Given the made up equation
2X + 3Y --> 8Z
If we need to make 23.3 moles of Z, how many moles of Y would we need to start with?

Answers

Answer 1

According to the fictitious equation, 8.74 moles of Y would be required to initiate the reaction if we needed to produce 23.3 moles of Z.

How many moles of Y are there, exactly?

The balanced chemical equation states that 2 moles of X and 3 moles of Y combine to create 8 moles of Z. In other words, 3 moles Y / 8 moles Z = x moles Y / 23.3 moles Z indicates that the mole ratio of Y to Z is 3:8.

where x is the required number of moles of Y.

Y = 3 moles * 23.

8 moles Z times x moles Y equals 3 moles Z.

69.9 = 8x

x = 8.74

As a result, 8.74 moles of Y would be required to make 23.3 moles of Z.

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Related Questions

The chemical process in which small organic molecules called monomers bond together to form a chain is called __________.

Answers

polymerization.
you’re welcome <3

Answer:

polymerization

Explanation:

any process in which relatively small molecules, called monomers, combine chemically to produce a very large chainlike or network molecule, called a polymer.

A 32.0 L cylinder containing helium gas at a pressure of 38.5 atm is used to fill a weather balloon in order to lift equipment into the stratosphere. What is the final pressure (in atm) in the cylinder after a 355 L balloon is filled to a pressure of 1.20 atm.

Answers

Answer:

Explanation:

We can use Boyle's Law, which states that the product of pressure and volume is constant for a fixed amount of gas at a constant temperature. We can use this law to find the final pressure in the cylinder after filling the balloon.

The initial pressure and volume of the helium gas in the cylinder are:

P1 = 38.5 atm

V1 = 32.0 L

The final volume of the gas after filling the balloon is:

V2 = 355 L

Using Boyle's Law, we can write:

P1V1 = P2V2

where P2 is the final pressure in the cylinder.

Solving for P2, we get:

P2 = (P1V1) / V2

Plugging in the values, we get:

P2 = (38.5 atm x 32.0 L) / 355 L

P2 = 3.48 atm

Therefore, the final pressure in the cylinder after filling the balloon is 3.48 atm.

a chemist titrates 190 ml of .2412 nitrous acid solution with .377 M KOH solution. Calculate the ph at equivalence. The pKa of nitrous acid is 3.35

Answers

Therefore, the pH at equivalence is 5.27 as a chemist titrates 190 ml of .2412 nitrous acid solution with .377 M KOH solution.

What is titration?

Titration is a laboratory technique used to determine the concentration of a solution (the analyte) by reacting it with a solution of known concentration (the titrant). This is typically done by slowly adding the titrant to the analyte until the reaction is complete, which can be determined by a change in color, pH, or other measurable property. The point at which the reaction is complete is called the equivalence point, and it corresponds to the stoichiometrically equivalent amounts of the analyte and titrant.

Here,

Nitrous acid (HNO2) is a weak acid, so we can use the Henderson-Hasselbalch equation to calculate the pH at equivalence:

pH = pKa + log([A-]/[HA])

where pKa is the acid dissociation constant, [A-] is the concentration of the conjugate base (NO2-), and [HA] is the concentration of the acid (HNO2).

At equivalence, the moles of acid will be equal to the moles of base. We can use this relationship to calculate the concentration of HNO2:

moles of HNO2 = (volume of HNO2 solution) x (concentration of HNO2 solution)

moles of KOH = (volume of KOH solution) x (concentration of KOH solution)

Since the stoichiometric ratio of KOH to HNO2 is 1:1, the moles of HNO2 will be equal to the moles of KOH at equivalence.

moles of HNO2 = moles of KOH

(volume of HNO2 solution) x (concentration of HNO2 solution) = (volume of KOH solution) x (concentration of KOH solution)

We can rearrange this equation to solve for the concentration of HNO2:

concentration of HNO2 = [(volume of KOH solution) x (concentration of KOH solution)] / (volume of HNO2 solution)

Now we can substitute this value into the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

pH = 3.35 + log([0.377 M]/[concentration of HNO2])

Plugging in the values, we get:

concentration of HNO2 = (190 ml) x (0.2412 M) / 1000 ml = 0.04581 moles/L

pH = 3.35 + log([0.377 M]/[0.04581 M])

pH = 5.27

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Speculate on how this effect of K+ on NCC action could simultaneously prevent hyperkalemia (from the high dietary K+ intake) AND promote increased Na+ excretion, leading to modulation of blood pressure.​

Answers

Answer:

When there is a high dietary intake of potassium (K+), there is a higher concentration of K+ in the extracellular fluid (ECF) which causes the cell membrane to depolarize. This could lead to hyperkalemia, which is a serious condition that can lead to cardiac arrhythmia, muscle weakness, and even death.

