the force of gravity works towards the bottom.

We can use trigonometry to determine the force due to gravity along the ramp.

[tex]F_g = Mg sin\theta[/tex]

The force due to friction is equal to:
[tex]F_f = \mu N[/tex]

The normal force is the vertical component of the force due to gravity, so:
[tex]F_f = \mu Mgcos\theta[/tex]

Now, the combination of these two forces produces a component of the centripetal force. Drawing a diagram, we see that the true centripetal force is the HYPOTENUSE, while these forces sum up to its horizontal component along the ramp.

Therefore:
[tex]F_c sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]

The centripetal force is equivalent to:
[tex]F_c = \frac{Mv^2}{r}[/tex]

m = mass (kg)

v = velocity (m/s)
r = radius (m)

Rewrite:
[tex]\frac{Mv^2}{r}sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]

Cancel out 'M'.

[tex]\frac{v^2}{r}sin\theta = gsin\theta - \mu gcos\theta[/tex]

Rearrange to solve for 'r'.

[tex]r = \frac{v^2sin\theta}{gsin\theta - \mu gcos\theta}[/tex]

Plug in values and solve.
[tex]r = \frac{(27.1^2)sin(29.1)}{(9.8)sin(29.1) - 0.4(9.8)cos(29.1)} = \boxed{266.365 m}[/tex]

Answer:

A dot B = C     is the vector equation for this expression

A · B = A B cos θ

3 * 4 cos θ = 1       the value 1 is their dot product

cos θ = 1 / 12 = .083       θ = 85.2 deg

[tex]\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A[/tex]

For residences, series circuits are impracticable. Parallel circuits are practical because each appliance is controlled by its own switch, which prevents the other appliances from being turned off. A) The appliances are all turned on. The conductor wire is carrying a considerable quantity of current (arrow).

Answer:

The static frictional force is the force between the magnetic forces statically and contains only two objects during this physical reaction. It results in electricity and a slight shock.

[tex]\\ \rm\rightarrowtail F=-kx[/tex]

[tex]\\ \rm\rightarrowtail F=-20(0.03)[/tex]

[tex]\\ \rm\rightarrowtail F=-0.6N[/tex]

The distance traveled by the arrow and horizontal velocity are directly proportional, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.

If the horizontal distance the projectile would travel before hitting the target is 70.67 m, the time of motion of the projectile is calculated as;

X = Vx(t)

t = X/Vx

t = X/Vcosθ

t = (70.67) / (45 x cos10)

t = 1.6 s

When the archery target is moved further away from the archer, the archer needs increase the initial velocity of the arrow assuming the angle of projection is constant.

Since the distance and horizontal velocity are directly proportional to each other, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.

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Answer:

Adam Was the first person

Explanation:

Answer:

God is

Explanation:

Adam was the first human, Yes but God is the one who man Adam in his image and likeness, that is God looks just like the human

because we are made in God's image

Muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.

The quadriceps, hamstrings, the calf muscles and the hip adductors are the muscles which get stronger by doing walking because impact is produced on these muscles while walking. Walking is a good exercise which have many health benefits.

So we can conclude that muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.

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Answer:

introversion is the correct answer

Explanation:

God bless! Have a great day!

Answer:

Answer:

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Given the data from the question, the total output of non-useful energy from the heat engine is 150 J

A heat engine is a device / equipment that can convert or transfer thermal energy into useful-work. Some examples of heat engines include

From the question given above, the following data were obtained:

Output (non-useful) = Input – Output (useful)

Output (non-useful) = 300 – 150

Output (non-useful) = 150 J

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Answer:

1/R = 1/R1 + 1/R2 + 1/R3

1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75

1/1.75 = .572

multiplying this by 100 gives us

R = 57.2 ohms

The smallest resistor (100 ohms) will draw the most current

(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)

Hi there!

We can use the following equation to solve for equivalent resistance:

[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}[/tex]

We can plug in the givens and solve.

[tex]\frac{1}{R_T} = \frac{1}{100} + \frac{1}{200} + \frac{1}{400} \\\\\frac{1}{R_T} = 0.175\\\\R_T = \frac{1}{0.175} = \boxed{57.143 \Omega}[/tex]

The resistor that would draw the most current is the 100 Ohm resistor because current chooses the path of LEAST RESISTANCE. This can also be proved mathematically with the following:

For resistors in parallel, the POTENTIAL DIFFERENCE (VOLTAGE) is the same.

Since I = V/R, a smaller 'R' means a larger 'I'. Thus, the smallest resistor would have the greatest current through it.

Answer:

I think D sorry if I'm wrong

The region with high electric potential  (80 V and 70 V) will have high electric field while the region with low electric potential (20 V) will have low electric field.

Electric field is the field that surrounds electrically charged particles and exerts force on all other charged particles in the field.

E = V/d

where;

Since electric field is directly proportional to electric potential, the region with high electric potential  (80 V and 70 V) will have high electric field while the region with low electric potential (20 V) will have low electric field.

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Answer:

M1 g L1 = 19 kg * 9.8 m/s^2 * 5 m = counter clockwise torque - Cassie at left end

M1 g L1 = M2 g L2        for torques to balance

L2 = M1 L1 / M2 = 19 * 5 / 31 = 3.06 M

Alex should sit at 3.1 m from the fulcrum (at 5 m from each end)

Voltage = 5 volts

[tex]\sf \dfrac{number \ of \ turns \ in \ primary \ coil}{voltage\ in \ primary \ coil} = \dfrac{number \ of \ turns \ in \ secondary\ coil}{voltage\ in \ secondary\ coil}[/tex]

[tex]\hookrightarrow \sf \dfrac{400}{100} = \dfrac{20}{V_2}[/tex]

[tex]\hookrightarrow \sf 400V_2}{} = 20*100[/tex]

[tex]\hookrightarrow \sf V_2 = 5 V[/tex]

Answer:

D

Explanation:

The accounts receivable would need to be changed to reset the accounts if the future service received cash in advance

Answer:

I'd probably drop it on my toes. That would happen.

Explanation: