given that ax60=b work out the value of 4b/a

There are three values of x where the instantaneous rate of change of f(x) are equal in the open and closed intervals

The function is given as:

[tex]f(x) = \frac 14x^4 - \frac 23x^3 + \frac 12x^2 - \frac 12x[/tex]

Calculate f(0)

[tex]f(0) = \frac 14 * 0^4 - \frac 23 * 0^3 + \frac 12 *0^2 - \frac 12 * 0[/tex]

[tex]f(0) = 0[/tex]

Calculate f(1.565)

[tex]f(1.565) = \frac 14 * 1.565^4 - \frac 23 * 1.565^3 + \frac 12 *1.565^2 - \frac 12 * 1.565[/tex]

[tex]f(1.565) = -0.613[/tex]

The average rate of change is then calculated using:

[tex]m = \frac{f(1.565) - f(0)}{1.565 - 0}[/tex]

This gives

[tex]m = \frac{-0.613 - 0}{1.565 - 0}[/tex]

[tex]m = -0.392[/tex]

Differentiate the function f(x)

[tex]f'(x) = x^3 - 2x^2 + x - \frac 12[/tex]

Set f'(x) to [tex]m = -0.392[/tex]

[tex]x^3 - 2x^2 + x - \frac 12 = -0.392[/tex]

From the graph of the above equation (see attachment), we have three values of x at:

x = 0.1492, x = 0.5614 and x = 1.2894

Hence, there are three values of x in the open interval (0,1.565)

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Answer:

63.1%

631/1,000

Step-by-step explanation:

Answer:

Step-by-step explanation:

Volume of the figure = Base area * height

Base area:

Base area = area of trpezium + area of triangle

Trapezium:

a, b area the length of parallel sides and h is the height of trapezium.

a = 8 m ; b =  5 m & h = 3 m

[tex]\boxed{ \text{ Area of trapezium = $\dfrac{(a +b)*h}{2} $}}[/tex]

                               [tex]=\dfrac{(8+5)*3}{2}\\\\\\=\dfrac{13*3}{2}\\\\\\= \dfrac{39}{2}\\\\\\= 19.5 \ m^{2}[/tex]

Triangle:

height = 4 m & base = 8 m

[tex]\boxed{\text{Area of triangle =$\dfrac{1}{2}*base*height$}}[/tex]

                           [tex]=\dfrac{1}{2}*8*4\\\\\\= 4*4\\\\= 16 \ m^{2}[/tex]

Base area = 19.5 + 16

                 = 35.5 m²

Volume of the figure = Base area * height

                                     = 35.5 * 14

                                      = 497 m³

Answer:

Step-by-step explanation:

answer: y = -5 + 19

We can use the point-slope formula to find an equation to solve this problem. The point-slope formula states: (y−y1)=m(x−x1)

Where m is the slope and (x1y1) is a point the line passes through.

Susbtituting the slope and values from the point from the problem gives:

(y−−1)=−5(x−4)

(y+1)=−5(x−4)

We can also solve this for the slope-intercept form. The slope-intercept form of a linear equation is: y=mx+b

Where m is the slope and b is the y-intercept value.

Substitute the slope from the problem for m and the values of the point from the problem for x and y and solve for b:

−1=(−5⋅4)+b

−1=−20+b

20−1=20−20+b

19=0+b

19=b

We can substitute for m and b in the formula to find the equation:

y=−5x+19

Answer:

Step-by-step explanation:

Pls give brainlest if right.

10/20-3/6 ?

Answer:

80 inches cubed

Step-by-step explanation:

V=bh

b= 5 x4 h=4

5 x 4 x 4 = 80

Answer:

2.25 miles

Step-by-step explanation:

1/4 of 9 is 2.25

Answer:

2.25 miles away

Step-by-step explanation:

first make 1/4 a percent

second set up a proportion

then solve the proportion and then you get 2.25 and add a label

Therefore, the resulting expression for the price Genevieve will pay

will be:  p - 100 - 3/20p

-lukelaws

Answer:

the ratio of one bag of flour is 8

In parallelogram SAVE, the value of the angle is m∠SEV = 125° while in parallelogram MORE ∠MOR = 111

A parallelogram is a quadrilateral with equal opposite and parallel sides. Opposite angles are equal.