The Na-Cl cotransporter (NCC) plays a key role in the regulation of blood pressure by reabsorbing Na+ in the distal tubules of the kidneys. The NCC is regulated by the renin-angiotensin-aldosterone system (RAAS) and aldosterone increases reabsorption of Na+ through the NCC.

However, a high K+ intake can inhibit the actions of the RAAS, reducing aldosterone secretion and, therefore, reducing the reabsorption of Na+ through the NCC. This leads to increased Na+ excretion in the urine, which helps decrease blood pressure.

In addition, the increased excretion of Na+ will further limit any potential increases in serum potassium concentrations, reducing the chances of developing hyperkalemia. Therefore, the effect of K+ on NCC can simultaneously prevent hyperkalemia and promote increased Na+ excretion, leading to modulation of blood pressure.

HELP PLSSS

the screenshot is attached. it has it all there

Answers

The balanced chemical equation for the reaction is

Cl2 + 2HO → 2HCl + O2

What is  reaction ?

Reaction is a response to a situation or stimulus. It can be physical, mental, or emotional, and can range from subtle to extreme. It is a way to cope with the environment and is an important part of survival. Reactions can be conscious or unconscious and can be reflexive or voluntary. They can also be positive or negative, depending on the situation. Reactions vary depending on the individual, their experiences and their circumstances. Learning to recognize, understand, and control reactions can help people navigate challenging situations  

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In the previous steps, you determined:
pre-1982 pennies contribute 1.24 g to the
overall mass
post-1982 pennies contribute 1.50 g to
the overall mass
The overall weighted average mass comes
from combining the mass contributions
from each type of penny. Add the masses
from the previous steps together to get the
overall weighted average mass.
Weighted Average -
Pre-1982 Contribution + Post-1982
Contribution
What is the weighted average mass of a
penny from this sample?
Enter

Answers

Answer:

2.74

Explanation:

Okay, let's go through the previous steps:

Pre-1982 pennies contribute 1.24 g to the overall mass

Post-1982 pennies contribute 1.50 g to the overall mass

To calculate the weighted average mass, I'll add these contributions together:

Pre-1982 contribution: 1.24 g

Post-1982 contribution: 1.50 g

Total weighted average mass = 1.24 g + 1.50 g = 2.74 g

urea, chemical formula (NH2)2CO, is used for fertilizer and many other things. calculate the number of N, C, O, and H atoms in 1.78*10^4g of urea.

Answers

To calculate the number of N, C, O, and H atoms in 1.78*10^4g of urea, we need to first calculate the number of moles of urea, and then use the mole ratios between the elements and the compound.

The molar mass of urea can be calculated by adding up the atomic masses of its constituent elements:

Molar mass of urea = 2(14.01 g/mol N) + 2(1.01 g/mol H) + 12.01 g/mol C + 1(16.00 g/mol O)
= 60.06 g/mol

To calculate the number of moles of urea, we can divide the given mass by the molar mass:

Number of moles of urea = 1.78*10^4 g / 60.06 g/mol
= 296.26 mol

Using the chemical formula (NH2)2CO, we can see that there are 2 nitrogen atoms (N), 1 carbon atom (C), 1 oxygen atom (O), and 2 hydrogen atoms (H) in one molecule of urea.

Therefore, in 296.26 moles of urea, there are:

- 2 nitrogen atoms x 296.26 moles = 592.52 moles of N
- 1 carbon atom x 296.26 moles = 296.26 moles of C
- 1 oxygen atom x 296.26 moles = 296.26 moles of O
- 2 hydrogen atoms x 296.26 moles = 592.52 moles of H

To convert from moles to atoms, we can use Avogadro's number, which is the number of atoms in one mole of a substance:

1 mole = 6.022 x 10^23 atoms

Therefore, in 1.78*10^4g of urea, there are:

- 2 nitrogen atoms x 296.26 moles x 6.022 x 10^23 atoms/mole = 7.16 x 10^26 atoms of N
- 1 carbon atom x 296.26 moles x 6.022 x 10^23 atoms/mole = 1.79 x 10^26 atoms of C
- 1 oxygen atom x 296.26 moles x 6.022 x 10^23 atoms/mole = 1.79 x 10^26 atoms of O
- 2 hydrogen atoms x 296.26 moles x 6.022 x 10^23 atoms/mole = 7.16 x 10^26 atoms of H

Therefore, there are approximately 7.16 x 10^26 atoms of N, 1.79 x 10^26 atoms of C, 1.79 x 10^26 atoms of O, and 7.16 x 10^26 atoms of H in 1.78*10^4g of urea.

Answer this correctly please

Answers

Answer:a. 2Hg(NO3)2(s) → 2Hg(l) + 2NO2(g) + O2(g)

b. Ca3(PO4)2(aq) + 2H3PO4(aq) → 3Ca(H2PO4)2(aq)

c. 3NaOH(aq) + FeCl3(aq) → Fe(OH)3(aq) + 3NaCl(aq)

Explanation:

. What is the relative rate of effusion of Ar compared to Cl₂?

Answers

Answer:

Ar effuses 1.37 times faster than Cl₂

Explanation:

The relative rate of effusion of two gases is given by the inverse ratio of the square root of their molar masses.

The molar mass of Ar is 39.95 g/mol

The molar mass of Cl₂ is 70.91 g/mol.

Therefore, the relative rate of effusion of Ar compared to Cl₂ can be calculated as follows:

Sqrt is the square root

sqrt(70.91)/sqrt(39.95) = 1.37

So, Ar effuses 1.37 times faster than Cl₂.

Calculate the mass in grams of 4.21×1024
molecules of propylamine. The chemical formula for propylamine is C3H9N.

Answers

Answer:

413.9 grams.

Explanation:

First, we need to calculate the molar mass of propylamine (C3H9N):

Molar mass of propylamine = (3 × atomic mass of carbon) + (9 × atomic mass of hydrogen) + atomic mass of nitrogen

Molar mass of propylamine = (3 × 12.01 g/mol) + (9 × 1.01 g/mol) + 14.01 g/mol

Molar mass of propylamine = 59.11 g/mol

Next, we can use Avogadro's number to convert the number of molecules to moles:

1 mole of propylamine = 6.022 × 10^23 molecules

moles of propylamine = (4.21 × 10^24 molecules) / (6.022 × 10^23 molecules/mol)

moles of propylamine = 7.001 mol

Finally, we can use the molar mass to convert moles to grams:

mass of propylamine = moles of propylamine × molar mass of propylamine

mass of propylamine = 7.001 mol × 59.11 g/mol

mass of propylamine = 413.9 g

Therefore, the mass of 4.21×1024 molecules of propylamine is 413.9 grams.

Question 4:
1. Suppose a 70-kg individual drinks 2 L/day of water containing 0.1
mg/L of 1,1-dichloroethylene for 20 years.
(a) Find the hazard quotient for this exposure.
(b) Find the cancer risk.
(c) If the individual drinks this water for 30 years instead of just 20,
recompute the hazard quotient and the cancer risk.

Answers

(a) The hazard quotient is:

HQ = Intake / RfD = 0.0002 mg/day / 0.02 mg/kg/day = 0.01

(b) The cancer risk is 1 in 10,000.

(c) The cancer risk is 1 in 1,000.

What is Hazard quotient?

Hazard quotient (HQ) is a measure used in risk assessment to evaluate the potential health risk posed by exposure to a chemical or other hazard. It is calculated as the ratio of the dose or exposure level of the chemical to a reference dose (RfD) or reference concentration (RfC) established by regulatory agencies or scientific bodies as a safe level of exposure. If the hazard quotient is greater than 1, it suggests that the level of exposure is of potential concern and additional risk assessment may be needed.