In parallelogram SAVE:

m∠VAS = m∠SEV

3x - 5 = 2x + 15

x = 20

m∠VAS = 3(20) - 5 = 55 degrees

m∠VAS + m∠SEV = 180 (consecutive interior angles)

55 + m∠SEV = 180

m∠SEV = 125°

In parallelogram MORE:

∠MOR + ∠ORE = 180 (consecutive interior angles)

4x - 5 + 2x + 11 = 180

x = 29

∠MOR = 4(29) - 5 = 111

In parallelogram SAVE, the value of the angle is m∠SEV = 125° while in parallelogram MORE ∠MOR = 111

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Answer:

  3, 52

Step-by-step explanation:

The given relation can be expressed by the equation ...

  x +(17x +1) = 55 . . . . . . where x represents the smaller number

__

Solution

  18x = 54 . . . . . . . . . collect terms, subtract 1

  x = 3 . . . . . . . . . divide by 18

The smaller number is 3. The larger number is 55-3 = 52.

The intervals indicated on the graph are:

-7 < x < -3, -3 < x < -1, & 1 < x < 3 are increasing

-1 < x < 1, & 3 < x < 5 are decreasing

5 < x < 7 is neither

The interval of a function is increasing when the line slopes upward to the right along the interval. This means that the function value would increase as the input values decrease within the given interval.

On the other hand, the interval decreases when the line of the function slopes downwards within the interval. This implies that as the function value decreases, the input values increase within the given interval.

Therefore, from the graph given, we can conclude that:

-7 < x < -3: increasing

-3 < x < -1: increasing

-1 < x < 1: decreasing

1 < x < 3: increasing

3 < x < 5: decreasing

5 < x < 7: neither

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The volume and surface area of the composite shape are 575.6cm³ and 518.1cm² respectively

Composite shapes are the combination of two or more shapes combined together.

The composite shape given is made up of a hemisphere and a cone

Volume of the composite shape = 2/3πr³ + 1/3πr²h
Volume of the composite shape = 1/3πr²(2r+h)

Volume of the composite shape = 1/3(3.14)(5)²(2(5)+12)

Volume of the composite shape = 1/3(3.14)(5)²(22)
Volume of the composite shape = 575.6cm³

Hence the volume of the composite shape is 575.6cm³

Calculate the surface area

Surface area = πr(r+l) + 3π r²

Surface area = 3.14(5)(13+5) + 3(3.14)(25)
Surface area = 282.6 + 235.5 = 518.1 square cm

Hence the surface area of the composite figure is 518.1 square cm

Answer: 7.07

Step-by-step explanation:

Answers:

Sample Variance = 31.03

Sample Standard Deviation = 5.57

See the table below.

===================================================

Explanation:

M refers to the midpoint of each interval. The midpoint is [tex]M = \frac{a+b}{2}[/tex] where a,b are the left and right endpoints.

For example, [tex]M = \frac{0+4}{2} = \frac{4}{2} = 2[/tex] in the first row.

Multiply the frequency with the midpoint to get the third column. Summing this column of values leads to 4+49+180+153+154 = 540 shown at the bottom of that column.

Divide this sum over the sum of the frequencies (2+7+15+9+7 = 40) and we arrive at [tex]\overline{x} = \frac{540}{40} = 13.5[/tex] which is the sample mean xbar.

--------------------------------------------------------------------------

After we determine xbar, we subtract it from each value of M. Then we square the result to get [tex](M - \overline{x})^2[/tex]. Multiply that with the column f to get the new column [tex]f(M-\overline{x})^2[/tex].

This column is added to arrive at 1210 shown in the table below. Divide this over the sum of the frequencies minus 1. So we divide by n-1 = 40-1 = 39 to get roughly 31.03

This is the sample variance.

The square root of this is sqrt(31.03) = 5.57 and this is the approximate sample standard deviation.

Answer:

  g(n) = g(n-1) -15

  g(1) = -65

Step-by-step explanation:

We can find the recursive formula from the explicit formula for this arithmetic sequence by substituting 1 and (n+1) for n in the explicit formula.

__

  g(n+1) = -50 -15(n+1) = (-50 -15n) -15 . . . . . find g(n+1)

  g(n+1) = g(n) -15

and ...

  g(1) = -50 -15(1) = -65

Then the recursive formula can ge written as ...

  g(n) = g(n-1) -15

  g(1) = -65

_____

Additional comment

We found g(n+1) = g(n) -15. Substituting n-1 for n in this formula puts it in the form we need for answering the question:

  g((n-1)+1) = g(n-1) -15

  g(n) = g(n -1) -15

Either of these forms tells you how to get the next term from the previous one.