(a) The hazard quotient (HQ) is calculated as the daily intake of a chemical divided by its reference dose (RfD). The RfD for 1,1-dichloroethylene is 0.02 mg/kg/day.

The daily intake of 1,1-dichloroethylene can be calculated as:

Intake = concentration × ingestion rate × body weight

Intake = 0.1 μg/L × 2 L/day × 70 kg = 14 μg/day = 0.0002 mg/day

The hazard quotient is:

HQ = Intake / RfD = 0.0002 mg/day / 0.02 mg/kg/day = 0.01

(b) The cancer risk from exposure to 1,1-dichloroethylene can be estimated using the unit risk factor (URF) for this chemical, which is 0.5 per mg/kg/day. The cancer risk is calculated as:

Risk = Intake × URF = 0.0002 mg/day × 0.5 per mg/kg/day = 0.0001

Therefore, the cancer risk is 1 in 10,000.

(c) If the individual drinks this water for 30 years, the total exposure would be:

Exposure = Intake × 365 days/year × 30 years = 2.19 mg

The new hazard quotient is:

HQ = Exposure / (RfD × body weight) = 2.19 mg / (0.02 mg/kg/day × 70 kg) = 1.57

The new cancer risk is:

Risk = Exposure × URF = 2.19 mg × 0.5 per mg/kg/day = 1.10

Therefore, the cancer risk is 1 in 1,000.

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In order to survive, organisms must maintain stable conditions in their bodies, even though their external environments are always changing.

For example, humans need to maintain an internal temperature around 37°C. Blood needs to have a pH around 7.4 and an oxygen saturation close to 100%.

What needs to happen in order to maintain these conditions?
A.
Organisms must be at rest.
B.
Genes must be altered each time cells replicate.
C.
Organ systems must interact with one another.
D.
all of these

Answers

A.Homeostasis Conditions inside of an organ system must remain constant, despite changes to its external environment.An organism is kept alive by numerous chemical processes.

What mechanism does the organism use to keep its surroundings stable?

Homeostasis is a self-regulating process that allows an organism to retain internal stability while adapting to shifting external situations. It has emerged as the key unifying idea of physiology.

When are living things capable of maintaining constant internal conditions?

The preservation of a steady internal environment is known as homeostasis.The term "homeostasis" was developed to define the chemical and physical conditions that an organism needs maintain in order for its constituent cells, tissues, organs, or organ systems to function correctly.

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For all the reactions, identify the reaction type and name the products formed.

1) Provide the balanced chemical equation for the complete combustion of propan-2-ol

2) 2 moles of Fluorine gas react with 2-methylpropane (provide at least two structural isomers)

3) 4-methylpent-1-ene reacts with hydrogen bromide (identify major and minor products if necessary)

MUST BE DONE ASAP 35 POINTS

Answers

Answer:

1) Reaction type: Combustion

Balanced equation: C3H8O + 5O2 → 3CO2 + 4H2O

2) Reaction type: Halogenation

Balanced equation: C4H10 + 2F2 → C4H9F + HF + F

Structural isomers of 2-methylpropane:

- 2-fluoro-2-methylpropane

- 2,2-difluoropropane

3) Reaction type: Addition

Balanced equation: C6H12 + HBr → C6H13Br

The major product is 4-bromo-4-methylpentane. The minor product is 3-bromo-4-methylpentane.

b) The beach in Antibes, France, is composed of small, smooth rocks that have been worn
down by being tumbled against each other by the energy of the sea water
Physical or chemical?
Specific type of physical or chemical:

Answers

Answer: A

Explanation: red eye

Which of the following terms would best classify of pure sodium chloride

Answers

An example of a substance with a set proportion of elements that are chemically linked together to form a single entity is sodium chloride. These substances are referred to as compounds.

Why is NaCl entirely an ion?

The reason why NaCl is powerful and highly ionic by nature is due to the electrostatic force contained within the free ions. The fact that NaCl may conduct electricity while it is molten is another compelling argument for classifying it as an ion.

Why doesn't pure dry NaCl conduct?

There are no free ions in solid NaCl because the ions are bound in their lattice structure places, but the ions can move freely in liquid or molten form, which allows them to conduct electricity.

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The given question is incomplete. The complete question is:

Which of the following terms would best classify a sample of pure sodium chloride?