Answer:

g(n) = g(n-1) -15

g(1) = -65

Step-by-step explanation:

answer on khan

Answer:

Step-by-step explanation:

Compare the corresponding points, the best is vertices

Find the difference of coordinates, the rule of translation right and up

The formula of g(x) in therms of h(x) is:

Answer:

g(x) = h(x - 7) + 5

Step-by-step explanation:

Vertex of a parabola

The turning point (stationary point) of the curve.

To find the series of translations that transform the graph of y = h(x) onto y = g(x), compare the vertices of both graphs.

Vertex of h(x) = (-2, -7)

Vertex of g(x) = (5, -2)

Therefore, y = h(x) has been translated 7 units to the right and 5 units up.

Translations

For a > 0

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]

Therefore:

Therefore, the formula for g(x) in terms of h(x) is:

g(x) = h(x - 7) + 5

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Answer:

y=30

Step-by-step explanation:

it equals 30 because 2y+y=90. So now you know 3y=90. divide both sides by 3 so you can isolate the y. 90/3=30.

I have 90 because of the right angle. That is a 90-degree angle.

The lateral surface area of the triangular prism is 130 in sq. So, option D is the correct answer.

The lateral surface area of the triangular prism is the product of the perimeter of the base and length.

L = perimeter of the base × length.

The side of the base is given as 7in, 3in, and 3in

and the length is 10in

The lateral surface area of the triangular prism = perimeter of the base × length.

L = (7in + 3in + 3in) 10

L = 13 × 10

L = 130 in sq.

Hence, The lateral surface area of the triangular prism is 130 in sq. So, option D is the correct answer.

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Answer:

130 ig

Step-by-step explanation:

Answer:

A)Let's let M = the number of Multiple choice problems and

N = the number of essay questions.

B)Also, since there are 36 questions altogether, we can say that

M + N = 36

So, therefore

M = 36 - N

Step-by-step explanation:

Hope this helped I couldn’t get C very confusing.

Answer:

See below

Step-by-step explanation:

8.2 + 2/3w  = 10.7 + 1/6 w

   1/2 w    = 2.5

      w = 5 weeks

Answer:

all numbers except √34

Step-by-step explanation:

the top three are whole numbers and therefore rational

Answer:

3.

Step-by-step explanation:

You use a "centroid." There is a ratio. As provided, MW is 9. The ratio is 1:2, and CW is smaller. The answer is 3.

"The centroid is also known as the geometric center of the object. The centroid of a triangle is the point of intersection of all the three medians of a triangle. The medians are divided into a 2:1 ratio by the centroid." -cuemath .com > geometry > centroid-of-a-triangle

Answer:

u cant find the area if you dont add a picture or say if the cm is the width or the lenth.

L BOZO

Step-by-step explanation:

Answer:

PLEASE ADD PICTURE OR NOT ANSWER!

Step-by-step explanation:

We don’t know the problem. Pls apply it.

Answer:

x=−7 ±(7)2−4(1)(8)√2(1)

Step-by-step explanation:

I risked it all and got it right

Answer: A

Step-by-step explanation:

Given Information :-

⠀

⠀

To Find :-

⠀

⠀

Formula Used :-

⠀

[tex] \qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star[/tex]

⠀

Solution :-

⠀

Putting the given values, we get,

⠀

[tex]\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\ [/tex]

Thus, the value of the exterior angles of a Decagon is 36°.

⠀

[tex] \underline{ \rule{227pt}{2pt}} \\ \\ [/tex]

Answer:

⠀

Explanation :

⠀

For a regular polygon of n sides, we have

[tex]{ \longrightarrow \qquad \pmb{ \it{Each \: exterior \: angle = { \bigg( {\dfrac{360}{n} } \bigg)^{ \circ} }}}}[/tex]

⠀

Here, We are to find the measure of each exterior angle of a regular decagon.

⠀

⠀

Now, substituting the value :

⠀

[tex]\sf \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = { \bigg( {\dfrac{360}{10} } \bigg)}^{ \circ} [/tex]

⠀

[tex]\sf \longrightarrow \qquad Each \: exterior \: angle _{(Decagon)}= { \bigg( {\dfrac{36 \cancel0}{1 \cancel0} } \bigg)}^{ \circ} [/tex]

⠀

[tex]\sf \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = { \bigg( {\dfrac{36}{1} } \bigg)}^{ \circ} [/tex]

⠀

[tex]{\pmb{ \frak{ \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = 36^{ \circ} }}}[/tex]

⠀

Therefore,