A) An element

B) A highly reactive metal

C) A poisonous gas

D) A compound

Zn + 2HCl → ZnCl2 + H2


How many moles of hydrogen are produced from the reaction of 2.3 moles of zinc?

Answers

2.3 moles of zinc will produce 4.6 moles of hydrogen gas.

What is the molar ratio between zinc and hydrogen in the given chemical equation?

Answer: The molar ratio between zinc and hydrogen in the given chemical equation is 1:1, which means that one mole of zinc reacts with one mole of hydrogen to produce one mole of hydrogen gas.

From the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of H2. Therefore, to determine the number of moles of H2 produced from 2.3 moles of Zn, we need to use stoichiometry.

1 mole of Zn → 1 mole of H2

2.3 moles of Zn → x moles of H2

x = 2.3 moles of H2

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when is an inferential control configuration needed? what do you think is its primary weakness? compare it to a simple feedback control configuration. which on is preferable?

Answers

By using inferential control, the difficult-to-measure controlled variables are approximated from certain simple process variables before being used in feedback control.

Which tool is employed to measure process variables?

The two types of flow meters that are frequently used to measure the density rate of flow or velocity of a flowing fluid are the venturi meter and the orifice meter. They are also referred to as variable heading meters.

Which 5 factors are the primary process variables?

An element of a physical or chemical amount that is typically monitored and managed throughout the operation of a sewage, wastewater, or industry treatment facility. Process variables like flow, level, tension, temp, turbidity, chlorine, & oxygen concentrations are frequently used.

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NH3 is a weak base ( b=1.8×10−5 ) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.036
M in NH4Cl at 25 °C?

Answers

the pH of a solution that is 0.036 M in NH4Cl at 25 °C, x=5.3×10−6 M​.

How acidic is a buffer that contains 0.020 M NH3 и 0.030 M NH4Cl?

We obtain a pH of 9.068 and 9.07 n by dividing the logarithm of the ammonium acid concentration (0.03) by the log of a ammonia concentration (0.02).

Is NH4Cl a salt with a high acidity?

Ammonia is a salt of a weak base and a strong acid, such as hydrochloric acid (like ammonium hydroxide).Ammonium chloride's formula is NH 4 Cl, hydrochloric acid's formula is and ammonium hydroxide's formula is NH 4 OH.

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How does sickle cell anemia effect homostasis?

What is the possibility sickle cell anemia is passed on?

How many people get this disease? How common is this disease? Who is most likley to get it?

What is the diagnosis for sickle cell anemia?

Answers

Sickle cell anemia is a genetic blood disorder that affects shape and function of red blood cells.

How does sickle cell anemia effect hemostasis?

Sickle cell anemia is a genetic blood disorder that affects the shape and function of red blood cells. Hemostasis refers to process of maintaining balance between clotting and bleeding and sickle cell anemia can disrupt this balance in several ways.

One of the main effects of sickle cell anemia on hemostasis is that it can cause Vaso-occlusion, which is blockage of small blood vessels by sickle cells. This can cause tissue damage, inflammation and pain, which in turn can trigger an overactive clotting response.

Sickle cell anemia is caused by mutations in HBB gene, which provides instructions for making protein called hemoglobin.

Sickle cell anemia is most commonly found in people of African descent, although it can also occur in people of Hispanic, Middle Eastern, and Mediterranean ancestry.

Diagnosis of sickle cell anemia involves blood test to look for the presence of sickle hemoglobin.

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What is the molar mass of argon gas (AN = 18)?

Answers

Answer:

molar mass = 79.90 g/mol

Explanation:

Argon as a gas is Ar₂. Molar mass, as found on a standard IUPAC Periodic table, located on most high school chemistry and physics textbooks, as well as data sheets in examinations, is 2×39.95 = 79.90 g/mol.

2.11 A 1.0-g sample of carbon dioxide (CO2) is fully decomposed into its elements, yielding 0.273 g of carbon and 0.727 g of oxygen. (a) What is the ratio of the mass of O to C? (b) If a sample of a different compound decomposes into 0.429 g of carbon and 0.571 g of oxygen, what is its ratio of the mass of O to C? (c) According to Dalton's atomic theory, what is the empirical formula of the second compound?

Answers

The mole ratio of carbon to oxygen is therefore 1:1, which means that the empirical formula of the second compound is CO.

What is Dalton's atomic theory?

According to Dalton's atomic theory, the empirical formula of a compound gives the smallest whole-number ratio of atoms in the compound. To determine the empirical formula of the second compound, we need to calculate the mole ratio of carbon to oxygen using the masses given in the problem.

The moles of carbon can be calculated as:

moles of C = 0.429 g / 12.01 g/mol = 0.0357 mol

The moles of oxygen can be calculated as:

moles of O = 0.571 g / 16.00 g/mol = 0.0357 mol

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An unknown element X has the following isotopes: ⁵²X (90.00% abundant, atomic mass = 52.04 amu), ⁴⁹X (8.00% abundant, atomic mass = 48.99 amu), and ⁵⁰X (2.00% abundant, atomic mass = 50.09 amu). What is the average atomic mass of X in amu?

Answers

An unknown element X has the following isotopes: ⁵²X (90.00% abundant, atomic mass = 52.04 amu), ⁴⁹X (8.00% abundant, atomic mass = 48.99 amu), and ⁵⁰X (2.00% abundant, atomic mass = 50.09 amu). The average atomic mass of X is 51.72 amu.

What are isotopes?

Isotopes are variations of chemical elements that have a varied number of neutrons but the same number of protons and electrons. In other words, isotopes are different forms of the same element that have different amounts of nucleons (the sum of protons and neutrons) because of variations in the total number of neutrons in each of their individual nuclei.

For instance, the carbon isotopes carbon-14, carbon-13, and carbon-12 all exist. A total of 8 neutrons are present in carbon-14, 7 neutrons are present in carbon-13, and 6 neutrons are present in carbon-12.

Using the formula:

Average atomic mass=∑[tex]\frac{abundance}{100}[/tex]× Atomic mass

Substituting the values,

Average atomic mass = 51.72 amu

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40.532 g of an unknown compound X is dissolved in 351.11 mL. What is the molarity of X? Here is some information to determine the identity of X. When 1.00g of X is dissolved in water and allowed to react wtih AgNO3, all the chlorine in X precipitates and 1.95g of AgCl is collected. When 1.00g of X undergoes complete combustion, 0.900 g of CO2 and 0.735 g of H2O were collected. The empirical and molecular formula are identical. Compound X only contains carbon, hydrogen, nitrogen, and chlorine.

Answers

Firsttttt, let's use the data from the reaction with AgNO3 to determine the amount of chlorine in X:

1.95 g AgCl = (1.95 g AgCl) / (143.32 g/mol AgCl) = 0.0136 mol AgCl
0.0136 mol AgCl = 0.0136 mol Cl

Since we know the empirical formula and the molar mass of X is 40.532 g/mol, we can use the empirical formula to calculate the molecular formula. Let's assume that the empirical formula is CₐHᵦNᵧClᵹ:

From the combustion reaction, we can calculate the moles of carbon and hydrogen in X:

0.900 g CO2 = (0.900 g CO2) / (44.01 g/mol CO2) = 0.0205 mol CO2
0.735 g H2O = (0.735 g H2O) / (18.02 g/mol H2O) = 0.0408 mol H2O
0.0205 mol CO2 = 0.0205 mol C
0.0408 mol H2O = 0.0408 mol H
Using the law of conservation of mass, we can find the moles of nitrogen and chlorine in X:

0.0136 mol Cl = 0.0136 mol Clᵹ
0.0205 mol C + 0.0408 mol H + 0.0136 mol Clᵹ = 0.0754 mol total
0.0754 mol total = 0.0754 mol X

Now we can calculate the mole ratio of each element in X:

C: 0.0205 mol / 0.0754 mol = 0.272
H: 0.0408 mol / 0.0754 mol = 0.542
N: 0 / 0.0754 mol = 0
Cl: 0.0136 mol / 0.0754 mol = 0.181

The empirical formula is therefore C₀.₂₇H₀.₅₄N₀.₀Cl₀.₁₈.

The molar mass of the empirical formula is:
0.272 g/mol C + 0.542 g/mol H + 0.018 g/mol Cl = 0.832 g/mol
The molecular formula mass is 40

Which statement about fossil fuels is true?
_____________________________________
(any wrong/spams answers will be reported)
_____________________________________

(A) They are found deep within the earth.

(B) They do not cause pollution.

(C) They are renewable.

Answers

Explanation:

• they are found deep within earth

Answer:

A

Explanation:

fossil fuels are remains of dead plants and animals. so, they are found underground

1. Where would the convection currents be in this boiling pot of water?
2. What part of the water is the hottest?
3. What part of the water is the coolest?
4. Where is the water most dense?
5. Where is the water least dense?
6. Describe how the water in this pot will move?

Answers

All the questions- answers are mentioned below.

What is temperature ?

Temperature is a unit used to represent how hot or cold something is. It can be stated using the Celsius or Fahrenheit scales, among others. Temperature shows which way heat energy will naturally flow, i.e., from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature).

What is convection currents?

By the mass motion of a fluid, such as water, air, or molten rock, convection currents move heat from one location to another. The ocean currents, atmospheric weather, and geology of the earth are all driven by the heat transfer function of convection currents.

Water boiling in a pot can be seen to have convection currents. The water is heated by the heat source at the pan's base, which also gives the water more energy and causes its molecules to flow more quickly. Water density is impacted by temperature changes as well. The water is heated by the heat source at the pan's base, which also gives the water more energy and causes its molecules to flow more quickly. Water density is impacted by temperature changes as well.

Therefore, All the questions- answers are mentioned above.

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Why are mass and volume extensive properties and why is density an intensive property?

Answers

Answer: Density is an intensive property because there is a narrow range of densities across the samples. No matter what the initial mass was, densities were essentially the same. Since intensive properties do not depend on the amount of material, the data indicate that density is an intensive property of matter.

Density is an intensive property of matter that illustrates how much mass a substance has in a given amount of volume.

10. For the reaction
H₂(g) + O₂(g) → H₂O(l)
H=-286 kJ/mol
What is the enthalpy change when 10.4 mol of hydrogen gas reacts with excess oxygen?
a. 27.5 kJ
b.-27.5 kJ
c. 3.64 x 10-2 J
d. -2.97 × 10³ J
e. -1.48 x 10³ J

Answers

E. Is the correct answer for the question

What is the mass, in grams, of 2.45 moles of calcium atoms?

Answers

Answer:

98.20 g

Explanation:

1 mole of Ca has 40.08 g

=> 2.45 x 40.08 = 98.196 or 98.20 g

oxidation of 3-methyl-2-pentanol

Spell out the full name of the compound.

Answers

The product of oxidation of 3-methyl-2-pentanol is 3-methyl-pentan-2-one.

The oxidation of alcohol produces aldehyde and ketones.

What is oxidation of alcohol?

Alcohols are a class of substances that have one, two, or more hydroxyl (-OH) groups bonded to the single alkane bond. These substances all have the generic formula R-OH. They play a crucial role in organic chemistry since they can be altered or transformed into other chemicals, including aldehydes and ketones, among others. There are two distinct sorts of alcohol reactions. These reactions have the ability to break the R-O bond or even the O-H bond.

The oxidation process transforms the alcohols into aldehydes and ketones. One of the most significant reactions in the study of organic chemistry is this one.

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A client has a product that reads 75mls per serving. The client consumes 180 mls of the product which reads per serving 13.5g carbs, 10g protein, and 4g fat. How much energy has the client consumed.

Answers

Answer:

To calculate the energy consumed by the client, we need to use the following formula:

Energy (in calories) = (grams of carbohydrate x 4) + (grams of protein x 4) + (grams of fat x 9)

First, let's calculate the amount of each nutrient in the 180ml serving:

Carbohydrates: (75 ml / serving) x (13.5 g / 75 ml) x 180 ml = 32.4 g

Protein: (75 ml / serving) x (10 g / 75 ml) x 180 ml = 24 g

Fat: (75 ml / serving) x (4 g / 75 ml) x 180 ml = 9.6 g

Now we can calculate the energy consumed:

Energy = (32.4 g x 4) + (24 g x 4) + (9.6 g x 9) = 129.6 + 96 + 86.4 = 312 calories

Therefore, the client has consumed 312 calories from the 180 ml serving of the product.

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